Divided differences

Book summary

Summary of the book…

Book cover

?

Keywords

keyword1,

PDF

pdf file

Cite this book as:

D.V. Ionescu, Diferenţe divizate. (Romanian) [Divided differences] With a French summary. Editura Academiei Republicii Socialiste România, Bucharest, 1978. 303 pp.

Book Title
Publisher
Print ISBN
Authors
Topics
Online ISBN

Google scholar

The book on google scholar.

summary

Română

Preface

D. V. Ionescu, Diferențe divizate [Divided Differences], Editura Academiei Republicii Socialiste România, Bucharest, 1978, pp. 5–7

It is known that the divided difference of order \(n\) of a function \(f\) on the simple nodes \(x_0, x_1, \ldots, x_n\), which is denoted by

\[ [x_0, x_1, \ldots, x_n; f], \]

is defined by a recurrence formula, starting from the definition of the divided difference of order one on the nodes \(x_0, x_1\).

In the present work, the divided difference of order \(n\) on the simple nodes \(x_0, x_1, \ldots, x_n\), the notation being chosen so that \(x_0 \lt x_1 \lt \ldots \lt x_n\), is defined in the first place by means of a boundary value problem. To this end we use “the method of the function \(\varphi\)”, which assumes that \(f \in C^n[x_0, x_n]\), and we arrive at the formula

(1)
\[ [x_0, x_1, \ldots, x_n; f] = \int_{x_0}^{x_n} \varphi(s) f^{(n)}(s)\, ds. \]

The function \(\varphi\) has been studied, and it has been shown that it is positive on the interval \((x_0, x_n)\), which is a fundamental result of the work.

The definition of the divided difference of order \(n\) on simple nodes by means of a boundary value problem is extended, again by means of a boundary value problem, to the case of the nodes \(x_0, x_1, \ldots, x_k\), where \(x_0 \lt x_1 \lt \ldots \lt x_k\), of multiplicities \(n_0, n_1, \ldots, n_k\), and this divided difference is denoted by

\[ [\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f] \]

Denoting by \(n\) the number defined by \(n_0 + n_1 + \ldots + n_k = n + 1\) and assuming that \(f \in C^n[x_0, x_k]\), we prove the formula

(2)
\[ [\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f] = \int_{x_0}^{x_k} \varphi(s) f^{(n)}(s)\, ds \]

which gives at once the definition of the divided difference on multiple nodes and its integral representation. As in the case of formula (1), it is shown that the function \(\varphi\) is positive on the interval \((x_0, x_k)\), the proof, however, being much more delicate than in the case of simple nodes.

Applications are made of divided differences on simple or multiple nodes, and of their integral representations, to the Lagrange and Lagrange–Hermite interpolation formulas and to their remainders. We also determine the remainders of the Gauss and Turán quadrature formulas, establishing their connection with the integral representation of certain divided differences on multiple nodes.

The interest of the work also lies in the extension of the method of the function \(\varphi\) to the definition of the divided difference of order \(n\) of a function of two variables on the grid of nodes \(M_{i,k}\), \((i, k = 0, 1, \ldots n)\), which is denoted by

\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right] \]

and where \(x_0 \lt x_1 \lt \ldots \lt x_n\); \(y_0 \lt y_1 \lt \ldots \lt y_n\).

Under certain hypotheses on the function \(f\), which have been stated precisely in the work, it has been shown that we have the integral representation

(3)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right] = \iint_D \varphi \frac{\partial^{2n} f}{\partial x^n \partial y^n}\, dx\, dy \]

where \(D\) is the rectangle \(x_0 \leq x \leq x_n\); \(y_0 \leq y \leq y_n\), and the function \(\varphi\) has been studied, it being shown that it is positive in the open rectangle \(D\) and vanishes on its boundary.

We have likewise extended the definition of the divided difference of order \(n\) to a function \(f\) of three variables on the grid of nodes \(M_{i,j,k}(i, j, k = 0, 1, \ldots, n)\), where \(x_0 \lt x_1 \lt \ldots \lt x_n\); \(y_0 \lt y_1 \lt \ldots \lt y_n\); \(z_0 \lt z_1 \lt \ldots \lt z_n\), which is denoted by

\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f\right]. \]

Under certain hypotheses on the function \(f\), which have been stated precisely in the work, it has been shown that we have the integral representation

(4)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f\right] = \iiint_D \varphi \frac{\partial^{3n} f}{\partial x^n \partial y^n \partial z^n}\, dx\, dy\, dz, \]

where \(D\) is the parallelepiped \(x_0 \leq x \leq x_n\); \(y_0 \leq y \leq y_n\); \(z_0 \leq z \leq z_n\).

The function \(\varphi\) is positive in the open parallelepiped \(D\) and vanishes on its boundary.

Between the divided differences of order \(n\) of a function of \(p\) variables there is a recurrence relation, which has been established for \(p = 2, 3\). Taking it as the definition in general, and making suitable hypotheses on the function \(f\), we have established the definition of the divided difference of order \(n\) of a function \(f\) of the variables \(x_1, x_2, \ldots, x_p\) on the grid of nodes \(M_{i_1, i_2, \ldots, i_p}\), which we have denoted by

\[ \left[\begin{array}{l} x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} \\ x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] \]

where \(x_h^{(0)} \lt x_h^{(1)} \lt \ldots \lt x_h^{(n)}\), \(h = 1, 2, \ldots, p\).

We have shown that the following integral representation holds:

\[ \left[\begin{array}{l} x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} \\ x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] = \iint \cdots \int_D \varphi \frac{\partial^{pn} f}{\partial x_1^n \partial x_2^n \ldots \partial x_p^n}\, dx_1\, dx_2 \ldots dx_p \]

where \(D\) is the domain \(x_1^{(0)} \leq x_1 \leq x_1^{(n)}\); \(\ldots\); \(x_p^{(0)} \leq x_p \leq x_p^{(n)}\).

It has been proved that the function \(\varphi(x_1, x_2, \ldots, x_p)\) is positive in the open domain \(D\) and vanishes on its boundary.

D. V. Ionescu

↑ Contents

Română

D. V. Ionescu

Divided Differences

Diferențe divizate

English translation

Editura Academiei Republicii Socialiste România
Bucharest, 1978

Contents

    1. § 1.1. The first boundary value problem31
    2. § 1.2. The Lagrange interpolation formula40
    3. § 1.3. The case of nodes in arithmetic progression43
    1. § 2.1. The second boundary value problem47
    2. § 2.2. On a property of the coefficients \(\lambda_0, \lambda_1, \ldots, \lambda_{k-1}\) in formula (2.1.29)55
    3. § 2.3. On a property of the coefficients \(\lambda_0, \lambda_0^{(1)}, \ldots, \lambda_0^{(n_0-1)}\) and \(\lambda_k, \lambda_k^{(1)}, \ldots, \lambda_k^{(n_k-1)}\) of formula (2.1.29)59
    4. § 2.4. The fundamental theorem on the function \(\varphi\)65
    5. § 2.5. The Lagrange–Hermite interpolation formula76
    1. § 3.1. The integral representation of the divided difference \([a, \underbrace{x_1, \ldots, x_1}_{k}, \underbrace{x_2, \ldots, x_2}_{k}, \ldots, \underbrace{x_n, \ldots, x_n}_{k}, b; f]\)84
    2. § 3.2. The quadrature formula of Gauss93
    3. § 3.3. The quadrature formula of P. Turán98
    4. § 3.4. Extension of the Gauss quadrature formula115
    5. § 3.5. Extension of P. Turán's quadrature formula122
    1. § 4.1. The integration by parts formula for functions of two variables131
    2. § 4.2. Boundary value problem136
    3. § 4.3. The divided difference of order \(n\) of the function \(f\) on a grid of nodes \(M_{i,k}\), \((i, k = 0, 1, \ldots, n)\) and its integral representation164
    1. § 5.1. The integration by parts formula for functions of three variables169
    2. § 5.2. Boundary value problem183
    3. § 5.3. The problems \((P_{i,j,0})\), \((P_{0,j,k})\), \((P_{i,0,k})\)191
    4. § 5.4. The problem \((P_{i,j,1})\)208
    5. § 5.5. The general case: the problem \((P_{i,j,k})\)235
    6. § 5.6. The equations satisfied by the coefficients \(C_{i,j,0}, \ldots, C_{i,j,n}\) for \(i, j = 0, 1, \ldots, n\)261
    7. § 5.7. Conclusions285
    8. § 5.8. The divided difference of order \(n\) of the function \(f\) on the grid of nodes \(M_{i,j,k}(i, j, k = 0, 1, \ldots, n)\) and its integral representation288
    1. § 6.1. Definition of the divided difference of order \(n\) of a function of \(p\) variables by a recurrence formula293
    2. § 6.2. The integral representation of the divided difference of order \(n\) of the function \(f\) on the grid of nodes \(M_{i_1, i_2, \ldots, i_p}\)296

Original edition: Diferențe divizate, Editura Academiei Republicii Socialiste România, Bucharest, 1978; editor Petre Mocanu; 303 pages.

Complete English translation of the Romanian text. Page numbers in these contents and in the margins refer to the printed edition. Obvious misprints of the original — in the text, in the formulas and in the equation numbers — have been corrected silently in this translation; the Romanian version reproduces the text exactly as printed, with the misprints marked. The Brief introduction is translated from the French summary that closes the book. Titles in the bibliography are left in their original languages. Cross-references to formulas, sections, theorems and the bibliography are links.

Română

Introduction

D. V. Ionescu, Diferențe divizate [Divided Differences], Editura Academiei Republicii Socialiste România, Bucharest, 1978, pp. 11–29

For 25 years I have been publishing papers on numerical analysis regularly. I use a very fruitful research method, which I have called the method of the function \(\varphi\).

This method is essentially Green’s method, well known in mathematical physics, applied here to problems of numerical analysis. Several authors have published papers with concerns of this kind, among whom I mention H. Radon (1935) [33], G. Kowalewski (1932) [23], A. Ghizzetti and A. Ossicini (1970) [27].

The aim of the present work is, in the first place, to set out the definition of the divided difference of order \(n\) of a function \(f\) of one variable on the nodes \(x_0, x_1, \ldots, x_n\), where \(x_0 \lt x_1 \lt \ldots \lt x_n\), which is denoted by \([x_0, x_1, \ldots x_n; f]\), and to give its integral representation when \(f \in C^n[x_0, x_n]\).

This is done by means of the method of the function \(\varphi\), by treating a suitably posed boundary value problem which leads to the definition of the divided difference and to its integral representation by the formula

(1)
\[ [x_0, x_1, \ldots, x_n; f] = \int_{x_0}^{x_n} \varphi(s) f^{(n)}(s)\, ds. \]

We shall further specify the function \(\varphi\) and show that the research method employed allows it to be studied on the interval \([x_0, x_n]\).

We shall then treat the consequences that follow from this method for obtaining formula (1), and the most important part of the work will be devoted to the definition of the divided difference of order \(n\) for functions of two variables on a grid \(M_{i,k}(x_i, y_k)\), \(i, k = 0, 1, \ldots, n\), and to its integral representation, as well as for functions of three variables on a grid \(M_{i,j,k}(x_i, y_j, z_k)\), \(i, j, k = 0, 1, \ldots, n\), together with its integral representation.

The working method employed in the case of \(n\) variables, \(n = 2\) and \(n = 3\), gives rise to computational difficulties which have been skilfully circumvented and which become more complicated for \(n \gt 3\).

By means of the hypotheses imposed on the function \(f\) in the cases \(n = 2\) and \(n = 3\), we have brought to light a recurrence formula for divided differences.

The recurrence formula was given in the case \(n = 2\), a priori, by T. Popoviciu [31], who did not go further and did not give the integral representation of the divided difference. By changing the hypotheses on the function \(f\), we have arrived at the definition of the divided difference for functions of \(p\) variables by means of a recurrence formula, and at their integral representation. This is the subject of the last chapter of the work.

We shall now give, one by one, an account of the problems treated in each chapter.

1. In order to arrive at formula (1) by applying the method of the function \(\varphi\), we attach to the intervals \([x_0, x_1]\), \([x_1, x_2]\), \(\ldots\), \([x_{n-1}, x_n]\), respectively, the polynomials \(\varphi_1, \varphi_2, \ldots \varphi_n\), solutions of the differential equations

(2)
\[ \varphi_1^{(n)} = 0, \quad \varphi_2^{(n)} = 0, \ldots, \varphi_n^{(n)} = 0 \]

and we assume that \(f \in C^n[x_0, x_n]\). To each integral \(\int_{x_{i-1}}^{x_i} \varphi_i f^{(n)}\, ds\), \((i = 1, 2, \ldots, n)\), we apply the generalized integration by parts formula, and we add all these formulas. We obtain a formula of the form

(3)
\[ \mathscr{P}[f] = \int_{x_0}^{x_n} \varphi f^{(n)}\, ds, \]

where the function \(\varphi\) coincides with the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_n\) on the respective intervals, and where \(\mathscr{P}[f]\) is a functional depending on the values of the function \(f\) and of its derivatives \(f', f'', \ldots, f^{(n-1)}\) at the nodes. In connection with formula (3) we pose the following:

Boundary value problem. To determine the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_n\) such that \(\mathscr{P}[f]\) depends only on the values of \(f\) at the nodes and such that \(\mathscr{P}[f] = 1\) for \(f(x) = x^n\).

The solution \(\varphi\) of this problem is the spline function of order \(n-1\) defined on the interval \([x_0, x_n]\) with the nodes \(x_0, x_1, \ldots, x_n\) [35].

Definition. The divided difference of order \(n\) of the function \(f\) on the nodes \(x_0, x_1, \ldots, x_n\) is the value of the functional \(\mathscr{P}[f]\) in which the function \(\varphi\) is replaced by the solution of the boundary value problem; it is denoted by \([x_0, x_1, \ldots, x_n; f]\).

Replacing in formula (3) the function \(\varphi\) by the solution of the boundary value problem, we obtain the integral representation of the divided difference \([x_0, x_1, \ldots, x_n; f]\), that is, formula (1).

The function \(\varphi\), the solution of the boundary value problem posed above, is of great importance in the study of the divided difference. By means of the boundary conditions of the problem it is proved that the function \(\varphi\) is positive on the interval \((x_0, x_n)\). Formula (1) has also been obtained by other mathematicians, among whom I mention G. Peano [30], A. Sard [34], L. Tchakaloff [46].

In subsection 1.1.3 I have given a proof of formula (1) which arose from a conversation with Prof. P. J. Laurent [24] and which I attribute to Prof. Laurent.

I have applied formula (1) to establishing the Lagrange interpolation formula and its remainder, as well as to the theory of differences.

2. In Chapter II I have applied the method of the function \(\varphi\) in order to define the divided difference of a function \(f\) on the nodes \(x_0, x_1, \ldots, x_k\), \(x_0 \lt x_1 \lt \ldots \lt x_k\), of multiplicities \(n_0, n_1, \ldots, n_k\), and to obtain its integral representation.

Defining the number \(n\) by the formula \(n + 1 = n_0 + n_1 + \ldots + n_k\), I have attached to the intervals \([x_0, x_1]\), \([x_1, x_2]\), \(\ldots\), \([x_{k-1}, x_k]\) the polynomials \(\varphi_1\; \varphi_2, \ldots, \varphi_k\), solutions of the differential equations

(4)
\[ \varphi_1^{(n)} = 0, \quad \varphi_2^{(n)} = 0, \ldots, \varphi_k^{(n)} = 0. \]

Assuming that \(f \in C^n[x_0, x_k]\), I have applied the generalized integration by parts formula to the integrals \(\int_{x_{i-1}}^{x_i} \varphi_i f^{(n)}\, ds\), for \(i = 1, 2, \ldots, k\), and have added all these formulas term by term. I have obtained a formula of the form

(5)
\[ \mathscr{P}[f] = \int_{x_0}^{x_k} \varphi(s) f^{(n)}(s)\, ds, \]

where \(\mathscr{P}[f]\) is a functional depending on the values of \(f, f', f'', \ldots, f^{(n-1)}\) at the nodes \(x_0, x_1, \ldots, x_k\), while the function \(\varphi\) coincides with the polynomials \(\varphi_1, \varphi_2, \ldots \varphi_k\) on the intervals \([x_0, x_1]\), \([x_1, x_2]\), \(\ldots\), \([x_{k-1}, x_k]\).

In connection with formula (5) I have treated the following:

Boundary value problem. To determine the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_k\) such that the coefficients of \(f^{(n_0)}(x_0), \ldots, f^{(n-1)}(x_0);\ f^{(n_1)}(x_1), \ldots, f^{(n-1)}(x_1);\ \ldots;\ f^{(n_k)}(x_k), \ldots, f^{(n-1)}(x_k)\) vanish and such that \(\mathscr{P}[f] = 1\) for \(f(x) = x^n\).

It is proved that this boundary value problem has a unique solution.

Definition. The divided difference of order \(n\) of the function \(f\) on the nodes \(x_0, x_1, \ldots, x_k\), of multiplicities \(n_0, n_1, \ldots, n_k\), where \(n + 1 = n_0 + n_1 + \ldots + n_k\), is the value of the functional \(\mathscr{P}[f]\) in which the function \(\varphi\) is replaced by the solution of the boundary value problem; it is denoted by

(6)
\[ [\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f]. \]

If we denote by \(\Delta[f]\) the determinant (2.1.22)

(7)
\[ \Delta[f] = \begin{vmatrix} 1 & x_0 & \ldots & x_0^{n-1} & f(x_0) \\ 0 & 1 & \ldots & (x_0^{n-1})' & f'(x_0) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_0^{n-1})^{(n_0-1)} & f^{(n_0-1)}(x_0) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ \ldots & \ldots & \ldots & \ldots & \ldots \end{vmatrix} \]

then

(8)
\[ [\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f] = \frac{\Delta[f]}{\Delta[x^n]}. \]

Replacing in formula (5) the function \(\varphi\) by the solution of the boundary value problem, we obtain the integral representation of the divided difference (6), namely

(9)
\[ [\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f] = \int_{x_0}^{x_k} \varphi(s) f^{(n)}(s)\, ds. \]

By means of the boundary conditions of the boundary value problem, and with the preparation made in § 2.2 and § 2.3, there is proved in § 2.4 the fundamental theorem that the function \(\varphi\) in the integral representation (9) is positive on the interval \((x_0, x_k)\).

The proof I gave to show that the function \(\varphi\) in the integral representation (9) is positive on the interval \((x_0, x_k)\) when the nodes are multiple was used by Paraschiva Pavel to prove that the function \(\varphi\) in the integral representation of the remainder of the Gauss-type quadrature formula with multiple but distinct nodes, given by Tiberiu Popoviciu, keeps a constant sign on the interval of integration.

In § 2.5 the divided difference of a function on multiple nodes and its integral representation are given an important application: obtaining the Lagrange–Hermite interpolation formula and studying its remainder.

3. In Chapter III, § 3.2, a connection is established between the Gauss quadrature formula [9]

(10)
\[ \int_a^b f(x)\, dx = C_1 f(x_1) + C_2 f(x_2) + \ldots + C_n f(x_n) + R[f], \]

where the nodes \(x_1, x_2, \ldots, x_n\) are the roots of the Legendre polynomial associated with the interval \([a, b]\) and \(f \in C^{2n}[a, b]\), and the divided difference of a function \(g \in C^{2n+1}[a, b]\):

(11)
\[ [a, x_1, x_1, \ldots, x_n, x_n, b; g] = \int_a^b \varphi g^{(2n+1)}\, dx. \]

Writing

(12)
\[ {[}a, x_1, x_1, \ldots, x_n, x_n, b; g] = {} A_0 g(a) + A_1 g(x_1) + \ldots + A_n g(x_n) + A_{n+1} g(b) + A_1' g'(x_1) + \ldots + A_n' g'(x_n) \]

we have the following theorem:

Theorem 3.2.1. If in formula (12) the nodes \(x_1, x_2, \ldots, x_n\) are the roots of the Legendre polynomial associated with the interval \([a, b]\), then the coefficients \(A_1, A_2, \ldots, A_n\) in formula (12) are zero [10].

Since \(A_0 + A_{n+1} = 0\) and \(A_{n+1} \neq 0\), we deduce:

Theorem 3.2.2. The Gauss quadrature formula (10) is deduced from the integral representation of the divided difference (11) by replacing the nodes \(x_1, x_2, \ldots, x_n\) by the roots of the Legendre polynomial associated with the interval \([a, b]\) and setting \(g' = f\).

4. In § 3.3 we study P. Turán’s quadrature formula [47]

(13)
\[ \begin{aligned} \int_a^b p(x) f(x)\, dx = {} & C_1^{(0)} f(x_1) + \ldots + C_n^{(0)} f(x_n) + \\ & + C_1^{(1)} f'(x_1) + \ldots + C_n^{(1)} f'(x_n) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + C_1^{(2(s-1))} f^{(2(s-1))}(x_1) + \ldots + C_n^{(2(s-1))} f^{(2(s-1))}(x_n) + R[f], \end{aligned} \]

where \(p\) is a function integrable on the interval \([a, b]\) and positive on the interval \((a, b)\), while the right-hand side contains the derivatives \(f^{(l)}\) for \(l = 0, 1, \ldots, 2(s-1)\) at the nodes \(x_1, x_2, \ldots, x_n\).

P. Turán’s problem. To determine the nodes \(x_1, x_2, \ldots, x_n\) and the coefficients \(C_1^{(l)}, \ldots, C_n^{(l)}\), \(l = 0, 1, \ldots, 2(s-1)\), such that in formula (13) we have \(R[f] = 0\) for \(f(x) = x^k\), \(k = 0, 1, \ldots, 2ns-1\).

This problem is connected with a minimum problem of D. Jackson [22], namely: to determine uniquely the coefficients of the polynomial

(14)
\[ \omega_n(x) = x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n \]

such that the integral

(15)
\[ \int_a^b p(x)\, \omega_n^{2s}(x)\, dx, \]

where \(s\) is a natural number, is minimal.

In this work we give the proof of this theorem due to Margareta Frenkel [4], which seems to us better suited to the problems of Numerical Analysis than D. Jackson’s proof.

The polynomial \(\omega_n(x)\) which realizes the minimum of the integral (15) is called the minimizing polynomial.

It is proved that the coefficients \(\lambda_1, \lambda_2, \ldots, \lambda_n\) of the minimizing polynomial are uniquely determined by the equations

(16)
\[ \int_a^b p(x)\, \omega_n^{2s-1}(x)\, x^h\, dx = 0 \quad \text{for } h = 0, 1, \ldots, n-1. \]

The minimizing polynomial \(\omega_n\) has all its roots real, distinct and lying between \(a\) and \(b\).

Theorem 3.3.4. (P. Turán). The nodes \(x_1, x_2, \ldots, x_n\) in Turán’s problem are the roots of the minimizing polynomial of the integral (15).

Once the nodes in formula (13) have been determined, the coefficients \(C_1^{(l)}, \ldots, C_n^{(l)}\) for \(l = 0, 1, \ldots, 2(s-1)\) are easily determined.

5. Let us assume that \(p(x) = 1\). The remainder of Turán’s quadrature formula is then determined by a method analogous to the one presented in item 3 for determining the remainder of the Gauss formula.

Let us consider the divided difference

(17)
\[ [a, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, b; g] \]

of a function \(g \in C^{2ns+1}[a, b]\). We can write:

(18)
\[ \begin{aligned} {[}a, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, b; g] = {} & A_0 g(a) + A_1^{(0)} g(x_1) + \ldots + A_n^{(0)} g(x_n) + A_{n+1} g(b) + \\ & + A_1^{(1)} g'(x_1) + \ldots + A_n^{(1)} g'(x_n) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + A_1^{(2s-1)} g^{(2s-1)}(x_1) + \ldots + A_n^{(2s-1)} g^{(2s-1)}(x_n). \end{aligned} \]

Theorem 3.3.5. If \(x_1, x_2, \ldots, x_n\) are the nodes of the minimizing polynomial of the integral (15), then in formula (18) we have \(A_1^{(0)} = 0, \ldots, A_n^{(0)} = 0\).

Since \(A_0 + A_{n+1} = 0\) and \(A_{n+1} \neq 0\), we deduce:

Theorem 3.3.6. P. Turán’s quadrature formula is deduced from the integral representation of the divided difference (17) when \(g \in C^{2ns+1}[a, b]\):

(19)
\[ [a, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, b; g] = \int_a^b \varphi(t) g^{(2ns+1)}(t)\, dt \]

by replacing the nodes \(x_1, x_2, \ldots, x_n\) by the roots of the minimizing polynomial of the integral (15) and setting \(g' = f\).

6. In § 3.4 and § 3.5 the Gauss and P. Turán quadrature formulas with the weight \(\pi(x)\) are extended to the case when the multiple nodes \(a\) and \(b\), of multiplicities \(p\) and \(q\), are added to the nodes \(x_1, x_2, \ldots, x_n\).

When the weight is \(\pi(x) = 1\), one proceeds as in item 4, showing that the remainders of the Gauss and Turán quadrature formulas are connected with the integral representation of the divided differences (11) and (19), in which, however, the nodes \(a\) and \(b\) are multiple, of multiplicities \(p + 1\) and \(q + 1\) [11].

7. In Chapter IV the method of the function \(\varphi\), used to define the divided difference of order \(n\) of a function of one variable and to obtain its integral representation, is extended to functions of two variables. This extension will again be reached by means of a boundary value problem. At the basis of this work lies the integration by parts formula for a double integral. In § 4.1 it is shown that this formula was established by M. Nicolescu [26], and we shall write it in a form which we consider convenient for our work.

Theorem 4.1.1. If the functions \(f, \varphi\) are continuous on the rectangle \(\Delta\) defined by the inequalities

\[ \Delta : \qquad x_1 \leq x \leq x_2, \quad y_1 \leq y \leq y_2 \]

together with their partial derivatives

(20)
\[ \begin{aligned} & \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial^2 f}{\partial x \partial y}, \\ & \frac{\partial \varphi}{\partial x}, \frac{\partial \varphi}{\partial y}, \frac{\partial^2 \varphi}{\partial x \partial y}, \end{aligned} \]

then we have the formula

(21)
\[ \int_{x_1}^{x_2} \int_{y_1}^{y_2} \varphi \frac{\partial^2 f}{\partial x \partial y}\, dx\, dy = {} \varphi(x, y) f(x, y) \Big|_{x_1, y_1}^{x_2, y_2} - \sum \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x}(x, y) f(x, y) \Bigg|_{y_1}^{y_2} dx + \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^2 \varphi}{\partial x \partial y} f\, dx\, dy \]

which we call the integration by parts formula for double integrals.

8. Theorem 4.1.2. If the functions \(f, \varphi\) are continuous on the rectangle \(\Delta\) together with the partial derivatives

(22)
\[ \begin{aligned} & \frac{\partial^{2p-1} f}{\partial x^p \partial y^{p-1}}, \frac{\partial^{2p-1} f}{\partial x^{p-1} \partial y^p}, \frac{\partial^{2p} f}{\partial x^p \partial y^p}, \\ & \frac{\partial^{2p-1} \varphi}{\partial x^p \partial y^{p-1}}, \frac{\partial^{2p-1} \varphi}{\partial x^{p-1} \partial y^p}, \frac{\partial^{2p} \varphi}{\partial x^p \partial y^p} \end{aligned} \]

for \(p = 1, 2, \ldots, n\), then we have the generalized integration by parts formula

(23)
\[ \begin{aligned} \int_{x_1}^{x_2} \int_{y_1}^{y_2} \varphi \frac{\partial^{2n} f}{\partial x^n \partial y^n}\, dx\, dy = {} & \sum_{r=0}^{n-1} \frac{\partial^{2(n-r-1)} \varphi}{\partial x^{n-r-1} \partial y^{n-r-1}}(x, y) \frac{\partial^{2r} f}{\partial x^r \partial y^r}(x, y) \Bigg|_{x_1, y_1}^{x_2, y_2} - \\ & - \sum_{r=0}^{n-1} \sum \int_{x_1}^{x_2} \frac{\partial^{2(n-r)-1} \varphi}{\partial x^{n-r} \partial y^{n-r-1}}(x, y) \frac{\partial^{2r} f}{\partial x^r \partial y^r}(x, y) \Bigg|_{y_1}^{y_2} dx + \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^{2n} \varphi}{\partial x^n \partial y^n} f\, dx\, dy. \end{aligned} \]

9. Let us consider the rectangle

\[ D : \qquad x_0 \leq x \leq x_n, \quad y_0 \leq y \leq y_n \]

the nodes \(M_{i,k}(x_i, y_k)\), where

(24)
\[ x_0 \lt x_1 \lt \ldots \lt x_{n-1} \lt x_n, \quad y_0 \lt y_1 \lt \ldots \lt y_{n-1} \lt y_n \]

and the rectangles

\[ D_{i,k} : \quad x_i \leq x \leq x_{i+1}, \quad y_k \leq y \leq y_{k+1}, \quad \text{where } i, k = 0, 1, \ldots, n-1. \]

Let us further consider the functions \(\varphi_{i,k}\), \((i, k = 0, 1, \ldots, n-1)\), continuous on \(D_{i,k}\) together with the partial derivatives

(25)
\[ \frac{\partial^{2p-1} \varphi_{i,k}}{\partial x^p \partial y^{p-1}}, \frac{\partial^{2p-1} \varphi_{i,k}}{\partial x^{p-1} \partial y^p}, \frac{\partial^{2p} \varphi_{i,k}}{\partial x^p \partial y^p}, \quad \text{for } p = 1, 2, \ldots, n. \]

To each rectangle \(D_{i,k}\) and to the pair of functions \(f, \varphi_{i,k}\) let us apply the fundamental formula (23). We add all these formulas term by term and thus obtain the important formula:

(26)
\[ \sum_{i=0}^{n-1} \sum_{k=0}^{n-1} \iint_{D_{i,k}} \varphi_{i,k} \frac{\partial^{2n} f}{\partial x^n \partial y^n}\, dx\, dy = \mathscr{P}[f] + \sum_{i=0}^{n-1} \sum_{k=0}^{n-1} \iint_{D_{i,k}} \frac{\partial^{2n} \varphi_{i,k}}{\partial x^n \partial y^n} f\, dx\, dy, \]

where \(\mathscr{P}[f]\) is written more briefly in the form

(27)
\[ \begin{aligned} \mathscr{P}[f] = {} & \sum_{r=0}^{n-1} \sum_{i=0}^{n} \sum_{k=0}^{n} \left( \frac{\partial^{2(n-r-1)}(\varphi_{i,k} + \varphi_{i-1,k-1} - \varphi_{i,k-1} - \varphi_{i-1,k})}{\partial x^{n-r-1} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_i, y_k} + \\ & + \sum_{r=0}^{n-1} \sum_{i=0}^{n-1} \sum_{k=0}^{n} \int_{x_i}^{x_{i+1}} \left( \frac{\partial^{2(n-r)-1}(\varphi_{i,k} - \varphi_{i,k-1})}{\partial x^{n-r} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x, y_k} dx + \\ & + \sum_{r=0}^{n-1} \sum_{i=0}^{n} \sum_{k=0}^{n-1} \int_{y_k}^{y_{k+1}} \left( \frac{\partial^{2(n-r)-1}(\varphi_{i,k} - \varphi_{i-1,k})}{\partial x^{n-r-1} \partial y^{n-r}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_i, y} dy, \end{aligned} \]

where on the right-hand side we write all the terms with the following convention:

Convention (A). The function \(\varphi_{i,k}\) shall be considered equal to zero when one of the indices \(i, k\), or both, are equal to \(n\) or to \(-1\).

10. In connection with formula (26) and with the expression (27) of \(\mathscr{P}[f]\), we pose the following:

Boundary value problem. To determine the functions \(\varphi_{i,k}\), solutions of the partial differential equations

(28)
\[ \frac{\partial^{2n} \varphi_{i,k}}{\partial x^n \partial y^n} = 0 \quad \text{for } i, k = 0, 1, \ldots, n \]

such that \(\mathscr{P}[f]\) depends only on the values of \(f\) at the nodes \(M_{i,k}\) for \(i, k = 0, 1, \ldots, n\).

For this purpose the following boundary conditions are introduced:

(29)
\[ \begin{aligned} \frac{\partial^{2(n-r)-1}(\varphi_{i,k} - \varphi_{i,k-1})}{\partial x^{n-r} \partial y^{n-r-1}}(x, y_k) &= 0 \\ \frac{\partial^{2(n-r)-1}(\varphi_{i,k} - \varphi_{i-1,k})}{\partial x^{n-r-1} \partial y^{n-r}}(x_i, y) &= 0 \\ \frac{\partial^{2(n-r-1)}(\varphi_{i,k} + \varphi_{i-1,k-1} - \varphi_{i,k-1} - \varphi_{i-1,k})}{\partial x^{n-r-1} \partial y^{n-r-1}}(x_i, y_k) &= \begin{cases} C_{ik} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{aligned} \]

for \(r = 0, 1, \ldots, n-1\) and \(i, k = 0, 1, \ldots, n\). When we take \(i = 0\), \(k = 0\) or \(i = n\), \(k = n\); or \(i = n\); or \(k = n\), convention (A) must be taken into account in the boundary conditions (29). This problem is denoted by \((P_{i,k})\). First the problem \((P_{0,0})\) is solved, then successively \((P_{1,0}), \ldots, (P_{n-1,0})\); \((P_{0,1}), \ldots, (P_{n-1,1}), \ldots\); and so on.

The constants \(C_{i,k}\) will be determined up to a factor \(H\), so that the boundary value problem is possible. The factor \(H\) is determined so that

(30)
\[ \mathscr{P}[f] = 1, \quad \text{for } f(x, y) = x^n y^n. \]

With skill and patience one finds that

(31)
\[ \begin{aligned} \varphi_{i,k}(x, y) = {} & \left[ C_{0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} + \\ & + \left[ C_{0,1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,1} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_1)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,k} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,k} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_k)^{n-1}}{(n-1)!}, \end{aligned} \]

where the constants \(C_{i,k}\) are determined by also taking into account the last condition (30), and we have

(32)
\[ C_{i,k} = (-1)^{i+k} \frac{V(x_0, x_1, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)}{V(x_0, x_1, \ldots, x_n)} \, \frac{V(y_0, y_1, \ldots, y_{k-1}, y_{k+1}, \ldots, y_n)}{V(y_0, y_1, \ldots, y_n)}. \]

If in \(\mathscr{P}[f]\) we replace the functions \(\varphi_{i,k}\) by the solution of the boundary value problem, we find

(33)
\[ \mathscr{P}[f] = \sum_{i=0}^{n} \sum_{k=0}^{n} C_{i,k} f(x_i, y_k). \]

Definition 4.3.1. The expression \(\mathscr{P}[f]\) given by formula (33) is called the divided difference of order \(n\) of the function \(f\) on the grid \(M_{i,k}(i, k = 0, 1, \ldots n)\) and is denoted by

(34)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right]. \]

Theorem 4.3.1. The divided difference of order \(n\) of the function \(f\) on the grid of nodes \(M_{i,k}\), \((i, k = 0, 1, \ldots, n)\), is given by the formula

(35)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right] = \sum_{i=0}^{n} \sum_{k=0}^{n} C_{i,k} f(x_i, y_k). \]

Theorem 4.3.2. The divided difference of order \(n\) of the function \(f\) on the grid \(M_{ik}\), \((i, k = 0, 1, \ldots, n)\), has the integral representation:

(36)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right] = \iint_D \varphi \frac{\partial^{2n} f}{\partial x^n \partial y^n}\, dx\, dy, \]

where \(\varphi\) is the solution of the boundary value problem treated in § 4.2.

11. Taking into account the expression of the coefficients \(C_{i,k}\), introducing the divided differences of order \(n\) of the function \(u\) on the nodes \(x_0, x_1, \ldots, x_n\) and of the function \(v\) on the nodes \(y_0, y_1, \ldots, y_n\), and assuming that \(u \in C^n[x_0, x_n]\), \(v \in C^n[y_0, y_n]\), we have

(37)
\[ [x_0, x_1, \ldots, x_n; u] = \lambda_0 u(x_0) + \lambda_1 u(x_1) + \ldots + \lambda_n u(x_n) + \int_{x_0}^{x_n} \psi(s)\, u^{(n)}(s)\, ds \]
(38)
\[ [y_0, y_1, \ldots, y_n; v] = \mu_0 v(y_0) + \mu_1 v(y_1) + \ldots + \mu_n v(y_n) + \int_{y_0}^{y_n} \theta(t)\, v^{(n)}(t)\, dt. \]

The following theorems result:

Theorem 4.3.3. The coefficients \(C_{i,k}\) in the divided difference (35) are given by the formula

(39)
\[ C_{i,k} = \lambda_i \mu_k. \]

Theorem 4.3.4. The function \(\varphi_{i,k}(x, y)\) is the product

(40)
\[ \varphi_{i,k}(x, y) = \psi_i(x)\, \theta_k(y), \]

where

(41)
\[ \begin{aligned} \psi_i(x) &= \lambda_0 \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + \lambda_i \frac{(x - x_i)^{n-1}}{(n-1)!}; \\ \theta_k(y) &= \mu_0 \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + \mu_k \frac{(y - y_k)^{n-1}}{(n-1)!}. \end{aligned} \]

It follows that the function \(\varphi\) in the integral representation (36) is the product of the spline functions \(\psi\) and \(\theta\) in the integral representations (37), (38).

Theorem 4.3.5. The function \(\varphi\) in the integral representation of the divided difference of the function \(f\) of two variables on the grid of nodes \(M_{ik}(x_i, y_k)\), \((i, k = 0, 1, \ldots, n)\), is positive on the open rectangle \(D\) and vanishes on the boundary of this rectangle.

12. Chapter V deals with the definition of the divided difference of a function \(f\) of three variables on a grid of nodes \(M_{i,j,k}(x_i, y_j, z_k)\), where \(i, j, k = 0, 1, \ldots, n\), and gives its integral representation under certain hypotheses on the function \(f\).

Theorem 5.1.1. If the functions \(f\) and \(\varphi\) of the three variables \(x, y, z\) are continuous on the parallelepiped \(\Delta\) defined by the inequalities

\[ \Delta : \qquad x_1 \leq x \leq x_2, \quad y_1 \leq y \leq y_2, \quad z_1 \leq z \leq z_2 \]

together with their partial derivatives

(42)
\[ \begin{aligned} & \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial f}{\partial z}, \frac{\partial^2 f}{\partial y \partial z}, \frac{\partial^2 f}{\partial z \partial x}, \frac{\partial^2 f}{\partial x \partial y}, \frac{\partial^3 f}{\partial x \partial y \partial z}, \\ & \frac{\partial \varphi}{\partial x}, \frac{\partial \varphi}{\partial y}, \frac{\partial \varphi}{\partial z}, \frac{\partial^2 \varphi}{\partial y \partial z}, \frac{\partial^2 \varphi}{\partial z \partial x}, \frac{\partial^2 \varphi}{\partial x \partial y}, \frac{\partial^3 \varphi}{\partial x \partial y \partial z}, \end{aligned} \]

then we have the transformation formula for triple integrals

(43)
\[ \begin{aligned} &\iiint_{\Delta} \varphi \frac{\partial^3 f}{\partial x\, \partial y\, \partial z}\, dx\, dy\, dz = \varphi(x, y, z) f(x, y, z) \bigg|_{x_1, y_1, z_1}^{x_2, y_2, z_2} - \sum \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x}(x, y, z) f(x, y, z) \bigg|_{y_1, z_1}^{y_2, z_2} dx + \\ &+ \sum \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^2 \varphi}{\partial x\, \partial y}(x, y, z) f(x, y, z) \bigg|_{z_1}^{z_2} dx\, dy - \iiint_{\Delta} \frac{\partial^3 \varphi}{\partial x\, \partial y\, \partial z} f\, dx\, dy\, dz, \end{aligned} \]

which is called the integration by parts formula for triple integrals.

13. The generalized integration by parts formula for triple integrals.

Theorem 5.1.4. If the functions \(f\) and \(\varphi\) satisfy the following conditions: they are continuous on the parallelepiped \(\Delta\) together with the partial derivatives

(44)
\[ \begin{array}{llll} \dfrac{\partial^{3p-2} f}{\partial x^p \partial y^{p-1} \partial z^{p-1}}, & \dfrac{\partial^{3p-2} f}{\partial x^{p-1} \partial y^p \partial z^{p-1}}, & \dfrac{\partial^{3p-2} f}{\partial x^{p-1} \partial y^{p-1} \partial z^p}, & \\ \dfrac{\partial^{3p-1} f}{\partial x^{p-1} \partial y^p \partial z^p}, & \dfrac{\partial^{3p-1} f}{\partial x^p \partial y^{p-1} \partial z^p}, & \dfrac{\partial^{3p-1} f}{\partial x^p \partial y^p \partial z^{p-1}}, & \dfrac{\partial^{3p} f}{\partial x^p \partial y^p \partial z^p}, \\ \dfrac{\partial^{3p-2} \varphi}{\partial x^p \partial y^{p-1} \partial z^{p-1}}, & \dfrac{\partial^{3p-2} \varphi}{\partial x^{p-1} \partial y^p \partial z^{p-1}}, & \dfrac{\partial^{3p-2} \varphi}{\partial x^{p-1} \partial y^{p-1} \partial z^p}, & \\ \dfrac{\partial^{3p-1} \varphi}{\partial x^{p-1} \partial y^p \partial z^p}, & \dfrac{\partial^{3p-1} \varphi}{\partial x^p \partial y^{p-1} \partial z^p}, & \dfrac{\partial^{3p-1} \varphi}{\partial x^p \partial y^p \partial z^{p-1}}, & \dfrac{\partial^{3p} \varphi}{\partial x^p \partial y^p \partial z^p} \end{array} \]

for \(p = 1, 2, \ldots, n\), then we have formula (5.1.7), which is called the generalized integration by parts formula for triple integrals and which can also be written in the form

(45)
\[ \begin{aligned} &\iiint_{\Delta} \varphi \frac{\partial^{3n} f}{\partial x^n \partial y^n \partial z^n}\, dx\, dy\, dz = \sum_{r=0}^{n-1} (-1)^{n-r-1} \frac{\partial^{3(n-r-1)} \varphi}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}}(x, y, z) \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y, z) \bigg|_{x_1, y_1, z_1}^{x_2, y_2, z_2} - \\ &- \sum_{r=0}^{n-1} (-1)^{n-r-1} \sum \int_{x_1}^{x_2} \frac{\partial^{3(n-r)-2} \varphi}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}}(x, y, z) \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y, z) \bigg|_{y_1, z_1}^{y_2, z_2} dx + \\ &+ \sum_{r=0}^{n-1} (-1)^{n-r-1} \sum \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^{3(n-r)-1} \varphi}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z) \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y, z) \bigg|_{z_1}^{z_2} dx\, dy + \\ &+ (-1)^n \iiint_{\Delta} \frac{\partial^{3n} \varphi}{\partial x^n \partial y^n \partial z^n} f\, dx\, dy\, dz. \end{aligned} \]

14. Let us consider the parallelepiped \(D\) defined by the inequalities

\[ D:\quad x_0 \leq x \leq x_n;\ y_0 \leq y \leq y_n;\ z_0 \leq z \leq z_n \]

and the grid of nodes \(M_{i,j,k}\), \((i, j, k = 0, 1, \ldots, n)\), with coordinates \((x_i, y_j, z_k)\), where

(46)
\[ x_0 \lt x_1 \lt \ldots \lt x_{n-1} \lt x_n;\ y_0 \lt y_1 \lt \ldots \lt y_{n-1} \lt y_n;\ z_0 \lt z_1 \lt \ldots \lt z_{n-1} \lt z_n \]

We shall denote by \(D_{i,j,k}\) the parallelepiped defined by the inequalities \(D_{i,j,k}\):

\[ x_i \leq x \leq x_{i+1};\ y_j \leq y \leq y_{j+1};\ z_k \leq z \leq z_{k+1}, \]

where \(i, j, k = 0, 1, \ldots, n - 1\).

With each parallelepiped \(D_{i,j,k}\) we associate a function \(\varphi_{i,j,k}\) continuous on \(D_{i,j,k}\) together with its partial derivatives appearing in the sequence (44). We likewise associate with the parallelepiped \(D\) a function \(f\) continuous on \(D\) together with the partial derivatives appearing in the sequence (44). Then the generalized integration by parts formula for triple integrals (45) can be applied to each parallelepiped \(D_{i,j,k}\) and to the functions \(f\), \(\varphi_{i,j,k}\). Adding all these formulas term by term, we shall have the formula

(47)
\[ \sum_{i,j,k=0}^{n-1} \iiint_{D_{i,j,k}} \varphi_{i,j,k} \frac{\partial^{3n} f}{\partial x^n \partial y^n \partial z^n}\, dx\, dy\, dz = \mathscr{P}[f] + (-1)^n \sum_{i,j,k=0}^{n-1} \iiint_{D_{i,j,k}} \frac{\partial^{3n} \varphi_{i,j,k}}{\partial x^n \partial y^n \partial z^n} f\, dx\, dy\, dz \]

where we have denoted by \(\mathscr{P}[f]\) the functional resulting from the computation, that is

(48)
\[ \begin{aligned} &\mathscr{P}[f] = \sum_{i,j,k=0}^{n} \sum_{r=0}^{n-1} (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \\ &\qquad [(\varphi_{i,j,k} + \varphi_{i-1,j-1,k} - \varphi_{i,j-1,k} - \varphi_{i-1,j,k}) - (\varphi_{i,j,k-1} + \varphi_{i-1,j-1,k-1} - \varphi_{i,j-1,k-1} - \varphi_{i-1,j,k-1})]_{x_i, y_j, z_k} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z_k) + \\ &+ \sum_{i,j,k=0}^{n} \sum_{r=0}^{n-1} (-1)^{n-r} \int_{x_i}^{x_{i+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,j,k} + \varphi_{i,j-1,k-1} - \varphi_{i,j,k-1} - \varphi_{i,j-1,k}]_{x, y_j, z_k} \\ &\qquad\qquad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_j, z_k)\, dx + \\ &+ \sum_{i,j,k=0}^{n} \sum_{r=0}^{n-1} (-1)^{n-r} \int_{y_j}^{y_{j+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,j,k} + \varphi_{i-1,j,k-1} - \varphi_{i,j,k-1} - \varphi_{i-1,j,k}]_{x_i, y, z_k} \\ &\qquad\qquad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y, z_k)\, dy + \end{aligned} \]
\[ \begin{aligned} &+ \sum_{i,j,k=0}^{n} \sum_{r=0}^{n-1} (-1)^{n-r} \int_{z_k}^{z_{k+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,j,k} + \varphi_{i-1,j-1,k} - \varphi_{i,j-1,k} - \varphi_{i-1,j,k}]_{x_i, y_j, z} \\ &\qquad\qquad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z)\, dz + \\ &+ \sum_{i,j,k=0}^{n} \sum_{r=0}^{n-1} (-1)^{n-r} \int_{y_j}^{y_{j+1}} \int_{z_k}^{z_{k+1}} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{i,j,k} - \varphi_{i-1,j,k}]_{x_i, y, z} \\ &\qquad\qquad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y, z)\, dy\, dz + \\ &+ \sum_{i,j,k=0}^{n} \sum_{r=0}^{n-1} (-1)^{n-r} \int_{x_i}^{x_{i+1}} \int_{z_k}^{z_{k+1}} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,j,k} - \varphi_{i,j-1,k}]_{x, y_j, z} \\ &\qquad\qquad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_j, z)\, dx\, dz + \\ &+ \sum_{i,j,k=0}^{n} \sum_{r=0}^{n-1} (-1)^{n-r} \int_{x_i}^{x_{i+1}} \int_{y_j}^{y_{j+1}} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,j,k} - \varphi_{i,j,k-1}]_{x, y, z_k} \\ &\qquad\qquad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y, z_k)\, dx\, dy. \end{aligned} \]

In applying formula (48) one takes into account:

Convention (A). The function \(\varphi_{i,j,k}\) must be considered zero when at least one of the indices \(i, j, k\) is \(-1\) or \(n\).

15. In connection with formulas (47) and (48) we shall treat the following:

Boundary value problem. To determine the functions \(\varphi_{i,j,k}\), solutions of the partial differential equations

(49)
\[ \frac{\partial^{3n} \varphi_{i,j,k}}{\partial x^n \partial y^n \partial z^n} = 0, \qquad (i, j, k = 0, 1, \ldots, n) \]

such that the functional \(\mathscr{P}[f]\) depends only on the values of \(f\) at the nodes \(M_{i,j,k}\).

For this purpose we shall introduce the following boundary conditions:

(50)
\[ \begin{aligned} &\frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{i,j,k} - \varphi_{i-1,j,k}]_{x_i, y, z} = 0 \\ &\frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,j,k} - \varphi_{i,j-1,k}]_{x, y_j, z} = 0 \\ &\frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,j,k} - \varphi_{i,j,k-1}]_{x, y, z_k} = 0 \end{aligned} \]

for \(i, j, k = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Next

(51)
\[ \begin{aligned} &\frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,j,k} + \varphi_{i,j-1,k-1} - \varphi_{i,j,k-1} - \varphi_{i,j-1,k}]_{x, y_j, z_k} = 0 \\ &\frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,j,k} + \varphi_{i-1,j,k-1} - \varphi_{i,j,k-1} - \varphi_{i-1,j,k}]_{x_i, y, z_k} = 0 \\ &\frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,j,k} + \varphi_{i-1,j-1,k} - \varphi_{i,j-1,k} - \varphi_{i-1,j,k}]_{x_i, y_j, z} = 0 \end{aligned} \]

for \(i, j, k = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Finally

(52)
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \Bigl[(\varphi_{i,j,k} + \varphi_{i-1,j-1,k} - \varphi_{i,j-1,k} - \varphi_{i-1,j,k}) - (\varphi_{i,j,k-1} + \varphi_{i-1,j-1,k-1} - \varphi_{i,j-1,k-1} - \varphi_{i-1,j,k-1})\Bigr]_{x_i, y_j, z_k} = \left\{\begin{array}{cl} C_{i,j,k} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{array}\right. \]

for \(i, j, k = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

The constants \(C_{i,j,k}\) will be determined up to a factor, which is determined by a new condition, namely

(53)
\[ \mathscr{P}[f] = 1, \quad \text{for } f(x, y, z) = x^n y^n z^n. \]

When one of the indices in \(\varphi_{i,j,k}\) is replaced by \(-1\) or \(n\), convention (A) must be taken into account.

16. The solution of this problem is

(54)
\[ \begin{aligned} \varphi_{i,j,k}(x, y, z) = {} & \left[C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0,0} \frac{(x - x_i)^{n-1}}{(n-1)!}\right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{0,j,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,j,0} \frac{(x - x_i)^{n-1}}{(n-1)!}\right] \frac{(y - y_j)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{0,0,k} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0,k} \frac{(x - x_i)^{n-1}}{(n-1)!}\right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_k)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{0,j,k} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,j,k} \frac{(x - x_i)^{n-1}}{(n-1)!}\right] \frac{(y - y_j)^{n-1}}{(n-1)!} \frac{(z - z_k)^{n-1}}{(n-1)!}. \end{aligned} \]

It is proved that the constants \(C_{i,j,k}\) are given by the following formulas:

(55)
\[ C_{i,j,k} = {} (-1)^{i+j+k} \frac{V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)}{V(x_0, x_1, \ldots, x_n)} \cdot \frac{V(y_0, \ldots, y_{j-1}, y_{j+1}, \ldots, y_n)}{V(y_0, y_1, \ldots, y_n)} \cdot \frac{V(z_0, \ldots, z_{k-1}, z_{k+1}, \ldots, z_n)}{V(z_0, z_1, \ldots, z_n)}. \]

The expression of \(\mathscr{P}[f]\), when the solution of the boundary value problem is put in place of the functions \(\varphi_{i,j,k}\), is

(56)
\[ \mathscr{P}[f] = \sum_{i,j,k=0}^{n} \lambda_i \mu_j \nu_k f(x_i, y_j, z_k), \]

where

(57)
\[ \begin{aligned} \lambda_i &= (-1)^{n+i} \frac{V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)}{V(x_0, x_1, \ldots, x_n)}, \\ \mu_j &= (-1)^{n+j} \frac{V(y_0, \ldots, y_{j-1}, y_{j+1}, \ldots, y_n)}{V(y_0, y_1, \ldots, y_n)}, \\ \nu_k &= (-1)^{n+k} \frac{V(z_0, \ldots, z_{k-1}, z_{k+1}, \ldots, z_n)}{V(z_0, z_1, \ldots, z_n)}. \end{aligned} \]

17. Definition 5.8.1. The expression of \(\mathscr{P}[f]\) given by formula (56) is called the divided difference of order \(n\) of the function \(f\) on the grid of nodes \(M_{i,j,k}\), \((i, j, k = 0, 1, \ldots, n)\), and is denoted by:

(58)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f\right]. \]

We have several theorems:

Theorem 5.8.1. The divided difference of order \(n\) of the function \(f\) on the grid of nodes \(M_{i,j,k}\), \((i, j, k = 0, 1, \ldots, n)\), is given by the formula

(59)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f\right] = \sum_{i,j,k=0}^{n} \lambda_i \mu_j \nu_k f(x_i, y_j, z_k). \]

Theorem 5.8.2. If the function \(f\) is continuous on the parallelepiped \(D\) together with its partial derivatives (44), for \(p = 1, 2, \ldots, n\), then the divided difference of order \(n\) of the function \(f\) on the grid \(M_{i,j,k}\), \((i, j, k = 0, 1, \ldots, n)\), has an integral representation, given by the formula:

(60)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f\right] = \iiint_D \varphi \frac{\partial^{3n} f}{\partial x^n \partial y^n \partial z^n}\, dx\, dy\, dz, \]

where the function \(\varphi\) is the solution of the boundary value problem treated above.

Theorem 5.8.3. The function \(\varphi_{i,j,k}\) is the product of three functions, one of \(x\), another of \(y\) and another of \(z\).

We have

(61)
\[ \begin{aligned} &\varphi_{i,j,k}(x, y, z) = (-1)^n \left[\lambda_0 \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + \lambda_i \frac{(x - x_i)^{n-1}}{(n-1)!}\right] \cdot \\ &\cdot \left[\mu_0 \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + \mu_j \frac{(y - y_j)^{n-1}}{(n-1)!}\right] \cdot \left[\nu_0 \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + \nu_k \frac{(z - z_k)^{n-1}}{(n-1)!}\right]. \end{aligned} \]

18. If for the functions \(u \in C^n[x_0, x_n]\), \(v \in C^n[y_0, y_n]\), \(w \in C^n[z_0, z_n]\) and their divided differences on the nodes \(x_0, x_1, \ldots, x_n\), \(y_0, y_1, \ldots, y_n\), \(z_0, z_1, \ldots, z_n\) we have the integral representations

(62)
\[ \begin{aligned} {[}x_0, x_1, \ldots, x_n ; u] &= \int_{x_0}^{x_n} \psi(x)\, u^{(n)}(x)\, dx \\ {[}y_0, y_1, \ldots, y_n ; v] &= \int_{y_0}^{y_n} \theta(y)\, v^{(n)}(y)\, dy \\ {[}z_0, z_1, \ldots, z_n ; w] &= \int_{z_0}^{z_n} \chi(z)\, w^{(n)}(z)\, dz, \end{aligned} \]

formula (61) shows that

(63)
\[ \varphi_{i,j,k}(x, y, z) = \psi_i(x)\, \theta_j(y)\, \chi_k(z). \]

Theorem 5.8.4. The function \(\varphi\) in the integral representation (60) is the product of the spline functions \(\psi\), \(\theta\), \(\chi\) in the integral representations (62), that is, we have

(64)
\[ \varphi(x, y, z) = \psi(x)\, \theta(y)\, \chi(z). \]

19. Theorem 5.8.5. The function \(\varphi\) in the integral representation (60) of the divided difference of order \(n\) of the function \(f\) of three variables is positive on the open parallelepiped \(D\) and vanishes on the boundary of this parallelepiped.

20. T. Popoviciu defined the divided difference of order \(n\) of a function of two variables on the grid of nodes \(M_{i,k}(x_i, y_k)\), \((i, k = 0, 1, \ldots, n)\), by the recurrence formula, which he gave a priori,

(65)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right] = [x_0, x_1, \ldots, x_n ; [y_0, y_1, \ldots, y_n ; f(x, y)]]. \]

T. Popoviciu was not concerned with the integral representation of the divided difference (65).

Formula (65) also follows from our formulas (32), (33), obtained with the boundary value problem treated in Chapter IV and the hypotheses of that chapter. In addition, the integral representation of the divided difference (65) has also been obtained, by formula (36).

From the boundary value problem treated in Chapter V there resulted the definition of the divided difference of a function \(f\) of three variables on the grid of nodes \(M_{i,j,k}(x_i, y_j, z_k)\), \((i, j, k = 0, 1, \ldots, n)\), by formula (59), and its integral representation by formula (60), under the hypotheses of Chapter V imposed on the function \(f\).

From formula (59) there follows the recurrence formula

(66)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f\right] = \left[x_0, x_1, \ldots, x_n ; \left[\begin{array}{l} y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f(x, y, z)\right]\right]. \]

Formula (66) is important; it gives us an idea of how one could define the divided difference of a function \(f\) of \(p\) variables on a grid of nodes \(M_{i_1, i_2, \ldots, i_p}\), and of how its integral representation can be obtained, by making suitable hypotheses on the function \(f\), different from those made in Chapters IV and V, in order to treat the corresponding boundary value problems.

21. Let us consider a function \(f\) of the variables \(x_1, x_2, \ldots, x_p\), and let us take on the axis \(Ox_h\), which corresponds to the variable \(x_h\), the nodes \(x_h^{(0)}, x_h^{(1)}, \ldots, x_h^{(n)}\) such that

\[ x_h^{(0)} \lt x_h^{(1)} \lt \ldots \lt x_h^{(n)}. \]

Letting \(h\) take the values \(1, 2, \ldots, p\), we obtain a grid of nodes \(M_{i_1, i_2, \ldots, i_p}\) with coordinates \((x_1^{(i_1)}, x_2^{(i_2)}, \ldots, x_p^{(i_p)})\), \(i_1, i_2, \ldots, i_p\) taking values in the set of numbers \(0, 1, \ldots, n\).

Then we have the following definition:

Definition 6.1.1. The divided difference of order \(n\) of the function \(f\) of the variables \(x_1, x_2, \ldots, x_p\) on the grid of nodes \(M_{i_1, i_2, \ldots, i_p}\), which we denote by

(67)
\[ \left[\begin{array}{l} x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} \\ x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ \ldots\ldots\ldots\ldots\ldots\ldots \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right], \]

is defined by the formula

(68)
\[ \left[\begin{array}{l} x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} \\ x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ \ldots\ldots\ldots\ldots\ldots\ldots \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] = \sum_{i_1, \ldots, i_p = 0}^{n} \lambda_1^{(i_1)} \lambda_2^{(i_2)} \ldots \lambda_p^{(i_p)} f(x_1^{(i_1)}, x_2^{(i_2)}, \ldots, x_p^{(i_p)}), \]

where

(69)
\[ \lambda_h^{(i)} = (-1)^{n+i} \frac{V(x_h^{(0)}, \ldots, x_h^{(i-1)}, x_h^{(i+1)}, \ldots, x_h^{(n)})}{V(x_h^{(0)}, x_h^{(1)}, \ldots, x_h^{(n)})} \]

for \(h = 1, 2, \ldots, p\) and \(i = 0, 1, \ldots, n\).

Theorem 6.1.2. The divided difference of order \(n\) of the function \(f\) of \(p\) variables on the grid of nodes \(M_{i_1, i_2, \ldots, i_p}\) satisfies the recurrence formula

(70)
\[ \left[\begin{array}{l} x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} \\ x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ \ldots\ldots\ldots\ldots\ldots\ldots \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] = \left[x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} ; \left[\begin{array}{l} x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ x_3^{(0)}, x_3^{(1)}, \ldots, x_3^{(n)} \\ \ldots\ldots\ldots\ldots\ldots\ldots \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right]\right]. \]

22. The integral representation of the divided difference (67) can be obtained when the function \(f\) satisfies the following hypotheses, which we denote by \((H_p)\), \((H_{p-1})\), \(\ldots\), \((H_1)\).

We consider the domain \(D\) defined by the following inequalities:

\[ D:\ x_1^{(0)} \leq x_1 \leq x_1^{(n)};\ x_2^{(0)} \leq x_2 \leq x_2^{(n)};\ \ldots;\ x_p^{(0)} \leq x_p \leq x_p^{(n)}. \]

Hypothesis \((H_p)\) states that all the partial derivatives

(71)
\[ \frac{\partial^h f}{\partial x_p^h} \]

exist and are continuous in \(D\) for \(h = 0, 1, \ldots, n\).

Hypothesis \((H_{p-1})\) states that all the partial derivatives

(72)
\[ \frac{\partial^{h+n} f}{\partial x_{p-1}^h \partial x_p^n} \]

exist and are continuous in \(D\), for \(h = 0, 1, \ldots, n\).

And so on.

The last hypothesis \((H_1)\) states that all the partial derivatives

(73)
\[ \frac{\partial^{h+(p-1)n} f}{\partial x_1^h \partial x_2^n \ldots \partial x_p^n} \]

exist and are continuous in \(D\) for \(h = 0, 1, \ldots, n\).

This being so, let us consider, in general, the integral representation of the divided difference of order \(n\) of the function \(g\) of the variable \(x_h\) on the nodes \(x_h^{(0)}, x_h^{(1)}, \ldots, x_h^{(n)}\), which, when \(g \in C^n[x_h^{(0)}, x_h^{(n)}]\), is given by the formula

(74)
\[ [x_h^{(0)}, x_h^{(1)}, \ldots, x_h^{(n)} ; g] = \int_{x_h^{(0)}}^{x_h^{(n)}} \varphi_h(s)\, g^{(n)}(s)\, ds, \]

where \(\varphi_h\) is the spline function studied in Chapter I, which is positive on the interval \((x_h^{(0)}, x_h^{(n)})\).

23. We have the following:

Theorem 6.2.1. If the function \(f\) satisfies the hypotheses \((H_p)\), \((H_{p-1})\), \(\ldots\), \((H_1)\) on the domain \(D\), then we have the integral representation:

(75)
\[ \left[\begin{array}{l} x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} \\ x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ \ldots\ldots\ldots\ldots\ldots\ldots \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] = \iint \ldots \int_D \varphi(s_1, s_2, \ldots, s_p) \frac{\partial^{pn} f}{\partial s_1^n \partial s_2^n \ldots \partial s_p^n}\, ds_1\, ds_2 \ldots ds_p \]

where the function

(76)
\[ \varphi(s_1, s_2, \ldots, s_p) = \varphi_1(s_1)\, \varphi_2(s_2) \ldots \varphi_p(s_p) \]

is positive on the open domain \(D\) and vanishes on its boundary.

24. Several Romanian mathematicians have published books on Numerical Analysis, among whom I mention Acad. Gh. Marinescu [25], Acad. T. Popoviciu [32], D. V. Ionescu [8], C. M. Bucur [1], I. Cuculescu [2], Al. I. Șchiop [37], [38] and Mărgărit Pavelescu [29]; these books have been very well received among mathematicians.

I hope that this book, Divided Differences, which aims to introduce a systematic method of research into Numerical Analysis, the method of the function \(\varphi\), will also contribute to a still greater development of research in this field.

↑ Contents

Română

Chapter I

The method of the function \(\varphi\) applied to a function of one variable, and divided differences in the case of simple nodes

D. V. Ionescu, Diferențe divizate [Divided Differences], Editura Academiei Republicii Socialiste România, Bucharest, 1978, pp. 31–46

§ 1.1. The first boundary value problem

In this section we shall study a boundary value problem which will lead to the definition of the divided difference of order \(n\) of a function \(f\) on the simple nodes \(x_0, x_1, \ldots, x_n\), where \(x_0 \lt x_1 \lt \ldots \lt x_n\), and to its integral representation when \(f \in C^n[x_0, x_n]\).

1.1.1. Let us consider the simple nodes \(x_0, x_1, \ldots, x_n\), where

(1.1.1)
\[ x_0 \lt x_1 \lt \ldots \lt x_n \]

and a function \(f \in C^n[x_0, x_n]\).

To the intervals \([x_0, x_1]\), \([x_1, x_2]\), \(\ldots\), \([x_{n-1}, x_n]\) let us attach the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_n\) of degree at most \(n - 1\), which means that

(1.1.2)
\[ \varphi_1^{(n)} = 0, \quad \varphi_2^{(n)} = 0, \quad \ldots, \quad \varphi_n^{(n)} = 0 \]

and let us compute the integrals

(1.1.3)
\[ \int_{x_0}^{x_1} \varphi_1 f^{(n)}\, ds, \int_{x_1}^{x_2} \varphi_2 f^{(n)}\, ds, \ldots, \int_{x_{n-1}}^{x_n} \varphi_n f^{(n)}\, ds. \]

Applying the generalized integration by parts formula to each integral, we shall have

(1.1.4)
\[ \begin{aligned} \int_{x_0}^{x_1} \varphi_1 f^{(n)}\, ds &= \left(\varphi_1 f^{(n-1)} - \varphi_1' f^{(n-2)} + \ldots + (-1)^{n-1} \varphi_1^{(n-1)} f\right)_{x_0}^{x_1}, \\ \int_{x_1}^{x_2} \varphi_2 f^{(n)}\, ds &= \left(\varphi_2 f^{(n-1)} - \varphi_2' f^{(n-2)} + \ldots + (-1)^{n-1} \varphi_2^{(n-1)} f\right)_{x_1}^{x_2}, \\ \ldots\ldots\ldots\ldots\ldots\ldots &\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ \int_{x_{n-1}}^{x_n} \varphi_n f^{(n)}\, ds &= \left(\varphi_n f^{(n-1)} - \varphi_n' f^{(n-2)} + \ldots + (-1)^{n-1} \varphi_n^{(n-1)} f\right)_{x_{n-1}}^{x_n}. \end{aligned} \]

Adding formulas (1.1.4) term by term, we shall obtain a formula whose right-hand side, which we denote by \(\mathscr{P}[f]\), depends on the values of \(f, f', \ldots, f^{(n-1)}\) at the nodes \(x_0, x_1, \ldots, x_n\). We shall thus have the formula

(1.1.5)
\[ \mathscr{P}[f] = \int_{x_0}^{x_n} \varphi(s) f^{(n)}(s)\, ds, \]

where the function \(\varphi\) coincides with the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_n\) on the intervals \([x_0, x_1]\), \([x_1, x_2]\), \(\ldots\), \([x_{n-1}, x_n]\).

In connection with formula (1.1.5) we pose the following

Boundary value problem. Determine the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_n\), solutions of the differential equations (1.1.2), such that \(\mathscr{P}[f]\) involves only the values of \(f\) at the nodes \(x_0, x_1, \ldots, x_n\), and such that \(\mathscr{P}[f] = 1\) for \(f(x) = x^n\).

The polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_n\) must therefore satisfy the boundary conditions

(1.1.6)
\[ \begin{array}{llll} \varphi_1(x_0) = 0, & \varphi_1'(x_0) = 0, \ldots, & \varphi_1^{(n-2)}(x_0) & = 0 \\ \varphi_2(x_1) = \varphi_1(x_1), & \varphi_2'(x_1) = \varphi_1'(x_1), \ldots, & \varphi_2^{(n-2)}(x_1) & = \varphi_1^{(n-2)}(x_1) \\ \ldots\ldots\ldots\ldots\ldots\ldots & \ldots\ldots\ldots\ldots\ldots\ldots & \ldots\ldots\ldots\ldots & \ldots\ldots\ldots\ldots \\ \varphi_n(x_{n-1}) = \varphi_{n-1}(x_{n-1}), & \varphi_n'(x_{n-1}) = \varphi_{n-1}'(x_{n-1}), \ldots, & \varphi_n^{(n-2)}(x_{n-1}) & = \varphi_{n-1}^{(n-2)}(x_{n-1}) \\ \varphi_n(x_n) = 0, & \varphi_n'(x_n) = 0, \ldots, & \varphi_n^{(n-2)}(x_n) & = 0 \end{array} \]

and, in addition, we must have

(1.1.7)
\[ \mathscr{P}[f] = 1 \]

for \(f(x) = x^n\).

We shall prove that the boundary value problem thus posed has a unique solution. Then, replacing the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_n\) in formula (1.1.4) by the solution of this problem and adding, we obtain a formula of the form (1.1.5), which is very important and which is the subject of this section.

1.1.2. It is evident that the polynomials

(1.1.8)
\[ \begin{aligned} \varphi_1(s) &= \lambda_0 \frac{(s - x_0)^{n-1}}{(n-1)!} \\ \varphi_2(s) &= \lambda_0 \frac{(s - x_0)^{n-1}}{(n-1)!} + \lambda_1 \frac{(s - x_1)^{n-1}}{(n-1)!} \\ \ldots\ldots\ldots &\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ \varphi_n(s) &= \lambda_0 \frac{(s - x_0)^{n-1}}{(n-1)!} + \lambda_1 \frac{(s - x_1)^{n-1}}{(n-1)!} + \ldots + \lambda_{n-1} \frac{(s - x_{n-1})^{n-1}}{(n-1)!} \end{aligned} \]

satisfy the differential equations (1.1.2) and the boundary conditions (1.1.6) relative to the nodes \(x_0, x_1, \ldots, x_{n-1}\), whatever \(\lambda_0, \lambda_1, \ldots, \lambda_{n-1}\) may be. The constants \(\lambda_0, \lambda_1, \ldots, \lambda_{n-1}\) will be determined so that the boundary conditions relative to the node \(x_n\) are satisfied as well.

We shall have the system of equations

(1.1.9)
\[ \begin{array}{llll} \lambda_0(x_n - x_0) & + \lambda_1(x_n - x_1) & + \ldots + \lambda_{n-1}(x_n - x_{n-1}) & = 0 \\ \lambda_0(x_n - x_0)^2 & + \lambda_1(x_n - x_1)^2 & + \ldots + \lambda_{n-1}(x_n - x_{n-1})^2 & = 0 \\ \ldots\ldots\ldots\ldots & \ldots\ldots\ldots\ldots & \ldots\ldots\ldots\ldots\ldots\ldots & \ldots \\ \lambda_0(x_n - x_0)^{n-1} & + \lambda_1(x_n - x_1)^{n-1} & + \ldots + \lambda_{n-1}(x_n - x_{n-1})^{n-1} & = 0 \end{array} \]

which determines \(\lambda_0, \lambda_1, \ldots, \lambda_{n-1}\) up to a factor.

Introducing a new constant \(\lambda_n\) by the equation

(1.1.10)
\[ \lambda_0 + \lambda_1 + \ldots + \lambda_n = 0, \]

the system of equations (1.1.9) and equation (1.1.10) reduce to the system

(1.1.11)
\[ \begin{array}{lll} \lambda_0 + \lambda_1 & + \ldots + \lambda_n & = 0 \\ \lambda_0 x_0 + \lambda_1 x_1 & + \ldots + \lambda_n x_n & = 0 \\ \ldots\ldots\ldots\ldots\ldots & \ldots\ldots\ldots\ldots & \ldots \\ \lambda_0 x_0^{n-1} + \lambda_1 x_1^{n-1} & + \ldots + \lambda_n x_n^{n-1} & = 0 \end{array} \]

which determines \(\lambda_0, \lambda_1, \ldots, \lambda_n\) up to a factor.

The solution of system (1.1.11) is given by the formulas

(1.1.12)
\[ \frac{\lambda_0}{V(x_1, x_2, \ldots, x_n)} = \frac{\lambda_1}{-V(x_0, x_2, \ldots, x_n)} = \ldots = \frac{\lambda_n}{(-1)^n V(x_0, x_1, \ldots, x_{n-1})} = H, \]

where \(V(x_0, x_1, \ldots, x_n)\) is the Vandermonde determinant and where \(H\) is a new constant which will be determined presently.

The polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_n\) are thus determined by formulas (1.1.8) up to a factor \(H\), and therefore we can use them.

We shall first have

(1.1.13)
\[ \begin{aligned} \varphi_1^{(n-1)}(s) &= \lambda_0 \\ \varphi_2^{(n-1)}(s) &= \lambda_0 + \lambda_1 \\ \ldots\ldots\ldots &\ldots\ldots\ldots \\ \varphi_n^{(n-1)}(s) &= \lambda_0 + \lambda_1 + \ldots + \lambda_{n-1}. \end{aligned} \]

Replacing the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_n\) in formulas (1.1.4) by the solution of the boundary value problem and adding, we shall have

\[ \begin{aligned} \mathscr{P}[f] = (-1)^{n-1}\bigl[&-\varphi_1^{(n-1)}(x_0) f(x_0) + [\varphi_1^{(n-1)}(x_1) - \varphi_2^{(n-1)}(x_1)] f(x_1) + \ldots \\ &\ldots + [\varphi_{n-1}^{(n-1)}(x_{n-1}) - \varphi_n^{(n-1)}(x_{n-1})] f(x_{n-1}) + \varphi_n^{(n-1)}(x_n) f(x_n)\bigr] \end{aligned} \]

that is,

(1.1.14)
\[ \mathscr{P}[f] = (-1)^n[\lambda_0 f(x_0) + \lambda_1 f(x_1) + \ldots + \lambda_n f(x_n)]. \]

Taking formulas (1.1.12) into account, we can write

\[ \mathscr{P}[f] = (-1)^n H \{f(x_0) V(x_1, x_2, \ldots, x_n) - f(x_1) V(x_0, x_2, \ldots, x_n) + \ldots + (-1)^n f(x_n) V(x_0, x_1, \ldots, x_{n-1})\} \]

that is,

(1.1.15)
\[ \mathscr{P}[f] = H \begin{vmatrix} 1 & x_0 & \ldots & x_0^{n-1} & f(x_0) \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & x_n & \ldots & x_n^{n-1} & f(x_n) \end{vmatrix} \]

Now let us determine the constant \(H\). Replacing the function \(f(x)\) in formula (1.1.15) by \(x^n\) and taking condition (1.1.7) into account, we shall have \(H \cdot V(x_0, x_1, \ldots, x_n) = 1\), and therefore

(1.1.16)
\[ H = \frac{1}{V(x_0, x_1, \ldots, x_n)}. \]

The constant \(H\) having been determined, formula (1.1.15) becomes

(1.1.17)
\[ \mathscr{P}[f] = \frac{1}{V(x_0, x_1, \ldots, x_n)} \begin{vmatrix} 1 & x_0 & \ldots & x_0^{n-1} & f(x_0) \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & x_n & \ldots & x_n^{n-1} & f(x_n) \end{vmatrix} \]

Definition 1.1.1. We shall say that the functional \(\mathscr{P}[f]\) given by formula (1.1.17) and obtained by means of the solution of the boundary value problem posed in subsection 1.1.1 is the divided difference of order \(n\) of the function \(f\) on the nodes \(x_0, x_1, \ldots, x_n\), and we shall denote it by

(1.1.18)
\[ [x_0, x_1, \ldots, x_n; f]. \]

Formula (1.1.5), in which the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_n\) are replaced by the solution of the boundary value problem posed in subsection 1.1.1, can be written, by means of formula (1.1.17) and notation (1.1.18), in the form

(1.1.19)
\[ [x_0, x_1, \ldots, x_n; f] = \int_{x_0}^{x_n} \varphi f^{(n)}\, ds \]

and we have thus arrived at the following fundamental theorem:

Theorem 1.1.1. When \(f \in C^n[x_0, x_n]\), the divided difference of order \(n\) of the function on the nodes \(x_0, x_1, \ldots, x_n\) can be represented by a definite integral, by formula (1.1.19).

Taking formula (1.1.14) into account, formula (1.1.19) can also be written in the form

(1.1.20)
\[ \lambda_0 f(x_0) + \lambda_1 f(x_1) + \ldots + \lambda_n f(x_n) = (-1)^n \int_{x_0}^{x_n} \varphi f^{(n)}\, ds, \]

where the coefficients \(\lambda_i\) are given by formulas (1.1.12) and (1.1.16), that is,

(1.1.21)
\[ \lambda_i = (-1)^i \frac{V(x_0, x_1, \ldots, x_{i-1}, x_{i+1}, \ldots x_n)}{V(x_0, x_1, \ldots, x_n)}, \quad \text{for } i = 0, 1, \ldots, n. \]

One can also write

(1.1.22)
\[ \lambda_i = \frac{(-1)^n}{(x_i - x_0) \ldots (x_i - x_{i-1})(x_i - x_{i+1}) \ldots (x_i - x_n)} \quad \text{for } i = 0, 1, \ldots, n \]

and there follows the identity

(1.1.23)
\[ \frac{(-1)^n}{(x - x_0)(x - x_1) \ldots (x - x_n)} = \frac{\lambda_0}{x - x_0} + \frac{\lambda_1}{x - x_1} + \ldots + \frac{\lambda_n}{x - x_n} \]

which gives a practical means of computing the coefficients of formula (1.1.20).

Formulas (1.1.19), (1.1.20) and (1.1.23) show that we have the identity

(1.1.24)
\[ \left[x_0, x_1, \ldots, x_n; \frac{1}{x - s}\right] = \frac{1}{(x - x_0)(x - x_1) \ldots (x - x_n)}. \]

Introducing the notation of spline functions

(1.1.25)
\[ (s - x_i)_+^m = \left\{\begin{array}{ll} (s - x_i)^m & \text{if } s \geq x_i \\ 0 & \text{if } s \leq x_i \end{array}\right. \]

we can write the function \(\varphi\) in the form

(1.1.26)
\[ \varphi(s) = \lambda_0 \frac{(s - x_0)_+^{n-1}}{(n-1)!} + \lambda_1 \frac{(s - x_1)_+^{n-1}}{(n-1)!} + \ldots + \lambda_n \frac{(s - x_n)_+^{n-1}}{(n-1)!} \]

because, assuming successively that \(s \in [x_0, x_1]\), \(s \in [x_1, x_2]\), \(\ldots\), \(s \in [x_{n-1}, x_n]\), we recover formulas (1.1.8).

Following I. J. Schoenberg — [35] — the function given by formula (1.1.26) is called the spline function of order \(n-1\) defined on the interval \([x_0, x_n]\) and on the nodes \(x_0, x_1, \ldots, x_n\).

Thus the boundary value problem posed in subsection 1.1.1 can serve as an introduction to the theory of spline functions.

It may also be observed that formula (1.1.17) shows that Definition 1.1.1, which we have given for the divided difference of order \(n\) of the function \(f\) on the nodes \(x_0, x_1, \ldots, x_n\), agrees with the classical definition.

1.1.3. Theorem 1.1.1 was first given by G. Peano [30], and we also find it in the works of several mathematicians, for example in the works of L. Tchakaloff [46] and A. Sard [34]. In our method of finding formula (1.1.19), the boundary value problem posed in subsection 1.1.1 has led us in a remarkable way, at the same time, to Definition 1.1.1 of the divided difference of order \(n\) of the function \(f\) on the nodes \(x_0, x_1, \ldots, x_n\), and to its representation by a definite integral, by formula (1.1.19), when \(f \in C^n[x_0, x_n]\).

Professor P. J. Laurent [24] communicated to me, in a conversation, another proof of formula (1.1.19), which starts from the classical definition of the divided difference of a function and uses Taylor's formula and the symbol \((s - x_i)_+^m\) introduced by formula (1.1.25).

Assuming that \(x_0 \lt x_1 \lt \ldots \lt x_n\) and that \(f \in C^n[x_0, x_n]\), we can apply Taylor's formula and obtain

\[ f(x_i) = f(x_n) + \frac{x_i - x_n}{1!} f'(x_n) + \ldots + \frac{(x_i - x_n)^{n-1}}{(n-1)!} f^{(n-1)}(x_n) + \int_{x_n}^{x_i} \frac{(x_i - s)^{n-1}}{(n-1)!} f^{(n)}(s)\, ds \quad \text{for } i = 0, 1, \ldots, n. \]

It follows that we can write the divided difference \([x_0, x_1, \ldots, x_n; f]\), according to its classical definition, in the form

\[ [x_0, x_1, \ldots, x_n; f] = \frac{1}{(n-1)!\, V(x_0, x_1, \ldots, x_n)} \begin{vmatrix} 1 & x_0 & \ldots & x_0^{n-1} & \int_{x_n}^{x_0} (x_0 - s)^{n-1} f^{(n)}(s)\, ds \\ 1 & x_1 & \ldots & x_1^{n-1} & \int_{x_n}^{x_1} (x_1 - s)^{n-1} f^{(n)}(s)\, ds \\ \ldots & \ldots & \ldots & \ldots & \ldots\ldots\ldots\ldots\ldots\ldots \\ 1 & x_n & \ldots & x_n^{n-1} & \int_{x_n}^{x_n} (x_n - s)^{n-1} f^{(n)}(s)\, ds \end{vmatrix} \]

that is,

\[ [x_0, x_1, \ldots, x_n; f] = \frac{(-1)^n}{(n-1)!\, V(x_0, x_1, \ldots, x_n)} \begin{vmatrix} 1 & x_0 & \ldots & x_0^{n-1} & \int_{x_0}^{x_n} (s - x_0)^{n-1} f^{(n)}(s)\, ds \\ 1 & x_1 & \ldots & x_1^{n-1} & \int_{x_1}^{x_n} (s - x_1)^{n-1} f^{(n)}(s)\, ds \\ \ldots & \ldots & \ldots & \ldots & \ldots\ldots\ldots\ldots\ldots\ldots \\ 1 & x_n & \ldots & x_n^{n-1} & \int_{x_n}^{x_n} (s - x_n)^{n-1} f^{(n)}(s)\, ds \end{vmatrix} \]

By means of the notation \((s - x_i)_+^{n-1}\), the preceding formula becomes

\[ [x_0, x_1, \ldots, x_n; f] = \frac{(-1)^n}{(n-1)!\, V(x_0, x_1, \ldots, x_n)} \begin{vmatrix} 1 & x_0 & \ldots & x_0^{n-1} & \int_{x_0}^{x_n} (s - x_0)_+^{n-1} f^{(n)}(s)\, ds \\ 1 & x_1 & \ldots & x_1^{n-1} & \int_{x_1}^{x_n} (s - x_1)_+^{n-1} f^{(n)}(s)\, ds \\ \ldots & \ldots & \ldots & \ldots & \ldots\ldots\ldots\ldots\ldots\ldots \\ 1 & x_n & \ldots & x_n^{n-1} & \int_{x_{n-1}}^{x_n} (s - x_n)_+^{n-1} f^{(n)}(s)\, ds \end{vmatrix} \]

or again

\[ [x_0, x_1, \ldots, x_n; f] = \frac{(-1)^n}{(n-1)!\, V(x_0, x_1, \ldots, x_n)} \int_{x_0}^{x_n} \begin{vmatrix} 1 & x_0 & \ldots & x_0^{n-1} & (s - x_0)_+^{n-1} \\ 1 & x_1 & \ldots & x_1^{n-1} & (s - x_1)_+^{n-1} \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & x_n & \ldots & x_n^{n-1} & (s - x_n)_+^{n-1} \end{vmatrix} f^{(n)}(s)\, ds \]

Expanding the determinant on the right-hand side along the elements of the last column, we obtain formula (1.1.19), where the function \(\varphi(s)\) is given by formula (1.1.26).

1.1.4. The boundary conditions of the problem posed in subsection 1.1.1 make it possible to study the function \(\varphi\) in formula (1.1.19), whose expression is given by formula (1.1.26). For this purpose we shall give several theorems:

Theorem 1.1.2. In formula (1.1.20) we have the inequalities

(1.1.27)
\[ (-1)^k(\lambda_0 + \lambda_1 + \ldots + \lambda_k) \gt 0, \quad \text{for } k = 0, 1, \ldots, n - 1. \]

This theorem is evident for \(k = 0\) and \(k = n-1\), and therefore for \(n = 2\). Indeed, by formula (1.1.21), for \(k = 0\) we have \(\lambda_0 \gt 0\), and for \(k = n-1\) we have \((-1)^{n-1}(\lambda_0 + \lambda_1 + \ldots + \lambda_{n-1}) = (-1)^n \lambda_n \gt 0\).

It remains to prove the theorem for \(k = 1, 2, \ldots, n-2\) and \(n \gt 2\).

To this end let us consider the interpolation polynomial \(h_k(x)\) defined by the conditions

(1.1.28)
\[ \begin{aligned} &h_k(x_0) = 1, \quad h_k(x_1) = 1, \quad \ldots, \quad h_k(x_k) = 1, \\ &h_k(x_{k+1}) = 0, \quad \ldots, \quad h_k(x_{n-1}) = 0. \end{aligned} \]

It is evident that the polynomial \(h_k(x)\) is of degree at most \(n-1\) and is not a constant, because for \(k = 1, 2, \ldots, n-2\) we have, by conditions (1.1.28), \(h_k(x_0) = 1\), whereas \(h_k(x_{n-1}) = 0\).

Applying Rolle's theorem to the polynomial \(h_k(x)\) and to the intervals \([x_0, x_1]\), \([x_1, x_2]\), \(\ldots\), \([x_{k-1}, x_k]\), \([x_{k+1}, x_{k+2}]\), \(\ldots\), \([x_{n-2}, x_{n-1}]\), we deduce that the derivative \(h_k'(x)\) has \(n-2\) distinct roots, \(k\) to the left of \(x_k\) and \(n-2-k\) to the right of \(x_k\). It follows that the polynomial \(h_k(x)\) has degree \(n-1\).

Indeed, let us suppose that the degree of \(h_k(x)\) were less than \(n-1\). Since the derivative of \(h_k(x)\) vanishes at \(n-2\) distinct points, it would be identically zero, and therefore the polynomial \(h_k(x)\) would be a constant, which is impossible. Hence the degree of the polynomial \(h_k(x)\) is \(n-1\).

It follows that the polynomial \(h_k(x)\) does not vanish for \(x \gt x_{n-1}\), and since it is decreasing on the interval \([x_k, x_{k+1}]\), it has the sign of \((-1)\) on the interval \((x_{k+1}, x_{k+2})\), that of \((-1)^2\) on the interval \((x_{k+2}, x_{k+3})\), \(\ldots\), and it has the sign of \((-1)^{n-k-1}\) for \(x \gt x_{n-1}\). We therefore have

(1.1.29)
\[ (-1)^{n-k-1} h_k(x_n) \gt 0. \]

Replacing the function \(f\) in formula (1.1.20) by the polynomial \(h_k\), we have, by conditions (1.1.28), \(\lambda_0 + \lambda_1 + \ldots + \lambda_k + \lambda_n h_k(x_n) = 0\), and it follows that

(1.1.30)
\[ (-1)^k(\lambda_0 + \lambda_1 + \ldots + \lambda_k) = (-1)^{k+1} \lambda_n h_k(x_n). \]

But by inequality (1.1.29) and \((-1)^n \lambda_n \gt 0\), the right-hand side of formula (1.1.30) is positive, and therefore Theorem 1.1.2 is proved.

Corollary. The polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_n\) are of degree \(n-1\).

Indeed, by formulas (1.1.8) we have formulas (1.1.13), and since, by inequalities (1.1.27), the right-hand sides of formulas (1.1.13) are different from zero, it follows that the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_n\) are of degree \(n-1\).

Theorem 1.1.3. The derivative \(\varphi^{(n-2)}\) of the function \(\varphi\) in formula (1.1.19) has at most \(n-2\) zeros on the interval \((x_0, x_n)\).

Indeed, by the corollary of Theorem 1.1.2, the derivatives \(\varphi_1^{(n-2)}, \varphi_2^{(n-2)}, \ldots, \varphi_n^{(n-2)}\) are polynomials of the first degree, which have at most one root on the respective intervals \((x_0, x_1]\), \((x_1, x_2]\), \(\ldots\), \((x_{n-2}, x_{n-1}]\), \((x_{n-1}, x_n)\).

But we have

\[ \varphi_1(x) = \lambda_0 \frac{(x - x_0)^{n-1}}{(n-1)!}, \quad \varphi_n(x) = -\lambda_n \frac{(x - x_n)^{n-1}}{(n-1)!} \]

and therefore the derivatives \(\varphi_1^{(n-2)}, \varphi_n^{(n-2)}\) do not vanish on the intervals \((x_0, x_1]\), \([x_{n-1}, x_n)\). It then follows that the derivative \(\varphi^{(n-2)}\) has at most \(n-2\) zeros on the interval \((x_1, x_{n-1})\), and therefore on the interval \((x_0, x_n)\). Theorem 1.1.3 is thus proved.

1.1.5. It is very important to study the sign of the function \(\varphi\) on the interval \((x_0, x_n)\). For \(n = 1\), formula (1.1.19) becomes

\[ [x_0, x_1; f] = \frac{f(x_1) - f(x_0)}{x_1 - x_0} = \int_{x_0}^{x_1} \varphi(s) f'(s)\, ds, \]

where \(\varphi(s) = \dfrac{1}{x_1 - x_0}\), and therefore the function \(\varphi\) is positive on the interval \((x_0, x_1)\).

For \(n=2\) we have \(\varphi_1(x) = \dfrac{x-x_0}{(x_1-x_0)(x_2-x_0)}\), \(\varphi_2(x) = \dfrac{x_2-x}{(x_2-x_0)(x_2-x_1)}\), and therefore the function \(\varphi\) is positive on the interval \((x_0, x_2)\).

In general we have the following theorem:

Theorem 1.1.4. The function \(\varphi\) in formula (1.1.19) is positive on the interval \((x_0, x_n)\).

For the proof we assume that \(n \gt 2\) and observe that, by the boundary conditions (1.1.6), the function \(\varphi\) is continuous together with its successive derivatives \(\varphi', \varphi'', \ldots, \varphi^{(n-2)}\) on the interval \([x_0, x_n]\). In addition, we have

(1.1.31)
\[ \begin{aligned} &\varphi(x_0) = 0,\ \varphi'(x_0) = 0, \ldots, \varphi^{(n-2)}(x_0) = 0, \\ &\varphi(x_n) = 0,\ \varphi'(x_n) = 0, \ldots, \varphi^{(n-2)}(x_n) = 0. \end{aligned} \]

Let us first prove that the function \(\varphi\) does not vanish on the interval \((x_0, x_n)\). To this end we assume the contrary, namely that the function \(\varphi\) vanishes at least once on this interval, at a point \(\xi_1^{(0)}\). Applying Rolle's theorem to the function \(\varphi\) and to the intervals \([x_0, \xi_1^{(0)}]\), \([\xi_1^{(0)}, x_n]\), we deduce that the derivative \(\varphi'\) vanishes at least at two points \(\xi_1^{(1)}, \xi_2^{(1)}\) of the interval \((x_0, x_n)\). Then, applying Rolle's theorem to the function \(\varphi'\) and to the intervals \([x_0, \xi_1^{(1)}]\), \([\xi_1^{(1)}, \xi_2^{(1)}]\), \([\xi_2^{(1)}, x_n]\), we deduce that the derivative \(\varphi''\) vanishes at least at three points \(\xi_1^{(2)}, \xi_2^{(2)}, \xi_3^{(2)}\) of the interval \((x_0, x_n)\), \(\ldots\), and so on. We arrive at the conclusion that the derivative \(\varphi^{(n-2)}\) vanishes at least at \(n-1\) points \(\xi_1^{(n-2)}, \xi_2^{(n-2)}, \ldots, \xi_{n-1}^{(n-2)}\) of the interval \((x_0, x_n)\). But this contradicts Theorem 1.1.3, which shows that the number of zeros of \(\varphi^{(n-2)}\) on the interval \((x_0, x_n)\) is at most \(n-2\). We must therefore reject the hypothesis that the function \(\varphi\) vanishes at least once on the interval \((x_0, x_n)\), and consequently it keeps its sign on this interval. We have \(\varphi_1(s) = \lambda_0 \dfrac{(s-x_0)^{n-1}}{(n-1)!} \gt 0\) on the interval \((x_0, x_1]\), and therefore the function \(\varphi\) is positive on the interval \((x_0, x_n)\). Theorem 1.1.4 is thus proved.

Theorem 1.1.5. We have the formula

(1.1.32)
\[ \int_{x_0}^{x_n} \varphi(s)\, ds = \frac{1}{n!}. \]

To prove it, it suffices to replace the function \(f(x)\) in formula (1.1.19) by \(x^n\) and to observe that its left-hand side becomes equal to 1. Formula (1.1.32) then follows immediately.

Corollary. Formulas (1.1.19), (1.1.32) lead in a simple way to the well-known formula

(1.1.33)
\[ [x_0, x_1, \ldots, x_n; f] = \frac{f^{(n)}(\xi)}{n!}, \]

where \(\xi \in (x_0, x_n)\).

Indeed, it suffices to apply the mean value formula to the right-hand side of formula (1.1.19) and to take formula (1.1.32) into account.

§ 1.2. The Lagrange interpolation formula

The representation of the divided difference of a function \(f\) on simple nodes by a definite integral leads in a remarkable way to the Lagrange interpolation formula, to its remainder, and to the Lagrange interpolation polynomial.

1.2.1. Let us consider a function \(f \in C^n[a, b]\) and the simple nodes \(x_1, x_2, \ldots, x_n\) of the interval \((a, b)\), where \(x_1 \lt x_2 \lt \ldots \lt x_n\), as well as a node \(x \in (a, b)\) which, however, does not coincide with any of the nodes \(x_1, x_2, \ldots, x_n\). The node \(x\) may lie to the left of \(x_1\), or to the right of \(x_n\), or in the interval \((x_1, x_n)\), without coinciding with any of the nodes \(x_2, x_3, \ldots, x_{n-1}\).

Let us first assume that \(x \in (x_i, x_{i+1})\), where \(i\) is one of the numbers \(1, 2, \ldots, n-1\). In this case we can consider the integral representation of the divided difference of order \(n\) of the function \(f\) on the nodes \(x_1, \ldots, x_i, x, x_{i+1}, \ldots, x_n\) and write the formula

(1.2.1)
\[ [x_1, \ldots, x_i, x, x_{i+1}, \ldots, x_n; f] = \int_{x_1}^{x_n} \varphi_i(x, s) f^{(n)}(s)\, ds, \]

where we have denoted the function \(\varphi\) of formula (1.1.19) by \(\varphi_i(x, s)\), in order to indicate that it depends on the node \(x \in (x_i, x_{i+1})\).

The left-hand side of formula (1.2.1) can be replaced by

\[ [x, x_1, \ldots, x_n; f] = \frac{1}{V(x, x_1, \ldots, x_n)} \begin{vmatrix} 1 & x & \ldots & x^{n-1} & f(x) \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & x_n & \ldots & x_n^{n-1} & f(x_n) \end{vmatrix} \]

and formula (1.2.1) can be written in the form

(1.2.2)
\[ (-1)^n \frac{V(x_1, x_2, \ldots, x_n)}{V(x, x_1, \ldots, x_n)} f(x) = \frac{-1}{V(x, x_1, \ldots, x_n)} \begin{vmatrix} 1 & x & \ldots & x^{n-1} & 0 \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & x_n & \ldots & x_n^{n-1} & f(x_n) \end{vmatrix} + \int_{x_1}^{x_n} \varphi_i(x, s) f^{(n)}(s)\, ds. \]

Introducing the polynomial

(1.2.3)
\[ \omega(x) = (x-x_1)(x-x_2)\ldots(x-x_n) \]

we have \((-1)^n \dfrac{V(x, x_1, \ldots, x_n)}{V(x_1, \ldots, x_n)} = \omega(x)\), and we can write formula (1.2.2) in the form

(1.2.4)
\[ f(x) = \frac{(-1)^{n+1}}{V(x_1, x_2, \ldots, x_n)} \begin{vmatrix} 1 & x & \ldots & x^{n-1} & 0 \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & x_n & \ldots & x_n^{n-1} & f(x_n) \end{vmatrix} + \omega(x) \int_{x_1}^{x_n} \varphi_i(x, s) f^{(n)}(s)\, ds. \]

The first term of formula (1.2.4) is a polynomial \(L_{n-1}(x)\), which we consider on the whole interval \([a, b]\) and whose degree is at most \(n-1\). We shall write

(1.2.5)
\[ L_{n-1}(x) = \frac{(-1)^{n-1}}{V(x_1, x_2, \ldots, x_n)} \begin{vmatrix} 1 & x & \ldots & x^{n-1} & 0 \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & x_n & \ldots & x_n^{n-1} & f(x_n) \end{vmatrix}. \]

The polynomial \(L_{n-1}(x)\) is related to the function \(f\) by the following two theorems:

Theorem 1.2.1. The values of the polynomial \(L_{n-1}\) at the nodes \(x_1, x_2, \ldots, x_n\) are equal to the values of the function \(f\) at these nodes, that is,

(1.2.6)
\[ L_{n-1}(x_k) = f(x_k), \qquad (k = 1, 2, \ldots, n). \]

Indeed, replacing \(x\) by \(x_k\) in formula (1.2.5), we obtain

\[ L_{n-1}(x_k) = \frac{(-1)^{n+1}}{V(x_1, x_2, \ldots, x_n)} \begin{vmatrix} 0 & 0 & \ldots & 0 & -f(x_k) \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & x_n & \ldots & x_n^{n-1} & f(x_n) \end{vmatrix} \]

and therefore we have \(L_{n-1}(x_k) = f(x_k)\) for \(k = 1, 2, \ldots, n\).

Theorem 1.2.2. The polynomial

(1.2.7)
\[ P_{n-1}(x) = A_0 x^{n-1} + A_1 x^{n-2} + \ldots + A_{n-1} \]

of degree at most \(n-1\), whose coefficients are determined by the conditions

(1.2.8)
\[ P_{n-1}(x_k) = f(x_k), \qquad (k = 1, 2, \ldots, n) \]

is identical with the polynomial \(L_{n-1}(x)\).

Indeed, the equations which determine the coefficients of the polynomial \(P_{n-1}\) are

(1.2.9)
\[ \begin{aligned} A_{n-1} + A_{n-2} x_1 + \ldots + A_0 x_1^{n-1} &= f(x_1) \\ A_{n-1} + A_{n-2} x_2 + \ldots + A_0 x_2^{n-1} &= f(x_2) \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots& \\ A_{n-1} + A_{n-2} x_n + \ldots + A_0 x_n^{n-1} &= f(x_n) \end{aligned} \]

and the determinant of this system is different from zero.

Eliminating the constants \(A_{n-1}, A_{n-2}, \ldots, A_0\) between equations (1.2.7) and (1.2.9), we find

\[ \begin{vmatrix} 1 & x & \ldots & x^{n-1} & P_{n-1}(x) \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & x_n & \ldots & x_n^{n-1} & f(x_n) \end{vmatrix} = 0 \]

and, solving this equation for \(P_{n-1}(x)\), we find that \(P_{n-1}(x) = L_{n-1}(x)\).

Formula (1.2.4) can be written in the form

(1.2.10)
\[ f(x) = L_{n-1}(x) + R_i(x), \qquad (i = 1, 2, \ldots, n-1) \]

this appears as an approximation formula, which is called the Lagrange interpolation formula. The function \(f\) is approximated on the interval \([a, b]\) by the polynomial \(L_{n-1}\), which is called the Lagrange interpolation polynomial.

The remainder of formula (1.2.10) is

(1.2.11)
\[ R_i(x) = \omega(x) \int_{x_1}^{x_n} \varphi_i(x, s) f^{(n)}(s)\, ds, \qquad (i = 1, 2, \ldots, n-1); \]

it depends on \(x\) and on the index which shows that \(x \in (x_i, x_{i+1})\).

1.2.2. If \(x \lt x_1\), we have the integral representation

(1.2.12)
\[ [x, x_1, \ldots, x_n; f] = \int_x^{x_n} \varphi_0(x, s) f^{(n)}(s)\, ds, \]

where we have denoted the function \(\varphi(s)\) of formula (1.1.19) by \(\varphi_0(x, s)\) in order to indicate that it corresponds to the node \(x \lt x_1\).

Proceeding as in subsection 1.2.1, we arrive at the Lagrange interpolation formula

(1.2.13)
\[ f(x) = L_{n-1}(x) + R_0(x), \]

where the remainder of this formula is

(1.2.14)
\[ R_0(x) = \omega(x) \int_x^{x_n} \varphi_0(x, s) f^{(n)}(s)\, ds. \]

If \(x \gt x_n\), we have the integral representation

(1.2.15)
\[ [x_1, x_2, \ldots, x_n, x; f] = \int_{x_1}^{x} \varphi_n(x, s) f^{(n)}(s)\, ds, \]

where we have denoted the function \(\varphi\) of formula (1.1.19) by \(\varphi_n(x, s)\) in order to show that it corresponds to the node \(x \gt x_n\).

Proceeding as in subsection 1.2.1, we arrive at the Lagrange interpolation formula

(1.2.16)
\[ f(x) = L_{n-1}(x) + R_n(x), \]

where the remainder \(R_n(x)\) is given by the formula

(1.2.17)
\[ R_n(x) = \omega(x) \int_{x_1}^{x} \varphi_n(x, s) f^{(n)}(s)\, ds. \]

1.2.3. The function \(\varphi_i(x, s)\) is positive on the interval \((x_1, x_n)\), \((i = 1, 2, \ldots, n-1)\), as are the functions \(\varphi_0(x, s)\), \(\varphi_n(x, s)\) on the intervals \((x, x_n)\), \((x_1, x)\). We have

\[ \int_{x_1}^{x_n} \varphi_i(x, s)\, ds = \frac{1}{n!}, \qquad (i = 1, 2, \ldots, n-1) \]

and

\[ \int_x^{x_n} \varphi_0(x, s)\, ds = \frac{1}{n!}, \qquad \int_{x_1}^{x} \varphi_n(x, s)\, ds = \frac{1}{n!}. \]

Hence we obtain for \(R_i(x)\) the well-known estimate

(1.2.18)
\[ |R_i(x)| \leq \frac{M_i}{n!} |\omega(x)|, \qquad (i = 0, 1, \ldots, n), \]

where

(1.2.19)
\[ M_i = \sup_{s \in (x_1, x_n)} |f^{(n)}(s)|, \qquad (i = 1, 2, \ldots, n-1) \]

and

(1.2.20)
\[ M_0 = \sup_{s \in (x, x_n)} |f^{(n)}(s)|, \qquad M_n = \sup_{s \in (x_1, x)} |f^{(n)}(s)|. \]

§ 1.3. The case of nodes in arithmetic progression

In this section we consider the divided difference of order \(n\) of a function \(f\) on the nodes \(x_0, x_1, \ldots, x_n\) in arithmetic progression with common difference \(h = x_1 - x_0\). We shall thus be led to define the difference of order \(n\) of a function \(f\) on the nodes \(x_0, x_1, \ldots, x_n\) in arithmetic progression, and to establish its integral representation when \(f \in C^n[x_0, x_n]\).

1.3.1. As is well known, the divided difference \([x_0, x_1, \ldots, x_n; f]\) has the recurrence property

(1.3.1)
\[ [x_0, x_1, \ldots, x_n; f] = \frac{[x_1, x_2, \ldots, x_n; f] - [x_0, x_1, \ldots, x_{n-1}; f]}{x_n - x_0} \]

which is easily proved starting from the fundamental formula (1.1.17). In order to be able to apply formula (1.3.1) also for \(n = 1\), we agree to write \([x; f] = f(x)\).

Definition 1.3.1. The difference \(f(x_1) - f(x_0)\) is called the difference of the first order of the function \(f\) at the point \(x_0\) and on the nodes \(x_0, x_1\); it is denoted by \(\Delta^1 f(x_0)\), that is,

(1.3.2)
\[ \Delta^1 f(x_0) = f(x_1) - f(x_0). \]

The difference of order \(n\) of the function \(f\) at the point \(x_0\) and on the nodes \(x_0, x_1, \ldots, x_n\), which is denoted by \(\Delta^n f(x_0)\), is defined by the following recurrence formula

(1.3.3)
\[ \Delta^n f(x_0) = \Delta^1(\Delta^{n-1} f(x_0)) \]

that is,

(1.3.3′)
\[ \Delta^n f(x_0) = \Delta^{n-1} f(x_1) - \Delta^{n-1} f(x_0). \]

In order to apply formula (1.3.3) also for \(n = 1\), we agree to write \(\Delta^0 f(x) = f(x)\).

Taking into account the first part of this definition, we can write

(1.3.4)
\[ [x_0, x_1; f] = \frac{f(x_1) - f(x_0)}{x_1 - x_0} = \frac{\Delta^1 f(x_0)}{1!\, h}. \]

Theorem 1.3.1. When the nodes \(x_0, x_1, \ldots, x_n\) are in arithmetic progression with common difference \(h = x_1 - x_0\), we have the formula

(1.3.5)
\[ [x_0, x_1, \ldots, x_n; f] = \frac{\Delta^n f(x_0)}{n!\, h^n}. \]

We shall prove formula (1.3.5) by the method of complete induction. For \(n = 1\) the formula is true, because it coincides with formula (1.3.4).

Let us assume that formula (1.3.5) is true for \(n\) arbitrary nodes in arithmetic progression, and let us prove that it is true for \(n + 1\) nodes in arithmetic progression.

To this end we apply formula (1.3.1) and obtain

\[ [x_0, x_1, \ldots, x_n; f] = \frac{\Delta^{n-1} f(x_1) - \Delta^{n-1} f(x_0)}{(n-1)!\, h^{n-1}\, nh} = \frac{\Delta^1(\Delta^{n-1} f(x_0))}{n!\, h^n} \]

which means, by formula (1.3.3), that

\[ [x_0, x_1, \ldots, x_n; f] = \frac{\Delta^n f(x_0)}{n!\, h^n} \]

and therefore Theorem 1.3.1 is proved.

Theorem 1.3.2. For the difference of order \(n\) of the function \(f\) on the nodes \(x_0, x_1, \ldots, x_n\) we have the formula

(1.3.6′)
\[ \Delta^n f(x_0) = f(x_n) - C_n^1 f(x_{n-1}) + \ldots + (-1)^n C_n^n f(x_0). \]

Indeed, this formula is true for \(n = 1\), because it coincides with the defining formula (1.3.2). Further, formula (1.3.6′) is proved by the method of complete induction, using the defining formula (1.3.2).

1.3.2. Using the integral representation of the divided difference

(1.3.6)
\[ [x_0, x_1, \ldots, x_n; f] = \int_{x_0}^{x_n} \varphi(s) f^{(n)}(s)\, ds \]

and formula (1.3.5), we deduce the following theorem

Theorem 1.3.3. 1°. When the nodes \(x_0, x_1, \ldots, x_n\) are in arithmetic progression with common difference \(h = x_1 - x_0\) and \(f \in C^n[x_0, x_0 + nh]\), we have the integral representation

(1.3.7)
\[ \Delta^n f(x_0) = f(x_0 + nh) - C_n^1 f(x_0 + (n-1)h) + \ldots + (-1)^n C_n^n f(x_0) = \int_{x_0}^{x_0+nh} \psi(s) f^{(n)}(s)\, ds \]

with

(1.3.8)
\[ \psi(s) = n!\, h^n \varphi(s), \]

where \(\varphi(s)\) is the function in representation (1.3.6).

2°. We have the formula

(1.3.9)
\[ \int_{x_0}^{x_0+nh} \psi(s)\, ds = h^n. \]

1.3.3. We shall give some important applications of formula (1.3.7).

1°. Let us first put \(f(x) = (x - x_0)^r\) in formula (1.3.7), where \(r \leq n\). Taking also formula (1.3.9) into account, we shall then have the identities

(1.3.10)
\[ n^r - C_n^1 (n-1)^r + \ldots + (-1)^{n-1} C_n^{n-1} 1^r = \begin{cases} 0 & \text{if } r \lt n \\ n! & \text{if } r = n. \end{cases} \]

2°. Putting next \(f(x) = (x - x_0)^{n+1}\) in formula (1.3.7), we shall have

(1.3.11)
\[ n^{n+1} - C_n^1 (n-1)^{n+1} + \ldots + (-1)^{n-1} C_n^{n-1} 1^{n+1} = \frac{(n+1)!}{h^{n+1}} \int_{x_0}^{x_0+nh} \psi(s)(s - x_0)\, ds. \]

But according to formula (1.1.19), we have

(1.3.12)
\[ {[}x_0, x_0 + h, \ldots, x_0 + nh; (x - x_0)^{n+1}] = (n+1)! \int_{x_0}^{x_0+nh} \varphi(s)(s - x_0)\, ds. \]

The left-hand side of formula (1.3.12) is

\[ \frac{1}{V(x_0, x_1, \ldots, x_n)} \begin{vmatrix} 1 & x_0 & \ldots & x_0^{n-1} & (x_0 - x_0)^{n+1} \\ 1 & x_1 & \ldots & x_1^{n-1} & (x_1 - x_0)^{n+1} \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & x_n & \ldots & x_n^{n-1} & (x_n - x_0)^{n+1} \end{vmatrix} = x_0 + x_1 + \ldots + x_n - (n+1)x_0 = (x_1 - x_0) + (x_2 - x_0) + \ldots + (x_n - x_0) = \frac{n(n+1)}{2} h \]

and therefore, by formula (1.3.12), we have

\[ \int_{x_0}^{x_0+nh} \varphi(s)(s - x_0)\, ds = \frac{h}{2(n-1)!}. \]

Returning to formula (1.3.11) and taking formula (1.3.8) into account, we shall have the identity

(1.3.13)
\[ n^{n+1} - C_n^1 (n-1)^{n+1} + \ldots + (-1)^{n-1} C_n^{n-1} 1^{n+1} = \frac{n(n+1)}{2} n! \]

Identities (1.3.10) and (1.3.13) are known. What is interesting is that we have deduced them from the integral representation (1.3.7).

↑ Contents

Română

Chapter II

The method of the function \(\varphi\) and divided differences in the case of multiple nodes

D. V. Ionescu, Diferențe divizate [Divided Differences], Editura Academiei Republicii Socialiste România, Bucharest, 1978, pp. 47–81

§ 2.1. The second boundary value problem

In this section we shall study a new boundary value problem which will lead us to the definition of the divided difference of a function \(f\) on the nodes \(x_0, x_1, \ldots, x_k\) of multiplicities \(n_0, n_1, \ldots, n_k\), where \(x_0 \lt x_1 \lt \ldots \lt x_k\) and where \(n + 1 = n_0 + n_1 + \ldots + n_k\), as well as to its representation by a definite integral when \(f \in C^n[x_0, x_k]\).

2.1.1. Let us consider the nodes \(x_0, x_1, \ldots, x_k\), where

(2.1.1)
\[ x_0 \lt x_1 \lt \ldots \lt x_k \]

which are of multiplicities \(n_0, n_1, \ldots, n_k\), and let us denote by \(n\) the number defined by

(2.1.2)
\[ n + 1 = n_0 + n_1 + \ldots + n_k. \]

To the intervals \([x_0, x_1]\), \([x_1, x_2], \ldots, [x_{k-1}, x_k]\) we attach the polynomials \(\varphi_1, \varphi_2, \ldots \varphi_k\), solutions of the differential equations

(2.1.3)
\[ \varphi_1^{(n)} = 0,\ \varphi_2^{(n)} = 0,\ \ldots,\ \varphi_k^{(n)} = 0 \]

and we compute the integrals \(\int_{x_0}^{x_1} \varphi_1 f^{(n)}\, ds\), \(\int_{x_1}^{x_2} \varphi_2 f^{(n)}\, ds, \ldots, \int_{x_{k-1}}^{x_k} \varphi_k f^{(n)}\, ds\).

Applying the generalized integration by parts formula, we shall have

(2.1.4)
\[ \begin{aligned} \int_{x_0}^{x_1} \varphi_1 f^{(n)}\, ds &= (\varphi_1 f^{(n-1)} - \varphi_1' f^{(n-2)} + \ldots + (-1)^{n-1} \varphi_1^{(n-1)} f)_{x_0}^{x_1}, \\ \int_{x_1}^{x_2} \varphi_2 f^{(n)}\, ds &= (\varphi_2 f^{(n-1)} - \varphi_2' f^{(n-2)} + \ldots + (-1)^{n-1} \varphi_2^{(n-1)} f)_{x_1}^{x_2}, \\ &\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ \int_{x_{k-1}}^{x_k} \varphi_k f^{(n)}\, ds &= (\varphi_k f^{(n-1)} - \varphi_k' f^{(n-2)} + \ldots + (-1)^{n-1} \varphi_k^{(n-1)} f)_{x_{k-1}}^{x_k}. \end{aligned} \]

Adding formulas (2.1.4) term by term, we obtain a formula of the form

(2.1.5)
\[ \mathscr{P}[f] = \int_{x_0}^{x_k} \varphi f^{(n)}\, ds, \]

where the function \(\varphi\) coincides with the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_k\) on the intervals \([x_0, x_1]\), \([x_1, x_2], \ldots, [x_{k-1}, x_k]\), and where \(\mathscr{P}[f]\) depends on the values of \(f, f', \ldots, f^{(n-1)}\) at the nodes \(x_0, x_1, \ldots, x_k\).

In connection with formula (2.1.5) we pose the following

Boundary value problem. Determine the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_k\), solutions of the differential equations (2.1.3), such that in \(\mathscr{P}[f]\) the coefficients of

(2.1.6)
\[ \begin{aligned} & f^{(n_0)}(x_0),\ f^{(n_0+1)}(x_0),\ \ldots,\ f^{(n-1)}(x_0), \\ & f^{(n_1)}(x_1),\ f^{(n_1+1)}(x_1),\ \ldots,\ f^{(n-1)}(x_1), \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & f^{(n_k)}(x_k),\ f^{(n_k+1)}(x_k),\ \ldots,\ f^{(n-1)}(x_k) \end{aligned} \]

are zero, and such that \(\mathscr{P}[f] = 1\) for \(f(x) = x^n\).

For this we must introduce the boundary conditions

(2.1.7)
\[ \begin{aligned} & \varphi_1(x_0) = 0,\ \varphi_1'(x_0) = 0,\ \ldots,\ \varphi_1^{(n-n_0-1)}(x_0) = 0 \\ & \varphi_2(x_1) = \varphi_1(x_1),\ \varphi_2'(x_1) = \varphi_1'(x_1),\ \ldots,\ \varphi_2^{(n-n_1-1)}(x_1) = \varphi_1^{(n-n_1-1)}(x_1) \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & \varphi_k(x_{k-1}) = \varphi_{k-1}(x_{k-1}),\ \varphi_k'(x_{k-1}) = \varphi_{k-1}'(x_{k-1}),\ \ldots,\ \varphi_k^{(n-n_{k-1}-1)}(x_{k-1}) = \varphi_{k-1}^{(n-n_{k-1}-1)}(x_{k-1}) \\ & \varphi_k(x_k) = 0,\ \varphi_k'(x_k) = 0,\ \ldots,\ \varphi_k^{(n-n_k-1)}(x_k) = 0 \end{aligned} \]

and also

(2.1.8)
\[ \mathscr{P}[x^n] = 1. \]

The solution of the differential equations (2.1.3) which satisfies the boundary conditions (2.1.7) relative to the nodes \(x_0, x_1, \ldots, x_{k-1}\) is given by the formulas

(2.1.9)
\[ \begin{aligned} \varphi_1(s) &= \lambda_0 \frac{(s - x_0)^{n-1}}{(n-1)!} - \lambda_0^{(1)} \frac{(s - x_0)^{n-2}}{(n-2)!} + \ldots + (-1)^{n_0-1} \lambda_0^{(n_0-1)} \frac{(s - x_0)^{n-n_0}}{(n-n_0)!}, \\ \varphi_2(s) &= \lambda_0 \frac{(s - x_0)^{n-1}}{(n-1)!} - \lambda_0^{(1)} \frac{(s - x_0)^{n-2}}{(n-2)!} + \ldots + (-1)^{n_0-1} \lambda_0^{(n_0-1)} \frac{(s - x_0)^{n-n_0}}{(n-n_0)!} + \\ &\quad + \lambda_1 \frac{(s - x_1)^{n-1}}{(n-1)!} - \lambda_1^{(1)} \frac{(s - x_1)^{n-2}}{(n-2)!} + \ldots + (-1)^{n_1-1} \lambda_1^{(n_1-1)} \frac{(s - x_1)^{n-n_1}}{(n-n_1)!}, \\ &\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ \varphi_k(s) &= \lambda_0 \frac{(s - x_0)^{n-1}}{(n-1)!} - \lambda_0^{(1)} \frac{(s - x_0)^{n-2}}{(n-2)!} + \ldots + (-1)^{n_0-1} \lambda_0^{(n_0-1)} \frac{(s - x_0)^{n-n_0}}{(n-n_0)!} + \\ &\quad + \lambda_1 \frac{(s - x_1)^{n-1}}{(n-1)!} - \lambda_1^{(1)} \frac{(s - x_1)^{n-2}}{(n-2)!} + \ldots + (-1)^{n_1-1} \lambda_1^{(n_1-1)} \frac{(s - x_1)^{n-n_1}}{(n-n_1)!} + \\ &\quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &\quad + \lambda_{k-1} \frac{(s - x_{k-1})^{n-1}}{(n-1)!} - \lambda_{k-1}^{(1)} \frac{(s - x_{k-1})^{n-2}}{(n-2)!} + \\ &\quad + \ldots + (-1)^{n_{k-1}-1} \lambda_{k-1}^{(n_{k-1}-1)} \frac{(s - x_{k-1})^{n-n_{k-1}}}{(n-n_{k-1})!} \end{aligned} \]

where the coefficients \(\lambda_0, \lambda_0^{(1)}, \ldots, \lambda_0^{(n_0-1)}, \ldots, \lambda_{k-1}, \lambda_{k-1}^{(1)}, \ldots, \lambda_{k-1}^{(n_{k-1}-1)}\) are constants. The number of these constants is \(n_0 + n_1 + \ldots + n_{k-1} = n - n_k + 1\).

The constants \(\lambda_0, \ldots, \lambda_{k-1}^{(n_{k-1}-1)}\) are determined by writing that the boundary conditions at the point \(x_k\) are satisfied. We then have the equations

(2.1.10)
\[ \begin{aligned} & \lambda_0 \frac{(x_k - x_0)^{n-1}}{(n-1)!} - \lambda_0^{(1)} \frac{(x_k - x_0)^{n-2}}{(n-2)!} + \ldots + (-1)^{n_0-1} \lambda_0^{(n_0-1)} \frac{(x_k - x_0)^{n-n_0}}{(n-n_0)!} + \\ & \quad + \lambda_1 \frac{(x_k - x_1)^{n-1}}{(n-1)!} - \lambda_1^{(1)} \frac{(x_k - x_1)^{n-2}}{(n-2)!} + \ldots + (-1)^{n_1-1} \lambda_1^{(n_1-1)} \frac{(x_k - x_1)^{n-n_1}}{(n-n_1)!} + \\ & \quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & \quad + \lambda_{k-1} \frac{(x_k - x_{k-1})^{n-1}}{(n-1)!} - \lambda_{k-1}^{(1)} \frac{(x_k - x_{k-1})^{n-2}}{(n-2)!} + \\ & \quad + \ldots + (-1)^{n_{k-1}-1} \lambda_{k-1}^{(n_{k-1}-1)} \frac{(x_k - x_{k-1})^{n-n_{k-1}}}{(n-n_{k-1})!} = 0 \\ & \lambda_0 \frac{(x_k - x_0)^{n-2}}{(n-2)!} - \lambda_0^{(1)} \frac{(x_k - x_0)^{n-3}}{(n-3)!} + \ldots + (-1)^{n_0-1} \lambda_0^{(n_0-1)} \frac{(x_k - x_0)^{n-n_0-1}}{(n-n_0-1)!} + \\ & \quad + \lambda_1 \frac{(x_k - x_1)^{n-2}}{(n-2)!} - \lambda_1^{(1)} \frac{(x_k - x_1)^{n-3}}{(n-3)!} + \ldots + (-1)^{n_1-1} \lambda_1^{(n_1-1)} \frac{(x_k - x_1)^{n-n_1-1}}{(n-n_1-1)!} + \\ & \quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & \quad + \lambda_{k-1} \frac{(x_k - x_{k-1})^{n-2}}{(n-2)!} - \lambda_{k-1}^{(1)} \frac{(x_k - x_{k-1})^{n-3}}{(n-3)!} + \\ & \quad + \ldots + (-1)^{n_{k-1}-1} \lambda_{k-1}^{(n_{k-1}-1)} \frac{(x_k - x_{k-1})^{n-n_{k-1}-1}}{(n-n_{k-1}-1)!} = 0 \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & \lambda_0 \frac{(x_k - x_0)^{n_k}}{n_k!} - \lambda_0^{(1)} \frac{(x_k - x_0)^{n_k-1}}{(n_k-1)!} + \ldots + (-1)^{n_0-1} \lambda_0^{(n_0-1)} \frac{(x_k - x_0)^{n_k-n_0+1}}{(n_k-n_0+1)!} + \\ & \quad + \lambda_1 \frac{(x_k - x_1)^{n_k}}{n_k!} - \lambda_1^{(1)} \frac{(x_k - x_1)^{n_k-1}}{(n_k-1)!} + \ldots + (-1)^{n_1-1} \lambda_1^{(n_1-1)} \frac{(x_k - x_1)^{n_k-n_1+1}}{(n_k-n_1+1)!} + \\ & \quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & \quad + \lambda_{k-1} \frac{(x_k - x_{k-1})^{n_k}}{n_k!} - \lambda_{k-1}^{(1)} \frac{(x_k - x_{k-1})^{n_k-1}}{(n_k-1)!} + \\ & \quad + \ldots + (-1)^{n_{k-1}-1} \lambda_{k-1}^{(n_{k-1}-1)} \frac{(x_k - x_{k-1})^{n_k-n_{k-1}+1}}{(n_k-n_{k-1}+1)!} = 0. \end{aligned} \]

We adopt the convention that in equations (2.1.10) the terms in which the exponents of \(x_k - x_0, x_k - x_1, \ldots, x_k - x_{k-1}\) are negative are to be taken as zero.

Equations (2.1.10) can also be written in the form

(2.1.11)
\[ \begin{aligned} & \lambda_0(x_k - x_0)^{n_k} - \lambda_0^{(1)} n_k (x_k - x_0)^{n_k-1} + \ldots + \\ & \quad + (-1)^{n_0-1} \lambda_0^{(n_0-1)} n_k(n_k-1) \ldots (n_k - n_0 + 2)(x_k - x_0)^{n_k-n_0+1} + \\ & \quad + \lambda_1 (x_k - x_1)^{n_k} - \lambda_1^{(1)} n_k (x_k - x_1)^{n_k-1} + \ldots + \\ & \quad + (-1)^{n_1-1} \lambda_1^{(n_1-1)} n_k (n_k-1) \ldots (n_k - n_1 + 2)(x_k - x_1)^{n_k-n_1+1} + \\ & \quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & \quad + \lambda_{k-1} (x_k - x_{k-1})^{n_k} - \lambda_{k-1}^{(1)} n_k (x_k - x_{k-1})^{n_k-1} + \ldots + \\ & \quad + (-1)^{n_{k-1}-1} \lambda_{k-1}^{(n_{k-1}-1)} n_k(n_k-1) \ldots (n_k - n_{k-1} + 2)(x_k - x_{k-1})^{n_k-n_{k-1}+1} = 0 \\ & \lambda_0(x_k - x_0)^{n_k+1} - \lambda_0^{(1)} (n_k+1)(x_k - x_0)^{n_k} + \ldots + \\ & \quad + \lambda_1 (x_k - x_1)^{n_k+1} - \lambda_1^{(1)} (n_k+1)(x_k - x_1)^{n_k} + \ldots \\ & \quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & \quad + \lambda_{k-1} (x_k - x_{k-1})^{n_k+1} - \lambda_{k-1}^{(1)} (n_k+1)(x_k - x_{k-1})^{n_k} + \ldots = 0 \\ & \quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & \quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & \lambda_0(x_k - x_0)^{n-1} - \lambda_0^{(1)} (n-1)(x_k - x_0)^{n-2} + \ldots + \\ & \quad + \lambda_1(x_k - x_1)^{n-1} - \lambda_1^{(1)} (n-1)(x_k - x_1)^{n-2} + \ldots + \\ & \quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & \quad + \lambda_{k-1} (x_k - x_{k-1})^{n-1} - \lambda_{k-1}^{(1)} (n-1)(x_k - x_{k-1})^{n-2} + \ldots = 0. \end{aligned} \]

The matrix of the coefficients of this system is

(2.1.12)
\[ \left\| \begin{array}{llllll} (x_k - x_0)^{n_k} & n_k(x_k - x_0)^{n_k-1} \ldots & n_k(n_k-1) & \ldots (n_k - n_0 + 2) & (x_k - x_0)^{n_k-n_0+1} & (x_k - x_1)^{n_k} \ldots \\ (x_k - x_0)^{n_k+1} & (n_k+1)(x_k - x_0)^{n_k} \ldots & (n_k+1)n_k & \ldots (n_k - n_0 + 3) & (x_k - x_0)^{n_k-n_0+2} & (x_k - x_1)^{n_k+1} \ldots \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & & & & \ldots\ldots\ldots\ldots\ldots\ldots & \\ (x_k - x_0)^{n-1} & (n-1)(x_k - x_0)^{n-2} \ldots & (n-1)(n-2) & \ldots (n - n_0 + 1) & (x_k - x_0)^{n-n_0} & (x_k - x_1)^{n-1} \ldots \end{array} \right\| \]

The entries of the 2nd, 3rd, \(\ldots\), \((n_0)\)th columns are the derivatives of the first, the 2nd, \(\ldots\), the \((n_0 - 1)\)th order of the entries of the first column. In the matrix there is a second group of columns relative to the column of \((x_k - x_1)^{n_k}\), a third one relative to the column of \((x_k - x_2)^{n_k}\), \(\ldots\), and a last group relative to the column of \((x_k - x_{k-1})^{n_k}\).

Matrix (2.1.12) has rank \(n - n_k\).

Indeed, it is easily shown that the determinant obtained from matrix (2.1.12) by deleting the last column is not zero, because it differs by a nonzero factor from the generalized Vandermonde determinant

\[ V(\underbrace{x_k - x_0, \ldots, x_k - x_0}_{n_0}, \underbrace{x_k - x_1, \ldots, x_k - x_1}_{n_1}, \ldots, \underbrace{x_k - x_{k-1}, \ldots, x_k - x_{k-1}}_{n_{k-1}-1}) \]

which is not zero.

Thus the coefficients \(\lambda_0, \lambda_0^{(1)}, \ldots, \lambda_0^{(n_0-1)}, \ldots, \lambda_{k-1}, \lambda_{k-1}^{(1)}, \ldots, \lambda_{k-1}^{(n_{k-1}-1)}\) are determined up to a factor. It follows that the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_k\) given by formulas (2.1.9) are determined up to a factor, and we can use them.

In formula (2.1.5) we can replace the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_k\) by the solution of the boundary value problem. Then \(\mathscr{P}[f]\) reduces to

(2.1.13)
\[ \begin{aligned} \mathscr{P}[f] = (-1)^n \{ & \varphi_1^{(n-1)}(x_0) f(x_0) - \varphi_1^{(n-2)}(x_0) f'(x_0) + \ldots + \\ & + (-1)^{n_0-1} \varphi_1^{(n-n_0)}(x_0) f^{(n_0-1)}(x_0) + \\ & + [\varphi_2^{(n-1)}(x_1) - \varphi_1^{(n-1)}(x_1)] f(x_1) - [\varphi_2^{(n-2)}(x_1) - \varphi_1^{(n-2)}(x_1)] f'(x_1) + \ldots + \\ & + (-1)^{n_1-1} [\varphi_2^{(n-n_1)}(x_1) - \varphi_1^{(n-n_1)}(x_1)] f^{(n_1-1)}(x_1) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + [\varphi_k^{(n-1)}(x_{k-1}) - \varphi_{k-1}^{(n-1)}(x_{k-1})] f(x_{k-1}) - [\varphi_k^{(n-2)}(x_{k-1}) - \\ & - \varphi_{k-1}^{(n-2)}(x_{k-1})] f'(x_{k-1}) + \ldots + (-1)^{n_{k-1}-1} [\varphi_k^{(n-n_{k-1})}(x_{k-1}) - \\ & - \varphi_{k-1}^{(n-n_{k-1})}(x_{k-1})] f^{(n_{k-1}-1)}(x_{k-1}) - \varphi_k^{(n-1)}(x_k) f(x_k) + \\ & + \varphi_k^{(n-2)}(x_k) f'(x_k) - \ldots + (-1)^{n_k} \varphi_k^{(n-n_k)}(x_k) f^{(n_k-1)}(x_k) \}. \end{aligned} \]

But by formulas (2.1.9) we have

(2.1.14)
\[ \begin{aligned} \varphi_1^{(n-1)}(x_0) &= \lambda_0 \\ \varphi_1^{(n-2)}(x_0) &= -\lambda_0^{(1)} \\ \ldots\ldots\ldots\ldots\ldots & \\ \varphi_1^{(n-n_0)}(x_0) &= (-1)^{n_0-1} \lambda_0^{(n_0-1)} \\ \varphi_2^{(n-1)}(x_1) - \varphi_1^{(n-1)}(x_1) &= \lambda_1 \\ \varphi_2^{(n-2)}(x_1) - \varphi_1^{(n-2)}(x_1) &= -\lambda_1^{(1)} \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ \varphi_2^{(n-n_1)}(x_1) - \varphi_1^{(n-n_1)}(x_1) &= (-1)^{n_1-1} \lambda_1^{(n_1-1)} \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ \varphi_k^{(n-1)}(x_{k-1}) - \varphi_{k-1}^{(n-1)}(x_{k-1}) &= \lambda_{k-1} \\ \varphi_k^{(n-2)}(x_{k-1}) - \varphi_{k-1}^{(n-2)}(x_{k-1}) &= -\lambda_{k-1}^{(1)} \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ \varphi_k^{(n-n_{k-1})}(x_{k-1}) - \varphi_{k-1}^{(n-n_{k-1})}(x_{k-1}) &= (-1)^{n_{k-1}-1} \lambda_{k-1}^{(n_{k-1}-1)}. \end{aligned} \]

We shall also write

(2.1.15)
\[ \begin{aligned} \varphi_k^{(n-1)}(x_k) &= -\lambda_k \\ \varphi_k^{(n-2)}(x_k) &= +\lambda_k^{(1)} \\ \ldots\ldots\ldots\ldots & \\ \varphi_k^{(n-n_k)}(x_k) &= (-1)^{n_k} \lambda_k^{(n_k-1)}. \end{aligned} \]

Since the function \(\varphi_k\) is determined by the last formula (2.1.9) by means of the coefficients \(\lambda_0, \lambda_0^{(1)}, \ldots, \lambda_0^{(n_0-1)}, \ldots, \lambda_{k-1}, \lambda_{k-1}^{(1)}, \ldots, \lambda_{k-1}^{(n_{k-1}-1)}\), the new coefficients \(\lambda_k, \lambda_k^{(1)} \ldots\) introduced by formulas (2.1.15) are determined, like the other coefficients \(\lambda_0, \ldots, \lambda_{k-1}^{(n_{k-1}-1)}\), up to a factor.

Taking all these formulas into account, formula (2.1.13) becomes

(2.1.16)
\[ \begin{aligned} \mathscr{P}[f] = (-1)^n \{ & \lambda_0 f(x_0) + \lambda_0^{(1)} f'(x_0) + \ldots + \lambda_0^{(n_0-1)} f^{(n_0-1)}(x_0) + \\ & + \lambda_1 f(x_1) + \lambda_1^{(1)} f'(x_1) + \ldots + \lambda_1^{(n_1-1)} f^{(n_1-1)}(x_1) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \lambda_{k-1} f(x_{k-1}) + \lambda_{k-1}^{(1)} f'(x_{k-1}) + \ldots + \lambda_{k-1}^{(n_{k-1}-1)} f^{(n_{k-1}-1)}(x_{k-1}) + \\ & + \lambda_k f(x_k) + \lambda_k^{(1)} f'(x_k) + \ldots + \lambda_k^{(n_k-1)} f^{(n_k-1)}(x_k) \}. \end{aligned} \]

Replacing in formula (2.1.5) the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_k\) by the solution of the boundary value problem, we can write

(2.1.17)
\[ \begin{aligned} (-1)^n \Bigl\{ & \lambda_0 f(x_0) + \lambda_0^{(1)} f'(x_0) + \ldots + \lambda_0^{(n_0-1)} f^{(n_0-1)}(x_0) + \\ & + \lambda_1 f(x_1) + \lambda_1^{(1)} f'(x_1) + \ldots + \lambda_1^{(n_1-1)} f^{(n_1-1)}(x_1) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \lambda_{k-1} f(x_{k-1}) + \lambda_{k-1}^{(1)} f'(x_{k-1}) + \ldots + \lambda_{k-1}^{(n_{k-1}-1)} f^{(n_{k-1}-1)}(x_{k-1}) + \\ & + \lambda_k f(x_k) + \lambda_k^{(1)} f'(x_k) + \ldots + \lambda_k^{(n_k-1)} f^{(n_k-1)}(x_k) \Bigr\} = \int_{x_0}^{x_k} \varphi f^{(n)}\, ds. \end{aligned} \]

2.1.2. An important consequence of this formula is that the coefficients \(\lambda_0, \lambda_0^{(1)}, \ldots, \lambda_0^{(n_0-1)}, \ldots, \lambda_k, \lambda_k^{(1)}, \ldots, \lambda_k^{(n_k-1)}\) satisfy the equations which we would deduce from formula (2.1.17) by replacing the function \(f\) successively by \(1, x, \ldots, x^{n-1}\). These equations are the following:

(2.1.18)
\[ \begin{array}{lll} \lambda_0 & + \lambda_k & = 0 \\ \lambda_0 x_0 + \lambda_0^{(1)} (x_0)' & + \lambda_k x_k + \lambda_k^{(1)} (x_k)' & = 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & & \\ \lambda_0 x_0^{n-1} + \lambda_0^{(1)} (x_0^{n-1})' + \ldots + \lambda_0^{(n_0-1)} (x_0^{n-1})^{(n_0-1)} + \ldots & + \lambda_k x_k^{n-1} + \lambda_k^{(1)} (x_k^{n-1})' + \ldots + \lambda_k^{(n_k-1)} (x_k^{n-1})^{(n_k-1)} & = 0 \end{array} \]

The matrix of system (2.1.18) is

(2.1.19)
\[ \left\| \begin{array}{llllll} 1 & 0 & \ldots 0 & \ldots 1 & 0 & \ldots 0 \\ x_0 & (x_0)' & \ldots 0 & \ldots x_k & (x_k)' & \ldots 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & & & & & \\ x_0^{n-1} & (x_0^{n-1})' & \ldots (x_0^{n-1})^{(n_0-1)} & \ldots x_k^{n-1} & (x_k^{n-1})' & \ldots (x_k^{n-1})^{(n_k-1)} \end{array} \right\| \]

Let us denote by \(D_0, D_0^{(1)}, \ldots, D_0^{(n_0-1)}, \ldots, D_k, D_k^{(1)}, \ldots, D_k^{(n_k-1)}\) the determinants of the matrices deduced from matrix (2.1.19) by deleting successively the 1st, the 2nd, \(\ldots\), the last column. Then the solution of system (2.1.18) is given by the formulas

(2.1.20)
\[ \begin{aligned} & \frac{\lambda_0}{D_0} = \frac{\lambda_0^{(1)}}{-D_0^{(1)}} = \ldots = \frac{\lambda_0^{(n_0-1)}}{(-1)^{n_0-1} D_0^{(n_0-1)}} = \\ & = \frac{\lambda_1}{(-1)^{n_0} D_1} = \frac{\lambda_1^{(1)}}{(-1)^{n_0+1} D_1^{(1)}} = \ldots = \frac{\lambda_1^{(n_1-1)}}{(-1)^{n_0+n_1-1} D_1^{(n_1-1)}} = \\ & = \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots = \\ & = \frac{\lambda_k}{(-1)^{n_0+n_1+\ldots+n_{k-1}} D_k} = \frac{\lambda_k^{(1)}}{(-1)^{n_0+n_1+\ldots+n_{k-1}+1} D_k^{(1)}} = \\ & = \ldots = \frac{\lambda_k^{(n_k-1)}}{(-1)^{n_0+n_1+\ldots+n_k-1} D_k^{(n_k-1)}} = H, \end{aligned} \]

where \(H\) is a constant which we shall determine.

Replacing in formula (2.1.16) the coefficients \(\lambda_0, \lambda_0^{(1)}, \ldots, \lambda_0^{(n_0-1)}, \ldots, \lambda_k, \lambda_k^{(1)}, \ldots, \lambda_k^{(n_k-1)}\) by the values deduced from formulas (2.1.20), we obtain

(2.1.21)
\[ \begin{aligned} \mathscr{P}[f] = (-1)^n H \Bigl\{ & D_0 f(x_0) - D_0^{(1)} f'(x_0) + \ldots + (-1)^{n_0-1} D_0^{(n_0-1)} f^{(n_0-1)}(x_0) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + (-1)^{n_0+n_1+\ldots+n_{k-1}} D_k f(x_k) + (-1)^{n_0+n_1+\ldots+n_{k-1}+1} D_k^{(1)} f'(x_k) + \ldots + \\ & + (-1)^{n_0+n_1+\ldots+n_k-1} D_k^{(n_k-1)} f^{(n_k-1)}(x_k) \Bigr\}. \end{aligned} \]

But the large bracket multiplied by \((-1)^n\) is equal to the determinant

(2.1.22)
\[ \Delta[f] = \begin{vmatrix} 1 & x_0 & \ldots x_0^{n-1} & f(x_0) \\ (1)' & (x_0)' & \ldots (x_0^{n-1})' & f'(x_0) \\ \ldots\ldots\ldots\ldots\ldots\ldots & & & \\ (1)^{(n_0-1)} & (x_0)^{(n_0-1)} & \ldots (x_0^{n-1})^{(n_0-1)} & f^{(n_0-1)}(x_0) \\ \ldots\ldots\ldots\ldots\ldots\ldots & & & \\ \ldots\ldots\ldots\ldots\ldots\ldots & & & \end{vmatrix} \]

and therefore

(2.1.23)
\[ \mathscr{P}[f] = H \Delta[f]. \]

According to the last boundary condition (2.1.8), \(\mathscr{P}[f]\) must reduce to 1 when \(f(x)\) is replaced by \(x^n\). Formula (2.1.23) shows that we must take

(2.1.24)
\[ H = \frac{1}{\Delta[x^n]} \]

and therefore the expression of \(\mathscr{P}[f]\) is

(2.1.25)
\[ \mathscr{P}[f] = \frac{\Delta[f]}{\Delta[x^n]}. \]

All the constants \(\lambda_0, \lambda_0^{(1)}, \ldots, \lambda_0^{(n_0-1)}, \ldots, \lambda_k, \lambda_k^{(1)}, \ldots, \lambda_k^{(n_k-1)}\) are now determined, and the boundary value problem is completely solved.

Definition 2.1.1. The expression of \(\mathscr{P}[f]\) given by formula (2.1.25), when in \(\mathscr{P}[f]\) the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_k\) are replaced by the solution of the boundary value problem, is called the divided difference of order \(n\) of the function \(f\) on the nodes \(x_0, x_1, \ldots, x_k\) of multiplicities \(n_0, n_1, \ldots, n_k\), where \(n + 1 = n_0 + n_1 + \ldots + n_k\). It is denoted by

(2.1.26)
\[ [\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f]. \]

Formula (2.1.25) shows that

(2.1.27)
\[ [\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f] = \frac{\Delta[f]}{\Delta[x^n]}, \]

where \(\Delta[f]\) is the determinant (2.1.22).

Formula (2.1.27) leads to the following theorem:

Theorem 2.1.1. The divided difference of the function \(f\) on the nodes \(x_0, x_1, \ldots, x_k\) of multiplicities \(n_0, n_1, \ldots, n_k\), where \(x_0 \lt x_1 \lt \ldots \lt x_k\) and \(n_0 + n_1 + \ldots + n_k = n + 1\), admits, when \(f \in C^n[x_0, x_k]\), an integral representation given by the formula

(2.1.28)
\[ [\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f] = \int_{x_0}^{x_k} \varphi f^{(n)}\, ds, \]

where the function \(\varphi\) coincides on the intervals \([x_0, x_1]\), \([x_1, x_2], \ldots, [x_{k-1}, x_k]\) with the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_k\) which represent the solution of the boundary value problem posed in subsection 2.1.1.

The integral representation (2.1.28) can also be written in the following form:

(2.1.29)
\[ \begin{aligned} & \lambda_0 f(x_0) + \lambda_0^{(1)} f'(x_0) + \ldots + \lambda_0^{(n_0-1)} f^{(n_0-1)}(x_0) + \\ & + \lambda_1 f(x_1) + \lambda_1^{(1)} f'(x_1) + \ldots + \lambda_1^{(n_1-1)} f^{(n_1-1)}(x_1) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \lambda_{k-1} f(x_{k-1}) + \lambda_{k-1}^{(1)} f'(x_{k-1}) + \ldots + \lambda_{k-1}^{(n_{k-1}-1)} f^{(n_{k-1}-1)}(x_{k-1}) + \\ & + \lambda_k f(x_k) + \lambda_k^{(1)} f'(x_k) + \ldots + \lambda_k^{(n_k-1)} f^{(n_k-1)}(x_k) = (-1)^n \int_{x_0}^{x_k} \varphi f^{(n)}\, ds \end{aligned} \]

in which we have displayed the coefficients of \(f(x_0), f'(x_0), \ldots, f^{(n_0-1)}(x_0), \ldots, f(x_k), f'(x_k) \ldots, f^{(n_k-1)}(x_k)\).

§ 2.2. On a property of the coefficients \(\lambda_0, \lambda_1, \ldots, \lambda_{k-1}\) in formula (2.1.29)

In this section we shall prove that the coefficients \(\lambda_0, \lambda_1, \ldots, \lambda_j\) in formula (2.1.29) have the property expressed by \(\lambda_0 + \lambda_1 + \ldots + \lambda_j \neq 0\), for \(j = 0, 1, \ldots, k - 1\).

2.2.1. Theorem 2.2.1. The coefficient \(\lambda_k^{(n_k-1)}\) in formula (2.1.29) is different from zero.

Indeed, by formulas (2.1.20) we have \(\lambda_k^{(n_k-1)} = (-1)^n H D_k^{(n_k-1)}\).

But the determinant \(D_k^{(n_k-1)}\) is the generalized Vandermonde determinant

\[ D_k^{(n_k-1)} = V(\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k-1}) \]

and, taking formula (2.1.24) into account, we have

(2.2.1)
\[ \lambda_k^{(n_k-1)} = (-1)^n \frac{V(\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k-1})}{V(\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k})} \]

which means that \(\lambda_k^{(n_k-1)} \neq 0\), and therefore the theorem is proved.

Theorem 2.2.1 is also valid in the case when the node \(x_k\) is simple, that is, in the case when \(n_k = 1\).

In this case formula (2.2.1) is replaced by

(2.2.1′)
\[ \lambda_k = (-1)^n \frac{V\left(\underbrace{x_0, \ldots, x_0}_{n_0}, \ldots, \underbrace{x_{k-1}, \ldots, x_{k-1}}_{n_{k-1}}\right)}{V\left(\underbrace{x_0, \ldots, x_0}_{n_0}, \ldots, \underbrace{x_{k-1}, \ldots, x_{k-1}}_{n_{k-1}}, x_k\right)} \]

and therefore \(\lambda_k \neq 0\).

2.2.2. Theorem 2.2.2. The coefficients \(\lambda_0, \lambda_1, \ldots, \lambda_j\) of formula (2.1.29) have the property expressed by

(2.2.2)
\[ \lambda_0 + \lambda_1 + \ldots + \lambda_j \neq 0, \]

for \(j = 0, 1, \ldots, k-1\).

To prove this theorem, let us introduce the interpolation polynomial \(h_j\) defined by the following conditions:

(2.2.3)
\[ \begin{array}{lll} h_j(x_0) = 1 \qquad & h_j(x_1) = 1 \qquad & h_j(x_j) = 1, \\ h_j'(x_0) = 0 \qquad & h_j'(x_1) = 0 \qquad & h_j'(x_j) = 0, \\ \ldots\ldots\ldots\ldots\ldots ; & \ldots\ldots\ldots\ldots\ldots ; & \ldots\ldots\ldots\ldots\ldots ;\ \ldots \\ h_j^{(n_0-1)}(x_0) = 0 \qquad & h_j^{(n_1-1)}(x_1) = 0 \qquad & h_j^{(n_j-1)}(x_j) = 0, \end{array} \]

and

(2.2.4)
\[ \begin{array}{lll} h_j(x_{j+1}) = 0 \qquad & h_j(x_{k-1}) = 0 \qquad & h_j(x_k) = 0, \\ h_j'(x_{j+1}) = 0 \qquad & h_j'(x_{k-1}) = 0, \qquad & h_j'(x_k) = 0, \\ \ldots\ldots\ldots\ldots\ldots ; & \ldots\ldots\ldots\ldots\ldots ; & \ldots\ldots\ldots\ldots\ldots ;\ \ldots \\ h_j^{(n_{j+1}-1)}(x_{j+1}) = 0 \qquad & h_j^{(n_{k-1}-1)}(x_{k-1}) = 0 \qquad & h_j^{(n_k-2)}(x_k) = 0, \end{array} \]

where it is assumed that \(n_k \gt 1\).

The number of conditions which determine the polynomial \(h_j\) is \(n_0 + n_1 + \ldots + n_{k-1} + n_k - 1 = n\), whence it follows that the degree of the polynomial \(h_j\) is at most \(n-1\).

From conditions (2.2.3) and (2.2.4) one can form the system of equations which determines the coefficients of the polynomial \(h_j(x) = A_0 x^{n-1} + A_1 x^{n-2} + \ldots + A_{n-1}\).

The determinant of the system in \(A_0, A_1, \ldots, A_{n-1}\) is the generalized Vandermonde determinant

\[ V(\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k-1}) \]

which is different from zero, so that the polynomial \(h_j\) is uniquely determined.

It may be added that the polynomial \(h_j\) is not identically zero, since we have \(h_j(x_0) = 1\), whereas \(h_j(x_k) = 0\), and this holds for \(j = 0, 1, \ldots, k-1\).

Replacing the function \(f\) in formula (2.1.29) by the polynomial \(h_j\), we obtain the formula

(2.2.5)
\[ \lambda_0 + \lambda_1 + \ldots + \lambda_j + \lambda_k^{(n_k-1)} h_j^{(n_k-1)}(x_k) = 0. \]

In this formula we have \(\lambda_k^{(n_k-1)} \neq 0\), by Theorem 2.2.1, and in order to prove Theorem 2.2.2 it remains to show that \(h_j^{(n_k-1)}(x_k) \neq 0\).

2.2.3. Theorem 2.2.3. For the interpolation polynomial \(h_j\) defined by conditions (2.2.3) and (2.2.4), where \(n_k \gt 1\), we have \(h_j^{(n_k-1)}(x_k) \neq 0\).

Let us denote by \(p\) the highest order of the derivatives occurring in conditions (2.2.3) and (2.2.4). Let us also denote by \(m_1\) the number of nodes \(x_0, x_1, \ldots, x_k\) at which \(h_j'\) vanishes, then by \(m_2\) the number of nodes \(x_0, x_1, \ldots, x_k\) at which \(h_j''\) vanishes, …, and finally by \(m_p\) the number of nodes \(x_0, x_1, \ldots, x_k\) at which \(h_j^{(p)}\) vanishes. Expressing the number of conditions (2.2.3) and (2.2.4) in two different ways, we obtain the equality

\[ 1 + k + m_1 + m_2 + \ldots + m_p = n_0 + n_1 + \ldots + n_{k-1} + (n_k - 1) = n \]

whence it follows that

(2.2.6)
\[ k + m_1 + m_2 + \ldots + m_p = n - 1. \]

Applying Rolle's theorem successively, it follows that the derivative \(h_j'\) has \(k + m_1 - 1\) distinct roots on the interval \([x_0, x_k]\), that the derivative \(h_j''\) has \(k + m_1 + m_2 - 2\) distinct roots on the interval \([x_0, x_k]\), …, and that the derivative \(h_j^{(p)}\) has

(2.2.7)
\[ N = k + m_1 + m_2 + \ldots + m_p - p = n - p - 1 \]

roots on the interval \([x_0, x_k]\).

The degree of the polynomial \(h_j\) being at most \(n-1\), that of \(h_j^{(p)}\) will be at most \(n-p-1\). But we have shown above that \(h_j^{(p)}\) has \(n-p-1\) distinct roots on the interval \([x_0, x_k]\).

Hence the degree of the polynomial \(h_j^{(p)}\) is \(n-p-1\), or less than \(n-p-1\). Let us prove that it is impossible for the degree of \(h_j^{(p)}\) to be less than \(n-p-1\).

Indeed, let us suppose that the polynomial \(h_j^{(p)}\) had degree less than \(n-p-1\). Since this polynomial has \(n-p-1\) distinct roots, it would be identically zero. It follows that the derivative \(h_j^{(p-1)}\) must be a constant, and this constant is zero, because the derivative vanishes at one of the points \(x_0, x_1, \ldots, x_j\). Hence \(h_j^{(p-1)}\) is an identically zero polynomial. Continuing this reasoning, we reach the conclusion that the polynomial \(h_j\) must be a constant, which is impossible, since \(h_j(x_0) = 1\), whereas \(h_j(x_k) = 0\).

Thus the polynomial \(h_j^{(p)}\) is of degree \(n-p-1\) and has \(n-p-1\) distinct roots on the interval \([x_0, x_k]\).

This being established, we can complete the proof of Theorem 2.2.3 and prove that \(h_j^{(n_k-1)}(x_k) \neq 0\).

Let us first treat the case \(n_k - 2 \lt p\) and suppose that \(h_j^{(n_k-1)}(x_k) = 0\). Repeating the reasoning based on Rolle's theorem, we are led to assert that the derivative \(h_j^{(p)}\) must have \(n-p\) distinct roots on the interval \([x_0, x_k]\), which is false, because we have proved that the number of roots of \(h_j^{(p)}\) is \(n-p-1\).

Let us finally treat the case \(n_k - 2 = p\) and suppose that \(h_j^{(n_k-1)}(x_k) = h_j^{(p+1)}(x_k) = 0\). Since the derivative \(h_j^{(p)}\) has \(n-p-1\) distinct roots on the interval \([x_0, x_k]\), its derivative \(h_j^{(p+1)}\) has \(n-p-2\) distinct roots on the interval \((x_0, x_k)\) and, in addition, the root \(x_k\), by our hypothesis. In all, the derivative \(h_j^{(p+1)}\) has \(n-p-1\) distinct roots on the interval \((x_0, x_k)\). But this is impossible, because \(h_j^{(p+1)}\), being a polynomial of degree \(n-p-2\), has at most \(n-p-2\) roots on the interval \([x_0, x_k]\). We have thus reached a contradiction, and we must drop the hypothesis that \(h_j^{(n_k-1)}(x_k) = 0\), which means that \(h_j^{(n_k-1)}(x_k) \neq 0\).

2.2.4. We can now prove Theorem 2.2.2 in the case \(n_k \gt 1\).

Indeed, we have formula (2.2.5), and we have proved Theorems 2.2.1 and 2.2.3, which show that \(\lambda_k^{(n_k-1)} \neq 0\) and \(h_j^{(n_k-1)}(x_k) \neq 0\). It follows that \(\lambda_0 + \lambda_1 + \ldots + \lambda_j \neq 0\) for \(j = 0, 1, \ldots, k-1\).

It remains to prove Theorem 2.2.2 in the case \(n_k = 1\).

2.2.5. To this end we introduce the interpolation polynomial, which we again denote by \(h_j\), defined by the following conditions:

(2.2.7)
\[ \begin{array}{lll} h_j(x_0) = 1 \qquad & h_j(x_1) = 1 \qquad & h_j(x_j) = 1 \\ h_j'(x_0) = 0 \qquad & h_j'(x_1) = 0 \qquad & h_j'(x_j) = 0 \\ \ldots\ldots\ldots\ldots\ldots ; & \ldots\ldots\ldots\ldots\ldots ; & \ldots\ldots\ldots\ldots\ldots ; \\ h_j^{(n_0-1)}(x_0) = 0 \qquad & h_j^{(n_1-1)}(x_1) = 0 \qquad & h_j^{(n_j-1)}(x_j) = 0 \end{array} \]

and

(2.2.8)
\[ \begin{array}{ll} h_j(x_{j+1}) = 0 \qquad & h_j(x_{k-1}) = 0 \\ h_j'(x_{j+1}) = 0 \qquad & h_j'(x_{k-1}) = 0 \\ \ldots\ldots\ldots\ldots\ldots ; & \ldots\ldots\ldots\ldots\ldots \\ h_j^{(n_{j+1}-1)}(x_{j+1}) = 0 \qquad & h_j^{(n_{k-1}-1)}(x_{k-1}) = 0 \end{array} \]

where \(j = 0, 1, \ldots, k-2\).

The number of conditions which determine the polynomial \(h_j\) is

(2.2.9)
\[ n_0 + n_1 + \ldots + n_{k-1} = n \]

whence it follows that the polynomial \(h_j\) is of degree at most \(n-1\).

As in subsection 2.2.2, one easily sees that the polynomial \(h_j\) is uniquely determined. Moreover, \(h_j\) is not identically zero, because, whatever \(j = 0, 1, \ldots, k-2\) may be, we have \(h_j(x_0) = 1\), whereas \(h_j(x_{k-1}) = 0\).

Replacing the function \(f\) in formula (2.1.29) by the polynomial \(h_j\), we have

(2.2.10)
\[ \lambda_0 + \lambda_1 + \ldots + \lambda_j + \lambda_k h_j(x_k) = 0, \quad\text{for } j = 0, 1, \ldots, k-1. \]

By Theorem 2.2.1, formula (2.2.1′), we have \(\lambda_k \neq 0\).

It remains to prove that \(h_j(x_k) \neq 0\), which is done by the following theorem:

Theorem 2.2.4. For the interpolation polynomial \(h_j\) defined by conditions (2.2.7), (2.2.8) we have \(h_j(x_k) \neq 0\).

As in subsection 2.2.3, let us denote by \(p\) the highest order of the derivatives occurring in conditions (2.2.7) and (2.2.8). We also denote by \(m_1\) the number of points \(x_0, x_1, \ldots, x_{k-1}\) at which \(h_j'\) vanishes, by \(m_2\) the number of points \(x_0, x_1, \ldots, x_{k-1}\) at which \(h_j''\) vanishes, …, and by \(m_p\) the number of points \(x_0, x_1, \ldots, x_{k-1}\) at which \(h_j^{(p)}\) vanishes. We have

(2.2.11)
\[ k + m_1 + m_2 + \ldots + m_p = n_0 + n_1 + \ldots + n_{k-1} = n. \]

Applying Rolle's theorem successively, we deduce that \(h_j'\) has \(k + m_1 - 2\) roots on the interval \([x_0, x_{k-1}]\), then that \(h_j''\) has \(k + m_1 + m_2 - 3\) roots on the interval \([x_0, x_{k-1}]\), …, and that \(h_j^{(p)}\) has \(N = k + m_1 + m_2 + \ldots + m_p - (p + 1) = n - p - 1\) roots on the interval \([x_0, x_{k-1}]\).

As in subsection 2.2.3, one deduces that the derivative \(h_j^{(p)}\) is a polynomial of degree \(n-p-1\) which vanishes at \(n-p-1\) distinct points of the interval \([x_0, x_{k-1}]\).

This being established, one easily proves that \(h_j(x_k) \neq 0\).

Indeed, let us suppose that \(h_j(x_k)\) were zero. Then, applying Rolle's theorem successively to \(h_j\), we reach the conclusion that \(h_j^{(p)}\) must have one more root, to the right of the last root exhibited above. But this is impossible, because it has been proved that \(h_j^{(p)}\) has only \(n-p-1\) roots on the interval \([x_0, x_{k-1}]\).

Hence \(h_j(x_k) \neq 0\), and therefore Theorem 2.2.4 is proved.

2.2.6. Theorem 2.2.5. The polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_k\) given by formulas (2.1.9) are of degree \(n-1\).

Indeed, the coefficients of \(s^{n-1}\) in these polynomials are

\[ \begin{array}{l} \lambda_0 \\ \lambda_0 + \lambda_1 \\ \ldots\ldots \\ \lambda_0 + \lambda_1 + \ldots + \lambda_{k-1}, \end{array} \]

and, by Theorem 2.2.2, they are all different from zero.

§ 2.3. On a property of the coefficients \(\lambda_0, \lambda_0^{(1)}, \ldots, \lambda_0^{(n_0-1)}\) and \(\lambda_k, \lambda_k^{(1)}, \ldots, \lambda_k^{(n_k-1)}\) of formula (2.1.29)

The aim of this section is to prove a theorem on the coefficients of \(f(x_0), f'(x_0), \ldots, f^{(n_0-1)}(x_0)\) and \(f(x_k), f'(x_k), \ldots, f^{(n_k-1)}(x_k)\) in the divided difference

\[ [\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f] \]

when the nodes \(x_0, x_1, \ldots, x_k\) have multiplicities \(n_0, n_1, \ldots, n_k\) and \(x_0 \lt x_1 \lt \ldots \lt x_k\). We shall make use of the formula

\[ \left[\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f\right] = \frac{\Delta[f]}{\Delta[x^n]}, \]

where \(\Delta[f]\) is the determinant

(2.1.22)
\[ \Delta[f] = \begin{vmatrix} 1 & x_0 & \ldots & x_0^{n-1} & f(x_0) \\ 0 & (x_0)' & \ldots & (x_0^{n-1})' & f'(x_0) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & (x_0)^{(n_0-1)} & \ldots & (x_0^{n-1})^{(n_0-1)} & f^{(n_0-1)}(x_0) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ \ldots & \ldots & \ldots & \ldots & \ldots \end{vmatrix} \]

2.3.1. Theorem 2.3.1. If the nodes \(x_0, x_1, \ldots, x_k\) are such that

(2.3.1)
\[ x_0 \lt x_1 \lt \ldots \lt x_k, \]

then in the divided difference (2.1.27) of the function \(f\) on the nodes \(x_0, x_1, \ldots, x_k\) of multiplicities \(n_0, n_1, \ldots, n_k\), the coefficients of \(f(x_0), f'(x_0), \ldots, f^{(n_0-1)}(x_0)\) and those of \(f(x_k), f'(x_k), \ldots, f^{(n_k-1)}(x_k)\) are different from zero.

Clearly it suffices to prove only one of the parts of the theorem. The other part is proved in an analogous way.

We have already proved, in Theorem 2.2.1, that the coefficient \(\lambda_k^{(n_k-1)}\) is different from zero. It remains to prove Theorem 2.3.1 for the coefficients \(\lambda_k, \lambda_k^{(1)}, \ldots, \lambda_k^{(n_k-2)}\).

2.3.2. Let us first prove that \(\lambda_k \neq 0\). This amounts to proving that the determinant

(2.3.2)
\[ d_{n_k-1} = \begin{vmatrix} 1 & x_0 & \ldots & x_0^{n-1} \\ 0 & 1 & \ldots & (x_0^{n-1})' \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_0^{n-1})^{(n_0-1)} \\ \ldots & \ldots & \ldots & \ldots \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_{k-1}^{n-1})^{(n_{k-1}-1)} \\ 0 & 1 & \ldots & (x_k^{n-1})' \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{n-1})^{(n_k-1)} \end{vmatrix} \]

where \(n + 1 = n_0 + n_1 + \ldots + n_{k-1} + n_k\), is different from zero.

For brevity we write the determinant (2.3.2) in the form

(2.3.3)
\[ d_{n_k-1} = \begin{vmatrix} \ldots & \ldots & \ldots & \ldots \\ 0 & 1 & \ldots & (x_k^{n-1})' \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{n-1})^{(n_k-1)} \end{vmatrix} \]

We shall put

(2.3.4)
\[ n_0 + n_1 + \ldots + n_{k-1} = N \quad\text{and}\quad n_k - 1 = j. \]

Then formula (2.3.3) becomes

(2.3.5)
\[ d_j = \begin{vmatrix} \ldots & \ldots & \ldots & \ldots \\ 0 & 1 & \ldots & (x_k^{N+j-1})' \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{N+j-1})^{(j)} \end{vmatrix} \]

2.3.3. Let us first prove that the determinant

(2.3.6)
\[ d_1 = \begin{vmatrix} \ldots & \ldots & \ldots & \ldots \\ 0 & 1 & \ldots & (x_k^N)' \end{vmatrix} \]

is different from zero.

To this end we consider the polynomial

(2.3.7)
\[ \Delta_1(x) = \begin{vmatrix} \ldots & \ldots & \ldots & \ldots \\ 1 & x & \ldots & x^N \end{vmatrix} \]

which is of degree \(N\), because the coefficient of \(x^N\) is the generalized Vandermonde determinant

\[ V = V(\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_{k-1}, \ldots, x_{k-1}}_{n_{k-1}}) \]

which is different from zero. We can write

\[ \Delta_1(x) = V\, (x - x_0)^{n_0}(x - x_1)^{n_1} \ldots (x - x_{k-1})^{n_{k-1}}. \]

The polynomial \(\Delta_1\) has all its roots real and lying in the interval \([x_0, x_{k-1}]\). The derivative \(\Delta_1'\) likewise has all its roots real and lying in the same interval. It follows that \(\Delta_1'(x) \neq 0\) for \(x \gt x_{k-1}\), and in particular that \(\Delta_1'(x_k) \neq 0\). But \(\Delta_1'(x_k) = d_1\), and therefore we have proved that \(d_1 \neq 0\).

2.3.4. To prove that the determinant (2.3.5) is different from zero, we use the method of complete induction.

Let us suppose that the determinant (2.3.5) is different from zero for the index \(j\), which was proved in subsection 2.3.3 for \(j = 1\), and let us prove that the determinant

(2.3.8)
\[ d_{j+1} = \begin{vmatrix} \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 1 & \ldots & (x_k^{N+j-1})' & (x_k^{N+j})' \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{N+j-1})^{(j)} & (x_k^{N+j})^{(j)} \\ 0 & 0 & \ldots & (x_k^{N+j-1})^{(j+1)} & (x_k^{N+j})^{(j+1)} \end{vmatrix} \]

is different from zero.

To this end we introduce the polynomial

(2.3.9)
\[ \Delta_{j+1}(x) = \begin{vmatrix} \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 1 & \ldots & (x_k^{N+j-1})' & (x_k^{N+j})' \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{N+j-1})^{(j)} & (x_k^{N+j})^{(j)} \\ 1 & x & \ldots & x^{N+j-1} & x^{N+j} \end{vmatrix} \]

which is of degree \(N + j\), because the coefficient of \(x^{N+j}\) is the determinant \(d_j\), which we have assumed to be different from zero. We can write

\[ \Delta_{j+1}(x) = (x - x_0)^{n_0}(x - x_1)^{n_1} \ldots (x - x_{k-1})^{n_{k-1}} U_j(x), \]

where \(U_j(x)\) is a polynomial of degree \(j\).

The polynomial \(\Delta_{j+1}\) has \(n_0 + n_1 + \ldots + n_{k-1} = N\) real roots lying in the interval \([x_0, x_{k-1}]\). The derivative \(\Delta_{j+1}'\) has \(N-1\) real roots lying in the same interval, and the root \(x_k\) of multiplicity \(j\), which means that \(\Delta_{j+1}'\) has all its roots real and lying in the interval \([x_0, x_k]\). It then follows that the derivative \((\Delta_{j+1}')^{(j)} = \Delta_{j+1}^{(j+1)}\) has all its roots real and lying in the interval \([x_0, x_k)\). We deduce that \(\Delta_{j+1}^{(j+1)}(x_k) \neq 0\). But \(\Delta_{j+1}^{(j+1)}(x_k) = d_{j+1}\), and therefore \(d_{j+1} \neq 0\).

Thus we have proved that the coefficient \(\lambda_k\) is different from zero.

2.3.5. To prove that \(\lambda_k^{(l)} \neq 0\), where \(l\) is one of the numbers \(1, 2, \ldots, n_k-2\), we must prove that the determinant

(2.3.10)
\[ d_{n_k-1}^{(l)} = \begin{vmatrix} 1 & x_0 & \ldots & x_0^{n-1} \\ 0 & 1 & \ldots & (x_0^{n-1})' \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_0^{n-1})^{(n_0-1)} \\ \ldots & \ldots & \ldots & \ldots \\ \ldots & \ldots & \ldots & \ldots \\ 1 & x_k & \ldots & x_k^{n-1} \\ 0 & 1 & \ldots & (x_k^{n-1})' \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{n-1})^{(l-1)} \\ 0 & 0 & \ldots & (x_k^{n-1})^{(l+1)} \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{n-1})^{(n_k-1)} \end{vmatrix} \]

where \(n + 1 = n_0 + n_1 + \ldots + n_{k-1} + n_k\), is different from zero.

For brevity, let us write the preceding determinant in the form

(2.3.11)
\[ d_{n_k-1}^{(l)} = \begin{vmatrix} \ldots & \ldots & \ldots & \ldots \\ 1 & x_k & \ldots & x_k^{n-1} \\ 0 & 1 & \ldots & (x_k^{n-1})' \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{n-1})^{(l-1)} \\ 0 & 0 & \ldots & (x_k^{n-1})^{(l+1)} \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{n-1})^{(n_k-1)} \end{vmatrix} \]

We shall put \(n_0 + n_1 + \ldots + n_{k-1} = N\), \(n_k - 1 = l + j\), and therefore \(n = N + l + j\). Then the determinant (2.3.11) becomes

(2.3.12)
\[ d_{l+j}^{(l)} = \begin{vmatrix} \ldots & \ldots & \ldots & \ldots \\ 1 & x_k & \ldots & x_k^{N+l+j-1} \\ 0 & 1 & \ldots & (x_k^{N+l+j-1})' \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{N+l+j-1})^{(l-1)} \\ 0 & 0 & \ldots & (x_k^{N+l+j-1})^{(l+1)} \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{N+l+j-1})^{(l+j)} \end{vmatrix} \]

Let us first prove that for \(j = 1\) the determinant

(2.3.13)
\[ d_{l+1}^{(l)} = \begin{vmatrix} \ldots & \ldots & \ldots & \ldots \\ 1 & x_k & \ldots & x_k^{N+l} \\ 0 & 1 & \ldots & (x_k^{N+l})' \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{N+l})^{(l-1)} \\ 0 & 0 & \ldots & (x_k^{N+l})^{(l+1)} \end{vmatrix} \]

is different from zero.

To this end we consider the polynomial

(2.3.14)
\[ \Delta_{l+1}(x) = \begin{vmatrix} \ldots & \ldots & \ldots & \ldots \\ 1 & x_k & \ldots & x_k^{N+l} \\ 0 & 1 & \ldots & (x_k^{N+l})' \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{N+l})^{(l-1)} \\ 1 & x & \ldots & x^{N+l} \end{vmatrix} \]

which is of degree \(N + l\), because the coefficient of \(x^{N+l}\) is the generalized Vandermonde determinant

\[ V = V(\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_{k-1}, \ldots, x_{k-1}}_{n_{k-1}}, \underbrace{x_k, \ldots, x_k}_{l}) \]

which is not zero.

We can write

\[ \Delta_{l+1}(x) = V(x - x_0)^{n_0} \ldots (x - x_{k-1})^{n_{k-1}}(x - x_k)^l. \]

All the roots of the polynomial \(\Delta_{l+1}\) are real and lie in the interval \([x_0, x_k]\). It follows that the roots of the successive derivatives of this polynomial are real and lie in the same interval. In particular, the roots of \(\Delta_{l+1}^{(l+1)}\) are all contained in the interval \([x_0, x_k)\), so that \(\Delta_{l+1}^{(l+1)}(x_k) \neq 0\). But \(\Delta_{l+1}^{(l+1)}(x_k) = d_{l+1}^{(l)}\), and therefore we have proved that \(d_{l+1}^{(l)} \neq 0\).

2.3.6. We shall prove by the method of complete induction that the determinant \(d_{l+j}^{(l)}\) is different from zero. We have already seen in subsection 2.3.5 that \(d_{l+1}^{(l)} \neq 0\). We shall suppose that for the index \(j\) we have \(d_{l+j}^{(l)} \neq 0\), and we shall prove that the determinant

(2.3.15)
\[ d_{l+j+1}^{(l)} = \begin{vmatrix} \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & x_k & \ldots & x_k^{N+l+j-1} & x_k^{N+l+j} \\ 0 & 1 & \ldots & (x_k^{N+l+j-1})' & (x_k^{N+l+j})' \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{N+l+j-1})^{(l-1)} & (x_k^{N+l+j})^{(l-1)} \\ 0 & 0 & \ldots & (x_k^{N+l+j-1})^{(l+1)} & (x_k^{N+l+j})^{(l+1)} \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{N+l+j-1})^{(l+j+1)} & (x_k^{N+l+j})^{(l+j+1)} \end{vmatrix} \]

is also different from zero.

To this end we consider the polynomial

(2.3.16)
\[ \Delta_{l+j+1}(x) = \begin{vmatrix} \ldots & \ldots & \ldots & \ldots \\ 1 & x_k & \ldots & x_k^{N+l+j} \\ 0 & 1 & \ldots & (x_k^{N+l+j})' \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{N+l+j})^{(l-1)} \\ 0 & 0 & \ldots & (x_k^{N+l+j})^{(l+1)} \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{N+l+j})^{(l+j)} \\ 1 & x & \ldots & x^{N+l+j} \end{vmatrix} \]

which is of degree \(N + l + j\), because the coefficient of \(x^{N+l+j}\) is the determinant \(d_{l+j}^{(l)}\), which we have assumed to be different from zero.

We can write the polynomial \(\Delta_{l+j+1}\) in the form

\[ \Delta_{l+j+1}(x) = (x - x_0)^{n_0}(x - x_1)^{n_1} \ldots (x - x_{k-1})^{n_{k-1}}(x - x_k)^l U_j(x), \]

where \(U_j(x)\) is a polynomial of degree \(j\).

The polynomial \(\Delta_{l+j+1}\), of degree \(N + l + j\), has \(N + l\) roots on the interval \([x_0, x_k]\). It follows that the derivative \(\Delta_{l+j+1}^{(l)}\) has \(N + j\) roots on the interval \([x_0, x_k]\). The polynomial \(\Delta_{l+j+1}^{(l)}\) no longer has the root \(x_k\), because \(\Delta_{l+j+1}^{(l)}(x_k)\) is a generalized Vandermonde determinant, which is not zero. But the derivative \((\Delta_{l+j+1}^{(l)})' = \Delta_{l+j+1}^{(l+1)}\) has the root \(x_k\) of multiplicity \(j\). Finally, the derivative \((\Delta_{l+j+1}^{(l+1)})^{(j)} = \Delta_{l+j+1}^{(l+j+1)}\), of degree \(N - 1\), has all its \(N-1\) roots real and lying in the interval \([x_0, x_k]\). We therefore have \(\Delta_{l+j+1}^{(l+j+1)}(x_k) \neq 0\). But \(\Delta_{l+j+1}^{(l+j+1)}(x_k) = d_{l+j+1}^{(l)}\), and therefore \(d_{l+j+1}^{(l)} \neq 0\).

Thus Theorem 2.3.1 is proved.

§ 2.4. The fundamental theorem on the function \(\varphi\)

The aim of this section is to prove that the function \(\varphi\) in the integral representation

(2.1.28)
\[ [\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f] = \int_{x_0}^{x_k} \varphi f^{(n)}\, ds \]

is positive on the interval \((x_0, x_k)\), as in the case of simple nodes (Theorem 1.1.4).

2.4.1. Let us denote by \(n-n_i-1\) the smallest number of the sequence

(2.4.1)
\[ n - n_1 - 1,\ n - n_2 - 1,\ \ldots,\ n - n_{k-1} - 1 \]

and let us observe that the function \(\varphi\) is continuous on the interval \([x_0, x_k]\), together with its successive derivatives up to order \(n-n_i-1\). The derivatives of order higher than \(n-n_i-1\) are continuous on certain subintervals of \([x_0, x_k]\). In particular, the function \(\varphi\) is continuous, together with its successive derivatives up to the \(n^{\text{th}}\) order, on each interval \([x_0, x_1], [x_1, x_2], \ldots, [x_{k-1}, x_k]\).

The theorem on the sign of the function \(\varphi\) on the interval \((x_0, x_k)\) will be easily deduced from the following theorem:

Theorem 2.4.1. The number \(N\) of zeros of the derivative \(\varphi^{(n-n_i-1)}\) on the interval \((x_0, x_k)\) is at most equal to

(2.4.2)
\[ N = n + n_i - n_0 - n_k + 1 \]

when \(n - n_0 - 1 \lt n - n_i - 1\) and \(n - n_k - 1 \lt n - n_i - 1\), or

(2.4.3)
\[ N = n - n_0 \]

when \(n - n_0 - 1 \lt n - n_i - 1 \leq n - n_k - 1\), or

(2.4.4)
\[ N = n - n_k \]

when \(n - n_k - 1 \lt n - n_i - 1 \leq n - n_0 - 1\), or

(2.4.5)
\[ N = n - n_i - 1 \]

when \(n - n_0 - 1 \geq n - n_i - 1\) and \(n - n_k - 1 \geq n - n_i - 1\).

We shall prove this theorem in stages, using several auxiliary lemmas.

2.4.2. Let us consider an interval \([x_j, x_{j+1})\) with \(j \gt 0\), and let us attach the numbers \(n-n_j-1\) and \(n-n_{j+1}-1\) to its endpoints. We have

First lemma. The number of zeros of the derivative \(\varphi^{(n-n_j-1)}\) on the interval \([x_j, x_{j+1})\) is at most \(m_j = n_j\).

Likewise, the number of zeros of \(\varphi^{(n-n_{j+1}-1)}\) on the interval \([x_j, x_{j+1})\) is at most \(m'_j = n_{j+1}\).

It suffices to prove the first part of the lemma.

To this end we shall prove that the derivative \(\varphi^{(n-n_j-1)}\) cannot have \(n_j + 1\) zeros on the interval \([x_j, x_{j+1})\).

Indeed, let us suppose that on the interval \([x_j, x_{j+1})\) the number of zeros of \(\varphi^{(n-n_j-1)}\) is equal to \(n_j + 1\). Since this number is at least 2, we may apply Rolle's theorem. We deduce that the derivative \(\varphi^{(n-n_j)}\) has \(n_j\) zeros on the interval \([x_j, x_{j+1})\), that \(\varphi^{(n-n_j+1)}\) has \(n_j - 1\) zeros on the same interval, \(\ldots\), and that \(\varphi^{(n-1)}\) must have one zero on the same interval. But this is impossible because, by Theorem 2.2.5, the derivative \(\varphi^{(n-1)}\) is equal to the constant \(\lambda_0 + \lambda_1 + \ldots + \lambda_j\), which is different from zero. Hence the number of zeros of the derivative \(\varphi^{(n-n_j-1)}\) on the interval \([x_j, x_{j+1})\) is at most \(m_j = n_j\).

The second part of the lemma is proved in the same way.

2.4.3. Let us consider three consecutive nodes \(x'_1, x'_2, x'_3\) from the set of nodes \(x_1, x_2, \ldots, x_{k-1}\), with their multiplicities \(n'_1, n'_2, n'_3\).

Second lemma. If \(n-n'_1-1 \leq n-n'_2-1\), the number of zeros of \(\varphi^{(n-n'_1-1)}\) on the interval \([x'_1, x'_3)\) is at most \(m = n'_1 + n'_2\).

If \(n-n'_3-1 \leq n-n'_2-1\), the number of zeros of \(\varphi^{(n-n'_3-1)}\) on the interval \([x'_1, x'_3)\) is at most \(m' = n'_2 + n'_3\).

This lemma is evident if \(n'_2 = n'_1\), because in this case the number of zeros of \(\varphi^{(n-n'_1-1)}\) on the interval \([x'_1, x'_3)\) is equal to the number of zeros of \(\varphi^{(n-n'_2-1)}\) on the same interval, that is, on the interval \([x'_1, x'_2)\) and on \([x'_2, x'_3)\). But by the first lemma this number is \(n'_2 + n'_2 = 2n'_2\), and therefore the lemma is proved.

Let us now suppose that \(n-n'_1-1 \lt n-n'_2-1\) and let us prove that the number of zeros of the derivative \(\varphi^{(n-n'_1-1)}\) on the interval \([x'_1, x'_3)\) is \(m = n'_1 + n'_2\). To this end we first observe that the derivative \(\varphi^{(n-n'_1-1)}\) is continuous on the interval \([x'_1, x'_3)\), together with its successive derivatives up to order \(n-n'_2-1\). Let us prove that it is impossible for \(\varphi^{(n-n'_1-1)}\) to have \(n'_1 + n'_2 + 1\) zeros on the interval \([x'_1, x'_3)\).

Indeed, supposing that \(\varphi^{(n-n'_1-1)}\) had \(n'_1 + n'_2 + 1\) zeros on the interval \([x'_1, x'_3)\), the derivative \(\varphi^{(n-n'_1)}\) would have to have \(n'_1 + n'_2\) zeros on the interval \([x'_1, x'_3), \ldots\), and the derivative \(\varphi^{(n-n'_2-1)}\) would have to have \(2n'_2 + 1\) zeros on the interval \([x'_1, x'_3)\). But this is impossible because, by the first lemma, \(\varphi^{(n-n'_2-1)}\) has at most \(n'_2\) zeros on the interval \([x'_1, x'_2)\) and \(n'_2\) zeros on the interval \([x'_2, x'_3)\), that is, at most \(2n'_2\) zeros on the interval \([x'_1, x'_3)\). Comparing these two results we find a contradiction, and therefore the number of zeros of \(\varphi^{(n-n'_1-1)}\) on the interval \([x'_1, x'_3)\) is at most \(m = n'_1 + n'_2\).

The second part of the lemma is proved analogously.

2.4.4. Let us consider a group of consecutive nodes \(x'_1, x'_2, \ldots, x'_r\) from the set \(x_1, x_2, \ldots, x_k\), where \(r \gt 3\), with their multiplicities, which we denote by \(n'_1, n'_2, \ldots, n'_r\). We denote by \(n-n'-1\) the smallest number of the sequence

(2.4.6)
\[ n - n'_2 - 1,\ n - n'_3 - 1,\ \ldots,\ n - n'_{r-1} - 1. \]

We have

Third lemma. If \(n-n'_1-1\) and \(n-n'_r-1 \leq n-n'-1\), the number of zeros of \(\varphi^{(n-n'_1-1)}\) on the interval \([x'_1, x'_r)\) is at most

(2.4.7)
\[ m = n'_1 + n'_2 + \ldots + n'_{r-1} \]

and the number of zeros of \(\varphi^{(n-n'_r-1)}\) on the interval \([x'_1, x'_r)\) is at most:

(2.4.8)
\[ m' = n'_2 + n'_3 + \ldots + n'_r. \]

For \(r = 3\) the sequence (2.4.6) reduces to its first term and the third lemma coincides with the second lemma; hence it is true.

To prove the third lemma we use the method of complete induction, and we already know that this lemma is true for \(r = 3\), because in this case the third lemma coincides with the second lemma. We shall suppose that the third lemma has been proved for \(r \lt l\) and we shall prove it for \(r = l\).

For this purpose we denote by \(n - n'_j - 1\) the smallest number of the sequence

(2.4.9)
\[ n - n'_2 - 1,\ n - n'_3 - 1,\ \ldots\ n - n'_{l-1} - 1, \]

and by \(x'_j\) one of the points \(x'_2, x'_3, \ldots, x'_{l-1}\) which corresponds to \(n - n'_j - 1\). We obviously have \(j \lt l\).

If \(n - n'_1 - 1 = n - n'_j - 1\), that is, \(n'_1 = n'_j\), then the number of zeros of \(\varphi^{(n-n'_1-1)}\) on the interval \([x'_1, x'_l)\) is equal to the number of zeros of \(\varphi^{(n-n'_j-1)}\) on the same interval. Since we have assumed the third lemma for \(r = j \lt l\), we may apply it, and hence the number of zeros of \(\varphi^{(n-n'_j-1)}\) on the interval \([x'_1, x'_l)\) is equal to the sum of the numbers of zeros of \(\varphi^{(n-n'_j-1)}\) on the intervals \([x'_1, x'_j)\) and \([x'_j, x'_l)\); it is at most equal to \((n'_2 + n'_3 + \ldots + n'_j) + (n'_j + n'_{j+1} + \ldots + n'_{l-1})\), and since \(n'_j = n'_1\), the preceding number is \(m = n'_1 + n'_2 + \ldots + n'_{l-1}\), which proves the third lemma.

Let us now suppose that \(n-n'_1-1 \lt n-n'_j-1\) and prove that the derivative \(\varphi^{(n-n'_1-1)}\) cannot have more than \(m = n'_1 + n'_2 + \ldots + n'_{l-1}\) zeros on the interval \([x'_1, x'_l)\).

To this end let us assume the contrary, namely that \(\varphi^{(n-n'_1-1)}\) had

(2.4.10)
\[ n'_1 + n'_2 + \ldots + n'_{l-1} + 1, \]

zeros on the interval \([x'_1, x'_l)\). By the boundary conditions (2.1.7) and the hypothesis that \(n-n'_j-1\) is the smallest of the numbers of the sequence (2.4.9), the function \(\varphi\) is continuous on the interval \([x'_1, x'_l)\), together with its successive derivatives up to order \(n - n'_j - 1\). Then, applying Rolle's theorem, we deduce that the derivative \(\varphi^{(n-n'_1)}\) would have to have \(n'_1 + n'_2 + \ldots + n'_{l-1}\) zeros on the interval \([x'_1, x'_l), \ldots\), and that the derivative \(\varphi^{(n-n'_1+n'_1-n'_j-1)} = \varphi^{(n-n'_j-1)}\) would have to have

(2.4.11)
\[ n'_2 + n'_3 + \ldots + n'_{l-1} + n'_j + 1, \]

zeros on the interval \([x'_1, x'_l)\).

By the third lemma, which we have assumed for \(j \lt l\), the derivative \(\varphi^{(n-n'_j-1)}\) has \(n'_2 + \ldots + n'_j\) zeros on the interval \([x'_1, x'_j)\) and \(n'_j + n'_{j+1} + \ldots + n'_{l-1}\) zeros on the interval \([x'_j, x'_l)\), that is,

(2.4.12)
\[ n'_2 + n'_3 + \ldots + n'_{l-1} + n'_j \]

zeros on the interval \([x'_1, x'_l)\). There is a contradiction between the numbers (2.4.11) and (2.4.12). We must therefore discard the hypothesis that the derivative \(\varphi^{(n-n'_1-1)}\) had \(n'_1 + n'_2 + \ldots + n'_{l-1} + 1\) zeros on the interval \([x'_1, x'_l)\), and consequently the number of zeros of \(\varphi^{(n-n'_1-1)}\) on the interval \([x'_1, x'_l)\) is at most \(m = n'_1 + n'_2 + \ldots + n'_{l-1}\).

Thus the first part of the third lemma is proved, and the second part is proved analogously.

2.4.5. Fourth lemma. If \(n-n_0-1 \lt n-n_1-1\), the number of zeros of \(\varphi^{(n-n_1-1)}\) on the interval \((x_0, x_1)\) is at most

(2.4.13)
\[ m = n_1 \]

and if \(n - n_0 - 1 \geq n - n_1 - 1\), the number of zeros of \(\varphi^{(n-n_1-1)}\) on the interval \((x_0, x_1)\) is at most

(2.4.14)
\[ m = n_0 - 1. \]

Let us first prove the first part of the lemma.

To this end we shall prove that it is impossible for the derivative \(\varphi^{(n-n_1-1)}\) to have \(n_1 + 1\) zeros on the interval \((x_0, x_1)\).

Indeed, let us suppose that \(\varphi^{(n-n_1-1)}\) had \(n_1 + 1\) zeros on the interval \((x_0, x_1)\). Then, applying Rolle's theorem, we deduce that \(\varphi^{(n-n_1)}\) would have to have \(n_1\) zeros on the interval \((x_0, x_1), \ldots\) and that \(\varphi^{(n-1)}\) would have to have one zero on the interval \((x_0, x_1)\). But this is impossible by Theorems 2.2.2 and 2.2.5.

The contradiction brought to light by this reasoning shows that the derivative \(\varphi^{(n-n_1-1)}\) has at most \(m = n_1\) zeros on the interval \((x_0, x_1)\).

Let us now pass to the second part of the lemma, supposing that \(n-n_0-1 \geq n-n_1-1\). In this case the reasoning must take into account the boundary conditions at the point \(x_0\)

(2.4.15)
\[ \varphi(x_0) = 0,\ \varphi'(x_0) = 0,\ \ldots,\ \varphi^{(n-n_0-1)}(x_0) = 0. \]

In this case we have to prove that the derivative \(\varphi^{(n-n_1-1)}\) has at most \(n_0 - 1\) zeros on the interval \((x_0, x_1)\).

To this end let us prove that it is impossible for the derivative \(\varphi^{(n-n_1-1)}\) to have \(n_0\) zeros on the interval \((x_0, x_1)\).

Rolle's theorem can then be applied, taking into account the boundary conditions (2.4.15):

(2.4.16)
\[ \varphi^{(n-n_1-1)}(x_0) = 0,\ \varphi^{(n-n_1)}(x_0) = 0,\ \ldots,\ \varphi^{(n-n_0-1)}(x_0) = 0. \]

The derivative \(\varphi^{(n-n_1)}\) would have \(n_0\) zeros on the interval \((x_0, x_1)\); \(\varphi^{(n-n_1+1)}\) would likewise have \(n_0\) zeros on the interval \((x_0, x_1), \ldots\), \(\varphi^{(n-n_0)}\) would still have \(n_0\) zeros on the interval \((x_0, x_1)\). Further, since the successive derivatives no longer vanish at \(x_0\), the derivative \(\varphi^{(n-n_0+1)}\) would have \(n_0 - 1\) zeros on the interval \((x_0, x_1), \ldots\), and the derivative \(\varphi^{(n-1)}\) would have one zero on the interval \((x_0, x_1)\). But this is impossible by Theorems 2.2.2 and 2.2.5.

Again we have a contradiction, and therefore the number of zeros of \(\varphi^{(n-n_1-1)}\), when \(n-n_0-1 \geq n-n_1-1\), on the interval \((x_0, x_1)\) is at most \(m = n_0 - 1\).

The fourth lemma is thus proved.

2.4.6. Let us suppose that in the sequence

(2.4.16′)
\[ n - n_1 - 1,\ n - n_2 - 1,\ \ldots,\ n - n_h - 1 \]

which corresponds to the nodes \(x_1, x_2, \ldots, x_h\), the last term is smaller than the others.

Then we have:

Fifth lemma. If \(n-n_0-1 \lt n-n_h-1\), the number of zeros of \(\varphi^{(n-n_h-1)}\) on the interval \((x_0, x_h)\) is at most

(2.4.17)
\[ m = n_1 + n_2 + \ldots + n_h. \]

If \(n - n_0 - 1 \geq n - n_h - 1\), the number of zeros of \(\varphi^{(n-n_h-1)}\) on the interval \((x_0, x_h)\) is at most

(2.4.18)
\[ m = n_0 - 1 + n_1 + \ldots + n_{h-1}. \]

This lemma is true for \(h = 1\), because in this case it coincides with the fourth lemma.

We shall carry out the proof of this lemma by the method of complete induction. Let us suppose that the fifth lemma has been proved for \(h \lt j\) and let us prove it for \(h = j\).

Let us consider the sequence

(2.4.19)
\[ n-n_1-1,\ n-n_2-1,\ \ldots,\ n-n_{j-1}-1,\ n-n_j-1 \]

and suppose that \(n - n_j - 1\) is the smallest term of the sequence.

Let us further consider the sequence

(2.4.20)
\[ n-n_1-1,\ n-n_2-1,\ \ldots,\ n-n_{j-1}-1 \]

and suppose that \(n-n_l-1\) is the smallest term of this sequence.

Let us denote by \(x_l\) the node closest to \(x_0\) which corresponds to \(n-n_l-1\).

By the boundary conditions (2.1.7), the function \(\varphi\) is continuous on the interval \([x_0, x_j]\), together with its successive derivatives up to order \(n-n_l-1\).

We shall examine successively the following three cases:

(2.4.21)
\[ \begin{gathered} n-n_0-1 \lt n-n_j-1;\quad n-n_0-1 = n-n_j-1; \\ n-n_0-1 \gt n-n_j-1. \end{gathered} \]

1° Let us first suppose that \(n-n_0-1 \lt n-n_j-1\). Let us prove that the derivative \(\varphi^{(n-n_j-1)}\) has at most \(n_1 + n_2 + \ldots + n_j\) zeros on the interval \((x_0, x_j)\).

To this end let us suppose the contrary, namely that \(\varphi^{(n-n_j-1)}\) had

(2.4.22)
\[ n_1 + n_2 + \ldots + n_j + 1, \]

zeros on the interval \((x_0, x_j)\), and let us show that this hypothesis leads to a contradiction.

We can apply Rolle's theorem to the derivative \(\varphi^{(n-n_j-1)}\) and to its successive derivatives with respect to the interval \([x_0, x_j]\). We deduce that \(\varphi^{(n-n_j)}\) would have at most \(n_1 + n_2 + \ldots + n_j\) zeros on the interval \((x_0, x_j), \ldots\), and that \(\varphi^{(n-n_l-1)}\) would have

(2.4.23)
\[ n_1 + n_2 + \ldots + n_{j-1} + n_l + 1 \]

zeros on the interval \((x_0, x_j)\).

But we have \(l \lt j\) and \(n-n_0-1 \lt n-n_l-1\), so that the number of zeros of \(\varphi^{(n-n_l-1)}\) on the interval \((x_0, x_l)\) is at most \(n_1 + n_2 + \ldots + n_l\), by the fifth lemma, which we have assumed for \(l \lt j\). On the other hand, the number of zeros of \(\varphi^{(n-n_l-1)}\) on the interval \([x_l, x_j)\) is given by the third lemma, and it is at most equal to \(n_l + n_{l+1} + \ldots + n_{j-1}\). Hence the number of zeros of \(\varphi^{(n-n_l-1)}\) on the interval \((x_0, x_j)\) is at most equal to

(2.4.24)
\[ n_1 + n_2 + \ldots + n_{j-1} + n_l. \]

Since there is a disagreement between the numbers (2.4.23) and (2.4.24), we must reject the hypothesis that \(\varphi^{(n-n_j-1)}\) had \(n_1 + n_2 + \ldots + n_j + 1\) zeros on the interval \((x_0, x_j)\), and therefore \(\varphi^{(n-n_j-1)}\) has at most \(n_1 + n_2 + \ldots + n_j\) zeros on the interval \((x_0, x_j)\).

Thus the fifth lemma is proved in the case \(n-n_0-1 \lt n-n_j-1\).

2° Let us suppose that \(n-n_0-1 = n-n_j-1\) and let us prove that the number of zeros of \(\varphi^{(n-n_j-1)}\) on the interval \((x_0, x_j)\) is at most \(n_0 - 1 + n_1 + \ldots + n_{j-1}\).

Let us suppose the contrary, namely that the number of zeros of \(\varphi^{(n-n_j-1)}\) on the interval \((x_0, x_j)\) is \(n_0 + n_1 + \ldots + n_{j-1}\). Let us show that this hypothesis leads to a contradiction.

Because of the boundary conditions (2.1.7) at the point \(x_0\), the number of zeros of \(\varphi^{(n-n_j-1)}\) on the interval \([x_0, x_j)\) is \(n_0 + n_1 + \ldots + n_{j-1} + 1\), since, as \(n_j = n_0\), it follows that \(\varphi^{(n-n_j-1)}(x_0) = \varphi^{(n-n_0-1)}(x_0) = 0\). Applying Rolle's theorem we deduce that \(\varphi^{(n-n_j)}\) has \(n_1 + n_2 + \ldots + n_j\) zeros on the interval \((x_0, x_j), \ldots\), and that \(\varphi^{(n-n_l-1)}\) has

(2.4.25)
\[ n_1 + n_2 + \ldots + n_{j-1} + n_l + 1, \]

zeros on the interval \((x_0, x_j)\).

But the number of zeros of \(\varphi^{(n-n_l-1)}\) on the interval \((x_0, x_l)\) is, by the fifth lemma, which we have assumed for \(l \lt j\), equal to \(n_1 + n_2 + \ldots + n_l\), and by the third lemma the number of zeros of \(\varphi^{(n-n_l-1)}\) on the interval \([x_l, x_j)\) is at most \(n_l + n_{l+1} + \ldots + n_{j-1}\). Hence the number of zeros of \(\varphi^{(n-n_l-1)}\) on the interval \([x_0, x_j)\) is the sum \((n_1 + n_2 + \ldots + n_l) + (n_l + n_{l+1} + \ldots + n_{j-1})\), that is,

(2.4.26)
\[ n_1 + n_2 + \ldots + n_{j-1} + n_l. \]

Since there is a contradiction between the numbers (2.4.25) and (2.4.26), it follows that we must reject the hypothesis that the number of zeros of \(\varphi^{(n-n_j-1)}\) on the interval \((x_0, x_j)\) is \(n_0 + n_1 + \ldots + n_{j-1}\), and therefore it is at most equal to \(n_0 - 1 + n_1 + \ldots + n_{j-1}\).

The fifth lemma is therefore proved in the case \(n-n_0-1 = n-n_j-1\).

3°. Let us finally suppose that \(n-n_0-1 \gt n-n_j-1\). In this case we shall examine three cases separately: \(n - n_0 - 1 \lt n - n_l - 1\); \(n - n_0 - 1 = n - n_l - 1\); \(n - n_0 - 1 \gt n - n_l - 1\).

Let us prove that in these cases the number of zeros of \(\varphi^{(n-n_j-1)}\) on the interval \((x_0, x_j)\) is at most \(n_0 - 1 + n_1 + \ldots + n_{j-1}\).

a) Let us first suppose that \(n-n_0-1 \lt n-n_l-1\). Since \(n-n_j-1 \lt n-n_0-1\), we must take into account that, by the boundary conditions (2.1.7) at the point \(x_0\), we have

(2.4.27)
\[ \varphi^{(n-n_j-1)}(x_0) = 0,\ \varphi^{(n-n_j)}(x_0) = 0,\ \ldots,\ \varphi^{(n-n_0-1)}(x_0) = 0. \]

Let us prove that it is impossible for the number of zeros of \(\varphi^{(n-n_j-1)}\) on the interval \((x_0, x_j)\) to be \(n_0 + n_1 + \ldots + n_{j-1}\).

Indeed, in this case the number of zeros of \(\varphi^{(n-n_j-1)}\) on the interval \((x_0, x_j)\) is \(n_0 + n_1 + \ldots + n_{j-1} + 1\). Applying Rolle's theorem we deduce that the number of zeros of \(\varphi^{(n-n_j)}\) on the interval \([x_0, x_j)\) is still \(n_0 + n_1 + \ldots + n_{j-1} + 1 \ldots\), and that the number of zeros of \(\varphi^{(n-n_0-1)}\) on the interval \([x_0, x_j)\) is still \(n_0 + n_1 + \ldots + n_{j-1}\). Then, applying Rolle's theorem again, we deduce that the number of zeros of \(\varphi^{(n-n_0)}\) on the interval \((x_0, x_j)\) is \(n_0 + n_1 + \ldots + n_{j-1}, \ldots\), and that the number of zeros of \(\varphi^{(n-n_l-1)}\) on the interval \((x_0, x_j)\) is

(2.4.28)
\[ n_1 + n_2 + \ldots + n_{j-1} + n_l + 1. \]

But to obtain the number of zeros of \(\varphi^{(n-n_l-1)}\) on the interval \((x_0, x_j)\), we can apply the fifth lemma to the interval \((x_0, x_l)\), since \(l \lt j\), and then the third lemma to the interval \([x_l, x_j)\). This number is at most

(2.4.29)
\[ (n_1 + n_2 + \ldots + n_l) + (n_l + n_{l+1} + \ldots + n_{j-1}) = n_1 + n_2 + \ldots + n_{j-1} + n_l. \]

Since the numbers (2.4.28) and (2.4.29) are different, we must reject the hypothesis that the number of zeros of \(\varphi^{(n-n_j-1)}\) on the interval \((x_0, x_j)\) is \(n_0 + n_1 + \ldots + n_{j-1}\), and therefore this number is \(n_0 + n_1 + \ldots + n_{j-1} - 1\), which proves our lemma.

b) Let us consider the other two cases \(n-n_0-1 \geq n-n_l-1\). We must then take into account that, by the boundary conditions (2.1.7) at the point \(x_0\), we have

(2.4.30)
\[ \varphi^{(n-n_j-1)}(x_0) = 0,\ \varphi^{(n-n_j)}(x_0) = 0,\ \ldots,\ \varphi^{(n-n_l-1)}(x_0) = 0. \]

We shall prove that the number of zeros of \(\varphi^{(n-n_j-1)}\) on the interval \((x_0, x_j)\) is at most equal to \(n_0 - 1 + n_1 + \ldots + n_{j-1}\).

To this end let us suppose that the number of zeros of \(\varphi^{(n-n_j-1)}\) on the interval \((x_0, x_j)\) is \(n_0 + n_1 + \ldots + n_{j-1}\). Applying Rolle's theorem successively and taking into account conditions (2.4.30), we deduce that the number of zeros of \(\varphi^{(n-n_j)}\) on the interval \((x_0, x_j)\) is still \(n_0 + n_1 + \ldots + n_{j-1}, \ldots\) and that the number of zeros of \(\varphi^{(n-n_l-1)}\) on the interval \((x_0, x_j)\) is still

(2.4.31)
\[ n_0 + n_1 + \ldots + n_{j-1}. \]

But the number of zeros of \(\varphi^{(n-n_l-1)}\) on the interval \((x_0, x_j)\) can be found by applying the fifth lemma to the interval \((x_0, x_l)\), bearing in mind that \(n-n_0-1 \geq n-n_l-1\), and by applying the third lemma to the interval \([x_l, x_j)\). This number is therefore

(2.4.32)
\[ (n_0 - 1 + n_1 + \ldots + n_{l-1}) + (n_l + n_{l+1} + \ldots + n_{j-1}) = n_0 + n_1 + \ldots + n_{j-1} - 1. \]

Since there is a disagreement between the numbers (2.4.31) and (2.4.32), we must reject the hypothesis that the number of zeros of \(\varphi^{(n-n_j-1)}\) on the interval \((x_0, x_j)\) is \(n_0 + n_1 + \ldots + n_{j-1}\). Hence it is at most \(n_0 - 1 + n_1 + \ldots + n_{j-1}\), and therefore the fifth lemma is proved in the case \(n-n_0-1 \gt n-n_j-1\) and \(n-n_0-1 \geq n-n_l-1\).

The fifth lemma is thus completely proved.

2.4.7. Let us consider all the nodes \(x_0, x_1, \ldots, x_k\) with their multiplicities \(n_0, n_1, \ldots, n_k\). Let us denote by \(n-n_i-1\) the smallest number of the sequence

(2.4.33)
\[ n-n_1-1,\ n-n_2-1,\ \ldots,\ n-n_{k-1}-1 \]

and by \(x_{i_1}, x_{i_2}, \ldots, x_{i_p}\) the nodes which correspond to \(n-n_i-1\), \(x_{i_1}\) being the one closest to \(x_0\). From the preceding lemmas the following remark results:

Remark. The number of zeros of \(\varphi^{(n-n_i-1)}\) on the interval \((x_0, x_{i_r})\) is at most equal to

(2.4.34)
\[ m = n_1 + n_2 + \ldots + n_{i_r} \]

when \(n-n_0-1 \lt n-n_i-1\), or to

(2.4.35)
\[ m = n_0 - 1 + n_1 + \ldots + n_{i_r-1} \]

when \(n-n_0-1 \geq n-n_i-1\).

Indeed, if \(n-n_0-1 \lt n-n_i-1\), the number of zeros of \(\varphi^{(n-n_i-1)}\) on the interval \((x_0, x_{i_r})\) is equal to the sum of the numbers of zeros of \(\varphi^{(n-n_i-1)}\) on the intervals \((x_0, x_{i_1}), [x_{i_1}, x_{i_2}), \ldots, [x_{i_{r-1}}, x_{i_r})\), which are given, for the first interval, by the fifth lemma and, for the other intervals, by the third lemma. We shall therefore have

\[ m = (n_1 + \ldots + n_{i_1}) + (n_{i_1+1} + \ldots + n_{i_2}) + \ldots + (n_{i_{r-1}+1} + \ldots + n_{i_r}) \]

that is,

\[ m = n_1 + n_2 + \ldots + n_{i_r} \]

which proves formula (2.4.34).

If \(n-n_0-1 \geq n-n_i-1\), the same reasoning shows that

\[ m = (n_0 - 1 + n_1 + \ldots + n_{i_1-1}) + (n_{i_1+1} + \ldots + n_{i_2}) + \ldots + (n_{i_r-1} + \ldots + n_{i_r}) \]

and since \(n_{i_1} = n_{i_r}\), we can write

\[ m = n_0 - 1 + n_1 + \ldots + n_{i_r-1} \]

which proves formula (2.4.35).

2.4.8. Let us consider the sequence of nodes \(x_h, x_{h+1}, \ldots, x_k\) and suppose that the numbers \(n-n_{h+1}-1, n-n_{h+2}-1, \ldots, n-n_{k-1}-1\) are greater than \(n-n_h-1\).

We have:

Sixth lemma. The number of zeros of \(\varphi^{(n-n_h-1)}\) on the interval \((x_h, x_k)\) is at most

(2.4.36)
\[ m' = n_h + n_{h+1} + \ldots + n_{k-1}, \]

when \(n-n_k-1 \lt n-n_h-1\), or

(2.4.37)
\[ m' = n_{h+1} + n_{h+2} + \ldots + n_k - 1, \]

when \(n-n_k-1 \geq n-n_h-1\).

The proof of this lemma is analogous to the proof of the fifth lemma. It is carried out by the method of complete induction, first proving the lemma analogous to the fourth lemma for the nodes \(x_{k-1}, x_k\) and taking into account the boundary conditions at the point \(x_k\). Then one assumes that the sixth lemma has been proved for the sequence of nodes \(x_h, x_{h+1}, \ldots, x_k\), where \(h \gt j\), and one proves the sixth lemma for \(h = j\).

A remark analogous to the one made in subsection 2.4.7 can be added.

2.4.9. The proof of Theorem 2.4.1 follows immediately from the preceding lemmas.

Let us denote, as above, by \(n-n_i-1\) the smallest number of the sequence \(n-n_1-1, n-n_2-1, \ldots, n-n_{k-1}-1\) and by \(x_i\) one of the points which correspond to \(n-n_i-1\).

The number of zeros of \(\varphi^{(n-n_i-1)}\) on the interval \((x_0, x_k)\) is equal to the sum of the numbers of zeros of \(\varphi^{(n-n_i-1)}\) on the intervals \((x_0, x_i)\) and \([x_i, x_k)\). It is at most equal to \(N = m + m'\), where the numbers \(m\) and \(m'\) are given by the fifth lemma and by the sixth lemma, through formulas (2.4.17) and (2.4.36).

1° If \(n-n_0-1\) and \(n-n_k-1 \lt n-n_i-1\), we have \(N = (n_1 + n_2 + \ldots + n_i) + (n_i + \ldots + n_{k-1})\), and, bearing in mind that \(n + 1 = n_0 + n_1 + \ldots + n_k\), we can write

\[ N = n + n_i - n_0 - n_k + 1, \]

so that formula (2.4.2) is proved.

2° If \(n-n_0-1 \lt n-n_i-1 \leq n-n_k-1\), we have \(N = (n_1 + n_2 + \ldots + n_i) + (n_{i+1} + \ldots + n_k - 1)\), that is,

\[ N = n - n_0 \]

and formula (2.4.3) is proved.

3° If \(n-n_k-1 \lt n-n_i-1 \leq n-n_0-1\), we have \(N = (n_0 - 1 + n_1 + \ldots + n_{i-1}) + (n_i + \ldots + n_{k-1})\), that is,

\[ N = n - n_k \]

and formula (2.4.4) is proved.

4° If \(n-n_0-1 \geq n-n_i-1\) and \(n-n_k-1 \geq n-n_i-1\), we have \(N = (n_0 - 1 + n_1 + \ldots + n_{i-1}) + (n_{i+1} + \ldots + n_k - 1)\), that is,

\[ N = n - n_i - 1, \]

and formula (2.4.5) is proved.

2.4.10. Theorem 2.4.2. The function \(\varphi\) in the integral representation (2.1.28) of the divided difference of the function \(f\) on the nodes \(x_0, x_1, \ldots, x_k\) of multiplicities \(n_0, n_1, \ldots, n_k\), when \(f \in C^n[x_0, x_k]\) and \(n + 1 = n_0 + n_1 + \ldots + n_k\), is positive on the interval \((x_0, x_k)\).

Let us denote, as in the preceding subsections, by \(n-n_i-1\) the smallest number of the sequence \(n-n_1-1, n-n_2-1, \ldots, n-n_{k-1}-1\), and let us observe that the function \(\varphi\) is continuous on the interval \((x_0, x_k)\), together with its successive derivatives up to order \(n-n_i-1\), which follows from the boundary conditions (2.1.7). Let us also write the boundary conditions at the points \(x_0, x_k\)

(2.4.38)
\[ \begin{aligned} &\varphi(x_0) = 0,\ \varphi'(x_0) = 0, \ldots, \varphi^{(n-n_0-1)}(x_0) = 0 \\ &\varphi(x_k) = 0,\ \varphi'(x_k) = 0, \ldots, \varphi^{(n-n_k-1)}(x_k) = 0. \end{aligned} \]

To prove Theorem 2.4.2, we first suppose that the function \(\varphi\) vanishes at least once on the interval \((x_0, x_k)\). Then, taking into account this hypothesis and the boundary conditions (2.4.38), we can determine by Rolle's theorem the number \(N'\) of zeros of the derivative \(\varphi^{(n-n_i-1)}\) on the interval \((x_0, x_k)\). But we have shown that the number of zeros of \(\varphi^{(n-n_i-1)}\) is at most equal to the number \(N\) determined by Theorem 2.4.1. We shall show that there is a contradiction between the numbers \(N\) and \(N'\), brought to light by the relation \(N' = N+1\). From this contradiction it will follow that the function \(\varphi\) does not vanish on the interval \((x_0, x_k)\).

We shall prove the formula \(N' = N + 1\) in detail, going again through all the cases examined in subsection 2.4.9, where the proof of Theorem 2.4.1 was given.

1° Let us suppose that \(n-n_0-1\) and \(n-n_k-1 \lt n-n_i-1\). We may restrict ourselves to the case \(n-n_0-1 \lt n-n_k-1\).

Applying Rolle's theorem successively and taking into account the boundary conditions (2.4.38) and the fact that the function \(\varphi\) vanishes at a point of the interval \((x_0, x_k)\), we deduce that the derivative \(\varphi'\) vanishes at two points of the interval \((x_0, x_k)\), \(\ldots\), and that the derivative \(\varphi^{(n-n_0-1)}\) vanishes at \(n - n_0\) points of the interval \((x_0, x_k)\).

Further, the derivative \(\varphi^{(n-n_0)}\) vanishes at \(n-n_0+1\) points of the interval \((x_0, x_k)\), \(\ldots\), and the derivative \(\varphi^{(n-n_k-1)}\) vanishes at \(n - n_0 + 1\) points of the interval \((x_0, x_k)\).

Finally, the derivative \(\varphi^{(n-n_k)}\) vanishes at \(n-n_0+1\) points of the interval \((x_0, x_k)\), the derivative \(\varphi^{(n-n_k+1)}\) vanishes at \(n-n_0\) points of the interval \((x_0, x_k)\), \(\ldots\), and the derivative \(\varphi^{(n-n_i-1)}\) vanishes at \(N' = n + n_i - n_0 - n_k + 2\) points of the interval \((x_0, x_k)\).

But this is impossible because, by Theorem 2.4.1, in the case \(n-n_0-1 \lt n-n_i-1\), \(n-n_k-1 \lt n-n_i-1\), the number of zeros of \(\varphi^{(n-n_i-1)}\) on the interval \((x_0, x_k)\) is at most \(N = n + n_i - n_0 - n_k + 1\).

There is therefore a contradiction between the numbers \(N\) and \(N'\); we have \(N' = N + 1\), and therefore we must reject the hypothesis that the function \(\varphi\) vanishes at least once on the interval \((x_0, x_k)\).

Hence the function \(\varphi\) does not vanish on the interval \((x_0, x_k)\).

By analogous reasoning one reaches the same conclusion when \(n-n_0-1 \geq n-n_k-1\).

2° Let us suppose that \(n-n_0-1 \lt n-n_i-1 \leq n-n_k-1\), and let us assume, as above, that the function \(\varphi\) vanishes at least once on the interval \((x_0, x_k)\). Then, proceeding as in the preceding case, we reach the conclusion that the derivative \(\varphi^{(n-n_i-1)}\) must vanish at \(N' = n-n_0+1\) points of the interval \((x_0, x_k)\).

But, by Theorem 2.4.1, the derivative \(\varphi^{(n-n_i-1)}\) has at most \(N = n-n_0\) zeros on the interval \((x_0, x_k)\).

There is therefore a contradiction between the numbers \(N\) and \(N'\); we have \(N' = N+1\), and therefore we must reject the hypothesis that the function \(\varphi\) vanishes at least once on the interval \((x_0, x_k)\).

Hence the function \(\varphi\) does not vanish on the interval \((x_0, x_k)\).

3°. Let us suppose that \(n-n_k-1 \lt n-n_i-1 \leq n-n_0-1\) and let us assume that the function \(\varphi\) vanishes at least once on the interval \((x_0, x_k)\). Then, proceeding as in the preceding cases, we reach the conclusion that the derivative \(\varphi^{(n-n_i-1)}\) must vanish at \(N' = n-n_k+1\) points of the interval \((x_0, x_k)\).

But, by Theorem 2.4.1, the derivative \(\varphi^{(n-n_i-1)}\) has at most \(N = n-n_k\) zeros on the interval \((x_0, x_k)\).

There is therefore a contradiction between the numbers \(N\) and \(N'\); we have \(N' = N+1\), and therefore we must reject the hypothesis that the function \(\varphi\) vanishes at least once on the interval \((x_0, x_k)\).

Hence the function \(\varphi\) does not vanish on the interval \((x_0, x_k)\).

4°. Let us suppose that \(n-n_0-1 \geq n-n_i-1\) and \(n-n_k-1 \geq n-n_i-1\), and let us assume that the function \(\varphi\) vanishes at least once on the interval \((x_0, x_k)\). Then, proceeding as in the preceding cases, we reach the conclusion that the derivative \(\varphi^{(n-n_i-1)}\) must vanish at \(N' = n-n_i\) points of the interval \((x_0, x_k)\).

But, by Theorem 2.4.1, the derivative \(\varphi^{(n-n_i-1)}\) has at most \(N = n-n_i-1\) zeros on the interval \((x_0, x_k)\).

There is therefore a contradiction between the numbers \(N\) and \(N'\); we have \(N' = N+1\), and therefore we must reject the hypothesis that the function \(\varphi\) vanishes at least once on the interval \((x_0, x_k)\).

Hence the function \(\varphi\) does not vanish on the interval \((x_0, x_k)\).

We have thus proved that in all cases the function \(\varphi\) does not vanish on the interval \((x_0, x_k)\). The sign of the function \(\varphi\) can be found by observing that if in formulas (2.1.27) and (2.1.28) the function \(f(x)\) is replaced by \(x^n\), one finds \(1 = n! \int_{x_0}^{x_k} \varphi(s)\, ds\), whence it follows that the function \(\varphi\) is positive on the interval \((x_0, x_k)\) and we have the formula

(2.4.39)
\[ \int_{x_0}^{x_k} \varphi(s)\, ds = \frac{1}{n!}. \]

2.4.11. Theorem 2.4.3. When \(f \in C^n[x_0, x_k]\) and \(n + 1 = n_0 + n_1 + \ldots + n_k\), the divided difference of the function \(f\) on the nodes \(x_0, x_1, \ldots, x_k\) of multiplicities \(n_0, n_1, \ldots, n_k\) can be written in the form

(2.4.40)
\[ \begin{gathered} {[}\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f] = \frac{f^{(n)}(\xi)}{n!}, \quad \text{where} \\ \xi \in (x_0, x_k). \end{gathered} \]

Indeed, by Theorem 2.4.2 the function \(\varphi\) in the integral representation (2.1.28) is positive on the interval \((x_0, x_k)\) and we have formula (2.4.39). The mean value theorem can be applied, and we are led to formula (2.4.40).

Formula (2.4.40) shows that

(2.4.41)
\[ \left|[\underbrace{x_0, \ldots, x_0}_{n_0}, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k} ; f]\right| \leq \frac{M_n}{n!}. \]

where

(2.4.42)
\[ M_n = \sup_{(x_0, x_k)} |f^{(n)}(x)| \]

§ 2.5. The Lagrange–Hermite interpolation formula

The representation of the divided difference of a function \(f\) on multiple nodes by a definite integral leads in a remarkable way to the Lagrange–Hermite interpolation formula, to its remainder and to the Lagrange–Hermite polynomial.

2.5.1. Let us consider a function \(f\) defined on the interval \((a, b)\) and the nodes \(x_1, x_2, \ldots, x_k\) of multiplicities \(n_1, n_2, \ldots, n_k\), such that \(a \lt x_1 \lt \ldots \lt x_k \lt b\), as well as the simple node \(x \in (a, b)\), which does not coincide with any of the nodes \(x_1, x_2, \ldots, x_k\). The node \(x\) may lie to the left of \(x_1\), to the right of \(x_k\), or in the interval \((x_1, x_k)\).

Let us first suppose that the node \(x \in (x_i, x_{i+1})\), where \(i\) is one of the numbers \(1, 2, \ldots, k-1\). Then we can consider the divided difference

(2.5.1)
\[ [\underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_i, \ldots, x_i}_{n_i}, x, \underbrace{x_{i+1}, \ldots, x_{i+1}}_{n_{i+1}}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f] \]

and its integral representation

(2.5.2)
\[ {[}\underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_i, \ldots, x_i}_{n_i}, x, \underbrace{x_{i+1}, \ldots, x_{i+1}}_{n_{i+1}}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f] = \int_{x_1}^{x_k} \varphi_i(x, s) f^{(n)}(s)\, ds \]

where the number \(n\) is given by the formula

(2.5.3)
\[ n = n_1 + n_2 + \ldots + n_k \]

and where we have denoted the function \(\varphi\) of formula (2.1.28) by \(\varphi_i(x, s)\), to show that it depends on the node \(x \in (x_i, x_{i+1})\).

The left-hand side of formula (2.5.2) can be replaced by

(2.5.4)
\[ {[}x, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f] = \frac{1}{V(x, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k})} \begin{vmatrix} 1 & x & \ldots & x^{n-1} & f(x) \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_1^{n-1})^{(n_1-1)} & f^{(n_1-1)}(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & x_k & \ldots & x_k^{n-1} & f(x_k) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_k^{n-1})^{(n_k-1)} & f^{(n_k-1)}(x_k) \end{vmatrix} \]

and therefore formula (2.5.2) becomes

(2.5.5)
\[ (-1)^n \frac{V(\underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k})}{V(x, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k})} f(x) = \frac{-1}{V(x, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k})} \begin{vmatrix} 1 & x & \ldots & x^{n-1} & 0 \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_1^{n-1})^{(n_1-1)} & f^{(n_1-1)}(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ \ldots & \ldots & \ldots & \ldots & \ldots \end{vmatrix} + \int_{x_1}^{x_k} \varphi_i(x, s) f^{(n)}(s)\, ds \]

But

\[ V(x, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}) = (-1)^n V(\underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}) (x - x_1)^{n_1} \ldots (x - x_k)^{n_k} \]

so that, introducing the polynomial

(2.5.6)
\[ \omega(x) = (x-x_1)^{n_1} (x-x_2)^{n_2} \ldots (x-x_k)^{n_k} \]

we can write

(2.5.7)
\[ (-1)^n \frac{V(x, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k})}{V(\underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k})} = \omega(x) \]

Formula (2.5.5) becomes

(2.5.8)
\[ \begin{gathered} f(x) = \frac{(-1)^{n+1}}{V(\underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k})} \begin{vmatrix} 1 & x & \ldots & x^{n-1} & 0 \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_1^{n-1})^{(n_1-1)} & f^{(n_1-1)}(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \end{vmatrix} + \\ + \omega(x) \int_{x_1}^{x_k} \varphi_i(x, s) f^{(n)}(s)\, ds \end{gathered} \]

The first term of the right-hand side is a polynomial \(H_{n-1}(x)\), which is of degree at most \(n-1\). We shall write

(2.5.9)
\[ H_{n-1}(x) = \frac{(-1)^{n-1}}{V(\underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k})} \begin{vmatrix} 1 & x & \ldots & x^{n-1} & 0 \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_1^{n-1})^{(n_1-1)} & f^{(n_1-1)}(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ \ldots & \ldots & \ldots & \ldots & \ldots \end{vmatrix} \]

Concerning the polynomial \(H_{n-1}\) we have the following two theorems:

Theorem 2.5.1. For the polynomial \(H_{n-1}\) and its successive derivatives we have the following formulas:

(2.5.10)
\[ \begin{array}{llll} H_{n-1}(x_1) = f(x_1) & H_{n-1}(x_2) = f(x_2) & & H_{n-1}(x_k) = f(x_k) \\ H'_{n-1}(x_1) = f'(x_1) & H'_{n-1}(x_2) = f'(x_2) & & H'_{n-1}(x_k) = f'(x_k) \\ \ldots\ldots\ldots\ldots\ldots\ldots & \ldots\ldots\ldots\ldots\ldots\ldots ; & \ldots ; & \ldots\ldots\ldots\ldots\ldots\ldots \\ H_{n-1}^{(n_1-1)}(x_1) = f^{(n_1-1)}(x_1) & H_{n-1}^{(n_2-1)}(x_2) = f^{(n_2-1)}(x_2) & & H_{n-1}^{(n_k-1)}(x_k) = f^{(n_k-1)}(x_k) \end{array} \]

Indeed, replacing \(x\) by \(x_l\) in formula (2.5.9) and in the successive derivatives of both its sides, we can write

\[ \begin{gathered} H_{n-1}(x_l) = \frac{(-1)^{n-1}}{V(\underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k})} \begin{vmatrix} 0 & 0 & \ldots & 0 & -f(x_l) \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_1^{n-1})^{(n_1-1)} & f^{(n_1-1)}(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \end{vmatrix} \\[2ex] H'_{n-1}(x_l) = \frac{(-1)^{n-1}}{V(\underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k})} \begin{vmatrix} 0 & 0 & \ldots & 0 & -f'(x_l) \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_1^{n-1})^{(n_1-1)} & f^{(n_1-1)}(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \end{vmatrix} \\[1ex] \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \end{gathered} \]

which shows that

\[ H_{n-1}(x_l) = f(x_l),\ H'_{n-1}(x_l) = f'(x_l), \ldots, H_{n-1}^{(n_l-1)}(x_l) = f^{(n_l-1)}(x_l) \]

and therefore Theorem 2.5.1 is proved.

Theorem 2.5.2. The polynomial

(2.5.11)
\[ P_{n-1}(x) = A_0 x^{n-1} + A_1 x^{n-2} + \ldots + A_{n-1} \]

of degree at most \(n-1\), whose coefficients are determined by the conditions

(2.5.12)
\[ \begin{array}{lcl} P_{n-1}(x_1) = f(x_1) & & P_{n-1}(x_k) = f(x_k) \\ P'_{n-1}(x_1) = f'(x_1) & & P'_{n-1}(x_k) = f'(x_k) \\ \ldots\ldots\ldots\ldots\ldots\ldots & ; \ldots ; & \ldots\ldots\ldots\ldots\ldots\ldots \\ P_{n-1}^{(n_1-1)}(x_1) = f^{(n_1-1)}(x_1) & & P_{n-1}^{(n_k-1)}(x_k) = f^{(n_k-1)}(x_k) \end{array} \]

and

(2.5.13)
\[ n = n_1 + n_2 + \ldots + n_k \]

is identical with the polynomial \(H_{n-1}\).

Indeed, the equations which determine the coefficients of the polynomial \(P_{n-1}\) are

(2.5.14)
\[ \begin{aligned} A_{n-1} + A_{n-2}x_1 + \ldots + A_0 x_1^{n-1} &= f(x_1) \\ A_{n-2}(x_1)' + \ldots + A_0(x_1^{n-1})' &= f'(x_1) \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots &\ldots\ldots\ldots\ldots \\ A_{n-2}(x_1)^{(n_1-1)} + \ldots + A_0(x_1^{n-1})^{(n_1-1)} &= f^{(n_1-1)}(x_1) \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots &\ldots\ldots\ldots\ldots \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots &\ldots\ldots\ldots\ldots \end{aligned} \]

and the determinant of this system is different from zero.

Eliminating the coefficients \(A_{n-1}, A_{n-2}, \ldots, A_0\) between equations (2.5.11) and (2.5.14), one finds:

(2.5.15)
\[ \begin{vmatrix} 1 & x & \ldots & x^{n-1} & P_{n-1}(x) \\ 1 & x_1 & \ldots & x_1^{n-1} & f(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_1^{n-1})^{(n_1-1)} & f^{(n_1-1)}(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \end{vmatrix} = 0. \]

This equation, solved with respect to \(P_{n-1}(x)\) and compared with \(H_{n-1}(x)\), shows that \(P_{n-1} = H_{n-1}\), and therefore Theorem 2.5.2 is proved.

Formula (2.5.8) can be written in the form

(2.5.4)
\[ f(x) = H_{n-1}(x) + R_i(x). \]

It appears as an approximation formula, which is called the Lagrange–Hermite interpolation formula. The function \(f\) is approximated by the polynomial \(H_{n-1}\), which is called the Hermite interpolation polynomial.

The Hermite interpolation polynomial is given by formula (2.5.9) or by Theorem 2.5.2.

The remainder of formula (2.5.11) is:

(2.5.12)
\[ R_i(x) = \omega(x) \int_{x_1}^{x_k} \varphi_i(x, s) f^{(n)}(s)\, ds ; \]

it depends on \(x\) and on the index \(i\), which indicates that \(x \in (x_i, x_{i+1})\), where \(i\) can be \(1, 2, \ldots, k-1\).

2.5.2. If \(x \lt x_1\), we have the integral representation:

(2.5.13)
\[ [x, \underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}; f] = \int_{x}^{x_k} \varphi_0(x, s) f^{(n)}(s)\, ds, \]

where we have denoted the function \(\varphi\) of formula (2.1.28) by \(\varphi_0(x, s)\), to show that it corresponds to the node \(x \lt x_1\).

Proceeding as in subsection 2.5.1, we arrive at the Lagrange–Hermite interpolation formula

(2.5.14)
\[ f(x) = H_{n-1}(x) + R_0(x), \]

where the remainder of this formula is:

(2.5.15′)
\[ R_0(x) = \omega(x) \int_{x}^{x_k} \varphi_0(x, s) f^{(n)}(s)\, ds. \]

If \(x \gt x_k\), we have the integral representation

(2.5.16)
\[ [\underbrace{x_1, \ldots, x_1}_{n_1}, \ldots, \underbrace{x_k, \ldots, x_k}_{n_k}, x; f] = \int_{x_1}^{x} \varphi_k(x, s) f^{(n)}(s)\, ds, \]

where we have denoted the function \(\varphi\) of formula (2.1.28) by \(\varphi_k(x, s)\), to show that it corresponds to the node \(x \gt x_k\).

Proceeding as in subsection 2.5.1, we arrive at the Lagrange–Hermite interpolation formula:

(2.5.17)
\[ f(x) = H_{n-1}(x) + R_k(x), \]

where the remainder is given by the formula:

(2.5.18)
\[ R_k(x) = \omega(x) \int_{x_1}^{x} \varphi_k(x, s) f^{(n)}(s)\, ds. \]

2.5.3. The function \(\varphi_i(x, s)\) is positive on the interval \((x_1, x_k)\) for \(i = 1, 2, \ldots, k-1\), just like the functions \(\varphi_0(x, s), \varphi_k(x, s)\) on the intervals \((x, x_k), (x_1, x)\). We have

\[ \int_{x_1}^{x_k} \varphi_i(x, s)\, ds = \frac{1}{n!}, \qquad (i = 1, 2, \ldots, k-1) \]

and

\[ \int_{x}^{x_k} \varphi_0(x, s)\, ds = \frac{1}{n!}, \qquad \int_{x_1}^{x} \varphi_k(x, s)\, ds = \frac{1}{n!}. \]

For the remainders \(R_i(x)\) we obtain the estimates

(2.5.19)
\[ |R_i(x)| \leq \frac{M_i}{n!} |\omega(x)| \]

for \(i = 0, 1, \ldots, k\), where

(2.5.20)
\[ M_i = \sup_{s \in (x_1, x_k)} |f^{(n)}(s)|, \quad (i = 1, 2, \ldots, k-1) \]

and

(2.5.21)
\[ M_0 = \sup_{s \in (x, x_k)} |f^{(n)}(s)|, \qquad M_k = \sup_{s \in (x_1, x)} |f^{(n)}(s)|. \]

↑ Contents

Română

Chapter III

The remainder in the quadrature formulas of Gauss and P. Turán

D. V. Ionescu, Diferențe divizate [Divided Differences], Editura Academiei Republicii Socialiste România, Bucharest, 1978, pp. 83–129

It is known that the nodes \(x_1, x_2, \ldots, x_n\) and the coefficients \(C_1, C_2, \ldots, C_n\) of the quadrature formula

(3.1)
\[ \int_a^b f(x)\, dx = C_1 f(x_1) + C_2 f(x_2) + \ldots + C_n f(x_n) + R[f] \]

can be determined so that the remainder \(R[f]\) vanishes when the function \(f(x)\) is replaced by \(1, x, \ldots, x^{2n-1}\). The nodes \(x_1, x_2, \ldots, x_n\) are the roots of the Legendre polynomial associated with the interval \([a, b]\). Formula (3.1) is called Gauss's quadrature formula.

P. Turán [47] gave a beautiful extension of Gauss's quadrature formula, proving that one can determine the nodes and the coefficients of the quadrature formula

(3.2)
\[ \begin{aligned} \int_a^b f(x)\, dx = {} & C_1 f(x_1) + C_2 f(x_2) + \ldots + C_n f(x_n) + \\ & + C_1' f'(x_1) + C_2' f'(x_2) + \ldots + C_n' f'(x_n) + \\ & + C_1'' f''(x_1) + C_2'' f''(x_2) + \ldots + C_n'' f''(x_n) + R[f] \end{aligned} \]

so that the remainder \(R[f]\) vanishes when the function \(f(x)\) is replaced by \(1, x, \ldots, x^{4n-1}\).

More generally, P. Turán considered quadrature formulas of the form

(3.3)
\[ \int_a^b f(x)\, dx = \sum_{j=0}^{2k} [C_1^{(j)} f^{(j)}(x_1) + C_2^{(j)} f^{(j)}(x_2) + \ldots + C_n^{(j)} f^{(j)}(x_n)] + R[f] \]

and determined the nodes and the coefficients so that the remainder \(R[f]\) vanishes when the function \(f(x)\) is replaced by \(1, x, \ldots, x^{2(k+1)n-1}\).

Formulas (3.3) form a class; they are called the formulas of P. Turán. For \(k = 0\), formula (3.3) becomes Gauss's quadrature formula.

In this chapter we shall determine the remainders of the quadrature formulas of Gauss and P. Turán.

We have shown that Gauss's quadrature formula and its remainder can be derived from the divided difference

(3.4)
\[ [a, x_1, x_1, \ldots, x_n, x_n, b; g], \]

where \(x_1, x_2, \ldots, x_n\) are the roots of the Legendre polynomial associated with the interval \([a, b]\), and where we put \(g' = f\).

Using Theorem 2.4.3, one can derive an estimate of the absolute value of the remainder of Gauss's quadrature formula. Using the integral representation (2.1.28), we are led to the integral representation of the remainder \(R[f]\) of Gauss's quadrature formula.

This idea will be taken up again for P. Turán's quadrature formula (3.2) or for the general formula (3.3).

This chapter begins with the integral representation of the divided difference

(3.5)
\[ [a, \underbrace{x_1, \ldots, x_1}_{k}, \underbrace{x_2, \ldots, x_2}_{k}, \ldots, \underbrace{x_n, \ldots, x_n}_{k}, b; g] \]

by the method used in Chapter II. However, the proof concerning the sign of the function \(\varphi\) on the interval \((a, b)\) is simpler in the case of the divided difference (3.5) than in the general case. This is due to the fact that in the divided difference (3.5) the nodes \(a, b\) are simple and the nodes \(x_1, x_2, \ldots, x_n\) are multiple, all of the same multiplicity \(k\).

§ 3.1. The integral representation of the divided difference \([a, \underbrace{x_1, \ldots, x_1}_{k}, \underbrace{x_2, \ldots, x_2}_{k}, \ldots, \underbrace{x_n, \ldots, x_n}_{k}, b; f]\)

3.1.1. In view of the integral representation of the divided difference

(3.1.1)
\[ [a, \underbrace{x_1, \ldots, x_1}_{k}, \underbrace{x_2, \ldots, x_2}_{k}, \ldots, \underbrace{x_n, \ldots, x_n}_{k}, b; f] \]

let us consider the number \(N\) defined by \(N + 1 = 1 + kn + 1\), that is,

(3.1.2)
\[ N = kn + 1, \]

where \(k \gt 1\), and let us assume that \(f \in C^{kn+1}[a, b]\).

We proceed as in Chapter II and associate with the intervals \([a, x_1], [x_1, x_2], \ldots, [x_n, b]\) the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_{n+1}\), solutions of the differential equations

(3.1.3)
\[ \varphi_1^{(N)} = 0, \quad \varphi_2^{(N)} = 0, \quad \ldots, \quad \varphi_{n+1}^{(N)} = 0. \]

We have the following formulas:

(3.1.4)
\[ \int_a^{x_1} \varphi_1^{(N)} f\, ds = 0, \quad \int_{x_1}^{x_2} \varphi_2^{(N)} f\, ds = 0, \quad \ldots, \quad \int_{x_n}^{b} \varphi_{n+1}^{(N)} f\, ds = 0. \]

Applying the generalized integration by parts formula to each integral (3.1.4), we shall have

(3.1.5)
\[ \begin{aligned} (\varphi_1 f^{(N-1)} - \varphi_1' f^{(N-2)} + \ldots + (-1)^{N-1} \varphi_1^{(N-1)} f)_a^{x_1} &= \int_a^{x_1} \varphi_1 f^{(N)}\, ds, \\ (\varphi_2 f^{(N-1)} - \varphi_2' f^{(N-2)} + \ldots + (-1)^{N-1} \varphi_2^{(N-1)} f)_{x_1}^{x_2} &= \int_{x_1}^{x_2} \varphi_2 f^{(N)}\, ds, \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots &\ldots\ldots\ldots\ldots \\ (\varphi_{n+1} f^{(N-1)} - \varphi_{n+1}' f^{(N-2)} + \ldots + (-1)^{N-1} \varphi_{n+1}^{(N-1)} f)_{x_n}^{b} &= \int_{x_n}^{b} \varphi_{n+1} f^{(N)}\, ds. \end{aligned} \]

Adding formulas (3.1.5) term by term, we obtain the formula:

(3.1.6)
\[ \mathscr{P}[f] = \int_a^b \varphi f^{(N)}\, ds, \]

where \(\mathscr{P}[f]\) depends on the values of \(f\) and of its successive derivatives \(f', f'', \ldots, f^{(N-1)}\) at the nodes \(a, x_1, \ldots, x_n, b\), and where the function \(\varphi\) coincides on the intervals \([a, x_1], [x_1, x_2], \ldots, [x_n, b]\) with the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_{n+1}\).

Concerning formula (3.1.6), we pose the following problem:

Boundary value problem. Determine the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_{n+1}\), solutions of the differential equations (3.1.3), such that in \(\mathscr{P}[f]\) the coefficients of

(3.1.7)
\[ \begin{array}{ll} f'(a), \ldots, & f^{(k)}(a), \ldots, f^{(N-1)}(a) \\ & f^{(k)}(x_1), \ldots, f^{(N-1)}(x_1) \\ & \ldots\ldots\ldots\ldots\ldots\ldots \\ & f^{(k)}(x_n), \ldots, f^{(N-1)}(x_n) \\ f'(b), \ldots, & f^{(k)}(b), \ldots, f^{(N-1)}(b) \end{array} \]

are zero and \(\mathscr{P}[x^N] = 1\).

For this we must introduce the boundary conditions:

(3.1.8)
\[ \begin{array}{llll} \varphi_1(a) = 0, \quad & \varphi_1'(a) = 0 \quad & \ldots, & \varphi_1^{(N-2)}(a) = 0, \\ \varphi_2(x_1) = \varphi_1(x_1), \quad & \varphi_2'(x_1) = \varphi_1'(x_1) \quad & \ldots, & \varphi_2^{(N-k-1)}(x_1) = \varphi_1^{(N-k-1)}(x_1) \\ \ldots\ldots\ldots\ldots & \ldots\ldots\ldots\ldots & \ldots\ldots & \ldots\ldots\ldots\ldots\ldots\ldots \\ \varphi_{n+1}(x_n) = \varphi_n(x_n), \quad & \varphi_{n+1}'(x_n) = \varphi_n'(x_n), \quad & \ldots, & \varphi_{n+1}^{(N-k-1)}(x_n) = \varphi_n^{(N-k-1)}(x_n), \\ \varphi_{n+1}(b) = 0, \quad & \varphi_{n+1}'(b) = 0, \quad & \ldots, & \varphi_{n+1}^{(N-2)}(b) = 0. \end{array} \]

The solution of this boundary value problem is easily obtained. The differential equations (3.1.3) and the boundary conditions (3.1.8) at the points \(a, x_1, \ldots, x_n\) are satisfied by the polynomials:

\[ \begin{aligned} \varphi_1(s) &= \lambda_0 \frac{(s-a)^{N-1}}{(N-1)!}; \\ \varphi_2(s) &= \lambda_0 \frac{(s-a)^{N-1}}{(N-1)!} + \lambda_1 \frac{(s-x_1)^{N-1}}{(N-1)!} - \\ &\qquad - \lambda_1^{(1)} \frac{(s-x_1)^{N-2}}{(N-2)!} + \ldots + (-1)^{k-1} \lambda_1^{(k-1)} \frac{(s-x_1)^{N-k}}{(N-k)!} \\ \varphi_3(s) &= \lambda_0 \frac{(s-a)^{N-1}}{(N-1)!} + \lambda_1 \frac{(s-x_1)^{N-1}}{(N-1)!} - \\ &\qquad - \lambda_1^{(1)} \frac{(s-x_1)^{N-2}}{(N-2)!} + \ldots + (-1)^{k-1} \lambda_1^{(k-1)} \frac{(s-x_1)^{N-k}}{(N-k)!} + \end{aligned} \]
(3.1.9)
\[ \begin{aligned} &\qquad + \lambda_2 \frac{(s-x_2)^{N-1}}{(N-1)!} - \lambda_2^{(1)} \frac{(s-x_2)^{N-2}}{(N-2)!} + \ldots + (-1)^{k-1} \lambda_2^{(k-1)} \frac{(s-x_2)^{N-k}}{(N-k)!} \\ \ldots\ldots\ldots\ldots &\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ \varphi_{n+1}(s) &= \lambda_0 \frac{(s-a)^{N-1}}{(N-1)!} + \lambda_1 \frac{(s-x_1)^{N-1}}{(N-1)!} - \\ &\qquad - \lambda_1^{(1)} \frac{(s-x_1)^{N-2}}{(N-2)!} + \ldots + (-1)^{k-1} \lambda_1^{(k-1)} \frac{(s-x_1)^{N-k}}{(N-k)!} + \\ &\qquad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &\qquad + \lambda_n \frac{(s-x_n)^{N-1}}{(N-1)!} - \lambda_n^{(1)} \frac{(s-x_n)^{N-2}}{(N-2)!} + \ldots + (-1)^{k-1} \lambda_n^{(k-1)} \frac{(s-x_n)^{N-k}}{(N-k)!}, \end{aligned} \]

where \(\lambda_0, \lambda_1, \lambda_1^{(1)}, \ldots, \lambda_1^{(k-1)}, \ldots, \lambda_n, \lambda_n^{(1)}, \ldots, \lambda_n^{(k-1)}\) are constants.

The constants \(\lambda_0, \lambda_1, \ldots, \lambda_n^{(k-1)}\) are determined by requiring that the boundary conditions (3.1.8) at the point \(b\) be satisfied. We then obtain the equations

(3.1.10)
\[ \begin{aligned} &\lambda_0(b-a)^{N-1} + \lambda_1(b-x_1)^{N-1} - \lambda_1^{(1)}(N-1)(b-x_1)^{N-2} + \ldots \\ &\qquad \ldots + (-1)^{k-1} \lambda_1^{(k-1)}(N-1) \ldots (N-k+1)(b-x_1)^{N-k} + \\ &\qquad\quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &\qquad\quad + \lambda_n(b-x_n)^{N-1} - \lambda_n^{(1)}(N-1)(b-x_n)^{N-2} + \ldots \\ &\qquad \ldots + (-1)^{k-1} \lambda_n^{(k-1)}(N-1) \ldots (N-k+1)(b-x_n)^{N-k} = 0, \\ &\lambda_0(b-a)^{N-2} + \lambda_1(b-x_1)^{N-2} - \lambda_1^{(1)}(N-2)(b-x_1)^{N-3} + \ldots \\ &\qquad \ldots + (-1)^{k-1} \lambda_1^{(k-1)}(N-2) \ldots (N-k)(b-x_1)^{N-k-1} + \\ &\qquad\quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &\qquad\quad + \lambda_n(b-x_n)^{N-2} - \lambda_n^{(1)}(N-2)(b-x_n)^{N-3} + \ldots \\ &\qquad \ldots + (-1)^{k-1} \lambda_n^{(k-1)}(N-2) \ldots (N-k)(b-x_n)^{N-k-1} = 0 \\ &\qquad \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ &\qquad \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ &\lambda_0(b-a) + \lambda_1(b-x_1) - \lambda_1^{(1)} + \\ &\qquad\quad + \ldots\ldots\ldots\ldots + \\ &\qquad\quad + \lambda_n(b-x_n) - \lambda_n^{(1)} = 0. \end{aligned} \]

Introducing a new unknown \(\lambda_{n+1}\) through the equation

(3.1.11)
\[ \lambda_0 + \lambda_1 + \ldots + \lambda_n + \lambda_{n+1} = 0, \]

equations (3.1.10) can be written in the form

(3.1.12)
\[ \begin{aligned} &\lambda_0 + \lambda_1 + \ldots + \lambda_n + \lambda_{n+1} = 0 \\ &\lambda_0 a + \lambda_1 x_1 + \lambda_1^{(1)} + \ldots + \lambda_n x_n + \lambda_n^{(1)} + \lambda_{n+1} b = 0 \\ &\lambda_0 a^2 + \lambda_1 x_1^2 + 2 \lambda_1^{(1)} x_1 + 2.1\, \lambda_1^{(2)} + \ldots + \lambda_n x_n^2 + 2 \lambda_n^{(1)} x_n + 2\,.\,1\,.\, \lambda_n^{(2)} + \lambda_{n+1} b^2 = 0 \\ &\qquad \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ &\lambda_0 a^{N-1} + \lambda_1 x_1^{N-1} + (N-1) \lambda_1^{(1)} x_1^{N-2} + \ldots + (N-1) \ldots (N-k+1) \lambda_1^{(k-1)} x_1^{N-k} + \\ &\qquad\qquad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &\qquad\qquad + \lambda_n x_n^{N-1} + (N-1) \lambda_n^{(1)} x_n^{N-2} + \ldots + \\ &\qquad + (N-1) \ldots (N-k+1) \lambda_n^{(k-1)} x_n^{N-k} + \lambda_{n+1} b^{N-1} = 0. \end{aligned} \]

The number of unknowns in system (3.1.12) is \(1 + kn + 1 = N + 1\) and the number of equations of the system is \(N\). The rank of the coefficient matrix of system (3.1.12) is \(N\). Denoting by \(D_0, D_1, D_1^{(1)}, \ldots, D_1^{(k-1)}, \ldots, D_n, D_n^{(1)}, \ldots, D_n^{(k-1)}, D_{n+1}\) the determinants of the matrices obtained from the matrix of system (3.1.12) by deleting the first, the second, \(\ldots\), the last column of the matrix of the system, we have

(3.1.13)
\[ \frac{\lambda_0}{D_0} = \frac{\lambda_1}{-D_1} = \frac{\lambda_1^{(1)}}{D_1^{(1)}} = \ldots = \frac{\lambda_1^{(k-1)}}{(-1)^k D_1^{(k-1)}} = \ldots = \frac{\lambda_n}{(-1)^{(n-1)k+1} D_n} = \frac{\lambda_n^{(1)}}{(-1)^{(n-1)k+2} D_n^{(1)}} = \ldots = \frac{\lambda_n^{(k-1)}}{(-1)^{(n-1)k+k} D_n^{(k-1)}} = \frac{\lambda_{n+1}}{(-1)^{nk+1} D_{n+1}} = H, \]

where \(H\) is a constant.

The constants \(\lambda_0, \lambda_1, \lambda_1^{(1)}, \ldots, \lambda_1^{(k-1)}, \ldots, \lambda_n, \lambda_n^{(1)}, \ldots, \lambda_n^{(k-1)}, \lambda_{n+1}\) being determined up to a factor \(H\), the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_{n+1}\) are likewise determined up to the factor \(H\). Replacing in formula (3.1.6) the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_{n+1}\) by the solution of the boundary value problem, we find for \(\mathscr{P}[f]\) the expression

(3.1.14)
\[ \begin{aligned} \mathscr{P}[f] = (-1)^N \Bigl\{ & \varphi_1^{(N-1)}(a) f(a) + [\varphi_2^{(N-1)}(x_1) - \varphi_1^{(N-1)}(x_1)] f(x_1) - [\varphi_2^{(N-2)}(x_1) - \\ & - \varphi_1^{(N-2)}(x_1)] f'(x_1) + \ldots + (-1)^{k-1} [\varphi_2^{(N-k)}(x_1) - \varphi_1^{(N-k)}(x_1)] f^{(k-1)}(x_1) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + [\varphi_{n+1}^{(N-1)}(x_n) - \varphi_n^{(N-1)}(x_n)] f(x_n) - [\varphi_{n+1}^{(N-2)}(x_n) - \varphi_n^{(N-2)}(x_n)] f'(x_n) + \ldots \\ & \ldots + (-1)^{k-1} [\varphi_{n+1}^{(N-k)}(x_n) - \varphi_n^{(N-k)}(x_n)] f^{(k-1)}(x_n) - \varphi_{n+1}^{(N-1)}(b) f(b) \Bigr\}. \end{aligned} \]

But by formulas (3.1.9) we have

\[ \left\{ \begin{aligned} \varphi_1^{(N-1)}(s) &= \lambda_0 \\ \varphi_2^{(N-1)}(s) &= \lambda_0 + \lambda_1 \\ \varphi_3^{(N-1)}(s) &= \lambda_0 + \lambda_1 + \lambda_2 \\ \ldots\ldots\ldots &\ldots\ldots\ldots \\ \varphi_{n+1}^{(N-1)}(s) &= \lambda_0 + \lambda_1 + \lambda_2 + \ldots + \lambda_n \end{aligned} \right. \]
\[ \left\{ \begin{aligned} \varphi_1^{(N-2)}(s) &= \lambda_0(s-a) \\ \varphi_2^{(N-2)}(s) &= \lambda_0(s-a) + \lambda_1(s-x_1) - \lambda_1^{(1)} \\ \varphi_3^{(N-2)}(s) &= \lambda_0(s-a) + \lambda_1(s-x_1) - \lambda_1^{(1)} \\ &\phantom{{}= \lambda_0(s-a)} + \lambda_2(s-x_2) - \lambda_2^{(1)} \\ \ldots\ldots\ldots &\ldots\ldots\ldots\ldots\ldots \\ \varphi_{n+1}^{(N-2)}(s) &= \lambda_0(s-a) + \lambda_1(s-x_1) - \lambda_1^{(1)} \\ &\phantom{{}= \lambda_0(s-a)} + \lambda_2(s-x_2) - \lambda_2^{(1)} \\ &\phantom{{}= \lambda_0(s-a)} + \ldots\ldots\ldots\ldots + \\ &\phantom{{}= \lambda_0(s-a)} + \lambda_n(s-x_n) - \lambda_n^{(1)} \end{aligned} \right. \]
(3.1.15)
\[ \left\{ \begin{aligned} \varphi_1^{(N-3)}(s) &= \lambda_0 \frac{(s-a)^2}{2!} \\ \varphi_2^{(N-3)}(s) &= \lambda_0 \frac{(s-a)^2}{2!} + \lambda_1 \frac{(s-x_1)^2}{2!} - \lambda_1^{(1)}(s-x_1) + \lambda_1^{(2)} \\ \varphi_3^{(N-3)}(s) &= \lambda_0 \frac{(s-a)^2}{2!} + \lambda_1 \frac{(s-x_1)^2}{2!} - \lambda_1^{(1)}(s-x_1) + \lambda_1^{(2)} \\ &\phantom{{}= \lambda_0 \frac{(s-a)^2}{2!}} + \lambda_2 \frac{(s-x_2)^2}{2!} - \lambda_2^{(1)}(s-x_2) + \lambda_2^{(2)} \\ \ldots\ldots\ldots &\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ \varphi_{n+1}^{(N-3)}(s) &= \lambda_0 \frac{(s-a)^2}{2!} + \lambda_1 \frac{(s-x_1)^2}{2!} - \lambda_1^{(1)}(s-x_1) + \lambda_1^{(2)} \\ &\phantom{{}= \lambda_0 \frac{(s-a)^2}{2!}} + \lambda_2 \frac{(s-x_2)^2}{2!} - \lambda_2^{(1)}(s-x_2) + \lambda_2^{(2)} \\ &\phantom{{}= \lambda_0 \frac{(s-a)^2}{2!}} + \ldots\ldots\ldots\ldots\ldots\ldots \\ &\phantom{{}= \lambda_0 \frac{(s-a)^2}{2!}} + \lambda_n \frac{(s-x_n)^2}{2!} - \lambda_n^{(1)}(s-x_n) + \lambda_n^{(2)} \end{aligned} \right. \]
\[ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \]
\[ \left\{ \begin{aligned} \varphi_1^{(N-k)}(s) &= \lambda_0 \frac{(s-a)^{k-1}}{(k-1)!} \\ \varphi_2^{(N-k)}(s) &= \lambda_0 \frac{(s-a)^{k-1}}{(k-1)!} + \lambda_1 \frac{(s-x_1)^{k-1}}{(k-1)!} - \\ &\qquad - \lambda_1^{(1)} \frac{(s-x_1)^{k-2}}{(k-2)!} + \ldots + (-1)^{k-1} \lambda_1^{(k-1)} \\ \varphi_3^{(N-k)}(s) &= \lambda_0 \frac{(s-a)^{k-1}}{(k-1)!} + \lambda_1 \frac{(s-x_1)^{k-1}}{(k-1)!} - \\ &\qquad - \lambda_1^{(1)} \frac{(s-x_1)^{k-2}}{(k-2)!} + \ldots + (-1)^{k-1} \lambda_1^{(k-1)} \\ &\qquad + \lambda_2 \frac{(s-x_2)^{k-1}}{(k-1)!} - \lambda_2^{(1)} \frac{(s-x_2)^{k-2}}{(k-2)!} + \ldots + (-1)^{k-1} \lambda_2^{(k-1)} \\ &\qquad \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ \varphi_{n+1}^{(N-k)}(s) &= \lambda_0 \frac{(s-a)^{k-1}}{(k-1)!} + \lambda_1 \frac{(s-x_1)^{k-1}}{(k-1)!} - \\ &\qquad - \lambda_1^{(1)} \frac{(s-x_1)^{k-2}}{(k-2)!} + \ldots + (-1)^{k-1} \lambda_1^{(k-1)} \\ &\qquad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ &\qquad + \lambda_n \frac{(s-x_n)^{k-1}}{(k-1)!} - \lambda_n^{(1)} \frac{(s-x_n)^{k-2}}{(k-2)!} + \ldots + (-1)^{k-1} \lambda_n^{(k-1)}. \end{aligned} \right. \]

Formula (3.1.14) becomes

(3.1.16)
\[ \begin{aligned} \mathscr{P}[f] = (-1)^N \Bigl\{ & \lambda_0 f(a) + \lambda_1 f(x_1) + \lambda_1^{(1)} f'(x_1) + \ldots + \lambda_1^{(k-1)} f^{(k-1)}(x_1) + \\ & + \lambda_2 f(x_2) + \lambda_2^{(1)} f'(x_2) + \ldots + \lambda_2^{(k-1)} f^{(k-1)}(x_2) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \lambda_n f(x_n) + \lambda_n^{(1)} f'(x_n) + \ldots + \lambda_n^{(k-1)} f^{(k-1)}(x_n) + \lambda_{n+1} f(b) \Bigr\}. \end{aligned} \]

Replacing the constants \(\lambda_0, \lambda_1, \ldots, \lambda_1^{(k-1)}, \ldots, \lambda_n^{(k-1)}, \lambda_{n+1}\) by their expressions derived from formulas (3.1.13), we see that formula (3.1.16) reduces to:

(3.1.17)
\[ \mathscr{P}[f] = H \begin{vmatrix} 1 & a & a^2 \ldots a^{N-1} & f(a) \\ 1 & x_1 & x_1^2 \ldots x_1^{N-1} & f(x_1) \\ 0 & 1 & 2x_1 \ldots (x_1^{N-1})' & f'(x_1) \\ \ldots & \ldots & \ldots\ldots\ldots\ldots & \ldots\ldots \\ 0 & 0 & 0 \ldots (x_1^{N-1})^{(k-1)} & f^{(k-1)}(x_1) \\ \ldots & \ldots & \ldots\ldots\ldots\ldots & \ldots\ldots \\ \ldots & \ldots & \ldots\ldots\ldots\ldots & \ldots\ldots \\ 1 & x_n & x_n^2 \ldots x_n^{N-1} & f(x_n) \\ \ldots & \ldots & \ldots\ldots\ldots\ldots & \ldots\ldots \\ 0 & 0 & 0 \ldots (x_n^{N-1})^{(k-1)} & f^{(k-1)}(x_n) \\ 1 & b & b^2 \ldots b^{N-1} & f(b) \end{vmatrix}. \]

It remains to take into account the last boundary condition \(\mathscr{P}[x^N] = 1\) as well. Formula (3.1.17) shows that we must have

(3.1.18)
\[ HV(a, \underbrace{x_1, \ldots, x_1}_{k}, \ldots, \underbrace{x_n, \ldots, x_n}_{k}, b) = 1 \]

whence it follows that \(\mathscr{P}[f]\) reduces to the divided difference

(3.1.19)
\[ \mathscr{P}[f] = [a, \underbrace{x_1, \ldots, x_1}_{k}, \ldots, \underbrace{x_n, \ldots, x_n}_{k}, b; f]. \]

Finally, taking into account formula (3.1.6), we have:

Theorem 3.1.1. If \(f \in C^N[a, b]\), where \(N = nk + 1\), we have the integral representation

(3.1.20)
\[ [a, \underbrace{x_1, \ldots, x_1}_{k}, \underbrace{x_2, \ldots, x_2}_{k}, \ldots, \underbrace{x_n, \ldots, x_n}_{k}, b; f] = \int_a^b \varphi f^{(N)}\, ds, \]

where the function \(\varphi\) coincides on the intervals \([a, x_1], [x_1, x_2], \ldots, [x_n, b]\) with the polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_{n+1}\) given by formulas (3.1.9), (3.1.13), (3.1.18).

Formula (3.1.20) can also be written in the form:

(3.1.21)
\[ \begin{aligned} &\lambda_0 f(a) + \lambda_1 f(x_1) + \lambda_1^{(1)} f'(x_1) + \ldots + \lambda_1^{(k-1)} f^{(k-1)}(x_1) + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \lambda_n f(x_n) + \lambda_n^{(1)} f'(x_n) + \ldots + \lambda_n^{(k-1)} f^{(k-1)}(x_n) + \lambda_{n+1} f(b) = \\ &\qquad\qquad\qquad = (-1)^N \int_a^b \varphi f^{(N)}\, ds. \end{aligned} \]

We shall now prove several theorems on the coefficients of formula (3.1.21) and on the function \(\varphi\).

3.1.2. Theorem 3.1.2. We have

(3.1.22)
\[ \lambda_0 + \lambda_1 + \ldots + \lambda_r \neq 0 \quad \text{for } r = 0, 1, \ldots, n. \]

For \(r = 0\) the theorem is obvious, because by formulas (3.1.13) and (3.1.18) we have

\[ \lambda_0 = HD_0 = \frac{V(\underbrace{x_1, \ldots, x_1}_{k}, \ldots, \underbrace{x_n, \ldots, x_n}_{k}, b)}{V(a, \underbrace{x_1, \ldots, x_1}_{k}, \ldots, \underbrace{x_n, \ldots, x_n}_{k}, b)} \neq 0. \]

The theorem is also obvious for \(r = n\), because by the first equation of (3.1.12), and by (3.1.13) and (3.1.18), we have

\[ \lambda_0 + \lambda_1 + \ldots + \lambda_n = -\lambda_{n+1} \]

and

\[ \lambda_{n+1} = (-1)^N D_{n+1} H = (-1)^N \frac{V(a, \underbrace{x_1, \ldots, x_1}_{k}, \ldots, \underbrace{x_n, \ldots, x_n}_{k})}{V(a, \underbrace{x_1, \ldots, x_1}_{k}, \ldots, \underbrace{x_n, \ldots, x_n}_{k}, b)}. \]

It remains to prove the theorem for \(r = 1, 2, \ldots, n-1\).

To this end, let us introduce the interpolation polynomial \(h(x; r) = h(x)\) determined by the conditions

(3.1.23)
\[ \begin{aligned} h(a) = 1,\ h(x_1) = 1,\ \ldots,\ h(x_r) = 1,\ h(x_{r+1}) = 0,\ \ldots,\ h(x_n) = 0, \\ h'(x_1) = 0,\ \ldots,\ h'(x_r) = 0,\ h'(x_{r+1}) = 0,\ \ldots,\ h'(x_n) = 0, \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ h^{(k-1)}(x_1) = 0,\ \ldots,\ h^{(k-1)}(x_r) = 0,\ h^{(k-1)}(x_{r+1}) = 0,\ \ldots,\ h^{(k-1)}(x_n) = 0. \end{aligned} \]

It is easy to show that the polynomial \(h\) is completely determined by the \(nk + 1 = N\) conditions (3.1.23). It follows that the degree of the polynomial \(h\) is at most \(N-1\).

We add that the polynomial \(h\) is not identically zero, because for any \(r = 1, 2, \ldots, n-1\) we have \(h(a) = 1\), whereas \(h(x_n) = 0\).

Replacing in formula (3.1.21) the function \(f\) by the polynomial \(h\), we have

(3.1.24)
\[ \lambda_0 + \lambda_1 + \ldots + \lambda_r + \lambda_{n+1} h(b) = 0 \]

and Theorem 3.1.2, which we have in view, amounts to proving that for the polynomial \(h\) determined by conditions (3.1.23) we have \(h(b) \neq 0\).

Let us first prove that the polynomial \(h^{(k-1)}\) is of degree \(N-k\). Applying Rolle's theorem and taking into account conditions (3.1.23), we find that the derivative \(h'\) vanishes at \(n-1 + n = 2n-1\) distinct points of the interval \([a, x_n)\), then that the derivative \(h''\) vanishes at \(2n-2+n\) distinct points of the same interval, \(\ldots\), and finally that the derivative \(h^{(k-1)}\) vanishes at \(kn - (k-1) = N-k\) distinct points of the same interval.

We have thus exhibited, for the polynomial \(h^{(k-1)}\) of degree at most \(N-k\), \(N-k\) distinct roots in the interval \([a, x_n]\). This will help us to show that the degree of the polynomial \(h^{(k-1)}\) is \(N-k\).

Indeed, let us assume the contrary, namely that the degree of the polynomial \(h^{(k-1)}\) is less than \(N-k\). Then, since this polynomial has \(N-k\) distinct roots, it is identically zero, and \(h^{(k-2)}\) is a constant, which is zero because \(h^{(k-2)}(x_1) = 0\). One shows in the same way that the derivative \(h^{(k-3)}\) is zero, \(\ldots\), and finally that \(h'\) is zero. It would follow that the polynomial \(h\) is a constant, which is impossible because \(h(a) = 1\) and \(h(x_n) = 0\).

Hence the hypothesis that the degree of the derivative \(h^{(k-1)}\) is less than \(N-k\) must be rejected, and therefore the degree of \(h^{(k-1)}\) is \(N-k\).

We can now complete the proof and show that \(h(b) \neq 0\). Let us assume the contrary, namely that \(h(b) = 0\). Then, repeating the preceding arguments, we arrive at the conclusion that the successive derivatives \(h', h'', \ldots, h^{(k-1)}\) must have one more root in the interval \((x_n, b)\). But this is impossible, because it has been shown that the polynomial \(h^{(k-1)}\) of degree \(N-k\) has \(N-k\) distinct roots in the interval \([a, x_n]\). Hence the hypothesis that \(h(b) = 0\) must be rejected, and therefore \(h(b) \neq 0\).

Theorem 3.1.2 is thus proved.

3.1.3. Theorem 3.1.3. The polynomials \(\varphi_1, \varphi_2, \ldots, \varphi_{n+1}\) given by formulas (3.1.9) are of degree \(N-1\).

Indeed, by formulas (3.1.9) the coefficients of \(s^{N-1}\) in these polynomials are

\[ \begin{array}{l} \lambda_0 \\ \lambda_0 + \lambda_1 \\ \ldots\ldots\ldots\ldots \\ \lambda_0 + \lambda_1 + \ldots + \lambda_n \end{array} \]

and by Theorem 3.1.2 they are all different from zero.

3.1.4. Theorem 3.1.4. The derivative \(\varphi^{(N-k-1)}\) has at most \(k(n-1)\) zeros in the interval \((a, b)\).

Indeed, by formulas (3.1.9) and the boundary conditions (3.1.8) at the point \(b\), we have \(\varphi_1(s) = \lambda_0 \frac{(s-a)^{N-1}}{(N-1)!}\), \(\varphi_{n+1}(s) = -\lambda_{n+1} \frac{(s-b)^{N-1}}{(N-1)!}\), and therefore the derivative \(\varphi^{(N-k-1)}\) does not vanish on the intervals \((a, x_1], [x_n, b)\).

On the other hand, the derivatives \(\varphi_2^{(N-k-1)}, \varphi_3^{(N-k-1)}, \ldots, \varphi_n^{(N-k-1)}\) are polynomials of degree \(k\), and the coefficients of \(\frac{x^k}{k!}\) in them are \(\lambda_0 + \lambda_1, \lambda_0 + \lambda_1 + \lambda_2, \ldots, \lambda_0 + \lambda_1 + \ldots + \lambda_{n-1}\), all different from zero by Theorem 3.1.3. It follows that the derivative \(\varphi^{(N-k-1)}\) has at most \(k\) zeros on each of the intervals \((x_1, x_2], \ldots, (x_{n-1}, x_n)\), and therefore the derivative \(\varphi^{(N-k-1)}\) has at most \(k(n-1)\) zeros in the interval \((a, b)\).

Theorem 3.1.4 is therefore proved.

3.1.5. Theorem 3.1.5. The function \(\varphi\) in the integral representation (3.1.20) is positive on the interval \((a, b)\) and we have

(3.1.24′)
\[ \int_a^b \varphi\, ds = \frac{1}{N!}. \]

To prove this theorem, let us first show that the function \(\varphi\) does not vanish on the interval \((a, b)\). Let us assume the contrary, namely that the function \(\varphi\) vanishes at least at one point of the interval \((a, b)\), and let us observe that, by the boundary conditions (3.1.8), the function \(\varphi\) and its successive derivatives \(\varphi', \varphi'', \ldots, \varphi^{(N-k-1)}\) are continuous on the interval \([a, b]\). Then, applying Rolle's theorem successively, we deduce that the derivative \(\varphi'\) must have two zeros in the interval \((a, b)\), that the derivative \(\varphi''\) must have three zeros in the interval \((a, b)\), \(\ldots\), and that the derivative \(\varphi^{(N-k-1)}\) must have \(N-k = k(n-1) + 1\) zeros in the interval \((a, b)\). But this is impossible, because by Theorem 3.1.4 the derivative \(\varphi^{(N-k-1)}\) has at most \(k(n-1)\) zeros in the interval \((a, b)\). Hence the hypothesis that the function \(\varphi\) vanishes at least at one point of the interval \((a, b)\) must be rejected, and therefore the function \(\varphi\) does not vanish on the interval \((a, b)\).

If in formula (3.1.20) we replace the function \(f\) by \(x^N\), we deduce that \(1 = N! \int_a^b \varphi\, ds\), whence it follows that the function \(\varphi\) is positive on the interval \((a, b)\) and that formula (3.1.24′) holds.

§ 3.2. The quadrature formula of Gauss

3.2.1. Let us consider Gauss's quadrature formula of the form

(3.2.1)
\[ \int_a^b p(x) f(x)\, dx = C_1 f(x_1) + C_2 f(x_2) + \ldots + C_n f(x_n) + R[f], \]

where \(p\) is a weight, a function integrable on the interval \([a, b]\) and positive on the interval \((a, b)\).

Gauss's problem. Determine the nodes \(x_1, x_2, \ldots, x_n\) and the coefficients \(C_1, C_2, \ldots, C_n\) in formula (3.2.1) so that in this formula we have \(R[x^k] = 0\) for \(k = 0, 1, \ldots, 2n-1\).

We shall then have the identity

(3.2.2)
\[ \int_a^b p(x) f(x)\, dx = C_1 f(x_1) + C_2 f(x_2) + \ldots + C_n f(x_n) \]

for \(f(x) = x^k\), where \(k = 0, 1, \ldots, 2n-1\).

We must require that formula (3.2.2) become an identity when the function \(f(x)\) is replaced by

(3.2.3)
\[ 1, x, \ldots, x^{n-1} \]

and

(3.2.4)
\[ x^n, x^{n+1}, \ldots, x^{2n-1}. \]

We may also say that formula (3.2.2) holds when the function \(f\) is replaced by an arbitrary polynomial \(Q\) of degree at most \(2n-1\).

Let us denote by

(3.2.5)
\[ \omega_n(x) = x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n, \]

the polynomial whose roots are the nodes of formula (3.2.2). To determine the nodes \(x_1, x_2, \ldots, x_n\) means to determine the coefficients of the polynomial \(\omega_n(x)\).

The polynomials

(3.2.6)
\[ Q(x) = \omega_n(x)\, x^h, \]

where \(h = 0, 1, \ldots, n-1\), are of degree \(n + h \leq 2n-1\).

Replacing in formula (3.2.2) the function \(f\) by the polynomials \(Q\), we obtain the equations

(3.2.7)
\[ \int_a^b p(x)\, \omega_n(x)\, x^h\, dx = 0 \text{ for } h = 0, 1, \ldots, n-1, \]

because the polynomial \(\omega_n(x)\) vanishes for \(x_1, x_2, \ldots, x_n\).

As is well known, equations (3.2.7) determine the polynomial \(\omega_n(x)\), and from these equations one deduces the fundamental orthogonality property:

(3.2.8)
\[ \int_a^b p(x)\, \omega_n(x)\, \omega_m(x)\, dx = 0 \quad\text{for } n \neq m, \]

which means that the polynomials \(\omega_m\) form a sequence of polynomials orthogonal with respect to the function \(p(x)\) on the interval \([a, b]\), where \(m = 0, 1, \ldots\) and \(\omega_0(x) = 1\).

It is known that the polynomial \(\omega_n(x)\), whose coefficients are determined by equations (3.2.7), has all its roots real, distinct and lying between \(a\) and \(b\).

Thus the nodes of formula (3.2.2) are the roots of the polynomial \(\omega_n\). In particular, when \(p(x) = 1\), the nodes \(x_1, x_2, \ldots, x_n\) of formula (3.2.2) are the roots of the Legendre polynomial of degree \(n\) attached to the interval \([a, b]\).

Once the nodes of formula (3.2.2) have been determined, it is easy to determine the coefficients \(C_1, C_2, \ldots, C_n\). It suffices to require that formula (3.2.2) become an identity when the function \(f\) is replaced by the functions (3.2.3). The system of equations

(3.2.9)
\[ \begin{aligned} C_1 + C_2 + \ldots + C_n &= \int_a^b p(x)\, dx \\ C_1 x_1 + C_2 x_2 + \ldots + C_n x_n &= \int_a^b p(x)\, x\, dx \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_1 x_1^{n-1} + C_2 x_2^{n-1} + \ldots + C_n x_n^{n-1} &= \int_a^b p(x)\, x^{n-1}\, dx \end{aligned} \]

determines the coefficients \(C_1, C_2, \ldots, C_n\), its determinant being the Vandermonde determinant of the distinct nodes \(x_1, x_2, \ldots, x_n\).

Thus Gauss's problem is completely solved [9].

Another argument leading to these results can be found in paper [8].

Gauss's problem leads us to the identities:

(3.2.10)
\[ \begin{aligned} C_1 + C_2 + \ldots + C_n &= \int_a^b p(x)\, dx \\ C_1 x_1 + C_2 x_2 + \ldots + C_n x_n &= \int_a^b p(x)\, x\, dx \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_1 x_1^{2n-1} + C_2 x_2^{2n-1} + \ldots + C_n x_n^{2n-1} &= \int_a^b p(x)\, x^{2n-1}\, dx, \end{aligned} \]

obtained by adjoining to equations (3.2.9) the identities that result from replacing in formula (3.2.2) the function \(f\) by the functions (3.2.4).

It now remains to determine the remainder \(R[f]\) of Gauss's quadrature formula, when the nodes and the coefficients have been determined by Gauss's problem and when it is assumed that \(f \in C^{2n}[a, b]\). This problem was treated by us in general, with the method of the function \(\varphi\), for a weight \(p(x)\) integrable on the interval \([a, b]\) and positive on the interval \((a, b)\), in our paper [8].

However, when \(p(x) = 1\), the determination of the remainder \(R[f]\) can be connected with the integral representation of a divided difference, as we shall see below.

3.2.2. Let us consider the divided difference of the function \(g\) on the simple nodes \(a, b\) and the distinct double nodes \(x_1, x_2, \ldots, x_n\):

(3.2.11)
\[ [a, x_1, x_1, \ldots, x_n, x_n, b; g]. \]

As is well known, we have

(3.2.12)
\[ [a, x_1, x_1, \ldots, x_n, x_n, b; g] = V^{-1} \begin{vmatrix} 1 & a & \ldots & a^{2n} & g(a) \\ 1 & x_1 & \ldots & x_1^{2n} & g(x_1) \\ 0 & 1 & \ldots & (x_1^{2n})' & g'(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & x_n & \ldots & x_n^{2n} & g(x_n) \\ 0 & 1 & \ldots & (x_n^{2n})' & g'(x_n) \\ 1 & b & \ldots & b^{2n} & g(b) \end{vmatrix} \]

where \(V\) is the generalized Vandermonde determinant \(V(a, x_1, x_1, \ldots, x_n, x_n, b)\).

Expanding the determinant on the right-hand side of formula (3.2.12) along the elements of the last column, we have

(3.2.13)
\[ \begin{aligned} {[}a, x_1, x_1, \ldots, x_n, x_n, b; g] = {} & A_0\, g(a) + A_1\, g(x_1) + \ldots + A_n\, g(x_n) + A_{n+1}\, g(b) + \\ & + A'_1\, g'(x_1) + \ldots + A'_n\, g'(x_n), \end{aligned} \]

where

(3.2.14)
\[ A_1 = V^{-1} \begin{vmatrix} 1 & a & \ldots & a^{2n} \\ 0 & 1 & \ldots & (x_1^{2n})' \\ 1 & x_2 & \ldots & x_2^{2n} \\ 0 & 1 & \ldots & (x_2^{2n})' \\ \ldots & \ldots & \ldots & \ldots \\ 1 & x_n & \ldots & x_n^{2n} \\ 0 & 1 & \ldots & (x_n^{2n})' \\ 1 & b & \ldots & b^{2n} \end{vmatrix} ;\ A_2 = \ldots ;\ \ldots ;\ A_n = \ldots \]

We have the following theorem:

Theorem 3.2.1. If in formula (3.2.13) the nodes \(x_1, x_2, \ldots, x_n\) are the roots of the Legendre polynomial associated with the interval \((a, b)\), then the coefficients \(A_1, A_2, \ldots, A_n\) are zero.

It suffices to carry out the proof for one of these coefficients, for example for \(A_1\). To this end, we write \(A_1\) in the form

\[ A_1 = L_1 \begin{vmatrix} -1 & 0 & \ldots & 0 & 1 & \ldots & 1 & 1 \\ -a & 1 & \ldots & 1 & x_2 & \ldots & x_n & b \\ -a^2 & 2x_1 & \ldots & 2x_n & x_2^2 & \ldots & x_n^2 & b^2 \\ \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots \\ -a^{2n} & 2n x_1^{2n-1} & \ldots & 2n x_n^{2n-1} & x_2^{2n} & \ldots & x_n^{2n} & b^{2n} \end{vmatrix}, \]

where \(L_1\) is a coefficient that differs from \(V^{-1}\) by a factor of 1 or \(-1\).

Adding the elements of the last column to the elements of the first column, and placing the factors \(1, 2, \ldots, 2n\) beside \(L_1\), we can write \(A_1\) in the form:

(3.2.15)
\[ A_1 = (2n)!\, L_1 \begin{vmatrix} 0 & 0 & \ldots & 0 & 1 & \ldots & 1 & 1 \\ \int_a^b dx & 1 & \ldots & 1 & x_2 & \ldots & x_n & b \\ \int_a^b x\, dx & x_1 & \ldots & x_n & \frac{x_2^2}{2} & \ldots & \frac{x_n^2}{2} & \frac{b^2}{2} \\ \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots \\ \int_a^b x^{2n-1}\, dx & x_1^{2n-1} & \ldots & x_n^{2n-1} & \frac{x_2^{2n}}{2n} & \ldots & \frac{x_n^{2n}}{2n} & \frac{b^{2n}}{2n} \end{vmatrix}. \]

The elements of the first \(n+1\) columns satisfy one and the same linear relation, as follows from identities (3.2.10). It follows that \(A_1 = 0\), and therefore Theorem 3.2.1 is proved.

3.2.3. This being so, let us replace in formula (3.2.13) the nodes \(x_1, x_2, \ldots, x_n\) by the roots of the Legendre polynomial associated with the interval \([a, b]\). By Theorem 3.2.1 we shall have \(A_1 = 0, \ldots, A_n = 0\), and we can write

(3.2.16)
\[ {[}a, x_1, x_1, \ldots, x_n, x_n, b; g] = A_0\, g(a) + A_{n+1}\, g(b) + A'_1\, g'(x_1) + \ldots + A'_n\, g'(x_n). \]

Replacing in this identity the function \(g\) by 1, we deduce that

(3.2.17)
\[ A_0 + A_{n+1} = 0. \]

On the other hand, we have

(3.2.18)
\[ A_{n+1} = V(a, x_1, x_1, \ldots, x_n, x_n) \neq 0. \]

It follows that formula (3.2.16) can be written in the form:

(3.2.19)
\[ {[}a, x_1, x_1, \ldots, x_n, x_n, b; g] = A_{n+1} \int_a^b g'(s)\, ds + A'_1\, g'(x_1) + \ldots + A'_n\, g'(x_n). \]

Let us replace in this identity the function \(g\) by:

(3.2.20)
\[ g(x) = \int_a^x f(s)\, ds \]

and divide both sides by \(A_{n+1}\). We shall have the formula:

(3.2.21)
\[ \int_a^b f\, ds = C_1 f(x_1) + C_2 f(x_2) + \ldots + C_n f(x_n) + R[f] \]

which is precisely Gauss's quadrature formula, with the nodes \(x_1, x_2, \ldots, x_n\), the roots of the Legendre polynomial associated with the interval \([a, b]\), and with the coefficients

(3.2.22)
\[ C_1 = -\frac{A'_1}{A_{n+1}}, \quad C_2 = -\frac{A'_2}{A_{n+1}}, \ldots, \quad C_n = -\frac{A'_n}{A_{n+1}} \]

and the remainder

(3.2.23)
\[ R[f] = \frac{1}{A_{n+1}} \left[a, x_1, x_1, \ldots, x_n, x_n, b; \int_a^x f\, ds\right]. \]

If we use the integral representation of the divided difference on the right-hand side of formula (3.2.23), we obtain the integral representation of the remainder \(R[f]\), when \(f \in C^{2n}[a, b]\):

(3.2.24)
\[ R[f] = \frac{1}{A_{n+1}} \int_a^b \varphi f^{(2n)}\, ds, \]

where on the right-hand side there appears the function \(\varphi\) of the integral representation of the divided difference (3.2.11) corresponding to the nodes \(x_1, x_2, \ldots, x_n\), the roots of the Legendre polynomial associated with the interval \([a, b]\).

We thus have:

Theorem 3.2.2. Gauss's quadrature formula (3.2.21) is derived from the integral representation of the divided difference (3.2.11):

(3.2.25)
\[ [a, x_1, x_1, \ldots, x_n, x_n, b; g] = \int_a^b \varphi g^{(2n+1)}\, dx \]

by replacing the nodes \(x_1, x_2, \ldots, x_n\) by the roots of the Legendre polynomial associated with the interval \([a, b]\) and setting \(g' = f\).

The coefficients of Gauss's formula are given by formulas (3.2.22) and the remainder \(R[f]\) is given by formula (3.2.24).

3.2.4. Introducing the polynomial

(3.2.26)
\[ \omega_n(x) = (x - x_1)(x - x_2) \ldots (x - x_n), \]

where \(x_1, x_2, \ldots, x_n\) are the roots of the Legendre polynomial associated with the interval \([a, b]\), and replacing in formula (3.2.21) the function \(f\) by \(\omega_n^2\), we obtain

\[ \int_a^b \omega_n^2\, dx = \frac{(2n)!}{A_{n+1}} \int_a^b \varphi\, ds. \]

But \(\int_a^b \varphi\, ds = \frac{1}{(2n+1)!}\), and therefore we deduce from the preceding formula

(3.2.27)
\[ \frac{1}{A_{n+1}} = (2n+1) \int_a^b \omega_n^2\, dx \]

which is an interesting interpretation of the coefficient \(\frac{1}{A_{n+1}}\) on the right-hand side of formula (3.2.24).

§ 3.3. The quadrature formula of P. Turán

3.3.1. Let us consider the quadrature formula of the form

(3.3.1)
\[ \int_a^b p(x) f(x)\, dx = \sum_{l=0}^{2(s-1)} [C_1^{(l)} f^{(l)}(x_1) + C_2^{(l)} f^{(l)}(x_2) + \ldots + C_n^{(l)} f^{(l)}(x_n)] + R[f], \]

where \(p\) is a function integrable on the interval \([a, b]\) and positive on the interval \((a, b)\), and where the right-hand side contains the derivatives \(f^{(l)}(x)\) at the nodes \(x_1, x_2, \ldots, x_n\) for \(l = 0, 1, \ldots, 2(s-1)\). This formula has been the subject of important investigations by P. Turán [47] and is called P. Turán's quadrature formula.

P. Turán's problem. Determine the nodes \(x_1, x_2, \ldots, x_n\) and the coefficients \(C_1^{(l)}, C_2^{(l)}, \ldots, C_n^{(l)}\), \(l = 0, 1, \ldots, 2(s-1)\), so that in formula (3.3.1) we have \(R[f] = 0\) for \(f(x) = x^k\), \(k = 0, 1, \ldots, 2ns-1\).

We shall then have the identity

(3.3.2)
\[ \begin{aligned} \int_a^b p(x) f(x)\, dx = {} & C_1^{(0)} f(x_1) + \ldots + C_n^{(0)} f(x_n) + \\ & + C_1^{(1)} f'(x_1) + \ldots + C_n^{(1)} f'(x_n) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + C_1^{(2(s-1))} f^{(2(s-1))}(x_1) + \ldots + C_n^{(2(s-1))} f^{(2(s-1))}(x_n) \end{aligned} \]

for \(f(x) = x^k\), \(k = 0, 1, \ldots, 2ns-1\).

P. Turán showed that this problem is connected with a minimum problem, namely: to determine the coefficients \(\lambda_1, \lambda_2, \ldots, \lambda_n\) so that the integral

(3.3.3)
\[ \int_a^b p(x) (x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n)^{2s}\, dx \]

where \(s\) is a natural number, is minimal.

Theorem 3.3.1. (D. Jackson) [22]. The coefficients \(\lambda_1, \lambda_2, \ldots, \lambda_n\) of the polynomial in integral (3.3.3) can be determined uniquely so that integral (3.3.3) is minimal.

The polynomial that realizes the minimum of integral (3.3.3) is called the minimizing polynomial of the integral. Below we shall give a simple proof of Theorem 3.3.1, due to Margareta Frenkel [4]. The minimizing polynomial of integral (3.3.3):

(3.3.4)
\[ \omega_n(x) = x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n \]

enjoys important properties, analogous to the properties of the Legendre polynomials.

We shall first prove:

Theorem 3.3.2. The coefficients \(\lambda_1, \lambda_2, \ldots, \lambda_n\) of the minimizing polynomial of integral (3.3.3) are determined by the equations

(3.3.5)
\[ \int_a^b p(x)\, \omega_n^{2s-1}(x)\, x^h\, dx = 0 \text{ for } h = 0, 1, \ldots, n-1. \]

For \(s = 1\), equations (3.3.5) express the property of the Legendre polynomials of being orthogonal with respect to the interval \((a, b)\) and the weight \(p\).

Next we shall prove:

Theorem 3.3.3. The minimizing polynomial \(\omega_n\) of integral (3.3.3) has all its roots real, distinct and lying between \(a\) and \(b\).

The minimizing polynomial \(\omega_n\) is very important for P. Turán's problem, because we have:

Theorem 3.3.4. (P. Turán). 1° The nodes \(x_1, x_2, \ldots, x_n\) corresponding to P. Turán's problem are the roots of the minimizing polynomial of integral (3.3.3).

2° The coefficients of P. Turán's identity (3.3.2) are given by the system of linear equations:

\[ \begin{aligned} \sum_{j=1}^{n} C_j^{(0)} &= \int_a^b p(x)\, dx \\ \sum_{j=1}^{n} [C_j^{(0)} x_j + C_j^{(1)} (x_j)'] &= \int_a^b p(x)\, x\, dx \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ \sum_{j=1}^{n} [C_j^{(0)} x_j^{(2s-1)n-1} + C_j^{(1)} (x_j^{(2s-1)n-1})' + \ldots + C_j^{(2(s-1))} (x_j^{(2s-1)n-1})^{(2(s-1))}] &= \\ &= \int_a^b p(x)\, x^{(2s-1)n-1}\, dx. \end{aligned} \]

whose determinant is different from zero.

Finally, we shall show that the remainder \(R[f]\) of the quadrature formula (3.3.1) of P. Turán, when \(f \in C^{2ns}[a, b]\) and \(p(x) = 1\), can be connected with the integral representation of a divided difference, as we did for the remainder of Gauss's formula [10].

3.3.2. Proof of D. Jackson's Theorem 3.3.1, given by Margareta Frenkel. Let us consider the integral

(3.3.6)
\[ \delta_{2s}(\lambda_1, \lambda_2, \ldots, \lambda_n) = \int_a^b p(x) (x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n)^{2s}\, dx, \]

where \(p\) is a function integrable on the interval \([a, b]\) and positive on the interval \((a, b)\), \(s\) is a natural number, and \(\lambda_1, \lambda_2, \ldots, \lambda_n\) are real coefficients. We shall determine the coefficients \(\lambda_1, \lambda_2, \ldots, \lambda_n\) uniquely so that the integral \(\delta_{2s}(\lambda_1, \lambda_2, \ldots, \lambda_n)\) is minimal.

To this end, we shall consider the function

(3.3.7)
\[ w(\lambda_0, \lambda_1, \ldots, \lambda_n) = \int_a^b p(x) (\lambda_0 x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n)^{2s}\, dx \]

and observe that it has the following properties:

1° We have

(3.3.8)
\[ w(1, \lambda_1, \ldots, \lambda_n) = \delta_{2s}(\lambda_1, \ldots, \lambda_n). \]

2° \(w(\lambda_0, \lambda_1, \ldots, \lambda_n)\) is a homogeneous polynomial of degree \(2s\), which means that it can be written in the form:

(3.3.9)
\[ w(\lambda_0, \lambda_1, \ldots, \lambda_n) = \sum w_{i_0, i_1, \ldots, i_n} \lambda_0^{i_0} \lambda_1^{i_1} \ldots \lambda_n^{i_n}, \]

where \(i_0 + i_1 + \ldots + i_n = 2s\).

3° We have

(3.3.10)
\[ w(\lambda_0, \lambda_1, \ldots, \lambda_n) \geq 0 \quad\text{and} \]
(3.3.11)
\[ w(\lambda_0, \lambda_1, \ldots, \lambda_n) = 0 \]

if and only if \(\lambda_0^2 + \lambda_1^2 + \ldots + \lambda_n^2 = 0\).

These properties are obvious.

4° One can determine two positive numbers \(\alpha\) and \(\beta\), \(\alpha \lt \beta\), such that

(3.3.12)
\[ \alpha |\lambda|^{2s} \leq w(\lambda_0, \lambda_1, \ldots, \lambda_n) \leq \beta |\lambda|^{2s}, \]

where

(3.3.13)
\[ |\lambda| = \sqrt{\lambda_0^2 + \lambda_1^2 + \ldots + \lambda_n^2}. \]

Indeed, let us consider the set of points of \(\mathbb{R}^{n+1}\) lying on the sphere \(S_1\) of radius 1, that is, the set of systems of numbers \((\mu_0, \mu_1, \ldots, \mu_n)\) for which \(|\mu| = 1\). Since this set is bounded and closed, and the function \(w(\lambda_0, \lambda_1, \ldots, \lambda_n)\) considered on this sphere is continuous, we can determine the numbers

(3.3.14)
\[ \alpha = \inf_{(\lambda_0, \lambda_1, \ldots, \lambda_n) \in S_1} w(\lambda_0, \lambda_1, \ldots, \lambda_n); \quad \beta = \sup_{(\lambda_0, \lambda_1, \ldots, \lambda_n) \in S_1} w(\lambda_0, \lambda_1, \ldots, \lambda_n). \]

The number \(\alpha\) is positive, because the function \(w(\lambda_0, \lambda_1, \ldots, \lambda_n)\) is positive on the sphere and its \(\inf\) is attained on the sphere; hence it is positive.

We shall have

(3.3.15)
\[ \alpha \leq w(\mu_0, \mu_1, \ldots, \mu_n) \leq \beta \quad\text{for } |\mu| = 1. \]

Given an arbitrary system of real numbers \((\lambda_0, \lambda_1, \ldots, \lambda_n)\), one can determine a system of numbers \((\mu_0, \mu_1, \ldots, \mu_n)\), where \(|\mu| = 1\), and a positive number \(l\) such that

(3.3.16)
\[ \lambda_i = l \mu_i, \qquad (i = 0, 1, \ldots, n). \]

Since the function \(w(\lambda_0, \lambda_1, \ldots, \lambda_n)\) is a homogeneous polynomial of degree \(2s\), we have \(w(\lambda_0, \lambda_1, \ldots, \lambda_n) = l^{2s} w(\mu_0, \mu_1, \ldots, \mu_n)\), and by inequalities (3.3.15) we have

(3.3.17)
\[ l^{2s} \alpha \leq w(\lambda_0, \lambda_1, \ldots, \lambda_n) \leq l^{2s} \beta. \]

Formulas (3.3.16) show that \(l = |\lambda| = \sqrt{\lambda_0^2 + \lambda_1^2 + \ldots + \lambda_n^2}\), and therefore inequalities (3.3.17) can be written in the form

(3.3.18)
\[ \alpha |\lambda|^{2s} \leq w(\lambda_0, \lambda_1, \ldots, \lambda_n) \leq \beta |\lambda|^{2s}, \]

or else in the form

(3.3.19)
\[ \alpha (\lambda_0^2 + \lambda_1^2 + \ldots + \lambda_n^2)^s \leq w(\lambda_0, \lambda_1, \ldots, \lambda_n) \leq \beta (\lambda_0^2 + \lambda_1^2 + \ldots + \lambda_n^2)^s. \]

This being so, let us set \(\lambda_0 = 1\) in integral (3.3.7). Then this integral becomes a function \(w(1, \lambda_1, \ldots, \lambda_n)\) of \(\lambda_1, \lambda_2, \ldots, \lambda_n\):

(3.3.20)
\[ w(1, \lambda_1, \ldots, \lambda_n) = \int_a^b p(x) (x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n)^{2s}\, dx \]

which is fundamental for this proof and will be studied below.

Inequalities (3.3.19) become

(3.3.21)
\[ \alpha (1 + \lambda_1^2 + \ldots + \lambda_n^2)^s \leq w(1, \lambda_1, \ldots, \lambda_n) \leq \beta (1 + \lambda_1^2 + \ldots + \lambda_n^2)^s. \]

With the function \(w(1, \lambda_1, \ldots, \lambda_n)\) we shall associate the number \(\nu\) defined by the equation

(3.3.22)
\[ \alpha(1 + \nu^2)^s = \beta, \quad \text{where } \nu^2 = \lambda_1^2 + \lambda_2^2 + \ldots + \lambda_n^2. \]

We shall have

(3.3.23)
\[ \nu^2 = \left(\frac{\beta}{\alpha}\right)^{\frac{1}{s}} - 1. \]

The function \(w(1, \lambda_1, \ldots, \lambda_n)\) has several properties:

First property. We have \(w(1, \lambda_1, \ldots, \lambda_n) \gt \beta\) for \(\lambda_1^2 + \lambda_2^2 + \ldots + \lambda_n^2 \gt \nu^2\).

Indeed, by inequalities (3.3.21) we have \(w(1, \lambda_1, \ldots, \lambda_n) \geq \alpha(1 + \lambda_1^2 + \ldots + \lambda_n^2)^s\), and for \(\lambda_1^2 + \ldots + \lambda_n^2 \gt \nu^2\) we shall have \(w(1, \lambda_1, \ldots, \lambda_n) \gt \alpha(1 + \nu^2)^s = \alpha \dfrac{\beta}{\alpha} = \beta\); therefore the first property is proved.

Second property. The function \(w(1, \lambda_1, \ldots, \lambda_n)\) considered for \(\lambda_1^2 + \ldots + \lambda_n^2 \leq \nu^2\) is a continuous function defined on a bounded and closed set. Hence it attains its inf at a point \((\lambda_1^0, \ldots, \lambda_n^0)\) and we can write

(3.3.24)
\[ I = \inf_{\lambda_1^2 + \ldots + \lambda_n^2 \leq \nu^2} w(1, \lambda_1, \ldots, \lambda_n) = w(1, \lambda_1^0, \ldots, \lambda_n^0). \]

Third property. We have

(3.3.25)
\[ I = \inf_{\lambda_1^2 + \ldots + \lambda_n^2 \leq \nu^2} w(1, \lambda_1, \ldots, \lambda_n) \leq \beta \]

To prove this property, let us first observe that the point \((0, 0, \ldots, 0)\) belongs to the set of points \((\lambda_1, \ldots, \lambda_n)\) for which \(\lambda_1^2 + \ldots + \lambda_n^2 \leq \nu^2\), and inequalities (3.3.21) show that \(w(1, 0, \ldots, 0) \leq \beta\). By the definition of \(w(1, \lambda_1, \ldots, \lambda_n)\) we have

\[ I \leq w(1, \lambda_1, \ldots, \lambda_n) \leq \beta \]

for every point \((\lambda_1, \ldots, \lambda_n)\) for which \(\lambda_1^2 + \ldots + \lambda_n^2 \lt \nu^2\). In particular, we shall have

\[ I \leq w(1, 0, \ldots, 0) \leq \beta \]

and thus the third property is proved.

Fourth property. The function \(w(1, \lambda_1, \ldots, \lambda_n)\) considered for \((\lambda_1, \ldots, \lambda_n) \in \mathbb{R}^n\) has an inf attained at least at one point of \(\mathbb{R}^n\).

To see this, we observe that if we consider the function \(w(1, \lambda_1, \ldots, \lambda_n)\) for \(\lambda_1^2 + \ldots + \lambda_n^2 \geq \nu^2\), we have by the first property \(w(1, \lambda_1, \ldots, \lambda_n) \gt \beta\).

But if we consider the function \(w(1, \lambda_1, \ldots, \lambda_n)\) for \(\lambda_1^2 + \ldots + \lambda_n^2 \leq \nu^2\), it has an inf attained at \((\lambda_1^0, \ldots, \lambda_n^0)\), and by the third property we have

\[ I = \inf_{\lambda_1^2 + \ldots + \lambda_n^2 \leq \nu^2} w(1, \lambda_1, \ldots, \lambda_n) \leq \beta. \]

Hence \(I\) is the inf of the function \(w(1, \lambda_1, \ldots, \lambda_n)\) for \((\lambda_1, \ldots, \lambda_n) \in \mathbb{R}^n\), and it is attained at the point \((\lambda_1^0, \ldots, \lambda_n^0) \in \mathbb{R}^n\), because, by the first property, \(I\) cannot be attained at points \((\lambda_1, \ldots, \lambda_n)\) for which \(\lambda_1^2 + \ldots + \lambda_n^2 \gt \nu^2\).

Fifth property. If

(3.3.26)
\[ I = \inf_{(\lambda_1, \ldots, \lambda_n) \in \mathbb{R}^n} w(1, \lambda_1, \ldots, \lambda_n) = w(1, \lambda_1^0, \ldots, \lambda_n^0), \]

then we have the formulas

(3.3.27)
\[ \frac{\partial w}{\partial \lambda_1}(1, \lambda_1^0, \ldots, \lambda_n^0) = 0, \ldots, \frac{\partial w}{\partial \lambda_n}(1, \lambda_1^0, \ldots, \lambda_n^0) = 0. \]

Indeed, the function \(w(1, \lambda_1, \ldots, \lambda_n)\) is defined at every point \((\lambda_1, \ldots, \lambda_n) \in \mathbb{R}^n\), and the point \((\lambda_1^0, \ldots, \lambda_n^0)\) at which the function attains its inf is an interior point. It follows that \((\lambda_1^0, \ldots, \lambda_n^0)\) is a minimum point, and therefore we have formulas (3.3.27).

Sixth property. The point \((\lambda_1^0, \ldots, \lambda_n^0)\) at which the function \(w(1, \lambda_1, \ldots, \lambda_n)\) attains its inf for \((\lambda_1, \ldots, \lambda_n) \in \mathbb{R}^n\) is unique.

This property is connected with the inequality

(3.3.28)
\[ \left(\frac{u + v}{2}\right)^{2s} \lt \frac{u^{2s} + v^{2s}}{2} \]

valid for \(s = 1, 2, \ldots\) and \(u \neq v\), which is a particular case of the inequality

(3.3.29)
\[ (Au + Bv)^{2s} \lt Au^{2s} + Bv^{2s}, \]

where \(A\) and \(B\) are two positive real numbers, \(A + B = 1\), and \(u \neq v\).

Inequality (3.3.28) is easily proved.

This being so, let us assume that the point \((\lambda_1^0, \ldots, \lambda_n^0)\) at which the function \(w(1, \lambda_1, \ldots, \lambda_n)\) attains its inf is not unique, which means that there exist at least two different points \((\lambda_1^0, \ldots, \lambda_n^0)\) and \((\lambda_1', \ldots, \lambda_n')\) at which the inf is attained. Then we have

(3.3.30)
\[ I = \inf_{(\lambda_1, \ldots, \lambda_n) \in \mathbb{R}^n} w(1, \lambda_1, \ldots, \lambda_n) = w(1, \lambda_1^0, \ldots, \lambda_n^0) = w(1, \lambda_1^1, \ldots, \lambda_n^1). \]

The polynomials

(3.3.31)
\[ u(x) = x^n + \lambda_1^0 x^{n-1} + \ldots + \lambda_n^0, \quad v(x) = x^n + \lambda_1^1 x^{n-1} + \ldots + \lambda_n^1 \]

are not identical. They may coincide at a certain number of points \(c_1, c_2, \ldots, c_q\) of the interval \([a, b]\), where \(q \leq n\).

On the intervals \((a, c_1), (c_1, c_2), \ldots, (c_q, b)\) we shall have the inequalities

\[ \left(\frac{u(x) + v(x)}{2}\right)^{2s} \lt \frac{u^{2s}(x) + v^{2s}(x)}{2} \]

as inequality (3.3.28) shows.

Taking into account formulas (3.3.31), we can write

\[ \left(x^n + \frac{(\lambda_1^0 + \lambda_1^1) x^{n-1} + \ldots + (\lambda_n^0 + \lambda_n^1)}{2}\right)^{2s} \lt \frac{1}{2}(x^n + \lambda_1^0 x^{n-1} + \ldots + \lambda_n^0)^{2s} + \frac{1}{2}(x^n + \lambda_1^1 x^{n-1} + \ldots + \lambda_n^1)^{2s} \]

valid on each interval \((a, c_1), (c_1, c_2), \ldots, (c_q, b)\).

Multiplying both sides of this inequality by \(p(x)\), where \(x \in (c_i, c_{i+1})\), and integrating from \(c_i\) to \(c_{i+1}\), we have

(3.3.32)
\[ \begin{aligned} &\int_{c_i}^{c_{i+1}} p(x) \left(x^n + \frac{(\lambda_1^0 + \lambda_1^1) x^{n-1} + \ldots + (\lambda_n^0 + \lambda_n^1)}{2}\right)^{2s} dx \lt \\ &\qquad \lt \frac{1}{2} \int_{c_i}^{c_{i+1}} p(x) (x^n + \lambda_1^0 x^{n-1} + \ldots + \lambda_n^0)^{2s}\, dx + \\ &\qquad + \frac{1}{2} \int_{c_i}^{c_{i+1}} p(x) (x^n + \lambda_1^1 x^{n-1} + \ldots + \lambda_n^1)^{2s}\, dx. \end{aligned} \]

We may consider inequalities (3.3.32) for \(i = 0, 1, \ldots, q\), where \(c_0 = a\), \(c_{q+1} = b\).

Adding all these inequalities term by term, we find

\[ \begin{aligned} &\int_a^b p(x) \left(x^n + \frac{(\lambda_1^0 + \lambda_1^1) x^{n-1} + \ldots + (\lambda_n^0 + \lambda_n^1)}{2}\right)^{2s} dx \lt \\ &\qquad \lt \frac{1}{2} \int_a^b p(x) (x^n + \lambda_1^0 x^{n-1} + \ldots + \lambda_n^0)^{2s}\, dx + \\ &\qquad + \frac{1}{2} \int_a^b p(x) (x^n + \lambda_1^1 x^{n-1} + \ldots + \lambda_n^1)^{2s}\, dx, \end{aligned} \]

that is,

(3.3.33)
\[ w\left(1, \frac{\lambda_1^0 + \lambda_1^1}{2}, \ldots, \frac{\lambda_n^0 + \lambda_n^1}{2}\right) \lt \frac{1}{2} w(1, \lambda_1^0, \ldots, \lambda_n^0) + \frac{1}{2} w(1, \lambda_1^1, \ldots, \lambda_n^1). \]

But we have assumed that

\[ w(1, \lambda_1^0, \ldots, \lambda_n^0) = w(1, \lambda_1^1, \ldots, \lambda_n^1) = \inf_{(\lambda_1, \ldots, \lambda_n) \in \mathbb{R}^n} w(1, \lambda_1, \ldots, \lambda_n) \]

and it follows from inequality (3.3.33) that

\[ w\left(1, \frac{\lambda_1^0 + \lambda_1^1}{2}, \ldots, \frac{\lambda_n^0 + \lambda_n^1}{2}\right) \lt \inf_{(\lambda_1, \ldots, \lambda_n) \in \mathbb{R}^n} w(1, \lambda_1, \ldots, \lambda_n) \]

which contradicts the definition of the inf of \(w\).

From this contradiction follows the uniqueness of the point \((\lambda_1^0, \ldots, \lambda_n^0)\) at which the function \(w(1, \lambda_1, \ldots, \lambda_n)\) attains its inf.

Seventh property. The function \(w(1, \lambda_1, \ldots, \lambda_n)\) cannot have any relative minimum other than the minimum corresponding to the point \((\lambda_1^0, \ldots, \lambda_n^0)\), where it attains its inf.

Let us assume that there exists a point \((\lambda_1', \ldots, \lambda_n')\) different from \((\lambda_1^0, \ldots, \lambda_n^0)\) at which the function \(w(1, \lambda_1, \ldots, \lambda_n)\) has a relative minimum. This means that there exists a number \(\gamma \gt 0\) such that for every point \((\lambda_1, \ldots, \lambda_n)\) in a \(\gamma\)-neighborhood of the point \((\lambda_1', \ldots, \lambda_n')\) we have

(3.3.34)
\[ w(1, \lambda_1, \ldots, \lambda_n) \gt w(1, \lambda_1', \ldots, \lambda_n'). \]

Let us consider the polynomials \(\varphi_{\lambda^0}(x) = x^n + \lambda_1^0 x^{n-1} + \ldots + \lambda_n^0\), \(\varphi_{\lambda^1}(x) = x^n + \lambda_1' x^{n-1} + \ldots + \lambda_n'\) and \(\varphi(x) = A\varphi_{\lambda^0}(x) + B\varphi_{\lambda^1}(x)\), where \(A\) and \(B\) are two positive numbers, \(A + B = 1\). The numbers \(A\), \(B\) will be subjected to further conditions, which we shall specify later.

We can write

\[ \varphi(x) = x^n + (A\lambda_1^0 + B\lambda_1') x^{n-1} + \ldots + (A\lambda_n^0 + B\lambda_n'). \]

Since the points \((\lambda_1^0, \ldots, \lambda_n^0)\), \((\lambda_1', \ldots, \lambda_n')\) are distinct, the polynomials \(\varphi_{\lambda^0}\), \(\varphi_{\lambda^1}\) are not identical. They may coincide at a certain number of points \(d_1, \ldots, d_q\). Let us put \(d_0 = a\), \(d_{q+1} = b\) and apply inequality (3.3.29) on each interval \((a, d_1), (d_1, d_2), \ldots, (d_q, b)\). We shall have

\[ (\varphi(x))^{2s} \lt A(\varphi_{\lambda^0}(x))^{2s} + B(\varphi_{\lambda^1}(x))^{2s}, \quad x \in (d_i, d_{i+1}),\ i = 0, 1, \ldots, q. \]

Multiplying both sides by \(p(x)\), then integrating from \(d_i\) to \(d_{i+1}\) and adding these inequalities term by term, we shall have

(3.3.35)
\[ w(1, A\lambda_1^0 + B\lambda_1', \ldots, A\lambda_n^0 + B\lambda_n') \lt Aw(1, \lambda_1^0, \ldots, \lambda_n^0) + Bw(1, \lambda_1', \ldots, \lambda_n'). \]

Let us now consider a positive number \(\varepsilon \lt \gamma\) and choose the number \(A\) such that

(3.3.36)
\[ A |\lambda_i' - \lambda_i^0| \lt \varepsilon, \qquad (i = 1, 2, \ldots, n). \]

Then the point \((A\lambda_1^0 + B\lambda_1', \ldots, A\lambda_n^0 + B\lambda_n')\) belongs to the neighborhood of \((\lambda_1', \ldots, \lambda_n')\), where \(\varepsilon \lt \gamma\), because

\[ |\lambda_i' - A\lambda_i^0 - B\lambda_i'| = |\lambda_i' - A\lambda_i^0 - (1 - A)\lambda_i'| = A|\lambda_i' - \lambda_i^0| \lt \varepsilon. \]

Let us return to inequality (3.3.35), which we write in the form

\[ w(1, A\lambda_1^0 + B\lambda_1', \ldots, A\lambda_n^0 + B\lambda_n') \lt Aw(1, \lambda_1^0, \ldots, \lambda_n^0) + (1 - A)\, w(1, \lambda_1', \ldots, \lambda_n') \]

or else in the form

(3.3.37)
\[ w(1, A\lambda_1^0 + B\lambda_1', \ldots, A\lambda_n^0 + B\lambda_n') + A[w(1, \lambda_1', \ldots, \lambda_n') - w(1, \lambda_1^0, \ldots, \lambda_n^0)] \lt w(1, \lambda_1', \ldots, \lambda_n'). \]

But since \((\lambda_1^0, \ldots, \lambda_n^0)\) is the point at which the function \(w(1, \lambda_1, \ldots, \lambda_n)\) attains its inf, the large bracket on the left-hand side is positive. On the left-hand side of inequality (3.3.37) both terms are positive, and it follows that for a number \(A\) satisfying the inequalities \(A \lt 1\) and \(A|\lambda_i' - \lambda_i^0| \lt \varepsilon\), \(i = 1, 2, \ldots, n\), we have the inequality \(w(1, A\lambda_1^0 + B\lambda_1', \ldots, A\lambda_n^0 + B\lambda_n') \lt w(1, \lambda_1', \ldots, \lambda_n')\), which contradicts the hypothesis that the function \(w(1, \lambda_1, \ldots, \lambda_n)\) has a minimum at \((\lambda_1', \ldots, \lambda_n')\).

We must reject this hypothesis, and therefore the function \(w(1, \lambda_1, \ldots, \lambda_n)\) has no relative minimum other than at the point \((\lambda_1^0, \ldots, \lambda_n^0)\), where it attains its inf.

Eighth property. The function \(w(1, \lambda_1, \ldots, \lambda_n)\) has no maximum.

Let us assume that there exists a point \((\lambda_1'', \ldots, \lambda_n'') \in \mathbb{R}^n\) at which the function \(w(1, \lambda_1, \ldots, \lambda_n)\) has a maximum. This means that there would exist a positive number \(\gamma\) such that for every point \((\lambda_1, \ldots, \lambda_n)\) in a \(\gamma\)-neighborhood of \((\lambda_1'', \ldots, \lambda_n'')\) we have

(3.3.38)
\[ w(1, \lambda_1'', \ldots, \lambda_n'') \gt w(1, \lambda_1, \ldots, \lambda_n). \]

This inequality holds for all points \((\lambda_1, \ldots, \lambda_n)\) satisfying the conditions

(3.3.39)
\[ |\lambda_i'' - \lambda_i| \lt \gamma, \qquad (i = 1, 2, \ldots, n). \]

Let us proceed as in the proof of the seventh property and consider the polynomials \(\varphi_{\lambda^0}(x) = x^n + \lambda_1^0 x^{n-1} + \ldots + \lambda_n^0\); \(\varphi_\lambda(x) = x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n\), where \((\lambda_1^0, \ldots, \lambda_n^0)\) is the point at which the function \(w(1, \lambda_1, \ldots, \lambda_n)\) attains its inf, and \((\lambda_1, \ldots, \lambda_n)\) is a point that will be specified later.

Let us also consider the polynomial

(3.3.40)
\[ \varphi(x) = A\varphi_{\lambda^0}(x) + B\varphi_\lambda(x), \]

where \(A\), \(B\) are two positive numbers, \(A + B = 1\), and where \(A\) will be subjected to further conditions, which we shall specify later. We have

(3.3.41)
\[ \varphi(x) = x^n + (A\lambda_1^0 + B\lambda_1) x^{n-1} + \ldots + A\lambda_n^0 + B\lambda_n. \]

Let us assume that the point \((\lambda_1, \ldots, \lambda_n)\) is given by the equations

(3.3.42)
\[ \lambda_i'' = A\lambda_i^0 + B\lambda_i, \qquad (i = 1, 2, \ldots, n) \]

that is,

(3.3.43)
\[ \lambda_i = \frac{\lambda_i'' - A\lambda_i^0}{B}. \qquad (i = 1, 2, \ldots, n) \]

so that

(3.3.44)
\[ \varphi(x) = x^n + \lambda_1'' x^{n-1} + \ldots + \lambda_n''. \]

Since the points \((\lambda_1^0, \ldots, \lambda_n^0)\), \((\lambda_1, \ldots, \lambda_n)\) are distinct, the polynomials \(\varphi_{\lambda^0}\), \(\varphi_\lambda\) are not identical. Proceeding as in the proof of the seventh property and using inequality (3.3.29), we deduce the inequality

(3.3.45)
\[ w(1, \lambda_1'', \ldots, \lambda_n'') \lt Aw(1, \lambda_1^0, \ldots, \lambda_n^0) + Bw(1, \lambda_1, \ldots, \lambda_n). \]

This being so, let \(\varepsilon\) be a positive number, \(\varepsilon \lt \gamma\), and let us show that we can impose conditions on \(A\) such that the point \((\lambda_1, \ldots, \lambda_n)\) lies in a \(\gamma\)-neighborhood of the point \((\lambda_1'', \ldots, \lambda_n'')\). Formulas (3.3.42) show that

\[ \lambda_i'' - \lambda_i = \frac{A(\lambda_i^0 - \lambda_i'')}{1 - A}, \qquad (i = 1, 2, \ldots, n). \]

In order that the point \((\lambda_1, \ldots, \lambda_n)\) lie in an \(\varepsilon\)-neighborhood of the point \((\lambda_1'', \ldots, \lambda_n'')\), we shall take \(A\) such that

\[ \frac{A}{1 - A} |\lambda_i^0 - \lambda_i''| \lt \varepsilon \lt \gamma, \qquad (i = 1, 2, \ldots, n) \]

that is,

(3.3.46)
\[ A \lt \frac{\varepsilon}{|\lambda_i'' - \lambda_i^0| + \varepsilon} \qquad (i = 1, 2, \ldots, n) \]

and we observe that \(A \lt 1\).

Returning to inequality (3.3.45), we can write \(w(1, \lambda_1'', \ldots, \lambda_n'') \lt Aw(1, \lambda_1^0, \ldots, \lambda_n^0) + (1 - A)\, w(1, \lambda_1, \ldots, \lambda_n)\), or else

(3.3.47)
\[ w(1, \lambda_1'', \ldots, \lambda_n'') + A[w(1, \lambda_1, \ldots, \lambda_n) - w(1, \lambda_1^0, \ldots, \lambda_n^0)] \lt w(1, \lambda_1, \ldots, \lambda_n). \]

But the large bracket is positive, because \((\lambda_1^0, \ldots, \lambda_n^0)\) is the point at which the function \(w(1, \lambda_1, \ldots, \lambda_n)\) attains its inf.

It then follows from inequality (3.3.47) that at the point \((\lambda_1, \ldots, \lambda_n)\) we have \(w(1, \lambda_1'', \ldots, \lambda_n'') \lt w(1, \lambda_1, \ldots, \lambda_n)\), which is contrary to the hypothesis that the function \(w(1, \lambda_1, \ldots, \lambda_n)\) has a maximum at the point \((\lambda_1'', \ldots, \lambda_n'')\), a hypothesis expressed by inequalities (3.3.38).

We must therefore reject this hypothesis, and consequently the function \(w(1, \lambda_1, \ldots, \lambda_n)\) has no maximum.

The eighth property is thus proved.

By means of the properties of the function

(3.3.48)
\[ w(1, \lambda_1, \ldots, \lambda_n) = \int_a^b p(x) (x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n)^{2s}\, dx \]

it has been shown that it has a unique minimum, equal to its inf and attained at the point \((\lambda_1^0, \ldots, \lambda_n^0)\).

The coefficients \(\lambda_1, \lambda_2, \ldots, \lambda_n\) of the minimizing polynomial are determined uniquely by equations (3.3.27), that is, by the equations

(3.3.49)
\[ \frac{\partial w}{\partial \lambda_1}(1, \lambda_1, \ldots, \lambda_n) = 0, \ldots, \frac{\partial w}{\partial \lambda_n}(1, \lambda_1, \ldots, \lambda_n) = 0, \]

which can be written in the form

(3.3.50)
\[ \int_a^b p(x)\, \omega_n^{2s-1}(x)\, x^h\, dx = 0 \quad \text{for } h = 0, 1, \ldots, n - 1 \]

where \(\omega_n(x) = x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n\) is the minimizing polynomial.

Thus Theorems 3.3.1 and 3.3.2 are proved.

3.3.3. Proof of Theorem 3.3.3. Once the polynomial

(3.3.4)
\[ \omega_n(x) = x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n \]

has been determined by equations (3.3.5)

(3.3.5)
\[ \int_a^b p(x)\, \omega_n^{2s-1}(x)\, x^h\, dx = 0, \]

where \(h = 0, 1, \ldots, n - 1\), which determine its coefficients \(\lambda_1, \lambda_2, \ldots, \lambda_n\), we shall prove that it has all its roots real, distinct and lying between \(a\) and \(b\).

Let us first prove that the polynomial \(\omega_n(x)\) has all its roots real and lying between \(a\) and \(b\). To this end, we observe that from equations (3.3.5) we can deduce the identity

(3.3.51)
\[ \int_a^b p(x)\, \omega_n^{2(s-1)}(x)\, \omega_n(x)\, Q(x)\, dx = 0 \]

valid for every polynomial of degree at most \(n-1\), and we take into account that, by our hypotheses, the function \(p(x)\) is positive on the interval \((a, b)\).

If we put \(Q(x) = 1\) in identity (3.3.51), we must have

(3.3.52)
\[ \int_a^b p(x)\, \omega_n^{2(s-1)}(x)\, \omega_n(x)\, dx = 0 \]

which proves that the polynomial \(\omega_n(x)\) has at least one root \(x_1\) lying between \(a\) and \(b\), since otherwise identity (3.3.52) would be impossible.

Suppose we have proved that the polynomial \(\omega_n(x)\) has \(x_1, x_2, \ldots, x_k\) roots lying between \(a\) and \(b\), \(k \lt n\), which is true for \(k = 1\). Then let us write

(3.3.53)
\[ \omega_n(x) = (x - x_1) \ldots (x - x_k)\, \pi_{n-k}(x), \]

where \(\pi_{n-k}(x)\) is a polynomial of degree \(n-k\). Let us prove that the polynomial \(\pi_{n-k}(x)\) must have at least one real root lying between \(a\) and \(b\).

Indeed, let us replace in identity (3.3.51) the polynomial \(\omega_n(x)\) by formula (3.3.53); then, choosing \(Q(x) = (x - x_1) \ldots (x - x_k)\), we can write

(3.3.54)
\[ \int_a^b p(x)\, \omega_n^{2(s-1)}(x)\, (x - x_1)^2 \ldots (x - x_k)^2\, \pi_{n-k}(x)\, dx = 0 \]

which proves that the polynomial \(\pi_{n-k}(x)\) has at least one real root \(x_{k+1}\) lying between \(a\) and \(b\), since otherwise identity (3.3.54) would be impossible.

The preceding argument proves that all the roots of the polynomial \(\omega_n(x)\) are real and lie between \(a\) and \(b\).

Let us now prove that the roots of the polynomial \(\omega_n(x)\) are distinct.

To this end, let us assume that the polynomial \(\omega_n(x)\) has two equal roots \(x'\), \(x''\), which allows us to write

(3.3.55)
\[ \omega_n(x) = (x - x')^2\, \pi_2(x), \]

where \(\pi_2(x)\) is a polynomial of degree \(n - 2\).

If we choose \(Q(x) = \pi_2(x)\) in identity (3.3.51), we can write this identity in the form

(3.3.56)
\[ \int_a^b p(x)\, \omega_n^{2(s-1)}(x)\, (x - x')^2\, \pi_2^2(x)\, dx = 0 \]

which is impossible.

Hence all the roots of the polynomial \(\omega_n(x)\) are distinct, and Theorem 3.3.3 is proved.

3.3.4. We shall give the proof of P. Turán's Theorem 3.3.4 on the nodes and the coefficients of the formula

(3.3.57)
\[ \begin{aligned} \int_a^b p(x) f(x)\, dx = {} & C_1^{(0)} f(x_1) + \ldots + C_n^{(0)} f(x_n) + \\ & + C_1^{(1)} f'(x_1) + \ldots + C_n^{(1)} f'(x_n) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + C_1^{(2(s-1))} f^{(2(s-1))}(x_1) + \ldots + C_n^{(2(s-1))} f^{(2(s-1))}(x_n). \end{aligned} \]

This formula must be valid for \(f(x) = x^k\), where \(k = 0, 1, \ldots, 2ns - 1\).

To determine the nodes and the coefficients of formula (3.3.57), we must require that this formula become an identity when we replace the function \(f\) by

(3.3.58)
\[ \begin{array}{lll} 1, & x & , \ldots, x^{n-1} \\ x^n, & x^{n+1} & , \ldots, x^{2n-1} \\ \ldots\ldots\ldots & \ldots\ldots & , \ldots, \ldots\ldots \\ x^{(2s-2)n}, & x^{(2s-2)n+1} & , \ldots, x^{(2s-1)n-1} \end{array} \]

and

(3.3.59)
\[ x^{(2s-1)n}, x^{(2s-1)n+1}, \ldots, x^{2sn-1}. \]

We may also say that formula (3.3.57) holds when the function \(f\) is replaced by an arbitrary polynomial \(Q\) of degree at most \(2sn - 1\).

Let us denote by

(3.3.60)
\[ \omega_n(x) = x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n \]

the polynomial whose roots are the nodes \(x_1, x_2, \ldots, x_n\) of formula (3.3.57). To determine the nodes \(x_1, x_2, \ldots, x_n\) means to determine the coefficients \(\lambda_1, \lambda_2, \ldots, \lambda_n\) of the polynomial \(\omega_n(x)\).

The polynomials

(3.3.61)
\[ Q(x) = \omega_n^{2s-1}(x)\, x^h, \]

where \(h = 0, 1, \ldots, n - 1\), are of degree \((2s - 1)n + h \leq 2sn - 1\). The polynomial \(Q(x)\) can also be written in the form

(3.3.62)
\[ Q(x) = (x - x_1)^{2s-1} \ldots (x - x_n)^{2s-1} x^h \]

and one sees that \(Q(x), Q'(x), \ldots, Q^{(2(s-1))}(x)\) vanish for \(x = x_1, \ldots, x = x_n\). It follows that if in formula (3.3.57) the function \(f\) is replaced by the polynomial (3.3.61) or (3.3.62), we obtain the equations

(3.3.63)
\[ \int_a^b p(x)\, \omega_n^{2s-1}(x)\, x^h\, dx = 0 \]

for determining the coefficients \(\lambda_1, \lambda_2, \ldots, \lambda_n\) of the polynomial \(\omega_n(x)\). This system is identical with system (3.3.5) and was studied in the proofs of Theorems 3.3.1 and 3.3.2. It was shown that this system has a unique solution, which gives the minimizing polynomial of the integral

(3.3.3)
\[ \int_a^b p(x)\, \omega_n^{2s}(x)\, dx. \]

Moreover, it was proved in Theorem 3.3.3 that the polynomial \(\omega_n(x)\) has real, distinct roots lying between \(a\) and \(b\).

Hence the nodes \(x_1, x_2, \ldots, x_n\) of formula (3.3.57) are the roots of the minimizing polynomial \(\omega_n(x)\) of integral (3.3.3).

Thus the first part of Theorem 3.3.4 is proved.

It remains to determine the coefficients of formula (3.3.57). For this it suffices to write that formula (3.3.57) is satisfied when the function \(f\) is replaced by the functions (3.3.58).

We then find the system of linear equations

(3.3.64)
\[ \begin{aligned} \sum_{j=1}^{n} C_j^{(0)} &= \int_a^b p(x)\, dx \\ \sum_{j=1}^{n} [C_j^{(0)} x_j + C_j^{(1)} (x_j)'] &= \int_a^b p(x)\, x\, dx \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots &\ldots\ldots\ldots\ldots \\ \sum_{j=1}^{n} [C_j^{(0)} x_j^{(2s-1)n-1} + C_j^{(1)} (x_j^{(2s-1)n-1})' + \ldots + C_j^{2(s-1)} (x_j^{(2s-1)n-1})^{2(s-1)}] &= \int_a^b p(x)\, x^{(2s-1)n-1}\, dx \end{aligned} \]

This is a system of \((2s-1)n\) equations in \((2s-1)n\) unknowns \(C_1^{(0)}, C_1^{(1)}, \ldots, C_1^{(2s-2)}, \ldots, C_n^{(0)}, C_n^{(1)}, \ldots, C_n^{(2s-2)}\), whose determinant is the generalized Vandermonde determinant \(V(\underbrace{x_1, \ldots, x_1}_{2s-1}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s-1})\), which is different from zero because the nodes \(x_1, x_2, \ldots, x_n\) are distinct.

The second part of Theorem 3.3.4 is therefore proved. The coefficients of formula (3.3.57) are given by the system of equations (3.3.64).

3.3.5. The remainder of P. Turán's quadrature formula when \(p(x) = 1\). Let us suppose that in P. Turán's quadrature formula (3.3.1) we have \(p(x) = 1\). Then the remainder of this formula can be determined by a method analogous to the one used to determine the remainder of the Gauss formula (§ 3.2).

To this end let us consider the divided difference of the function \(g\) on the simple nodes \(a, b\) and on the distinct nodes \(x_1, x_2, \ldots, x_n\), each of multiplicity \(2s\):

(3.3.65)
\[ [a, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, b; g]. \]

We have

(3.3.66)
\[ [a, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, b; g] = V^{-1} \begin{vmatrix} 1 & a & \ldots & a^{2ns} & g(a) \\ 1 & x_1 & \ldots & x_1^{2ns} & g(x_1) \\ 0 & 1 & \ldots & (x_1^{2ns})' & g'(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_1^{2ns})^{(2s-1)} & g^{(2s-1)}(x_1) \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & b & \ldots & b^{2ns} & g(b) \end{vmatrix} \]

where \(V\) is the generalized Vandermonde determinant,

(3.3.67)
\[ V = V(a, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, b). \]

Let us expand the determinant on the right-hand side of formula (3.3.66) along the elements of the last column. We shall have

(3.3.68)
\[ \begin{aligned} {[}a, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, b; g] &= A_0 g(a) + A_1^{(0)} g(x_1) + \ldots + A_n^{(0)} g(x_n) + A_{n+1} g(b) + \\ &\quad + A_1^{(1)} g'(x_1) + \ldots + A_n^{(1)} g'(x_n) + \\ &\quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &\quad + A_1^{(2s-1)} g^{(2s-1)}(x_1) + \ldots + A_n^{(2s-1)} g^{(2s-1)}(x_n), \end{aligned} \]

where \(A_1^{(0)}, A_2^{(0)}, \ldots, A_n^{(0)}\) are the coefficients in which we are particularly interested in this work. We have

(3.3.69)
\[ A_1^{(0)} = V^{-1} \begin{vmatrix} 1 & a & \ldots & a^{2ns} \\ 0 & 1 & \ldots & (x_1^{2ns})' \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_1^{2ns})^{(2s-1)} \\ 1 & x_2 & \ldots & x_2^{2ns} \\ 0 & 1 & \ldots & (x_2^{2ns})' \\ \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & \ldots & (x_2^{2ns})^{(2s-1)} \\ \ldots & \ldots & \ldots & \ldots \\ 1 & b & \ldots & b^{2ns} \end{vmatrix} ;\ A_2^{(0)} = \ldots ;\ \ldots ;\ A_n^{(0)} = \ldots \]

Let

(3.3.70)
\[ \pi_n(x) = x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n \]

be the minimizing polynomial of the integral

(3.3.71)
\[ \int_a^b (x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n)^{2s}\, dx, \]

which was studied in subsection 3.3.2 and whose roots are real, distinct and lie between \(a\) and \(b\).

We have:

Theorem 3.3.5. If in formula (3.3.68) the nodes \(x_1, x_2, \ldots, x_n\) are the roots of the minimizing polynomial \(\pi_n\) of the integral (3.3.71), then the coefficients \(A_1^{(0)}, A_2^{(0)}, \ldots, A_n^{(0)}\) are zero.

It suffices to give the proof for one of these coefficients, for example for \(A_1^{(0)}\).

To this end we write the coefficient \(A_1^{(0)}\) in the form

\[ A_1^{(0)} = L_1^{(0)} \begin{vmatrix} -1 & 0 & 0 & \ldots 0 & \ldots 0 & \ldots 0 & 1 & \ldots 1 & 1 \\ -a & 1 & 0 & 0 & 1 & 0 & x_2 & x_n & b \\ -a^2 & (x_1^2)' & (x_1^2)'' & \ldots 0 & \ldots (x_n^2)' & \ldots 0 & x_2^2 & \ldots x_n^2 & b^2 \\ \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots \\ -a^{2ns} & (x_1^{2ns})' & (x_1^{2ns})'' & \ldots (x_1^{2ns})^{(2s-1)} & \ldots (x_n^{2ns})' & \ldots (x_n^{2ns})^{(2s-1)} & x_2^{2ns} & \ldots x_n^{2ns} & b^{2ns} \end{vmatrix} \]

where \(L_1^{(0)}\) is a coefficient which differs from \(V^{-1}\) by a factor of 1 or \(-1\).

Adding the elements of the last column to the elements of the first column and placing next to \(L_1^{(0)}\) the factor \(1, 2, \ldots, 2ns\), we can write \(A_1^{(0)}\) in the form

(3.3.72)
\[ A_1^{(0)} = (2ns)!\, L_1^{(0)} \begin{vmatrix} 0 & 0 & 0 & \ldots 0 & \ldots 0 & \ldots 0 & 1 & \ldots 1 & 1 \\ \int_a^b dx & 1 & 0 & \ldots 0 & \ldots 1 & \ldots 0 & x_2 & \ldots x_n & b \\ \int_a^b x\, dx & x_1 & 1 & \ldots 0 & \ldots x_n & \ldots 0 & \frac{x_2^2}{2} & \ldots \frac{x_n^2}{2} & \frac{b^2}{2} \\ \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots \\ \int_a^b x^{2ns-1}\, dx & x_1^{2ns-1} & (x_1^{2ns-1})' & \ldots (x_1^{2ns-1})^{(2s-2)} & \ldots x_n^{2ns-1} & \ldots (x_n^{2ns-1})^{(2s-2)} & \frac{x_2^{2ns}}{2ns} & \ldots \frac{x_n^{2ns}}{2ns} & \frac{b^{2ns}}{2ns} \end{vmatrix} \]

But if we write that P. Turán's formula (3.3.57) is verified when the function \(f\) is replaced by the functions (3.3.58) and (3.3.59), we have the identities

(3.3.73)
\[ \begin{aligned} \sum_{j=1}^{n} C_j^{(0)} &= \int_a^b dx \\ \sum_{j=1}^{n} [C_j^{(0)} x_j + C_j^{(1)} (x_j)'] &= \int_a^b x\, dx \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots &\ldots\ldots\ldots\ldots \\ \sum_{j=1}^{n} [C_j^{(0)} x_j^{2ns-1} + C_j^{(1)} (x_j^{2ns-1})' + \ldots + C_j^{(2s-2)} (x_j^{2ns-1})^{(2s-2)}] &= \int_a^b x^{2ns-1}\, dx \end{aligned} \]

Then among the elements of the first \((2s-1)n + 1\) columns of the determinant in formula (3.3.72) there is one and the same linear combination, given by identity (3.3.73), and therefore \(A_1^{(0)} = 0\).

Thus Theorem 3.3.5 is proved.

Taking Theorem 3.3.5 into account, formula (3.3.68) becomes, when \(x_1, x_2, \ldots, x_n\) are the roots of the minimizing polynomial \(\pi_n\) of the integral (3.3.71):

(3.3.74)
\[ \begin{aligned} & [a, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, b; g] = A_0 g(a) + A_1^{(1)} g'(x_1) + \ldots + A_n^{(1)} g'(x_n) + A_{n+1} g(b) + \\ &\quad + A_1^{(2)} g''(x_1) + \ldots + A_n^{(2)} g''(x_n) + \\ &\quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &\quad + A_1^{(2s-1)} g^{(2s-1)}(x_1) + \ldots + A_n^{(2s-1)} g^{(2s-1)}(x_n) \end{aligned} \]

If in this formula the function \(g\) is replaced by 1, we see that

(3.3.75)
\[ A_0 + A_{n+1} = 0. \]

On the other hand, we have

\[ A_0 = -V(\underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, b) \neq 0 \]

and therefore formula (3.3.74) can be written in the form

(3.3.77)
\[ \begin{aligned} & [a, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, b; g] = A_{n+1} \int_a^b g'(x)\, dx + A_1^{(1)} g'(x_1) + \ldots + A_n^{(1)} g'(x_n) + \\ &\quad + A_1^{(2)} g''(x_1) + \ldots + A_n^{(2)} g''(x_n) + \\ &\quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &\quad + A_1^{(2s-1)} g^{(2s-1)}(x_1) + \ldots + A_n^{(2s-1)} g^{(2s-1)}(x_n). \end{aligned} \]

Replacing in this identity the function \(g\) by

(3.3.78)
\[ g(x) = \int_a^x f(t)\, dt \]

and dividing both sides by \(A_{n+1}\), we obtain the formula

(3.3.79)
\[ \begin{aligned} \int_a^b f(x)\, dx &= C_1^{(0)} f(x_1) + \ldots + C_n^{(0)} f(x_n) + \\ &\quad + C_1^{(1)} f'(x_1) + \ldots + C_n^{(1)} f'(x_n) + \\ &\quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &\quad + C_1^{2(s-1)} f^{2(s-1)}(x_1) + \ldots + C_n^{2(s-1)} f^{2(s-1)}(x_n) + R[f], \end{aligned} \]

which is precisely P. Turán's quadrature formula, in which

(3.3.80)
\[ \begin{aligned} C_1^{(0)} &= -\frac{A_1^{(1)}}{A_{n+1}}, \ldots, & C_n^{(0)} &= -\frac{A_n^{(1)}}{A_{n+1}} \\ C_1^{(1)} &= -\frac{A_1^{(2)}}{A_{n+1}}, \ldots, & C_n^{(1)} &= -\frac{A_n^{(2)}}{A_{n+1}} \\ \ldots\ldots\ldots &\ldots\ldots\ldots\ldots\ldots\ldots & \ldots\ldots &\ldots\ldots\ldots \\ C_1^{2(s-1)} &= -\frac{A_1^{(2s-1)}}{A_{n+1}}, \ldots, & C_n^{2(s-1)} &= -\frac{A_n^{(2s-1)}}{A_{n+1}} \end{aligned} \]

and the remainder \(R[f]\) is

(3.3.81)
\[ R[f] = \frac{1}{A_{n+1}} \left[a, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, b; \int_a^x f(t)\, dt\right]. \]

If we use the integral representation of the divided difference on the right-hand side of formula (3.3.81), when \(f \in C^{2ns}[a, b]\), we obtain the integral representation of the remainder \(R[f]\):

(3.3.82)
\[ R[f] = \frac{1}{A_{n+1}} \int_a^b \varphi(t) f^{(2ns)}(t)\, dt \]

where the right-hand side contains the function \(\varphi\) of the integral representation of the divided difference (3.3.65) corresponding to the nodes \(x_1, x_2, \ldots, x_n\), which are the roots of the minimizing polynomial of the integral (3.3.71).

We have thus obtained:

Theorem 3.3.6. P. Turán's quadrature formula (3.3.79) is derived from the integral representation of the divided difference (3.3.65) when \(g \in C^{2ns+1}[a, b]\):

(3.3.83)
\[ [a, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, b; g] = \int_a^b \varphi(t)\, g^{(2ns+1)}(t)\, dt \]

by replacing the nodes \(x_1, x_2, \ldots, x_n\) by the roots of the minimizing polynomial \(\pi_n\) of the integral (3.3.71) and setting \(g' = f\).

The coefficients of P. Turán's formula are given by formulas (3.3.80) and the remainder \(R[f]\) by formula (3.3.82).

3.3.6. Replacing in P. Turán's quadrature formula the function \(f(x)\) by \(\pi_n^{2s}(x) = (x - x_1)^{2s}(x - x_2)^{2s} \ldots (x - x_n)^{2s}\), and taking into account expression (3.3.82) of the remainder \(R[f]\), we have

\[ \int_a^b \pi_n^{2s}(x)\, dx = \frac{(2ns)!}{A_{n+1}} \int_a^b \varphi(t)\, dt. \]

But

\[ \int_a^b \varphi(t)\, dt = \frac{1}{(2ns+1)!} \]

and therefore we have:

(3.3.84)
\[ \frac{1}{A_{n+1}} = (2ns+1) \int_a^b \pi_n^{2s}(x)\, dx, \]

which relates the coefficient \(\frac{1}{A_{n+1}}\) of formula (3.3.82) to the minimizing polynomial \(\pi_n\) of the integral (3.3.71).

3.3.7. The problem of determining the remainder \(R[f]\) also arises for P. Turán's quadrature formulas (3.3.1) with weight \(p\). This problem was solved by Paraschiva Pavel [28], who used our method of investigation, the method of the function \(\varphi\).

§ 3.4. Extension of the Gauss quadrature formula

3.4.1. In an earlier paper [6] we studied the quadrature formula of the form

(3.4.1)
\[ \begin{aligned} \int_a^b \pi(x) f(x)\, dx &= A_0 f(a) + A_1 f'(a) + \ldots + A_{p-1} f^{(p-1)}(a) + \\ &\quad + C_1 f(x_1) + C_2 f(x_2) + \ldots + C_n f(x_n) + \\ &\quad + B_0 f(b) + B_1 f'(b) + \ldots + B_{q-1} f^{(q-1)}(b) + R[f] \end{aligned} \]

which we regard as an extension of the Gauss quadrature formula, or else as a Gauss-type formula. In this formula \(\pi\) is a weight, a function integrable on the interval \([a, b]\) and positive on the interval \((a, b)\). Concerning this formula we shall first treat the following:

Problem. Determine the nodes \(x_1, x_2, \ldots, x_n\) and the coefficients \(A_0, A_1, \ldots, A_{p-1}, C_1, C_2, \ldots, C_n, B_0, B_1, \ldots, B_{q-1}\) so that in formula (3.4.1) we have \(R[f] = 0\) for \(f(x) = x^k\), \(k = 0, 1, \ldots, 2n + p + q - 1\).

We shall then have the identity

(3.4.2)
\[ \begin{aligned} \int_a^b \pi(x) f(x)\, dx &= A_0 f(a) + A_1 f'(a) + \ldots + A_{p-1} f^{(p-1)}(a) + \\ &\quad + C_1 f(x_1) + C_2 f(x_2) + \ldots + C_n f(x_n) + \\ &\quad + B_0 f(b) + B_1 f'(b) + \ldots + B_{q-1} f^{(q-1)}(b), \end{aligned} \]

for \(f(x) = x^k\), where \(k = 0, 1, \ldots, 2n + p + q - 1\).

We have to write that formula (3.4.2) becomes an identity when the function \(f\) is replaced by

(3.4.3)
\[ 1,\quad x,\quad \ldots,\quad x^{p+q-1} \]
(3.4.4)
\[ x^{p+q},\quad x^{p+q+1},\quad \ldots,\quad x^{p+q+n-1} \]
(3.4.5)
\[ x^{p+q+n},\quad x^{p+q+n+1},\quad \ldots,\quad x^{p+q+2n-1}. \]

We can also write that formula (3.4.2) holds when the function \(f\) is replaced by an arbitrary polynomial \(Q\) of degree at most \(2n + p + q - 1\).

Let us denote by

(3.4.6)
\[ \omega_n(x) = x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n \]

the polynomial whose roots are the nodes \(x_1, x_2, \ldots, x_n\) of formula (3.4.2), and let us observe that determining \(x_1, x_2, \ldots, x_n\) is the same as determining the coefficients \(\lambda_1, \lambda_2, \ldots, \lambda_n\) of the polynomial \(\omega_n(x)\).

The polynomials

(3.4.7)
\[ Q(x) = (x - a)^p (b - x)^q \omega_n(x)\, x^h, \]

where \(h = 0, 1, \ldots, n-1\), have degree \(n + p + q + h \leq 2n + p + q - 1\).

Replacing in formula (3.4.2) the function \(f\) by the polynomial \(Q\), we deduce the equations

(3.4.8)
\[ \int_a^b \pi(x) (x - a)^p (b - x)^q \omega_n(x) x^h\, dx = 0 \quad\text{for } h = 0, 1, \ldots, n-1 \]

because the polynomial \(\omega_n\) vanishes for \(x_1, x_2, \ldots, x_n\).

As is well known, the system formed by equations (3.4.8), where \(h = 0, 1, \ldots, n-1\), determines the polynomial \(\omega_n\), and equations (3.4.8) show that we have the fundamental orthogonality property

(3.4.9)
\[ \int_a^b \pi(x) (x - a)^p (b - x)^q \omega_n(x)\, \omega_m(x)\, dx = 0 \]

for \(n \neq m\), which means that the polynomials \(\omega_n\) form a sequence of orthogonal polynomials with respect to the weight \(\pi(x) (x-a)^p (b-x)^q\) and the interval \([a, b]\), where \(m = 0, 1, \ldots\) and \(\omega_0(x) = 1\).

It is known that the polynomial \(\omega_n\) is determined by the coefficients (3.4.6), which are given by equations (3.4.8). All its roots are real, distinct and lie between \(a\) and \(b\).

Thus the first part of our problem is solved; the nodes \(x_1, x_2, \ldots, x_n\) of formula (3.4.2) are the roots of the polynomial \(\omega_n\).

Once the nodes \(x_1, x_2, \ldots, x_n\) have been determined, the coefficients \(C_1, C_2, \ldots, C_n\) follow at once. For this, the function \(f\) in identity (3.4.2) is replaced by the polynomials

(3.4.10)
\[ Q(x) = (x - a)^p (b - x)^q x^h, \]

where \(h = 0, 1, \ldots, n-1\).

We obtain the system of equations

(3.4.11)
\[ \begin{aligned} (x_1 - a)^p (b - x_1)^q C_1 + \ldots + (x_n - a)^p (b - x_n)^q C_n &= \int_a^b \pi(x) (x - a)^p (b - x)^q\, dx \\ (x_1 - a)^p (b - x_1)^q x_1 C_1 + \ldots + (x_n - a)^p (b - x_n)^q x_n C_n &= \int_a^b \pi(x) (x - a)^p (b - x)^q x\, dx \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots &\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ (x_1 - a)^p (b - x_1)^q x_1^{n-1} C_1 + \ldots + (x_n - a)^p (b - x_n)^q x_n^{n-1} C_n &= \\ &= \int_a^b \pi(x) (x - a)^p (b - x)^q x^{n-1}\, dx \end{aligned} \]

which determines \(C_1, C_2, \ldots, C_n\).

Indeed, the determinant of system (3.4.11) is

\[ [(x_1 - a)(x_2 - a) \ldots (x_n - a)]^p [(b - x_1)(b - x_2) \ldots (b - x_n)]^q V(x_1, x_2, \ldots, x_n). \]

It is different from zero, because the roots \(x_1, x_2, \ldots, x_n\) of the polynomial \(\omega_n\) are real, distinct and lie between \(a\) and \(b\).

Thus the coefficients \(C_1, C_2, \ldots, C_n\) of formula (3.4.2) are determined by the system of equations (3.4.11).

We may add that the coefficients \(C_1, C_2, \ldots, C_n\) are positive.

Indeed, replacing in identity (3.4.2) the function \(f\) by the polynomial \(Q(x) = (x - a)^p (b - x)^q \left(\frac{\omega_n(x)}{x - x_i}\right)^2\) of degree \(2n + p + q - 2\), we have the equation

\[ \int_a^b \pi(x) (x - a)^p (b - x)^q \left(\frac{\omega_n(x)}{x - x_i}\right)^2 dx = C_i (x_i - a)^p (b - x_i)^q [\omega_n'(x_i)]^2, \]

which determines \(C_i\) and shows that \(C_i \gt 0\), \(i = 1, 2, \ldots, n\).

The coefficients \(C_1, C_2, \ldots, C_n\) having been determined, the coefficients \(A_0, A_1, \ldots, A_{p-1}, B_0, B_1, \ldots, B_{q-1}\) can be determined by writing that identity (3.4.2) is satisfied when the function \(f\) is replaced by the polynomial

(3.4.12)
\[ Q(x) = x^h, \]

where \(h = 0, 1, \ldots, p + q - 1\). We have the system:

(3.4.13)
\[ \begin{aligned} & A_0 + B_0 = \int_a^b \pi(x)\, dx - (C_1 + C_2 + \ldots + C_n) \\ & A_0 a + A_1 + B_0 b + B_1 = \int_a^b \pi(x)\, x\, dx - (C_1 x_1 + \ldots + C_n x_n) \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & A_0 a^{p+q-1} + A_1 (a^{p+q-1})' + \ldots + A_{p-1} (a^{p+q-1})^{(p-1)} + B_0 b^{p+q-1} + \\ & + B_1 (b^{p+q-1})' + \ldots + B_{q-1} (b^{p+q-1})^{(q-1)} = \int_a^b \pi(x)\, x^{p+q-1}\, dx - (C_1 x_1^{p+q-1} + \ldots + C_n x_n^{p+q-1}), \end{aligned} \]

which determines the coefficients \(A_0, A_1, \ldots, A_{p-1}, B_0, B_1, \ldots B_{q-1}\), because the determinant of the system is the generalized Vandermonde determinant

\[ V(\underbrace{a, \ldots, a}_{p}, \underbrace{b, \ldots, b}_{q}) \neq 0. \]

Thus the problem posed for the quadrature formula (3.4.1) is completely solved.

Let us now determine the remainder \(R[f]\) of the quadrature formula (3.4.1) when the nodes and the coefficients have been determined by the problem posed above and when \(f \in C^{2n+p+q}[a, b]\). This problem was treated by us with the method of the function \(\varphi\), for an arbitrary weight \(\pi(x)\), integrable on the interval \([a, b]\) and positive on the interval \((a, b)\), in our paper [6].

But when \(\pi(x) = 1\), the determination of the remainder \(R[f]\) can be linked to the integral representation of a divided difference, as we shall see below.

3.4.2. Let us consider the divided difference of a function \(g\) on the nodes \(a, b\), of multiplicities \(p + 1\), \(q + 1\), and on the distinct double nodes \(x_1, x_2, \ldots, x_n\)

(3.4.14)
\[ [\underbrace{a, \ldots, a}_{p+1}, x_1, x_1, \ldots, x_n, x_n, \underbrace{b, \ldots, b}_{q+1}; g]. \]

Proceeding as in § 3.2, we can write

(3.4.15)
\[ \begin{aligned} & [\underbrace{a, \ldots, a}_{p+1}, x_1, x_1, \ldots, x_n, x_n, \underbrace{b, \ldots, b}_{q+1}; g] = M_0 g(a) + M_1 g'(a) + \ldots + M_p g^{(p)}(a) + \\ &\quad + P_1 g(x_1) + P_2 g(x_2) + \ldots + P_n g(x_n) + \\ &\quad + P_1' g'(x_1) + P_2' g'(x_2) + \ldots + P_n' g'(x_n) + \\ &\quad + Q_0 g(b) + Q_1 g'(b) + \ldots + Q_q g^{(q)}(b). \end{aligned} \]

Concerning this formula we have:

Theorem 3.4.1. If in formula (3.4.15) the nodes \(x_1, x_2, \ldots, x_n\) are the roots of the polynomial \(\omega_n\) (3.4.7), determined by equations (3.4.8), then on the right-hand side of this formula we have

(3.4.16)
\[ P_1 = 0,\ P_2 = 0,\ \ldots,\ P_n = 0 \]

It suffices to give the proof for one of these coefficients, for example for \(P_1\).

Setting

(3.4.17)
\[ N = 2n + p + q \]

we have

(3.4.18)
\[ P_1 = (-1)^{q+1} V^{-1} \begin{vmatrix} 1 & a & a^2 & \ldots & a^N \\ 0 & 1 & (a^2)' & \ldots & (a^N)' \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & 0 & \ldots & (a^N)^{(p)} \\ 0 & 1 & (x_1^2)' & \ldots & (x_1^N)' \\ 1 & x_2 & x_2^2 & \ldots & x_2^N \\ 0 & 1 & (x_2^2)' & \ldots & (x_2^N)' \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 1 & x_n & x_n^2 & \ldots & x_n^N \\ 0 & 1 & (x_n^2)' & \ldots & (x_n^N)' \\ 1 & b & b^2 & \ldots & b^N \\ 0 & 1 & (b^2)' & \ldots & (b^N)' \\ \ldots & \ldots & \ldots & \ldots & \ldots \\ 0 & 0 & 0 & \ldots & (b^N)^{(q)} \end{vmatrix} \]

where \(V\) is the generalized Vandermonde determinant

(3.4.19)
\[ V = V(\underbrace{a, \ldots, a}_{p+1}, x_1, x_1, \ldots, x_n, x_n, \underbrace{b, \ldots, b}_{q+1}) \]

We can also write

\[ P_1 = L_1 \begin{vmatrix} -1 & 0 & 0 & \ldots & 0 & 0 & \ldots & 0 & 0 & \ldots & 0 & 1 & \ldots & 1 & 1 \\ -a & 1 & 0 & \ldots & 0 & 1 & \ldots & 1 & 1 & \ldots & 0 & x_2 & \ldots & x_n & b \\ -a^2 & (a^2)' & (a^2)'' & \ldots & 0 & (x_1^2)' & \ldots & (x_n^2)' & (b^2)' & \ldots & 0 & x_2^2 & \ldots & x_n^2 & b^2 \\ \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots \\ -a^N & (a^N)' & (a^N)'' & \ldots & (a^N)^{(p)} & (x_1^N)' & \ldots & (x_n^N)' & (b^N)' & \ldots & (b^N)^{(q)} & x_2^N & \ldots & x_n^N & b^N \end{vmatrix} \]

where \(L_1\) differs from \(V^{-1}\) by a factor of 1 or \(-1\).

Adding the elements of the last column to those of the first column, and then dividing the elements of the second row, of the third row, \(\ldots\), of the last row by \(1, 2, \ldots, N\), respectively, we can also write \(P_1\) in the form

\[ P_1 = N!\, L_1 \begin{vmatrix} 0 & 0 & 0 & \ldots & 0 & 0 & \ldots & 0 & 0 & \ldots & 0 & 1 & \ldots & 1 & 1 \\ \int_a^b dx & 1 & 0 & \ldots & 0 & 1 & \ldots & 1 & 1 & \ldots & 0 & x_2 & \ldots & x_n & b \\ \int_a^b x\, dx & a & 1 & \ldots & 0 & x_1 & \ldots & x_n & b & \ldots & 0 & \frac{x_2^2}{2} & \ldots & \frac{x_n^2}{2} & \frac{b^2}{2} \\ \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots \\ \int_a^b x^{N-1}\, dx & a^{N-1} & (a^{N-1})' & \ldots & (a^{N-1})^{(p-1)} & x_1^{N-1} & \ldots & x_n^{N-1} & b^{N-1} & \ldots & (b^{N-1})^{(q-1)} & \frac{x_2^N}{N} & \ldots & \frac{x_n^N}{N} & \frac{b^N}{N} \end{vmatrix} \]

In this form we see that the coefficient \(P_1\) is zero, because, \(x_1, x_2, \ldots, x_n\) being the roots of the polynomial \(\omega_n\), among the elements of the first \(n + p + q + 1\) columns there is one and the same linear combination, which results from formula (3.4.2) for \(f(x) = x^k\), where \(k = 0, 1, \ldots, N-1\).

Theorem 3.4.1 is thus proved.

3.4.3. This being so, let us replace in formula (3.4.15) the nodes \(x_1, x_2, \ldots, x_n\) by the roots of the polynomial \(\omega_n\), (3.4.7), determined by equations (3.4.8). Then, by Theorem 3.4.1, we have \(P_1 = 0, \ldots, P_n = 0\) and formula (3.4.15) becomes

(3.4.20)
\[ \begin{aligned} & [\underbrace{a, \ldots, a}_{p+1}, x_1, x_1, \ldots, x_n, x_n, \underbrace{b, \ldots, b}_{q+1}; g] = M_0 g(a) + M_1 g'(a) + \ldots + M_p g^{(p)}(a) + \\ &\quad + P_1' g'(x_1) + P_2' g'(x_2) + \ldots + P_n' g'(x_n) + \\ &\quad + Q_0 g(b) + Q_1 g'(b) + \ldots + Q_q g^{(q)}(b). \end{aligned} \]

If in this identity \(g(x)\) is replaced by 1, we deduce that

(3.4.21)
\[ M_0 + Q_0 = 0. \]

On the other hand, by Theorem 2.3.1 we have \(Q_0 \neq 0\), so that formula (3.4.20) can be written

\[ \begin{aligned} & [\underbrace{a, \ldots, a}_{p+1}, x_1, x_1, \ldots, x_n, x_n, \underbrace{b, \ldots, b}_{q+1}; g] = Q_0 \int_a^b g'(x)\, dx + M_1 g'(a) + \ldots + M_p g^{(p)}(a) + \\ & \qquad + P'_1 g'(x_1) + \ldots + P'_n g'(x_n) + \\ & \qquad + Q_1 g'(b) + \ldots + Q_q g^{(q)}(b). \end{aligned} \]

Let us replace in this identity the function \(g\) by

(3.4.23)
\[ g(x) = \int_a^x f(s)\, ds \]

and divide by \(Q_0\). We shall have the formula

(3.4.1)
\[ \begin{aligned} \int_a^b f(x)\, dx &= A_0 f(a) + A_1 f'(a) + \ldots + A_{p-1} f^{(p-1)}(a) + \\ &\quad + C_1 f(x_1) + C_2 f(x_2) + \ldots + C_n f(x_n) + \\ &\quad + B_0 f(b) + B_1 f'(b) + \ldots + B_{q-1} f^{(q-1)}(b) + R[f], \end{aligned} \]

which is precisely the formula (3.4.1) that we have in view and that we have regarded as an extension of the Gauss quadrature formula.

In this formula the nodes \(x_1, x_2, \ldots, x_n\) are the roots, real, distinct and lying between \(a\) and \(b\), of the polynomial \(\omega_n\), (3.4.6), given by equations (3.4.8), and the coefficients are related to the coefficients of the divided difference (3.4.20) by the formulas

(3.4.24)
\[ \begin{aligned} & A_0 = -\frac{M_1}{Q_0},\quad A_1 = -\frac{M_2}{Q_0},\quad \ldots,\quad A_{p-1} = -\frac{M_p}{Q_0} \\ & B_0 = -\frac{Q_1}{Q_0},\quad B_1 = -\frac{Q_2}{Q_0},\quad \ldots,\quad B_{q-1} = -\frac{Q_q}{Q_0} \\ & C_1 = -\frac{P'_1}{Q_0},\quad C_2 = -\frac{P'_2}{Q_0},\quad \ldots,\quad C_n = -\frac{P'_n}{Q_0}. \end{aligned} \]

The remainder \(R[f]\) is given by:

(3.4.25)
\[ R[f] = \frac{1}{Q_0} \left[ \underbrace{a, \ldots, a}_{p+1}, x_1, x_1, \ldots, x_n, x_n, \underbrace{b, \ldots, b}_{q+1}; \int_a^x f(s)\, ds \right]. \]

If we use the integral representation of the right-hand side of formula (3.4.25), we obtain the integral representation of the remainder \(R[f]\), when \(f \in C^N[a, b]\)

(3.4.26)
\[ R[f] = \frac{1}{Q_0} \int_a^b \varphi f^{(N)}\, ds, \]

where the right-hand side contains the function \(\varphi\) from the integral representation of the divided difference (3.4.14) corresponding to the roots of the polynomial \(\omega_n\) determined by equations (3.4.8).

We thus have:

Theorem 3.4.2. The Gauss-type quadrature formula (3.4.1) is derived from the integral representation of the divided difference (3.4.14)

(3.4.27)
\[ [\underbrace{a, \ldots, a}_{p+1}, x_1, x_1, \ldots, x_n, x_n, \underbrace{b, \ldots, b}_{q+1}; g] = \int_a^b \varphi g^{(N+1)}\, dx, \]

where \(N = 2n + p + q\), by replacing the nodes \(x_1, x_2, \ldots, x_n\) by the roots \(x_1, x_2, \ldots, x_n\) of the polynomial \(\omega_n\) given by equations (3.4.7) and (3.4.8) and setting \(g' = f\).

The coefficients of formula (3.4.1) are given by formulas (3.4.24) and the remainder \(R[f]\) is given by formula (3.4.25).

3.4.4. Replacing in formula (3.4.1) the function \(f\) by

(3.4.28)
\[ (x - a)^p (b - x)^q \omega_n^2(x), \]

where \(\omega_n\) is the polynomial determined by equations (3.4.7) and (3.4.8), which vanishes at \(x_1, x_2, \ldots, x_n\), and taking formula (3.4.26) into account, we obtain

\[ \int_a^b (x - a)^p (b - x)^q \omega_n^2(x)\, dx = (-1)^q \frac{N!}{Q_0} \int_a^b \varphi\, ds. \]

But for the integral representation (3.4.27) we have \(\int_a^b \varphi\, ds = \frac{1}{(N+1)!}\) and therefore:

\[ \int_a^b (x - a)^p (b - x)^q \omega_n^2(x)\, dx = (-1)^q \frac{1}{Q_0} \frac{1}{N+1} \]

whence it follows that

(3.4.29)
\[ \frac{1}{Q_0} = (-1)^q (2n + p + q + 1) \int_a^b (x - a)^p (b - x)^q \omega_n^2(x)\, dx \]

which is an interesting interpretation of the coefficient \(\frac{1}{Q_0}\) on the right-hand side of formula (3.4.26).

§ 3.5. Extension of P. Turán's quadrature formula

3.5.1. In § 3.4 we considered an extension of the Gauss quadrature formula. Let us consider the quadrature formula of the form

(3.5.1)
\[ \begin{aligned} \int_a^b \pi(x) f(x)\, dx &= A_0 f(a) + A_1 f'(a) + \ldots + A_{p-1} f^{(p-1)}(a) + \\ &\quad + \sum_{l=0}^{2(s-1)} (C_1^{(l)} f^{(l)}(x_1) + \ldots + C_n^{(l)} f^{(l)}(x_n)) + \\ &\quad + B_0 f(b) + B_1 f'(b) + \ldots + B_{q-1} f^{(q-1)}(b) + R[f] \end{aligned} \]

as an extension of P. Turán's quadrature formula. In this formula \(\pi\) is a function integrable on the interval \([a, b]\) and positive on the interval \((a, b)\).

On the right-hand side there appear the derivatives \(f^{(l)}(x_j)\) of the function \(f\) for \(l = 0, 1, \ldots, 2(s-1)\) and \(j = 1, 2, \ldots, n\). The coefficients of formula (3.5.1) will be specified by the following fundamental problem, which we designate as:

P. Turán's problem. Determine the nodes \(x_1, x_2, \ldots, x_n\) and the coefficients \(C_1^{(l)}, \ldots, C_n^{(l)}\) for \(l = 0, 1, \ldots, 2(s-1)\), as well as the coefficients \(A_0, A_1, \ldots, A_{p-1}, B_0, B_1, \ldots B_{q-1}\), so that in formula (3.5.1) we have \(R[x^k] = 0\) for \(k = 0, 1, \ldots, 2ns + p + q - 1\).

We shall then have the identity

(3.5.2)
\[ \begin{aligned} \int_a^b \pi(x) f(x)\, dx &= A_0 f(a) + A_1 f'(a) + \ldots + A_{p-1} f^{(p-1)}(a) + \\ &\quad + C_1^{(0)} f(x_1) + C_2^{(0)} f(x_2) + \ldots + C_n^{(0)} f(x_n) + \\ &\quad + C_1^{(1)} f'(x_1) + C_2^{(1)} f'(x_2) + \ldots + C_n^{(1)} f'(x_n) + \\ &\quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ &\quad + C_1^{2(s-1)} f^{2(s-1)}(x_1) + C_2^{2(s-1)} f^{2(s-1)}(x_2) + \ldots + C_n^{2(s-1)} f^{2(s-1)}(x_n) + \\ &\quad + B_0 f(b) + B_1 f'(b) + \ldots + B_{q-1} f^{(q-1)}(b), \end{aligned} \]

for \(f(x) = x^k\), where \(k = 0, 1, \ldots, 2ns + p + q - 1\).

To determine the nodes and the coefficients of formula (3.5.2) we must write the identities that result when the function \(f\) is replaced by

(3.5.3)
\[ \begin{array}{lll} 1, & x, \ldots, & x^{p+q-1} \\ x^{p+q}, & x^{p+q+1}, \ldots, & x^{p+q+n-1} \\ \ldots\ldots\ldots & \ldots\ldots\ldots & \ldots\ldots\ldots \\ x^{p+q+(2s-2)n}, & x^{p+q+(2s-2)n+1}, \ldots, & x^{p+q+(2s-1)n-1} \end{array} \]

and

(3.5.4)
\[ x^{p+q+(2s-1)n},\ x^{p+q+(2s-1)n+1},\ \ldots,\ x^{p+q+2sn-1}. \]

We can also write that formula (3.5.2) is verified when the function \(f\) is replaced by an arbitrary polynomial \(Q\) of degree at most \(p + q + 2sn - 1\).

Let us denote by

(3.5.5)
\[ \omega_n(x) = x^n + \lambda_1 x^{n-1} + \ldots + \lambda_n \]

the polynomial whose roots are the nodes \(x_1, x_2, \ldots, x_n\) of identity (3.5.2). Determining the nodes \(x_1, x_2, \ldots, x_n\) is the same as determining the coefficients \(\lambda_1, \lambda_2, \ldots, \lambda_n\) of the polynomial \(\omega_n\).

The polynomials

(3.5.6)
\[ Q(x) = (x - a)^p (b - x)^q \omega_n^{2s-1}(x)\, x^h, \]

where \(h = 0, 1, \ldots, n - 1\), are of degree \(p + q + (2s - 1)n + h \leq p + q + 2sn - 1\). The polynomial \(Q\) can also be written in the form

(3.5.7)
\[ Q(x) = (x - a)^p (b - x)^q (x - x_1)^{2s-1} \ldots (x - x_n)^{2s-1} x^h \]

and we see that it has the roots \(a, b, x_1, \ldots, x_n\) of multiplicities \(p, q, 2s-1, \ldots, 2s-1\).

It follows that if in formula (3.5.2) the function \(f\) is replaced by the polynomial \(Q\), we must have

(3.5.8)
\[ \int_a^b \pi(x) (x - a)^p (b - x)^q \omega_n^{2s-1}(x)\, x^h\, dx = 0 \]

for \(h = 0, 1, \ldots, n-1\).

Equations (3.5.8) determine the polynomial \(\omega_n\) uniquely. By a theorem of D. Jackson [22], \(\omega_n\) is the minimizing polynomial of the integral

(3.5.9)
\[ \int_a^b \pi(x) (x - a)^p (b - x)^q \omega_n^{2s}(x)\, dx \]

and it has been proved (Theorem 3.3.3) that the polynomial \(\omega_n\) has all its roots real, distinct and lying between \(a\) and \(b\).

Hence the nodes \(x_1, x_2, \ldots, x_n\) of formula (3.5.2) are the roots of the minimizing polynomial of the integral (3.5.9).

It remains to determine the coefficients of formula (3.5.2).

For this we must write that identity (3.5.2) is satisfied when the function \(f\) is replaced by the polynomials (3.5.3).

We shall have the linear equations

(3.5.10)
\[ \begin{aligned} & A_0 + \sum_{j=1}^{n} C_j^{(0)} + B_0 = \int_a^b \pi(x)\, dx \\ & A_0 a + A_1 + \sum_{j=1}^{n} (C_j^{(0)} x_j + C_j^{(1)}) + B_0 b + B_1 = \int_a^b \pi(x)\, x\, dx \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & A_0 a^{(2s-1)n+p+q-1} + A_1 (a^{(2s-1)n+p+q-1})' + \ldots + A_{p-1} (a^{(2s-1)n+p+q-1})^{(p-1)} + \\ & \qquad + \sum_{j=1}^{n} [C_j^{(0)} x_j^{(2s-1)n+p+q-1} + C_j^{(1)} (x_j^{(2s-1)n+p+q-1})' + \ldots + \\ & \qquad + C_j^{2(s-1)} (x_j^{(2s-1)n+p+q-1})^{2(s-1)}] + \\ & + B_0 b^{(2s-1)n+p+q-1} + B_1 (b^{(2s-1)n+p+q-1})' + \ldots + B_{q-1} (b^{(2s-1)n+p+q-1})^{(q-1)} = \\ & \qquad = \int_a^b \pi(x) x^{(2s-1)n+p+q-1}\, dx \end{aligned} \]

whose number is \((2s-1)n+p+q\), in \(p+(2s-1)n+q\) unknowns \(A_0, A_1, \ldots, A_{p-1}, C_j^{(0)}, C_j^{(1)}, \ldots, C_j^{2(s-1)}, j = 1, 2, \ldots, n\) and \(B_0, B_1, \ldots, B_{q-1}\).

This system determines all the coefficients because its determinant is the generalized Vandermonde determinant

\[ V(\underbrace{a, \ldots, a}_{p}, \underbrace{x_1, \ldots, x_1}_{2s-1}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s-1}, \underbrace{b, \ldots, b}_{q}) \neq 0. \]

Thus P. Turán's problem for the quadrature formula (3.5.1) is completely solved.

Once the nodes and the coefficients of formula (3.5.1) have been determined, it remains to determine the remainder \(R[f]\) of the formula, assuming that \(f \in C^{2ns+p+q}[a, b]\). This problem was treated by P. Pavel [28] with the method of the function \(\varphi\), for a weight \(\pi\) integrable on the interval \([a, b]\) and positive on the interval \((a, b)\).

But if \(\pi(x) = 1\), the determination of the remainder \(R[f]\) can be linked to the integral representation of a divided difference, as we shall see below.

3.5.2. Let us consider the divided difference of a function \(g\) on the nodes \(a, b\) of multiplicities \(p + 1, q + 1\) and on the distinct nodes \(x_1, x_2, \ldots, x_n\), each of multiplicity \(2s\)

(3.5.11)
\[ [\underbrace{a, \ldots, a}_{p+1}, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, \underbrace{b, \ldots, b}_{q+1}; g] \]

Proceeding as in § 3.2, we can write

(3.5.12)
\[ \begin{aligned} & [\underbrace{a, \ldots, a}_{p+1}, \underbrace{x_1, \ldots x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, \underbrace{b, \ldots, b}_{q+1}; g] = M_0 g(a) + M_1 g'(a) + \ldots + M_p g^{(p)}(a) + \\ & + P_1^{(0)} g(x_1) + P_2^{(0)} g(x_2) + \ldots + P_n^{(0)} g(x_n) + \\ & + P_1^{(1)} g'(x_1) + P_2^{(1)} g'(x_2) + \ldots + P_n^{(1)} g'(x_n) + \\ & \quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + P_1^{(2s-1)} g^{(2s-1)}(x_1) + P_2^{(2s-1)} g^{(2s-1)}(x_2) + \ldots + P_n^{(2s-1)} g^{(2s-1)}(x_n) + \\ & + Q_0 g(b) + Q_1 g'(b) + \ldots + Q_q g^{(q)}(b). \end{aligned} \]

Concerning this formula we have:

Theorem 3.5.1. If in formula (3.5.12) the nodes \(x_1, x_2, \ldots, x_n\) are the roots of the minimizing polynomial \(\omega_n\) of the integral (3.5.9), then on the right-hand side of this formula we have

(3.5.13)
\[ P_1^{(0)} = 0,\ P_2^{(0)} = 0,\ \ldots,\ P_n^{(0)} = 0. \]

It suffices to prove this theorem for one of the coefficients, for example for \(P_1^{(0)}\).

Setting

(3.5.14)
\[ N = 2ns + p + q, \]

we have

(3.5.15)
\[ P_1^{(0)} = (-1)^{q+1} V^{-1} \begin{vmatrix} 1 & a & a^2, & \ldots, a^N \\ 0 & 1 & (a^2)' & \ldots, (a^N)' \\ \ldots & \ldots & \ldots & \ldots\ldots \\ 0 & 0 & 0 & \ldots (a^N)^{(p)} \\ 0 & 1 & (x_1^2)' & \ldots (x_1^N)' \\ \ldots & \ldots & \ldots & \ldots\ldots \\ 0 & 0 & 0 & \ldots (x_1^N)^{(2s-1)} \\ \ldots & \ldots & \ldots & \ldots\ldots \\ 1 & x_n & x_n^2, & \ldots, x_n^N \\ 0 & 1 & (x_n^2)' & \ldots (x_n^N)' \\ \ldots & \ldots & \ldots & \ldots\ldots \\ 0 & 0 & 0 & \ldots (x_n^N)^{(2s-1)} \\ 1 & b & b^2 & \ldots b^N \\ 0 & 1 & (b^2)' & \ldots (b^N)' \\ \ldots & \ldots & \ldots & \ldots\ldots \\ 0 & 0 & 0 & \ldots (b^N)^{(q)} \end{vmatrix} \]

where \(V\) is the generalized Vandermonde determinant

(3.5.16)
\[ V = V(\underbrace{a, \ldots, a}_{p+1}, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, \underbrace{b, \ldots, b}_{q+1}). \]

We can also write

\[ P_1^{(0)} = L_1 \begin{vmatrix} -1 & 0 & \ldots 0 & 0 & \ldots 0 & \ldots 0 & \ldots 0 & 0 & \ldots 0 & 1 \\ -a & 1 & \ldots 0 & 1 & \ldots 0 & \ldots 1 & \ldots 0 & 1 & \ldots 0 & b \\ -a^2 & (a^2)' & \ldots 0 & (x_1^2)' & \ldots 0 & \ldots (x_n^2)' & \ldots 0 & (b^2)' & \ldots 0 & b^2 \\ \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots \\ -a^N & (a^N)' & \ldots (a^N)^{(p)} & (x_1^N)' & \ldots (x_1^N)^{(2s-1)} & \ldots (x_n^N)' & \ldots (x_n^N)^{(2s-1)} & (b^N)' & \ldots (b^N)^{(q)} & b^N \end{vmatrix} \]

where \(L_1\) differs from \(V^{-1}\) by a factor of 1 or \(-1\).

Adding the elements of the last column to the elements of the first column and then dividing the elements of the 2nd, the 3rd, \(\ldots\), the last row by \(1, 2, \ldots, N\), respectively, we can write \(P_1^{(0)}\) in the form

\[ P_1^{(0)} = L_1 \left| \begin{array}{lllllllllllll} 0 & 0 & \ldots 0 & 0 & \ldots 0 & \ldots 0 & \ldots 0 & 0 & \ldots 0 & 1 & 1 & \ldots & 1 \\ \int_a^b dx & 1 & \ldots 0 & 1 & \ldots 0 & \ldots 1 & \ldots 0 & 1 & \ldots 0 & b & x_2 & \ldots & x_n \\ \int_a^b x\, dx & a & \ldots 0 & x_1 & \ldots 0 & \ldots x_n & \ldots 0 & b & \ldots 0 & \frac{b^2}{2} & \frac{x_2^2}{2} & \ldots & \frac{x_n^2}{2} \\ \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots \\ \int_a^b x^{N-1}\, dx & a^{N-1} & \ldots (a^{N-1})^{(p-1)} & x_1^{N-1} & \ldots (x_1^{N-1})^{(2s-2)} & \ldots x_n^{N-1} & \ldots (x_n^{N-1})^{(2s-2)} & b^{N-1} & \ldots (b^{N-1})^{(q-1)} & \frac{b^N}{N} & \frac{x_2^N}{N} & \ldots & \frac{x_n^N}{N} \end{array} \right| \]

In this form we see that the coefficient \(P_1^{(0)}\) is zero, because, \(x_1, x_2, \ldots, x_n\) being the roots of the polynomial \(\omega_n\), among the elements of the first \((2s-1)n+p+q+1\) columns there is one and the same linear combination, which results from formula (3.5.2).

Theorem 3.5.1 is thus proved.

3.5.3. This being so, let us replace in formula (3.5.12) the nodes \(x_1, x_2, \ldots, x_n\) by the roots of the polynomial \(\omega_n\) determined by equations (3.5.5), (3.5.8). Then, by Theorem 3.5.1, we have \(P_1^{(0)} = 0, \ldots, P_n^{(0)} = 0\) and formula (3.5.12) becomes

(3.5.17)
\[ \begin{aligned} & [\underbrace{a, \ldots, a}_{p+1}, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, \underbrace{b, \ldots, b}_{q+1}; g] = M_0 g(a) + M_1 g'(a) + \ldots + M_p g^{(p)}(a) + \\ & + P_1^{(1)} g'(x_1) + \ldots + P_n^{(1)} g'(x_n) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + P_1^{(2s-1)} g^{(2s-1)}(x_1) + \ldots + P_n^{(2s-1)} g^{(2s-1)}(x_n) + \\ & + Q_0 g(b) + Q_1 g'(b) + \ldots + Q_q g^{(q)}(b). \end{aligned} \]

If in this identity \(g(x)\) is replaced by 1, we have

(3.5.18)
\[ M_0 + Q_0 = 0 \]

and, by Theorem 2.3.1, we have \(Q_0 \neq 0\), so that formula (3.5.17) becomes

(3.5.19)
\[ \begin{aligned} & [\underbrace{a, \ldots, a}_{p+1}, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, \underbrace{b, \ldots, b}_{q+1}; g] = Q_0 \int_a^b g'(x)\, dx + M_1 g'(a) + \ldots + M_p g^{(p)}(a) + \\ & \qquad + P_1^{(1)} g'(x_1) + \ldots + P_n^{(1)} g'(x_n) + \\ & \qquad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & \qquad + P_1^{(2s-1)} g^{(2s-1)}(x_1) + \ldots + P_n^{(2s-1)} g^{(2s-1)}(x_n) + \\ & \qquad + Q_1 g'(b) + \ldots + Q_q g^{(q)}(b). \end{aligned} \]

Let us replace in this identity the function \(g\) by

(3.5.20)
\[ g(x) = \int_a^x f(t)\, dt \]

and divide by \(Q_0\). We shall have the formula

(3.5.21)
\[ \begin{aligned} \int_a^b f(x)\, dx &= A_0 f(a) + A_1 f'(a) + \ldots + A_{p-1} f^{(p-1)}(a) + \\ &\quad + C_1^{(0)} f(x_1) + C_2^{(0)} f(x_2) + \ldots + C_n^{(0)} f(x_n) + \\ &\quad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &\quad + C_1^{2(s-1)} f^{2(s-1)}(x_1) + C_2^{2(s-1)} f^{2(s-1)}(x_2) + \ldots + C_n^{2(s-1)} f^{2(s-1)}(x_n) + \\ &\quad + B_0 f(b) + B_1 f'(b) + \ldots + B_{q-1} f^{(q-1)}(b) + R[f] \end{aligned} \]

which is precisely the formula (3.5.1) that we have in view and that we regard as an extension of P. Turán's quadrature formula.

In formula (3.5.21) the nodes \(x_1, x_2, \ldots, x_n\) are the roots, real, distinct and lying between \(a\) and \(b\), of the polynomial \(\omega_n\) determined by equations (3.5.5), (3.5.8), which is the minimizing polynomial of the integral (3.5.9) corresponding to \(\pi(x) = 1\), and the coefficients are related to the coefficients of the divided difference (3.5.17) corresponding to the roots of the polynomial \(\omega_n\) by the formulas

(3.5.22)
\[ \begin{aligned} & A_0 = -\frac{M_1}{Q_0},\quad A_1 = -\frac{M_2}{Q_0},\quad \ldots,\quad A_{p-1} = -\frac{M_p}{Q_0} \\ & B_0 = -\frac{Q_1}{Q_0},\quad B_1 = -\frac{Q_2}{Q_0},\quad \ldots,\quad B_{q-1} = -\frac{Q_q}{Q_0} \\ & C_1^{(0)} = -\frac{P_1^{(1)}}{Q_0},\quad C_2^{(0)} = -\frac{P_2^{(1)}}{Q_0},\quad \ldots,\quad C_n^{(0)} = -\frac{P_n^{(1)}}{Q_0} \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & C_1^{2(s-1)} = -\frac{P_1^{(2s-1)}}{Q_0},\quad C_2^{2(s-1)} = -\frac{P_2^{(2s-1)}}{Q_0},\quad \ldots,\quad C_n^{2(s-1)} = -\frac{P_n^{(2s-1)}}{Q_0}. \end{aligned} \]

The remainder \(R[f]\) is given by the expression

(3.5.23)
\[ R[f] = \frac{1}{Q_0} [\underbrace{a, \ldots, a}_{p+1}, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, \underbrace{b, \ldots, b}_{q+1}; \int_a^x f(t)\, dt] \]

If we use the integral representation of the right-hand side of formula (3.5.23), we obtain the integral representation of the remainder \(R[f]\) when \(f \in C^N[a, b]\)

(3.5.24)
\[ R[f] = \frac{1}{Q_0} \int_a^b \varphi f^{(N)}\, dt \]

where the right-hand side contains the function \(\varphi\) from the integral representation of the divided difference (3.5.11) corresponding to the roots of the polynomial \(\omega_n\) determined by equations (3.5.5), (3.5.8).

We thus have

Theorem 3.5.2. P. Turán's quadrature formula is derived from the integral representation of the divided difference (3.5.11):

(3.5.25)
\[ [\underbrace{a, \ldots, a}_{p+1}, \underbrace{x_1, \ldots, x_1}_{2s}, \ldots, \underbrace{x_n, \ldots, x_n}_{2s}, \underbrace{b, \ldots, b}_{q+1}; g] = \int_a^b \varphi g^{(N+1)}\, dx, \]

where \(N = 2ns+p+q\), by replacing the nodes \(x_1, x_2, \ldots, x_n\) by the roots of the polynomial \(\omega_n\) given by equations (3.5.5), (3.5.8) and setting \(g' = f\).

The coefficients of formula (3.5.1) are given by formulas (3.5.22) and the remainder \(R[f]\) is given by formula (3.5.23) or (3.5.24).

3.5.4. Replacing in formula (3.5.1), where \(\pi(x) = 1\), the function \(f\) by

(3.5.26)
\[ (x-a)^p (b-x)^q \omega_n^{2s}(x), \]

where \(\omega_n\) is the polynomial determined by equations (3.5.5) and (3.5.8), and taking formula (3.5.24) into account, we have

\[ \int_a^b (x-a)^p (b-x)^q \omega_n^{2s}(x)\, dx = (-1)^q \frac{N!}{Q_0} \int_a^b \varphi(t)\, dt. \]

But for the integral representation (3.5.25) we have \(\int_a^b \varphi\, dt = \frac{1}{(N+1)!}\) and therefore

\[ \int_a^b (x-a)^p (b-x)^q \omega_n^{2s}(x)\, dx = (-1)^q \frac{1}{Q_0} \cdot \frac{1}{N+1} \]

whence it follows that

(3.5.27)
\[ \frac{1}{Q_0} = (-1)^q (2ns+p+q+1) \int_a^b (x-a)^p (b-x)^q \omega_n^{2s}(x)\, dx \]

which is an interesting interpretation of the coefficient \(\frac{1}{Q_0}\) on the right-hand side of formula (3.5.24), related to the integral (3.5.9), whose minimizing polynomial is \(\omega_n\).

↑ Contents

Română

Chapter IV

The divided difference of a function of two variables and its representation by a double integral

D. V. Ionescu, Diferențe divizate [Divided Differences], Editura Academiei Republicii Socialiste România, Bucharest, 1978, pp. 131–168

In this chapter the method of the function \(\varphi\), set out in the first chapter in order to define the divided difference of a function of one variable and to obtain its integral representation, is extended to functions of two variables. We shall again arrive at this extension through a boundary value problem.

§ 4.1. The integration by parts formula for functions of two variables

In this section we establish the integration by parts formula for double integrals, and then the generalized integration by parts formula.

4.1.1. Theorem 4.1.1. If the functions \(f, \varphi\) are continuous on the rectangle \(\Delta\), together with their partial derivatives

(4.1.1)
\[ \begin{gathered} \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial^2 f}{\partial x \partial y} \\ \frac{\partial \varphi}{\partial x}, \frac{\partial \varphi}{\partial y}, \frac{\partial^2 \varphi}{\partial x \partial y} \end{gathered} \]

where

\[ \Delta : \qquad x_1 \leq x \leq x_2, \quad y_1 \leq y \leq y_2, \]

then we have the transformation formula

(4.1.2)
\[ \begin{aligned} \iint_\Delta \varphi \frac{\partial^2 f}{\partial x \partial y}\, dx\, dy = {} & \varphi(x_2, y_2) f(x_2, y_2) + \varphi(x_1, y_1) f(x_1, y_1) - \\ & - \varphi(x_1, y_2) f(x_1, y_2) - \varphi(x_2, y_1) f(x_2, y_1) - \\ & - \int_{x_1}^{x_2} \left[ \frac{\partial \varphi}{\partial x}(x, y_2) f(x, y_2) - \frac{\partial \varphi}{\partial x}(x, y_1) f(x, y_1) \right] dx - \\ & - \int_{y_1}^{y_2} \left[ \frac{\partial \varphi}{\partial y}(x_2, y) f(x_2, y) - \frac{\partial \varphi}{\partial y}(x_1, y) f(x_1, y) \right] dy + \iint_\Delta \frac{\partial^2 \varphi}{\partial x \partial y} f\, dx\, dy. \end{aligned} \]

Formula (4.1.2) was called by Academician M. Nicolescu the integration by parts formula for double integrals [26].

We shall write formula (4.1.2) in the form

(4.1.3)
\[ \int_{x_1}^{x_2} \int_{y_1}^{y_2} \varphi \frac{\partial^2 f}{\partial x \partial y}\, dx\, dy = {} \varphi(x, y) f(x, y) \Big|_{x_1, y_1}^{x_2, y_2} - \sum \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x}(x, y) f(x, y) \Bigg|_{y_1}^{y_2} dx + \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^2 \varphi}{\partial x \partial y} f\, dx\, dy, \]

where the symbols on the right-hand side are the following:

(4.1.4)
\[ \begin{aligned} & F(x, y) \Big|_{x_1}^{x_2} = F(x_2, y) - F(x_1, y), \\ & F(x, y) \Big|_{x_1, y_1}^{x_2, y_2} = \left( F(x, y) \Big|_{x_1}^{x_2} \right) \Bigg|_{y_1}^{y_2} = F(x_2, y_2) + F(x_1, y_1) - F(x_1, y_2) - F(x_2, y_1), \\ & \sum \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x} f \Bigg|_{y_1}^{y_2} dx = \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x}(x, y) f(x, y) \Bigg|_{y_1}^{y_2} dx + \int_{y_1}^{y_2} \frac{\partial \varphi}{\partial y}(x, y) f(x, y) \Bigg|_{x_1}^{x_2} dy. \end{aligned} \]

To prove formula (4.1.2) we shall write its left-hand side in the form

\[ I = \int_{x_1}^{x_2} \int_{y_1}^{y_2} \varphi \frac{\partial^2 f}{\partial x \partial y}\, dx\, dy = \int_{x_1}^{x_2} dx \int_{y_1}^{y_2} \varphi \frac{\partial}{\partial y} \left( \frac{\partial f}{\partial x} \right) dy \]

and apply the integration by parts formula to the integral \(\int_{y_1}^{y_2}\). We shall have

\[ I = \int_{x_1}^{x_2} \varphi(x, y_2) \frac{\partial f}{\partial x}(x, y_2)\, dx - \int_{x_1}^{x_2} \varphi(x, y_1) \frac{\partial f}{\partial x}(x, y_1)\, dx - \int_{y_1}^{y_2} dy \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial y} \frac{\partial f}{\partial x}\, dx. \]

Applying the integration by parts formula once more to each integral \(\int_{x_1}^{x_2}\), we obtain:

\[ \begin{aligned} I = {} & \varphi(x_2, y_2) f(x_2, y_2) - \varphi(x_1, y_2) f(x_1, y_2) - \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x}(x, y_2) f(x, y_2)\, dx - \\ & - \varphi(x_2, y_1) f(x_2, y_1) + \varphi(x_1, y_1) f(x_1, y_1) + \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x}(x, y_1) f(x, y_1)\, dx - \\ & - \int_{y_1}^{y_2} \frac{\partial \varphi}{\partial y}(x_2, y) f(x_2, y)\, dy + \int_{y_1}^{y_2} \frac{\partial \varphi}{\partial y}(x_1, y) f(x_1, y)\, dy + \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^2 \varphi}{\partial x \partial y} f\, dx\, dy. \end{aligned} \]

which is precisely formula (4.1.2).

4.1.2. Theorem 4.1.2. If the functions \(f, \varphi\) are continuous, together with their partial derivatives

(4.1.5)
\[ \begin{gathered} \frac{\partial^{2p-1} f}{\partial x^p \partial y^{p-1}}, \frac{\partial^{2p-1} f}{\partial x^{p-1} \partial y^p}, \frac{\partial^{2p} f}{\partial x^p \partial y^p} \\ \frac{\partial^{2p-1} \varphi}{\partial x^p \partial y^{p-1}}, \frac{\partial^{2p-1} \varphi}{\partial x^{p-1} \partial y^p}, \frac{\partial^{2p} \varphi}{\partial x^p \partial y^p} \end{gathered} \]

for \(p = 1, 2, \ldots, n\), on the rectangle \(\Delta\), then we have the transformation formula

(4.1.6)
\[ \begin{aligned} \int_{x_1}^{x_2} \int_{y_1}^{y_2} \varphi \frac{\partial^{2n} f}{\partial x^n \partial y^n}\, dx\, dy = {} & \sum_{r=0}^{n-1} \frac{\partial^{2(n-r-1)} \varphi}{\partial x^{n-r-1} \partial y^{n-r-1}}(x, y) \frac{\partial^{2r} f}{\partial x^r \partial y^r}(x, y) \Bigg|_{x_1, y_1}^{x_2, y_2} - \\ & - \sum_{r=0}^{n-1} \sum \int_{x_1}^{x_2} \frac{\partial^{2(n-r)-1} \varphi}{\partial x^{n-r} \partial y^{n-r-1}}(x, y) \frac{\partial^{2r} f}{\partial x^r \partial y^r}(x, y) \Bigg|_{y_1}^{y_2} dx + \\ & + \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^{2n} \varphi}{\partial x^n \partial y^n} f\, dx\, dy. \end{aligned} \]

We shall say that formula (4.1.6) is the generalized integration by parts formula for double integrals.

To prove formula (4.1.6), let us replace in formula (4.1.3) the function \(f\) by \(\dfrac{\partial^{2(n-1)} f}{\partial x^{n-1} \partial y^{n-1}}\). We shall have

\[ \begin{aligned} \int_{x_1}^{x_2} \int_{y_1}^{y_2} \varphi \frac{\partial^{2n} f}{\partial x^n \partial y^n}\, dx\, dy = {} & \varphi(x, y) \frac{\partial^{2(n-1)} f}{\partial x^{n-1} \partial y^{n-1}}(x, y) \Bigg|_{x_1, y_1}^{x_2, y_2} - \\ & - \sum \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x}(x, y) \frac{\partial^{2(n-1)} f}{\partial x^{n-1} \partial y^{n-1}}(x, y) \Bigg|_{y_1}^{y_2} dx + \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^2 \varphi}{\partial x \partial y} \frac{\partial^{2(n-1)} f}{\partial x^{n-1} \partial y^{n-1}}\, dx\, dy. \end{aligned} \]

Let us further replace in formula (4.1.3) the function \(\varphi\) by \(\dfrac{\partial^2 \varphi}{\partial x \partial y}\) and the function \(f\) by \(\dfrac{\partial^{2(n-2)} f}{\partial x^{n-2} \partial y^{n-2}}\). We shall have

\[ \begin{aligned} \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^2 \varphi}{\partial x \partial y} \frac{\partial^{2(n-1)} f}{\partial x^{n-1} \partial y^{n-1}}\, dx\, dy = {} & \frac{\partial^2 \varphi}{\partial x \partial y}(x, y) \frac{\partial^{2(n-2)} f}{\partial x^{n-2} \partial y^{n-2}}(x, y) \Bigg|_{x_1, y_1}^{x_2, y_2} - \\ & - \sum \int_{x_1}^{x_2} \frac{\partial^3 \varphi}{\partial x^2 \partial y}(x, y) \frac{\partial^{2(n-2)} f}{\partial x^{n-2} \partial y^{n-2}}(x, y) \Bigg|_{y_1}^{y_2} dx + \\ & + \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^4 \varphi}{\partial x^2 \partial y^2} \frac{\partial^{2(n-2)} f}{\partial x^{n-2} \partial y^{n-2}}\, dx\, dy. \end{aligned} \]

We continue this procedure until we reach the formula

\[ \begin{aligned} \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^{2(n-1)} \varphi}{\partial x^{n-1} \partial y^{n-1}} \frac{\partial^2 f}{\partial x \partial y}\, dx\, dy = {} & \frac{\partial^{2(n-1)} \varphi}{\partial x^{n-1} \partial y^{n-1}}(x, y) f(x, y) \Bigg|_{x_1, y_1}^{x_2, y_2} - \\ & - \sum \int_{x_1}^{x_2} \frac{\partial^{2(n-1)+1} \varphi}{\partial x^n \partial y^{n-1}}(x, y) f(x, y) \Bigg|_{y_1}^{y_2} dx + \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^{2n} \varphi}{\partial x^n \partial y^n} f\, dx\, dy. \end{aligned} \]

Adding all these formulas term by term, we obtain formula (4.1.6).

4.1.3. Let us consider the rectangle

\[ D : \qquad x_0 \leq x \leq x_n, \qquad y_0 \leq y \leq y_n \]

the nodes \(M_{i,k}(x_i, y_k)\), where

(4.1.7)
\[ x_0 \lt x_1 \lt \ldots \lt x_{n-1} \lt x_n, \qquad y_0 \lt y_1 \lt \ldots \lt y_{n-1} \lt y_n \]

and the rectangles

\[ D_{i,k} : \qquad x_i \leq x \leq x_{i+1}, \qquad y_k \leq y \leq y_{k+1}, \]

where \(i, k = 0, 1, \ldots, n-1\).

We also consider the functions \(\varphi_{i,k}\), \((i, k = 0, 1, \ldots, n-1)\), continuous on \(D_{i,k}\), together with the partial derivatives

(4.1.8)
\[ \frac{\partial^{2p-1} \varphi_{i,k}}{\partial x^p \partial y^{p-1}}, \frac{\partial^{2p-1} \varphi_{i,k}}{\partial x^{p-1} \partial y^p}, \frac{\partial^{2p} \varphi_{i,k}}{\partial x^p \partial y^p} \quad \text{for } p = 1, 2, \ldots, n. \]

Figure 4.1.1 shows the tiling of the rectangle \(D\) by the rectangles \(D_{i,k}\), with the nodes \(M_{i,k}\) marked.

M0,n M0,n−1 M0,2 M0,1 M0,0 M1,n M1,n−1 M1,2 M1,1 M1,0 M2,n M2,n−1 M2,2 M2,1 M2,0 Mn−1,n Mn−1,n−1 Mn−1,2 Mn−1,1 Mn−1,0 Mn,n Mn,n−1 Mn,2 Mn,1 Mn,0 D0,0 D0,1 D0,n−1 D1,0 D1,1 D1,n−1 Dn−1,0 Dn−1,1 Dn−1,n−1
Fig. 4.1.1.

To each rectangle \(D_{i,k}\) and to the functions \(f, \varphi_{i,k}\) we can apply the fundamental formula (4.1.6). Adding all these formulas term by term, we obtain a formula that is important for this chapter:

(4.1.9)
\[ \sum_{i=0}^{n-1} \sum_{k=0}^{n-1} \int_{x_i}^{x_{i+1}} \int_{y_k}^{y_{k+1}} \varphi_{i,k} \frac{\partial^{2n} f}{\partial x^n \partial y^n}\, dx\, dy = \mathscr{P}[f] + \sum_{i=0}^{n-1} \sum_{k=0}^{n-1} \int_{x_i}^{x_{i+1}} \int_{y_k}^{y_{k+1}} \frac{\partial^{2n} \varphi_{i,k}}{\partial x^n \partial y^n} f\, dx\, dy, \]

where

(4.1.10)
\[ \begin{aligned} \mathscr{P}[f] = {} & \sum_{r=0}^{n-1} \sum_{i=0}^{n-1} \sum_{k=0}^{n-1} \frac{\partial^{2(n-r-1)} \varphi_{i,k}}{\partial x^{n-r-1} \partial y^{n-r-1}}(x, y) \frac{\partial^{2r} f}{\partial x^r \partial y^r}(x, y) \Bigg|_{x_i, y_k}^{x_{i+1}, y_{k+1}} - \\ & - \sum_{r=0}^{n-1} \sum_{i=0}^{n-1} \sum_{k=0}^{n-1} \sum \int_{x_i}^{x_{i+1}} \frac{\partial^{2(n-r)-1} \varphi_{i,k}}{\partial x^{n-r} \partial y^{n-r-1}}(x, y) \frac{\partial^{2r} f}{\partial x^r \partial y^r}(x, y) \Bigg|_{y_k}^{y_{k+1}} dx. \end{aligned} \]

Taking formulas (4.1.4) into account, we can also write formula (4.1.10) in the form

(4.1.11)
\[ \begin{aligned} \mathscr{P}[f] = {} & \sum_{r=0}^{n-1} \left\{ \left( \frac{\partial^{2(n-r-1)} \varphi_{n-1,n-1}}{\partial x^{n-r-1} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_n, y_n} - \left( \frac{\partial^{2(n-r-1)} \varphi_{n-1,0}}{\partial x^{n-r-1} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_n, y_0} - \left( \frac{\partial^{2(n-r-1)} \varphi_{0,n-1}}{\partial x^{n-r-1} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_0, y_n} + \left( \frac{\partial^{2(n-r-1)} \varphi_{0,0}}{\partial x^{n-r-1} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_0, y_0} \right\} + \\ & + \sum_{r=0}^{n-1} \sum_{i=1}^{n-1} \left\{ \left( \frac{\partial^{2(n-r-1)}(\varphi_{i,0} - \varphi_{i-1,0})}{\partial x^{n-r-1} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_i, y_0} - \left( \frac{\partial^{2(n-r-1)}(\varphi_{i,n-1} - \varphi_{i-1,n-1})}{\partial x^{n-r-1} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_i, y_n} \right\} + \\ & + \sum_{r=0}^{n-1} \sum_{k=1}^{n-1} \left\{ \left( \frac{\partial^{2(n-r-1)}(\varphi_{0,k} - \varphi_{0,k-1})}{\partial x^{n-r-1} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_0, y_k} - \left( \frac{\partial^{2(n-r-1)}(\varphi_{n-1,k} - \varphi_{n-1,k-1})}{\partial x^{n-r-1} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_n, y_k} \right\} + \\ & + \sum_{r=0}^{n-1} \sum_{i=1}^{n-1} \sum_{k=1}^{n-1} \left( \frac{\partial^{2(n-r-1)}(\varphi_{i,k} + \varphi_{i-1,k-1} - \varphi_{i,k-1} - \varphi_{i-1,k})}{\partial x^{n-r-1} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_i, y_k} + \\ & + \sum_{r=0}^{n-1} \sum_{i=0}^{n-1} \int_{x_i}^{x_{i+1}} \left[ \left( \frac{\partial^{2(n-r)-1} \varphi_{i,0}}{\partial x^{n-r} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x, y_0} - \left( \frac{\partial^{2(n-r)-1} \varphi_{i,n-1}}{\partial x^{n-r} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x, y_n} \right] dx + \\ & + \sum_{r=0}^{n-1} \sum_{i=0}^{n-1} \sum_{k=1}^{n-1} \int_{x_i}^{x_{i+1}} \left( \frac{\partial^{2(n-r)-1}(\varphi_{i,k} - \varphi_{i,k-1})}{\partial x^{n-r} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x, y_k} dx + \\ & + \sum_{r=0}^{n-1} \sum_{k=0}^{n-1} \int_{y_k}^{y_{k+1}} \left[ \left( \frac{\partial^{2(n-r)-1} \varphi_{0,k}}{\partial x^{n-r-1} \partial y^{n-r}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_0, y} - \left( \frac{\partial^{2(n-r)-1} \varphi_{n-1,k}}{\partial x^{n-r-1} \partial y^{n-r}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_n, y} \right] dy + \\ & + \sum_{r=0}^{n-1} \sum_{k=0}^{n-1} \sum_{i=1}^{n-1} \int_{y_k}^{y_{k+1}} \left( \frac{\partial^{2(n-r)-1}(\varphi_{i,k} - \varphi_{i-1,k})}{\partial x^{n-r-1} \partial y^{n-r}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_i, y} dy. \end{aligned} \]

The writing of formula (4.1.11) can be shortened by adopting the following convention:

Convention (A). The function \(\varphi_{i,k}\) will be considered equal to zero when one of the indices \(i, k\), or both of them, are equal to \(n\) or to \(-1\).

With this convention, formula (4.1.11) can be written in the form

(4.1.12)
\[ \begin{aligned} \mathscr{P}[f] = {} & \sum_{r=0}^{n-1} \sum_{i=0}^{n} \sum_{k=0}^{n} \left( \frac{\partial^{2(n-r-1)}(\varphi_{i,k} + \varphi_{i-1,k-1} - \varphi_{i,k-1} - \varphi_{i-1,k})}{\partial x^{n-r-1} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_i, y_k} + \\ & + \sum_{r=0}^{n-1} \sum_{i=0}^{n-1} \sum_{k=0}^{n} \int_{x_i}^{x_{i+1}} \left( \frac{\partial^{2(n-r)-1}(\varphi_{i,k} - \varphi_{i,k-1})}{\partial x^{n-r} \partial y^{n-r-1}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x, y_k} dx + \\ & + \sum_{r=0}^{n-1} \sum_{k=0}^{n-1} \sum_{i=0}^{n} \int_{y_k}^{y_{k+1}} \left( \frac{\partial^{2(n-r)-1}(\varphi_{i,k} - \varphi_{i-1,k})}{\partial x^{n-r-1} \partial y^{n-r}} \frac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_i, y} dy \end{aligned} \]

because \(\mathscr{P}[f]\) given by formula (4.1.12) coincides, in view of convention (A), with \(\mathscr{P}[f]\) given by formula (4.1.11).

§ 4.2. Boundary value problem

In connection with formula (4.1.12) or (4.1.11), we shall pose a boundary value problem with the aim of arriving at the definition of the divided difference of the function \(f\) on the nodes \(M_{i,k}\), \((i, k = 0, 1, \ldots, n)\), and at its representation by a double integral.

4.2.1. Formula (4.1.12) shows that \(\mathscr{P}[f]\) depends on \(\left( \dfrac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_i, y_k}\) for \(r = 0, 1, \ldots, n-1\) and \(i, k = 0, 1, \ldots, n\), on \(\left( \dfrac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x, y_k}\) for \(r = 0, 1, \ldots, n-1\) and \(k = 0, 1, \ldots, n\), as well as on \(\left( \dfrac{\partial^{2r} f}{\partial x^r \partial y^r} \right)_{x_i, y}\) for \(r = 0, 1, \ldots, n-1\) and \(i = 0, 1, \ldots, n\).

In connection with formula (4.1.9) and with expression (4.1.12) of \(\mathscr{P}[f]\), it is of great interest to treat the following boundary value problem:

Boundary value problem. Determine the functions \(\varphi_{i,k}\), solutions of the partial differential equations

(4.2.1)
\[ \frac{\partial^{2n} \varphi_{i,k}}{\partial x^n \partial y^n} = 0 \quad \text{for } i, k = 0, 1, \ldots, n-1 \]

such that \(\mathscr{P}[f]\) depends only on the values of \(f\) at the nodes \(M_{i,k}\), for \(i, k = 0, 1, \ldots, n\).

For this, the following boundary conditions must be introduced:

(4.2.2)
\[ \begin{gathered} \frac{\partial^{2(n-r)-1}(\varphi_{i,k} - \varphi_{i,k-1})}{\partial x^{n-r} \partial y^{n-r-1}}(x, y_k) = 0 \\ \frac{\partial^{2(n-r)-1}(\varphi_{i,k} - \varphi_{i-1,k})}{\partial x^{n-r-1} \partial y^{n-r}}(x_i, y) = 0 \\ \frac{\partial^{2(n-r-1)}(\varphi_{i,k} + \varphi_{i-1,k-1} - \varphi_{i,k-1} - \varphi_{i-1,k})}{\partial x^{n-r-1} \partial y^{n-r-1}}(x_i, y_k) = \begin{cases} C_{i,k} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{gathered} \]

for \(r = 0, 1, \ldots, n-1\) and \(i, k = 0, 1, \ldots, n\). When we set \(i = n\), or \(k = n\), or \(i = k = 0\), or else \(i = k = n\) in the boundary conditions (4.2.2), we must take into account convention (A), made in subsection 4.1.3.

This boundary value problem will be denoted by \((P_{i,k})\), and the functions \(\varphi_{i,k}\) will be determined first on \(D_{0,0}\), then on \(D_{1,0}, \ldots, D_{n-1,0}\), next on \(D_{0,1}, \ldots, D_{n-1,1}, \ldots\), and so on.

The constants \(C_{i,k}\), \(i, k = 0, 1, \ldots, n\), will be determined, up to a factor, so that the problem is solvable. To determine them completely we shall introduce the supplementary condition

(4.2.3)
\[ \mathscr{P}[x^n, y^n] = 1. \]

4.2.2. Problem \((P_{0,0})\). Setting \(i = k = 0\) in equations (4.2.1) and in the boundary conditions (4.2.2), and taking convention (A) into account, problem \((P_{0,0})\) consists in determining the solution of the partial differential equation

(4.2.4)
\[ \frac{\partial^{2n} \varphi_{0,0}}{\partial x^n \partial y^n} = 0 \]

which satisfies the boundary conditions

(4.2.5)
\[ \begin{gathered} \frac{\partial^{2(n-r)-1} \varphi_{0,0}}{\partial x^{n-r} \partial y^{n-r-1}}(x, y_0) = 0 \\ \frac{\partial^{2(n-r)-1} \varphi_{0,0}}{\partial x^{n-r-1} \partial y^{n-r}}(x_0, y) = 0 \\ \frac{\partial^{2(n-r-1)} \varphi_{0,0}}{\partial x^{n-r-1} \partial y^{n-r-1}}(x_0, y_0) = \begin{cases} C_{0,0} & \text{if } r = 0, \\ 0 & \text{if } r \neq 0. \end{cases} \end{gathered} \]

This problem is very simple and has the solution

(4.2.6)
\[ \varphi_{0,0}(x, y) = C_{0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!}. \]

4.2.3. Problem \((P_{i,0})\), for \(i = 1, 2, \ldots, n-1\) and \(n\). Setting \(k = 0\) in equations (4.2.1) and in the boundary conditions (4.2.2), and taking convention (A) into account, problem \((P_{i,0})\) consists in determining the solution of the partial differential equation

(4.2.7)
\[ \frac{\partial^{2n} \varphi_{i,0}}{\partial x^n \partial y^n} = 0 \]

which satisfies the boundary conditions:

(4.2.8)
\[ \begin{gathered} \frac{\partial^{2(n-r)-1} \varphi_{i,0}}{\partial x^{n-r} \partial y^{n-r-1}}(x, y_0) = 0, \\ \frac{\partial^{2(n-r)-1}(\varphi_{i,0} - \varphi_{i-1,0})}{\partial x^{n-r-1} \partial y^{n-r}}(x_i, y) = 0, \\ \frac{\partial^{2(n-r-1)}(\varphi_{i,0} - \varphi_{i-1,0})}{\partial x^{n-r-1} \partial y^{n-r-1}}(x_i, y_0) = \begin{cases} C_{i,0} & \text{if } r = 0, \\ 0 & \text{if } r \neq 0, \end{cases} \end{gathered} \]

for \(i = 1, 2, \ldots, n-1\) and \(n\), taking convention (A) into account. As can be seen, this is a recurrence problem. We shall first determine \(\varphi_{1,0}\) and then, by the method of complete induction, we shall determine \(\varphi_{i,0}\) for \(i = 1, 2, \ldots, n-1\).

4.2.4. Let us first integrate the partial differential equation (4.2.7) for \(i = 1\):

(4.2.9)
\[ \frac{\partial^{2n} \varphi_{1,0}}{\partial x^n \partial y^n} = 0 \]

with the boundary conditions (4.2.8) corresponding to \(r = 0\), that is

(4.2.10)
\[ \begin{gathered} \frac{\partial^{2n-1} \varphi_{1,0}}{\partial x^n \partial y^{n-1}}(x, y_0) = 0, \\ \frac{\partial^{2n-1} \varphi_{1,0}}{\partial x^{n-1} \partial y^n}(x_1, y) = \frac{\partial^{2n-1} \varphi_{0,0}}{\partial x^{n-1} \partial y^n}(x_1, y) = 0, \\ \frac{\partial^{2(n-1)} \varphi_{1,0}}{\partial x^{n-1} \partial y^{n-1}}(x_1, y_0) = C_{1,0} + \frac{\partial^{2(n-1)} \varphi_{0,0}}{\partial x^{n-1} \partial y^{n-1}}(x_1, y_0) = C_{0,0} + C_{1,0}. \end{gathered} \]

We find

(4.2.9₁)
\[ \frac{\partial^{2(n-1)} \varphi_{1,0}}{\partial x^{n-1} \partial y^{n-1}}(x, y) = C_{0,0} + C_{1,0}. \]

Then equation (4.2.9) is integrated with conditions (4.2.8) corresponding to \(r = 1\) and \(i = 1\), that is

(4.2.11)
\[ \begin{gathered} \frac{\partial^{2n-3} \varphi_{1,0}}{\partial x^{n-1} \partial y^{n-2}}(x, y_0) = 0, \\ \frac{\partial^{2n-3} \varphi_{1,0}}{\partial x^{n-2} \partial y^{n-1}}(x_1, y) = \frac{\partial^{2n-3} \varphi_{0,0}}{\partial x^{n-2} \partial y^{n-1}}(x_1, y_0) = C_{0,0}(x_1 - x_0), \\ \frac{\partial^{2(n-2)} \varphi_{1,0}}{\partial x^{n-2} \partial y^{n-2}}(x_1, y_0) = \frac{\partial^{2(n-2)} \varphi_{0,0}}{\partial x^{n-2} \partial y^{n-2}}(x_1, y_0) = 0. \end{gathered} \]

We find

(4.2.9₂)
\[ \frac{\partial^{2(n-2)} \varphi_{1,0}}{\partial x^{n-2} \partial y^{n-2}}(x, y) = [C_{0,0}(x - x_0) + C_{1,0}(x - x_1)](y - y_0). \]

Let us suppose we have proved that

(4.2.9ᵣ)
\[ \frac{\partial^{2(n-r)} \varphi_{1,0}}{\partial x^{n-r} \partial y^{n-r}}(x, y) = \left[ C_{0,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0} \frac{(x - x_1)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \]

which holds for \(r = 1\) and \(r = 2\), and let us prove that the same formula is also valid for the index \(r+1\).

For this we must integrate equation (4.2.9ᵣ) with the boundary conditions (4.2.8) corresponding to the index \(r\):

\[ \begin{gathered} \frac{\partial^{2(n-r)-1} \varphi_{1,0}}{\partial x^{n-r} \partial y^{n-r-1}}(x, y_0) = 0, \\ \frac{\partial^{2(n-r)-1} \varphi_{1,0}}{\partial x^{n-r-1} \partial y^{n-r}}(x_1, y) = \frac{\partial^{2(n-r)-1} \varphi_{0,0}}{\partial x^{n-r-1} \partial y^{n-r}}(x_1, y) = C_{0,0} \frac{(x_1 - x_0)^r}{r!} \frac{(y - y_0)^{r-1}}{(r-1)!}, \\ \frac{\partial^{2(n-r-1)} \varphi_{1,0}}{\partial x^{n-r-1} \partial y^{n-r-1}}(x_1, y_0) = \frac{\partial^{2(n-r-1)} \varphi_{0,0}}{\partial x^{n-r-1} \partial y^{n-r-1}}(x_1, y_0) = 0. \end{gathered} \]

Integrating, we find

(4.2.9ᵣ₊₁)
\[ \frac{\partial^{2(n-r-1)} \varphi_{1,0}}{\partial x^{n-r-1} \partial y^{n-r-1}}(x, y) = \left[ C_{0,0} \frac{(x - x_0)^r}{r!} + C_{1,0} \frac{(x - x_1)^r}{r!} \right] \frac{(y - y_0)^r}{r!}. \]

Since formula (4.2.9ᵣ₊₁) is obtained from formula (4.2.9ᵣ) by replacing \(r\) by \(r+1\), it follows that formula (4.2.9ᵣ) is general; it holds for \(r = 1, 2, \ldots, n\).

For \(r = n\) we have

(4.2.9ₙ)
\[ \varphi_{1,0}(x, y) = \left[ C_{0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + C_{1,0} \frac{(x - x_1)^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!}. \]

4.2.5. Let us suppose we have proved that

(4.2.13)
\[ \varphi_{i,0}(x, y) = \left[ C_{0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \]

which is true for \(i = 1\), because in this case formula (4.2.13) reduces to formula (4.2.9ₙ). Let us prove that formula (4.2.13) is also valid for the index \(i + 1\).

For this we shall integrate the partial differential equation

(4.2.14)
\[ \frac{\partial^{2n} \varphi_{i+1,0}}{\partial x^n \partial y^n} = 0 \]

first with the boundary conditions

(4.2.15)
\[ \begin{gathered} \frac{\partial^{2n-1} \varphi_{i+1,0}}{\partial x^n \partial y^{n-1}}(x, y_0) = 0, \\ \frac{\partial^{2n-1} \varphi_{i+1,0}}{\partial x^{n-1} \partial y^n}(x_{i+1}, y) = \frac{\partial^{2n-1} \varphi_{i,0}}{\partial x^{n-1} \partial y^n}(x_{i+1}, y) = 0, \\ \frac{\partial^{2(n-1)} \varphi_{i+1,0}}{\partial x^{n-1} \partial y^{n-1}}(x_{i+1}, y_0) = C_{i+1,0} + \frac{\partial^{2(n-1)} \varphi_{i,0}}{\partial x^{n-1} \partial y^{n-1}}(x_{i+1}, y_0) = C_{0,0} + \ldots + C_{i+1,0}, \end{gathered} \]

and then with the boundary conditions

(4.2.16)
\[ \begin{gathered} \frac{\partial^{2(n-r)-1} \varphi_{i+1,0}}{\partial x^{n-r} \partial y^{n-r-1}}(x, y_0) = 0, \\ \frac{\partial^{2(n-r)-1} \varphi_{i+1,0}}{\partial x^{n-r-1} \partial y^{n-r}}(x_{i+1}, y) = \frac{\partial^{2(n-r)-1} \varphi_{i,0}}{\partial x^{n-r-1} \partial y^{n-r}}(x_{i+1}, y) = \left[ C_{0,0} \frac{(x_{i+1} - x_0)^r}{r!} + \ldots + C_{i,0} \frac{(x_{i+1} - x_i)^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \\ \frac{\partial^{2(n-r-1)} \varphi_{i+1,0}}{\partial x^{n-r-1} \partial y^{n-r-1}}(x_{i+1}, y_0) = \frac{\partial^{2(n-r-1)} \varphi_{i,0}}{\partial x^{n-r-1} \partial y^{n-r-1}}(x_{i+1}, y_0) = 0, \end{gathered} \]

for \(r = 1, 2, \ldots, n-1\).

We first find

\[ \frac{\partial^{2(n-1)}\varphi_{i+1,0}}{\partial x^{n-1}\partial y^{n-1}}(x, y) = C_{0,0} + C_{1,0} + \ldots + C_{i+1,0}, \]

after that we find

\[ \frac{\partial^{2(n-2)}\varphi_{i+1,0}}{\partial x^{n-2}\partial y^{n-2}}(x, y) = [C_{0,0}(x - x_0) + \ldots + C_{i+1,0}(x - x_{i+1})](y - y_0) \]

and, applying the method of complete induction as in subsection 4.2.4, we find

\[ \frac{\partial^{2(n-r)}\varphi_{i+1,0}}{\partial x^{n-r}\partial y^{n-r}}(x, y) = \left[C_{0,0}\frac{(x-x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,0}\frac{(x-x_{i+1})^{r-1}}{(r-1)!}\right]\frac{(y-y_0)^{r-1}}{(r-1)!} \]

which shows that formula (4.2.13) is general; it holds for \(i = 0, 1, \ldots, n-1\).

4.2.6. It remains to write that conditions (4.2.2) are satisfied for \(i = n\), \(k = 0\) and \(r = 0, 1, \ldots, n-1\). We must take convention (A) into account. These conditions reduce to:

(4.2.17)
\[ \frac{\partial^{2(n-r)-1}\varphi_{n-1,0}}{\partial x^{n-r-1}\partial y^{n-r}}(x_n, y) = 0 \]

and

(4.2.18)
\[ -\frac{\partial^{2(n-r-1)}\varphi_{n-1,0}}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_n, y_0) = \begin{cases} C_{n,0} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \]

for \(r = 0, 1, \ldots, n-1\).

Formula (4.2.13) gives, for \(i = n-1\),

(4.2.19)
\[ \varphi_{n-1,0}(x, y) = \left[C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0}\frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y - y_0)^{n-1}}{(n-1)!} \]

For \(r = 0\), condition (4.2.17) is satisfied because \(\varphi_{n-1,0}\) is a polynomial of degree \(n-1\) in \(y\), whereas condition (4.2.18) leads to the relation

(4.2.20)
\[ C_{0,0} + C_{1,0} + \ldots + C_{n,0} = 0. \]

For \(r = 1, 2, \ldots, n-1\), conditions (4.2.17) are

\[ \frac{\partial^{2(n-r)-1}\varphi_{n-1,0}}{\partial x^{n-r-1}\partial y^{n-r}}(x_n, y) = \left[C_{0,0}\frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0}\frac{(x_n - x_{n-1})^r}{r!}\right]\frac{(y-y_0)^{r-1}}{(r-1)!} \]

and for them to be satisfied we must take

(4.2.21)
\[ C_{0,0}(x_n - x_0)^r + \ldots + C_{n-1,0}(x_n - x_{n-1})^r = 0, \quad \text{for } r = 1, 2, \ldots, n-1. \]

Conditions (4.2.18) are satisfied, because the derivatives \(\frac{\partial^{2(n-r-1)}\varphi_{n-1,0}}{\partial x^{n-r-1}\partial y^{n-r-1}}\) have the property of vanishing when \(x = x_n\), for \(r = 1, 2, \ldots, n-1\).

Indeed, we have

\[ \frac{\partial^{2(n-r-1)}\varphi_{n-1,0}}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_n, y) = \left[C_{0,0}\frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0}\frac{(x_n - x_{n-1})^r}{r!}\right]\frac{(y - y_0)^r}{r!} \]

and the large bracket is zero by equations (4.2.21) for \(r = 1, 2, \ldots, n-1\).

Relations (4.2.20) and (4.2.21) can be written in the form:

(4.2.22)
\[ \begin{array}{lllll} C_{0,0} & + C_{1,0} & + \ldots & + C_{n,0} & = 0 \\ C_{0,0} x_0 & + C_{1,0} x_1 & + \ldots & + C_{n,0} x_n & = 0 \\ \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots \\ C_{0,0} x_0^{n-1} & + C_{1,0} x_1^{n-1} & + \ldots & + C_{n,0} x_n^{n-1} & = 0 \end{array} \]

and these equations determine \(C_{0,0}, C_{1,0}, \ldots, C_{n,0}\) up to a factor. We have

\[ \frac{C_{0,0}}{V(x_1, x_2, \ldots, x_n)} = \frac{C_{1,0}}{-V(x_0, x_2, \ldots, x_n)} = \frac{C_{n,0}}{(-1)^n V(x_0, x_1, \ldots, x_{n-1})} = H_0 \]

and therefore

(4.2.23)
\[ C_{i,0} = (-1)^i H_0 V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n) \quad \text{for } i = 0, 1, \ldots, n. \]

The factor \(H_0\) will be determined later.

4.2.7. Problem \((P_{0,k})\) for \(k = 1, 2, \ldots, n-1\) and \(n\). Setting \(i = 0\) in equation (4.2.1) and in the boundary conditions (4.2.2), and taking convention (A) into account, problem \((P_{0,k})\) consists in determining the solution of the partial differential equation:

(4.2.24)
\[ \frac{\partial^{2n}\varphi_{0,k}}{\partial x^n \partial y^n} = 0 \]

which satisfies the boundary conditions:

(4.2.25)
\[ \begin{gathered} \frac{\partial^{2(n-r)-1}(\varphi_{0,k} - \varphi_{0,k-1})}{\partial x^{n-r}\partial y^{n-r-1}}(x, y_k) = 0 \\ \frac{\partial^{2(n-r)-1}\varphi_{0,k}}{\partial x^{n-r-1}\partial y^{n-r}}(x_0, y) = 0 \\ \frac{\partial^{2(n-r-1)}(\varphi_{0,k} - \varphi_{0,k-1})}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_0, y_k) = \begin{cases} C_{0,k} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{gathered} \]

for \(k = 1, 2, \ldots, n-1\) and \(n\), taking convention (A) into account.

The solution of this problem is found as in the case of problem \((P_{i,0})\). We shall have

(4.2.26)
\[ \varphi_{0,k}(x, y) = \frac{(x-x_0)^{n-1}}{(n-1)!}\left[C_{0,0}\frac{(y-y_0)^{n-1}}{(n-1)!} + C_{0,1}\frac{(y - y_1)^{n-1}}{(n-1)!} + \ldots + C_{0,k}\frac{(y-y_k)^{n-1}}{(n-1)!}\right], \]

where the coefficients \(C_{0,0}, C_{0,1}, \ldots, C_{0,n}\) are given by the equations

(4.2.27)
\[ C_{0,0} + C_{0,1} + \ldots + C_{0,n} = 0 \]

and

(4.2.28)
\[ C_{0,0}(y_n - y_0)^r + C_{0,1}(y_n - y_1)^r + \ldots + C_{0,n-1}(y_n - y_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\).

The system formed by equations (4.2.27), (4.2.28) can also be written in the form:

(4.2.29)
\[ \begin{array}{lllll} C_{0,0} & + C_{0,1} & + \ldots & + C_{0,n} & = 0, \\ C_{0,0} y_0 & + C_{0,1} y_1 & + \ldots & + C_{0,n} y_n & = 0, \\ \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots \\ C_{0,0} y_0^{n-1} & + C_{0,1} y_1^{n-1} & + \ldots & + C_{0,n} y_n^{n-1} & = 0. \end{array} \]

4.2.8. Problem \((P_{ik})\), \(i, k = 1, 2, \ldots, n-1\) and \(n\). This problem was stated in subsection 4.2.1. It is a recurrence problem with two indices \(i\) and \(k\). Setting first \(k = 1\), we shall determine \(\varphi_{1,1}, \varphi_{2,1}, \ldots, \varphi_{n-1,1}\). Then, by the method of complete induction, we shall determine, for the index \(k\), the functions \(\varphi_{1,k}, \varphi_{2,k}, \ldots, \varphi_{n-1,k}\). Taking into account convention (A) and condition (4.2.3), all the coefficients \(C_{i,k}\) will be determined.

Let us begin by determining \(\varphi_{1,1}\). We have to integrate the partial differential equation

(4.2.30)
\[ \frac{\partial^{2n}\varphi_{1,1}}{\partial x^n \partial y^n} = 0 \]

with the boundary conditions

(4.2.31)
\[ \begin{gathered} \frac{\partial^{2(n-r)-1}(\varphi_{1,1} - \varphi_{1,0})}{\partial x^{n-r}\partial y^{n-r-1}}(x, y_1) = 0 \\ \frac{\partial^{2(n-r)-1}(\varphi_{1,1} - \varphi_{0,1})}{\partial x^{n-r-1}\partial y^{n-r}}(x_1, y) = 0 \\ \frac{\partial^{2(n-r-1)}(\varphi_{1,1} + \varphi_{0,0} - \varphi_{1,0} - \varphi_{0,1})}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_1, y_1) = \begin{cases} C_{1,1} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{gathered} \]

for \(r = 0, 1, \ldots, n-1\).

The functions \(\varphi_{0,0}, \varphi_{1,0}, \varphi_{0,1}\) being determined by equations (4.2.6), (4.2.13), (4.2.26), we can deduce from formulas (4.2.31) the boundary conditions for the function \(\varphi_{1,1}\) and thus determine \(\varphi_{1,1}\).

We have

\[ \begin{aligned} \varphi_{0,0}(x, y) &= C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!}\,\frac{(y-y_0)^{n-1}}{(n-1)!} \\ \varphi_{1,0}(x, y) &= \left[C_{0,0}\frac{(x - x_0)^{n-1}}{(n-1)!} + C_{1,0}\frac{(x - x_1)^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!} \\ \varphi_{0,1}(x, y) &= \left[C_{0,0}\frac{(y-y_0)^{n-1}}{(n-1)!} + C_{0,1}\frac{(y-y_1)^{n-1}}{(n-1)!}\right]\frac{(x-x_0)^{n-1}}{(n-1)!} \end{aligned} \]

so that conditions (4.2.31) become, for \(r = 0\),

(4.2.31₀)
\[ \begin{gathered} \frac{\partial^{2n-1}\varphi_{1,1}}{\partial x^n \partial y^{n-1}}(x, y_1) = 0 \\ \frac{\partial^{2n-1}\varphi_{1,1}}{\partial x^{n-1}\partial y^n}(x_1, y) = 0 \\ \frac{\partial^{2(n-1)}\varphi_{1,1}}{\partial x^{n-1}\partial y^{n-1}}(x_1, y_1) = C_{0,0} + C_{1,0} + C_{0,1} + C_{1,1}. \end{gathered} \]

we find

(4.2.32)
\[ \frac{\partial^{2(n-1)}\varphi_{1,1}}{\partial x^{n-1}\partial y^{n-1}}(x, y) = (C_{0,0} + C_{1,0}) + (C_{0,1} + C_{1,1}). \]

For \(r = 1, 2, \ldots, n-1\), the boundary conditions are:

(4.2.31ᵣ)
\[ \begin{gathered} \frac{\partial^{2(n-r)-1}\varphi_{1,1}}{\partial x^{n-r}\partial y^{n-r-1}}(x, y_1) = \left[C_{0,0}\frac{(x-x_0)^{r-1}}{(r-1)!} + C_{1,0}\frac{(x-x_1)^{r-1}}{(r-1)!}\right]\frac{(y_1 - y_0)^r}{r!}, \\ \frac{\partial^{2(n-r)-1}\varphi_{1,1}}{\partial x^{n-r-1}\partial y^{n-r}}(x_1, y) = \left[C_{0,0}\frac{(y-y_0)^{r-1}}{(r-1)!} + C_{0,1}\frac{(y-y_1)^{r-1}}{(r-1)!}\right]\frac{(x_1 - x_0)^r}{r!}, \\ \frac{\partial^{2(n-r-1)}\varphi_{1,1}}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_1, y_1) = C_{0,0}\frac{(x_1 - x_0)^r}{r!}\,\frac{(y_1 - y_0)^r}{r!}. \end{gathered} \]

Integrating equation (4.2.32) with conditions (4.2.31₁), we find

(4.2.33)
\[ \frac{\partial^{2(n-2)}\varphi_{1,1}}{\partial x^{n-2}\partial y^{n-2}}(x, y) = [C_{0,0}(x-x_0) + C_{1,0}(x-x_1)](y-y_0) + [C_{0,1}(x-x_0) + C_{1,1}(x-x_1)](y-y_1). \]

Let us suppose we have proved that

(4.2.34)
\[ \frac{\partial^{2(n-r)}\varphi_{1,1}}{\partial x^{n-r}\partial y^{n-r}}(x, y) = \left[C_{0,0}\frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0}\frac{(x - x_1)^{r-1}}{(r-1)!}\right]\frac{(y - y_0)^{r-1}}{(r-1)!} + \left[C_{0,1}\frac{(x-x_0)^{r-1}}{(r-1)!} + C_{1,1}\frac{(x - x_1)^{r-1}}{(r-1)!}\right]\frac{(y-y_1)^{r-1}}{(r-1)!} \]

which is true for \(r = 2\), because in this case formula (4.2.34) coincides with formula (4.2.33). Let us prove that formula (4.2.34) is also valid for the index \(r + 1\). For this we must integrate equation (4.2.34) with conditions (4.2.31ᵣ).

Proceeding as above, we find

(4.2.35)
\[ \frac{\partial^{2(n-r-1)}\varphi_{1,1}}{\partial x^{n-r-1}\partial y^{n-r-1}}(x, y) = \left[C_{0,0}\frac{(x-x_0)^r}{r!} + C_{1,0}\frac{(x-x_1)^r}{r!}\right]\frac{(y-y_0)^r}{r!} + \left[C_{0,1}\frac{(x-x_0)^r}{r!} + C_{1,1}\frac{(x-x_1)^r}{r!}\right]\frac{(y-y_1)^r}{r!}. \]

Since this formula is obtained from formula (4.2.34) by replacing \(r\) by \(r + 1\), it follows that formula (4.2.34) is general; it holds for \(r = 1, 2, \ldots, n\). For \(r = n\), formula (4.2.34) is

(4.2.36)
\[ \varphi_{1,1}(x, y) = \left[C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + C_{1,0}\frac{(x - x_1)^{n-1}}{(n-1)!}\right]\frac{(y - y_0)^{n-1}}{(n-1)!} + \left[C_{0,1}\frac{(x - x_0)^{n-1}}{(n-1)!} + C_{1,1}\frac{(x - x_1)^{n-1}}{(n-1)!}\right]\frac{(y - y_1)^{n-1}}{(n-1)!} \]

4.2.9. Let us suppose it has been proved that

(4.2.37)
\[ \varphi_{i,1}(x, y) = \left[C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0}\frac{(x - x_i)^{n-1}}{(n-1)!}\right]\frac{(y - y_0)^{n-1}}{(n-1)!} + \left[C_{0,1}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,1}\frac{(x - x_i)^{n-1}}{(n-1)!}\right]\frac{(y - y_1)^{n-1}}{(n-1)!} \]

which is true for \(i = 1\), because in this case formula (4.2.37) coincides with formula (4.2.36). Let us prove that formula (4.2.37) is also valid for the index \(i + 1\).

For this we must integrate the partial differential equation

(4.2.38)
\[ \frac{\partial^{2n}\varphi_{i+1,1}}{\partial x^n \partial y^n} = 0 \]

with the boundary conditions

(4.2.39ᵣ)
\[ \begin{gathered} \frac{\partial^{2(n-r)-1}(\varphi_{i+1,1} - \varphi_{i+1,0})}{\partial x^{n-r}\partial y^{n-r-1}}(x, y_1) = 0, \\ \frac{\partial^{2(n-r)-1}(\varphi_{i+1,1} - \varphi_{i,1})}{\partial x^{n-r-1}\partial y^{n-r}}(x_{i+1}, y) = 0, \\ \frac{\partial^{2(n-r-1)}(\varphi_{i+1,1} + \varphi_{i,0} - \varphi_{i+1,0} - \varphi_{i,1})}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_{i+1}, y_1) = \begin{cases} C_{i+1,1} & \text{if } r = 0, \\ 0 & \text{if } r \neq 0 \end{cases} \end{gathered} \]

To these conditions we further add formulas (4.2.37) and (4.2.13) for the indices \(i\) and \(i + 1\), which we have already proved.

Let us first integrate equation (4.2.38) with conditions (4.2.39₀), which are the following:

\[ \begin{gathered} \frac{\partial^{2n-1}\varphi_{i+1,1}}{\partial x^n \partial y^{n-1}}(x, y_1) = 0, \\ \frac{\partial^{2n-1}\varphi_{i+1,1}}{\partial x^{n-1}\partial y^n}(x_{i+1}, y) = 0, \\ \frac{\partial^{2(n-1)}\varphi_{i+1,1}}{\partial x^{n-1}\partial y^{n-1}}(x_{i+1}, y_1) = C_{0,0} + C_{1,0} + \ldots + C_{i+1,0} + C_{0,1} + C_{1,1} + \ldots + C_{i+1,1}. \end{gathered} \]

We find

(4.2.40)
\[ \begin{aligned} \frac{\partial^{2(n-1)}\varphi_{i+1,1}}{\partial x^{n-1}\partial y^{n-1}}(x, y) &= C_{0,0} + C_{1,0} + \ldots + C_{i+1,0} + \\ &+ C_{0,1} + C_{1,1} + \ldots + C_{i+1,1}. \end{aligned} \]

For \(r = 1\), formulas (4.2.39₁) give

\[ \begin{aligned} \frac{\partial^{2n-3}\varphi_{i+1,1}}{\partial x^{n-1}\partial y^{n-2}}(x, y_1) &= (C_{0,0} + C_{1,0} + \ldots + C_{i+1,0})(y_1 - y_0) \\ \frac{\partial^{2n-3}\varphi_{i+1,1}}{\partial x^{n-2}\partial y^{n-1}}(x_{i+1}, y) &= C_{0,0}(x_{i+1} - x_0) + \ldots + C_{i,0}(x_{i+1} - x_i) + \\ &+ C_{0,1}(x_{i+1} - x_0) + \ldots + C_{i,1}(x_{i+1} - x_i), \\ \frac{\partial^{2(n-2)}\varphi_{i+1,1}}{\partial x^{n-2}\partial y^{n-2}}(x_{i+1}, y_1) &= [C_{0,0}(x_{i+1} - x_0) + \ldots + C_{i,0}(x_{i+1} - x_i)](y_1 - y_0). \end{aligned} \]

Integrating equation (4.2.40) with these conditions, we find

(4.2.41)
\[ \begin{aligned} \frac{\partial^{2(n-2)}\varphi_{i+1,1}}{\partial x^{n-2}\partial y^{n-2}}(x, y) &= [C_{0,0}(x-x_0) + \ldots + C_{i+1,0}(x-x_{i+1})](y - y_0) + \\ &+ [C_{0,1}(x-x_0) + \ldots + C_{i+1,1}(x-x_{i+1})](y - y_1). \end{aligned} \]

Let us suppose it has been proved that

(4.2.42)
\[ \begin{aligned} \frac{\partial^{2(n-r)}\varphi_{i+1,1}}{\partial x^{n-r}\partial y^{n-r}}(x, y) &= \left[C_{0,0}\frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,0}\frac{(x - x_{i+1})^{r-1}}{(r-1)!}\right]\frac{(y - y_0)^{r-1}}{(r-1)!} + \\ &+ \left[C_{0,1}\frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,1}\frac{(x - x_{i+1})^{r-1}}{(r-1)!}\right]\frac{(y - y_1)^{r-1}}{(r-1)!} \end{aligned} \]

which is true for \(r = 2\), because, in this case, formula (4.2.42) coincides with formula (4.2.41). Let us prove that formula (4.2.42) is also valid for the index \(r + 1\).

For this we must integrate equation (4.2.42) with conditions (4.2.39ᵣ). Taking into account formulas (4.2.37) and (4.2.13) for the indices \(i\) and \(i + 1\), the boundary conditions give

\[ \begin{aligned} \frac{\partial^{2(n-r)-1}\varphi_{i+1,1}}{\partial x^{n-r}\partial y^{n-r-1}}(x, y_1) &= \left[C_{0,0}\frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,0}\frac{(x-x_{i+1})^{r-1}}{(r-1)!}\right]\frac{(y_1 - y_0)^r}{r!} \\ \frac{\partial^{2(n-r)-1}\varphi_{i+1,1}}{\partial x^{n-r-1}\partial y^{n-r}}(x_{i+1}, y) &= \left[C_{0,0}\frac{(x_{i+1}-x_0)^r}{r!} + \ldots + C_{i,0}\frac{(x_{i+1} - x_i)^r}{r!}\right]\frac{(y - y_0)^{r-1}}{(r-1)!} + \\ &+ \left[C_{0,1}\frac{(x_{i+1} - x_0)^r}{r!} + \ldots + C_{i,1}\frac{(x_{i+1} - x_i)^r}{r!}\right]\frac{(y - y_1)^{r-1}}{(r-1)!}, \\ \frac{\partial^{2(n-r-1)}\varphi_{i+1,1}}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_{i+1}, y_1) &= \left[C_{0,0}\frac{(x_{i+1} - x_0)^r}{r!} + \ldots + C_{i,0}\frac{(x_{i+1} - x_i)^r}{r!}\right]\frac{(y_1 - y_0)^r}{r!}. \end{aligned} \]

Integrating equation (4.2.42) with these conditions, we find

(4.2.43)
\[ \begin{aligned} \frac{\partial^{2(n-r-1)}\varphi_{i+1,1}}{\partial x^{n-r-1}\partial y^{n-r-1}}(x, y) &= \left[C_{0,0}\frac{(x-x_0)^r}{r!} + \ldots + C_{i+1,0}\frac{(x-x_{i+1})^r}{r!}\right]\frac{(y-y_0)^r}{r!} + \\ &+ \left[C_{0,1}\frac{(x-x_0)^r}{r!} + \ldots + C_{i+1,1}\frac{(x - x_{i+1})^r}{r!}\right]\frac{(y-y_1)^r}{r!}. \end{aligned} \]

Formula (4.2.43) is obtained from formula (4.2.42) by replacing \(r\) by \(r + 1\). Formula (4.2.42) is therefore general; it holds for \(r = 1, 2, \ldots, n\). For \(r = n\) we have

(4.2.44)
\[ \begin{aligned} \varphi_{i+1,1}(x, y) &= \left[C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{i+1,0}\frac{(x-x_{i+1})^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!} + \\ &+ \left[C_{0,1}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{i+1,1}\frac{(x - x_{i+1})^{n-1}}{(n-1)!}\right]\frac{(y - y_1)^{n-1}}{(n-1)!} \end{aligned} \]

Formula (4.2.44) is obtained from formula (4.2.37) by replacing \(i\) by \(i + 1\). Hence formula (4.2.37) is general; it holds for \(i = 1, 2, \ldots, n-1\).

4.2.10. It remains to write that conditions (4.2.2) are satisfied for \(i = n\), \(k = 1\) and \(r = 0, 1, \ldots, n-1\). We must take convention (A) into account. These conditions reduce to:

(4.2.45)
\[ \frac{\partial^{2(n-r)-1}\varphi_{n-1,1}}{\partial x^{n-r-1}\partial y^{n-r}}(x_n, y) = 0 \]
(4.2.46)
\[ \frac{\partial^{2(n-r-1)}(\varphi_{n-1,0} - \varphi_{n-1,1})}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_n, y_1) = \begin{cases} C_{n,1} & \text{if } r = 0. \\ 0 & \text{if } r \neq 0. \end{cases} \]

We must take into account formula (4.2.19)

\[ \varphi_{n-1,0}(x, y) = \left[C_{0,0}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0}\frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y - y_0)^{n-1}}{(n-1)!}. \]

For \(r = 0\), condition (4.2.45) is satisfied, because \(\varphi_{n-1,1}\) is a polynomial of degree \(n-1\) in \(y\). Condition (4.2.46) reduces to:

(4.2.47)
\[ C_{0,1} + C_{1,1} + \ldots + C_{n-1,1} + C_{n,1} = 0. \]

For \(r = 1, 2, \ldots, n-1\) we have

\[ \begin{aligned} \frac{\partial^{2(n-r)-1}\varphi_{n-1,1}}{\partial x^{n-r-1}\partial y^{n-r}}(x_n, y) &= \left[C_{0,0}\frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0}\frac{(x_n - x_{n-1})^r}{r!}\right]\frac{(y - y_0)^{r-1}}{(r-1)!} + \\ &+ \left[C_{0,1}\frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1}\frac{(x_n - x_{n-1})^r}{r!}\right]\frac{(y - y_1)^{r-1}}{(r-1)!} \end{aligned} \]

But by equations (4.2.21) the first large bracket on the right-hand side is zero for \(r = 1, 2, \ldots, n-1\). There remains

\[ \frac{\partial^{2(n-r)-1}\varphi_{n-1,1}}{\partial x^{n-r-1}\partial y^{n-r}}(x_n, y) = \left[C_{0,1}\frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1}\frac{(x_n - x_{n-1})^r}{r!}\right]\frac{(y - y_1)^{r-1}}{(r-1)!} \]

For conditions (4.2.45) to be satisfied for \(r = 1, 2, \ldots, n-1\), we must take

(4.2.48)
\[ C_{0,1}(x_n - x_0)^r + \ldots + C_{n-1,1}(x_n - x_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\).

On the other hand, we have

\[ \frac{\partial^{2(n-r-1)}(\varphi_{n-1,1} - \varphi_{n-1,0})}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_n, y) = \left[C_{0,1}\frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1}\frac{(x_n - x_{n-1})^r}{r!}\right]\frac{(y - y_1)^r}{r!} \]

and it follows from equations (4.2.48) that conditions (4.2.46) are satisfied for \(r = 1, 2, \ldots, n-1\).

Hence the coefficients \(C_{0,1}, \ldots, C_{n,1}\) are determined by equations (4.2.47) and (4.2.48). The system formed by these equations can also be written in the form

(4.2.49)
\[ \begin{array}{lllll} C_{0,1} & + C_{1,1} & + \ldots & + C_{n,1} & = 0 \\ C_{0,1} x_0 & + C_{1,1} x_1 & + \ldots & + C_{n,1} x_n & = 0 \\ \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots \\ C_{0,1} x_0^{n-1} & + C_{1,1} x_1^{n-1} & + \ldots & + C_{n,1} x_n^{n-1} & = 0. \end{array} \]

We have

\[ \frac{C_{01}}{V(x_1, x_2, \ldots, x_n)} = \frac{C_{11}}{-V(x_0, x_2, \ldots, x_n)} = \ldots = \frac{C_{n1}}{(-1)^n V(x_0, x_1, \ldots, x_{n-1})} = H_1, \]

where \(H_1\) is a factor that will be determined later. From these equations we deduce

(4.2.50)
\[ C_{i1} = (-1)^i H_1 V(x_0, x_1, \ldots, x_{i-1}, x_{i+1} \ldots x_n) \quad \text{for } i = 0, 1, \ldots, n. \]

4.2.11. Let us suppose it has been proved that

(4.2.51)
\[ \begin{aligned} \varphi_{ij}(x, y) &= \left[C_{0,0}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0}\frac{(x - x_i)^{n-1}}{(n-1)!}\right]\frac{(y - y_0)^{n-1}}{(n-1)!} + \\ &+ \left[C_{0,1}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,1}\frac{(x - x_i)^{n-1}}{(n-1)!}\right]\frac{(y - y_1)^{n-1}}{(n-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,j}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,j}\frac{(x - x_i)^{n-1}}{(n-1)!}\right]\frac{(y - y_j)^{n-1}}{(n-1)!} \end{aligned} \]

for \(j = 1, 2, \ldots, k\) and \(i = 1, 2, \ldots, n-1\), where the coefficients \(C_{i,j}\) of this formula are given by the equations:

(4.2.52)
\[ C_{0,j} + C_{1,j} + \ldots + C_{n,j} = 0 \]

and

(4.2.53)
\[ C_{0,j}(x_n - x_0)^r + C_{1,j}(x_n - x_1)^r + \ldots + C_{n-1,j}(x_n - x_{n-1})^r = 0 \]

for \(j = 0, 1, \ldots, k\) and \(r = 1, 2, \ldots, n-1\). The system formed by these equations can also be written in the form:

(4.2.54)
\[ \begin{array}{lllll} C_{0,j} & + C_{1,j} & + \ldots & + C_{n,j} & = 0 \\ C_{0,j} x_0 & + C_{1,j} x_1 & + \ldots & + C_{n,j} x_n & = 0 \\ \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots \\ C_{0,j} x_0^{n-1} & + C_{1,j} x_1^{n-1} & + \ldots & + C_{n,j} x_n^{n-1} & = 0 \end{array} \]

and gives the following relations:

\[ \frac{C_{0,j}}{V(x_1, x_2, \ldots, x_n)} = \frac{C_{1,j}}{-V(x_0, x_2, \ldots, x_n)} = \ldots = \frac{C_{n,j}}{(-1)^n V(x_0, x_1, \ldots, x_{n-1})} = H_j, \]

where the coefficient \(H_j\) will be determined later on. It follows that

(4.2.55)
\[ C_{i,j} = (-1)^i H_j V(x_0, x_1, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n) \]

for \(i = 0, 1, \ldots, n\).

Formula (4.2.51) is true for \(j = 1\), since in this case it coincides with formula (4.2.37). Likewise, the system formed by equations (4.2.52) and (4.2.53) is true for \(j = 0, 1\), since in this case it coincides with equations (4.2.20), (4.2.21) and (4.2.47), (4.2.48).

We shall show further that formula (4.2.51) is valid for \(j = k + 1\) and that the coefficients \(C_{0,k+1}, C_{1,k+1}, \ldots, C_{n,k+1}\) are also given by equations (4.2.52), (4.2.53) for \(j = k + 1\).

4.2.12. In order to prove that formula (4.2.51) is valid for \(j = k + 1\), we must first integrate the partial differential equation

(4.2.56)
\[ \frac{\partial^{2n}\varphi_{1,k+1}}{\partial x^n \partial y^n} = 0 \]

with the boundary conditions

\[ \begin{gathered} \frac{\partial^{2(n-r)-1}(\varphi_{1,k+1} - \varphi_{1,k})}{\partial x^{n-r}\partial y^{n-r-1}}(x, y_{k+1}) = 0, \\ \frac{\partial^{2(n-r)-1}(\varphi_{1,k+1} - \varphi_{0,k+1})}{\partial x^{n-r-1}\partial y^{n-r}}(x_1, y) = 0, \\ \frac{\partial^{2(n-r-1)}(\varphi_{1,k+1} + \varphi_{0,k} - \varphi_{1,k} - \varphi_{0,k+1})}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_1, y_{k+1}) = \begin{cases} C_{1,k+1} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{gathered} \]

for \(r = 0, 1, \ldots, n-1\).

By formula (4.2.51), and for \(i = 1\) and \(j = k\), we have

\[ \begin{aligned} \varphi_{1,k}(x, y) &= \left[C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + C_{1,0}\frac{(x-x_1)^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,k}\frac{(x-x_0)^{n-1}}{(n-1)!} + C_{1,k}\frac{(x-x_1)^{n-1}}{(n-1)!}\right]\frac{(y-y_k)^{n-1}}{(n-1)!} \end{aligned} \]

and then, by formula (4.2.26), we have

\[ \varphi_{0,k}(x, y) = \frac{(x-x_0)^{n-1}}{(n-1)!}\left[C_{0,0}\frac{(y-y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,k}\frac{(y-y_k)^{n-1}}{(n-1)!}\right] \]

and

\[ \varphi_{0,k+1}(x, y) = \frac{(x-x_0)^{n-1}}{(n-1)!}\left[C_{0,0}\frac{(y-y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,k+1}\frac{(y-y_{k+1})^{n-1}}{(n-1)!}\right]. \]

Proceeding as in subsection 4.2.8, one shows that for \(r = 0\) we have

(4.2.58)
\[ \frac{\partial^{2(n-1)}\varphi_{1,k+1}}{\partial x^{n-1}\partial y^{n-1}}(x, y) = C_{0,0} + C_{1,0} + C_{0,1} + C_{1,1} + \ldots\ldots\ldots + C_{0,k+1} + C_{1,k+1} \]

Further, for \(r = 1\) we have

(4.2.59)
\[ \begin{aligned} \frac{\partial^{2(n-2)}\varphi_{1,k+1}}{\partial x^{n-2}\partial y^{n-2}}(x, y) &= [C_{0,0}(x-x_0) + C_{1,0}(x-x_1)](y-y_0) + \\ &+ [C_{0,1}(x-x_0) + C_{1,1}(x-x_1)](y-y_1) + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ [C_{0,k+1}(x-x_0) + C_{1,k+1}(x-x_1)](y-y_{k+1}) \end{aligned} \]

and, in general, for the index \(r\) we have

(4.2.60)
\[ \begin{aligned} \frac{\partial^{2(n-r)}\varphi_{1,k+1}}{\partial x^{n-r}\partial y^{n-r}}(x, y) &= \left[C_{0,0}\frac{(x-x_0)^{r-1}}{(r-1)!} + C_{1,0}\frac{(x-x_1)^{r-1}}{(r-1)!}\right]\frac{(y-y_0)^{r-1}}{(r-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,k+1}\frac{(x-x_0)^{r-1}}{(r-1)!} + C_{1,k+1}\frac{(x-x_1)^{r-1}}{(r-1)!}\right]\frac{(y-y_{k+1})^{r-1}}{(r-1)!}. \end{aligned} \]

This formula is valid for \(r = 1, 2, \ldots, n\) and therefore, for \(r = n\), we have

(4.2.61)
\[ \begin{aligned} \varphi_{1,k+1}(x, y) &= \left[C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + C_{1,0}\frac{(x-x_1)^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,k+1}\frac{(x-x_0)^{n-1}}{(n-1)!} + C_{1,k+1}\frac{(x-x_1)^{n-1}}{(n-1)!}\right]\frac{(y-y_{k+1})^{n-1}}{(n-1)!}. \end{aligned} \]

4.2.13. Let us suppose it has been proved that

(4.2.62)
\[ \begin{aligned} \varphi_{i,k+1}(x, y) &= \left[C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0}\frac{(x-x_i)^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!} + \\ &+ \ldots + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,k+1}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,k+1}\frac{(x-x_i)^{n-1}}{(n-1)!}\right]\frac{(y-y_{k+1})^{n-1}}{(n-1)!} \end{aligned} \]

which is true for \(i = 1\), since in this case formula (4.2.62) coincides with formula (4.2.61). We shall show that formula (4.2.62) is also valid when the index \(i\) is replaced by \(i + 1\).

To this end we shall integrate the partial differential equation

(4.2.63)
\[ \frac{\partial^{2n}\varphi_{i+1,k+1}}{\partial x^n \partial y^n} = 0 \]

with the boundary conditions (4.2.2) corresponding to the indices \(i + 1\), \(k + 1\), that is

(4.2.64)
\[ \begin{gathered} \frac{\partial^{2(n-r)-1}(\varphi_{i+1,k+1} - \varphi_{i+1,k})}{\partial x^{n-r}\partial y^{n-r-1}}(x, y_{k+1}) = 0, \\ \frac{\partial^{2(n-r)-1}(\varphi_{i+1,k+1} - \varphi_{i,k+1})}{\partial x^{n-r-1}\partial y^{n-r}}(x_{i+1}, y) = 0, \\ \frac{\partial^{2(n-r-1)}(\varphi_{i+1,k+1} + \varphi_{i,k} - \varphi_{i+1,k} - \varphi_{i,k+1})}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_{i+1}, y_{k+1}) = \begin{cases} C_{i+1,k+1} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{gathered} \]

for \(r = 0, 1, \ldots, n-1\).

We must take into account formula (4.2.51) corresponding to \(j = k\), that is

(4.2.65)
\[ \begin{aligned} \varphi_{i,k}(x, y) &= \left[C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0}\frac{(x-x_i)^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,k}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,k}\frac{(x-x_i)^{n-1}}{(n-1)!}\right]\frac{(y-y_k)^{n-1}}{(n-1)!} \end{aligned} \]

then the same formula, but with the index \(i\) replaced by \(i + 1\), that is

(4.2.66)
\[ \begin{aligned} \varphi_{i+1,k}(x, y) &= \left[C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{i+1,0}\frac{(x-x_{i+1})^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,k}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{i+1,k}\frac{(x-x_{i+1})^{n-1}}{(n-1)!}\right]\frac{(y-y_k)^{n-1}}{(n-1)!} \end{aligned} \]

and finally formula (4.2.62).

Proceeding as in subsection 4.2.8, one shows that for \(r = 0\) we have

(4.2.67)
\[ \frac{\partial^{2(n-1)}\varphi_{i+1,k+1}}{\partial x^{n-1}\partial y^{n-1}}(x, y) = C_{0,0} + \ldots + C_{i+1,0} + C_{0,1} + \ldots + C_{i+1,1} + \ldots\ldots\ldots\ldots + C_{0,k+1} + \ldots + C_{i+1,k+1}. \]

Further, for \(r = 1\) we have

(4.2.68)
\[ \begin{aligned} \frac{\partial^{2(n-2)}\varphi_{i+1,k+1}}{\partial x^{n-2}\partial y^{n-2}}(x, y) &= [C_{0,0}(x-x_0) + \ldots + C_{i+1,0}(x-x_{i+1})](y-y_0) + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ [C_{0,k+1}(x-x_0) + \ldots + C_{i+1,k+1}(x-x_{i+1})](y-y_{k+1}) \end{aligned} \]

and, in general, for the index \(r\), we have

(4.2.69)
\[ \begin{aligned} & \frac{\partial^{2(n-r)}\varphi_{i+1,k+1}}{\partial x^{n-r}\partial y^{n-r}}(x, y) = \left[C_{0,0}\frac{(x-x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,0}\frac{(x-x_{i+1})^{r-1}}{(r-1)!}\right]\frac{(y-y_0)^{r-1}}{(r-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,k+1}\frac{(x-x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,k+1}\frac{(x-x_{i+1})^{r-1}}{(r-1)!}\right]\frac{(y-y_{k+1})^{r-1}}{(r-1)!}. \end{aligned} \]

This formula is valid for \(r = 1, 2, \ldots, n\). For \(r = n\) we have

(4.2.70)
\[ \begin{aligned} \varphi_{i+1,k+1}(x, y) &= \left[C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{i+1,0}\frac{(x-x_{i+1})^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,k+1}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{i+1,k+1}\frac{(x-x_{i+1})^{n-1}}{(n-1)!}\right]\frac{(y-y_{k+1})^{n-1}}{(n-1)!} \end{aligned} \]

which proves that formula (4.2.62) is valid when the index \(i\) is replaced by \(i + 1\). Formula (4.2.62) is therefore valid for \(i = 1, 2, \ldots, n-1\).

4.2.14. It remains to write that conditions (4.2.2) are satisfied for \(\varphi_{i,k+1}\) when \(i = n\) and \(r = 0, 1, \ldots, n-1\). Taking into account convention (A), these conditions are:

(4.2.71)
\[ \frac{\partial^{2(n-r)-1}\varphi_{n-1,k+1}}{\partial x^{n-r-1}\partial y^{n-r}}(x_n, y) = 0 \]
(4.2.72)
\[ \frac{\partial^{2(n-r-1)}(\varphi_{n-1,k} - \varphi_{n-1,k+1})}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_n, y_{k+1}) = \begin{cases} C_{n,k+1} & \text{if } r = 0, \\ 0 & \text{if } r \neq 0. \end{cases} \]

Formula (4.2.62) for \(i = n-1\) becomes

(4.2.73)
\[ \begin{aligned} \varphi_{n-1,k+1}(x, y) &= \left[C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,k+1}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,k+1}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_{k+1})^{n-1}}{(n-1)!} \end{aligned} \]

while formula (4.2.51) for \(i = n-1\) and \(j = k\) is

(4.2.74)
\[ \begin{aligned} \varphi_{n-1,k}(x, y) &= \left[C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,k}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,k}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_k)^{n-1}}{(n-1)!}. \end{aligned} \]

Let us consider conditions (4.2.71) and (4.2.72) for \(r = 0\); they are

\[ \begin{gathered} \frac{\partial^{2n-1}\varphi_{n-1,k+1}}{\partial x^{n-1}\partial y^n}(x_n, y) = 0, \\ \frac{\partial^{2(n-1)}(\varphi_{n-1,k} - \varphi_{n-1,k+1})}{\partial x^{n-1}\partial y^{n-1}}(x_n, y_{k+1}) = C_{n,k+1}. \end{gathered} \]

The first condition is satisfied, \(\varphi_{n-1,k+1}(x_n, y)\) being a polynomial in \(y\) of degree \(n-1\). The second condition leads to the equation

(4.2.75)
\[ C_{0,k+1} + \ldots + C_{n-1,k+1} + C_{n,k+1} = 0. \]

Let us consider conditions (4.2.71) and (4.2.72) for \(r = 1, 2, \ldots, n-1\). For conditions (4.2.71) we have

\[ \begin{aligned} & \frac{\partial^{2(n-r)-1}\varphi_{n-1,k+1}}{\partial x^{n-r-1}\partial y^{n-r}}(x_n, y) = \left[C_{0,0}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,0}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_0)^{r-1}}{(r-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,k}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,k}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_k)^{r-1}}{(r-1)!} + \\ &+ \left[C_{0,k+1}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,k+1}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_{k+1})^{r-1}}{(r-1)!}. \end{aligned} \]

Equations (4.2.53) are satisfied for \(j = 0, 1, \ldots, k\) and \(r = 1, 2, \ldots, n-1\). The first \(k + 1\) brackets on the right-hand side are therefore zero. There remains

\[ \frac{\partial^{2(n-r)-1}\varphi_{n-1,k+1}}{\partial x^{n-r-1}\partial y^{n-r}}(x_n, y) = \left[C_{0,k+1}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,k+1}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_{k+1})^{r-1}}{(r-1)!} \]

and in order that conditions (4.2.71) be satisfied for \(r = 1, 2, \ldots, n-1\), we must take

(4.2.76)
\[ C_{0,k+1}(x_n - x_0)^r + \ldots + C_{n-1,k+1}(x_n - x_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n-1. \]

On the other hand, we have

\[ \frac{\partial^{2(n-r-1)}(\varphi_{n-1,k} - \varphi_{n-1,k+1})}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_n, y) = -\left[C_{0,k+1}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,k+1}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_{k+1})^r}{r!} \]

and, by equations (4.2.76), conditions (4.2.72) are satisfied for \(r = 1, 2, \ldots, n-1\).

We have thus proved that the system formed by equations (4.2.52) and (4.2.53) is also true for \(j = k + 1\); it is then true for \(j = 0, 1, \ldots, n-1\), and formulas (4.2.55) are valid for \(i = 0, 1, \ldots, n\) and \(j = 0, 1, \ldots, n-1\).

4.2.15. We must examine the boundary conditions for \(\varphi_{i,k}\) in the case when \(i = 0, 1, \ldots, n-1\) and \(k = n\). It was already shown in subsection 4.2.7, when problem \((P_{0,k})\) was treated, that the coefficients \(C_{0,0}, C_{0,1}, \ldots, C_{0,n}\) are given by the system of equations

(4.2.27)
\[ C_{0,0} + C_{0,1} + \ldots + C_{0,n} = 0 \]
(4.2.28)
\[ C_{0,0}(y_n - y_0)^r + \ldots + C_{0,n-1}(y_n - y_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n-1. \]

It remains to show that for \(i = 1, 2, \ldots, n-1\) and \(r = 1, 2, \ldots, n-1\) we have

(4.2.77)
\[ C_{i,0} + C_{i,1} + \ldots + C_{i,n} = 0, \]
(4.2.78)
\[ C_{i,0}(y_n - y_0)^r + C_{i,1}(y_n - y_1)^r + \ldots + C_{i,n-1}(y_n - y_{n-1})^r = 0. \]

To this end let us set \(k = n\) in conditions (4.2.2) and take into account convention (A). We shall have the conditions:

(4.2.79)
\[ \frac{\partial^{2(n-r)-1}\varphi_{i,n-1}}{\partial x^{n-r}\partial y^{n-r-1}}(x, y_n) = 0 \]

and

(4.2.80)
\[ \frac{\partial^{2(n-r-1)}(\varphi_{i-1,n-1} - \varphi_{i,n-1})}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_i, y_n) = \begin{cases} C_{i,n} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \]

for \(i = 1, 2, \ldots, n-1\) and \(r = 0, 1, \ldots, n-1\).

We may also write \(\varphi_{i,n-1}\), given by formula (4.2.65) for \(k = n-1\), in the form

(4.2.81)
\[ \begin{aligned} \varphi_{i,n-1}(x, y) &= \left[C_{0,0}\frac{(y-y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n-1}\frac{(y-y_{n-1})^{n-1}}{(n-1)!}\right]\frac{(x-x_0)^{n-1}}{(n-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{i,0}\frac{(y-y_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n-1}\frac{(y-y_{n-1})^{n-1}}{(n-1)!}\right]\frac{(x-x_i)^{n-1}}{(n-1)!} \end{aligned} \]

and we shall also consider the same formula when the index \(i\) is replaced by \(i-1\).

We first observe that condition (4.2.79) for \(r = 0\) is satisfied, since \(\varphi_{i,n-1}(x, y_n)\) is a polynomial of degree \(n-1\) in \(x\).

Then condition (4.2.80) for \(r = 0\) leads to the equation

(4.2.82)
\[ C_{i,0} + C_{i,1} + \ldots + C_{i,n} = 0. \]

Let us now examine conditions (4.2.79) and (4.2.80) for \(r = 1, 2, \ldots, n-1\). We have

(4.2.83)
\[ \begin{aligned} & \frac{\partial^{2(n-r)-1}\varphi_{i,n-1}}{\partial x^{n-r}\partial y^{n-r-1}}(x, y_n) = \left[C_{0,0}\frac{(y_n-y_0)^r}{r!} + \ldots + C_{0,n-1}\frac{(y_n-y_{n-1})^r}{r!}\right]\frac{(x-x_0)^{r-1}}{(r-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{i,0}\frac{(y_n-y_0)^r}{r!} + \ldots + C_{i,n-1}\frac{(y_n-y_{n-1})^r}{r!}\right]\frac{(x-x_i)^{r-1}}{(r-1)!}. \end{aligned} \]

For \(i = 1\), this formula reduces to:

(4.2.84)
\[ \frac{\partial^{2(n-r)-1}\varphi_{1,n-1}}{\partial x^{n-r}\partial y^{n-r-1}}(x, y_n) = \left[C_{1,0}\frac{(y_n-y_0)^r}{r!} + \ldots + C_{1,n-1}\frac{(y_n-y_{n-1})^r}{r!}\right]\frac{(x-x_1)^{r-1}}{(r-1)!} \]

since, by equations (4.2.28), the first large bracket on the right-hand side is zero for \(r = 1, 2, \ldots, n-1\).

In order that conditions (4.2.79) be satisfied when \(r = 1, 2, \ldots, n-1\), we must take

(4.2.85)
\[ C_{1,0}(y_n - y_0)^r + \ldots + C_{1,n-1}(y_n - y_{n-1})^r = 0. \]

It is shown in the same way that conditions (4.2.79) for \(i = 2, 3, \ldots, n-1\) and \(r = 1, 2, \ldots, n-1\) lead to equations (4.2.78).

On the other hand, we have

\[ \frac{\partial^{2(n-r-1)}(\varphi_{i-1,n-1} - \varphi_{i,n-1})}{\partial x^{n-r-1}\partial y^{n-r-1}}(x, y_n) = -\left[C_{i,0}\frac{(y_n-y_0)^r}{r!} + \ldots + C_{i,n-1}\frac{(y_n-y_{n-1})^r}{r!}\right]\frac{(x-x_i)^r}{r!} \]

and from equations (4.2.78) it follows that conditions (4.2.80) are satisfied for \(r = 1, 2, \ldots, n-1\).

Equations (4.2.77) and (4.2.78) lead to the system

(4.2.86)
\[ \begin{array}{lll} C_{i,0} & + \ldots + C_{i,n} & = 0 \\ C_{i,0} y_0 & + \ldots + C_{i,n} y_n & = 0 \\ \ldots\ldots & \ldots\ldots\ldots\ldots & \ldots \\ C_{i,0} y_0^{n-1} & + \ldots + C_{i,n} y_n^{n-1} & = 0 \end{array} \]

valid for \(i = 0, 1, \ldots, n-1\).

4.2.16. The function \(\varphi_{n-1,0}\) has been determined by formula (4.2.19):

(4.2.19)
\[ \varphi_{n-1,0}(x, y) = \left[C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!}, \]

where the constants \(C_{0,0}, C_{1,0}, \ldots, C_{n,0}\) are determined by the equations

(4.2.22)
\[ \begin{array}{llll} C_{0,0} & + C_{1,0} & + \ldots + C_{n,0} & = 0 \\ C_{0,0} x_0 & + C_{1,0} x_1 & + \ldots + C_{n,0} x_n & = 0 \\ \ldots\ldots & \ldots\ldots & \ldots\ldots\ldots\ldots & \ldots \\ C_{0,0} x_0^{n-1} & + C_{1,0} x_1^{n-1} & + \ldots + C_{n,0} x_n^{n-1} & = 0. \end{array} \]

The function \(\varphi_{n-1,0}\) can also be written in the form

(4.2.87)
\[ \varphi_{n-1,0}(x, y) = -C_{n,0}\frac{(x-x_n)^{n-1}}{(n-1)!}\,\frac{(y-y_0)^{n-1}}{(n-1)!}. \]

Indeed, we have

\[ \begin{aligned} & C_{0,0}(x-x_0)^{n-1} + \ldots + C_{n-1,0}(x-x_{n-1})^{n-1} = (C_{0,0} + \ldots + C_{n-1,0})x^{n-1} - \\ & \begin{array}{ll} - C_{n-1}^1(C_{0,0} x_0 & + \ldots + C_{n-1,0} x_{n-1})x^{n-2} + \\ + \ldots\ldots\ldots\ldots\ldots\ldots & \ldots\ldots\ldots\ldots\ldots\ldots + \\ + (-1)^{n-1} C_{n-1}^{n-1}(C_{0,0} x_0^{n-1} & + \ldots + C_{n-1,0} x_{n-1}^{n-1}). \end{array} \end{aligned} \]

Taking into account equations (4.2.22), the preceding formula becomes

\[ C_{0,0}(x-x_0)^{n-1} + \ldots + C_{n-1,0}(x-x_{n-1})^{n-1} = -C_{n,0}(x^{n-1} - C_{n-1}^1 x_n x^{n-2} + \ldots + (-1)^{n-1} C_{n-1}^{n-1} x_n^{n-1}), \]

which means that formula (4.2.87) is proved.

The function \(\varphi_{n-1,1}\) can also be written in the form

(4.2.88)
\[ \varphi_{n-1,1}(x, y) = -\frac{(x-x_n)^{n-1}}{(n-1)!}\left[C_{n,0}\frac{(y-y_0)^{n-1}}{(n-1)!} + C_{n,1}\frac{(y-y_1)^{n-1}}{(n-1)!}\right]. \]

Indeed, formula (4.2.37), for \(i = n-1\), is

\[ \begin{aligned} \varphi_{n-1,1}(x, y) &= \left[C_{0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!} + \\ &+ \left[C_{0,1}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,1}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_1)^{n-1}}{(n-1)!}. \end{aligned} \]

But since the constants \(C_{0,0}, C_{1,0}, \ldots, C_{n,0}\) and \(C_{0,1}, C_{1,1}, \ldots, C_{n,1}\) are connected by equations (4.2.21) and

(4.2.89)
\[ \begin{array}{llll} C_{0,1} & + C_{1,1} & + \ldots + C_{n,1} & = 0 \\ C_{0,1} x_0 & + C_{1,1} x_1 & + \ldots + C_{n,1} x_n & = 0 \\ \ldots\ldots & \ldots\ldots & \ldots\ldots\ldots\ldots & \ldots \\ C_{0,1} x_0^{n-1} & + C_{1,1} x_1^{n-1} & + \ldots + C_{n,1} x_n^{n-1} & = 0 \end{array} \]

one shows as above that

\[ \begin{aligned} C_{0,0}(x-x_0)^{n-1} + \ldots + C_{n-1,0}(x-x_{n-1})^{n-1} &= -C_{n,0}(x-x_n)^{n-1}, \\ C_{0,1}(x-x_0)^{n-1} + \ldots + C_{n-1,1}(x-x_{n-1})^{n-1} &= -C_{n,1}(x-x_n)^{n-1}, \end{aligned} \]

whence formula (4.2.88) follows.

In general, the function \(\varphi_{n-1,k}\) can be written in the form

(4.2.90)
\[ \varphi_{n-1,k}(x, y) = -\frac{(x-x_n)^{n-1}}{(n-1)!}\left[C_{n,0}\frac{(y-y_0)^{n-1}}{(n-1)!} + \ldots + C_{n,k}\frac{(y-y_k)^{n-1}}{(n-1)!}\right]. \]

For \(k = n-1\), we shall need the formula

(4.2.91)
\[ \varphi_{n-1,n-1}(x, y) = -\frac{(x-x_n)^{n-1}}{(n-1)!}\left[C_{n,0}\frac{(y-y_0)^{n-1}}{(n-1)!} + \ldots + C_{n,n-1}\frac{(y-y_{n-1})^{n-1}}{(n-1)!}\right]. \]

4.2.17. The function \(\varphi_{0,n-1}\) has been determined by formula (4.2.26), corresponding to \(k = n-1\),

(4.2.26)
\[ \varphi_{0,n-1}(x, y) = \frac{(x-x_0)^{n-1}}{(n-1)!}\left[C_{0,0}\frac{(y-y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n-1}\frac{(y-y_{n-1})^{n-1}}{(n-1)!}\right], \]

where the constants \(C_{0,0}\), \(C_{0,1}\), \(\ldots, C_{0,n}\) are determined by the equations

(4.2.29)
\[ \begin{array}{llll} C_{0,0} & + C_{0,1} & + \ldots + C_{0,n} & = 0 \\ C_{0,0} y_0 & + C_{0,1} y_1 & + \ldots + C_{0,n} y_n & = 0 \\ \ldots\ldots & \ldots\ldots & \ldots\ldots\ldots\ldots & \ldots \\ C_{0,0} y_0^{n-1} & + C_{0,1} y_1^{n-1} & + \ldots + C_{0,n} y_n^{n-1} & = 0. \end{array} \]

The function \(\varphi_{0,n-1}\) can also be written in the form

(4.2.92)
\[ \varphi_{0,n-1}(x, y) = -C_{0,n}\frac{(x-x_0)^{n-1}}{(n-1)!}\,\frac{(y-y_n)^{n-1}}{(n-1)!}. \]

Indeed, with the help of equations (4.2.29), one shows as in subsection 4.2.16 that

\[ C_{0,0}(y-y_0)^{n-1} + \ldots + C_{0,n-1}(y-y_{n-1})^{n-1} = -C_{0,n}(y-y_n)^{n-1} \]

and therefore we have formula (4.2.92).

The function \(\varphi_{i,n-1}\) can also be written in the form:

(4.2.93)
\[ \varphi_{i,n-1}(x, y) = -\left[C_{0,n}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n}\frac{(x-x_i)^{n-1}}{(n-1)!}\right]\frac{(y-y_n)^{n-1}}{(n-1)!}. \]

Indeed, one takes into account formula (4.2.65) for \(k = n-1\),

\[ \begin{aligned} \varphi_{i,n-1}(x, y) &= \left[C_{0,0}\frac{(y-y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n-1}\frac{(y-y_{n-1})^{n-1}}{(n-1)!}\right]\frac{(x-x_0)^{n-1}}{(n-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{i,0}\frac{(y-y_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n-1}\frac{(y-y_{n-1})^{n-1}}{(n-1)!}\right]\frac{(x-x_i)^{n-1}}{(n-1)!} \end{aligned} \]

and one shows as in subsection 4.2.16, with the help of the systems of equations (4.2.86) for \(i = 0, 1, \ldots, n-1\), that the large brackets on the right-hand side are equal to \(-C_{0,n}\frac{(y-y_n)^{n-1}}{(n-1)!}, \ldots, -C_{i,n}\frac{(y-y_n)^{n-1}}{(n-1)!}\). Formula (4.2.93) then follows immediately.

For \(i = n-1\), we shall need the formula

(4.2.94)
\[ \varphi_{n-1,n-1}(x, y) = -\left[C_{0,n}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,n}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_n)^{n-1}}{(n-1)!} \]

4.2.18. Let us now determine the constant \(C_{n,n}\) and show that the system of equations (4.2.54), which is valid for \(j = 0, 1, \ldots, n-1\), is also valid for \(j = n\), and that the system of equations (4.2.86), which is valid for \(i = 0, 1, \ldots, n-1\), is also valid for \(i = n\).

Let us write the boundary conditions (4.2.2) corresponding to \(i = n\), \(k = n\). Taking into account convention (A), we shall have the conditions

(4.2.95)
\[ \frac{\partial^{2(n-r-1)}\varphi_{n-1,n-1}}{\partial x^{n-r-1}\partial y^{n-r-1}}(x_n, y_n) = \begin{cases} C_{n,n} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \]

for \(r = 0, 1, \ldots, n-1\).

If we use formula (4.2.91), condition (4.2.95) for \(r = 0\) gives the equation

(4.2.96)
\[ C_{n,0} + C_{n,1} + \ldots + C_{n,n-1} + C_{n,n} = 0 \]

and if we use formula (4.2.94), condition (4.2.95) for \(r = 0\) gives the equation

(4.2.97)
\[ C_{0,n} + C_{1,n} + \ldots + C_{n-1,n} + C_{n,n} = 0. \]

For \(r = 1, 2, \ldots, n-1\), conditions (4.2.95) are satisfied, since by formula (4.2.91) or (4.2.94) we have

\[ \begin{aligned} \frac{\partial^{2(n-r-1)}\varphi_{n-1,n-1}}{\partial x^{n-r-1}\partial y^{n-r-1}}(x, y) &= -\frac{(x - x_n)^r}{r!}\left[C_{n,0}\frac{(y - y_0)^r}{r!} + \ldots + C_{n,n-1}\frac{(y - y_{n-1})^r}{r!}\right] = \\ &= -\frac{(y - y_n)^r}{r!}\left[C_{0,n}\frac{(x - x_0)^r}{r!} + \ldots + C_{n-1,n}\frac{(x - x_{n-1})^r}{r!}\right] \end{aligned} \]

and for \(x = x_n\) and \(y = y_n\) the right-hand side is zero for \(r = 1, 2, \ldots, n-1\).

Let us now consider conditions (4.2.2) for \(i = n\), \(k = n-1\) and then for \(i = n-1\), \(k = n\). From these conditions we take only

(4.2.98)
\[ \frac{\partial^{2(n-r)-1}\varphi_{n-1,n-1}}{\partial x^{n-r-1}\partial y^{n-r}}(x_n, y) = 0 \]
(4.2.99)
\[ \frac{\partial^{2(n-r)-1}\varphi_{n-1,n-1}}{\partial x^{n-r}\partial y^{n-r-1}}(x, y_n) = 0 \qquad \text{for } r = 0, 1, \ldots, n-1. \]

For \(r = 0\) these conditions are satisfied, so that we may consider them only for \(r = 1, 2, \ldots, n-1\).

Using formula (4.2.91) we have

\[ \begin{gathered} \frac{\partial^{2(n-r)-1}\varphi_{n-1,n-1}}{\partial x^{n-r}\partial y^{n-r-1}}(x, y_n) = \\ = -\frac{(x - x_n)^{r-1}}{(r-1)!}\left[C_{n,0}\frac{(y_n - y_0)^r}{r!} + \ldots + C_{n,n-1}\frac{(y_n - y_{n-1})^r}{r!}\right]. \end{gathered} \]

In order that conditions (4.2.99) be satisfied, we must take

(4.2.100)
\[ C_{n,0}(y_n - y_0)^r + \ldots + C_{n,n-1}(y_n - y_{n-1})^r = 0 \qquad \text{for } r = 1, 2, \ldots, n-1. \]

Using formula (4.2.94) we shall have

\[ \frac{\partial^{2(n-r)-1}\varphi_{n-1,n-1}}{\partial x^{n-r-1}\partial y^{n-r}}(x_n, y) = -\left[C_{0,n}\frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n}\frac{(x_n - x_{n-1})^r}{r!}\right]\frac{(y - y_n)^{r-1}}{(r-1)!}. \]

In order that conditions (4.2.98) be satisfied, we must take

(4.2.101)
\[ C_{0,n}(x_n - x_0)^r + \ldots + C_{n-1,n}(x_n - x_{n-1})^r = 0 \qquad \text{for } r = 1, 2, \ldots, n-1. \]

Thus the constants \(C_{n,0}, C_{n,1}, \ldots, C_{n,n}\) are determined by the system formed by equations (4.2.96) and (4.2.100), that is, by the system

(4.2.102)
\[ \begin{array}{lllll} C_{n,0} & + C_{n,1} & + \ldots & + C_{n,n} & = 0 \\ C_{n,0} y_0 & + C_{n,1} y_1 & + \ldots & + C_{n,n} y_n & = 0 \\ \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots \\ C_{n,0} y_0^{n-1} & + C_{n,1} y_1^{n-1} & + \ldots & + C_{n,n} y_n^{n-1} & = 0 \end{array} \]

and the constants \(C_{0,n}, C_{1,n}, \ldots, C_{n,n}\) are determined by the system formed by equations (4.2.97) and (4.2.101), that is, by the system

(4.2.103)
\[ \begin{array}{lllll} C_{0,n} & + C_{1,n} & + \ldots & + C_{n,n} & = 0 \\ C_{0,n} x_0 & + C_{1,n} x_1 & + \ldots & + C_{n,n} x_n & = 0 \\ \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots \\ C_{0,n} x_0^{n-1} & + C_{1,n} x_1^{n-1} & + \ldots & + C_{n,n} x_n^{n-1} & = 0. \end{array} \]

Hence the system of equations (4.2.54) is also valid for \(j = n\), and the system of equations (4.2.86) is also valid for \(i = n\).

A consequence of this fact is that the function \(\varphi_{n-1,n-1}\) can also be written in the form

(4.2.104)
\[ \varphi_{n-1,n-1}(x, y) = C_{n,n}\frac{(x - x_n)^{n-1}}{(n-1)!}\frac{(y - y_n)^{n-1}}{(n-1)!}. \]

Indeed, let us consider formula (4.2.91), which gives the function \(\varphi_{n-1,n-1}\). One shows as in subsection 4.2.16 that, by equations (4.2.103), we have

\[ C_{0,n}(x - x_0)^{n-1} + C_{1,n}(x - x_1)^{n-1} + \ldots + C_{n-1,n}(x - x_{n-1})^{n-1} = -C_{n,n}(x - x_n)^{n-1} \]

and therefore we have formula (4.2.104).

4.2.19. To sum up, we have on the one hand the system of equations

(4.2.105)
\[ \begin{array}{lllll} C_{0,k} & + C_{1,k} & + \ldots & + C_{n,k} & = 0 \\ C_{0,k} x_0 & + C_{1,k} x_1 & + \ldots & + C_{n,k} x_n & = 0 \\ \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots \\ C_{0,k} x_0^{n-1} & + C_{1,k} x_1^{n-1} & + \ldots & + C_{n,k} x_n^{n-1} & = 0 \end{array} \]

which is satisfied by the constants \(C_{0,k}, C_{1,k}, \ldots, C_{n,k}\), and this for \(k = 0, 1, \ldots, n\), and on the other hand the system of equations

(4.2.106)
\[ \begin{array}{lllll} C_{i,0} & + C_{i,1} & + \ldots & + C_{i,n} & = 0 \\ C_{i,0} y_0 & + C_{i,1} y_1 & + \ldots & + C_{i,n} y_n & = 0 \\ \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots \\ C_{i,0} y_0^{n-1} & + C_{i,1} y_1^{n-1} & + \ldots & + C_{i,n} y_n^{n-1} & = 0 \end{array} \]

which is satisfied by the constants \(C_{i,0}, C_{i,1}, \ldots, C_{i,n}\), and this for \(i = 0, 1, \ldots, n\).

Equations (4.2.105) show that

\[ \begin{gathered} \frac{C_{0k}}{V(x_1, x_2, \ldots, x_n)} = \ldots = \frac{C_{ik}}{(-1)^i V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)} = \ldots = \\ = \frac{C_{nk}}{(-1)^n V(x_0, x_1, \ldots, x_{n-1})} = H_k \end{gathered} \]

and therefore

(4.2.107)
\[ C_{i,k} = (-1)^i H_k V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n) \quad \text{for } i, k = 0, 1, \ldots, n \]

where the \(H_k\) are constants.

Replacing in equations (4.2.106) the constants \(C_{ik}\) by formulas (4.2.107) for \(k = 0, 1, \ldots, n\), the index \(i\) being fixed, we obtain the equations

(4.2.108)
\[ \begin{array}{lllll} H_0 & + H_1 & + \ldots & + H_n & = 0 \\ H_0 y_0 & + H_1 y_1 & + \ldots & + H_n y_n & = 0 \\ \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots\ldots & \ldots \\ H_0 y_0^{n-1} & + H_1 y_1^{n-1} & + \ldots & + H_n y_n^{n-1} & = 0 \end{array} \]

which give

\[ \begin{gathered} \frac{H_0}{V(y_1, y_2, \ldots, y_n)} = \ldots = \frac{H_k}{(-1)^k V(y_0, \ldots, y_{k-1}, y_{k+1}, \ldots, y_n)} = \ldots = \\ = \frac{H_n}{(-1)^n V(y_0, y_1, \ldots, y_{n-1})} = H, \end{gathered} \]

where \(H\) is a constant which we shall determine by condition (4.2.3).

The preceding equations show that

(4.2.109)
\[ H_k = (-1)^k H V(y_0, \ldots, y_{k-1}, y_{k+1}, \ldots, y_n) \]

and therefore

(4.2.110)
\[ C_{ik} = (-1)^{i+k} H V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n) V(y_0, \ldots, y_{k-1}, y_{k+1}, \ldots, y_n). \]

4.2.20. Replacing, in the expression of \(\mathscr{P}[f]\) given by formula (4.1.12), the functions \(\varphi_{i,k}\) by the solution of the boundary value problem, we have

(4.2.111)
\[ \mathscr{P}[f] = \sum_{i=0}^{n} \sum_{k=0}^{n} C_{ik} f(x_i, y_k) \]

and, using formulas (4.2.110), we can write

(4.2.112)
\[ \mathscr{P}[f] = H \sum_{i=0}^{n} \sum_{k=0}^{n} (-1)^{i+k} V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n) V(y_0, \ldots, y_{k-1}, y_{k+1}, \ldots, y_n) f(x_i, y_k). \]

Condition (4.2.3) requires that

(4.2.3)
\[ \mathscr{P}[x^n y^n] = 1. \]

Replacing in formula (4.2.112) the function \(f(x, y)\) by \(f(x, y) = x^n y^n\), we shall have the equation

(4.2.113)
\[ 1 = H \sum_{i=0}^{n} (-1)^i V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n) x_i^n \cdot \sum_{k=0}^{n} (-1)^k V(y_0, \ldots, y_{k-1}, y_{k+1}, \ldots, y_n) y_k^n \]

which determines the constant \(H\).

However,

\[ \begin{aligned} & \sum_{i=0}^{n} (-1)^i V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n) x_i^n = (-1)^n V(x_0, x_1, \ldots, x_n) \\ & \sum_{k=0}^{n} (-1)^k V(y_0, \ldots, y_{k-1}, y_{k+1}, \ldots, y_n) y_k^n = (-1)^n V(y_0, y_1, \ldots, y_n) \end{aligned} \]

so that equation (4.2.113) becomes \(1 = H V(x_0, x_1, \ldots, x_n) V(y_0, y_1, \ldots, y_n)\) and therefore

(4.2.114)
\[ H = \frac{1}{V(x_0, x_1, \ldots, x_n)} \cdot \frac{1}{V(y_0, y_1, \ldots, y_n)}. \]

Formulas (4.2.110) then give

(4.2.115)
\[ C_{ik} = (-1)^{i+k} \frac{V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)}{V(x_0, x_1, \ldots, x_n)} \frac{V(y_0, \ldots, y_{k-1}, y_{k+1}, \ldots, y_n)}{V(y_0, y_1, \ldots, y_n)} \]

for \(i, k = 0, 1, \ldots, n\).

The constants \(C_{i,k}\) having been determined, the boundary value problem is completely solved.

§ 4.3. The divided difference of order \(n\) of the function \(f\) on a grid of nodes \(M_{i,k}\), \((i, k = 0, 1, \ldots, n)\) and its integral representation

4.3.1. When in formula (4.1.12) the functions \(\varphi_{i,k}\) are replaced by the solution of the boundary value problem, the functional \(\mathscr{P}[f]\) becomes

(4.3.1)
\[ \mathscr{P}[f] = \sum_{i=0}^{n} \sum_{k=0}^{n} C_{i,k} f(x_i, y_k), \]

where the coefficients \(C_{i,k}\) are given by formulas (4.2.115):

(4.3.2)
\[ C_{ik} = (-1)^{i+k} \frac{V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)}{V(x_0, x_1, \ldots, x_n)} \cdot \frac{V(y_0, \ldots, y_{k-1}, y_{k+1}, \ldots, y_n)}{V(y_0, y_1, \ldots, y_n)} \]

for \(i, k = 0, 1, \ldots, n\).

Definition 4.3.1. The expression \(\mathscr{P}[f]\), given by formula (4.3.1), is called the divided difference of order \(n\) of the function \(f\) on the grid \(M_{ik}\), \((i, k = 0, 1, 2, \ldots, n)\), and will be denoted by

(4.3.3)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right]. \]

Theorem 4.3.1. The divided difference of order \(n\) of the function \(f\) on the grid \(M_{i,k}\) is given by the formula

(4.3.4)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right] = \sum_{i=0}^{n} \sum_{k=0}^{n} C_{ik} f(x_i, y_k), \]

where the coefficients \(C_{i,k}\) are given by formulas (4.3.2).

Formula (4.3.4) is identical with formula (4.3.1).

Theorem 4.3.2. If the function \(f\) is continuous on the rectangle \(D\) defined by:

\[ D: \qquad x_0 \leq x \leq x_n, \quad y_0 \leq y \leq y_n, \]

together with its partial derivatives

(4.3.5)
\[ \frac{\partial^{2p-1} f}{\partial x^p \partial y^{p-1}}, \quad \frac{\partial^{2p-1} f}{\partial x^{p-1} \partial y^p}, \quad \frac{\partial^{2p} f}{\partial x^p \partial y^p} \quad \text{for } p = 1, 2, \ldots, n \]

and if the nodes \(M_{i,k}(x_i, y_k)\) \((i, k = 0, 1, \ldots, n)\) are such that

\[ x_0 \lt x_1 \lt \ldots \lt x_n, \quad y_0 \lt y_1 \lt \ldots \lt y_n, \]

then the divided difference of order \(n\) of the function \(f\) on the grid \(M_{i,k}\), \((i, k = 0, 1, \ldots, n)\), has an integral representation given by the formula

(4.3.6)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right] = \iint_D \varphi \frac{\partial^{2n} f}{\partial x^n \partial y^n}\, dx\, dy, \]

where the function \(\varphi\) is the solution of the boundary value problem treated in § 4.2.

The proof of this theorem is very simple. It suffices to replace in formula (4.1.9) the functions \(\varphi_{i,k}\) by the solution of the boundary value problem treated in § 4.2, and we shall have

\[ \mathscr{P}[f] = \sum_{i=0}^{n} \sum_{k=0}^{n} \int_{x_i}^{x_{i+1}} \int_{y_k}^{y_{k+1}} \varphi_{ik} \frac{\partial^{2n} f}{\partial x^n \partial y^n}\, dx\, dy \]

which means that we have the integral representation (4.3.6), where the function \(\varphi\) coincides on each rectangle \(D_{ik}\) with the function \(\varphi_{i,k}\).

4.3.3. Connection between the divided difference of a function of two variables and the divided differences of functions of one variable.

It is known that if one considers the divided difference of the function \(u\) on the nodes \(x_0, x_1, \ldots, x_n\), then we have

(4.3.7)
\[ [x_0, x_1, \ldots, x_n; u] = \lambda_0 u(x_0) + \lambda_1 u(x_1) + \ldots + \lambda_n u(x_n) \]

where

(4.3.8)
\[ \lambda_i = (-1)^{n+i} \frac{V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)}{V(x_0, x_1, \ldots, x_n)} \quad \text{for } i = 0, 1, \ldots, n \]

and likewise, if one considers the divided difference of the function \(v\) on the nodes \(y_0, y_1, \ldots, y_n\), then we have

(4.3.9)
\[ [y_0, y_1, \ldots, y_n; v] = \mu_0 v(y_0) + \mu_1 v(y_1) + \ldots + \mu_n v(y_n) \]

where

(4.3.10)
\[ \mu_k = (-1)^{n+k} \frac{V(y_0, \ldots, y_{k-1}, y_{k+1}, \ldots, y_n)}{V(y_0, y_1, \ldots, y_n)} \quad \text{for } k = 0, 1, \ldots, n. \]

Theorem 4.3.3. The coefficients \(C_{i,k}\) of the divided difference of the function \(f\) on the grid \(M_{i,k}\), \((i, k = 0, 1, \ldots, n)\), are connected with the coefficients \(\lambda_i\) and \(\mu_k\) of the divided differences of the functions \(u\) and \(v\) on the nodes \(x_0, x_1, \ldots, x_n\) and \(y_0, y_1, \ldots, y_n\) by the relation

(4.3.11)
\[ C_{i,k} = \lambda_i \mu_k, \quad \text{for } i, k = 0, 1, \ldots, n. \]

To prove this theorem it suffices to take into account formulas (4.3.8), (4.3.10) and (4.3.2).

Returning to formula (4.3.4) and replacing the coefficients \(C_{i,k}\) by the product \(\lambda_i \mu_k\), we can write

\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right] = \sum_{i=0}^{n} \lambda_i \sum_{k=0}^{n} \mu_k f(x_i, y_k). \]

Taking into account formulas (4.3.9) and (4.3.7), we shall have

\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right] = \sum_{i=0}^{n} \lambda_i [y_0, y_1, \ldots, y_n; f(x_i, y)] \]

that is

(4.3.12)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right] = [x_0, x_1, \ldots, x_n; [y_0, y_1, \ldots, y_n; f(x, y)]]. \]

This is the formula which T. Popoviciu [31] took a priori as the definition of the divided difference of a function of two variables.

It is evident that one can also write

(4.3.13)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right] = [y_0, y_1, \ldots, y_n; [x_0, x_1, \ldots, x_n; f(x, y)]]. \]

4.3.4. If \(u \in C^n[x_0, x_n]\), the divided difference of order \(n\) of the function \(u\) on the nodes \(x_0, x_1, \ldots, x_n\), given by formula (4.3.7), has an integral representation

(4.3.14)
\[ [x_0, x_1, \ldots, x_n; u] = \int_{x_0}^{x_n} \psi(s)\, u^{(n)}(s)\, ds, \]

where \(\psi\) is the spline function:

(4.3.15)
\[ \psi(s) = \lambda_0 \frac{(s - x_0)^{n-1}}{(n-1)!} + \lambda_1 \frac{(s - x_1)^{n-1}}{(n-1)!} + \ldots + \lambda_n \frac{(s - x_n)^{n-1}}{(n-1)!} \]

which coincides on the intervals \([x_0, x_1], [x_1, x_2], \ldots, [x_{n-1}, x_n]\) with the polynomials

(4.3.16)
\[ \begin{aligned} \psi_0(s) &= \lambda_0 \frac{(s - x_0)^{n-1}}{(n-1)!}, \\ \psi_1(s) &= \lambda_0 \frac{(s - x_0)^{n-1}}{(n-1)!} + \lambda_1 \frac{(s - x_1)^{n-1}}{(n-1)!}, \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ \psi_i(s) &= \lambda_0 \frac{(s - x_0)^{n-1}}{(n-1)!} + \lambda_1 \frac{(s - x_1)^{n-1}}{(n-1)!} + \ldots + \lambda_i \frac{(s - x_i)^{n-1}}{(n-1)!}, \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ \psi_{n-1}(s) &= \lambda_0 \frac{(s - x_0)^{n-1}}{(n-1)!} + \lambda_1 \frac{(s - x_1)^{n-1}}{(n-1)!} + \ldots + \lambda_{n-1} \frac{(s - x_{n-1})^{n-1}}{(n-1)!}. \end{aligned} \]

Likewise, if \(v \in C^n[y_0, y_n]\), the divided difference of order \(n\) of the function \(v\) on the nodes \(y_0, y_1, \ldots, y_n\), given by formula (4.3.9), has an integral representation

(4.3.17)
\[ [y_0, y_1, \ldots, y_n; v] = \int_{y_0}^{y_n} \theta(t)\, v^{(n)}(t)\, dt, \]

where \(\theta\) is the spline function

(4.3.18)
\[ \theta(t) = \mu_0 \frac{(t - y_0)^{n-1}}{(n-1)!} + \mu_1 \frac{(t - y_1)^{n-1}}{(n-1)!} + \ldots + \mu_n \frac{(t - y_n)^{n-1}}{(n-1)!} \]

which coincides on the intervals \([y_0, y_1], [y_1, y_2], \ldots, [y_{n-1}, y_n]\) with the polynomials

(4.3.19)
\[ \begin{aligned} \theta_0(t) &= \mu_0 \frac{(t - y_0)^{n-1}}{(n-1)!}, \\ \theta_1(t) &= \mu_0 \frac{(t - y_0)^{n-1}}{(n-1)!} + \mu_1 \frac{(t - y_1)^{n-1}}{(n-1)!}, \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ \theta_k(t) &= \mu_0 \frac{(t - y_0)^{n-1}}{(n-1)!} + \mu_1 \frac{(t - y_1)^{n-1}}{(n-1)!} + \ldots + \mu_k \frac{(t - y_k)^{n-1}}{(n-1)!}, \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ \theta_{n-1}(t) &= \mu_0 \frac{(t - y_0)^{n-1}}{(n-1)!} + \mu_1 \frac{(t - y_1)^{n-1}}{(n-1)!} + \ldots + \mu_{n-1} \frac{(t - y_{n-1})^{n-1}}{(n-1)!}. \end{aligned} \]

In the integral representation (4.3.6) the function \(\varphi\) coincides on each rectangle \(D_{i,k}\) with the function \(\varphi_{i,k}\) given by formula (4.2.65)

(4.2.65)
\[ \begin{aligned} \varphi_{ik}(x, y) = {} & \left[C_{0,0}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0}\frac{(x - x_i)^{n-1}}{(n-1)!}\right]\frac{(y - y_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & + \left[C_{0,k}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,k}\frac{(x - x_i)^{n-1}}{(n-1)!}\right]\frac{(y - y_k)^{n-1}}{(n-1)!}. \end{aligned} \]

Replacing in this formula the constants \(C_{i,k}\) by formulas (4.3.11), for \(i = 0, 1, \ldots, i\) and \(k = 0, 1, \ldots, k\), the preceding formula can be written in the form

\[ \varphi_{i,k}(x, y) = {} \biggl[\lambda_0 \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + \lambda_i \frac{(x - x_i)^{n-1}}{(n-1)!}\biggr] \biggl[\mu_0 \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + \mu_k \frac{(y - y_k)^{n-1}}{(n-1)!}\biggr]. \]

Taking into account formulas (4.3.16) and (4.3.19), we can write the preceding formula in the form

(4.3.20)
\[ \varphi_{i,k}(x, y) = \psi_i(x)\, \theta_k(y) \]

and therefore we have the following theorem:

Theorem 4.3.4. The function \(\varphi\) in the integral representation (4.3.6) is the product of the spline functions \(\psi\) and \(\theta\) from the integral representations (4.3.14) and (4.3.17), that is

(4.3.21)
\[ \varphi(x, y) = \psi(x)\, \theta(y). \]

Indeed, it suffices to observe that this formula is true on each rectangle \(D_{i,k}\), as formula (4.3.20) shows.

4.3.5. Theorem 4.3.5. The function \(\varphi\) in the integral representation (4.3.6) of the divided difference of order \(n\) of the function \(f\) of two variables is positive on the open rectangle \(D\) and vanishes on the boundary of this rectangle.

Indeed, it has been shown that the spline functions \(\psi\) and \(\theta\) are positive, the first on the interval \((x_0, x_n)\), the second on the interval \((y_0, y_n)\). It then follows from formula (4.3.21) that the function \(\varphi\) is positive on the open rectangle \(D\) and vanishes on the boundary of this rectangle.

The function \(\varphi\) is an example of a spline function of two variables.

↑ Contents

Română

Chapter V

The divided difference of a function of three variables and its representation by a triple integral

D. V. Ionescu, Diferențe divizate [Divided Differences], Editura Academiei Republicii Socialiste România, Bucharest, 1978, pp. 169–292

In this chapter the method of the function \(\varphi\) is extended to functions of three variables, with the aim of arriving at the definition of the divided difference of order \(n\) of a function of three variables on a grid \(M_{i,j,k}\), \((i, j, k = 0, 1, \ldots, n)\), and at its representation by a triple integral. We shall again make this extension by means of a boundary value problem [20].

§ 5.1. The integration by parts formula for functions of three variables

In this section we shall establish, as in § 4.1, the integration by parts formula for the triple integral, and then the generalized integration by parts formula.

5.1.1. We recall here the integration by parts formula for the functions \(f\) and \(\varphi\), continuous on the interval \([x_1, x_2]\) together with their derivatives \(f'\) and \(\varphi'\). This formula is

(5.1.1)
\[ \int_{x_1}^{x_2} \varphi f'\, dx = \varphi f \Big|_{x_1}^{x_2} - \int_{x_1}^{x_2} \varphi' f\, dx. \]

Next we consider the functions \(f\) and \(\varphi\) of two variables \(x\) and \(y\), continuous together with their partial derivatives

(5.1.2)
\[ \begin{gathered} \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial^2 f}{\partial x \partial y} \\ \frac{\partial \varphi}{\partial x}, \frac{\partial \varphi}{\partial y}, \frac{\partial^2 \varphi}{\partial x \partial y}, \end{gathered} \]

on a rectangle defined by the inequalities \(x_1 \leq x \leq x_2\), \(y_1 \leq y \leq y_2\).

For these functions we established in § 4.1 the integration by parts formula for double integrals:

(5.1.3)
\[ \int_{x_1}^{x_2} \int_{y_1}^{y_2} \varphi \frac{\partial^2 f}{\partial x \partial y}\, dx\, dy = {} \varphi(x, y) f(x, y) \Big|_{x_1, y_1}^{x_2, y_2} - \sum \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x}(x, y) f(x, y) \Bigg|_{y_1}^{y_2} dx + \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^2 \varphi}{\partial x \partial y} f\, dx\, dy. \]

The proof and the notation of this formula were given in § 4.1.

5.1.2. Theorem 5.1.1. If the functions \(f\) and \(\varphi\) of three variables \(x, y, z\) are continuous on the parallelepiped \(\Delta\) together with their partial derivatives:

(5.1.4)
\[ \begin{gathered} \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial f}{\partial z}, \frac{\partial^2 f}{\partial y \partial z}, \frac{\partial^2 f}{\partial z \partial x}, \frac{\partial^2 f}{\partial x \partial y}, \frac{\partial^3 f}{\partial x \partial y \partial z}, \\ \frac{\partial \varphi}{\partial x}, \frac{\partial \varphi}{\partial y}, \frac{\partial \varphi}{\partial z}, \frac{\partial^2 \varphi}{\partial y \partial z}, \frac{\partial^2 \varphi}{\partial z \partial x}, \frac{\partial^2 \varphi}{\partial x \partial y}, \frac{\partial^3 \varphi}{\partial x \partial y \partial z}, \end{gathered} \]

where \(\Delta : x_1 \leq x \leq x_2,\ y_1 \leq y \leq y_2,\ z_1 \leq z \leq z_2\), we have the integration by parts formula for triple integrals:

(5.1.5)
\[ \begin{aligned} \int_{x_1}^{x_2} \int_{y_1}^{y_2} \int_{z_1}^{z_2} \varphi \frac{\partial^3 f}{\partial x \partial y \partial z}\, dx\, dy\, dz = {} & \varphi(x, y, z) f(x, y, z) \Big|_{x_1, y_1, z_1}^{x_2, y_2, z_2} - \\ & - \sum \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x}(x, y, z) f(x, y, z) \Bigg|_{y_1, z_1}^{y_2, z_2} dx + \\ & + \sum \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^2 \varphi}{\partial x \partial y}(x, y, z) f(x, y, z) \Bigg|_{z_1}^{z_2} dx\, dy - \\ & - \int_{x_1}^{x_2} \int_{y_1}^{y_2} \int_{z_1}^{z_2} \frac{\partial^3 \varphi}{\partial x \partial y \partial z} f\, dx\, dy\, dz. \end{aligned} \]

Indeed, by the integration by parts formula (5.1.1), we can write

\[ \begin{aligned} \int_{x_1}^{x_2} \int_{y_1}^{y_2} \int_{z_1}^{z_2} \varphi \frac{\partial^3 f}{\partial x \partial y \partial z}\, dx\, dy\, dz & = \int_{x_1}^{x_2} \int_{y_1}^{y_2} dx\, dy \int_{z_1}^{z_2} \varphi(x, y, z) \frac{\partial}{\partial z} \left( \frac{\partial^2 f}{\partial x \partial y} \right) dz = \\ & = \int_{x_1}^{x_2} \int_{y_1}^{y_2} \varphi(x, y, z_2) \frac{\partial^2 f}{\partial x \partial y}(x, y, z_2)\, dx\, dy - \\ & - \int_{x_1}^{x_2} \int_{y_1}^{y_2} \varphi(x, y, z_1) \frac{\partial^2 f}{\partial x \partial y}(x, y, z_1)\, dx\, dy - \int_{z_1}^{z_2} dz \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial \varphi}{\partial z} \frac{\partial^2 f}{\partial x \partial y}\, dx\, dy. \end{aligned} \]

Applying the integration by parts formula for double integrals (5.1.3) to the first two double integrals and to the double integral \(\int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial \varphi}{\partial z} \frac{\partial^2 f}{\partial x \partial y}\, dx\, dy\), we shall have

\[ \begin{aligned} & \int_{x_1}^{x_2} \int_{y_1}^{y_2} \int_{z_1}^{z_2} \varphi \frac{\partial^3 f}{\partial x \partial y \partial z}\, dx\, dy\, dz = \varphi(x, y, z_2) f(x, y, z_2) \Big|_{x_1, y_1}^{x_2, y_2} - \varphi(x, y, z_1) f(x, y, z_1) \Big|_{x_1, y_1}^{x_2, y_2} - \\ & - \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x}(x, y, z_2) f(x, y, z_2) \Big|_{y_1}^{y_2} dx + \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x}(x, y, z_1) f(x, y, z_1) \Big|_{y_1}^{y_2} dx - \\ & - \int_{y_1}^{y_2} \frac{\partial \varphi}{\partial y}(x, y, z_2) f(x, y, z_2) \Big|_{x_1}^{x_2} dy + \int_{y_1}^{y_2} \frac{\partial \varphi}{\partial y}(x, y, z_1) f(x, y, z_1) \Big|_{x_1}^{x_2} dy + \\ & + \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^2 \varphi}{\partial x \partial y}(x, y, z_2) f(x, y, z_2)\, dx\, dy - \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^2 \varphi}{\partial x \partial y}(x, y, z_1) f(x, y, z_1)\, dx\, dy - \\ & - \int_{z_1}^{z_2} \frac{\partial \varphi}{\partial z}(x, y, z) f(x, y, z) \Big|_{x_1, y_1}^{x_2, y_2} dz + \int_{x_1}^{x_2} \int_{z_1}^{z_2} \frac{\partial^2 \varphi}{\partial x \partial z}(x, y, z) f(x, y, z) \Bigg|_{y_1}^{y_2} dx\, dz + \\ & + \int_{y_1}^{y_2} \int_{z_1}^{z_2} \frac{\partial^2 \varphi}{\partial y \partial z}(x, y, z) f(x, y, z) \Bigg|_{x_1}^{x_2} dy\, dz - \int_{x_1}^{x_2} \int_{y_1}^{y_2} \int_{z_1}^{z_2} \frac{\partial^3 \varphi}{\partial x \partial y \partial z} f\, dx\, dy\, dz, \end{aligned} \]

that is

\[ \begin{aligned} & \int_{x_1}^{x_2} \int_{y_1}^{y_2} \int_{z_1}^{z_2} \varphi \frac{\partial^3 f}{\partial x \partial y \partial z}\, dx\, dy\, dz = \varphi(x, y, z) f(x, y, z) \Big|_{x_1, y_1, z_1}^{x_2, y_2, z_2} - \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x}(x, y, z) f(x, y, z) \Bigg|_{y_1, z_1}^{y_2, z_2} dx - \\ & - \int_{y_1}^{y_2} \frac{\partial \varphi}{\partial y}(x, y, z) f(x, y, z) \Bigg|_{x_1, z_1}^{x_2, z_2} dy - \int_{z_1}^{z_2} \frac{\partial \varphi}{\partial z}(x, y, z) f(x, y, z) \Bigg|_{x_1, y_1}^{x_2, y_2} dz + \\ & + \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^2 \varphi}{\partial x \partial y}(x, y, z) f(x, y, z) \Bigg|_{z_1}^{z_2} dx\, dy + \int_{x_1}^{x_2} \int_{z_1}^{z_2} \frac{\partial^2 \varphi}{\partial x \partial z}(x, y, z) f(x, y, z) \Bigg|_{y_1}^{y_2} dx\, dz + \\ & + \int_{y_1}^{y_2} \int_{z_1}^{z_2} \frac{\partial^2 \varphi}{\partial y \partial z}(x, y, z) f(x, y, z) \Bigg|_{x_1}^{x_2} dy\, dz - \int_{x_1}^{x_2} \int_{y_1}^{y_2} \int_{z_1}^{z_2} \frac{\partial^3 \varphi}{\partial x \partial y \partial z} f\, dx\, dy\, dz, \end{aligned} \]

which means that we have formula (5.1.5).

5.1.3. The method we have given for obtaining the integration by parts formula (5.1.5) for a triple integral extends to multiple integrals in general. We shall not, however, dwell on these extensions, and we pass to applications.

5.1.4. The generalized integration by parts formula for triple integrals. Let us suppose that the functions \(f\) and \(\varphi\) of three variables \(x, y, z\) are continuous on the parallelepiped \(\Delta\) together with the partial derivatives:

(5.1.6)
\[ \begin{gathered} \frac{\partial^{3p-2} f}{\partial x^{p} \partial y^{p-1} \partial z^{p-1}}, \frac{\partial^{3p-2} f}{\partial x^{p-1} \partial y^{p} \partial z^{p-1}}, \frac{\partial^{3p-2} f}{\partial x^{p-1} \partial y^{p-1} \partial z^{p}}, \\ \frac{\partial^{3p-1} f}{\partial x^{p-1} \partial y^{p} \partial z^{p}}, \frac{\partial^{3p-1} f}{\partial x^{p} \partial y^{p-1} \partial z^{p}}, \frac{\partial^{3p-1} f}{\partial x^{p} \partial y^{p} \partial z^{p-1}}, \\ \frac{\partial^{3p} f}{\partial x^{p} \partial y^{p} \partial z^{p}}, \frac{\partial^{3p-2} \varphi}{\partial x^{p} \partial y^{p-1} \partial z^{p-1}}, \frac{\partial^{3p-2} \varphi}{\partial x^{p-1} \partial y^{p} \partial z^{p-1}}, \\ \frac{\partial^{3p-2} \varphi}{\partial x^{p-1} \partial y^{p-1} \partial z^{p}}, \frac{\partial^{3p-1} \varphi}{\partial x^{p-1} \partial y^{p} \partial z^{p}}, \frac{\partial^{3p-1} \varphi}{\partial x^{p} \partial y^{p-1} \partial z^{p}}, \frac{\partial^{3p-1} \varphi}{\partial x^{p} \partial y^{p} \partial z^{p-1}}, \frac{\partial^{3p} \varphi}{\partial x^{p} \partial y^{p} \partial z^{p}} \end{gathered} \]

for \(p = 1, 2, \ldots, n\).

Under this hypothesis we may replace in formula (5.1.5) the partial derivative \(\dfrac{\partial^3 f}{\partial x \partial y \partial z}\) by \(\dfrac{\partial^{3n} f}{\partial x^n \partial y^n \partial z^n}\). We shall have

\[ \begin{aligned} & \int_{x_1}^{x_2} \int_{y_1}^{y_2} \int_{z_1}^{z_2} \varphi \frac{\partial^{3n} f}{\partial x^{n} \partial y^{n} \partial z^{n}}\, dx\, dy\, dz = \varphi(x, y, z) \frac{\partial^{3(n-1)} f}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}} \Bigg|_{x_1, y_1, z_1}^{x_2, y_2, z_2} - \\ & - \sum \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x}(x, y, z) \frac{\partial^{3(n-1)} f}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}}(x, y, z) \Bigg|_{y_1, z_1}^{y_2, z_2} dx + \\ & + \sum \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^2 \varphi}{\partial x \partial y}(x, y, z) \frac{\partial^{3(n-1)} f}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}}(x, y, z) \Bigg|_{z_1}^{z_2} dx\, dy - \\ & - \int_{x_1}^{x_2} \int_{y_1}^{y_2} \int_{z_1}^{z_2} \frac{\partial^3 \varphi}{\partial x \partial y \partial z} \cdot \frac{\partial^{3(n-1)} f}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}}\, dx\, dy\, dz. \end{aligned} \]

To the last integral one may again apply the integration by parts formula, replacing the function \(\varphi\) by \(\dfrac{\partial^3 \varphi}{\partial x \partial y \partial z}\) and the function \(\dfrac{\partial^3 f}{\partial x \partial y \partial z}\) by \(\dfrac{\partial^{3(n-1)} f}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}}\). Further, one may apply the integration by parts formula to the new triple integral, replacing the function \(\varphi\) by \(\dfrac{\partial^6 \varphi}{\partial x^2 \partial y^2 \partial z^2}\) and \(\dfrac{\partial^{3(n-2)} f}{\partial x^{n-2} \partial y^{n-2} \partial z^{n-2}}\), \(\ldots\), and so on.

One finally arrives at the generalized integration by parts formula for a triple integral

(5.1.7)
\[ \begin{aligned} \int_{x_1}^{x_2} \int_{y_1}^{y_2} \int_{z_1}^{z_2} \varphi \frac{\partial^{3n} f}{\partial x^{n} \partial y^{n} \partial z^{n}}\, dx\, dy\, dz = {} & \varphi(x, y, z) \frac{\partial^{3(n-1)} f}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}} \Bigg|_{x_1, y_1, z_1}^{x_2, y_2, z_2} - \\ & - \frac{\partial^3 \varphi}{\partial x \partial y \partial z} \frac{\partial^{3(n-2)} f}{\partial x^{n-2} \partial y^{n-2} \partial z^{n-2}} \Bigg|_{x_1, y_1, z_1}^{x_2, y_2, z_2} + \ldots \\ & + (-1)^{n-1} \frac{\partial^{3(n-1)} \varphi}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}}(x, y, z) f(x, y, z) \Bigg|_{x_1, y_1, z_1}^{x_2, y_2, z_2} - \\ & - \left[ \sum \int_{x_1}^{x_2} \frac{\partial \varphi}{\partial x}(x, y, z) \cdot \frac{\partial^{3(n-1)} f}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}}(x, y, z) \Bigg|_{y_1, z_1}^{y_2, z_2} dx - \right. \\ & - \sum \int_{x_1}^{x_2} \frac{\partial^{4} \varphi}{\partial x^{2} \partial y \partial z}(x, y, z) \frac{\partial^{3(n-2)} f}{\partial x^{n-2} \partial y^{n-2} \partial z^{n-2}}(x, y, z) \Bigg|_{y_1, z_1}^{y_2, z_2} dx + \\ & \left. + \ldots + (-1)^{n-1} \sum \int_{x_1}^{x_2} \frac{\partial^{3(n-1)+1} \varphi}{\partial x^{n} \partial y^{n-1} \partial z^{n-1}}(x, y, z) f(x, y, z) \Bigg|_{y_1, z_1}^{y_2, z_2} dx \right] + \\ & + \sum \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^2 \varphi}{\partial x \partial y}(x, y, z) \frac{\partial^{3(n-1)} f}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}}(x, y, z) \Bigg|_{z_1}^{z_2} dx\, dy - \\ & - \sum \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^{5} \varphi}{\partial x^{2} \partial y^{2} \partial z}(x, y, z) \frac{\partial^{3(n-2)} f}{\partial x^{n-2} \partial y^{n-2} \partial z^{n-2}}(x, y, z) \Bigg|_{z_1}^{z_2} dx\, dy + \ldots \\ & + (-1)^{n-1} \sum \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^{3(n-1)+2} \varphi}{\partial x^{n} \partial y^{n} \partial z^{n-1}}(x, y, z) f(x, y, z) \Bigg|_{z_1}^{z_2} dx\, dy + \\ & + (-1)^n \int_{x_1}^{x_2} \int_{y_1}^{y_2} \int_{z_1}^{z_2} \frac{\partial^{3n} \varphi}{\partial x^{n} \partial y^{n} \partial z^{n}} f\, dx\, dy\, dz. \end{aligned} \]

We have thus obtained:

Theorem 5.1.4. If the functions \(f\) and \(\varphi\) satisfy the conditions formulated at the beginning of subsection 5.1.4, we have formula (5.1.7), which is called the generalized integration by parts formula for a triple integral and which can also be written in the form

(5.1.8)
\[ \begin{aligned} & \int_{x_1}^{x_2} \int_{y_1}^{y_2} \int_{z_1}^{z_2} \varphi \frac{\partial^{3n} f}{\partial x^{n} \partial y^{n} \partial z^{n}}\, dx\, dy\, dz = \sum_{r=0}^{n-1} (-1)^{n-r-1} \frac{\partial^{3(n-r-1)} \varphi}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}}(x, y, z) \frac{\partial^{3r} f}{\partial x^{r} \partial y^{r} \partial z^{r}}(x, y, z) \Bigg|_{x_1, y_1, z_1}^{x_2, y_2, z_2} - \\ & - \sum_{r=0}^{n-1} (-1)^{n-r-1} \sum \int_{x_1}^{x_2} \frac{\partial^{3(n-r)-2} \varphi}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}}(x, y, z) \frac{\partial^{3r} f}{\partial x^{r} \partial y^{r} \partial z^{r}}(x, y, z) \Bigg|_{y_1, z_1}^{y_2, z_2} dx + \\ & + \sum_{r=0}^{n-1} (-1)^{n-r-1} \sum \int_{x_1}^{x_2} \int_{y_1}^{y_2} \frac{\partial^{3(n-r)-1} \varphi}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z) \frac{\partial^{3r} f}{\partial x^{r} \partial y^{r} \partial z^{r}}(x, y, z) \Bigg|_{z_1}^{z_2} dx\, dy + \\ & + (-1)^n \int_{x_1}^{x_2} \int_{y_1}^{y_2} \int_{z_1}^{z_2} \frac{\partial^{3n} \varphi}{\partial x^{n} \partial y^{n} \partial z^{n}} f\, dx\, dy\, dz. \end{aligned} \]

5.1.5. Let us consider the parallelepiped \(D\) defined by the inequalities

\[ D : \quad x_0 \leq x \leq x_n ; \ y_0 \leq y \leq y_n ; \ z_0 \leq z \leq z_n \]

and the grid of nodes \(M_{i,j,k}\), \((i, j, k = 0, 1, \ldots, n)\), with coordinates \((x_i, y_j, z_k)\), where

(5.1.9)
\[ \begin{gathered} x_0 \lt x_1 \lt \ldots \lt x_{n-1} \lt x_n ; \quad y_0 \lt y_1 \lt \ldots \lt y_{n-1} \lt y_n ; \\ z_0 \lt z_1 \lt \ldots \lt z_{n-1} \lt z_n. \end{gathered} \]

We shall denote by \(D_{i,j,k}\) the parallelepiped defined by the inequalities

\[ D_{i,j,k} : \quad x_i \leq x \leq x_{i+1} ; \ y_j \leq y \leq y_{j+1} ; \ z_k \leq z \leq z_{k+1}, \]

where \(i, j, k = 0, 1, \ldots, n-1\).

To each parallelepiped \(D_{i,j,k}\) we associate a function \(\varphi_{i,j,k}\), continuous on \(D_{i,j,k}\) together with its partial derivatives of the same orders as the partial derivatives appearing in the sequence (5.1.6). Likewise, to the parallelepiped \(D\) we associate a function \(f\), continuous on \(D\) together with its partial derivatives of the same orders as the partial derivatives appearing in the sequence (5.1.6). Then the generalized integration by parts formula for triple integrals (5.1.7) or (5.1.8) can be applied to each parallelepiped \(D_{i,j,k}\) and to the functions \(f, \varphi_{i,j,k}\). Adding all these formulas term by term, we shall have the formula

(5.1.10)
\[ \sum_{i,j,k=0}^{n-1} \iiint\limits_{D_{i,j,k}} \varphi_{i,j,k} \frac{\partial^{3n} f}{\partial x^{n} \partial y^{n} \partial z^{n}}\, dx\, dy\, dz = \mathscr{P}[f] + (-1)^n \sum_{i,j,k=0}^{n-1} \iiint\limits_{D_{i,j,k}} \frac{\partial^{3n} \varphi_{i,j,k}}{\partial x^{n} \partial y^{n} \partial z^{n}} f\, dx\, dy\, dz, \]

where we have denoted by \(\mathscr{P}[f]\) the functional

(5.1.11)
\[ \begin{aligned} \mathscr{P}[f] = {} & \sum_{i,j,k=0}^{n-1} \sum_{r=0}^{n-1} (-1)^{n-r-1} \frac{\partial^{3(n-r-1)} \varphi_{i,j,k}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}}(x, y, z) \frac{\partial^{3r} f}{\partial x^{r} \partial y^{r} \partial z^{r}}(x, y, z) \Bigg|_{x_i, y_j, z_k}^{x_{i+1}, y_{j+1}, z_{k+1}} - \\ & - \sum_{i,j,k=0}^{n-1} \sum_{r=0}^{n-1} (-1)^{n-r-1} \int_{x_i}^{x_{i+1}} \frac{\partial^{3(n-r)-2} \varphi_{i,j,k}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}}(x, y, z) \frac{\partial^{3r} f}{\partial x^{r} \partial y^{r} \partial z^{r}}(x, y, z) \Bigg|_{y_j, z_k}^{y_{j+1}, z_{k+1}} dx - \\ & - \sum_{i,j,k=0}^{n-1} \sum_{r=0}^{n-1} (-1)^{n-r-1} \int_{y_j}^{y_{j+1}} \frac{\partial^{3(n-r)-2} \varphi_{i,j,k}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z) \frac{\partial^{3r} f}{\partial x^{r} \partial y^{r} \partial z^{r}}(x, y, z) \Bigg|_{x_i, z_k}^{x_{i+1}, z_{k+1}} dy - \\ & - \sum_{i,j,k=0}^{n-1} \sum_{r=0}^{n-1} (-1)^{n-r-1} \int_{z_k}^{z_{k+1}} \frac{\partial^{3(n-r)-2} \varphi_{i,j,k}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}}(x, y, z) \frac{\partial^{3r} f}{\partial x^{r} \partial y^{r} \partial z^{r}}(x, y, z) \Bigg|_{x_i, y_j}^{x_{i+1}, y_{j+1}} dz + \\ & + \sum_{i,j,k=0}^{n-1} \sum_{r=0}^{n-1} (-1)^{n-r-1} \int_{y_j}^{y_{j+1}} \int_{z_k}^{z_{k+1}} \frac{\partial^{3(n-r)-1} \varphi_{i,j,k}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}}(x, y, z) \frac{\partial^{3r} f}{\partial x^{r} \partial y^{r} \partial z^{r}}(x, y, z) \Bigg|_{x_i}^{x_{i+1}} dy\, dz + \\ & + \sum_{i,j,k=0}^{n-1} \sum_{r=0}^{n-1} (-1)^{n-r-1} \int_{x_i}^{x_{i+1}} \int_{z_k}^{z_{k+1}} \frac{\partial^{3(n-r)-1} \varphi_{i,j,k}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}}(x, y, z) \frac{\partial^{3r} f}{\partial x^{r} \partial y^{r} \partial z^{r}}(x, y, z) \Bigg|_{y_j}^{y_{j+1}} dx\, dz + \\ & + \sum_{i,j,k=0}^{n-1} \sum_{r=0}^{n-1} (-1)^{n-r-1} \int_{x_i}^{x_{i+1}} \int_{y_j}^{y_{j+1}} \frac{\partial^{3(n-r)-1} \varphi_{i,j,k}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z) \frac{\partial^{3r} f}{\partial x^{r} \partial y^{r} \partial z^{r}}(x, y, z) \Bigg|_{z_k}^{z_{k+1}} dx\, dy. \end{aligned} \]

When the node \(M_{i,j,k}\) is in the interior of the parallelepiped \(D\), the coefficient of \(\dfrac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z_k)\) results from formula (5.1.8) applied to all the parallelepipeds \(D_{i,j,k}\) having one of their vertices at the point \(M_{i,j,k}\). These parallelepipeds are:

\[ \begin{gathered} D_{i,j,k} ; \quad D_{i-1,j-1,k} ; \quad D_{i,j-1,k} ; \quad D_{i-1,j,k} ; \\ D_{i,j,k-1} ; \quad D_{i-1,j-1,k-1} ; \quad D_{i,j-1,k-1} ; \quad D_{i-1,j,k-1} . \end{gathered} \]

Taking into account formula (5.1.8), the coefficient of \(\dfrac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z_k)\) in \(\mathscr{P}[f]\) is

(5.1.12)
\[ (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \Bigl[(\varphi_{i,j,k} + \varphi_{i-1,j-1,k} - \varphi_{i,j-1,k} - \varphi_{i-1,j,k}) - (\varphi_{i,j,k-1} + \varphi_{i-1,j-1,k-1} - \varphi_{i,j-1,k-1} - \varphi_{i-1,j,k-1})\Bigr]_{x_i, y_j, z_k}. \]

Let us consider the node \(M_{i,j,0}\) situated on one of the faces of the parallelepiped \(D\), which means that \(0 \lt i, j \lt n\) and \(k = 0\). Then there are four parallelepipeds \(D_{i,j,0}\); \(D_{i-1,j-1,0}\); \(D_{i,j-1,0}\); \(D_{i-1,j,0}\) having the node \(M_{i,j,0}\) as a vertex.

The coefficient of \(\dfrac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z_0)\) in \(\mathscr{P}[f]\) is

(5.1.13)
\[ (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,j,0} + \varphi_{i-1,j-1,0} - \varphi_{i,j-1,0} - \varphi_{i-1,j,0}]_{x_i, y_j, z_0}. \]

The coefficient of \(\dfrac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_0, z_k)\) in \(\mathscr{P}[f]\) is

(5.1.14)
\[ (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,0,k} + \varphi_{i-1,0,k-1} - \varphi_{i,0,k-1} - \varphi_{i-1,0,k}]_{x_i, y_0, z_k}. \]

The coefficient of \(\dfrac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_0, y_j, z_k)\) in \(\mathscr{P}[f]\) is

(5.1.15)
\[ (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{0,j,k} + \varphi_{0,j-1,k-1} - \varphi_{0,j,k-1} - \varphi_{0,j-1,k}]_{x_0, y_j, z_k}. \]

Formulas (5.1.13), (5.1.14), (5.1.15) are written for \(0 \lt i, j \lt n\); \(0 \lt i, k \lt n\); \(0 \lt j, k \lt n\).

Likewise, the coefficients of \(\dfrac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z_n)\), \(\dfrac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_n, z_k)\), \(\dfrac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_n, y_j, z_k)\) in \(\mathscr{P}[f]\) are

(5.1.16)
\[ (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i-1,j,n-1} + \varphi_{i,j-1,n-1} - \varphi_{i,j,n-1} - \varphi_{i-1,j-1,n-1}]_{x_i, y_j, z_n} \]
(5.1.17)
\[ (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,n-1,k-1} + \varphi_{i-1,n-1,k} - \varphi_{i,n-1,k} - \varphi_{i-1,n-1,k-1}]_{x_i, y_n, z_k} \]
(5.1.18)
\[ (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,j-1,k} + \varphi_{n-1,j,k-1} - \varphi_{n-1,j,k} - \varphi_{n-1,j-1,k-1}]_{x_n, y_j, z_k}. \]

Formulas (5.1.16), (5.1.17), (5.1.18) are written for \(0 \lt i, j \lt n\); \(0 \lt i, k \lt n\); \(0 \lt j, k \lt n\).

The coefficient (5.1.12) of \(\dfrac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z_k)\) was written for nodes interior to the parallelepiped \(D\), the indices \(i, j, k\) not taking the values 0 or \(n\). The coefficients (5.1.13)—(5.1.18) can be made to enter into the general coefficient by adopting:

Convention (A). The function \(\varphi_{i,j,k}\) is to be considered zero when at least one of the indices \(i, j, k\) is \(-1\) or \(n\).

Indeed, taking this convention into account, the coefficient (5.1.12) reduces to the coefficient (5.1.13) when \(k = 0\), and the coefficient (5.1.12) reduces to the coefficient (5.1.16) when \(k = n, \ldots\).

For the nodes

(5.1.19)
\[ \begin{array}{ll} M_{i,0,0} ; & M_{i,0,n} \\ M_{0,j,0} ; & M_{0,n,k} \\ M_{0,0,k} ; & M_{0,j,n} \\ M_{n,j,0} ; & M_{n,n,k} \\ M_{i,n,0} ; & M_{n,j,n} \\ M_{n,0,k} ; & M_{i,n,n} \end{array} \]

situated on the edges of the parallelepiped \(D\), the coefficients of \(\dfrac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}\) in \(\mathscr{P}[f]\) are the following:

(5.1.20)
\[ \begin{aligned} & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,0,0} - \varphi_{i-1,0,0}]_{x_i, y_0, z_0} ; \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i-1,0,n-1} - \varphi_{i,0,n-1}]_{x_i, y_0, z_n} \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{0,j,0} - \varphi_{0,j-1,0}]_{x_0, y_j, z_0} ; \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{0,n-1,k-1} - \varphi_{0,n-1,k}]_{x_0, y_n, z_k} \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{0,0,k} - \varphi_{0,0,k-1}]_{x_0, y_0, z_k} ; \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{0,j-1,n-1} - \varphi_{0,j,n-1}]_{x_0, y_j, z_n} \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,j-1,0} - \varphi_{n-1,j,0}]_{x_n, y_j, z_0} ; \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,n-1,k} - \varphi_{n-1,n-1,k-1}]_{x_n, y_n, z_k} \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i-1,n-1,0} - \varphi_{i,n-1,0}]_{x_i, y_n, z_0} ; \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,j,n-1} - \varphi_{n-1,j-1,n-1}]_{x_n, y_j, z_n} \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,0,k-1} - \varphi_{n-1,0,k}]_{x_n, y_0, z_k} ; \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,n-1,n-1} - \varphi_{i-1,n-1,n-1}]_{x_i, y_n, z_n}. \end{aligned} \]

By convention (A), the coefficients (5.1.20) are deduced from the general coefficient by setting \(j = 0, k = 0, \ldots, j = n, k = n\).

For the vertices of the parallelepiped \(D\):

(5.1.21)
\[ \begin{array}{ll} M_{0,0,0} ; & M_{0,0,n} \\ M_{n,0,0} ; & M_{n,0,n} \\ M_{0,n,0} ; & M_{0,n,n} \\ M_{n,n,0} ; & M_{n,n,n} , \end{array} \]

the coefficients of \(\dfrac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z_k)\) are:

(5.1.22)
\[ \begin{aligned} & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{0,0,0}]_{x_0, y_0, z_0} ; \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [-\varphi_{0,0,n-1}]_{x_0, y_0, z_n} \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [-\varphi_{n-1,0,0}]_{x_n, y_0, z_0} ; \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,0,n-1}]_{x_n, y_0, z_n} \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [-\varphi_{0,n-1,0}]_{x_0, y_n, z_0} ; \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{0,n-1,n-1}]_{x_0, y_n, z_n} \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,n-1,0}]_{x_n, y_n, z_0} ; \\ & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [-\varphi_{n-1,n-1,n-1}]_{x_n, y_n, z_n}. \end{aligned} \]

By convention (A), the coefficients (5.1.22) are deduced from the general coefficient by setting \(i = 0, j = 0, k = 0, \ldots, i = n, j = n, k = n\).

Hence, writing in \(\mathscr{P}[f]\) the general term

\[ \begin{aligned} & (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [(\varphi_{i,j,k} + \varphi_{i-1,j-1,k} - \varphi_{i,j-1,k} - \varphi_{i-1,j,k}) - \\ & - (\varphi_{i,j,k-1} + \varphi_{i-1,j-1,k-1} - \varphi_{i,j-1,k-1} - \varphi_{i-1,j,k-1})]_{x_i, y_j, z_k} \frac{\partial^{3r} f}{\partial x^{r} \partial y^{r} \partial z^{r}}(x_i, y_j, z_k) \end{aligned} \]

one obtains all the terms of this form by letting the indices \(i, j, k\) take the values from 0 to \(n\) and taking convention (A) into account.

5.1.6. The coefficient of \(\dfrac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z_k)\) under the integral sign \(\int_{x_i}^{x_{i+1}}\) in \(\mathscr{P}[f]\), when \(0 \lt j, k \lt n\), results from formula (5.1.8) applied to all the parallelepipeds \(D_{i,j,k}\) which have the edge \([x_i, x_{i+1}]\) in common; these parallelepipeds are:

(5.1.23)
\[ D_{i,j,k};\ D_{i,j-1,k-1};\ D_{i,j,k-1};\ D_{i,j-1,k}. \]

The contribution of these parallelepipeds to the coefficient of \(\dfrac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z_k)\) is

(5.1.24)
\[ \int_{x_i}^{x_{i+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,j-1,k-1} + \varphi_{i,j,k} - \varphi_{i,j,k-1} - \varphi_{i,j-1,k}]_{x, y_j, z_k} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_j, z_k)\, dx. \]

We shall say that (5.1.24) is the general term of this form.

If \(k = 0\) but \(0 \lt j \lt n\), the parallelepipeds \(D_{i,j,0}\), \(D_{i,j-1,0}\) have the edge \([x_i, x_{i+1}]\) in common, and in \(\mathscr{P}[f]\) we have:

(5.1.25)
\[ \int_{x_i}^{x_{i+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,j,0} - \varphi_{i,j-1,0}]_{x, y_j, z_0} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_j, z_0)\, dx. \]

If \(k = n\) but \(0 \lt j \lt n\), only the parallelepipeds \(D_{i,j-1,n-1}\), \(D_{i,j,n-1}\) have the edge \([x_i, x_{i+1}]\) in common, and in \(\mathscr{P}[f]\) we have:

(5.1.26)
\[ \int_{x_i}^{x_{i+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,j-1,n-1} - \varphi_{i,j,n-1}]_{x, y_j, z_n} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_j, z_n)\, dx. \]

Likewise, if \(j = 0\) or \(j = n\), but \(0 \lt k \lt n\), only the parallelepipeds \(D_{i,0,k-1}\), \(D_{i,0,k}\) or \(D_{i,n-1,k-1}\), \(D_{i,n-1,k}\) have the edge \([x_i, x_{i+1}]\) in common, and in \(\mathscr{P}[f]\) we have:

(5.1.27)
\[ \int_{x_i}^{x_{i+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,0,k} - \varphi_{i,0,k-1}]_{x, y_0, z_k} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_0, z_k)\, dx \]

or

(5.1.28)
\[ \int_{x_i}^{x_{i+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,n-1,k-1} - \varphi_{i,n-1,k}]_{x, y_n, z_k} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_n, z_k)\, dx. \]

Finally, if \(j = 0\), \(k = 0\), only the parallelepiped \(D_{i,0,0}\) has the edge \([x_i, x_{i+1}]\), and in \(\mathscr{P}[f]\) we have

(5.1.29)
\[ \int_{x_i}^{x_{i+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,0,0}]_{x, y_0, z_0} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_0, z_0)\, dx. \]

Likewise, if \(j = n\), \(k = 0\), or \(j = 0\), \(k = n\), or \(j = n\), \(k = n\), the corresponding terms, analogous to the term (5.1.29), are

(5.1.30)
\[ \int_{x_i}^{x_{i+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [-\varphi_{i,n-1,0}]_{x, y_n, z_0} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_n, z_0)\, dx \]
(5.1.31)
\[ \int_{x_i}^{x_{i+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [-\varphi_{i,0,n-1}]_{x, y_0, z_n} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_0, z_n)\, dx \]
(5.1.32)
\[ \int_{x_i}^{x_{i+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [+\varphi_{i,n-1,n-1}]_{x, y_n, z_n} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_n, z_n)\, dx. \]

It should be observed that the terms (5.1.25)—(5.1.32) are deduced from the general term (5.1.24) by means of convention (A), made about the function \(\varphi_{i,j,k}\), when at least one of the indices is equal to 0 or to \(n\).

The same remarks apply to the integrals \(\int_{y_j}^{y_{j+1}}\) and \(\int_{z_k}^{z_{k+1}}\) in \(\mathscr{P}[f]\).

For the integrals \(\int_{y_j}^{y_{j+1}}\) in \(\mathscr{P}[f]\) we have, in the general case \(0 \lt i, k \lt n\), the general term

(5.1.33)
\[ \int_{y_j}^{y_{j+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,j,k} + \varphi_{i-1,j,k-1} - \varphi_{i-1,j,k} - \varphi_{i,j,k-1}]_{x_i, y, z_k} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y, z_k)\, dy \]

and all the other terms obtained from the general term when at least one of the indices \(i\), \(k\) has the value 0 or \(n\), taking convention (A) into account.

Likewise, for the integrals \(\int_{z_k}^{z_{k+1}}\) in \(\mathscr{P}[f]\) we have, in the general case \(0 \lt i, j \lt n\), the general term

(5.1.34)
\[ \int_{z_k}^{z_{k+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,j,k} + \varphi_{i-1,j-1,k} - \varphi_{i-1,j,k} - \varphi_{i,j-1,k}]_{x_i, y_j, z} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z)\, dz \]

and all the other terms obtained from the general term when at least one of the indices \(i\), \(j\) has the value 0 or \(n\), taking convention (A) into account.

5.1.7. The coefficient of \(\dfrac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y, z)\) in the double integral \(\int_{y_j}^{y_{j+1}} \int_{z_k}^{z_{k+1}}\) in \(\mathscr{P}[f]\), when \(0 \lt i \lt n\), results from formula (5.1.8) applied to the parallelepipeds

(5.1.35)
\[ D_{i-1,j,k};\ D_{i,j,k}. \]

We thus have the general term

(5.1.36)
\[ \int_{y_j}^{y_{j+1}} \int_{z_k}^{z_{k+1}} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{i-1,j,k} - \varphi_{i,j,k}]_{x_i, y, z} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y, z)\, dy\, dz. \]

For \(i = 0\) and \(i = n\) we have the terms:

(5.1.37)
\[ \int_{y_j}^{y_{j+1}} \int_{z_k}^{z_{k+1}} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [-\varphi_{0,j,k}]_{x_0, y, z} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_0, y, z)\, dy\, dz \]
(5.1.38)
\[ \int_{y_j}^{y_{j+1}} \int_{z_k}^{z_{k+1}} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{n-1,j,k}]_{x_n, y, z} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_n, y, z)\, dy\, dz. \]

These terms are deduced from the general term (5.1.36) by setting \(i = 0\) and \(i = n\) and taking convention (A) into account.

For the double integral \(\int_{x_i}^{x_{i+1}} \int_{z_k}^{z_{k+1}}\) in \(\mathscr{P}[f]\) we have, for \(0 \lt j \lt n\), the general term

(5.1.39)
\[ \int_{x_i}^{x_{i+1}} \int_{z_k}^{z_{k+1}} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,j-1,k} - \varphi_{i,j,k}]_{x, y_j, z} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_j, z)\, dx\, dz \]

and the terms obtained from the general term for \(j = 0\) and \(j = n\), taking convention (A) into account.

Likewise, for the double integral \(\int_{x_i}^{x_{i+1}} \int_{y_j}^{y_{j+1}}\) in \(\mathscr{P}[f]\) we have, for \(0 \lt k \lt n\), the general term

(5.1.40)
\[ \int_{x_i}^{x_{i+1}} \int_{y_j}^{y_{j+1}} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,j,k-1} - \varphi_{i,j,k}]_{x, y, z_k} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y, z_k)\, dx\, dy \]

and the terms obtained from the general term for \(k = 0\) and \(k = n\), taking convention (A) into account.

5.1.8. Gathering the results of the discussions carried out in subsections 5.1.5, 5.1.6, 5.1.7, we can write formula (5.1.11) in the following form:

(5.1.41)
\[ \begin{aligned} \mathscr{P}[f] = {} & \sum_{i,j,k=0}^{n} \sum_{r=0}^{n-1} (-1)^{n-r} \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \\ & \quad [(\varphi_{i,j,k} + \varphi_{i-1,j-1,k} - \varphi_{i,j-1,k} - \varphi_{i-1,j,k}) - (\varphi_{i,j,k-1} + \varphi_{i-1,j-1,k-1} - \varphi_{i,j-1,k-1} - \varphi_{i-1,j,k-1})]_{x_i, y_j, z_k} \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z_k) + \\ & + \sum_{i,j,k=0}^{n} \sum_{r=0}^{n-1} (-1)^{n-r} \int_{x_i}^{x_{i+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,j,k} + \varphi_{i,j-1,k-1} - \varphi_{i,j,k-1} - \varphi_{i,j-1,k}]_{x, y_j, z_k} \\ & \qquad \qquad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_j, z_k)\, dx + \\ & + \sum_{i,j,k=0}^{n} \sum_{r=0}^{n-1} (-1)^{n-r} \int_{y_j}^{y_{j+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,j,k} + \varphi_{i-1,j,k-1} - \varphi_{i,j,k-1} - \varphi_{i-1,j,k}]_{x_i, y, z_k} \\ & \qquad \qquad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y, z_k)\, dy + \\ & + \sum_{i,j,k=0}^{n} \sum_{r=0}^{n-1} (-1)^{n-r} \int_{z_k}^{z_{k+1}} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,j,k} + \varphi_{i-1,j-1,k} - \varphi_{i,j-1,k} - \varphi_{i-1,j,k}]_{x_i, y_j, z} \\ & \qquad \qquad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z)\, dz + \\ & + \sum_{i,j,k=0}^{n} \sum_{r=0}^{n-1} (-1)^{n-r} \int_{y_j}^{y_{j+1}} \int_{z_k}^{z_{k+1}} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{i,j,k} - \varphi_{i-1,j,k}]_{x_i, y, z} \\ & \qquad \qquad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y, z)\, dy\, dz + \\ & + \sum_{i,j,k=0}^{n} \sum_{r=0}^{n-1} (-1)^{n-r} \int_{x_i}^{x_{i+1}} \int_{z_k}^{z_{k+1}} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,j,k} - \varphi_{i,j-1,k}]_{x, y_j, z} \\ & \qquad \qquad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_j, z)\, dx\, dz + \\ & + \sum_{i,j,k=0}^{n} \sum_{r=0}^{n-1} (-1)^{n-r} \int_{x_i}^{x_{i+1}} \int_{y_j}^{y_{j+1}} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,j,k} - \varphi_{i,j,k-1}]_{x, y, z_k} \\ & \qquad \qquad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y, z_k)\, dx\, dy. \end{aligned} \]

In applying this formula, convention (A) must be taken into account, and in this way all the terms of formula (5.1.11) are obtained.

§ 5.2. Boundary value problem

Formulas (5.1.10) and (5.1.11), or (5.1.41), of § 5.1 are important, as we shall see in the following sections. In connection with formula (5.1.41) we shall pose a boundary value problem with the aim of arriving at the definition of the divided difference of order \(n\) of the function \(f\) on the nodes \(M_{i,j,k}\), where \(i, j, k = 0, 1, \ldots, n\), and at its integral representation. This problem is lengthy to treat, and for this reason it will be the subject of several sections.

5.2.1. Formula (5.1.41) shows that \(\mathscr{P}[f]\) depends on:

(5.2.1)
\[ \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z_k) \]
(5.2.2)
\[ \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_j, z_k), \quad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y, z_k), \quad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y_j, z) \]
(5.2.3)
\[ \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x_i, y, z), \quad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y_j, z), \quad \frac{\partial^{3r} f}{\partial x^r \partial y^r \partial z^r}(x, y, z_k) \]

for \(r = 0, 1, \ldots, n-1\) and \(i, j, k = 0, 1, \ldots, n\).

It is then of great interest to treat the following boundary value problem:

Boundary value problem. Determine the functions \(\varphi_{i,j,k}\), solutions of the partial differential equations

(5.2.4)
\[ \frac{\partial^{3n} \varphi_{i,j,k}}{\partial x^n \partial y^n \partial z^n} = 0 \quad \text{for } i, j, k = 0, 1, \ldots, n, \]

the function \(\varphi_{i,j,k}\) being determined on \(D_{i,j,k}\), in such a way that the functional \(\mathscr{P}[f]\) depends only on the values of \(f\) at the nodes \(M_{i,j,k}\).

For this purpose boundary conditions must be introduced, by requiring that the coefficients of the partial derivatives (5.2.3), (5.2.2) in formula (5.1.41), in \(\int_{y_j}^{y_{j+1}} \int_{z_k}^{z_{k+1}}, \ldots\) and in \(\int_{x_i}^{x_{i+1}}, \ldots\), be zero, and likewise that the coefficients of the partial derivatives (5.2.1) be zero for \(r = 1, 2, \ldots, n-1\), while they reduce to constants for \(r = 0\).

The boundary conditions that we shall introduce will therefore be the following:

(5.2.5)
\[ \begin{aligned} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{i,j,k} - \varphi_{i-1,j,k}]_{x_i, y, z} &= 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,j,k} - \varphi_{i,j-1,k}]_{x, y_j, z} &= 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,j,k} - \varphi_{i,j,k-1}]_{x, y, z_k} &= 0 \end{aligned} \]

for \(i, j, k = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Then

(5.2.6)
\[ \begin{aligned} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,j,k} + \varphi_{i,j-1,k-1} - \varphi_{i,j,k-1} - \varphi_{i,j-1,k}]_{x, y_j, z_k} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,j,k} + \varphi_{i-1,j,k-1} - \varphi_{i,j,k-1} - \varphi_{i-1,j,k}]_{x_i, y, z_k} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,j,k} + \varphi_{i-1,j-1,k} - \varphi_{i,j-1,k} - \varphi_{i-1,j,k}]_{x_i, y_j, z} &= 0 \end{aligned} \]

for \(i, j, k = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Finally

(5.2.7)
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \Bigl[(\varphi_{i,j,k} + \varphi_{i-1,j-1,k} - \varphi_{i,j-1,k} - \varphi_{i-1,j,k}) - (\varphi_{i,j,k-1} + \varphi_{i-1,j-1,k-1} - \varphi_{i,j-1,k-1} - \varphi_{i-1,j,k-1})\Bigr]_{x_i, y_j, z_k} = \begin{cases} C_{i,j,k} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \]

for \(i, j, k = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

When one of the indices in \(\varphi_{i,j,k}\) is replaced by \(-1\) or \(n\), convention (A), made in subsection 5.1.5, must be taken into account.

The boundary value problem for the determination of the function \(\varphi_{i,j,k}\) on the parallelepiped \(D_{i,j,k}\) will be denoted by \((P_{i,j,k})\).

In general, the solution of problem \((P_{i,j,k})\) depends on the solutions of problems \((P_{i-1,j-1,k})\), \((P_{i,j-1,k})\), \((P_{i-1,j,k})\), \((P_{i,j,k-1})\), \((P_{i-1,j-1,k-1})\), \((P_{i,j-1,k-1})\), \((P_{i-1,j,k-1})\), so that at first sight it appears to be a difficult problem. However, by proceeding methodically, we shall succeed in solving it.

We shall determine systematically \(\varphi_{0,0,0}\), \(\varphi_{i,0,0}\), \(\varphi_{0,j,0}\), \(\varphi_{0,0,k}\) for \(i, j, k = 1, 2, \ldots, n-1\). Then we shall determine \(\varphi_{i,j,0}\), \(\varphi_{0,j,k}\), \(\varphi_{i,0,k}\) for \(i, j, k = 1, 2, \ldots, n-1\). Finally, we shall determine \(\varphi_{i,j,k}\) for \(i, j, k = 1, 2, \ldots, n-1\).

The constants \(C_{i,j,k}\), where \(i, j, k = 0, 1, \ldots, n\), will be determined so that the boundary value problem is possible. They will not be determined completely by the preceding boundary conditions, and will depend on a factor. In order to determine this factor, a new condition will be imposed

(5.2.8)
\[ \mathscr{P}[x^n y^n z^n] = 1. \]

5.2.2. If in conditions (5.2.5) and (5.2.6) we set \(i = 0\), \(j = 0\), \(k = 0\) and take convention (A) into account, we have:

Problem \((P_{0,0,0})\). Determine the solution \(\varphi_{0,0,0}\) of the partial differential equation

(5.2.9)
\[ \frac{\partial^{3n} \varphi_{0,0,0}}{\partial x^n \partial y^n \partial z^n} = 0 \]

in \(D_{0,0,0}\), which satisfies the following boundary conditions:

(5.2.10)
\[ \begin{aligned} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{0,0,0}]_{x_0, y, z} &= 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{0,0,0}]_{x, y_0, z} &= 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{0,0,0}]_{x, y, z_0} &= 0 \end{aligned} \]

and

(5.2.11)
\[ \begin{aligned} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{0,0,0}]_{x, y_0, z_0} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{0,0,0}]_{x_0, y, z_0} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{0,0,0}]_{x_0, y_0, z} &= 0 \end{aligned} \]

and, finally,

(5.2.12)
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{0,0,0}]_{x_0, y_0, z_0} = \begin{cases} C_{0,0,0} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \]

for \(r = 0, 1, \ldots, n-1\).

The solution of this problem is

(5.2.13)
\[ \varphi_{0,0,0}(x, y, z) = C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!}. \]

5.2.3. If in conditions (5.2.5) and (5.2.6) we set \(j = 0\), \(k = 0\) and take convention (A) into account, we have:

Problem \((P_{i,0,0})\). Determine the solutions of the partial differential equations

(5.2.14)
\[ \frac{\partial^{3n} \varphi_{i,0,0}}{\partial x^n \partial y^n \partial z^n} = 0 \quad \text{for } i = 1, 2, \ldots, n-1, \]

with the following boundary conditions:

(5.2.15)
\[ \begin{aligned} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{i,0,0} - \varphi_{i-1,0,0}]_{x_i, y, z} &= 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,0,0}]_{x, y_0, z} &= 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,0,0}]_{x, y, z_0} &= 0 \end{aligned} \]

for \(i = 1, 2, \ldots, n-1, n\) and \(r = 0, 1, \ldots, n-1\).

Then

(5.2.16)
\[ \begin{aligned} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,0,0}]_{x, y_0, z_0} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,0,0} - \varphi_{i-1,0,0}]_{x_i, y, z_0} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,0,0} - \varphi_{i-1,0,0}]_{x_i, y_0, z} &= 0 \end{aligned} \]

for \(i = 1, 2, \ldots, n-1, n\) and \(r = 0, 1, \ldots, n-1\).

Finally

(5.2.17)
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,0,0} - \varphi_{i-1,0,0}]_{x_i, y_0, z_0} = \begin{cases} C_{i,0,0} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \]

for \(i = 1, 2, \ldots, n-1, n\) and \(r = 0, 1, \ldots, n-1\).

One determines \(\varphi_{i,0,0}\) step by step, taking into account that \(\varphi_{0,0,0}\) is given by formula (5.2.13). One determines \(\varphi_{1,0,0}\), then \(\varphi_{2,0,0}, \ldots\), and so on, as in subsections 4.2.4 and 4.2.5. One finds

(5.2.18)
\[ \frac{\partial^{3(n-r)} \varphi_{1,0,0}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0,0} \frac{(x - x_1)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} \]

for \(r = 1, 2, \ldots, n\).

Next, suppose that we have obtained the formula

(5.2.19)
\[ \frac{\partial^{3(n-r)} \varphi_{i,0,0}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,0,0} \frac{(x - x_i)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!}, \]

valid for \(r = 1, 2, \ldots, n\), which is correct for \(i = 1\), since in this case formula (5.2.19) coincides with formula (5.2.18).

To prove that formula (5.2.19) is valid for \(i = 1, 2, \ldots, n\), we use the method of complete induction. To this end one integrates the partial differential equation (5.2.14) corresponding to the index \(i + 1\), with the boundary conditions (5.2.15), (5.2.16), (5.2.17) corresponding to the index \(i + 1\), taking formula (5.2.19) into account. In this way one obtains a formula for \(\dfrac{\partial^{3(n-r)} \varphi_{i+1,0,0}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}\), valid for \(r = 1, 2, \ldots, n\), which is deduced from formula (5.2.19) by replacing \(i\) by \(i + 1\). This proves that formula (5.2.19) is general; it is valid for \(i = 1, 2, \ldots, n-1\).

For \(i = n - 1\) and \(r = n\), formula (5.2.19) gives us

(5.2.20)
\[ \varphi_{n-1,0,0}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!}. \]

It remains to determine the constants \(C_{0,0,0}, C_{1,0,0}, \ldots, C_{n,0,0}\) by conditions (5.2.15), (5.2.16), (5.2.17). For \(i = n\), and taking convention (A) into account, the conditions reduce to:

(5.2.21)
\[ \begin{aligned} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{n-1,0,0}]_{x_n, y, z} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{n-1,0,0}]_{x_n, y, z_0} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,0,0}]_{x_n, y_0, z} &= 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [-\varphi_{n-1,0,0}]_{x_n, y_0, z_0} &= \begin{cases} C_{n,0,0} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{aligned} \]

for \(r = 0, 1, \ldots, n-1\).

For \(r = 0\), formula (5.2.20) shows that the first three conditions (5.2.21) are satisfied, and the fourth condition gives the equation

(5.2.22)
\[ C_{0,0,0} + C_{1,0,0} + \ldots + C_{n,0,0} = 0. \]

Formula (5.2.20) shows that

\[ \frac{\partial^{3(n-r)-1} \varphi_{n-1,0,0}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}}(x_n, y, z) = \left[ C_{0,0,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} \]

and in order that the first condition (5.2.21) be satisfied when \(r = 1, 2, \ldots, n-1\), we must take

(5.2.23)
\[ C_{0,0,0}(x_n - x_0)^r + \ldots + C_{n-1,0,0}(x_n - x_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\).

On the other hand, we have

\[ \frac{\partial^{3(n-r)-2} \varphi_{n-1,0,0}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}}(x_n, y, z) = \left[ C_{0,0,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^r}{r!} \frac{(z - z_0)^{r-1}}{(r-1)!} \]
\[ \frac{\partial^{3(n-r)-2} \varphi_{n-1,0,0}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}}(x_n, y, z) = \left[ C_{0,0,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^r}{r!} \]
\[ \frac{\partial^{3(n-r-1)} \varphi_{n-1,0,0}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}}(x_n, y, z) = \left[ C_{0,0,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^r}{r!} \frac{(z - z_0)^r}{r!} \]

and it follows from equations (5.2.23) that the other conditions (5.2.21) are satisfied for \(r = 1, 2, \ldots, n-1\).

Hence the constants \(C_{0,0,0}, C_{1,0,0}, \ldots, C_{n,0,0}\) satisfy equations (5.2.22) and (5.2.23), which can also be written in the form

(5.2.24)
\[ \begin{array}{lll} C_{0,0,0} & + \ldots + C_{n,0,0} & = 0 \\ C_{0,0,0} x_0 & + \ldots + C_{n,0,0} x_n & = 0 \\ \ldots\ldots\ldots & \ldots\ldots\ldots\ldots\ldots & \ldots \\ C_{0,0,0} x_0^{n-1} & + \ldots + C_{n,0,0} x_n^{n-1} & = 0. \end{array} \]

One shows as in subsection 4.2.16 that \(\varphi_{n-1,0,0}\) can also be written in the form

(5.2.25)
\[ \varphi_{n-1,0,0}(x, y, z) = -C_{n,0,0} \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!}. \]

5.2.4. If in conditions (5.2.5) and (5.2.6) we set \(i = 0\), \(k = 0\) and take convention (A) into account, we have

Problem \((P_{0,j,0})\). Determine the solutions of the partial differential equations

(5.2.26)
\[ \frac{\partial^{3n} \varphi_{0,j,0}}{\partial x^n \partial y^n \partial z^n} = 0 \quad \text{for } j = 1, 2, \ldots, n-1, \]

with the following boundary conditions:

(5.2.27)
\[ \begin{gathered} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r}}[\varphi_{0,j,0}]_{x_0, y, z} = 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r}\partial y^{n-r-1}\partial z^{n-r}}[\varphi_{0,j,0} - \varphi_{0,j-1,0}]_{x, y_j, z} = 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r-1}}[\varphi_{0,j,0}]_{x, y, z_0} = 0 \end{gathered} \]

for \(j = 1, 2, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Next,

(5.2.28)
\[ \begin{gathered} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r}\partial y^{n-r-1}\partial z^{n-r-1}}[\varphi_{0,j,0} - \varphi_{0,j-1,0}]_{x, y_j, z_0} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r-1}}[\varphi_{0,j,0}]_{x_0, y, z_0} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r}}[\varphi_{0,j,0} - \varphi_{0,j-1,0}]_{x_0, y_j, z} = 0 \end{gathered} \]

for \(j = 1, 2, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Finally,

(5.2.29)
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}[\varphi_{0,j,0} - \varphi_{0,j-1,0}]_{x_0, y_j, z_0} = \begin{cases} C_{0,j,0} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \]

for \(j = 1, 2, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Proceeding as in subsection 5.2.3, one proves the formula

(5.2.30)
\[ \frac{\partial^{3(n-r)}\varphi_{0,j,0}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r}}(x, y, z) = \left[C_{0,0,0}\frac{(y-y_0)^{r-1}}{(r-1)!} + \ldots + C_{0,j,0}\frac{(y-y_j)^{r-1}}{(r-1)!}\right]\frac{(x-x_0)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!} \]

valid for \(j = 1, 2, \ldots, n-1\) and \(r = 1, 2, \ldots, n\).

One shows that the constants \(C_{0,0,0}, C_{0,1,0}, \ldots, C_{0,n,0}\) are determined by the equations

(5.2.31)
\[ C_{0,0,0} + \ldots + C_{0,n,0} = 0 \]

and

(5.2.32)
\[ C_{0,0,0}(y_n - y_0)^r + \ldots + C_{0,n-1,0}(y_n - y_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\). This system can be written in the form

(5.2.33)
\[ \begin{array}{lll} C_{0,0,0} & + \ldots + C_{0,n,0} & = 0 \\ C_{0,0,0} y_0 & + \ldots + C_{0,n,0} y_n & = 0 \\ \ldots\ldots\ldots & \ldots\ldots\ldots\ldots & \ldots \\ C_{0,0,0} y_0^{n-1} & + \ldots + C_{0,n,0} y_n^{n-1} & = 0. \end{array} \]

These equations show that, for \(r = n\) and \(j = n-1\), formula (5.2.30) can be written in the form

(5.2.34)
\[ \varphi_{0,n-1,0}(x, y, z) = -C_{0,n,0}\frac{(x-x_0)^{n-1}}{(n-1)!}\,\frac{(y-y_n)^{n-1}}{(n-1)!}\,\frac{(z-z_0)^{n-1}}{(n-1)!}. \]

5.2.5. If in conditions (5.2.5) and (5.2.6) we set \(i = 0\), \(j = 0\) and take convention (A) into account, we obtain:

Problem \((P_{0,0,k})\). Determine the solutions of the partial differential equations

(5.2.35)
\[ \frac{\partial^{3n}\varphi_{0,0,k}}{\partial x^n \partial y^n \partial z^n} = 0 \quad \text{for } k = 1, 2, \ldots, n-1, \]

with the following boundary conditions:

(5.2.36)
\[ \begin{gathered} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r}}[\varphi_{0,0,k}]_{x_0, y, z} = 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r}\partial y^{n-r-1}\partial z^{n-r}}[\varphi_{0,0,k}]_{x, y_0, z} = 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r-1}}[\varphi_{0,0,k} - \varphi_{0,0,k-1}]_{x, y, z_k} = 0 \end{gathered} \]

for \(k = 1, 2, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Next,

(5.2.37)
\[ \begin{gathered} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r}\partial y^{n-r-1}\partial z^{n-r-1}}[\varphi_{0,0,k} - \varphi_{0,0,k-1}]_{x, y_0, z_k} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r-1}}[\varphi_{0,0,k} - \varphi_{0,0,k-1}]_{x_0, y, z_k} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r}}[\varphi_{0,0,k}]_{x_0, y_0, z} = 0 \end{gathered} \]

for \(k = 1, 2, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Finally,

(5.2.38)
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}[\varphi_{0,0,k} - \varphi_{0,0,k-1}]_{x_0, y_0, z_k} = \begin{cases} C_{0,0,k} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \]

for \(k = 1, 2, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Proceeding as in subsection 5.2.3, one proves the formula

(5.2.39)
\[ \frac{\partial^{3(n-r)}\varphi_{0,0,k}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r}}(x, y, z) = \left[C_{0,0,0}\frac{(z-z_0)^{r-1}}{(r-1)!} + \ldots + C_{0,0,k}\frac{(z-z_k)^{r-1}}{(r-1)!}\right]\frac{(x-x_0)^{r-1}}{(r-1)!}\,\frac{(y-y_0)^{r-1}}{(r-1)!} \]

valid for \(r = 1, 2, \ldots, n\) and \(k = 1, 2, \ldots, n-1\).

The constants \(C_{0,0,0}, \ldots, C_{0,0,n}\) are given by the equations

(5.2.40)
\[ \begin{gathered} C_{0,0,0} + \ldots + C_{0,0,n} = 0 \\ C_{0,0,0}(z_n - z_0)^r + \ldots + C_{0,0,n-1}(z_n - z_{n-1})^r = 0 \end{gathered} \]

for \(r = 1, 2, \ldots, n-1\). This system can also be written in the form

(5.2.41)
\[ \begin{array}{lll} C_{0,0,0} & + \ldots + C_{0,0,n} & = 0 \\ C_{0,0,0} z_0 & + \ldots + C_{0,0,n} z_n & = 0 \\ \ldots\ldots\ldots & \ldots\ldots\ldots\ldots & \ldots \\ C_{0,0,0} z_0^{n-1} & + \ldots + C_{0,0,n} z_n^{n-1} & = 0. \end{array} \]

Equations (5.2.41) show that, for \(r = n\) and \(k = n-1\), formula (5.2.39) can be written in the form

(5.2.42)
\[ \varphi_{0,0,n-1} = -C_{0,0,n}\frac{(x-x_0)^{n-1}}{(n-1)!}\,\frac{(y-y_0)^{n-1}}{(n-1)!}\,\frac{(z-z_n)^{n-1}}{(n-1)!}. \]

§ 5.3. The problems \((P_{i,j,0})\), \((P_{0,j,k})\), \((P_{i,0,k})\)

5.3.1. If in the boundary conditions (5.2.5) and (5.2.6) we set \(k = 0\) and take convention (A) into account, we obtain:

Problem \((P_{i,j,0})\). Determine the solutions of the partial differential equations

(5.3.1)
\[ \frac{\partial^{3n}\varphi_{i,j,0}}{\partial x^n \partial y^n \partial z^n} = 0 \]

for \(i, j = 1, 2, \ldots, n-1\), which satisfy the boundary conditions:

(5.3.2)
\[ \begin{gathered} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r}}[\varphi_{i,j,0} - \varphi_{i-1,j,0}]_{x_i, y, z} = 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r}\partial y^{n-r-1}\partial z^{n-r}}[\varphi_{i,j,0} - \varphi_{i,j-1,0}]_{x, y_j, z} = 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r-1}}[\varphi_{i,j,0}]_{x, y, z_k} = 0 \end{gathered} \]

for \(i, j = 1, 2, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Next,

(5.3.3)
\[ \begin{gathered} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r}\partial y^{n-r-1}\partial z^{n-r-1}}[\varphi_{i,j,0} - \varphi_{i,j-1,0}]_{x, y_j, z_0} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r-1}}[\varphi_{i,j,0} - \varphi_{i-1,j,0}]_{x_i, y, z_0} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r}}[\varphi_{i,j,0} + \varphi_{i-1,j-1,0} - \varphi_{i,j-1,0} - \varphi_{i-1,j,0}]_{x_i, y_j, z} = 0 \end{gathered} \]

for \(i, j = 1, 2, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Finally,

(5.3.4)
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}[\varphi_{i,j,0} + \varphi_{i-1,j-1,0} - \varphi_{i,j-1,0} - \varphi_{i-1,j,0}]_{x_i, y_j, z_0} = \begin{cases} C_{i,j,0} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \]

for \(i, j = 1, 2, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

5.3.2. We first determine the function \(\varphi_{1,1,0}\) from the partial differential equation (5.3.1) and the boundary conditions (5.3.2), (5.3.3), (5.3.4) corresponding to \(i = 1\), \(j = 1\). For this we must take into account formula (5.2.13), formula (5.2.19) for \(i = 1\) and formula (5.2.30) for \(j = 1\). Then, proceeding as in subsection 4.2.8, we find

(5.3.5)
\[ \begin{aligned} &\frac{\partial^{3(n-r)}\varphi_{1,1,0}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r}}(x, y, z) = \left[C_{0,0,0}\frac{(x-x_0)^{r-1}}{(r-1)!} + C_{1,0,0}\frac{(x-x_1)^{r-1}}{(r-1)!}\right]\frac{(y-y_0)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!} + \\ &+ \left[C_{0,1,0}\frac{(x-x_0)^{r-1}}{(r-1)!} + C_{1,1,0}\frac{(x-x_1)^{r-1}}{(r-1)!}\right]\frac{(y-y_1)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!}, \end{aligned} \]

for \(r = 1, 2, \ldots, n\).

Next, by the method of complete induction, as in subsection 4.2.9, one proves the formula

(5.3.6)
\[ \begin{aligned} &\frac{\partial^{3(n-r)}\varphi_{i,1,0}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r}}(x, y, z) = \left[C_{0,0,0}\frac{(x-x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,0,0}\frac{(x-x_i)^{r-1}}{(r-1)!}\right]\frac{(y-y_0)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!} + \\ &+ \left[C_{0,1,0}\frac{(x-x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,1,0}\frac{(x-x_i)^{r-1}}{(r-1)!}\right]\frac{(y-y_1)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!}, \end{aligned} \]

for \(i = 1, 2, \ldots n-1\) and \(r = 1, 2, \ldots n\).

It remains to determine the constants \(C_{0,1,0}, \ldots, C_{n,1,0}\) from conditions (5.3.2), (5.3.3), (5.3.4) corresponding to the indices \(i = n\) and \(j = 1\). Taking convention (A) into account, these conditions are:

(5.3.7)
\[ \begin{gathered} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r}}[\varphi_{n-1,1,0}]_{x_n, y, z} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r-1}}[\varphi_{n-1,1,0}]_{x_n, y, z_0} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r}}[\varphi_{n-1,0,0} - \varphi_{n-1,1,0}]_{x_n, y_1, z} = 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}[\varphi_{n-1,0,0} - \varphi_{n-1,1,0}]_{x_n, y_1, z_0} = \begin{cases} C_{n,1,0} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases}. \end{gathered} \]

By formulas (5.3.6) and (5.2.20) we have

(5.3.8)
\[ \begin{aligned} &\varphi_{n-1,1,0}(x, y, z) = \left[C_{0,0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!}\,\frac{(z-z_0)^{n-1}}{(n-1)!} + \\ &+ \left[C_{0,1,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,1,0}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_1)^{n-1}}{(n-1)!}\,\frac{(z-z_0)^{n-1}}{(n-1)!} \end{aligned} \]

and

(5.3.9)
\[ \varphi_{n-1,0,0}(x, y, z) = \left[C_{0,0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!}\,\frac{(z-z_0)^{n-1}}{(n-1)!} \]

For \(r = 0\), conditions (5.3.7) are:

(5.3.10)
\[ \begin{gathered} \frac{\partial^{3n-1}}{\partial x^{n-1}\partial y^n \partial z^n}[\varphi_{n-1,1,0}]_{x_n, y, z} = 0 \\ \frac{\partial^{3n-2}}{\partial x^{n-1}\partial y^n \partial z^{n-1}}[\varphi_{n-1,1,0}]_{x_n, y, z_0} = 0 \\ \frac{\partial^{3n-2}}{\partial x^{n-1}\partial y^{n-1}\partial z^n}[\varphi_{n-1,0,0} - \varphi_{n-1,1,0}]_{x_n, y_1, z} = 0 \\ \frac{\partial^{3(n-1)}}{\partial x^{n-1}\partial y^{n-1}\partial z^{n-1}}[\varphi_{n-1,0,0} - \varphi_{n-1,1,0}]_{x_n, y_1, z_0} = C_{n,1,0}. \end{gathered} \]

The first three conditions (5.3.10) are satisfied, since \(\varphi_{n-1,0,0}\) is a polynomial of degree \(n-1\) in \(x\), in \(y\) and in \(z\).

The last condition (5.3.10) leads to the equation

(5.3.11)
\[ C_{0,1,0} + C_{1,1,0} + \ldots + C_{n,1,0} = 0. \]

By formula (5.3.8) we have

\[ \begin{aligned} &\frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r}}[\varphi_{n-1,1,0}]_{x_n, y, z} = \left[C_{0,0,0}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,0,0}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_0)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!} + \\ &+ \left[C_{0,1,0}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,1,0}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_1)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!}. \end{aligned} \]

But formula (5.2.23) shows that the first large bracket on the right-hand side vanishes for \(r = 1, 2, \ldots, n-1\). Then, for the first condition to be satisfied for \(r = 1, 2, \ldots, n-1\), we must take

(5.3.12)
\[ C_{0,1,0}(x_n - x_0)^r + \ldots + C_{n-1,1,0}(x_n - x_{n-1})^r = 0, \quad \text{for } r = 1, 2, \ldots, n-1. \]

Finally, we have

\[ \begin{aligned} &\frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r-1}}[\varphi_{n-1,1,0}]_{x_n, y, z} = \left[C_{0,0,0}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,0,0}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_0)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^r}{r!} + \\ &+ \left[C_{0,1,0}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,1,0}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_1)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^r}{r!} \end{aligned} \]
(5.3.13)
\[ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r}}[\varphi_{n-1,0,0} - \varphi_{n-1,1,0}]_{x_n, y, z} = -\left[C_{0,1,0}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,1,0}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_1)^r}{r!}\,\frac{(z-z_0)^{r-1}}{(r-1)!} \]
\[ \begin{aligned} &\frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}[\varphi_{n-1,0,0} - \varphi_{n-1,1,0}]_{x_n, y, z} = \\ &-\left[C_{0,1,0}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,1,0}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_1)^r}{r!}\,\frac{(z-z_0)^r}{r!} \end{aligned} \]

and from formulas (5.2.23) and (5.3.12) one sees that for \(r = 1, 2, \ldots, n-1\) the right-hand sides of these formulas vanish. Hence the remaining conditions (5.3.7) are satisfied for \(r = 1, 2, \ldots, n-1\).

Thus all the conditions (5.3.7) are satisfied, and the constants \(C_{0,1,0}, \ldots, C_{n,1,0}\) are determined by equations (5.3.11) and (5.3.12). The system formed by these equations can also be written in the form

(5.3.14)
\[ \begin{array}{lll} C_{0,1,0} & + \ldots + C_{n,1,0} & = 0 \\ C_{0,1,0} x_0 & + \ldots + C_{n,1,0} x_n & = 0 \\ \ldots\ldots\ldots & \ldots\ldots\ldots\ldots & \ldots \\ C_{0,1,0} x_0^{n-1} & + \ldots + C_{n,1,0} x_n^{n-1} & = 0. \end{array} \]

Let us suppose that we have proved that for \(l = 1, 2, \ldots, j\) we have the formula

(5.3.15)
\[ \begin{aligned} &\frac{\partial^{3(n-r)}\varphi_{i,l,0}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r}}(x, y, z) = \left[C_{0,0,0}\frac{(x-x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,0,0}\frac{(x-x_i)^{r-1}}{(r-1)!}\right]\frac{(y-y_0)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,l,0}\frac{(x-x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,l,0}\frac{(x-x_i)^{r-1}}{(r-1)!}\right]\frac{(y-y_l)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!} \end{aligned} \]

for \(l = 0, 1, 2, \ldots, j\), \(i = 1, 2, \ldots, n-1\) and \(r = 1, 2, \ldots, n\), where the constants \(C_{0,l,0} \ldots, C_{n,l,0}\) are determined by the equations

(5.3.16)
\[ \begin{gathered} C_{0,l,0} + \ldots + C_{n,l,0} = 0 \\ C_{0,l,0}(x_n - x_0)^r + \ldots + C_{n-1,l,0}(x_n - x_{n-1})^r = 0 \end{gathered} \]

for \(r = 1, 2, \ldots, n-1\). This system can also be written in the form

(5.3.17)
\[ \begin{array}{lll} C_{0,l,0} & + \ldots + C_{n,l,0} & = 0 \\ C_{0,l,0} x_0 & + \ldots + C_{n,l,0} x_n & = 0 \\ \ldots\ldots\ldots & \ldots\ldots\ldots\ldots & \ldots \\ C_{0,l,0} x_0^{n-1} & + \ldots + C_{n,l,0} x_n^{n-1} & = 0. \end{array} \]

Systems (5.3.16), (5.3.17) are valid for \(l = 0, 1, \ldots, j\).

This is true for \(l = 1\), because in this case formula (5.3.15) coincides with formula (5.3.6) and system (5.3.17) coincides with system (5.3.14).

We shall prove that formula (5.3.15) also holds for \(i = 1, 2, \ldots, n-1\), \(l = j + 1\) and \(r = 1, 2, \ldots, n\), the constants \(C_{0,j+1,0}, \ldots, C_{n,j+1,0}\) being given by system (5.3.16) or (5.3.17), for \(l = j + 1\).

To this end we integrate the partial differential equations

(5.3.18)
\[ \frac{\partial^{3n}\varphi_{i,j+1,0}}{\partial x^n \partial y^n \partial z^n} = 0 \quad \text{for } i = 1, 2, \ldots, n-1 \]

with the boundary conditions (5.3.2), (5.3.3), (5.3.4) corresponding to the indices \(i\), \(j + 1\).

We begin by determining \(\frac{\partial^{3(n-r)}\varphi_{1,j+1,0}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r}}\) for \(r = 1, 2, \ldots, n\), integrating the equation \(\frac{\partial^{3n}\varphi_{1,j+1,0}}{\partial x^n \partial y^n \partial z^n} = 0\) with the boundary conditions specified above for the indices \(1, j + 1\), and taking into account formula (5.3.15) for \(i = 1\), \(l = j\) and formula (5.2.30), which gives \(\frac{\partial^{3(n-r)}\varphi_{0,j,0}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r}}\) for \(j = 1, 2, \ldots, n-1\) and \(r = 1, 2, \ldots, n\). Applying the method of complete induction, one finds the formula

(5.3.19)
\[ \begin{aligned} &\frac{\partial^{3(n-r)}\varphi_{1,j+1,0}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r}}(x, y, z) = \left[C_{0,0,0}\frac{(x-x_0)^{r-1}}{(r-1)!} + C_{1,0,0}\frac{(x-x_1)^{r-1}}{(r-1)!}\right]\frac{(y-y_0)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,j+1,0}\frac{(x-x_0)^{r-1}}{(r-1)!} + C_{1,j+1,0}\frac{(x-x_1)^{r-1}}{(r-1)!}\right]\frac{(y-y_{j+1})^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!}, \end{aligned} \]

next, one assumes that we have the formula

(5.3.20)
\[ \begin{aligned} &\frac{\partial^{3(n-r)}\varphi_{i',j+1,0}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r}} = \left[C_{0,0,0}\frac{(x-x_0)^{r-1}}{(r-1)!} + \ldots + C_{i',0,0}\frac{(x-x_{i'})^{r-1}}{(r-1)!}\right]\frac{(y-y_0)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,j+1,0}\frac{(x-x_0)^{r-1}}{(r-1)!} + \ldots + C_{i',j+1,0}\frac{(x-x_{i'})^{r-1}}{(r-1)!}\right]\frac{(y-y_{j+1})^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!} \end{aligned} \]

valid for \(i' = 1, 2, \ldots, i\), which is true for \(i' = 1\), because in this case formula (5.3.20) coincides with formula (5.3.19). We shall prove that formula (5.3.20) also holds for \(i' = i + 1\). To this end we shall integrate the partial differential equation

\[ \frac{\partial^{3n}\varphi_{i+1,j+1,0}}{\partial x^n \partial y^n \partial z^n} = 0 \]

with the boundary conditions (5.3.2), (5.3.3), (5.3.4) corresponding to the indices \(i + 1\), \(j + 1\), \(0\).

To write these conditions one uses formula (5.3.20) for \(i' = i\) and formula (5.3.15) for \(l = j\). One arrives at the formula giving the derivative \(\frac{\partial^{3(n-r)}\varphi_{i+1,j+1,0}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r}}\), valid for \(r = 1, 2, \ldots, n\). One finds that this formula is obtained from formula (5.3.20) by replacing \(i'\) by \(i + 1\).

It follows that formula (5.3.20) is general; it is valid for \(i' = 1, 2, \ldots, n-1\). But formula (5.3.20) is obtained from formula (5.3.15) by replacing \(l\) by \(j+1\). Formula (5.3.15) is therefore general; it is valid for \(i = 1, 2, \ldots, n-1\) and \(l = 1, 2, \ldots, n-1\).

It remains to show how the constants \(C_{0,j+1,0}, \ldots, C_{n,j+1,0}\) are determined.

5.3.4. Taking convention (A) into account, the boundary conditions (5.3.2), (5.3.3), (5.3.4) for \(i = n\) are

(5.3.21)
\[ \begin{gathered} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r}}[\varphi_{n-1,j+1,0}]_{x_n, y, z} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r-1}}[\varphi_{n-1,j+1,0}]_{x_n, y, z_0} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r}}[\varphi_{n-1,j,0} - \varphi_{n-1,j+1,0}]_{x_n, y_{j+1}, z} = 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}[\varphi_{n-1,j,0} - \varphi_{n-1,j+1,0}]_{x_n, y_{j+1}, z_0} = \begin{cases} C_{n,j+1,0} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases}, \end{gathered} \]

Setting \(i = n-1\), \(l = j+1\), \(r = n\) in formula (5.3.15), we have

(5.3.22)
\[ \begin{aligned} &\varphi_{n-1,j+1,0}(x, y, z) = \left[C_{0,0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!}\,\frac{(z-z_0)^{n-1}}{(n-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,j+1,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,j+1,0}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_{j+1})^{n-1}}{(n-1)!}\,\frac{(z-z_0)^{n-1}}{(n-1)!} \end{aligned} \]

and further, replacing \(j + 1\) by \(j\), we have

(5.3.23)
\[ \begin{aligned} &\varphi_{n-1,j,0}(x, y, z) = \left[C_{0,0,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_0)^{n-1}}{(n-1)!}\,\frac{(z-z_0)^{n-1}}{(n-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,j,0}\frac{(x-x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,j,0}\frac{(x-x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y-y_j)^{n-1}}{(n-1)!}\,\frac{(z-z_0)^{n-1}}{(n-1)!} \end{aligned} \]

For \(r = 0\), the first three conditions (5.3.21) are satisfied, because \(\varphi_{n-1,j+1,0}\) and \(\varphi_{n-1,j,0}\) are polynomials of degree \(n-1\) in \(z\) and \(y\).

The fourth condition gives the equation

(5.3.24)
\[ C_{0,j+1,0} + \ldots + C_{n,j+1,0} = 0. \]

We have

\[ \begin{aligned} &\frac{\partial^{3(n-r)-1}\varphi_{n-1,j+1,0}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r}}(x_n, y, z) = \left[C_{0,0,0}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,0,0}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_0)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,j,0}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,j,0}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_j)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!} + \\ &+ \left[C_{0,j+1,0}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,j+1,0}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_{j+1})^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!} \end{aligned} \]

and since equation (5.3.16) is satisfied for \(r = 1, 2, \ldots, n-1\) and \(l = 1, 2, \ldots, j\), the preceding formula reduces to

\[ \frac{\partial^{3(n-r)-1}\varphi_{n-1,j+1,0}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r}}(x_n, y, z) = \left[C_{0,j+1,0}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,j+1,0}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_{j+1})^{r-1}}{(r-1)!}\,\frac{(z-z_0)^{r-1}}{(r-1)!}. \]

For the first condition (5.3.21) to be satisfied for \(r = 1, 2, \ldots, n-1\), we must take

(5.3.25)
\[ C_{0,j+1,0}(x_n - x_0)^r + \ldots + C_{n-1,j+1,0}(x_n - x_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n-1, \]

which shows that the constants \(C_{0,j+1,0}, \ldots, C_{n-1,j+1,0}\) satisfy system (5.3.16), i.e. system (5.3.17).

It remains to see that the other conditions (5.3.21) are also satisfied.

We have

(5.3.26)
\[ \begin{aligned} &\frac{\partial^{3(n-r)-2}\varphi_{n-1,j+1,0}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r-1}}(x_n, y, z) = \left[C_{0,0,0}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,0,0}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_0)^{r-1}}{(r-1)!}\,\frac{(z-z_0)^r}{r!} + \\ &+ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ &+ \left[C_{0,j+1,0}\frac{(x_n-x_0)^r}{r!} + \ldots + C_{n-1,j+1,0}\frac{(x_n-x_{n-1})^r}{r!}\right]\frac{(y-y_{j+1})^{r-1}}{(r-1)!}\,\frac{(z-z_0)^r}{r!} \end{aligned} \]

and the right-hand side vanishes because, by equations (5.3.16), each large bracket vanishes for \(r = 1, 2, \ldots, n-1\) and \(l = 0, 1, \ldots, j, j+1\). Hence conditions (5.3.21) are satisfied for \(r = 1, 2, \ldots, n-1\).

We have

(5.3.27)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} \left[\varphi_{n-1,j,0} - \varphi_{n-1,j+1,0}\right]_{x_n, y, z} = \\ & = -\left[C_{0,j+1,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,0} \frac{(x_n - x_{n-1})^r}{r!}\right] \frac{(y - y_{j+1})^r}{r!} \frac{(z - z_0)^{r-1}}{(r-1)!} \end{aligned} \]

and the right-hand side vanishes, as equations (5.3.25) show, for \(r = 1, 2, \ldots, n-1\). Hence conditions (5.3.21) are satisfied for \(r = 1, 2, \ldots, n-1\).

Finally, we have

(5.3.28)
\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \left[\varphi_{n-1,j,0} - \varphi_{n-1,j+1,0}\right]_{x_n, y, z} = \\ & = -\left[C_{0,j+1,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,0} \frac{(x_n - x_{n-1})^r}{r!}\right] \frac{(y - y_{j+1})^r}{r!} \frac{(z - z_0)^r}{r!} \end{aligned} \]

and therefore the last condition (5.3.21) is satisfied for \(r = 1, 2, \ldots, n-1\).

5.3.5. If in formula (5.3.15) we set \(i = n-1\) and take systems (5.3.17) into account, for \(l = 0, 1, \ldots, j\) we obtain the formula

(5.3.29)
\[ \varphi_{n-1,j,0} = -\left[C_{n,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{n,j,0} \frac{(y - y_j)^{n-1}}{(n-1)!}\right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} \]

which will be used later; it is valid for \(j = 0, 1, \ldots, n-1\).

5.3.6. We wish to show that the constants \(C_{i,j,0}\) also satisfy the systems of equations

(5.3.30)
\[ C_{i,0,0} + \ldots + C_{i,n,0} = 0 \]
(5.3.31)
\[ C_{i,0,0}(y_n - y_0)^r + \ldots + C_{i,n-1,0}(y_n - y_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\) and \(i = 0, 1, \ldots, n-1\), i.e. the system of equations

(5.3.32)
\[ \begin{array}{lll} C_{i,0,0} & + \ldots + C_{i,n,0} & = 0 \\ C_{i,0,0} y_0 & + \ldots + C_{i,n,0} y_n & = 0 \\ \ldots\ldots\ldots & \ldots\ldots\ldots\ldots\ldots & \ldots \\ C_{i,0,0} y_0^{n-1} & + \ldots + C_{i,n,0} y_n^{n-1} & = 0 \end{array} \]

for \(i = 0, 1, \ldots, n-1\).

The system formed by equations (5.3.30) and (5.3.31) is true for \(i = 0\), because in this case it coincides with the system formed by equations (5.2.31) and (5.2.32).

To this end we set \(j = n\) in the boundary conditions (5.3.2), (5.3.3), (5.3.4) and take convention (A) into account. We obtain the conditions

(5.3.33)
\[ \begin{gathered} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} \left[\varphi_{i,n-1,0}\right]_{x, y_n, z} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} \left[\varphi_{i,n-1,0}\right]_{x, y_n, z_0} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} \left[\varphi_{i-1,n-1,0} - \varphi_{i,n-1,0}\right]_{x_i, y_n, z} = 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \left[\varphi_{i-1,n-1,0} - \varphi_{i,n-1,0}\right]_{x_i, y_n, z_0} = \begin{cases} C_{i,n,0} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{gathered} \]

for \(r = 0, 1, \ldots, n-1\).

We write formulas (5.3.15) for \(l = n-1\) in the form

(5.3.34)
\[ \begin{aligned} & \frac{\partial^{3(n-r)} \varphi_{i,n-1,0}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}(x, y, z) = \left[C_{0,0,0} \frac{(y - y_0)^{r-1}}{(r-1)!} + \ldots + C_{0,n-1,0} \frac{(y - y_{n-1})^{r-1}}{(r-1)!}\right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{i,0,0} \frac{(y - y_0)^{r-1}}{(r-1)!} + \ldots + C_{i,n-1,0} \frac{(y - y_{n-1})^{r-1}}{(r-1)!}\right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} \end{aligned} \]

valid for \(i = 0, 1, \ldots, n-1\) and \(r = 1, 2, \ldots, n\).

Setting \(r = 0\) in formulas (5.3.33), we obtain the conditions

(5.3.35)
\[ \begin{gathered} \frac{\partial^{3n-1}}{\partial x^n \partial y^{n-1} \partial z^n} \left[\varphi_{i,n-1,0}\right]_{x, y_n, z} = 0 \\ \frac{\partial^{3n-2}}{\partial x^n \partial y^{n-1} \partial z^{n-1}} \left[\varphi_{i,n-1,0}\right]_{x, y_n, z_0} = 0 \\ \frac{\partial^{3n-2}}{\partial x^{n-1} \partial y^{n-1} \partial z^n} \left[\varphi_{i-1,n-1,0} - \varphi_{i,n-1,0}\right]_{x_i, y_n, z} = 0 \\ \frac{\partial^{3(n-1)}}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}} \left[\varphi_{i-1,n-1,0} - \varphi_{i,n-1,0}\right]_{x_i, y_n, z_0} = C_{i,n,0} \end{gathered} \]

The first three conditions are satisfied because \(\varphi_{i,n-1,0}\) and \(\varphi_{i-1,n-1,0}\) are polynomials of degree \(n-1\) in \(x\), in \(y\) and in \(z\).

The last condition (5.3.35) gives the equation

(5.3.36)
\[ C_{i,0,0} + \ldots + C_{i,n-1,0} + C_{i,n,0} = 0 \]

valid for \(i = 0, 1, \ldots, n-1\).

Let us now examine conditions (5.3.33) for \(r = 1, 2, \ldots n-1\). We have

\[ \begin{aligned} & \varphi_{i,n-1,0}(x, y, z) = \left[C_{0,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!}\right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{i,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!}\right] \frac{(x - x_i)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} \end{aligned} \]

and therefore

\[ \begin{aligned} & \frac{\partial^{3(n-r)-1} \varphi_{i,n-1,0}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}}(x, y_n, z) = \left[C_{0,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{0,n-1,0} \frac{(y_n - y_{n-1})^r}{r!}\right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{i,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,0} \frac{(y_n - y_{n-1})^r}{r!}\right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} \end{aligned} \]

The first large bracket on the right-hand side vanishes for \(r = 1, 2, \ldots, n-1\) by equations (5.2.32), and for the first conditions (5.3.33) to be satisfied for \(r = 1, 2, \ldots, n-1\) and \(i = 1, 2, \ldots, n-1\), equations (5.3.31) must hold for \(r = 1, 2, \ldots, n-1\). Likewise, we have

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} \left[\varphi_{i,n-1,0}\right]_{x, y_n, z} = \left[C_{0,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{0,n-1,0} \frac{(y_n - y_{n-1})^r}{r!}\right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^r}{r!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{i,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,0} \frac{(y_n - y_{n-1})^r}{r!}\right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(z - z_0)^r}{r!} \end{aligned} \]
\[ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} \left[\varphi_{i-1,n-1,0} - \varphi_{i,n-1,0}\right]_{x, y_n, z} = -\left[C_{i,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,0} \frac{(y_n - y_{n-1})^r}{r!}\right] \frac{(x - x_i)^r}{r!} \frac{(z - z_0)^{r-1}}{(r-1)!} \]
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \left[\varphi_{i-1,n-1,0} - \varphi_{i,n-1,0}\right]_{x, y_n, z} = -\left[C_{i,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,0} \frac{(y_n - y_{n-1})^r}{r!}\right] \frac{(x - x_i)^r}{r!} \frac{(z - z_0)^r}{r!} \]

and one sees from equations (5.3.31) that the other conditions (5.3.33) are satisfied for \(r = 1, 2, \ldots, n-1\).

5.3.7. Let us now prove that the system of equations

(5.3.17)
\[ \begin{array}{lll} C_{0,j,0} & + \ldots + C_{n,j,0} & = 0 \\ C_{0,j,0} x_0 & + \ldots + C_{n,j,0} x_n & = 0 \\ \ldots\ldots\ldots & \ldots\ldots\ldots\ldots\ldots & \ldots \\ C_{0,j,0} x_0^{n-1} & + \ldots + C_{n,j,0} x_n^{n-1} & = 0 \end{array} \]

which is valid for \(j = 0, 1, \ldots, n-1\), is also valid for \(j = n\), and that the system of equations

(5.3.32)
\[ \begin{array}{lll} C_{i,0,0} & + \ldots + C_{i,n,0} & = 0 \\ C_{i,0,0} y_0 & + \ldots + C_{i,n,0} y_n & = 0 \\ \ldots\ldots\ldots & \ldots\ldots\ldots\ldots\ldots & \ldots \\ C_{i,0,0} y_0^{n-1} & + \ldots + C_{i,n,0} y_n^{n-1} & = 0 \end{array} \]

which is valid for \(i = 0, 1, \ldots, n-1\), is also valid for \(i = n\).

To this end we observe that the formula

(5.3.36)
\[ \begin{aligned} \varphi_{i,j,0}(x, y, z) = {} & \left[C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0,0} \frac{(x - x_i)^{n-1}}{(n-1)!}\right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{0,j,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,j,0} \frac{(x - x_i)^{n-1}}{(n-1)!}\right] \frac{(y - y_j)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} \end{aligned} \]

can be written, by equations (5.3.17), for \(i = n-1\), in the form

(5.3.37)
\[ \varphi_{n-1,j,0}(x, y, z) = -\left[C_{n,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{n,j,0} \frac{(y - y_j)^{n-1}}{(n-1)!}\right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} \]

which is valid for \(j = 0, 1, \ldots, n-1\).

Likewise, formula (5.3.36) can be written, by equations (5.3.32), for \(j = n-1\), in the form

(5.3.38)
\[ \varphi_{i,n-1,0}(x, y, z) = -\left[C_{0,n,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n,0} \frac{(x - x_i)^{n-1}}{(n-1)!}\right] \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!}. \]

Finally, we observe that, setting \(i = n-1\) in formula (5.3.38) and \(j = n-1\) in formula (5.3.37), the function \(\varphi_{n-1,n-1,0}\) can be written in the form

(5.3.39)
\[ \varphi_{n-1,n-1,0}(x, y, z) = -\left[C_{0,n,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,n,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right] \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} \]

or in the form

(5.3.40)
\[ \varphi_{n-1,n-1,0}(x, y, z) = -\left[C_{n,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{n,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!}\right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!}. \]

Let us write the boundary conditions (5.3.2), (5.3.3), (5.3.4) for \(i = n\) and \(j = n\). By convention (A), these conditions are

(5.3.41)
\[ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} \left[\varphi_{n-1,n-1,0}\right]_{x_n, y_n, z} = 0 \]

and

(5.3.42)
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \left[\varphi_{n-1,n-1,0}\right]_{x_n, y_n, z_0} = \begin{cases} C_{n,n,0} & \text{if } r = 0, \\ 0 & \text{if } r \neq 0. \end{cases} \]

For \(r = 0\), condition (5.3.41) is satisfied, and condition (5.3.42) leads, by formula (5.3.39), to the equation

(5.3.43)
\[ C_{0,n,0} + \ldots + C_{n-1,n,0} + C_{n,n,0} = 0 \]

and, by formula (5.3.40), to the equation

(5.3.44)
\[ C_{n,0,0} + \ldots + C_{n,n-1,0} + C_{n,n,0} = 0. \]

Let us now consider conditions (5.3.2), (5.3.3), (5.3.4) for \(i = n\), \(j = n-1\) and then for \(i = n-1\), \(j = n\). Of these conditions we take only the following:

(5.3.45)
\[ \frac{\partial^{3(n-r)-1} \varphi_{n-1,n-1,0}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}}(x_n, y, z) = 0 \]

and

(5.3.46)
\[ \frac{\partial^{3(n-r)-1} \varphi_{n-1,n-1,0}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}}(x, y_n, z) = 0 \]

which are satisfied for \(r = 0\).

Using formula (5.3.39) we have

\[ \frac{\partial^{3(n-r)-1} \varphi_{n-1,n-1,0}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}}(x_n, y, z) = -\left[C_{0,n,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,0} \frac{(x_n - x_{n-1})^r}{r!}\right] \frac{(y - y_n)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} \]

and, using formula (5.3.40), we have

\[ \frac{\partial^{3(n-r)-1} \varphi_{n-1,n-1,0}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}}(x, y_n, z) = -\left[C_{n,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{n,n-1,0} \frac{(y_n - y_{n-1})^r}{r!}\right] \frac{(x - x_n)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!}. \]

For conditions (5.3.45), (5.3.46) to be satisfied for \(r = 1, 2, \ldots, n-1\), we must take

(5.3.47)
\[ C_{0,n,0}(x_n - x_0)^r + \ldots + C_{n-1,n,0}(x_n - x_{n-1})^r = 0 \]

and

(5.3.48)
\[ C_{n,0,0}(y_n - y_0)^r + \ldots + C_{n,n-1,0}(y_n - y_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n-1. \]

The system formed by equations (5.3.43) and (5.3.44) shows that system (5.3.17) is also valid for \(j = n\).

The system formed by equations (5.3.44) and (5.3.48) shows that system (5.3.32) is also valid for \(i = n\).

Let us observe, finally, that by formula (5.3.39) we have

\[ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} \left[\varphi_{n-1,n-1,0}\right]_{x_n, y, z} = -\left[C_{0,n,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,0} \frac{(x_n - x_{n-1})^r}{r!}\right] \frac{(y - y_n)^r}{r!} \frac{(z - z_0)^{r-1}}{(r-1)!} \]

and

\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \left[\varphi_{n-1,n-1,0}\right]_{x_n, y, z} = -\left[C_{0,n,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,0} \frac{(x_n - x_{n-1})^r}{r!}\right] \frac{(y - y_n)^r}{r!} \frac{(z - z_0)^r}{r!} \]

and by equations (5.3.47) it follows that conditions (5.3.41) and (5.3.42) are satisfied for \(r = 1, 2, \ldots, n-1\).

5.3.8. In summary, the solution of the boundary value problem posed in subsection 5.3.1 is as in formula (5.3.15), i.e.

(5.3.15)
\[ \begin{aligned} & \varphi_{i,j,0}(x, y, z) = \left[C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0,0} \frac{(x - x_i)^{n-1}}{(n-1)!}\right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{0,j,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,j,0} \frac{(x - x_i)^{n-1}}{(n-1)!}\right] \frac{(y - y_j)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!}, \end{aligned} \]

where the constants \(C_{i,j,0} (i, j = 0, 1, \ldots, n)\) satisfy the systems of equations

(5.3.17)
\[ \begin{array}{lll} C_{0,j,0} & + \ldots + C_{n,j,0} & = 0 \\ C_{0,j,0} x_0 & + \ldots + C_{n,j,0} x_n & = 0 \\ \ldots\ldots\ldots & \ldots\ldots\ldots\ldots\ldots & \ldots \\ C_{0,j,0} x_0^{n-1} & + \ldots + C_{n,j,0} x_n^{n-1} & = 0 \end{array} \]

for \(j = 0, 1, \ldots, n\) and

(5.3.32)
\[ \begin{array}{lll} C_{i,0,0} & + \ldots + C_{i,n,0} & = 0 \\ C_{i,0,0} y_0 & + \ldots + C_{i,n,0} y_n & = 0 \\ \ldots\ldots\ldots & \ldots\ldots\ldots\ldots\ldots & \ldots \\ C_{i,0,0} y_0^{n-1} & + \ldots + C_{i,n,0} y_n^{n-1} & = 0 \end{array} \]

for \(i = 0, 1, \ldots, n\).

Taking these systems into account, formulas (5.3.39) and (5.3.40) can be written in the form

(5.3.49)
\[ \varphi_{n-1,n-1,0}(x, y, z) = C_{n,n,0} \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!}. \]

5.3.9. If in the boundary conditions (5.2.5) and (5.2.6) we set \(i = 0\) and take convention (A) into account, we obtain

Problem \((P_{0,j,k})\). Determine the solutions of the partial differential equations

(5.3.50)
\[ \frac{\partial^{3n} \varphi_{0,j,k}}{\partial x^n \partial y^n \partial z^n} = 0 \quad \text{for } j, k = 0, 1, \ldots, n-1 \]

which satisfy the boundary conditions:

(5.3.51)
\[ \begin{gathered} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} \left[\varphi_{0,j,k}\right]_{x_0, y, z} = 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} \left[\varphi_{0,j,k} - \varphi_{0,j-1,k}\right]_{x, y_j, z} = 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} \left[\varphi_{0,j,k} - \varphi_{0,j,k-1}\right]_{x, y, z_k} = 0 \end{gathered} \]

for \(j, k = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Next,

(5.3.52)
\[ \begin{gathered} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} \left[\varphi_{0,j,k} + \varphi_{0,j-1,k-1} - \varphi_{0,j,k-1} - \varphi_{0,j-1,k}\right]_{x, y_j, z_k} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} \left[\varphi_{0,j,k} - \varphi_{0,j,k-1}\right]_{x_0, y, z_k} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} \left[\varphi_{0,j,k} - \varphi_{0,j-1,k}\right]_{x_0, y_j, z} = 0 \end{gathered} \]

for \(j, k = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Finally,

(5.3.53)
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \left[\varphi_{0,j,k} + \varphi_{0,j-1,k-1} - \varphi_{0,j-1,k} - \varphi_{0,j,k-1}\right]_{x_0, y_j, z_k} = \begin{cases} C_{0,j,k} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \]

for \(j, k = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Proceeding as in subsections 5.3.2 – 5.3.8, one proves that the solution of this problem is given by the formula

(5.3.54)
\[ \begin{aligned} & \varphi_{0,j,k}(x, y, z) = \left[C_{0,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,j,0} \frac{(y - y_j)^{n-1}}{(n-1)!}\right] \frac{(z - z_0)^{n-1}}{(n-1)!} \frac{(x - x_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{0,0,k} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,j,k} \frac{(y - y_j)^{n-1}}{(n-1)!}\right] \frac{(z - z_k)^{n-1}}{(n-1)!} \frac{(x - x_0)^{n-1}}{(n-1)!}, \end{aligned} \]

where the constants \(C_{0,j,k}\) satisfy, for \(j, k = 0, 1, \ldots, n\), the systems of equations

(5.3.55)
\[ \begin{array}{lll} C_{0,0,k} & + \ldots + C_{0,n,k} & = 0 \\ C_{0,0,k} y_0 & + \ldots + C_{0,n,k} y_n & = 0 \\ \ldots\ldots\ldots & \ldots\ldots\ldots\ldots\ldots & \ldots \\ C_{0,0,k} y_0^{n-1} & + \ldots + C_{0,n,k} y_n^{n-1} & = 0 \end{array} \]

and

(5.3.56)
\[ \begin{array}{lll} C_{0,j,0} & + \ldots + C_{0,j,n} & = 0 \\ C_{0,j,0} z_0 & + \ldots + C_{0,j,n} z_n & = 0 \\ \ldots\ldots\ldots & \ldots\ldots\ldots\ldots\ldots & \ldots \\ C_{0,j,0} z_0^{n-1} & + \ldots + C_{0,j,n} z_n^{n-1} & = 0. \end{array} \]

Taking these systems into account, one can write

(5.3.57)
\[ \varphi_{0,n-1,n-1}(x, y, z) = C_{0,n,n} \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(z - z_n)^{n-1}}{(n-1)!}. \]

5.3.10. If in the boundary conditions (5.2.5) and (5.2.6) we set \(j = 0\) and take convention (A) into account, we obtain

Problem \((P_{i,0,k})\). Determine the solutions of the partial differential equations

(5.3.58)
\[ \frac{\partial^{3n} \varphi_{i,0,k}}{\partial x^n \partial y^n \partial z^n} = 0 \quad \text{for } i, k = 0, 1, \ldots, n-1 \]

satisfying the boundary conditions:

(5.3.59)
\[ \begin{gathered} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} \left[\varphi_{i,0,k} - \varphi_{i-1,0,k}\right]_{x_i, y, z} = 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} \left[\varphi_{i,0,k}\right]_{x, y_0, z} = 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} \left[\varphi_{i,0,k} - \varphi_{i,0,k-1}\right]_{x, y, z_k} = 0 \end{gathered} \]

for \(i, k = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Further,

(5.3.60)
\[ \begin{gathered} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} \left[\varphi_{i,0,k} - \varphi_{i,0,k-1}\right]_{x, y_0, z_k} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} \left[\varphi_{i,0,k} + \varphi_{i-1,0,k-1} - \varphi_{i,0,k-1} - \varphi_{i-1,0,k}\right]_{x_i, y, z_k} = 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} \left[\varphi_{i,0,k} - \varphi_{i-1,0,k}\right]_{x_i, y_0, z} = 0 \end{gathered} \]

for \(i, k = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Finally,

(5.3.61)
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \left[\varphi_{i,0,k} + \varphi_{i-1,0,k-1} - \varphi_{i-1,0,k} - \varphi_{i,0,k-1}\right]_{x_i, y_0, z_k} = \begin{cases} C_{i,0,k} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \]

for \(i, k = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Proceeding as in subsections 5.3.2 – 5.3.8, one proves that the solution of this problem is given by the formula

(5.3.62)
\[ \begin{aligned} & \varphi_{i,0,k}(x, y, z) = \left[C_{0,0,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{0,0,k} \frac{(z - z_k)^{n-1}}{(n-1)!}\right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{i,0,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0,k} \frac{(z - z_k)^{n-1}}{(n-1)!}\right] \frac{(x - x_i)^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!} \end{aligned} \]

where the constants \(C_{i,0,k}\) satisfy, for \(i, k = 0, 1, \ldots, n\), the systems of equations

(5.3.63)
\[ \begin{array}{lll} C_{0,0,k} & + \ldots + C_{n,0,k} & = 0 \\ C_{0,0,k} x_0 & + \ldots + C_{n,0,k} x_n & = 0 \\ \ldots\ldots\ldots & \ldots\ldots\ldots\ldots\ldots & \ldots \\ C_{0,0,k} x_0^{n-1} & + \ldots + C_{n,0,k} x_n^{n-1} & = 0 \end{array} \]

and

(5.3.64)
\[ \begin{array}{lll} C_{i,0,0} & + \ldots + C_{i,0,n} & = 0 \\ C_{i,0,0} z_0 & + \ldots + C_{i,0,n} z_n & = 0 \\ \ldots\ldots\ldots & \ldots\ldots\ldots\ldots\ldots & \ldots \\ C_{i,0,0} z_0^{n-1} & + \ldots + C_{i,0,n} z_n^{n-1} & = 0 \end{array} \]
(5.3.65)
\[ \varphi_{n-1,0,n-1}(x, y, z) = C_{n,0,n} \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_n)^{n-1}}{(n-1)!}. \]

§ 5.4. The problem \((P_{i,j,1})\)

In this section we determine the solution \(\varphi_{i,j,1}\) of problem \((P_{i,j,1})\), following the same method as the one used to determine the function \(\varphi_{i,j,0}\), but with new boundary conditions which must be satisfied by the functions \(\varphi_{i,j,1}\). The functions \(\varphi_{i,j,0}\), \(\varphi_{i,0,k}\), \(\varphi_{0,j,k}\), \(\varphi_{i,0,0}\), \(\varphi_{0,j,0}\), \(\varphi_{0,0,k}\), \(\varphi_{0,0,0}\) determined in the preceding sections enter here, but with new boundary conditions for \(\varphi_{i,j,1}\). This section is an introduction to the general case.

5.4.1. Let us first determine the function \(\varphi_{1,1,1}\)

For this we must integrate the partial differential equation

(5.4.1)
\[ \frac{\partial^{3n}\varphi_{1,1,1}}{\partial x^n \partial y^n \partial z^n} = 0 \]

with the boundary conditions (5.2.5), (5.2.6), (5.2.7) corresponding to the indices \(i = 1\), \(j = 1\), \(k = 1\). These conditions are

(5.4.2)
\[ \begin{aligned} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r}}[\varphi_{1,1,1} - \varphi_{0,1,1}]_{x_1,y,z} &= 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r}\partial y^{n-r-1}\partial z^{n-r}}[\varphi_{1,1,1} - \varphi_{1,0,1}]_{x,y_1,z} &= 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r-1}}[\varphi_{1,1,1} - \varphi_{1,1,0}]_{x,y,z_1} &= 0 \end{aligned} \]

further,

(5.4.3)
\[ \begin{aligned} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r}\partial y^{n-r-1}\partial z^{n-r-1}}[\varphi_{1,1,1} + \varphi_{1,0,0} - \varphi_{1,1,0} - \varphi_{1,0,1}]_{x,y_1,z_1} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r-1}}[\varphi_{1,1,1} + \varphi_{0,1,0} - \varphi_{1,1,0} - \varphi_{0,1,1}]_{x_1,y,z_1} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r}}[\varphi_{1,1,1} + \varphi_{0,0,1} - \varphi_{1,0,1} - \varphi_{0,1,1}]_{x_1 y_1 z} &= 0. \end{aligned} \]

Finally,

(5.4.4)
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}\Bigl[(\varphi_{1,1,1} + \varphi_{0,0,1} - \varphi_{1,0,1} - \varphi_{0,1,1}) - (\varphi_{1,1,0} + \varphi_{0,0,0} - \varphi_{1,0,0} - \varphi_{0,1,0})\Bigr]_{x_1 y_1 z_1} = \begin{cases} C_{1,1,1} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \]

We can solve this problem because in § 5.2 and § 5.3 we have determined the functions \(\varphi_{0,0,0}\), \(\varphi_{1,0,0}\), \(\varphi_{0,1,0}\), \(\varphi_{0,0,1}\), \(\varphi_{1,1,0}\), \(\varphi_{1,0,1}\), \(\varphi_{0,1,1}\).

We found

(5.4.5)
\[ \varphi_{0,0,0} = C_{0,0,0}\frac{(x - x_0)^{n-1}}{(n-1)!}\frac{(y - y_0)^{n-1}}{(n-1)!}\frac{(z - z_0)^{n-1}}{(n-1)!} \]
(5.4.6)
\[ \begin{aligned} \varphi_{1,0,0}(x, y, z) &= \biggl[C_{0,0,0}\frac{(x - x_0)^{n-1}}{(n-1)!} + {} \\ &\qquad + C_{1,0,0}\frac{(x - x_1)^{n-1}}{(n-1)!}\biggr]\frac{(y - y_0)^{n-1}}{(n-1)!}\frac{(z - z_0)^{n-1}}{(n-1)!} \\ \varphi_{0,1,0}(x, y, z) &= \biggl[C_{0,0,0}\frac{(y - y_0)^{n-1}}{(n-1)!} + {} \\ &\qquad + C_{0,1,0}\frac{(y - y_1)^{n-1}}{(n-1)!}\biggr]\frac{(z - z_0)^{n-1}}{(n-1)!}\frac{(x - x_0)^{n-1}}{(n-1)!} \\ \varphi_{0,0,1}(x, y, z) &= \biggl[C_{0,0,0}\frac{(z - z_0)^{n-1}}{(n-1)!} + {} \\ &\qquad + C_{0,0,1}\frac{(z - z_1)^{n-1}}{(n-1)!}\biggr]\frac{(x - x_0)^{n-1}}{(n-1)!}\frac{(y - y_0)^{n-1}}{(n-1)!} \end{aligned} \]
(5.4.7)
\[ \begin{aligned} \varphi_{1,1,0}(x, y, z) &= \biggl[C_{0,0,0}\frac{(x - x_0)^{n-1}}{(n-1)!} + C_{1,0,0}\frac{(x - x_1)^{n-1}}{(n-1)!}\biggr]\frac{(y - y_0)^{n-1}}{(n-1)!}\frac{(z - z_0)^{n-1}}{(n-1)!} + {} \\ &\qquad + \biggl[C_{0,1,0}\frac{(x - x_0)^{n-1}}{(n-1)!} + C_{1,1,0}\frac{(x - x_1)^{n-1}}{(n-1)!}\biggr]\frac{(y - y_1)^{n-1}}{(n-1)!}\frac{(z - z_0)^{n-1}}{(n-1)!} \\ \varphi_{0,1,1}(x, y, z) &= \biggl[C_{0,0,0}\frac{(y - y_0)^{n-1}}{(n-1)!} + C_{0,1,0}\frac{(y - y_1)^{n-1}}{(n-1)!}\biggr]\frac{(z - z_0)^{n-1}}{(n-1)!}\frac{(x - x_0)^{n-1}}{(n-1)!} + {} \\ &\qquad + \biggl[C_{0,0,1}\frac{(y - y_0)^{n-1}}{(n-1)!} + C_{0,1,1}\frac{(y - y_1)^{n-1}}{(n-1)!}\biggr]\frac{(z - z_1)^{n-1}}{(n-1)!}\frac{(x - x_0)^{n-1}}{(n-1)!} \end{aligned} \]
\[ \begin{aligned} \varphi_{1,0,1}(x, y, z) &= \biggl[C_{0,0,0}\frac{(z - z_0)^{n-1}}{(n-1)!} + C_{0,0,1}\frac{(z - z_1)^{n-1}}{(n-1)!}\biggr]\frac{(x - x_0)^{n-1}}{(n-1)!}\frac{(y - y_0)^{n-1}}{(n-1)!} + {} \\ &\qquad + \biggl[C_{1,0,0}\frac{(z - z_0)^{n-1}}{(n-1)!} + C_{1,0,1}\frac{(z - z_1)^{n-1}}{(n-1)!}\biggr]\frac{(x - x_1)^{n-1}}{(n-1)!}\frac{(y - y_0)^{n-1}}{(n-1)!}. \end{aligned} \]

Then, taking these formulas into account, it follows that

\[ \frac{\partial^{3n-1}\varphi_{1,1,1}}{\partial x^{n-1}\partial y^n\partial z^n}(x_1, y, z) = 0, \qquad \frac{\partial^{3n-1}\varphi_{1,1,1}}{\partial x^n\partial y^{n-1}\partial z^n}(x, y_1, z) = 0, \]
\[ \frac{\partial^{3n-1}\varphi_{1,1,1}}{\partial x^n\partial y^n\partial z^{n-1}}(x, y, z_1) = 0, \]
\[ \frac{\partial^{3n-2}\varphi_{1,1,1}}{\partial x^n\partial y^{n-1}\partial z^{n-1}}(x, y_1, z_1) = 0, \qquad \frac{\partial^{3n-2}\varphi_{1,1,1}}{\partial x^{n-1}\partial y^n\partial z^{n-1}}(x_1, y, z_1) = 0, \]
\[ \frac{\partial^{3n-2}\varphi_{1,1,1}}{\partial x^{n-1}\partial y^{n-1}\partial z^n}(x_1, y_1, z) = 0 \]
\[ \frac{\partial^{3(n-1)}\varphi_{1,1,1}}{\partial x^{n-1}\partial y^{n-1}\partial z^{n-1}}(x_1, y_1, z_1) = (C_{0,0,0} + C_{1,0,0}) + (C_{0,1,0} + C_{1,1,0}) + (C_{0,0,1} + C_{1,0,1}) + (C_{0,1,1} + C_{1,1,1}). \]

Integrating equation (5.4.1) with these conditions, one finds

(5.4.8)
\[ \frac{\partial^{3(n-1)}\varphi_{1,1,1}}{\partial x^{n-1}\partial y^{n-1}\partial z^{n-1}}(x, y, z) = (C_{0,0,0} + C_{1,0,0}) + (C_{0,1,0} + C_{1,1,0}) + (C_{0,0,1} + C_{1,0,1}) + (C_{0,1,1} + C_{1,1,1}). \]

Next, we must integrate equation (5.4.1) with the boundary conditions (5.4.2), (5.4.3), (5.4.4). For this it is useful to write down the following formulas, which follow from formulas (5.4.5), (5.4.6), (5.4.7):

(5.4.9)
\[ \begin{aligned} \frac{\partial^{3(n-r-1)}\varphi_{0,0,0}(x, y, z)}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}} &= C_{0,0,0}\frac{(x - x_0)^r}{r!}\frac{(y - y_0)^r}{r!}\frac{(z - z_0)^r}{r!} \\ \frac{\partial^{3(n-r-1)}\varphi_{1,0,0}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}(x, y, z) &= \left[C_{0,0,0}\frac{(x - x_0)^r}{r!} + C_{1,0,0}\frac{(x - x_1)^r}{r!}\right]\frac{(y - y_0)^r}{r!}\frac{(z - z_0)^r}{r!} \\ \frac{\partial^{3(n-r-1)}\varphi_{0,1,0}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}(x, y, z) &= \left[C_{0,0,0}\frac{(y - y_0)^r}{r!} + C_{0,1,0}\frac{(y - y_1)^r}{r!}\right]\frac{(z - z_0)^r}{r!}\frac{(x - x_0)^r}{r!} \\ \frac{\partial^{3(n-r-1)}\varphi_{0,0,1}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}(x, y, z) &= \left[C_{0,0,0}\frac{(z - z_0)^r}{r!} + C_{0,0,1}\frac{(z - z_1)^r}{r!}\right]\frac{(x - x_0)^r}{r!}\frac{(y - y_0)^r}{r!} \\ \frac{\partial^{3(n-r-1)}\varphi_{1,1,0}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}(x, y, z) &= \left[C_{0,0,0}\frac{(x - x_0)^r}{r!} + C_{1,0,0}\frac{(x - x_1)^r}{r!}\right]\frac{(y - y_0)^r}{r!}\frac{(z - z_0)^r}{r!} + {} \\ &\quad + \left[C_{0,1,0}\frac{(x - x_0)^r}{r!} + C_{1,1,0}\frac{(x - x_1)^r}{r!}\right]\frac{(y - y_1)^r}{r!}\frac{(z - z_0)^r}{r!} \\ \frac{\partial^{3(n-r-1)}\varphi_{0,1,1}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}(x, y, z) &= \left[C_{0,0,0}\frac{(y - y_0)^r}{r!} + C_{0,1,0}\frac{(y - y_1)^r}{r!}\right]\frac{(z - z_0)^r}{r!}\frac{(x - x_0)^r}{r!} + {} \\ &\quad + \left[C_{0,0,1}\frac{(y - y_0)^r}{r!} + C_{0,1,1}\frac{(y - y_1)^r}{r!}\right]\frac{(z - z_1)^r}{r!}\frac{(x - x_0)^r}{r!} \end{aligned} \]
\[ \begin{aligned} \frac{\partial^{3(n-r-1)}\varphi_{1,0,1}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}(x, y, z) &= \left[C_{0,0,0}\frac{(z - z_0)^r}{r!} + C_{0,0,1}\frac{(z - z_1)^r}{r!}\right] \cdot {} \\ &\cdot \frac{(x - x_0)^r}{r!}\frac{(y - y_0)^r}{r!} + \left[C_{1,0,0}\frac{(z - z_0)^r}{r!} + C_{1,0,1}\frac{(z - z_1)^r}{r!}\right]\frac{(x - x_1)^r}{r!}\frac{(y - y_0)^r}{r!}. \end{aligned} \]

Then, by the boundary conditions (5.4.2), (5.4.3), (5.4.4), for \(r = 1\) we have

\[ \begin{aligned} \frac{\partial^{3n-4}\varphi_{1,1,1}}{\partial x^{n-2}\partial y^{n-1}\partial z^{n-1}}(x_1, y, z) &= (C_{0,0,0} + C_{0,1,0})(x_1 - x_0) + (C_{0,0,1} + C_{0,1,1})(x_1 - x_0) \\ \frac{\partial^{3n-4}\varphi_{1,1,1}}{\partial x^{n-1}\partial y^{n-2}\partial z^{n-1}}(x, y_1, z) &= (C_{0,0,0} + C_{1,0,0})(y_1 - y_0) + (C_{0,0,1} + C_{1,0,1})(y_1 - y_0) \\ \frac{\partial^{3n-4}\varphi_{1,1,1}}{\partial x^{n-1}\partial y^{n-1}\partial z^{n-2}}(x, y, z_1) &= (C_{0,0,0} + C_{1,0,0})(z_1 - z_0) + (C_{0,1,0} + C_{1,1,0})(z_1 - z_0) \\ \frac{\partial^{3n-5}\varphi_{1,1,1}}{\partial x^{n-1}\partial y^{n-2}\partial z^{n-2}}(x, y_1, z_1) &= (C_{0,0,0} + C_{1,0,0})(y_1 - y_0)(z_1 - z_0) \\ \frac{\partial^{3n-5}\varphi_{1,1,1}}{\partial x^{n-2}\partial y^{n-1}\partial z^{n-2}}(x_1, y, z_1) &= (C_{0,0,0} + C_{0,1,0})(x_1 - x_0)(z_1 - z_0) \\ \frac{\partial^{3n-5}\varphi_{1,1,1}}{\partial x^{n-2}\partial y^{n-2}\partial z^{n-1}}(x_1, y_1, z) &= (C_{0,0,0} + C_{0,0,1})(x_1 - x_0)(y_1 - y_0) \\ \frac{\partial^{3(n-2)}\varphi_{1,1,1}}{\partial x^{n-2}\partial y^{n-2}\partial z^{n-2}}(x_1, y_1, z_1) &= C_{0,0,0}(x_1 - x_0)(y_1 - y_0)(z_1 - z_0). \end{aligned} \]

Integrating the partial differential equation (5.4.8) with these conditions, one finds

(5.4.10)
\[ \begin{aligned} \frac{\partial^{3(n-2)}\varphi_{1,1,1}}{\partial x^{n-2}\partial y^{n-2}\partial z^{n-2}}(x, y, z) &= [C_{0,0,0}(x - x_0) + C_{1,0,0}(x - x_1)](y - y_0)(z - z_0) + {} \\ &\quad + [C_{0,1,0}(x - x_0) + C_{1,1,0}(x - x_1)](y - y_1)(z - z_0) + {} \\ &\quad + [C_{0,0,1}(x - x_0) + C_{1,0,1}(x - x_1)](y - y_0)(z - z_1) + {} \\ &\quad + [C_{0,1,1}(x - x_0) + C_{1,1,1}(x - x_1)](y - y_1)(z - z_1). \end{aligned} \]

Let us suppose we have proved that for the index \(r\) we have

(5.4.11)
\[ \begin{aligned} &\frac{\partial^{3(n-r)}\varphi_{1,1,1}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r}}(x, y, z) = \left[C_{0,0,0}\frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0,0}\frac{(x - x_1)^{r-1}}{(r-1)!}\right]\frac{(y - y_0)^{r-1}}{(r-1)!}\frac{(z - z_0)^{r-1}}{(r-1)!} + {} \\ &+ \left[C_{0,1,0}\frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,1,0}\frac{(x - x_1)^{r-1}}{(r-1)!}\right]\frac{(y - y_1)^{r-1}}{(r-1)!}\frac{(z - z_0)^{r-1}}{(r-1)!} + {} \\ &+ \left[C_{0,0,1}\frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0,1}\frac{(x - x_1)^{r-1}}{(r-1)!}\right]\frac{(y - y_0)^{r-1}}{(r-1)!}\frac{(z - z_1)^{r-1}}{(r-1)!} + {} \\ &+ \left[C_{0,1,1}\frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,1,1}\frac{(x - x_1)^{r-1}}{(r-1)!}\right]\frac{(y - y_1)^{r-1}}{(r-1)!}\frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]

which is true for \(r = 2\), because in this case formula (5.4.11) coincides with formula (5.4.10).

We shall prove that formula (5.4.11) also holds for the index \(r + 1\).

To this end we shall integrate equation (5.4.11) with the boundary conditions (5.4.2), (5.4.3), (5.4.4) relative to the index \(r\). By formulas (5.4.9) we shall have

\[ \begin{aligned} &\frac{\partial^{3(n-r)-1}\varphi_{1,1,1}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r}}(x_1, y, z) = \left[C_{0,0,0}\frac{(y - y_0)^{r-1}}{(r-1)!} + C_{0,1,0}\frac{(y - y_1)^{r-1}}{(r-1)!}\right]\frac{(x_1 - x_0)^r}{r!}\frac{(z - z_0)^{r-1}}{(r-1)!} + {} \\ &+ \left[C_{0,0,1}\frac{(y - y_0)^{r-1}}{(r-1)!} + C_{0,1,1}\frac{(y - y_1)^{r-1}}{(r-1)!}\right]\frac{(x_1 - x_0)^r}{r!}\frac{(z - z_1)^{r-1}}{(r-1)!} \\ &\frac{\partial^{3(n-r)-1}\varphi_{1,1,1}}{\partial x^{n-r}\partial y^{n-r-1}\partial z^{n-r}}(x, y_1, z) = \left[C_{0,0,0}\frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0,0}\frac{(x - x_1)^{r-1}}{(r-1)!}\right]\frac{(y_1 - y_0)^r}{r!}\frac{(z - z_0)^{r-1}}{(r-1)!} + {} \\ &+ \left[C_{0,0,1}\frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0,1}\frac{(x - x_1)^{r-1}}{(r-1)!}\right]\frac{(y_1 - y_0)^r}{r!}\frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]
\[ \begin{aligned} &\frac{\partial^{3(n-r)-1}\varphi_{1,1,1}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r-1}}(x, y, z_1) = \left[C_{0,0,0}\frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0,0}\frac{(x - x_1)^{r-1}}{(r-1)!}\right]\frac{(y - y_0)^{r-1}}{(r-1)!}\frac{(z_1 - z_0)^r}{r!} + {} \\ &+ \left[C_{0,1,0}\frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,1,0}\frac{(x - x_1)^{r-1}}{(r-1)!}\right]\frac{(y - y_1)^{r-1}}{(r-1)!}\frac{(z_1 - z_0)^r}{r!} \\ &\qquad\qquad \frac{\partial^{3(n-r)-2}\varphi_{1,1,1}}{\partial x^{n-r}\partial y^{n-r-1}\partial z^{n-r-1}}(x, y_1, z_1) = \\ &= \left[C_{0,0,0}\frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0,0}\frac{(x - x_1)^{r-1}}{(r-1)!}\right]\frac{(y_1 - y_0)^r}{r!}\frac{(z_1 - z_0)^r}{r!} \\ &\qquad\qquad \frac{\partial^{3(n-r)-2}\varphi_{1,1,1}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r-1}}(x_1, y, z_1) = \\ &= \left[C_{0,0,0}\frac{(y - y_0)^{r-1}}{(r-1)!} + C_{0,1,0}\frac{(y - y_1)^{r-1}}{(r-1)!}\right]\frac{(z_1 - z_0)^r}{r!}\frac{(x_1 - x_0)^r}{r!} \\ &\qquad\qquad \frac{\partial^{3(n-r)-2}\varphi_{1,1,1}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r}}(x_1, y_1, z) = \\ &= \left[C_{0,0,0}\frac{(z - z_0)^{r-1}}{(r-1)!} + C_{0,0,1}\frac{(z - z_1)^{r-1}}{(r-1)!}\right]\frac{(x_1 - x_0)^r}{r!}\frac{(y_1 - y_0)^r}{r!} \end{aligned} \]
\[ \frac{\partial^{3(n-r-1)}\varphi_{1,1,1}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}(x_1, y_1, z_1) = C_{0,0,0}\frac{(x_1 - x_0)^r}{r!}\frac{(y_1 - y_0)^r}{r!}\frac{(z_1 - z_0)^r}{r!}. \]

Integrating the partial differential equation (5.4.10) with these conditions, one finds

(5.4.12)
\[ \begin{aligned} &\frac{\partial^{3(n-r-1)}\varphi_{1,1,1}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}(x, y, z) = \left[C_{0,0,0}\frac{(x - x_0)^r}{r!} + C_{1,0,0}\frac{(x - x_1)^r}{r!}\right]\frac{(y - y_0)^r}{r!}\frac{(z - z_0)^r}{r!} + {} \\ &+ \left[C_{0,1,0}\frac{(x - x_0)^r}{r!} + C_{1,1,0}\frac{(x - x_1)^r}{r!}\right]\frac{(y - y_1)^r}{r!}\frac{(z - z_0)^r}{r!} + {} \\ &+ \left[C_{0,0,1}\frac{(x - x_0)^r}{r!} + C_{1,0,1}\frac{(x - x_1)^r}{r!}\right]\frac{(y - y_0)^r}{r!}\frac{(z - z_1)^r}{r!} + {} \\ &+ \left[C_{0,1,1}\frac{(x - x_0)^r}{r!} + C_{1,1,1}\frac{(x - x_1)^r}{r!}\right]\frac{(y - y_1)^r}{r!}\frac{(z - z_1)^r}{r!}. \end{aligned} \]

Formula (5.4.12) is obtained from formula (5.4.11) by replacing \(r\) by \(r + 1\), which shows that formula (5.4.11) is general; it is valid for \(r = 1, 2, \ldots, n-1\).

We have presented the computation of \(\varphi_{1,1,1}\) in detail in order to show the method that will be used routinely in this work.

5.4.2. We shall now prove the formula

(5.4.13)
\[ \begin{aligned} &\frac{\partial^{3(n-r)}\varphi_{i,1,1}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r}}(x, y, z) = \left[C_{0,0,0}\frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,0,0}\frac{(x - x_i)^{r-1}}{(r-1)!}\right]\frac{(y - y_0)^{r-1}}{(r-1)!}\frac{(z - z_0)^{r-1}}{(r-1)!} + {} \\ &+ \left[C_{0,1,0}\frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,1,0}\frac{(x - x_i)^{r-1}}{(r-1)!}\right]\frac{(y - y_1)^{r-1}}{(r-1)!}\frac{(z - z_0)^{r-1}}{(r-1)!} + {} \\ &+ \left[C_{0,0,1}\frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,0,1}\frac{(x - x_i)^{r-1}}{(r-1)!}\right]\frac{(y - y_0)^{r-1}}{(r-1)!}\frac{(z - z_1)^{r-1}}{(r-1)!} + {} \\ &+ \left[C_{0,1,1}\frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,1,1}\frac{(x - x_i)^{r-1}}{(r-1)!}\right]\frac{(y - y_1)^{r-1}}{(r-1)!}\frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]

valid for \(r = 1, 2, \ldots, n-1\) and \(i = 1, 2, \ldots, n-1\).

We use the method of complete induction and observe first that formula (5.4.13) is valid for \(i = 1\), since in this case it coincides with formula (5.4.10). To prove it in general, we shall assume that formula (5.4.13) is true for the index \(i\) and prove that it is also valid for the index \(i + 1\).

To this end we shall integrate the partial differential equation

(5.4.14)
\[ \frac{\partial^{3n}\varphi_{i+1,1,1}}{\partial x^n\partial y^n\partial z^n} = 0 \]

with the boundary conditions (5.4.2), (5.4.4) corresponding to the indices \(i + 1, 1, 1\) and for \(r = 0, 1, \ldots, n-1\).

For \(r = 0\), we are led to the equation

(5.4.15)
\[ \frac{\partial^{3(n-1)}\varphi_{i+1,1,1}}{\partial x^{n-1}\partial y^{n-1}\partial z^{n-1}}(x, y, z) = (C_{0,0,0} + \ldots + C_{i+1,0,0}) + (C_{0,1,0} + \ldots + C_{i+1,1,0}) + (C_{0,0,1} + \ldots + C_{i+1,0,1}) + (C_{0,1,1} + \ldots + C_{i+1,1,1}). \]

Next, integrating equation (5.4.15) with conditions (5.4.2), (5.4.3), (5.4.4) for \(r = 1\), one finds

(5.4.16)
\[ \begin{aligned} &\frac{\partial^{3(n-2)}\varphi_{i+1,1,1}}{\partial x^{n-2}\partial y^{n-2}\partial z^{n-2}}(x, y, z) = [C_{0,0,0}(x - x_0) + \ldots + C_{i+1,0,0}(x - x_{i+1})](y - y_0)(z - z_0) + {} \\ &+ [C_{0,1,0}(x - x_0) + \ldots + C_{i+1,1,0}(x - x_{i+1})](y - y_1)(z - z_0) + {} \\ &+ [C_{0,0,1}(x - x_0) + \ldots + C_{i+1,0,1}(x - x_{i+1})](y - y_0)(z - z_1) + {} \\ &+ [C_{0,1,1}(x - x_0) + \ldots + C_{i+1,1,1}(x - x_{i+1})](y - y_1)(z - z_1). \end{aligned} \]

By the method of complete induction one proves the formula

(5.4.17)
\[ \begin{aligned} &\frac{\partial^{3(n-r)}\varphi_{i+1,1,1}}{\partial x^{n-r}\partial y^{n-r}\partial z^{n-r}}(x, y, z) = \left[C_{0,0,0}\frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,0,0}\frac{(x - x_{i+1})^{r-1}}{(r-1)!}\right]\frac{(y - y_0)^{r-1}}{(r-1)!}\frac{(z - z_0)^{r-1}}{(r-1)!} + {} \\ &+ \left[C_{0,1,0}\frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,1,0}\frac{(x - x_{i+1})^{r-1}}{(r-1)!}\right]\frac{(y - y_1)^{r-1}}{(r-1)!}\frac{(z - z_0)^{r-1}}{(r-1)!} + {} \\ &+ \left[C_{0,0,1}\frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,0,1}\frac{(x - x_{i+1})^{r-1}}{(r-1)!}\right]\frac{(y - y_0)^{r-1}}{(r-1)!}\frac{(z - z_1)^{r-1}}{(r-1)!} + {} \\ &+ \left[C_{0,1,1}\frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,1,1}\frac{(x - x_{i+1})^{r-1}}{(r-1)!}\right]\frac{(y - y_1)^{r-1}}{(r-1)!}\frac{(z - z_1)^{r-1}}{(r-1)!}. \end{aligned} \]

This formula is true for \(r = 2\), because in this case it coincides with formula (5.4.16). Assuming that formula (5.4.17) is true for the index \(r\), one proves that it is also true for the index \(r + 1\) by integrating equation (5.4.17) with conditions (5.4.2), (5.4.3), (5.4.4) corresponding to the index \(r\). One arrives at a formula which can be obtained from formula (5.4.17) by replacing \(r\) by \(r + 1\). This proves that formula (5.4.13) is general; it is valid for \(i = 0, 1, \ldots, n-1\) and \(r = 1, 2, \ldots, n-1\).

5.4.3. To determine the constants \(C_{0,1,1} \ldots, C_{n,1,1}\) we set \(i = n\) in conditions (5.2.5), (5.2.6), (5.2.7). We obtain the conditions

\[ \begin{aligned} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r}}[\varphi_{n-1,1,1}]_{x_n,y,z} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r}\partial z^{n-r-1}}[\varphi_{n-1,1,0} - \varphi_{n-1,1,1}]_{x_n,y,z_1} &= 0 \end{aligned} \]
(5.4.18)
\[ \begin{aligned} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r}}[\varphi_{n-1,0,1} - \varphi_{n-1,1,1}]_{x_n,y_1,z} &= 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1}\partial y^{n-r-1}\partial z^{n-r-1}}[\varphi_{n-1,0,1} + \varphi_{n-1,1,0} - \varphi_{n-1,1,1} - \varphi_{n-1,0,0}]_{x_n,y_1,z_1} &= \begin{cases} C_{n,1,1} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0. \end{cases} \end{aligned} \]

Setting \(i = n-1\) in formulas (5.4.13), (5.3.15), (5.3.62), (5.2.20), we obtain

(5.4.19)
\[ \begin{aligned} &\varphi_{n-1,1,1}(x, y, z) = \left[C_{0,0,0}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0}\frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y - y_0)^{n-1}}{(n-1)!}\frac{(z - z_0)^{n-1}}{(n-1)!} + {} \\ &+ \left[C_{0,1,0}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,1,0}\frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y - y_1)^{n-1}}{(n-1)!}\frac{(z - z_0)^{n-1}}{(n-1)!} + {} \\ &+ \left[C_{0,0,1}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,1}\frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y - y_0)^{n-1}}{(n-1)!}\frac{(z - z_1)^{n-1}}{(n-1)!} + {} \\ &+ \left[C_{0,1,1}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,1,1}\frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y - y_1)^{n-1}}{(n-1)!}\frac{(z - z_1)^{n-1}}{(n-1)!} \\ &\varphi_{n-1,1,0}(x, y, z) = \left[C_{0,0,0}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0}\frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y - y_0)^{n-1}}{(n-1)!}\frac{(z - z_0)^{n-1}}{(n-1)!} + {} \\ &+ \left[C_{0,1,0}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,1,0}\frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y - y_1)^{n-1}}{(n-1)!}\frac{(z - z_0)^{n-1}}{(n-1)!} \\ &\varphi_{n-1,0,1}(x, y, z) = \left[C_{0,0,0}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0}\frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y - y_0)^{n-1}}{(n-1)!}\frac{(z - z_0)^{n-1}}{(n-1)!} + {} \\ &+ \left[C_{0,0,1}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,1}\frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y - y_0)^{n-1}}{(n-1)!}\frac{(z - z_1)^{n-1}}{(n-1)!} \\ &\varphi_{n-1,0,0}(x, y, z) = \left[C_{0,0,0}\frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0}\frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right]\frac{(y - y_0)^{n-1}}{(n-1)!}\frac{(z - z_0)^{n-1}}{(n-1)!} \end{aligned} \]

To these equations we add the following systems of equations:

(5.4.20)
\[ \begin{aligned} & C_{0,1,0}(x_n - x_0)^r + \ldots + C_{n-1,1,0}(x_n - x_{n-1})^r = 0 \\ & C_{0,0,1}(x_n - x_0)^r + \ldots + C_{n-1,0,1}(x_n - x_{n-1})^r = 0 \\ & C_{0,0,0}(x_n - x_0)^r + \ldots + C_{n-1,0,0}(x_n - x_{n-1})^r = 0. \end{aligned} \]

for \(r = 1, 2, \ldots, n-1\), which follow from equations (5.3.12), (5.3.63) and (5.2.23).

For \(r = 0\), the first three conditions (5.4.18) are satisfied because \(\varphi_{n-1,1,1}\), \(\varphi_{n-1,1,0}\), \(\varphi_{n-1,0,1}\), \(\varphi_{n-1,0,0}\) are polynomials of degree \(n-1\) in \(y\) and in \(z\).

The last condition (5.4.18) leads to the equation

(5.4.21)
\[ C_{0,1,1} + \ldots + C_{n-1,1,1} + C_{n,1,1} = 0. \]

By the first equation (5.4.19) we have

\[ \begin{aligned} & \frac{\partial^{3(n-r)-1} \varphi_{n-1,1,1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}}(x_n, y, z) = \left[ C_{0,0,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,1,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_1)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,0,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,1,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_1)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]

But by equations (5.4.20), valid for \(r = 1, 2, \ldots, n-1\), the first three large brackets of the preceding formula vanish, and there remains:

\[ \frac{\partial^{3(n-r)-1} \varphi_{n-1,1,1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}}(x_n, y, z) = \left[ C_{0,1,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_1)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!}. \]

This formula shows that the first condition (5.4.18) is satisfied for \(r = 1, 2, \ldots, n-1\) if we take

(5.4.22)
\[ C_{0,1,1}(x_n - x_0)^r + \ldots + C_{n-1,1,1}(x_n - x_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n-1. \]

We have the formulas

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{n-1,1,0} - \varphi_{n-1,1,1}]_{x_n, y, z} = -\left[ C_{0,0,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_1)^r}{r!} - \\ & - \left[ C_{0,1,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_1)^{r-1}}{(r-1)!} \frac{(z - z_1)^r}{r!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,0,1} - \varphi_{n-1,1,1}]_{x_n, y, z} = -\left[ C_{0,1,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_1)^r}{r!} \frac{(z - z_0)^{r-1}}{(r-1)!} - \\ & - \left[ C_{0,1,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_1)^r}{r!} \frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,0,1} + \varphi_{n-1,1,0} - \varphi_{n-1,1,1} - \varphi_{n-1,0,0}]_{x_n, y, z} = \\ & = -\left[ C_{0,1,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_1)^r}{r!} \frac{(z - z_1)^r}{r!} \end{aligned} \]

These formulas show that, by systems (5.4.20) and (5.4.22), valid for \(r = 1, 2, \ldots, n-1\), the other conditions (5.4.18) are satisfied for \(r = 1, 2, \ldots, n-1\).

We have thus proved that the constants \(C_{0,1,1}, \ldots, C_{n,1,1}\) are determined by equations (5.4.21) and (5.4.22). These constants satisfy the system of equations

(5.4.23)
\[ \begin{aligned} C_{0,1,1} + \ldots + C_{n,1,1} &= 0 \\ C_{0,1,1} x_0 + \ldots + C_{n,1,1} x_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,1,1} x_0^{n-1} + \ldots + C_{n,1,1} x_n^{n-1} &= 0 \end{aligned} \]

5.4.4. Let us suppose that we have proved the formula

(5.4.24)
\[ \begin{aligned} & \frac{\partial^{3(n-r)} \varphi_{i,l,1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,0,0} \frac{(x - x_i)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,l,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,l,0} \frac{(x - x_i)^{r-1}}{(r-1)!} \right] \frac{(y - y_l)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,0,1} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,0,1} \frac{(x - x_i)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,l,1} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,l,1} \frac{(x - x_i)^{r-1}}{(r-1)!} \right] \frac{(y - y_l)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]

valid for \(r = 1, 2, \ldots, n\); \(i = 0, 1, \ldots, n-1\) and \(l = 1, 2, \ldots, j\).

In this formula there appear the constants \(C_{0,l,0}, \ldots, C_{n,l,0}\), which satisfy the systems of equations

(5.4.25)
\[ \begin{aligned} C_{0,l,0} + \ldots + C_{n,l,0} &= 0 \\ C_{0,l,0}(x_n - x_0)^r + \ldots + C_{n-1,l,0}(x_n - x_{n-1})^r &= 0 \end{aligned} \]

for \(r = 1, 2, \ldots, n-1\) and \(l = 0, 1, \ldots, n\); this system reduces to the system

(5.4.26)
\[ \begin{aligned} C_{0,l,0} + \ldots + C_{n,l,0} &= 0 \\ C_{0,l,0} x_0 + \ldots + C_{n,l,0} x_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,l,0} x_0^{n-1} + \ldots + C_{n,l,0} x_n^{n-1} &= 0 \end{aligned} \]

(See subsections 5.3.3, 5.3.4, 5.3.7, 5.3.8.)

We assume that the constants \(C_{0,l,1}, \ldots, C_{n,l,1}\) satisfy the system of equations

(5.4.27)
\[ \begin{aligned} C_{0,l,1} + \ldots + C_{n,l,1} &= 0 \\ C_{0,l,1}(x_n - x_0)^r + \ldots + C_{n-1,l,1}(x_n - x_{n-1})^r &= 0 \end{aligned} \]

for \(r = 1, 2, \ldots, n-1\) and \(l = 0, 1, \ldots, j\). This system reduces to the system

(5.4.28)
\[ \begin{aligned} C_{0,l,1} + \ldots + C_{n,l,1} &= 0 \\ C_{0,l,1} x_0 + \ldots + C_{n,l,1} x_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,l,1} x_0^{n-1} + \ldots + C_{n,l,1} x_n^{n-1} &= 0. \end{aligned} \]

For \(l = 0\), system (5.4.27) reduces to the system formed by equations (5.3.11) and (5.3.12). For \(l = 1\), system (5.4.27) reduces to the system formed by equations (5.4.21) and (5.4.22).

We wish to prove that formula (5.4.24) still holds for \(l = j + 1\) and that the constants \(C_{0,j+1,1}, \ldots, C_{n,j+1,1}\) satisfy system (5.4.27), or (5.4.28), for \(l = j + 1\). For this we must integrate the partial differential equation

(5.4.29)
\[ \frac{\partial^{3n} \varphi_{i,j+1,1}}{\partial x^n \partial y^n \partial z^n} = 0 \]

with the boundary conditions (5.2.5), (5.2.6) and (5.2.7) for \(r = 0, 1, \ldots, n-1\), which correspond to the indices \(i, j + 1, 1\).

5.4.5. Let us begin by determining \(\varphi_{1,j+1,1}\). For this we must integrate the partial differential equation (5.4.29) with the boundary conditions (5.2.5), (5.2.6), (5.2.7) for \(r = 0, 1, \ldots, n-1\), which correspond to the indices \(1, j + 1, 1\).

Proceeding as in subsection 5.4.2 to prove formula (5.4.13), we obtain the formula

(5.4.30)
\[ \begin{aligned} & \frac{\partial^{3(n-r)} \varphi_{1,j+1,1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}(x, y, z) = \left[ C_{0,0,0} \frac{(y - y_0)^{r-1}}{(r-1)!} + \ldots + C_{0,j+1,0} \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{1,0,0} \frac{(y - y_0)^{r-1}}{(r-1)!} + \ldots + C_{1,j+1,0} \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \right] \frac{(x - x_1)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,0,1} \frac{(y - y_0)^{r-1}}{(r-1)!} + \ldots + C_{0,j+1,1} \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} + \\ & + \left[ C_{1,0,1} \frac{(y - y_0)^{r-1}}{(r-1)!} + \ldots + C_{1,j+1,1} \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \right] \frac{(x - x_1)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]

which can also be written in the form

(5.4.31)
\[ \begin{aligned} & \frac{\partial^{3(n-r)} \varphi_{1,j+1,1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0,0} \frac{(x - x_1)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,j+1,0} \frac{(x - x_1)^{r-1}}{(r-1)!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,0,1} \frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0,1} \frac{(x - x_1)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & + \left[ C_{0,j+1,1} \frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,j+1,1} \frac{(x - x_1)^{r-1}}{(r-1)!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]

and which is valid for \(r = 1, 2, \ldots, n-1\) and \(j = 0, 1, \ldots, n-2\).

5.4.6. Let us suppose that we have proved the formula

(5.4.32)
\[ \begin{aligned} & \frac{\partial^{3(n-r)} \varphi_{h,j+1,1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{h,0,0} \frac{(x - x_h)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{h,j+1,0} \frac{(x - x_h)^{r-1}}{(r-1)!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,0,1} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{h,0,1} \frac{(x - x_h)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,1} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{h,j+1,1} \frac{(x - x_h)^{r-1}}{(r-1)!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]

valid for \(r = 1, 2, \ldots, n\) and \(h = 0, 1, \ldots, i\). This is true for \(i = 0\) and \(i = 1\), because in these cases formula (5.4.32) coincides with formula (5.3.54) (and (5.4.31)).

Let us prove that formula (5.4.32) also holds for \(h = i + 1\).

For this we must integrate the partial differential equation

(5.4.33)
\[ \frac{\partial^{3n} \varphi_{i+1,j+1,1}}{\partial x^n \partial y^n \partial z^n} = 0 \]

with the boundary conditions (5.2.5), (5.2.6) and (5.2.7) corresponding to the indices \(i + 1, j + 1, 1\) and for \(r = 0, 1, \ldots, n-1\).

For \(r = 0\), one finds

(5.4.34)
\[ \frac{\partial^{3(n-1)} \varphi_{i+1,j+1,1}}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}}(x, y, z) = C_{0,0,0} + \ldots + C_{i+1,0,0} + \ldots\ldots\ldots\ldots + C_{0,j+1,0} + \ldots + C_{i+1,j+1,0} + C_{0,0,1} + \ldots + C_{i+1,0,1} + \ldots\ldots\ldots\ldots + C_{0,j+1,1} + \ldots + C_{i+1,j+1,1}. \]

For \(r = 1\), one finds

(5.4.35)
\[ \begin{aligned} & \frac{\partial^{3(n-2)} \varphi_{i+1,j+1,1}}{\partial x^{n-2} \partial y^{n-2} \partial z^{n-2}}(x, y, z) = [C_{0,0,0}(x - x_0) + \ldots + C_{i+1,0,0}(x - x_{i+1})](y - y_0)(z - z_0) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + [C_{0,j+1,0}(x - x_0) + \ldots + C_{i+1,j+1,0}(x - x_{i+1})](y - y_{j+1})(z - z_0) + \\ & + [C_{0,0,1}(x - x_0) + \ldots + C_{i+1,0,1}(x - x_{i+1})](y - y_0)(z - z_1) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + [C_{0,j+1,1}(x - x_0) + \ldots + C_{i+1,j+1,1}(x - x_{i+1})](y - y_{j+1})(z - z_1). \end{aligned} \]

Let us prove that in general we have

(5.4.36)
\[ \begin{aligned} & \frac{\partial^{3(n-r)} \varphi_{i+1,j+1,1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,0,0} \frac{(x - x_{i+1})^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,j+1,0} \frac{(x - x_{i+1})^{r-1}}{(r-1)!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,0,1} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,0,1} \frac{(x - x_{i+1})^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,1} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,j+1,1} \frac{(x - x_{i+1})^{r-1}}{(r-1)!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]

Formula (5.4.36) is true for \(r = 1\) and \(r = 2\), because in these cases it coincides with formulas (5.4.34), (5.4.35). To prove that formula (5.4.36) is true in general, we assume that it is true for the index \(r\) and prove that it is also true for the index \(r + 1\). For this we integrate equation (5.4.36) with the boundary conditions (5.2.5), (5.2.6) and (5.2.7) corresponding to the indices \(i + 1, j + 1, 1\) and to the index \(r\).

One finds

(5.4.37)
\[ \begin{aligned} & \frac{\partial^{3(n-r-1)} \varphi_{i+1,j+1,1}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^r}{r!} + \ldots + C_{i+1,0,0} \frac{(x - x_{i+1})^r}{r!} \right] \frac{(y - y_0)^r}{r!} \frac{(z - z_0)^r}{r!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,0} \frac{(x - x_0)^r}{r!} + \ldots + C_{i+1,j+1,0} \frac{(x - x_{i+1})^r}{r!} \right] \frac{(y - y_{j+1})^r}{r!} \frac{(z - z_0)^r}{r!} + \\ & + \left[ C_{0,0,1} \frac{(x - x_0)^r}{r!} + \ldots + C_{i+1,0,1} \frac{(x - x_{i+1})^r}{r!} \right] \frac{(y - y_0)^r}{r!} \frac{(z - z_1)^r}{r!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,1} \frac{(x - x_0)^r}{r!} + \ldots + C_{i+1,j+1,1} \frac{(x - x_{i+1})^r}{r!} \right] \frac{(y - y_{j+1})^r}{r!} \frac{(z - z_1)^r}{r!}. \end{aligned} \]

Formula (5.4.37) is obtained from formula (5.4.36) by replacing \(r\) by \(r + 1\). It follows that formula (5.4.36) is general; it is valid for \(r = 1, 2, \ldots, n-1\).

On the other hand, formula (5.4.36) is obtained from formula (5.4.32) by replacing \(h\) by \(i + 1\). It follows that formula (5.4.32) is general; it is valid for \(h = 0, 1, \ldots, n-1\).

5.4.6. We have thus proved the formula

(5.4.38)
\[ \begin{aligned} & \frac{\partial^{3(n-r)} \varphi_{i,j,1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,0,0} \frac{(x - x_i)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,j,0} \frac{(x - x_i)^{r-1}}{(r-1)!} \right] \frac{(y - y_j)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,0,1} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,0,1} \frac{(x - x_i)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,1} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i,j,1} \frac{(x - x_i)^{r-1}}{(r-1)!} \right] \frac{(y - y_j)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]

valid for \(r = 1, 2, \ldots, n\) and \(i, j = 0, 1, \ldots, n-1\).

It remains to prove that the constants \(C_{0,j+1,1}, \ldots, C_{n,j+1,1}\) satisfy system (5.4.27) or (5.4.28).

For this we write that conditions (5.2.5), (5.2.6) and (5.2.7) are satisfied when we set \(i = n\), \(k = 1\) and take convention (A) into account.

We shall have the following conditions:

(5.4.39)
\[ \begin{aligned} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} \bigl[\varphi_{n-1,j+1,1}\bigr]_{x_n, y, z} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} \bigl[\varphi_{n-1,j+1,0} - \varphi_{n-1,j+1,1}\bigr]_{x_n, y, z_1} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} \bigl[\varphi_{n-1,j,1} - \varphi_{n-1,j+1,1}\bigr]_{x_n, y_{j+1}, z} &= 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \bigl[\varphi_{n-1,j,1} + \varphi_{n-1,j+1,0} - \varphi_{n-1,j+1,1} - \varphi_{n-1,j,0}\bigr]_{x_n, y_{j+1}, z_1} &= \begin{cases} C_{n,j+1,1} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{aligned} \]

for \(r = 0, 1, \ldots, n-1\).

For \(r = 0\), the first three conditions (5.4.39) are satisfied because \(\varphi_{n-1,j+1,1}\), \(\varphi_{n-1,j,0}\), \(\varphi_{n-1,j,1}\) are polynomials of degree \(n-1\) in \(y\) and in \(z\).

The fourth condition (5.4.39) leads to the equation

(5.4.40)
\[ C_{0,j+1,1} + \ldots + C_{n,j+1,1} = 0. \]

We have the formula

(5.4.41)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1} \varphi_{n-1,j+1,1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}}(x_n, y, z) = \left[ C_{0,0,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,0,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]

But by equations (5.4.25) and (5.4.27) all the large brackets on the right-hand side, except the last, vanish for \(r = 1, 2, \ldots, n-1\). Then, for the first condition (5.4.39) to be satisfied, we must take

(5.4.42)
\[ C_{0,j+1,1}(x_n - x_0)^r + \ldots + C_{n-1,j+1,1}(x_n - x_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\), which, together with equation (5.4.40), proves that equations (5.4.27) also hold for \(l = j + 1\).

It remains for us to prove that the last three conditions (5.4.39) are satisfied for \(r = 1, 2, \ldots, n-1\).

By formulas (5.4.38) and (5.3.36) we have

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{n-1,j+1,0} - \varphi_{n-1,j+1,1}]_{x_n, y, z} = -\left[ C_{0,0,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_1)^r}{r!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{0,j+1,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_1)^r}{r!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,j,1} - \varphi_{n-1,j+1,1}]_{x_n, y, z} = -\left[ C_{0,j+1,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_{j+1})^r}{r!} \frac{(z - z_0)^{r-1}}{(r-1)!} - \\ & - \left[ C_{0,j+1,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_{j+1})^r}{r!} \frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,j,1} + \varphi_{n-1,j+1,0} - \varphi_{n-1,j+1,1} - \varphi_{n-1,j,0}]_{x_n, y, z} = \\ & = -\left[ C_{0,j+1,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_{j+1})^r}{r!} \frac{(z - z_1)^r}{r!}. \end{aligned} \]

These formulas show that, by equations (5.4.25) and (5.4.42), all the large brackets on the right-hand side vanish for \(r = 1, 2, \ldots, n-1\), which proves that the other boundary conditions (5.4.39) are satisfied for \(r = 1, 2, \ldots, n-1\).

5.4.7. We have proved that the constants \(C_{i,j,0}\) and \(C_{i,j,1}\) satisfy the systems of equations (5.4.26) and (5.4.28):

(5.4.43)
\[ \begin{aligned} C_{0,j,0} + \ldots + C_{n,j,0} &= 0 \\ C_{0,j,0} x_0 + \ldots + C_{n,j,0} x_n &= 0. \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,j,0} x_0^{n-1} + \ldots + C_{n,j,0} x_n^{n-1} &= 0 \end{aligned} \]

for \(j = 0, 1, \ldots, n\), and

(5.4.44)
\[ \begin{aligned} C_{0,j,1} + \ldots + C_{n,j,1} &= 0 \\ C_{0,j,1} x_0 + \ldots + C_{n,j,1} x_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,j,1} x_0^{n-1} + \ldots + C_{n,j,1} x_n^{n-1} &= 0 \end{aligned} \]

for \(j = 0, 1, \ldots, n-1\).

We have also proved that the constants \(C_{i,j,0}\) satisfy the systems of equations

(5.3.30)
\[ C_{i,0,0} + \ldots + C_{i,n,0} = 0 \]
(5.3.31)
\[ C_{i,0,0}(y_n - y_0)^r + \ldots + C_{i,n-1,0}(y_n - y_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\) and \(i = 0, 1, \ldots, n\), i.e. the system of equations

(5.3.32)
\[ \begin{aligned} C_{i,0,0} + \ldots + C_{i,n,0} &= 0 \\ C_{i,0,0} y_0 + \ldots + C_{i,n,0} y_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i,0,0} y_0^{n-1} + \ldots + C_{i,n,0} y_n^{n-1} &= 0 \end{aligned} \]

for \(i = 0, 1, \ldots, n\).

We wish to prove that the constants \(C_{i,j,1}\) satisfy the system of equations

(5.4.45)
\[ \begin{aligned} C_{i,0,1} + \ldots + C_{i,n,1} &= 0 \\ C_{i,0,1}(y_n - y_0)^r + \ldots + C_{i,n-1,1}(y_n - y_{n-1})^r &= 0 \end{aligned} \]

for \(r = 1, 2, \ldots, n-1\) and \(i = 0, 1, \ldots, n-1\), and

(5.4.46)
\[ \begin{aligned} C_{i,0,1} + \ldots + C_{i,n,1} &= 0 \\ C_{i,0,1} y_0 + \ldots + C_{i,n,1} y_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i,0,1} y_0^{n-1} + \ldots + C_{i,n,1} y_n^{n-1} &= 0 \end{aligned} \]

for \(i = 0, 1, \ldots, n-1\).

Let us set \(j = n\), \(k = 1\) in the boundary conditions (5.2.5), (5.2.6), (5.2.7) and take convention (A) into account. These conditions will be

(5.4.47)
\[ \begin{aligned} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} \bigl[\varphi_{i,n-1,1}\bigr]_{x, y_n, z} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} \bigl[\varphi_{i,n-1,0} - \varphi_{i,n-1,1}\bigr]_{x, y_n, z_1} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} \bigl[\varphi_{i-1,n-1,1} - \varphi_{i,n-1,1}\bigr]_{x_i, y_n, z} &= 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \bigl[\varphi_{i-1,n-1,1} + \varphi_{i,n-1,0} - \varphi_{i,n-1,1} - \varphi_{i-1,n-1,0}\bigr]_{x_i, y_n, z_1} &= \begin{cases} C_{i,n,1} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{aligned} \]

for \(r = 0, 1, \ldots, n-1\).

Formula (5.4.38), for \(j = n-1\) and \(r = n\), can be written in the form

\[ \begin{aligned} \varphi_{i,n-1,1}(x, y, z) = {} & \left[ C_{0,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_i)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \left[ C_{0,0,1} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n-1,1} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(z - z_1)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,0,1} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n-1,1} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_i)^{n-1}}{(n-1)!} \frac{(z - z_1)^{n-1}}{(n-1)!} \end{aligned} \]

and we have analogous formulas for \(\varphi_{i-1,n-1,1}\), \(\varphi_{i,n-1,0}\) and \(\varphi_{i-1,n-1,0}\), which we shall not write down.

Let us consider conditions (5.4.47) for \(r = 0\). The first three are satisfied, because the functions \(\varphi_{i,n-1,1}\), \(\varphi_{i-1,n-1,1}\), \(\varphi_{i,n-1,0}\), \(\varphi_{i-1,n-1,0}\) are polynomials of degree \(n-1\) in \(x\) and \(z\).

The fourth condition (5.4.47) leads to the equation

(5.4.49)
\[ C_{i,0,1} + \ldots + C_{i,n,1} = 0 \quad \text{for } i = 0, 1, \ldots, n-1. \]

Let us now examine conditions (5.4.47) for \(r = 1, 2, \ldots, n-1\).

We have

(5.4.50)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,n-1,1}]_{x, y_n, z} = \left[ C_{0,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{0,n-1,0} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,0} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,0,1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{0,n-1,1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,0,1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!}. \end{aligned} \]

But by equations (5.4.45) the first \(i+1\) large brackets vanish for \(r = 1, 2, \ldots, n-1\).

On the other hand, for the first condition (5.4.47) to be satisfied for \(i = 0\), we must take in formula (5.4.50)

\[ C_{0,0,1}(y_n - y_0)^r + \ldots + C_{0,n-1,1}(y_n - y_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n-1, \]

which, together with equation (5.4.49) for \(i = 0\), leads to system (5.3.55) for \(k = 1\), which we have already considered.

Further, for the first condition (5.4.47) to be satisfied for \(i = 1\), we must take in formula (5.4.50)

\[ C_{1,0,1}(y_n - y_0)^r + \ldots + C_{1,n-1,1}(y_n - y_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n-1. \]

Step by step one proves that we have the equations

\[ C_{i,0,1}(y_n - y_0)^r + \ldots + C_{i,n-1,1}(y_n - y_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n-1 \]

and \(i = 0, 1, \ldots, n-1\).

We have thus proved that the constants \(C_{i,j,1}\) satisfy the systems of equations (5.4.45) for \(r = 1, 2, \ldots, n-1\) and \(i = 0, 1, \ldots, n-1\), i.e. the systems of equations (5.4.46) for \(i = 0, 1, \ldots, n-1\).

It remains to show that the other boundary conditions (5.4.47) are satisfied for \(r = 1, 2, \ldots, n-1\).

For this we observe that we can write

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,n-1,0} - \varphi_{i,n-1,1}]_{x, y_n, z} = \\ & = - \left[ C_{0,0,1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{0,n-1,1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(z - z_1)^r}{r!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{i,0,1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(z - z_1)^r}{r!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i-1,n-1,1} - \varphi_{i,n-1,1}]_{x, y_n, z} = \\ & = - \left[ C_{i,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,0} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_i)^r}{r!} \frac{(z - z_0)^{r-1}}{(r-1)!} - \\ & - \left[ C_{i,0,1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_i)^r}{r!} \frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \Bigl[\varphi_{i-1,n-1,1} + \varphi_{i,n-1,0} - \varphi_{i,n-1,1} - \varphi_{i-1,n-1,0}\Bigr]_{x, y_n, z} = \\ & = - \left[ C_{i,0,1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_i)^r}{r!} \frac{(z - z_1)^r}{r!}. \end{aligned} \]

Equations (5.3.31) and (5.4.45) show that the other equations (5.4.47) are satisfied for \(r = 1, 2, \ldots, n-1\).

5.4.8. Formula (5.4.31), in which we set \(i = n-1\), becomes

(5.4.51)
\[ \begin{aligned} & \varphi_{n-1,j,1}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,j,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_j)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \left[ C_{0,0,1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_1)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,j,1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_j)^{n-1}}{(n-1)!} \frac{(z - z_1)^{n-1}}{(n-1)!}. \end{aligned} \]

But by systems (5.4.43) and (5.4.44) we can also write formula (5.4.51) in the form

(5.4.52)
\[ \begin{aligned} & \varphi_{n-1,j,1}(x, y, z) = - \left[ C_{n,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{n,j,0} \frac{(y - y_j)^{n-1}}{(n-1)!} \right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} - \\ & - \left[ C_{n,0,1} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{n,j,1} \frac{(y - y_j)^{n-1}}{(n-1)!} \right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(z - z_1)^{n-1}}{(n-1)!}. \end{aligned} \]

Later on we shall need this formula for \(j = n-1\), i.e.

(5.4.53)
\[ \begin{aligned} & \varphi_{n-1,n-1,1}(x, y, z) = - \left[ C_{n,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{n,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} - \\ & - \left[ C_{n,0,1} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{n,n-1,1} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(z - z_1)^{n-1}}{(n-1)!}. \end{aligned} \]

In the same way, if in formula (5.4.38) we set \(j = n-1\) and use systems (5.3.32) and (5.4.46), we have

(5.4.54)
\[ \begin{aligned} & \varphi_{i,n-1,1}(x, y, z) = - \left[ C_{0,n,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n,0} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} - \\ & - \left[ C_{0,n,1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n,1} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(z - z_1)^{n-1}}{(n-1)!} \end{aligned} \]

and later on we shall need this formula for \(i = n-1\), i.e.

(5.4.55)
\[ \begin{aligned} & \varphi_{n-1,n-1,1}(x, y, z) = - \left[ C_{0,n,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,n,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} - \\ & - \left[ C_{0,n,1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,n,1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(z - z_1)^{n-1}}{(n-1)!} \end{aligned} \]

5.4.9. To prove that the systems of equations (5.4.44) and (5.4.46) also hold for \(j = n\) and \(i = n\), let us write that conditions (5.2.5), (5.2.6), (5.2.7) are satisfied when we set \(i = n\), \(j = n\), \(k = 1\), taking convention (A) into account.

We shall have the following conditions:

(5.4.56)
\[ \begin{aligned} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,n-1,1}]_{x_n, y_n, z} &= 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,n-1,1} - \varphi_{n-1,n-1,0}]_{x_n, y_n, z_1} &= \begin{cases} C_{n,n,1} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0. \end{cases} \end{aligned} \]

To these conditions we add conditions (5.2.5), (5.2.6), (5.2.7) for \(i = n\), \(j = n-1\), \(k = 1\) and then for \(i = n-1\), \(j = n\), \(k = 1\). Of these equations we take only the following:

(5.4.57)
\[ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{n-1,n-1,1}]_{x_n, y, z} = 0 \]
(5.4.58)
\[ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,n-1,1}]_{x, y_n, z} = 0. \]

We shall use formulas (5.4.53), (5.4.55) as well as the formulas

(5.3.39)
\[ \varphi_{n-1,n-1,0}(x, y, z) = - \left[ C_{0,n,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,n,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} \]
(5.3.40)
\[ \varphi_{n-1,n-1,0}(x, y, z) = - \left[ C_{n,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{n,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} \]

If we consider conditions (5.4.56) for \(r = 0\), the first is satisfied because \(\varphi_{n-1,n-1,1}\) is a polynomial of degree \(n-1\) in \(z\). If we take formulas (5.4.55), (5.3.39) into account, the second condition (5.4.56) leads to the equation

(5.4.59)
\[ C_{0,n,1} + \ldots + C_{n,n,1} = 0 \]

and if we take formulas (5.4.53), (5.3.40) into account, the second condition (5.4.56) leads to the equation

(5.4.60)
\[ C_{n,0,1} + \ldots + C_{n,n,1} = 0. \]

Conditions (5.4.57), (5.4.58) are satisfied for \(r = 0\), because \(\varphi_{n-1,n-1,1}\) is a polynomial of degree \(n-1\) in \(x\), in \(y\) and in \(z\).

It remains to examine these conditions for \(r = 1, 2, \ldots, n-1\).

According to formulas (5.4.55) and (5.4.53) we have

(5.4.61)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{n-1,n-1,1}]_{x_n, y, z} = - \left[ C_{0,n,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_n)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} - \\ & - \left[ C_{0,n,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_n)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} \end{aligned} \]

and

(5.4.62)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,n-1,1}]_{x, y_n, z} = - \left[ C_{n,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{n,n-1,0} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_n)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} - \\ & - \left[ C_{n,0,1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{n,n-1,1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_n)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!}. \end{aligned} \]

But we have proved that

(5.3.47)
\[ C_{0,n,0}(x_n - x_0)^r + \ldots + C_{n-1,n,0}(x_n - x_{n-1})^r = 0 \]

and

(5.3.48)
\[ C_{n,0,0}(y_n - y_0)^r + \ldots + C_{n,n-1,0}(y_n - y_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\), so that formulas (5.4.61) and (5.4.62) reduce to

\[ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{n-1,n-1,1}]_{x_n, y, z} = - \left[ C_{0,n,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_n)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!} \]

and

\[ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,n-1,1}]_{x, y_n, z} = - \left[ C_{n,0,1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{n,n-1,1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_n)^{r-1}}{(r-1)!} \frac{(z - z_1)^{r-1}}{(r-1)!}. \]

For conditions (5.4.57) and (5.4.58) to be satisfied for \(r = 1, 2, \ldots, n-1\), we must take

(5.4.63)
\[ C_{0,n,1}(x_n - x_0)^r + \ldots + C_{n-1,n,1}(x_n - x_{n-1})^r = 0 \]

and

(5.4.64)
\[ C_{n,0,1}(y_n - y_0)^r + \ldots + C_{n,n-1,1}(y_n - y_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n-1. \]

Equations (5.4.59) and (5.4.63) for \(r = 1, 2, \ldots, n-1\) show that the system of equations (5.4.44) also holds for \(j = n\).

Likewise, equations (5.4.60) and (5.4.64) for \(r = 1, 2, \ldots, n-1\) show that the system of equations (5.4.46) also holds for \(i = n\).

It remains to prove that conditions (5.4.56) are satisfied for \(r = 1, 2, \ldots, n-1\).

Indeed, by equations (5.4.55) we have

(5.4.65)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,n-1,1}]_{x_n, y, z} = - \left[ C_{0,n,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_n)^{r-1}}{(r-1)!} \frac{(z - z_0)^r}{r!} - \\ & - \left[ C_{0,n,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_n)^{r-1}}{(r-1)!} \frac{(z - z_1)^r}{r!} \end{aligned} \]

and

(5.4.66)
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,n-1,1} - \varphi_{n-1,n-1,0}]_{x_n, y, z} = - \left[ C_{0,n,1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_n)^r}{r!} \frac{(z - z_1)^r}{r!}. \]

But equations (5.3.47) and (5.4.63) show that the large brackets on the right-hand sides of formulas (5.4.65), (5.4.66) vanish for \(r = 1, 2, \ldots, n-1\), which proves that conditions (5.4.56) are satisfied for \(r = 1, 2, \ldots, n-1\).

5.4.10. In summary, the solution of the boundary value problem \((P_{i,j,1})\) is given, by formulas (5.4.38), by

(5.4.67)
\[ \begin{aligned} & \varphi_{i,j,1}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0,0} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,j,0} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_j)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \left[ C_{0,0,1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0,1} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_1)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,j,1} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_j)^{n-1}}{(n-1)!} \frac{(z - z_1)^{n-1}}{(n-1)!} \end{aligned} \]

for \(i, j = 0, 1, \ldots, n-1\).

The constants \(C_{i,j,1}\) satisfy the systems of equations

(5.4.68)
\[ \begin{aligned} C_{0,j,1} + \ldots + C_{n,j,1} &= 0 \\ C_{0,j,1} x_0 + \ldots + C_{n,j,1} x_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,j,1} x_0^{n-1} + \ldots + C_{n,j,1} x_n^{n-1} &= 0 \end{aligned} \]

for \(j = 0, 1, \ldots, n\) and

(5.4.69)
\[ \begin{aligned} C_{i,0,1} + \ldots + C_{i,n,1} &= 0 \\ C_{i,0,1} y_0 + \ldots + C_{i,n,1} y_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i,0,1} y_0^{n-1} + \ldots + C_{i,n,1} y_n^{n-1} &= 0 \end{aligned} \]

for \(i = 0, 1, \ldots, n\).

§ 5.5. The general case: the problem \((P_{i,j,k})\)

5.5.1. Let us suppose that we have proved the formula

(5.5.1)
\[ \begin{aligned} & \varphi_{i,j,l}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0,0} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,j,0} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_j)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,l} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0,l} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_l)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,l} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,j,l} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_j)^{n-1}}{(n-1)!} \frac{(z - z_l)^{n-1}}{(n-1)!} \end{aligned} \]

for \(i, j = 0, 1, \ldots, n-1\) and \(l = 0, 1, \ldots, k\).

Formula (5.5.1) is true for \(l = 0\) and for \(l = 1\), because in these cases it coincides with formulas (5.3.15) and (5.4.67).

We wish to prove that formula (5.5.1) also holds for \(l = k+1\), and therefore that it holds for \(l = 0, 1, \ldots, n-1\).

We also assume that the constants \(C_{i,j,l}\) satisfy the systems of equations

(5.5.2)
\[ \begin{aligned} C_{0,j,l} + \ldots + C_{n,j,l} &= 0 \\ C_{0,j,l}(x_n - x_0)^r + \ldots + C_{n-1,j,l}(x_n - x_{n-1})^r &= 0 \end{aligned} \]

for \(r = 1, 2, \ldots, n-1\), \(j = 0, 1, \ldots, n-1\) and \(l = 0, 1, \ldots, k\), i.e. the systems

(5.5.3)
\[ \begin{aligned} C_{0,j,l} + \ldots + C_{n,j,l} &= 0 \\ C_{0,j,l} x_0 + \ldots + C_{n,j,l} x_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,j,l} x_0^{n-1} + \ldots + C_{n,j,l} x_n^{n-1} &= 0 \end{aligned} \]

for \(j = 0, 1, \ldots, n-1\) and \(l = 0, 1, \ldots, k\).

We assume, moreover, that the constants \(C_{i,j,l}\) satisfy the systems of equations

(5.5.4)
\[ \begin{aligned} C_{i,0,l} + \ldots + C_{i,n,l} &= 0 \\ C_{i,0,l}(y_n - y_0)^r + \ldots + C_{i,n-1,l}(y_n - y_{n-1})^r &= 0 \end{aligned} \]

for \(r = 1, 2, \ldots, n-1\), \(i = 0, 1, \ldots, n\) and \(l = 0, 1, \ldots, k\), i.e. the systems

(5.5.5)
\[ \begin{aligned} C_{i,0,l} + \ldots + C_{i,n,l} &= 0 \\ C_{i,0,l} y_0 + \ldots + C_{i,n,l} y_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i,0,l} y_0^{n-1} + \ldots + C_{i,n,l} y_n^{n-1} &= 0 \end{aligned} \]

for \(i = 0, 1, \ldots, n-1\) and \(l = 0, 1, \ldots, k\).

This is true for \(l = 0\), because in this case systems (5.5.3), (5.5.5) coincide with systems (5.3.17), (5.3.32).

It is also true for \(l = 1\), because in this case systems (5.5.3), (5.5.5) coincide with systems (5.4.68), (5.4.69).

We wish to prove that systems (5.5.2), (5.5.4), i.e. (5.5.3), (5.5.5), also hold for \(l = k+1\), and therefore that they hold for \(l = 0, 1, \ldots, n-1\).

We shall further prove that systems (5.5.3), (5.5.5) also hold for \(l = n\).

5.5.2. To solve the problems posed in subsection 5.5.1 we use the method of complete induction.

We shall integrate the partial differential equation

(5.5.6)
\[ \frac{\partial^{3n} \varphi_{i,j,k+1}}{\partial x^n \partial y^n \partial z^n} = 0 \]

with the boundary conditions (5.2.5), (5.2.6), (5.2.7) corresponding to the indices \(i\), \(j\), \(k+1\), i.e.

(5.5.7)
\[ \begin{aligned} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{i,j,k+1} - \varphi_{i-1,j,k+1}]_{x_i, y, z} &= 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,j,k+1} - \varphi_{i,j-1,k+1}]_{x, y_j, z} &= 0 \\ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,j,k+1} - \varphi_{i,j,k}]_{x, y, z_{k+1}} &= 0 \end{aligned} \]

for \(i, j = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Further,

(5.5.8)
\[ \begin{aligned} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,j,k+1} + \varphi_{i,j-1,k} - \varphi_{i,j,k} - \varphi_{i,j-1,k+1}]_{x, y_j, z_{k+1}} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,j,k+1} + \varphi_{i-1,j,k} - \varphi_{i,j,k} - \varphi_{i-1,j,k+1}]_{x_i, y, z_{k+1}} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,j,k+1} + \varphi_{i-1,j-1,k+1} - \varphi_{i,j-1,k+1} - \varphi_{i-1,j,k+1}]_{x_i, y_j, z} &= 0 \end{aligned} \]

for \(i, j = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

Finally,

(5.5.9)
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} \Bigl[(\varphi_{i,j,k+1} + \varphi_{i-1,j-1,k+1} - \varphi_{i,j-1,k+1} - \varphi_{i-1,j,k+1}) - (\varphi_{i,j,k} + \varphi_{i-1,j-1,k} - \varphi_{i,j-1,k} - \varphi_{i-1,j,k})\Bigr]_{x_i, y_j, z_{k+1}} = \begin{cases} C_{i,j,k+1} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \]

for \(i, j = 0, 1, \ldots, n\) and \(r = 0, 1, \ldots, n-1\).

5.5.3. Let us begin by determining \(\varphi_{1,1,k+1}\). For this we shall integrate the partial differential equation

(5.5.10)
\[ \frac{\partial^{3n}\varphi_{1,1,k+1}}{\partial x^n \partial y^n \partial z^n} = 0 \]

with the boundary conditions (5.5.7), (5.5.8), (5.5.9) corresponding to the indices \(i = 1\), \(j = 1\).

These conditions involve the functions

\[ \begin{gathered} \varphi_{1,1,k} \\ \varphi_{0,1,k}, \ \varphi_{1,0,k}, \ \varphi_{0,0,k} \\ \varphi_{0,1,k+1}, \ \varphi_{1,0,k+1}, \ \varphi_{0,0,k+1}. \end{gathered} \]

The first of these functions is given by formula (5.5.1) for \(i = 1\), \(j = 1\) and \(l = k\). The functions \(\varphi_{0,0,k}\) and \(\varphi_{0,0,k+1}\) are the solutions of problems \((P_{0,0,k})\), \((P_{0,0,k+1})\) treated in subsection 5.2.5. The functions \(\varphi_{1,0,k}\) and \(\varphi_{1,0,k+1}\) are the solutions of problems \((P_{1,0,k})\), \((P_{1,0,k+1})\) treated in subsection 5.3.10. The functions \(\varphi_{0,1,k}\) and \(\varphi_{0,1,k+1}\) are the solutions of problems \((P_{0,1,k})\), \((P_{0,1,k+1})\) treated in subsection 5.3.9. All these functions can be deduced from formula (5.5.1).

Integrating the partial differential equation (5.5.10) with conditions (5.5.7), (5.5.8), (5.5.9) corresponding to \(r = 0\), one finds

(5.5.11)
\[ \frac{\partial^{3(n-1)} \varphi_{1,1,k+1}}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}}(x, y, z) = (C_{0,0,0} + C_{1,0,0}) + (C_{0,1,0} + C_{1,1,0}) + \ldots\ldots\ldots\ldots\ldots\ldots + (C_{0,0,k+1} + C_{1,0,k+1}) + (C_{0,1,k+1} + C_{1,1,k+1}). \]

Next, integrating equation (5.5.11) with conditions (5.5.7), (5.5.8), (5.5.9) corresponding to \(r = 1\), one finds

(5.5.12)
\[ \begin{aligned} & \frac{\partial^{3(n-2)} \varphi_{1,1,k+1}}{\partial x^{n-2} \partial y^{n-2} \partial z^{n-2}}(x, y, z) = [C_{0,0,0}(x - x_0) + C_{1,0,0}(x - x_1)](y - y_0)(z - z_0) + \\ & + [C_{0,1,0}(x - x_0) + C_{1,1,0}(x - x_1)](y - y_1)(z - z_0) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + [C_{0,0,k+1}(x - x_0) + C_{1,0,k+1}(x - x_1)](y - y_0)(z - z_{k+1}) + \\ & + [C_{0,1,k+1}(x - x_0) + C_{1,1,k+1}(x - x_1)](y - y_1)(z - z_{k+1}). \end{aligned} \]

Let us suppose that we have proved the formula

(5.5.13)
\[ \begin{aligned} & \frac{\partial^{3(n-r)} \varphi_{1,1,k+1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0,0} \frac{(x - x_1)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,1,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,1,0} \frac{(x - x_1)^{r-1}}{(r-1)!} \right] \frac{(y - y_1)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0,k+1} \frac{(x - x_1)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,1,k+1} \frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,1,k+1} \frac{(x - x_1)^{r-1}}{(r-1)!} \right] \frac{(y - y_1)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \end{aligned} \]

This formula is true for \(r = 1\) and \(r = 2\), because in these cases it coincides with formulas (5.5.11) and (5.5.12). Formula (5.5.13) is also true for the index \(r + 1\), because, integrating equation (5.5.13) with conditions (5.5.7), (5.5.8), (5.5.9) corresponding to the indices \(1, 1, k + 1\) and to the index \(r\), one obtains formula (5.5.13) with the index \(r\) replaced by \(r + 1\).

Formula (5.5.13) is therefore general; it is valid for \(r = 1, 2, \ldots, n\).

5.5.4. We shall now prove the formula

(5.5.14)
\[ \begin{aligned} & \frac{\partial^{3(n-r)} \varphi_{i',1,k+1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i',0,0} \frac{(x - x_{i'})^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,1,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i',1,0} \frac{(x - x_{i'})^{r-1}}{(r-1)!} \right] \frac{(y - y_1)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i',0,k+1} \frac{(x - x_{i'})^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,1,k+1} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i',1,k+1} \frac{(x - x_{i'})^{r-1}}{(r-1)!} \right] \frac{(y - y_1)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \end{aligned} \]

for \(r = 1, 2, \ldots, n\) and \(i' = 0, 1, \ldots, n-1\).

We observe first that formula (5.5.14) is true for \(i' = 1\), because in this case it coincides with formula (5.5.13). Next we assume that formula (5.5.14) is true for the index \(i' = i\), and we shall prove that it is also true for the index \(i' = i + 1\).

To carry out the proof we shall integrate the partial differential equation

(5.5.15)
\[ \frac{\partial^{3n} \varphi_{i+1,1,k+1}}{\partial x^n \partial y^n \partial z^n} = 0 \]

with the boundary conditions (5.5.7), (5.5.8), (5.5.9) corresponding to the indices \(i + 1, 1, k + 1\) and for \(r = 0, 1, \ldots, n-1\).

These conditions involve the functions

\[ \begin{gathered} \varphi_{i+1,1,k} \\ \varphi_{i,1,k}; \quad \varphi_{i+1,0,k}; \quad \varphi_{i,0,k} \\ \varphi_{i,1,k+1}; \quad \varphi_{i+1,0,k+1}; \quad \varphi_{i,0,k+1}. \end{gathered} \]

The functions \(\varphi_{i+1,1,k}\), \(\varphi_{i,1,k}\) are given by formula (5.5.1) for the indices \(i + 1, 1, k\) and \(i, 1, k\). The functions \(\varphi_{i,0,k}\), \(\varphi_{i,0,k+1}\), \(\varphi_{i+1,0,k}\), \(\varphi_{i+1,0,k+1}\) are the solutions of problems \((P_{i,0,k})\), \((P_{i,0,k+1})\), \((P_{i+1,0,k})\), \((P_{i+1,0,k+1})\), which we treated in subsection 5.3.10. Finally, the function \(\varphi_{i,1,k+1}\) is given by formula (5.5.14) for \(r = n\), which we have assumed valid for \(i' = i\).

Integrating equation (5.5.15) with the boundary conditions (5.5.7), (5.5.8), (5.5.9) corresponding to the indices \(i + 1, 1, k + 1\) and for \(r = 0\), one finds

(5.5.16)
\[ \frac{\partial^{3(n-1)} \varphi_{i+1,1,k+1}}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}}(x, y, z) = {} (C_{0,0,0} + \ldots + C_{i+1,0,0}) + (C_{0,1,0} + \ldots + C_{i+1,1,0}) + \ldots\ldots\ldots\ldots\ldots\ldots + (C_{0,0,k+1} + \ldots + C_{i+1,0,k+1}) + (C_{0,1,k+1} + \ldots + C_{i+1,1,k+1}) \]

Next, integrating equation (5.5.16) with the boundary conditions (5.5.7), (5.5.8), (5.5.9) corresponding to the indices \(i + 1, 1, k + 1\) and for \(r = 1\), one finds

(5.5.17)
\[ \begin{aligned} & \frac{\partial^{3(n-2)} \varphi_{i+1,1,k+1}}{\partial x^{n-2} \partial y^{n-2} \partial z^{n-2}}(x, y, z) = [C_{0,0,0}(x - x_0) + \ldots + C_{i+1,0,0}(x - x_{i+1})] (y - y_0)(z - z_0) + \\ & + [C_{0,1,0}(x - x_0) + \ldots + C_{i+1,1,0}(x - x_{i+1})] (y - y_1)(z - z_0) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + [C_{0,0,k+1}(x - x_0) + \ldots + C_{i+1,0,k+1}(x - x_{i+1})] (y - y_0)(z - z_{k+1}) + \\ & + [C_{0,1,k+1}(x - x_0) + \ldots + C_{i+1,1,k+1}(x - x_{i+1})] (y - y_1)(z - z_{k+1}) \end{aligned} \]

Let us suppose that we have proved the formula

(5.5.18)
\[ \begin{aligned} & \frac{\partial^{3(n-r)} \varphi_{i+1,1,k+1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,0,0} \frac{(x - x_{i+1})^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,1,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,1,0} \frac{(x - x_{i+1})^{r-1}}{(r-1)!} \right] \frac{(y - y_1)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,0,k+1} \frac{(x - x_{i+1})^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,1,k+1} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,1,k+1} \frac{(x - x_{i+1})^{r-1}}{(r-1)!} \right] \frac{(y - y_1)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!}. \end{aligned} \]

This formula is true for \(r = 2\), because in this case it coincides with formula (5.5.17). Formula (5.5.18) is also valid for the index \(r + 1\), because, integrating equation (5.5.18) with the boundary conditions (5.5.7), (5.5.8), (5.5.9) corresponding to the indices \(i + 1, 1\), \(k + 1\) and to the index \(r\), one obtains formula (5.5.18) with \(r\) replaced by \(r + 1\).

Formula (5.5.18) is therefore general; it is valid for \(r = 1, 2, \ldots, n\).

On the other hand, formula (5.5.18) is obtained from formula (5.5.14) by replacing \(i'\) by \(i + 1\), which means that formula (5.5.14) is general; it is valid for \(i' = 0, 1, \ldots, n-1\).

It remains to determine the constants \(C_{0,1,k+1}, \ldots, C_{n,1,k+1}\).

5.5.5. Let us write conditions (5.5.7), (5.5.8), (5.5.9) for the indices \(n, 1, k + 1\), taking convention (A) into account. These conditions are:

(5.5.19)
\[ \begin{aligned} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{n-1,1,k+1}]_{x_n, y, z} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{n-1,1,k} - \varphi_{n-1,1,k+1}]_{x_n, y, z_{k+1}} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,0,k+1} - \varphi_{n-1,1,k+1}]_{x_n, y_1, z} &= 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,0,k+1} + \varphi_{n-1,1,k} - \varphi_{n-1,1,k+1} - \varphi_{n-1,0,k}]_{x_n, y_1, z_{k+1}} & = \begin{cases} C_{n,1,k+1} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{aligned} \]

for \(r = 0, 1, \ldots, n-1\).

By formula (5.5.14), for \(i' = n - 1\) we have

(5.5.20)
\[ \begin{aligned} & \varphi_{n-1,1,k+1}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \left[ C_{0,1,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,1,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_1)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,k+1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!} + \\ & + \left[ C_{0,1,k+1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,1,k+1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_1)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!} \end{aligned} \]

and by formula (5.3.62) we have

(5.5.21)
\[ \begin{aligned} & \varphi_{n-1,0,k}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,k} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_k)^{n-1}}{(n-1)!} \end{aligned} \]

valid for \(k = 0, 1, \ldots, n-1, n\).

Let us consider conditions (5.5.19) for \(r = 0\). The first three are satisfied, because \(\varphi_{n-1,1,k+1}\), \(\varphi_{n-1,1,k}\) and \(\varphi_{n-1,0,k}\) are polynomials of degree \(n - 1\) in \(y\) and in \(z\).

The fourth condition (5.5.19) gives the equation

(5.5.22)
\[ C_{0,1,k+1} + \ldots + C_{n,1,k+1} = 0. \]

Let us now examine conditions (5.5.19) for \(r = 1, 2, \ldots, n-1\). By formula (5.5.20) we have

(5.5.23)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{n-1,1,k+1}]_{x_n, y, z} = \left[ C_{0,0,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,1,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_1)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} + \\ & + \left[ C_{0,1,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_1)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \end{aligned} \]

But by equations (5.5.2) for \(j = 0, 1\) and \(l = 0, 1, \ldots, k\), the first \(2(k + 1)\) large brackets vanish for \(r = 1, 2, \ldots, n-1\). Likewise, by equations (5.3.63) we have

\[ C_{0,0,k}(x_n - x_0)^r + \ldots + C_{n-1,0,k}(x_n - x_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n-1 \]

and \(k = 0, 1, \ldots, n\).

Formula (5.5.23) becomes

\[ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{n-1,1,k+1}]_{x_n, y, z} = \left[ C_{0,1,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_1)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \]

and for the first condition (5.5.19) to be satisfied for \(r = 1, 2, \ldots, n-1\), we must take

(5.5.24)
\[ C_{0,1,k+1}(x_n - x_0)^r + \ldots + C_{n-1,1,k+1}(x_n - x_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\).

Equations (5.5.22), (5.5.24) show that system (5.5.2) or (5.5.3) is valid for \(j = 1\), and \(l = k + 1\).

It remains for us to show that the other conditions (5.5.19) are satisfied for \(r = 1, 2, \ldots, n-1\). This follows from the following formulas:

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{n-1,1,k} - \varphi_{n-1,1,k+1}]_{x_n, y, z} = -\left[ C_{0,0,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^r}{r!} - \\ & - \left[ C_{0,1,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_1)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^r}{r!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,0,k+1} - \varphi_{n-1,1,k+1}]_{x_n, y, z} = \\ & = -\left[ C_{0,1,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_1)^r}{r!} \frac{(z - z_0)^{r-1}}{(r-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & - \left[ C_{0,1,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_1)^r}{r!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,0,k+1} + \varphi_{n-1,1,k} - \varphi_{n-1,1,k+1} - \varphi_{n-1,0,k}]_{x_n, y, z} = \\ & = -\left[ C_{0,1,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,1,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_1)^r}{r!} \frac{(z - z_{k+1})^r}{r!} \end{aligned} \]

Equations (5.5.24) and (5.5.2) for \(j = 1\) and \(l = 0, 1, \ldots, k\), as well as equations (5.3.63) for \(k = 0, 1, \ldots, n\), show that all the large brackets in these formulas vanish for \(r = 1, 2, \ldots, n-1\), and therefore the other conditions (5.5.19) are satisfied for \(r = 1, 2, \ldots, n-1\).

5.5.6. Let us suppose that we have proved the formula

(5.5.25)
\[ \begin{aligned} & \varphi_{i,j',k+1}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0,0} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j',0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,j',0} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_{j'})^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0,k+1} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j',k+1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,j',k+1} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_{j'})^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!} \end{aligned} \]

valid for \(i = 0, 1, \ldots, n-1\) and \(j' = 0, 1, \ldots, j\), and let us prove that it is also valid for \(j' = j + 1\).

We assume, moreover, that the system

(5.5.26)
\[ \begin{aligned} C_{0,j',k+1} + \ldots + C_{n,j',k+1} &= 0 \\ C_{0,j',k+1}(x_n - x_0)^r + \ldots + C_{n-1,j',k+1}(x_n - x_{n-1})^r &= 0 \end{aligned} \]

for \(r = 1, 2, \ldots, n-1\), which leads to the system

(5.5.27)
\[ \begin{aligned} C_{0,j',k+1} + \ldots + C_{n,j',k+1} &= 0 \\ C_{0,j',k+1} x_0 + \ldots + C_{n,j',k+1} x_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,j',k+1} x_0^{n-1} + \ldots + C_{n,j',k+1} x_n^{n-1} &= 0 \end{aligned} \]

is true for \(j' = 0, 1, \ldots, j\), and let us prove that it is still true for \(j' = j + 1\).

To prove this we first show that formula (5.5.25) and system (5.5.26) or (5.5.27) are true for \(j' = 1\), because in this case we recover formula (5.5.14) corresponding to \(i' = 1\) and \(r = n\), and system (5.5.3) corresponding to \(j = 1\) and \(l = k + 1\).

5.5.7. We begin by determining \(\varphi_{1,j+1,k+1}\), integrating the partial differential equation

(5.5.28)
\[ \frac{\partial^{3n} \varphi_{1,j+1,k+1}}{\partial x^n \partial y^n \partial z^n} = 0 \]

with the boundary conditions (5.5.7), (5.5.8), (5.5.9) corresponding to the indices \(1, j + 1, k + 1\) and for \(r = 0, 1, \ldots, n-1\).

These conditions involve the functions

\[ \begin{gathered} \varphi_{1,j+1,k} \\ \varphi_{0,j+1,k}; \quad \varphi_{1,j,k}; \quad \varphi_{0,j,k} \\ \varphi_{0,j+1,k+1}; \quad \varphi_{1,j,k+1}; \quad \varphi_{0,j,k+1}. \end{gathered} \]

The functions \(\varphi_{1,j+1,k}\), \(\varphi_{1,j,k}\) are given by formulas (5.5.1) for \(l = k\). The functions \(\varphi_{0,j+1,k}\), \(\varphi_{0,j,k}\), \(\varphi_{0,j+1,k+1}\), \(\varphi_{0,j,k+1}\) are determined by problems \((P_{0,j+1,k})\), \((P_{0,j,k})\), \((P_{0,j+1,k+1})\), \((P_{0,j,k+1})\), treated in § 5.3. Finally, the function \(\varphi_{1,j,k+1}\) is given by formula (5.5.25), which we have assumed true for \(j' = j\) and \(i = 0, 1, \ldots, n-1\).

The boundary conditions (5.5.7), (5.5.8), (5.5.9) corresponding to the indices \(1, j + 1, k + 1\) and to \(r = 0\) lead to the equation

(5.5.29)
\[ \begin{aligned} \frac{\partial^{3(n-1)} \varphi_{1,j+1,k+1}}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}}(x, y, z) = {} & (C_{0,0,0} + C_{1,0,0}) + \ldots\ldots\ldots\ldots\ldots\ldots + (C_{0,j+1,0} + C_{1,j+1,0}) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots + \\ & + (C_{0,0,k+1} + C_{1,0,k+1}) + \ldots\ldots\ldots\ldots\ldots\ldots + (C_{0,j+1,k+1} + C_{1,j+1,k+1}) \end{aligned} \]

Integrating equation (5.5.29) with conditions (5.5.7), (5.5.8), (5.5.9) corresponding to the indices \(1, j + 1, k + 1\) and to \(r = 1\), one obtains the formula

(5.5.30)
\[ \begin{aligned} & \frac{\partial^{3(n-2)} \varphi_{1,j+1,k+1}}{\partial x^{n-2} \partial y^{n-2} \partial z^{n-2}}(x, y, z) = [C_{0,0,0}(x - x_0) + C_{1,0,0}(x - x_1)] (y - y_0)(z - z_0) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + [C_{0,j+1,0}(x - x_0) + C_{1,j+1,0}(x - x_1)] (y - y_{j+1})(z - z_0) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + [C_{0,0,k+1}(x - x_0) + C_{1,0,k+1}(x - x_1)] (y - y_0)(z - z_{k+1}) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + [C_{0,j+1,k+1}(x - x_0) + C_{1,j+1,k+1}(x - x_1)] (y - y_{j+1})(z - z_{k+1}). \end{aligned} \]

Let us suppose that we have proved the formula

(5.5.31)
\[ \begin{aligned} & \frac{\partial^{3(n-r)} \varphi_{1,j+1,k+1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0,0} \frac{(x - x_1)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,j+1,0} \frac{(x - x_1)^{r-1}}{(r-1)!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,0,k+1} \frac{(x - x_1)^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,k+1} \frac{(x - x_0)^{r-1}}{(r-1)!} + C_{1,j+1,k+1} \frac{(x - x_1)^{r-1}}{(r-1)!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \end{aligned} \]

which is valid for \(r = 1\) and \(r = 2\), because in these cases it coincides with formulas (5.5.29), (5.5.30). Formula (5.5.31) is also valid for the index \(r + 1\), because, integrating equation (5.5.31) with conditions (5.5.7), (5.5.8), (5.5.9) corresponding to the indices \(1, j + 1, k + 1\) and to \(r\), one recovers formula (5.5.31) with \(r\) replaced by \(r + 1\).

Formula (5.5.31) is therefore general; it is valid for \(r = 1, 2, \ldots, n\).

5.5.8. Let us suppose that we have proved the formula

(5.5.32)
\[ \begin{aligned} & \varphi_{i',j+1,k+1}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i',0,0} \frac{(x - x_{i'})^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i',j+1,0} \frac{(x - x_{i'})^{n-1}}{(n-1)!} \right] \frac{(y - y_{j+1})^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i',0,k+1} \frac{(x - x_{i'})^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,k+1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i',j+1,k+1} \frac{(x - x_{i'})^{n-1}}{(n-1)!} \right] \frac{(y - y_{j+1})^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!} \end{aligned} \]

for \(i' = 0, 1, \ldots, i\), which is true for \(i' = 1\), since in this case formula (5.5.32) coincides with formula (5.5.31) for \(r = n\). We shall prove that formula (5.5.32) is still true for \(i' = i + 1\).

To this end we shall integrate the partial differential equation

(5.5.33)
\[ \frac{\partial^{3n} \varphi_{i+1,j+1,k+1}}{\partial x^n \partial y^n \partial z^n} = 0 \]

with conditions (5.5.7), (5.5.8), (5.5.9), which correspond to the indices \(i + 1, j + 1, k + 1\) and to \(r = 0, 1, \ldots, n-1\).

These conditions involve the functions

\[ \begin{gathered} \varphi_{i+1,j+1,k}; \\ \varphi_{i,j+1,k}; \quad \varphi_{i+1,j,k}; \quad \varphi_{i,j,k}; \\ \varphi_{i,j+1,k+1}; \quad \varphi_{i+1,j,k+1}; \quad \varphi_{i,j,k+1}. \end{gathered} \]

By the hypothesis made in subsection 5.5.1, formula (5.5.1) gives the functions \(\varphi_{i+1,j+1,k}\); \(\varphi_{i,j+1,k}\); \(\varphi_{i+1,j,k}\); \(\varphi_{i,j,k}\). Likewise, by the hypothesis made in subsection 5.5.6, formula (5.5.25) gives the functions \(\varphi_{i,j,k+1}\) and \(\varphi_{i+1,j,k+1}\). Finally, we have assumed that formula (5.5.32) is valid for \(\varphi_{i,j+1,k+1}\). Hence we can write the boundary conditions (5.5.7), (5.5.8), (5.5.9) for the indices \(i + 1, j + 1, k + 1\) and for \(r = 0, 1, \ldots, n-1\).

For \(r = 0\), one finds

(5.5.34)
\[ \begin{aligned} \frac{\partial^{3(n-1)} \varphi_{i+1,j+1,k+1}}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}}(x, y, z) = {} & (C_{0,0,0} + \ldots + C_{i+1,0,0}) + \ldots\ldots\ldots\ldots\ldots\ldots + (C_{0,j+1,0} + \ldots + C_{i+1,j+1,0}) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots + \\ & + (C_{0,0,k+1} + \ldots + C_{i+1,0,k+1}) + \ldots\ldots\ldots\ldots\ldots\ldots + (C_{0,j+1,k+1} + \ldots + C_{i+1,j+1,k+1}). \end{aligned} \]

For \(r = 1\), one finds

(5.5.35)
\[ \begin{aligned} & \frac{\partial^{3(n-2)} \varphi_{i+1,j+1,k+1}}{\partial x^{n-2} \partial y^{n-2} \partial z^{n-2}}(x, y, z) = [C_{0,0,0}(x - x_0) + \ldots + C_{i+1,0,0}(x - x_{i+1})] (y - y_0)(z - z_0) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + [C_{0,j+1,0}(x - x_0) + \ldots + C_{i+1,j+1,0}(x - x_{i+1})] (y - y_{j+1})(z - z_0) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + [C_{0,0,k+1}(x - x_0) + \ldots + C_{i+1,0,k+1}(x - x_{i+1})] (y - y_0)(z - z_{k+1}) + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + [C_{0,j+1,k+1}(x - x_0) + \ldots + C_{i+1,j+1,k+1}(x - x_{i+1})] (y - y_{j+1})(z - z_{k+1}) \end{aligned} \]

Let us suppose that we have proved the formula

(5.5.36)
\[ \begin{aligned} & \frac{\partial^{3(n-r)} \varphi_{i+1,j+1,k+1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r}}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,0,0} \frac{(x - x_{i+1})^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,0} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,j+1,0} \frac{(x - x_{i+1})^{r-1}}{(r-1)!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,0,k+1} \frac{(x - x_{i+1})^{r-1}}{(r-1)!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,k+1} \frac{(x - x_0)^{r-1}}{(r-1)!} + \ldots + C_{i+1,j+1,k+1} \frac{(x - x_{i+1})^{r-1}}{(r-1)!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \end{aligned} \]

This formula is true for \(r = 1\) and \(r = 2\), because in these cases it coincides with formulas (5.5.34) and (5.5.35). It is also valid for the index \(r + 1\), because, integrating it with conditions (5.5.7), (5.5.8), (5.5.9) corresponding to the indices \(i + 1, j + 1, k + 1\) and to \(r\), one obtains a formula which is deduced from formula (5.5.36) by replacing the index \(r\) by \(r + 1\). Hence formula (5.5.36) is general; it is valid for \(r = 1, 2, \ldots, n\).

On the other hand, formula (5.5.36) for \(r = n\) is deduced from formula (5.5.32) by replacing the index \(i'\) by \(i + 1\). Hence formula (5.5.32) is general; it is valid for \(i' = 0, 1, \ldots, n-1\).

It also follows that formula (5.5.25) is general; it is valid for \(i, j = 0, 1, \ldots, n-1\).

Finally, we observe that formula (5.5.25) is deduced from formula (5.5.1) by replacing the index \(l\) by \(k + 1\). This proves that formula (5.5.1) is general; it is valid for \(i, j, l = 0, 1, \ldots, n-1\).

5.5.9. Let us write conditions (5.5.7), (5.5.8), (5.5.9) for the indices \(n, j + 1, k + 1\) and \(r = 0, 1, \ldots, n - 1\), taking convention (A) into account. These conditions are

(5.5.37)
\[ \begin{aligned} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{n-1,j+1,k+1}]_{x_n, y, z} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{n-1,j+1,k} - \varphi_{n-1,j+1,k+1}]_{x_n, y, z_{k+1}} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,j,k+1} - \varphi_{n-1,j+1,k+1}]_{x_n, y_{j+1}, z} &= 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,j,k+1} + \varphi_{n-1,j+1,k} - \varphi_{n-1,j+1,k+1} - \varphi_{n-1,j,k}]_{x_n, y_{j+1}, z_{k+1}} &= \begin{cases} C_{n,j+1,k+1} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{aligned} \]

for \(r = 0, 1, \ldots, n - 1\).

In order to write these conditions we need formula (5.5.1) for \(i = n - 1\), \(j + 1\) and \(l = k + 1\), that is

(5.5.38)
\[ \begin{aligned} \varphi_{n-1,j+1,k+1}(x, y, z) = {} & \left[ C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,j+1,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_{j+1})^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,k+1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,k+1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,j+1,k+1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_{j+1})^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!} \end{aligned} \]

and likewise the analogous formula, but for the indices \(j, k\); \(j + 1, k\); \(j, k + 1\).

For \(r = 0\) the first three conditions (5.5.37) are satisfied, and the fourth leads to the equation

(5.5.39)
\[ C_{0,j+1,k+1} + \ldots + C_{n,j+1,k+1} = 0. \]

Further, by formula (5.5.38), we have

(5.5.40)
\[ \begin{aligned} \frac{\partial^{3(n-r)-1} \varphi_{n-1,j+1,k+1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}}(x_n, y, z) = {} & \left[ C_{0,0,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!}. \end{aligned} \]

But by equations (5.5.2) we have

\[ C_{0,j,l}(x_n - x_0)^r + \ldots + C_{n-1,j,l}(x_n - x_{n-1})^r = 0 \]

for \(j = 0, 1, \ldots, n - 1\), \(l = 0, 1, \ldots, k\) and \(r = 1, 2, \ldots, n - 1\).

Formula (5.5.40) then reduces to:

\[ \begin{aligned} & \frac{\partial^{3(n-r)-1} \varphi_{n-1,j+1,k+1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}}(x_n, y, z) = \left[ C_{0,0,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j+1,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \end{aligned} \]

By system (5.3.63) we have

\[ C_{0,0,k}(x_n - x_0)^r + \ldots + C_{n-1,0,k}(x_n - x_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n - 1\) and \(k = 0, 1, \ldots, n - 1\).

In order that conditions (5.5.37) be satisfied as well for \(r = 1, 2, \ldots, n - 1\) and \(j = 0\), the preceding formula shows that we must take

\[ C_{0,1,k+1}(x_n - x_0)^r + \ldots + C_{n-1,1,k+1}(x_n - x_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n - 1\). This reasoning is continued until we arrive at the formula

\[ \frac{\partial^{3(n-r)-1} \varphi_{n-1,j+1,k+1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}}(x_n, y, z) = \left[ C_{0,j+1,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \]

and in order that the first condition (5.5.37) be satisfied for \(r = 1, 2, \ldots, n - 1\), we must take

(5.5.41)
\[ C_{0,j+1,k+1}(x_n - x_0)^r + \ldots + C_{n-1,j+1,k+1}(x_n - x_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n - 1\).

Thus the constants \(C_{0,j+1,k+1}, \ldots, C_{n,j+1,k+1}\) satisfy the system of equations (5.5.39), (5.5.41), which leads to the system

(5.5.42)
\[ \begin{aligned} C_{0,j+1,k+1} + \ldots + C_{n,j+1,k+1} &= 0 \\ C_{0,j+1,k+1} x_0 + \ldots + C_{n,j+1,k+1} x_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,j+1,k+1} x_0^{n-1} + \ldots + C_{n,j+1,k+1} x_n^{n-1} &= 0. \end{aligned} \]

We have therefore proved that system (5.5.3) is also valid for \(l = k + 1\). This means that system (5.5.3) is general; it is valid for \(j = 0, 1, \ldots, n - 1\) and \(l = 0, 1, \ldots, n - 1\).

It remains to show that the other conditions (5.5.37) are satisfied for \(r = 1, 2, \ldots, n - 1\). By formula (5.5.38) we have

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{n-1,j+1,k} - \varphi_{n-1,j+1,k+1}]_{x_n, y, z} = -\left[ C_{0,0,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,0,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_0)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^r}{r!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{0,j+1,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_{j+1})^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^r}{r!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,j,k+1} - \varphi_{n-1,j+1,k+1}]_{x_n, y, z} = \\ & = -\left[ C_{0,j+1,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,0} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_{j+1})^r}{r!} \frac{(z - z_0)^{r-1}}{(r-1)!} \end{aligned} \]
\[ \begin{aligned} & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{0,j+1,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_{j+1})^r}{r!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,j,k+1} + \varphi_{n-1,j+1,k} - \varphi_{n-1,j+1,k+1} - \varphi_{n-1,j,k}]_{x_n, y, z} = \\ & = -\left[ C_{0,j+1,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,j+1,k+1} \frac{(x_n - x_{n-1})^r}{r!} \right] \frac{(y - y_{j+1})^r}{r!} \frac{(z - z_{k+1})^r}{r!}. \end{aligned} \]

But by equations (5.5.2) and (5.5.41) we have

\[ C_{0,j,l}(x_n - x_0)^r + \ldots + C_{n-1,j,l}(x_n - x_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n - 1\) and \(j = 0, 1, \ldots, n - 1\), \(l = 0, 1, \ldots, k, k + 1\), and consequently the other conditions (5.5.37) are satisfied for \(r = 1, 2, \ldots, n - 1\).

5.5.10. We shall now prove that the systems of equations (5.5.4) and (5.5.5) are also valid for \(l = k + 1\), which means that the constants \(C_{i,0,k}, \ldots, C_{i,n,k}\) satisfy the system of equations

(5.5.43)
\[ \begin{aligned} C_{i,0,k} + \ldots + C_{i,n,k} &= 0 \\ C_{i,0,k} y_0 + \ldots + C_{i,n,k} y_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i,0,k} y_0^{n-1} + \ldots + C_{i,n,k} y_n^{n-1} &= 0 \end{aligned} \]

for \(i, k = 0, 1, \ldots, n - 1\).

To this end let us write conditions (5.5.7), (5.5.8), (5.5.9) for the indices \(i, n, k + 1\) and \(r = 0, 1, \ldots, n - 1\), taking convention (A) into account. These conditions are

(5.5.44)
\[ \begin{aligned} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,n-1,k+1}]_{x, y_n, z} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,n-1,k} - \varphi_{i,n-1,k+1}]_{x, y_n, z_{k+1}} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i-1,n-1,k+1} - \varphi_{i,n-1,k+1}]_{x_i, y_n, z} &= 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i-1,n-1,k+1} + \varphi_{i,n-1,k} - \varphi_{i,n-1,k+1} - \varphi_{i-1,n-1,k}]_{x_i, y_n, z_{k+1}} &= \begin{cases} C_{i,n,k+1} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{aligned} \]

for \(r = 0, 1, \ldots, n - 1\).

In order to write these conditions we need the function (5.5.1) for the indices \(i\), \(n - 1\), \(l = k + 1\), in the form

(5.5.45)
\[ \begin{aligned} & \varphi_{i,n-1,k+1}(x, y, z) = \left[ C_{0,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_i)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n-1,k+1} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!} \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,0,k+1} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n-1,k+1} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_i)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!}. \end{aligned} \]

For \(r = 0\) the first three equations (5.5.44) are satisfied, and the fourth condition gives the equation

(5.5.46)
\[ C_{i,0,k+1} + \ldots + C_{i,n,k+1} = 0. \]

Let us now examine conditions (5.5.44) for \(r = 1, 2, \ldots, n - 1\). We have

(5.5.47)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,n-1,k+1}]_{x, y_n, z} = \left[ C_{0,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{0,n-1,0} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,0} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{0,n-1,k+1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,0,k+1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,k+1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!}. \end{aligned} \]

But by equations (5.5.4) we have

\[ C_{i,0,l}(y_n - y_0)^r + \ldots + C_{i,n-1,l}(y_n - y_{n-1})^r = 0 \]

for \(i = 0, 1, \ldots, n - 1\), \(l = 0, 1, \ldots, k\) and \(r = 1, 2, \ldots, n - 1\).

Formula (5.5.47) reduces to:

(5.5.48)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,n-1,k+1}]_{x, y_n, z} = \left[ C_{0,0,k+1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{0,n-1,k+1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,0,k+1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,k+1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!}. \end{aligned} \]

By equations (5.3.55) we have

\[ C_{0,0,k}(y_n - y_0)^r + \ldots + C_{0,n-1,k}(y_n - y_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n - 1\) and \(k = 0, 1, \ldots, n - 1\).

Hence the first large bracket on the right-hand side of formula (5.5.48) vanishes, and its right-hand side begins with the second bracket; in order that the first condition (5.5.44) be satisfied for \(r = 1, 2, \ldots, n - 1\) and \(j = 0\), we must take in formula (5.5.48)

\[ C_{1,0,k+1}(y_n - y_0)^r + \ldots + C_{1,n-1,k+1}(y_n - y_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n - 1\). This reasoning is continued until we arrive at the formula

\[ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i,n-1,k+1}]_{x, y_n, z} = \left[ C_{i,0,k+1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,k+1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \]

and in order that the first condition (5.5.44) be satisfied for \(r = 1, 2, \ldots, n - 1\), we must take

(5.5.49)
\[ C_{i,0,k+1}(y_n - y_0)^r + \ldots + C_{i,n-1,k+1}(y_n - y_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n - 1\).

Thus the constants \(C_{i,0,k+1}, \ldots, C_{i,n,k+1}\) satisfy the system of equations (5.5.46) and (5.5.49), which leads to the system

(5.5.50)
\[ \begin{aligned} C_{i,0,k+1} + \ldots + C_{i,n,k+1} &= 0 \\ C_{i,0,k+1} y_0 + \ldots + C_{i,n,k+1} y_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i,0,k+1} y_0^{n-1} + \ldots + C_{i,n,k+1} y_n^{n-1} &= 0. \end{aligned} \]

We have therefore shown that system (5.5.5) is also valid for \(l = k + 1\). This means that system (5.5.5) is general; it is valid for \(i = 0, 1, \ldots, n - 1\) and \(l = 0, 1, \ldots, n - 1\).

It remains to show that the other conditions (5.5.44) are satisfied for \(r = 1, 2, \ldots, n - 1\). By formula (5.5.45) we have

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,n-1,k} - \varphi_{i,n-1,k+1}]_{x, y_n, z} = -\left[ C_{0,0,k+1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{0,n-1,k+1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^r}{r!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{i,0,k+1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,k+1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^r}{r!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{i-1,n-1,k+1} - \varphi_{i,n-1,k+1}]_{x, y_n, z} = \\ & = -\left[ C_{i,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,0} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_i)^r}{r!} \frac{(z - z_0)^{r-1}}{(r-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{i,0,k+1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,k+1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_i)^r}{r!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i-1,n-1,k+1} + \varphi_{i,n-1,k} - \varphi_{i,n-1,k+1} - \varphi_{i-1,n-1,k}]_{x, y_n, z} = \\ & = -\left[ C_{i,0,k+1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{i,n-1,k+1} \frac{(y_n - y_{n-1})^r}{r!} \right] \frac{(x - x_i)^r}{r!} \frac{(z - z_{k+1})^r}{r!}. \end{aligned} \]

But by equations (5.5.4) and (5.5.49) we have

\[ C_{i,0,l}(y_n - y_0)^r + \ldots + C_{i,n-1,l}(y_n - y_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n - 1\) and \(i = 0, 1, \ldots, n - 1\), \(l = 0, 1, \ldots, k, k + 1\), and consequently the other conditions (5.5.44) are satisfied for \(r = 1, 2, \ldots, n - 1\).

5.5.11. We now wish to determine the constants \(C_{0,n,k+1}, \ldots, C_{n,n,k+1}\) and then the constants \(C_{n,0,k+1}, \ldots, C_{n,n,k+1}\). To this end we assume that the system of equations

(5.5.51)
\[ \begin{aligned} C_{0,n,l} + \ldots + C_{n,n,l} &= 0 \\ C_{0,n,l}(x_n - x_0)^r + \ldots + C_{n-1,n,l}(x_n - x_{n-1})^r &= 0 \end{aligned} \]

for \(r = 1, 2, \ldots, n - 1\), which leads to the system

(5.5.52)
\[ \begin{aligned} C_{0,n,l} + \ldots + C_{n,n,l} &= 0 \\ C_{0,n,l} x_0 + \ldots + C_{n,n,l} x_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,n,l} x_0^{n-1} + \ldots + C_{n,n,l} x_n^{n-1} &= 0 \end{aligned} \]

as well as the system of equations

(5.5.53)
\[ \begin{aligned} C_{n,0,l} + \ldots + C_{n,n,l} &= 0 \\ C_{n,0,l}(y_n - y_0)^r + \ldots + C_{n,n-1,l}(y_n - y_{n-1})^r &= 0 \end{aligned} \]

for \(r = 1, 2, \ldots, n - 1\), which leads to the system

(5.5.54)
\[ \begin{aligned} C_{n,0,l} + \ldots + C_{n,n,l} &= 0 \\ C_{n,0,l} y_0 + \ldots + C_{n,n,l} y_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{n,0,l} y_0^{n-1} + \ldots + C_{n,n,l} y_n^{n-1} &= 0 \end{aligned} \]

are valid for \(l = 0, 1, \ldots, k\).

We wish to prove that the systems (5.5.51), (5.5.52), (5.5.53), (5.5.54) are also valid for \(l = k + 1\).

We have already proved that these systems are valid for \(l = 0\) (see subsection 5.3.8) and for \(l = 1\) (see subsection 5.4.10).

5.5.12. Let us consider formula (5.5.1), which is valid for \(i, j, l = 0, 1, \ldots, n - 1\). We shall write this formula for the indices \(i = n - 1\), \(j\) and \(l = k + 1\):

(5.5.55)
\[ \begin{aligned} & \varphi_{n-1,j,k+1}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,j,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_j)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,k+1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_0)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,k+1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,j,k+1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_j)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!} \end{aligned} \]

where the coefficients \(C_{0,j,k}, \ldots, C_{n,j,k}\) satisfy the equations

(5.5.56)
\[ \begin{aligned} C_{0,j,k} + \ldots + C_{n,j,k} &= 0 \\ C_{0,j,k} x_0 + \ldots + C_{n,j,k} x_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,j,k} x_0^{n-1} + \ldots + C_{n,j,k} x_n^{n-1} &= 0 \end{aligned} \]

for \(j, k = 0, 1, \ldots, n - 1\).

Taking these equations into account, formula (5.5.55) can be written in the form

(5.5.57)
\[ \begin{aligned} & \varphi_{n-1,j,k+1}(x, y, z) = \\ & = -\left[ C_{n,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{n,j,0} \frac{(y - y_j)^{n-1}}{(n-1)!} \right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{n,0,k+1} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{n,j,k+1} \frac{(y - y_j)^{n-1}}{(n-1)!} \right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!}. \end{aligned} \]

For \(j = n - 1\) this formula becomes

(5.5.58)
\[ \begin{aligned} & \varphi_{n-1,n-1,k+1}(x, y, z) = -\left[ C_{n,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{n,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{n,0,k+1} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{n,n-1,k+1} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!}. \end{aligned} \]

Likewise, formula (5.5.1) for the indices \(i, n - 1, k + 1\) can be written in the form

(5.5.59)
\[ \begin{aligned} & \varphi_{i,n-1,k+1}(x, y, z) = \left[ C_{0,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_i)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,k+1} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n-1,k+1} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,0,k+1} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n-1,k+1} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_i)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!}, \end{aligned} \]

where the coefficients \(C_{i,0,k}, \ldots, C_{i,n,k}\) satisfy the equations

(5.5.60)
\[ \begin{aligned} C_{i,0,k} + \ldots + C_{i,n,k} &= 0 \\ C_{i,0,k} y_0 + \ldots + C_{i,n,k} y_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i,0,k} y_0^{n-1} + \ldots + C_{i,n,k} y_n^{n-1} &= 0 \end{aligned} \]

for \(i, k = 0, 1, \ldots, n - 1\).

Taking these equations into account, formula (5.5.59) can be written in the form

(5.5.61)
\[ \begin{aligned} & \varphi_{i,n-1,k+1}(x, y, z) = -\left[ C_{0,n,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n,0} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{0,n,k+1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n,k+1} \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!}. \end{aligned} \]

For \(i = n - 1\) this formula becomes

(5.5.62)
\[ \begin{aligned} & \varphi_{n-1,n-1,k+1}(x, y, z) = -\left[ C_{0,n,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,n,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(z - z_0)^{n-1}}{(n-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{0,n,k+1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,n,k+1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(z - z_{k+1})^{n-1}}{(n-1)!}. \end{aligned} \]

Further on we shall need formulas (5.5.58) and (5.5.62).

5.5.13. Let us write the boundary conditions (5.5.7), (5.5.8), (5.5.9) corresponding to the indices \(i = n\), \(j = n\), \(k + 1\). Taking convention (A) into account, these conditions are

(5.5.63)
\[ \begin{aligned} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,n-1,k+1}]_{x_n, y_n, z} &= 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,n-1,k+1} - \varphi_{n-1,n-1,k}]_{x_n, y_n, z_{k+1}} &= \begin{cases} C_{n,n,k+1} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{aligned} \]

for \(r = 0, 1, \ldots, n - 1\).

For \(r = 0\) the first condition (5.5.63) is satisfied, because \(\varphi_{n-1,n-1,k+1}\) is a polynomial of degree \(n - 1\) in \(z\). The second condition leads to the equation

(5.5.64)
\[ C_{n,0,k+1} + \ldots + C_{n,n-1,k+1} + C_{n,n,k+1} = 0 \]

when formula (5.5.58) is used for \(\varphi_{n-1,n-1,k+1}\), or to the equation

(5.5.65)
\[ C_{0,n,k+1} + \ldots + C_{n-1,n,k+1} + C_{n,n,k+1} = 0 \]

when formula (5.5.62) is used for \(\varphi_{n-1,n-1,k+1}\).

Let us also consider the boundary conditions (5.5.7), (5.5.8), (5.5.9) for the indices \(i = n\), \(j = n - 1\), \(k + 1\) and \(i = n - 1\), \(j = n\), \(k + 1\). Of these conditions let us take only the following ones:

(5.5.66)
\[ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{n-1,n-1,k+1}]_{x_n, y, z} = 0 \]
(5.5.67)
\[ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,n-1,k+1}]_{x, y_n, z} = 0. \]

For \(r = 0\) these conditions are satisfied.

Let us examine these conditions for \(r = 1, 2, \ldots, n - 1\). Using formula (5.5.62) we have

(5.5.68)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{n-1,n-1,k+1}]_{x_n, y, z} = \\ & = -\left[C_{0,n,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,0} \frac{(x_n - x_{n-1})^r}{r!}\right] \frac{(y - y_n)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[C_{0,n,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,k+1} \frac{(x_n - x_{n-1})^r}{r!}\right] \frac{(y - y_n)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \end{aligned} \]

Likewise, using formula (5.5.58), we have

(5.5.69)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,n-1,k+1}]_{x, y_n, z} = \\ & = -\left[C_{n,0,0} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{n,n-1,0} \frac{(y_n - y_{n-1})^r}{r!}\right] \frac{(x - x_n)^{r-1}}{(r-1)!} \frac{(z - z_0)^{r-1}}{(r-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[C_{n,0,k+1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{n,n-1,k+1} \frac{(y_n - y_{n-1})^r}{r!}\right] \frac{(x - x_n)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!}. \end{aligned} \]

But by equations (5.5.51) the first \((k + 1)\) large brackets in formula (5.5.68) vanish for \(r = 1, 2, \ldots, n - 1\), and by equations (5.5.53) the first \((k + 1)\) large brackets in formula (5.5.69) vanish for \(r = 1, 2, \ldots, n - 1\). Formulas (5.5.68) and (5.5.69) reduce to:

\[ \begin{aligned} & \frac{\partial^{3(n-r)-1}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r}} [\varphi_{n-1,n-1,k+1}]_{x_n, y, z} = \\ & = -\left[C_{0,n,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,k+1} \frac{(x_n - x_{n-1})^r}{r!}\right] \frac{(y - y_n)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \end{aligned} \]

and

\[ \begin{aligned} & \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,n-1,k+1}]_{x, y_n, z} = \\ & = -\left[C_{n,0,k+1} \frac{(y_n - y_0)^r}{r!} + \ldots + C_{n,n-1,k+1} \frac{(y_n - y_{n-1})^r}{r!}\right] \frac{(x - x_n)^{r-1}}{(r-1)!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!} \end{aligned} \]

These two formulas show that the two conditions (5.5.66) and (5.5.67) are satisfied if we take

(5.5.70)
\[ C_{0,n,k+1}(x_n - x_0)^r + \ldots + C_{n-1,n,k+1}(x_n - x_{n-1})^r = 0 \]

and

(5.5.71)
\[ C_{n,0,k+1}(y_n - y_0)^r + \ldots + C_{n,n-1,k+1}(y_n - y_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n - 1\).

Equations (5.5.65) and (5.5.70) lead to the system

(5.5.72)
\[ \begin{aligned} & C_{0,n,k+1} && + \ldots + C_{n,n,k+1} && = 0 \\ & C_{0,n,k+1} x_0 && + \ldots + C_{n,n,k+1} x_n && = 0 \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & C_{0,n,k+1} x_0^{n-1} && + \ldots + C_{n,n,k+1} x_n^{n-1} && = 0. \end{aligned} \]

Likewise, equations (5.5.64) and (5.5.71) lead to the system

(5.5.73)
\[ \begin{aligned} & C_{n,0,k+1} && + \ldots + C_{n,n,k+1} && = 0 \\ & C_{n,0,k+1} y_0 && + \ldots + C_{n,n,k+1} y_n && = 0 \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & C_{n,0,k+1} y_0^{n-1} && + \ldots + C_{n,n,k+1} y_n^{n-1} && = 0. \end{aligned} \]

Systems (5.5.72), (5.5.73) show that systems (5.5.52), (5.5.54) are also valid for \(l = k + 1\).

It follows that systems (5.5.52), (5.5.54) are valid for \(l = 0, 1, \ldots, n - 1\).

Let us now prove that the other conditions (5.5.63) are satisfied for \(r = 1, 2, \ldots, n - 1\).

Formula (5.5.62) shows that

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,n-1,k+1}]_{x_n, y, z} = \\ & = -\left[C_{0,n,0} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,0} \frac{(x_n - x_{n-1})^r}{r!}\right] \frac{(y - y_n)^r}{r!} \frac{(z - z_0)^{r-1}}{(r-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[C_{0,n,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,k+1} \frac{(x_n - x_{n-1})^r}{r!}\right] \frac{(y - y_n)^r}{r!} \frac{(z - z_{k+1})^{r-1}}{(r-1)!}. \end{aligned} \]

Equations (5.5.51) and (5.5.70) show that all the large brackets on the right-hand side vanish for \(r = 1, 2, \ldots, n - 1\), and consequently condition (5.5.63) is satisfied for \(r = 1, 2, \ldots, n - 1\).

We may add that, by formula (5.5.58) and equations (5.5.53), we have

\[ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r}} [\varphi_{n-1,n-1,k+1}]_{x_n, y_n, z} = 0 \quad \text{for } r = 1, 2, \ldots, n - 1. \]

Finally, we have

\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,n-1,k+1} - \varphi_{n-1,n-1,k}]_{x_n, y, z} = \\ & -\left[C_{0,n,k+1} \frac{(x_n - x_0)^r}{r!} + \ldots + C_{n-1,n,k+1} \frac{(x_n - x_{n-1})^r}{r!}\right] \frac{(y - y_n)^r}{r!} \frac{(z - z_{k+1})^r}{r!} \end{aligned} \]

and equations (5.5.70) show that the right-hand side vanishes for \(r = 1, 2, \ldots, n - 1\).

We may add that

\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,n-1,k+1} - \varphi_{n-1,n-1,k}]_{x, y_n, z} = 0 \]

which follows from formula (5.5.58) and equations (5.5.71).

§ 5.6. The equations satisfied by the coefficients \(C_{i,j,0}, \ldots, C_{i,j,n}\) for \(i, j = 0, 1, \ldots, n\)

5.6.1. We shall prove that the coefficients \(C_{i,j,0}, \ldots, C_{i,j,n}\) satisfy the following equations:

(5.6.1)
\[ \begin{aligned} & C_{i,j,0} && + \ldots + C_{i,j,n} && = 0 \\ & C_{i,j,0} z_0 && + \ldots + C_{i,j,n} z_n && = 0 \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & C_{i,j,0} z_0^{n-1} && + \ldots + C_{i,j,n} z_n^{n-1} && = 0 \end{aligned} \]

for \(i, j = 0, 1, \ldots, n\).

It has already been proved that system (5.6.1) is valid for \(i = 0, 1, \ldots, n\) and \(j = 0\) (see subsection 5.3.10) and for \(i = 0\), \(j = 0, 1, \ldots, n\) (see subsection 5.3.9).

We shall first prove that system (5.6.1) is valid for \(j = 1\) and \(i = 0, 1, \ldots, n\).

For this we shall need the function \(\varphi_{i,j,k}\) given by formula (5.5.1), which we shall write in the following form:

(5.6.2)
\[ \begin{aligned} & \varphi_{i,j,k}(x, y, z) = \left[C_{0,0,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{0,0,k} \frac{(z - z_k)^{n-1}}{(n-1)!}\right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{i,0,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0,k} \frac{(z - z_k)^{n-1}}{(n-1)!}\right] \frac{(x - x_i)^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{0,j,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{0,j,k} \frac{(z - z_k)^{n-1}}{(n-1)!}\right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(y - y_j)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{i,j,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{i,j,k} \frac{(z - z_k)^{n-1}}{(n-1)!}\right] \frac{(x - x_i)^{n-1}}{(n-1)!} \frac{(y - y_j)^{n-1}}{(n-1)!}. \end{aligned} \]

For \(j = 1\) and \(k = n - 1\) we have

(5.6.3)
\[ \begin{aligned} & \varphi_{i,1,n-1}(x, y, z) = \left[C_{0,0,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{0,0,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!}\right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{i,0,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{i,0,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!}\right] \frac{(x - x_i)^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!} + \\ & + \left[C_{0,1,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{0,1,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!}\right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(y - y_1)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{i,1,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{i,1,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!}\right] \frac{(x - x_i)^{n-1}}{(n-1)!} \frac{(y - y_1)^{n-1}}{(n-1)!}. \end{aligned} \]

Let us take convention (A) into account and consider the boundary conditions (5.2.5), (5.2.6), (5.2.7) for the indices \(i, j = 1, n\). These conditions are

(5.6.4)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,1,n-1}]_{x, y, z_n} = 0 \\ & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,0,n-1} - \varphi_{i,1,n-1}]_{x, y_1, z_n} = 0 \\ & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i-1,1,n-1} - \varphi_{i,1,n-1}]_{x_i, y, z_n} = 0 \\ & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,0,n-1} + \varphi_{i-1,1,n-1} - \varphi_{i,1,n-1} - \varphi_{i-1,0,n-1}]_{x_i, y_1, z_n} = \begin{cases} C_{i,1,n} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{aligned} \]

for \(r = 0, 1, \ldots, n - 1\).

For \(r = 0\) the first three conditions (5.6.4) are satisfied, because \(\varphi_{i,1,n-1}\) and \(\varphi_{i-1,0,n-1}\) are polynomials of degree \(n - 1\) in \(x\) and \(y\).

The fourth condition (5.6.4) gives the equation

(5.6.5)
\[ C_{i,1,0} + \ldots + C_{i,1,n} = 0. \]

Let us now consider conditions (5.6.4) for \(r = 1, 2, \ldots, n - 1\).

By formula (5.6.3) we have

(5.6.6)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1} \varphi_{i,1,n-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z_n) = \left[C_{0,0,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{0,0,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(y - y_0)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{i,0,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{i,0,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(y - y_0)^{r-1}}{(r-1)!} + \\ & + \left[C_{0,1,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{0,1,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(y - y_1)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{i,1,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{i,1,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(y - y_1)^{r-1}}{(r-1)!}. \end{aligned} \]

But it has been shown that system (5.6.1) is valid for \(i = 0, 1, \ldots, n\) and \(j = 0\), whence it follows that

(5.6.7)
\[ C_{i,0,0}(z_n - z_0)^r + \ldots + C_{i,0,n-1}(z_n - z_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n - 1\).

Formula (5.6.6) reduces to

(5.6.8)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1} \varphi_{i,1,n-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z_n) = \left[C_{0,1,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{0,1,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(y - y_1)^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{i,1,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{i,1,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(y - y_1)^{r-1}}{(r-1)!}. \end{aligned} \]

But by equations (5.6.1), for \(i = 0\) and \(j = 1\), we have

\[ C_{0,1,0}(z_n - z_0)^r + \ldots + C_{0,1,n-1}(z_n - z_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n - 1. \]

Then formula (5.6.8), for \(i = 1\), reduces to:

\[ \frac{\partial^{3(n-r)-1} \varphi_{1,1,n-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z_n) = \left[C_{1,1,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{1,1,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_1)^{r-1}}{(r-1)!} \frac{(y - y_1)^{r-1}}{(r-1)!} \]

and in order that the first condition (5.6.4) be satisfied for \(r = 1, 2, \ldots, n - 1\) we must take

(5.6.9)
\[ C_{1,1,0}(z_n - z_0)^r + \ldots + C_{1,1,n-1}(z_n - z_{n-1})^r = 0. \]

Equation (5.6.5) for \(i = 1\) and equations (5.6.9) for \(r = 1, 2, \ldots, n - 1\) show that system (5.6.1) is valid for \(i = 1\) and \(j = 1\).

In the same way one proves that system (5.6.1) is valid for \(i = 2, 3, \ldots, n - 1\) and \(j = 1\).

It follows that we have

(5.6.10)
\[ C_{i,1,0}(z_n - z_0)^r + \ldots + C_{i,1,n-1}(z_n - z_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n - 1\) and \(i = 0, 1, \ldots, n - 1\).

Let us now examine the last three conditions (5.6.4) for \(r = 1, 2, \ldots, n - 1\) and prove that they are satisfied. By formula (5.6.3) we have

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,0,n-1} - \varphi_{i,1,n-1}]_{x, y, z_n} = \\ & = -\left[C_{0,1,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{0,1,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(y - y_1)^r}{r!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[C_{i,1,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{i,1,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_i)^{r-1}}{(r-1)!} \frac{(y - y_1)^r}{r!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i-1,1,n-1} - \varphi_{i,1,n-1}]_{x, y, z_n} = \\ & = -\left[C_{i,0,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{i,0,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_i)^r}{r!} \frac{(y - y_0)^{r-1}}{(r-1)!} - \\ & - \left[C_{i,1,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{i,1,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_i)^r}{r!} \frac{(y - y_1)^{r-1}}{(r-1)!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,0,n-1} + \varphi_{i-1,1,n-1} - \varphi_{i,1,n-1} - \varphi_{i-1,0,n-1}]_{x, y, z_n} = \\ & = -\left[C_{i,1,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{i,1,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_i)^r}{r!} \frac{(y - y_1)^r}{r!}. \end{aligned} \]

Taking into account equations (5.6.10) for \(r = 1, 2, \ldots, n - 1\) and \(i = 0, 1, \ldots, n - 1\), we deduce that the last three conditions (5.6.4) are satisfied for \(r = 1, 2, \ldots, n - 1\).

5.6.2. Further on we shall need two formulas, for \(\varphi_{n-1,1,n-1}\) and \(\varphi_{n-1,0,n-1}\).

Let us write formula (5.6.2) for \(i = n - 1\), \(k = n - 1\). We shall have

(5.6.11)
\[ \begin{aligned} & \varphi_{n-1,1,n-1}(x, y, z) = \left[C_{0,0,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{0,0,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!}\right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{n-1,0,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!}\right] \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!} + \\ & + \left[C_{0,1,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{0,1,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!}\right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(y - y_1)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{n-1,1,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,1,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!}\right] \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \frac{(y - y_1)^{n-1}}{(n-1)!} \end{aligned} \]

and let us write this formula in the form

(5.6.12)
\[ \begin{aligned} & \varphi_{n-1,1,n-1}(x, y, z) = \left[C_{0,0,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right] \frac{(z - z_0)^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{0,0,n-1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,n-1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right] \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!} + \\ & + \left[C_{0,1,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,1,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right] \frac{(z - z_0)^{n-1}}{(n-1)!} \frac{(y - y_1)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[C_{0,1,n-1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,1,n-1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!}\right] \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \frac{(y - y_1)^{n-1}}{(n-1)!} \end{aligned} \]

But we have proved that the system of equations

(5.5.3)
\[ \begin{aligned} & C_{0,j,l} && + \ldots + C_{n,j,l} && = 0 \\ & C_{0,j,l} x_0 && + \ldots + C_{n,j,l} x_n && = 0 \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & C_{0,j,l} x_0^{n-1} && + \ldots + C_{n,j,l} x_n^{n-1} && = 0 \end{aligned} \]

is valid for \(j, l = 0, 1, \ldots, n - 1\).

It then follows that for \(j = 0\) we have

(5.6.13)
\[ C_{0,0,l}(x - x_0)^{n-1} + \ldots + C_{n-1,0,l}(x - x_{n-1})^{n-1} = -C_{n,0,l}(x - x_n)^{n-1} \]

for \(l = 0, 1, \ldots, n - 1\).

Likewise, for \(j = 1\) we have

(5.6.14)
\[ C_{0,1,l}(x - x_0)^{n-1} + \ldots + C_{n-1,1,l}(x - x_{n-1})^{n-1} = -C_{n,1,l}(x - x_n)^{n-1} \]

for \(l = 0, 1, \ldots, n - 1\).

It then follows that formula (5.6.12) can be written in the form

(5.6.15)
\[ \begin{aligned} & \varphi_{n-1,1,n-1}(x, y, z) = -\left[C_{n,0,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{n,0,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!}\right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!} - \\ & - \left[C_{n,1,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{n,1,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!}\right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(y - y_1)^{n-1}}{(n-1)!}. \end{aligned} \]

In the same way one proves that

(5.6.16)
\[ \varphi_{n-1,0,n-1}(x, y, z) = -\left[C_{n,0,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{n,0,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!}\right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(y - y_0)^{n-1}}{(n-1)!}. \]

5.6.3. Let us now prove that the system of equations (5.6.1) is also valid for \(j = 1\) and \(i = n\).

To this end let us set \(i = n\), \(j = 1\), \(k = n\) in the boundary conditions (5.2.5), (5.2.6), (5.2.7) and take convention (A) into account. These conditions reduce to

(5.6.17)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{n-1,1,n-1}]_{x_n, y, z_n} = 0 \\ & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,1,n-1} - \varphi_{n-1,0,n-1}]_{x_n, y_1, z_n} = \begin{cases} C_{n,1,n} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{aligned} \]

for \(r = 0, 1, \ldots, n - 1\).

For \(r = 0\) the first condition (5.6.17) is satisfied, and the second leads, by formulas (5.6.15) and (5.6.16), to the equation

(5.6.18)
\[ C_{n,1,0} + \ldots + C_{n,1,n} = 0. \]

Let us now consider conditions (5.6.17) for \(r = 1, 2, \ldots, n - 1\). To this end let us write the boundary conditions (5.2.5), (5.2.6), (5.2.7) for \(i = n - 1\), \(j = 1\), \(k = n\) and, taking convention (A) into account, let us take from these conditions only the following one:

(5.6.19)
\[ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{n-1,1,n-1}]_{x, y, z_n} = 0 \quad \text{for } r = 0, 1, \ldots, n - 1. \]

For \(r = 0\) condition (5.6.19) is satisfied, \(\varphi_{n-1,1,n-1}\) being a polynomial of degree \(n - 1\) in \(x\) and in \(y\).

Let us now consider conditions (5.6.19) for \(r = 1, 2, \ldots, n - 1\). By formula (5.6.15) we have

(5.6.20)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1} \varphi_{n-1,1,n-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z_n) = -\left[C_{n,0,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{n,0,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_n)^{r-1}}{(r-1)!} \frac{(y - y_0)^{r-1}}{(r-1)!} - \\ & - \left[C_{n,1,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{n,1,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_n)^{r-1}}{(r-1)!} \frac{(y - y_1)^{r-1}}{(r-1)!}. \end{aligned} \]

But since system (5.6.1) is valid for \(i = 0, 1, \ldots, n\) and \(j = 0\), we have

(5.6.21)
\[ C_{n,0,0}(z_n - z_0)^r + \ldots + C_{n,0,n-1}(z_n - z_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n - 1. \]

Then formula (5.6.20) reduces to

\[ \frac{\partial^{3(n-r)-1} \varphi_{n-1,1,n-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z_n) = -\left[C_{n,1,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{n,1,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_n)^{r-1}}{(r-1)!} \frac{(y - y_1)^{r-1}}{(r-1)!} \]

and in order that condition (5.6.19) be satisfied for \(r = 1, 2, \ldots, n - 1\), we must take

(5.6.22)
\[ C_{n,1,0}(z_n - z_0)^r + \ldots + C_{n,1,n-1}(z_n - z_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n - 1. \]

The system of equations (5.6.18) and (5.6.22) shows that the system of equations (5.6.1) is valid for \(j = 1\) and \(i = n\).

It remains to show that conditions (5.6.17) are satisfied for \(r = 1, 2, \ldots, n - 1\).

By equations (5.6.15) and (5.6.16) we have

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{n-1,1,n-1}]_{x, y, z_n} = \\ & = -\left[C_{n,0,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{n,0,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_n)^r}{r!} \frac{(y - y_0)^{r-1}}{(r-1)!} - \\ & - \left[C_{n,1,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{n,1,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_n)^r}{r!} \frac{(y - y_1)^{r-1}}{(r-1)!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,1,n-1} - \varphi_{n-1,0,n-1}]_{x, y, z_n} = \\ & = -\left[C_{n,1,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{n,1,n-1} \frac{(z_n - z_{n-1})^r}{r!}\right] \frac{(x - x_n)^r}{r!} \frac{(y - y_1)^r}{r!}. \end{aligned} \]

By equations (5.6.21) and (5.6.22) for \(r = 1, 2, \ldots, n - 1\), the large brackets of the preceding formulas vanish, and consequently conditions (5.6.17) are satisfied for \(r = 1, 2, \ldots, n - 1\).

5.6.4. Let us consider the system of equations

(5.6.23)
\[ \begin{aligned} & C_{i',j',0} && + \ldots + C_{i',j',n} && = 0 \\ & C_{i',j',0} z_0 && + \ldots + C_{i',j',n} z_n && = 0 \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & C_{i',j',0} z_0^{n-1} && + \ldots + C_{i',j',n} z_n^{n-1} && = 0. \end{aligned} \]

It is valid for \(i' = 0\) and \(j' = 0, 1, \ldots, n\), because in this case it coincides with system (5.3.56) (see subsection 5.3.9). By equations (5.3.64), for \(i' = 1\) (see subsection 5.3.10), system (5.6.23) is valid for \(i = 1\), \(j' = 0\).

We wish to prove that if system (5.6.23) is valid for \(i' = 1\) and \(j' = 0, 1, \ldots, j-1\), which is true for \(j' = 0\), it is still true for \(i' = 1\) and \(j' = j\).

To this end let us write the boundary conditions (5.2.5), (5.2.6), (5.2.7) for the indices \(1, j, n\) and \(r = 0, 1, \ldots, n-1\). Taking convention (A) into account, these conditions are

(5.6.24)
\[ \begin{aligned} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{1,j,n-1}]_{x, y, z_n} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{1,j-1,n-1} - \varphi_{1,j,n-1}]_{x, y_j, z_n} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{0,j,n-1} - \varphi_{1,j,n-1}]_{x_1, y, z_n} &= 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{1,j-1,n-1} + \varphi_{0,j,n-1} - \varphi_{1,j,n-1} - \varphi_{0,j-1,n-1}]_{x_1, y_j, z_n} &= \begin{cases} C_{1,j,n} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{aligned} \]

for \(r = 0, 1, \ldots, n-1\).

By formula (5.6.2), for the indices \(i = 1, j, k = n-1\), we have

(5.6.25)
\[ \begin{aligned} & \varphi_{1,j,n-1}(x, y, z) = \left[ C_{0,0,0} \frac{(z - z_{0})^{n-1}}{(n-1)!} + \ldots + C_{0,0,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_{0})^{n-1}}{(n-1)!} \frac{(y - y_{0})^{n-1}}{(n-1)!} + \\ & + \left[ C_{1,0,0} \frac{(z - z_{0})^{n-1}}{(n-1)!} + \ldots + C_{1,0,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_{1})^{n-1}}{(n-1)!} \frac{(y - y_{0})^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,0} \frac{(z - z_{0})^{n-1}}{(n-1)!} + \ldots + C_{0,j,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_{0})^{n-1}}{(n-1)!} \frac{(y - y_{j})^{n-1}}{(n-1)!} + \\ & + \left[ C_{1,j,0} \frac{(z - z_{0})^{n-1}}{(n-1)!} + \ldots + C_{1,j,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_{1})^{n-1}}{(n-1)!} \frac{(y - y_{j})^{n-1}}{(n-1)!} \end{aligned} \]

and the analogous formulas for the indices \(1, j-1, n-1\); \(0, j, n-1\); \(0, j-1, n-1\).

For \(r = 0\) the first three conditions (5.6.24) are satisfied, and the fourth condition leads to the equation

(5.6.26)
\[ C_{1,j,0} + \ldots + C_{1,j,n} = 0. \]

Let us now examine conditions (5.6.24) for \(r = 1, 2, \ldots, n-1\). By formula (5.6.25) we have

(5.6.27)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1} \varphi_{1,j,n-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z_n) = \left[ C_{0,0,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{0,0,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{0})^{r-1}}{(r-1)!} \frac{(y - y_{0})^{r-1}}{(r-1)!} + \\ & + \left[ C_{1,0,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{1,0,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{1})^{r-1}}{(r-1)!} \frac{(y - y_{0})^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{0,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{0})^{r-1}}{(r-1)!} \frac{(y - y_{j})^{r-1}}{(r-1)!} + \\ & + \left[ C_{1,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{1,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{1})^{r-1}}{(r-1)!} \frac{(y - y_{j})^{r-1}}{(r-1)!}. \end{aligned} \]

But by equations (5.3.56) (see subsection 5.3.9) we have

(5.6.28)
\[ C_{0,j',0}(z_n - z_0)^r + \ldots + C_{0,j',n-1}(z_n - z_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\) and \(j' = 0, 1, \ldots, n\).

On the other hand, by the hypothesis we made in subsection 5.6.4, system (5.6.23) is valid for \(i = 1\) and \(j' = 0, 1, \ldots, j-1\), and consequently we have

(5.6.29)
\[ C_{1,j',0}(z_n - z_0)^r + \ldots + C_{1,j',n-1}(z_n - z_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\) and \(j' = 0, 1, \ldots, j-1\).

It then follows from formula (5.6.27) that

(5.6.30)
\[ \frac{\partial^{3(n-r)-1} \varphi_{1,j,n-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z_n) = \left[ C_{1,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{1,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{1})^{r-1}}{(r-1)!} \frac{(y - y_{j})^{r-1}}{(r-1)!} \]

and in order that the first condition (5.6.24) be satisfied for \(r = 1, 2, \ldots, n-1\), we must take

(5.6.31)
\[ C_{1,j,0}(z_n - z_0)^r + \ldots + C_{1,j,n-1}(z_n - z_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n-1. \]

The system formed by equations (5.6.26) and (5.6.31) shows that system (5.6.23) is valid for \(i = 1\) and \(j' = j\).

System (5.6.23) is therefore general for \(i = 1\); it is valid for \(j = 0, 1, \ldots, n-1\).

It remains to show that the other conditions (5.6.24) are satisfied for \(r = 1, 2, \ldots, n-1\).

By formula (5.6.25) we have

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{1,j-1,n-1} - \varphi_{1,j,n-1}]_{x, y, z_n} = \\ & = -\left[ C_{0,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{0,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{0})^{r-1}}{(r-1)!} \frac{(y - y_{j})^{r}}{r!} - \\ & - \left[ C_{1,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{1,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{1})^{r-1}}{(r-1)!} \frac{(y - y_{j})^{r}}{r!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{0,j,n-1} - \varphi_{1,j,n-1}]_{x, y, z_n} = \\ & = -\left[ C_{1,0,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{1,0,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{1})^{r}}{r!} \frac{(y - y_{0})^{r-1}}{(r-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{1,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{1,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{1})^{r}}{r!} \frac{(y - y_{j})^{r-1}}{(r-1)!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{1,j-1,n-1} + \varphi_{0,j,n-1} - \varphi_{1,j,n-1} - \varphi_{0,j-1,n-1}]_{x_1, y, z_n} = \\ & = -\left[ C_{1,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{1,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{1})^{r}}{r!} \frac{(y - y_{j})^{r}}{r!} \end{aligned} \]

By equations (5.6.28) and (5.6.31) the large brackets on the right-hand sides of these formulas vanish for \(r = 1, 2, \ldots, n-1\), which shows that the last three conditions (5.6.24) are satisfied for \(r = 1, 2, \ldots, n-1\).

5.6.5. It has been proved that the system of equations

(5.6.32)
\[ \begin{aligned} C_{i',j',0} + \ldots + C_{i',j',n} &= 0 \\ C_{i',j',0} z_0 + \ldots + C_{i',j',n} z_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i',j',0} z_0^{n-1} + \ldots + C_{i',j',n} z_n^{n-1} &= 0 \end{aligned} \]

is valid for \(i' = 0, 1\) and \(j' = 0, 1, \ldots, n-1\).

Let us prove that if system (5.6.32) is valid for \(i' = 0, 1, \ldots, i-1\) and \(j' = 0, 1, \ldots, n-1\), it is also valid for \(i' = i\) and \(j' = 0, 1, \ldots, n-1\).

To this end we consider the function \(\varphi_{i,j,k}\) for \(k = n-1\), that is

(5.6.33)
\[ \begin{aligned} & \varphi_{i,j,n-1}(x, y, z) = \left[ C_{0,0,0} \frac{(z - z_{0})^{n-1}}{(n-1)!} + \ldots + C_{0,0,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_{0})^{n-1}}{(n-1)!} \frac{(y - y_{0})^{n-1}}{(n-1)!} \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & + \left[ C_{i,0,0} \frac{(z - z_{0})^{n-1}}{(n-1)!} + \ldots + C_{i,0,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_{i})^{n-1}}{(n-1)!} \frac{(y - y_{0})^{n-1}}{(n-1)!} \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,0} \frac{(z - z_{0})^{n-1}}{(n-1)!} + \ldots + C_{0,j,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_{0})^{n-1}}{(n-1)!} \frac{(y - y_{j})^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,j,0} \frac{(z - z_{0})^{n-1}}{(n-1)!} + \ldots + C_{i,j,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_{i})^{n-1}}{(n-1)!} \frac{(y - y_{j})^{n-1}}{(n-1)!} \end{aligned} \]

The boundary conditions (5.2.5), (5.2.6), (5.2.7) for the indices \(i, j, n\) are the following:

(5.6.34)
\[ \begin{aligned} \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,j,n-1}]_{x, y, z_n} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,j-1,n-1} - \varphi_{i,j,n-1}]_{x, y_j, z_n} &= 0 \\ \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i-1,j,n-1} - \varphi_{i,j,n-1}]_{x_i, y, z_n} &= 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,j-1,n-1} + \varphi_{i-1,j,n-1} - \varphi_{i,j,n-1} - \varphi_{i-1,j-1,n-1}]_{x_i, y_j, z_n} &= \begin{cases} C_{i,j,n} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{aligned} \]

for \(r = 0, 1, \ldots, n-1\).

We consider conditions (5.6.34) for \(r = 0\).

The first three conditions are satisfied. The fourth condition leads to the equation

(5.6.35)
\[ C_{i,j,0} + \ldots + C_{i,j,n} = 0. \]

Let us now examine conditions (5.6.34) for \(r = 1, 2, \ldots, n-1\). By formula (5.6.33) we have

(5.6.36)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1} \varphi_{i,j,n-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z_n) = \left[ C_{0,0,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{0,0,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{0})^{r-1}}{(r-1)!} \frac{(y - y_{0})^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,0,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{i,0,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{i})^{r-1}}{(r-1)!} \frac{(y - y_{0})^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{0,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{0})^{r-1}}{(r-1)!} \frac{(y - y_{j})^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{i,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{i})^{r-1}}{(r-1)!} \frac{(y - y_{j})^{r-1}}{(r-1)!} \end{aligned} \]

But since system (5.6.32) is valid for \(i' = 0, 1, \ldots, i-1\) and \(j' = 0, 1, \ldots, n-1\), formula (5.6.36) reduces to

(5.6.37)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1} \varphi_{i,j,n-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z_n) = \left[ C_{0,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{0,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{0})^{r-1}}{(r-1)!} \frac{(y - y_{j})^{r-1}}{(r-1)!} + \\ & + \left[ C_{1,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{1,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{1})^{r-1}}{(r-1)!} \frac{(y - y_{j})^{r-1}}{(r-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{i,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{i})^{r-1}}{(r-1)!} \frac{(y - y_{j})^{r-1}}{(r-1)!} \end{aligned} \]

for \(r = 1, 2, \ldots, n-1\).

Since system (5.6.23) is valid for \(i = 0\), \(j = 0, 1, \ldots, n-1\), the first large bracket vanishes for \(r = 1, 2, \ldots, n-1\). Further, in order that the first condition (5.6.34) be satisfied when \(i = 1\), for \(r = 1, 2, \ldots, n-1\), we must take

(5.6.38)
\[ C_{1,j,0}(z_n - z_0)^r + \ldots + C_{1,j,n-1}(z_n - z_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n-1. \]

Equation (5.6.35) for \(i = 1\) and equations (5.6.38) show that system (5.6.32) is valid for \(i' = 1\) and \(j' = 0, 1, \ldots, n-1\).

Continuing this reasoning, one arrives step by step at the conclusion that system (5.6.32) is valid for \(i' = i\) and \(j' = 0, 1, \ldots, n-1\).

It remains for us to prove that system (5.6.32) is also valid for \(i = n\).

By formula (5.6.36) we have

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,j-1,n-1} - \varphi_{i,j,n-1}]_{x, y, z_n} = \\ & = -\left[ C_{0,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{0,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{0})^{r-1}}{(r-1)!} \frac{(y - y_{j})^{r}}{r!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ & - \left[ C_{i,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{i,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{i})^{r-1}}{(r-1)!} \frac{(y - y_{j})^{r}}{r!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i-1,j,n-1} - \varphi_{i,j,n-1}]_{x, y, z_n} = \\ & = -\left[ C_{i,0,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{i,0,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{i})^{r}}{r!} \frac{(y - y_{0})^{r-1}}{(r-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{i,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{i,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{i})^{r}}{r!} \frac{(y - y_{j})^{r-1}}{(r-1)!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,j-1,n-1} + \varphi_{i-1,j,n-1} - \varphi_{i,j,n-1} - \varphi_{i-1,j-1,n-1}]_{x, y, z_n} = \\ & = -\left[ C_{i,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{i,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{i})^{r}}{r!} \frac{(y - y_{j})^{r}}{r!} \end{aligned} \]

By equations (5.6.32) we have

\[ C_{i',j,0}(z_n - z_0)^r + \ldots + C_{i',j,n-1}(z_n - z_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\) and \(i' = 0, 1, \ldots, n\), and also

\[ C_{i,j',0}(z_n - z_0)^r + \ldots + C_{i,j',n-1}(z_n - z_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\) and \(j' = 0, 1, \ldots, j\).

The large brackets on the right-hand sides of the preceding formulas therefore vanish for \(r = 1, 2, \ldots, n-1\), and consequently the last three conditions (5.6.34) are satisfied for \(r = 1, 2, \ldots, n-1\).

5.6.6. In order to prove that system (5.6.32) is also valid for \(i = n\), let us write the boundary conditions (5.2.5), (5.2.6), (5.2.7) for \(i = n, j, k = n\). Taking convention (A) into account, these conditions are

(5.6.39)
\[ \begin{aligned} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{n-1,j,n-1}]_{x_n, y, z_n} &= 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,j,n-1} - \varphi_{n-1,j-1,n-1}]_{x_n, y_j, z_n} &= \begin{cases} C_{n,j,n} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{aligned} \]

for \(r = 1, 2, \ldots, n-1\).

To simplify the calculations, we need to write the function \(\varphi_{n-1,j,n-1}\) in another form.

By formula (5.6.2) we can write

(5.6.40)
\[ \begin{aligned} & \varphi_{n-1,j,n-1}(x, y, z) = \left[ C_{0,0,0} \frac{(x - x_{0})^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_{0})^{n-1}}{(n-1)!} \frac{(z - z_{0})^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,n-1} \frac{(x - x_{0})^{n-1}}{(n-1)!} + \ldots + C_{n-1,0,n-1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_{0})^{n-1}}{(n-1)!} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,0} \frac{(x - x_{0})^{n-1}}{(n-1)!} + \ldots + C_{n-1,j,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_{j})^{n-1}}{(n-1)!} \frac{(z - z_{0})^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,j,n-1} \frac{(x - x_{0})^{n-1}}{(n-1)!} + \ldots + C_{n-1,j,n-1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_{j})^{n-1}}{(n-1)!} \frac{(z - z_{n-1})^{n-1}}{(n-1)!}. \end{aligned} \]

But it has been proved (see subsection 5.5.9) that the constants \(C_{0,j,k}, \ldots, C_{n,j,k}\) satisfy the equations

(5.6.41)
\[ \begin{aligned} C_{0,j,l} + \ldots + C_{n,j,l} &= 0 \\ C_{0,j,l} x_0 + \ldots + C_{n,j,l} x_n &= 0. \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,j,l} x_0^{n-1} + \ldots + C_{n,j,l} x_n^{n-1} &= 0 \end{aligned} \]

for \(l = 0, 1, \ldots, n-1\) and \(j = 0, 1, \ldots, n\).

It follows that we shall have

\[ \begin{aligned} & C_{0,j,l}(x - x_0)^{n-1} + \ldots + C_{n-1,j,l}(x - x_{n-1})^{n-1} = x^{n-1}(C_{0,j,l} + \ldots + C_{n-1,j,l}) - \\ & \qquad - C_{n-1}^{1} x^{n-2}(C_{0,j,l} x_0 + \ldots + C_{n-1,j,l} x_{n-1}) + \\ & \qquad + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + (-1)^{n-1} C_{n-1}^{n-1}(C_{0,j,l} x_0^{n-1} + \ldots + C_{n-1,j,l} x_{n-1}^{n-1}) \end{aligned} \]

and, taking equations (5.6.41) into account, we shall have

(5.6.42)
\[ C_{0,j,l}(x - x_0)^{n-1} + \ldots + C_{n-1,j,l}(x - x_{n-1})^{n-1} = -C_{n,j,l}(x - x_n)^{n-1}. \]

We can then write formula (5.6.40) in the form

(5.6.43)
\[ \begin{aligned} & \varphi_{n-1,j,n-1}(x, y, z) = -\left[ C_{n,0,0} \frac{(z - z_{0})^{n-1}}{(n-1)!} + \ldots + C_{n,0,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_{n})^{n-1}}{(n-1)!} \frac{(y - y_{0})^{n-1}}{(n-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{n,j,0} \frac{(z - z_{0})^{n-1}}{(n-1)!} + \ldots + C_{n,j,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_{n})^{n-1}}{(n-1)!} \frac{(y - y_{j})^{n-1}}{(n-1)!} \end{aligned} \]

Let us write conditions (5.6.39) for \(r = 0\).

The first condition is satisfied, since \(\varphi_{n-1,j,n-1}\) is a polynomial of degree \(n-1\) in \(y\). The second condition leads to the equation

(5.6.44)
\[ C_{n,j,0} + \ldots + C_{n,j,n} = 0. \]

Let us also write the boundary conditions (5.2.5), (5.2.6), (5.2.7) for \(i = n-1, j, k = n\) and take convention (A) into account. Of these conditions let us take only the following one:

(5.6.45)
\[ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{n-1,j,n-1}]_{x, y, z_n} = 0 \quad \text{for } r = 0, 1, \ldots, n-1. \]

Condition (5.6.45) is satisfied for \(r = 0\).

Let us examine conditions (5.6.45) for \(r = 1, 2, \ldots, n-1\). We shall have

(5.6.46)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1} \varphi_{n-1,j,n-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z_n) = -\left[ C_{n,0,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{n,0,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{n})^{r-1}}{(r-1)!} \frac{(y - y_{0})^{r-1}}{(r-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{n,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{n,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{n})^{r-1}}{(r-1)!} \frac{(y - y_{j})^{r-1}}{(r-1)!}. \end{aligned} \]

But we have the system

(5.3.64)
\[ \begin{aligned} C_{i,0,0} + \ldots + C_{i,0,n} &= 0 \\ C_{i,0,0} z_0 + \ldots + C_{i,0,n} z_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i,0,0} z_0^{n-1} + \ldots + C_{i,0,n} z_n^{n-1} &= 0 \end{aligned} \]

which is true for \(i = 0, 1, \ldots, n\), whence it follows that

(5.6.47)
\[ C_{n,0,0}(z_n - z_0)^r + \ldots + C_{n,0,n-1}(z_n - z_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n-1. \]

Then in formula (5.6.46) the first large bracket on the right-hand side vanishes, and in order that conditions (5.6.45) be satisfied for \(j = 1\) and \(r = 1, 2, \ldots, n-1\), we must take

\[ C_{n,1,0}(z_n - z_0)^r + \ldots + C_{n,1,n-1}(z_n - z_{n-1})^r = 0 \quad \text{for } r = 1, 2, \ldots, n-1. \]

Following the same reasoning, one proves that

(5.6.48)
\[ C_{n,j,0}(z_n - z_0)^r + \ldots + C_{n,j,n-1}(z_n - z_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\) and \(j = 0, 1, \ldots, n-1\).

Equation (5.6.44) and equations (5.6.48) for \(r = 1, 2, \ldots, n-1\) show that system (5.6.23) is valid for \(i' = 0, 1, \ldots, n\) and \(j' = 0, 1, \ldots, n-1\).

It remains to show that system (5.6.23) is also valid for \(j' = n\) and \(i' = 0, 1, \ldots, n\).

But first let us show that conditions (5.6.39) are satisfied for \(r = 1, 2, \ldots, n-1\). We have

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r-1} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{n-1,j,n-1}]_{x, y, z_n} = \\ & = -\left[ C_{n,0,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{n,0,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{n})^{r}}{r!} \frac{(y - y_{0})^{r-1}}{(r-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{n,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{n,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{n})^{r}}{r!} \frac{(y - y_{j})^{r-1}}{(r-1)!} \end{aligned} \]

and

\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,j,n-1} - \varphi_{n-1,j-1,n-1}]_{x, y, z_n} = \\ & = -\left[ C_{n,j,0} \frac{(z_n - z_{0})^{r}}{r!} + \ldots + C_{n,j,n-1} \frac{(z_n - z_{n-1})^{r}}{r!} \right] \frac{(x - x_{n})^{r}}{r!} \frac{(y - y_{j})^{r}}{r!}. \end{aligned} \]

But by equations (5.6.48) the large brackets on the right-hand side vanish for \(r = 1, 2, \ldots, n-1\), which proves that conditions (5.6.39) are satisfied for \(r = 1, 2, \ldots, n-1\).

5.6.7. It has been proved (see subsection 5.3.9) that the system

(5.3.56)
\[ \begin{aligned} C_{0,j,0} + \ldots + C_{0,j,n} &= 0 \\ C_{0,j,0} z_0 + \ldots + C_{0,j,n} z_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,j,0} z_0^{n-1} + \ldots + C_{0,j,n} z_n^{n-1} &= 0 \end{aligned} \]

is valid for \(j = 0, 1, \ldots, n\). Hence for \(j = n\) we have

(5.6.49)
\[ \begin{aligned} C_{0,n,0} + \ldots + C_{0,n,n} &= 0 \\ C_{0,n,0} z_0 + \ldots + C_{0,n,n} z_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,n,0} z_0^{n-1} + \ldots + C_{0,n,n} z_n^{n-1} &= 0. \end{aligned} \]

We wish to prove that the system

(5.6.50)
\[ \begin{aligned} C_{i,n,0} + \ldots + C_{i,n,n} &= 0 \\ C_{i,n,0} z_0 + \ldots + C_{i,n,n} z_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i,n,0} z_0^{n-1} + \ldots + C_{i,n,n} z_n^{n-1} &= 0 \end{aligned} \]

which coincides with system (5.6.49) for \(i = 0\), is also valid for \(i = 1, 2, \ldots, n\).

To this end, we first consider the case \(i = 1\) and write the boundary conditions (5.2.5), (5.2.6), (5.2.7) for \(i = 1\), \(j = n\), \(k = n\), taking convention (A) into account. These conditions are

(5.6.51)
\[ \begin{aligned} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{1,n-1,n-1}]_{x, y_n, z_n} &= 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{1,n-1,n-1} - \varphi_{0,n-1,n-1}]_{x_1 y_n z_n} &= \begin{cases} C_{1,n,n} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0. \end{cases} \end{aligned} \]

The function \(\varphi_{1,n-1,n-1}\) given by formula (5.6.2) can be written in the form

(5.6.52)
\[ \begin{aligned} & \varphi_{1,n-1,n-1}(x, y, z) = \left[ C_{0,0,0} \frac{(y - y_{0})^{n-1}}{(n-1)!} + \ldots + C_{0,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(z - z_{0})^{n-1}}{(n-1)!} \frac{(x - x_{0})^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,n-1} \frac{(y - y_{0})^{n-1}}{(n-1)!} + \ldots + C_{0,n-1,n-1} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \frac{(x - x_{0})^{n-1}}{(n-1)!} + \\ & + \left[ C_{1,0,0} \frac{(y - y_{0})^{n-1}}{(n-1)!} + \ldots + C_{1,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(z - z_{0})^{n-1}}{(n-1)!} \frac{(x - x_{1})^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{1,0,n-1} \frac{(y - y_{0})^{n-1}}{(n-1)!} + \ldots + C_{1,n-1,n-1} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \frac{(x - x_{1})^{n-1}}{(n-1)!} \end{aligned} \]

But it has been shown (see subsection 5.5.12) that the system

(5.5.60)
\[ \begin{aligned} C_{i,0,k} + \ldots + C_{i,n,k} &= 0 \\ C_{i,0,k} y_0 + \ldots + C_{i,n,k} y_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i,0,k} y_0^{n-1} + \ldots + C_{i,n,k} y_n^{n-1} &= 0 \end{aligned} \]

is valid for \(i = 0, 1, \ldots, n\) and \(k = 0, 1, \ldots, n-1\).

Then for \(i = 0, 1\) we have

(5.6.53)
\[ C_{0,0,k}(y - y_0)^{n-1} + \ldots + C_{0,n-1,k}(y - y_{n-1})^{n-1} = -C_{0,n,k}(y - y_n)^{n-1} \]
(5.6.54)
\[ C_{1,0,k}(y - y_0)^{n-1} + \ldots + C_{1,n-1,k}(y - y_{n-1})^{n-1} = -C_{1,n,k}(y - y_n)^{n-1} \]

and consequently

(5.6.55)
\[ \begin{aligned} & \varphi_{1,n-1,n-1}(x, y, z) = -\left[ C_{0,n,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(y - y_n)^{n-1}}{(n-1)!} - \\ & - \left[ C_{1,n,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{1,n,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_1)^{n-1}}{(n-1)!} \frac{(y - y_n)^{n-1}}{(n-1)!}. \end{aligned} \]

In the same way one shows that

(5.6.56)
\[ \varphi_{0,n-1,n-1}(x, y, z) = -\left[ C_{0,n,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_0)^{n-1}}{(n-1)!} \frac{(y - y_n)^{n-1}}{(n-1)!}. \]

For \(r = 0\) the first condition (5.6.51) is satisfied, \(\varphi_{1,n-1,n-1}\) being a polynomial of degree \(n-1\) in \(x\). The second condition (5.6.51) leads, for \(r = 0\), to the equation

(5.6.57)
\[ C_{1,n,0} + \ldots + C_{1,n,n} = 0. \]

Let us write the boundary conditions (5.2.5), (5.2.6), (5.2.7) for \(i = 1\), \(j = n-1\), \(k = n\), and of these conditions let us choose only the following one:

(5.6.58)
\[ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{1,n-1,n-1}]_{x, y, z_n} = 0 \quad\text{for } r = 1, 2, \ldots, n-1. \]

By formula (5.6.55) we have

(5.6.59)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1} \varphi_{1,n-1,n-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z_n) = -\left[ C_{0,n,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{0,n,n-1} \frac{(z_n - z_{n-1})^r}{r!} \right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(y - y_n)^{r-1}}{(r-1)!} - \\ & - \left[ C_{1,n,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{1,n,n-1} \frac{(z_n - z_{n-1})^r}{r!} \right] \frac{(x - x_1)^{r-1}}{(r-1)!} \frac{(y - y_n)^{r-1}}{(r-1)!}. \end{aligned} \]

But by system (5.6.49) we have

(5.6.60)
\[ C_{0,n,0}(z_n - z_0)^r + \ldots + C_{0,n,n-1}(z_n - z_{n-1})^r = 0 \quad\text{for } r = 1, 2, \ldots, n-1. \]

Then, in order that conditions (5.6.51) be satisfied for \(r = 1, 2, \ldots, n-1\), we must take

(5.6.61)
\[ C_{1,n,0}(z_n - z_0)^r + \ldots + C_{1,n,n-1}(z_n - z_{n-1})^r = 0 \quad\text{for } r = 1, 2, \ldots, n-1. \]

Equations (5.6.57) and (5.6.61) show that system (5.6.50) is valid for \(i = 1\); it remains to show that conditions (5.6.51) are satisfied for \(r = 1, 2, \ldots, n-1\). By formulas (5.6.55) and (5.6.56) we have

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{1,n-1,n-1}]_{x, y_n, z_n} = \\ & = -\left[ C_{0,n,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{0,n,n-1} \frac{(z_n - z_{n-1})^r}{r!} \right] \frac{(x - x_0)^{r-1}}{(r-1)!} \frac{(y - y_n)^r}{r!} - \\ & - \left[ C_{1,n,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{1,n,n-1} \frac{(z_n - z_{n-1})^r}{r!} \right] \frac{(x - x_1)^{r-1}}{(r-1)!} \frac{(y - y_n)^r}{r!} \end{aligned} \]
\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{1,n-1,n-1} - \varphi_{0,n-1,n-1}]_{x, y, z_n} = \\ & = -\left[ C_{1,n,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{1,n,n-1} \frac{(z_n - z_{n-1})^r}{r!} \right] \frac{(x - x_1)^r}{r!} \frac{(y - y_n)^r}{r!}. \end{aligned} \]

But by equations (5.6.60) and (5.6.61) for \(r = 1, 2, \ldots, n-1\), the large brackets on the right-hand sides vanish for \(r = 1, 2, \ldots, n-1\), which shows that conditions (5.6.51) are satisfied for \(r = 1, 2, \ldots, n-1\).

5.6.8. Let us suppose that we have proved that the system

(5.6.62)
\[ \begin{aligned} C_{i',n,0} + \ldots + C_{i',n,n} &= 0 \\ C_{i',n,0} z_0 + \ldots + C_{i',n,n} z_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i',n,0} z_0^{n-1} + \ldots + C_{i',n,n} z_n^{n-1} &= 0 \end{aligned} \]

which is valid for \(i' = 0, 1\), is also valid for \(i' = 0, 1, \ldots, i-1\).

Let us prove that system (5.6.62) is also valid for \(i' = i\).

To this end let us write, as in the preceding subsection, the function \(\varphi_{i,n-1,n-1}\) in the form

(5.6.63)
\[ \begin{aligned} & \varphi_{i,n-1,n-1}(x, y, z) = \left[ C_{0,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(z - z_0)^{n-1}}{(n-1)!} \frac{(x - x_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{0,0,n-1} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n-1,n-1} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \frac{(x - x_0)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,0,0} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n-1,0} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(z - z_0)^{n-1}}{(n-1)!} \frac{(x - x_i)^{n-1}}{(n-1)!} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + \left[ C_{i,0,n-1} \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n-1,n-1} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right] \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \frac{(x - x_i)^{n-1}}{(n-1)!}. \end{aligned} \]

But the systems

(5.6.64)
\[ \begin{aligned} C_{i,0,k} + \ldots + C_{i,n,k} &= 0 \\ C_{i,0,k} y_0 + \ldots + C_{i,n,k} y_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i,0,k} y_0^{n-1} + \ldots + C_{i,n,k} y_n^{n-1} &= 0 \end{aligned} \]

are true for \(i = 0, 1, \ldots, n\) and \(k = 0, 1, \ldots, n-1\).

It then follows that

\[ C_{i,0,k}(y - y_0)^{n-1} + \ldots + C_{i,n-1,k}(y - y_{n-1})^{n-1} = -C_{i,n,k}(y - y_n)^{n-1} \]

for \(i = 0, 1, \ldots, n\) and \(k = 0, 1, \ldots, n-1\).

This allows us to write formula (5.6.63) in the form

(5.6.65)
\[ \begin{aligned} & \varphi_{i,n-1,n-1}(x, y, z) = -\left[ C_{0,n,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{0,n,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(x - x_0)^{n-1}}{(n-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{i,n,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{i,n,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(y - y_n)^{n-1}}{(n-1)!} \frac{(x - x_i)^{n-1}}{(n-1)!}. \end{aligned} \]

Let us write the boundary conditions (5.2.5), (5.2.6), (5.2.7) for the indices \(i\), \(j = n\), \(k = n\). Taking convention (A) into account, these conditions are

(5.6.66)
\[ \begin{aligned} \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,n-1,n-1}]_{x, y_n, z_n} &= 0 \\ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,n-1,n-1} - \varphi_{i-1,n-1,n-1}]_{x_i, y_n, z_n} &= \begin{cases} C_{i,n,n} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0 \end{cases} \end{aligned} \]

for \(r = 0, 1, \ldots, n-1\).

Let us consider conditions (5.6.66) for \(r = 0\). The first condition is satisfied, the function \(\varphi_{i,n-1,n-1}\) being a polynomial of degree \(n-1\) in \(z\). The second condition leads, by equation (5.6.65), to the equation

(5.6.67)
\[ C_{i,n,0} + \ldots + C_{i,n,n-1} + C_{i,n,n} = 0. \]

Let us examine conditions (5.6.66) for \(r = 1, 2, \ldots, n-1\). But first let us consider the boundary conditions (5.2.5), (5.2.6), (5.2.7) for the indices \(i\), \(j = n-1\), \(k = n\), and of these conditions let us take only the conditions

(5.6.68)
\[ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{i,n-1,n-1}]_{x, y, z_n} = 0 \quad\text{for } r = 1, 2, \ldots, n-1. \]

By formula (5.6.65) we have

(5.6.69)
\[ \begin{aligned} & \frac{\partial^{3(n-r)-1} \varphi_{i,n-1,n-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z_n) = -\left[ C_{0,n,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{0,n,n-1} \frac{(z_n - z_{n-1})^r}{r!} \right] \frac{(y - y_n)^{r-1}}{(r-1)!} \frac{(x - x_0)^{r-1}}{(r-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{i,n,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{i,n,n-1} \frac{(z_n - z_{n-1})^r}{r!} \right] \frac{(y - y_n)^{r-1}}{(r-1)!} \frac{(x - x_i)^{r-1}}{(r-1)!}. \end{aligned} \]

But by equations (5.6.60) and (5.6.61) the first two large brackets vanish for \(r = 1, 2, \ldots, n-1\). Then, for \(i = 2\), formula (5.6.69) reduces to

\[ \frac{\partial^{3(n-r)-1} \varphi_{2,n-1,n-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z_n) = -\left[ C_{2,n,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{2,n,n-1} \frac{(z_n - z_{n-1})^r}{r!} \right] \frac{(x - x_2)^{r-1}}{(r-1)!} \frac{(y - y_n)^{r-1}}{(r-1)!} \]

and in order that condition (5.6.68) be satisfied for \(r = 1, 2, \ldots, n-1\), we must take

\[ C_{2,n,0}(z_n - z_0)^r + \ldots + C_{2,n,n-1}(z_n - z_{n-1})^r = 0 \quad\text{for } r = 1, 2, \ldots, n-1. \]

In the same way one proves step by step, for the index \(i\), that we must have

(5.6.70)
\[ C_{i,n,0}(z_n - z_0)^r + \ldots + C_{i,n,n-1}(z_n - z_{n-1})^r = 0 \quad\text{for } r = 1, 2, \ldots, n-1. \]

Equations (5.6.67) and (5.6.70) for \(r = 1, 2, \ldots, n-1\) show that system (5.6.62) is valid for \(i' = i\).

It also follows that system (5.6.62) is valid for \(i = 0, 1, \ldots, n-1\).

The boundary conditions (5.6.66) hold for \(r = 1, 2, \ldots, n-1\). This follows from the following formulas.

By formula (5.6.65) we have

\[ \begin{aligned} & \frac{\partial^{3(n-r)-2}}{\partial x^{n-r} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,n-1,n-1}]_{x, y, z_n} = \\ & = -\left[ C_{0,n,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{0,n,n-1} \frac{(z_n - z_{n-1})^r}{r!} \right] \frac{(y - y_n)^r}{r!} \frac{(x - x_0)^{r-1}}{(r-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{i,n,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{i,n,n-1} \frac{(z_n - z_{n-1})^r}{r!} \right] \frac{(y - y_n)^r}{r!} \frac{(x - x_i)^{r-1}}{(r-1)!} \end{aligned} \]

and

\[ \begin{aligned} & \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{i,n-1,n-1} - \varphi_{i-1,n-1,n-1}]_{x, y, z_n} = \\ & = -\left[ C_{i,n,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{i,n,n-1} \frac{(z_n - z_{n-1})^r}{r!} \right] \frac{(y - y_n)^r}{r!} \frac{(x - x_i)^r}{r!}. \end{aligned} \]

But equations (5.6.70) show that the large brackets on the right-hand sides vanish for \(r = 1, 2, \ldots, n-1\), and consequently conditions (5.6.66) are satisfied for \(r = 1, 2, \ldots, n-1\).

It remains to show that system (5.6.62) is also valid for \(i = n\).

5.6.9. Let us write formula (5.6.65) for \(i = n-1\) in the form

(5.6.71)
\[ \begin{aligned} & \varphi_{n-1,n-1,n-1}(x, y, z) = -\left[ C_{0,n,0} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,n,0} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(z - z_0)^{n-1}}{(n-1)!} \frac{(y - y_n)^{n-1}}{(n-1)!} - \\ & - \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots - \\ & - \left[ C_{0,n,n-1} \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + C_{n-1,n,n-1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right] \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \frac{(y - y_n)^{n-1}}{(n-1)!}. \end{aligned} \]

But we have proved that the system

(5.6.72)
\[ \begin{aligned} C_{0,j,k} + \ldots + C_{n,j,k} &= 0 \\ C_{0,j,k} x_0 + \ldots + C_{n,j,k} x_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,j,k} x_0^{n-1} + \ldots + C_{n,j,k} x_n^{n-1} &= 0 \end{aligned} \]

is valid for \(j = 0, 1, \ldots, n\) and \(k = 0, 1, \ldots, n-1\). It then follows that for \(j = n\) we have

(5.6.73)
\[ C_{0,n,k}(x - x_0)^{n-1} + \ldots + C_{n-1,n,k}(x - x_{n-1})^{n-1} = -C_{n,n,k}(x - x_n)^{n-1} \]

and consequently formula (5.6.71) becomes

(5.6.74)
\[ \varphi_{n-1,n-1,n-1}(x, y, z) = +\left[ C_{n,n,0} \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + C_{n,n,n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right] \frac{(x - x_n)^{n-1}}{(n-1)!} \frac{(y - y_n)^{n-1}}{(n-1)!}. \]

This being so, let us write conditions (5.2.5), (5.2.6), (5.2.7) for \(i = n\), \(j = n\), \(k = n\) and take convention (A) into account. These conditions reduce to

(5.6.75)
\[ \frac{\partial^{3(n-r-1)}}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}} [\varphi_{n-1,n-1,n-1}]_{x_n, y_n, z_n} = \begin{cases} C_{n,n,n} & \text{if } r = 0 \\ 0 & \text{if } r \neq 0. \end{cases} \]

For \(r = 0\) condition (5.6.75) leads to the equation

(5.6.76)
\[ C_{n,n,0} + \ldots + C_{n,n,n} = 0. \]

Let us further write the boundary conditions (5.2.5), (5.2.6), (5.2.7) for \(i = n-1\), \(j = n-1\), \(k = n\), and of these conditions let us take only

(5.6.77)
\[ \frac{\partial^{3(n-r)-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}} [\varphi_{n-1,n-1,n-1}]_{x, y, z_n} = 0 \quad\text{for } r = 1, 2, \ldots, n-1. \]

By formula (5.6.74) we have

\[ \frac{\partial^{3(n-r)-1} \varphi_{n-1,n-1,n-1}}{\partial x^{n-r} \partial y^{n-r} \partial z^{n-r-1}}(x, y, z_n) = \left[ C_{n,n,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{n,n,n-1} \frac{(z_n - z_{n-1})^r}{r!} \right] \frac{(x - x_n)^{r-1}}{(r-1)!} \frac{(y - y_n)^{r-1}}{(r-1)!} \]

and in order that condition (5.6.77) be satisfied for \(r = 1, 2, \ldots, n-1\), we must take

(5.6.78)
\[ C_{n,n,0}(z_n - z_0)^r + \ldots + C_{n,n,n-1}(z_n - z_{n-1})^r = 0 \]

for \(r = 1, 2, \ldots, n-1\).

Equations (5.6.76) and (5.6.78) for \(r = 1, 2, \ldots, n-1\) show that we have

(5.6.79)
\[ \begin{aligned} C_{n,n,0} + \ldots + C_{n,n,n} &= 0 \\ C_{n,n,0} z_0 + \ldots + C_{n,n,n} z_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{n,n,0} z_0^{n-1} + \ldots + C_{n,n,n} z_n^{n-1} &= 0 \end{aligned} \]

which means that system (5.6.62) is valid for \(i = n\).

It remains to show that conditions (5.6.75) hold for \(r = 1, 2, \ldots, n-1\).

By formula (5.6.74) we have

\[ \frac{\partial^{3(n-r-1)} \varphi}{\partial x^{n-r-1} \partial y^{n-r-1} \partial z^{n-r-1}}(x, y, z_n) = \left[ C_{n,n,0} \frac{(z_n - z_0)^r}{r!} + \ldots + C_{n,n,n-1} \frac{(z_n - z_{n-1})^r}{r!} \right] \frac{(x - x_n)^r}{r!} \frac{(y - y_n)^r}{r!} \]

and equations (5.6.78) show that, for \(r = 1, 2, \ldots, n-1\), the right-hand side of this formula vanishes, which means that conditions (5.6.75) are satisfied for \(r = 1, 2, \ldots, n - 1\).

5.6.10. In summary, we have proved in this section that the system of equations

(5.6.80)
\[ \begin{aligned} C_{i,j,0} + \ldots + C_{i,j,n} &= 0 \\ C_{i,j,0} z_0 + \ldots + C_{i,j,n} z_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i,j,0} z_0^{n-1} + \ldots + C_{i,j,n} z_n^{n-1} &= 0 \end{aligned} \]

is valid for \(i, j = 0, 1, \ldots, n\).

§ 5.7. Conclusions

5.7.1. We have proved in the preceding sections that the constants \(C_{i,j,k}\), where \(i, j, k = 0, 1, \ldots, n\), satisfy the systems of equations

(5.7.1)
\[ \begin{aligned} C_{0,j,k} + \ldots + C_{n,j,k} &= 0 \\ C_{0,j,k} x_0 + \ldots + C_{n,j,k} x_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{0,j,k} x_0^{n-1} + \ldots + C_{n,j,k} x_n^{n-1} &= 0 \end{aligned} \]

and

(5.7.2)
\[ \begin{aligned} C_{i,0,k} + \ldots + C_{i,n,k} &= 0 \\ C_{i,0,k} y_0 + \ldots + C_{i,n,k} y_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i,0,k} y_0^{n-1} + \ldots + C_{i,n,k} y_n^{n-1} &= 0 \end{aligned} \]

and also

(5.7.3)
\[ \begin{aligned} C_{i,j,0} + \ldots + C_{i,j,n} &= 0 \\ C_{i,j,0} z_0 + \ldots + C_{i,j,n} z_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ C_{i,j,0} z_0^{n-1} + \ldots + C_{i,j,n} z_n^{n-1} &= 0. \end{aligned} \]

It follows from system (5.7.1) that

\[ \frac{C_{0,j,k}}{V(x_1, x_2, \ldots, x_n)} = \frac{C_{1,j,k}}{-V(x_0, x_2, \ldots, x_n)} = \ldots = \frac{C_{i,j,k}}{(-1)^i V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)} = \ldots = D_{j,k} \]

where \(D_{j,k}\) are constants. For \(i, j, k = 0, 1, \ldots, n\) we shall have

(5.7.4)
\[ C_{i,j,k} = (-1)^i V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n) D_{j,k}. \]

Substituting the constants \(C_{i,j,k}\) given by formulas (5.7.4) into system (5.7.2), we shall have the system

(5.7.5)
\[ \begin{aligned} D_{0,k} + \ldots + D_{n,k} &= 0 \\ D_{0,k} y_0 + \ldots + D_{n,k} y_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ D_{0,k} y_0^{n-1} + \ldots + D_{n,k} y_n^{n-1} &= 0 \end{aligned} \]

whence it follows that

\[ \frac{D_{0,k}}{V(y_1, y_2, \ldots, y_n)} = \frac{D_{1,k}}{-V(y_0, y_2, \ldots, y_n)} = \ldots = \frac{D_{j,k}}{(-1)^j V(y_0, \ldots, y_{j-1}, y_{j+1}, \ldots, y_n)} = \ldots = E_k, \]

where \(E_k\) are constants. For \(j, k = 0, 1, \ldots, n\) we shall have

(5.7.6)
\[ D_{j,k} = (-1)^j V(y_0, \ldots, y_{j-1}, y_{j+1}, \ldots, y_n) E_k \]

and consequently

(5.7.7)
\[ C_{i,j,k} = (-1)^{i+j} V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n) V(y_0, \ldots, y_{j-1}, y_{j+1}, \ldots, y_n) E_k. \]

Substituting the constants \(C_{i,j,k}\) given by formulas (5.7.7) into systems (5.7.3), we shall have the system

(5.7.8)
\[ \begin{aligned} E_0 + \ldots + E_n &= 0 \\ E_0 z_0 + \ldots + E_n z_n &= 0 \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots & \\ E_0 z_0^{n-1} + \ldots + E_n z_n^{n-1} &= 0 \end{aligned} \]

whence it follows that

\[ \frac{E_0}{V(z_1, z_2, \ldots, z_n)} = \frac{E_1}{-V(z_0, z_2, \ldots, z_n)} = \ldots = \frac{E_k}{(-1)^k V(z_0, \ldots, z_{k-1}, z_{k+1}, \ldots, z_n)} = \ldots = H, \]

where \(H\) is a new constant. For \(k = 0, 1, \ldots, n\) we shall have

(5.7.9)
\[ E_k = (-1)^k H V(z_0, \ldots, z_{k-1}, z_{k+1}, \ldots, z_n) \]

and formula (5.7.7) finally gives

(5.7.10)
\[ C_{i,j,k} = (-1)^{i+j+k} H V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n) \cdot V(y_0, \ldots, y_{j-1}, y_{j+1}, \ldots, y_n) V(z_0, \ldots, z_{k-1}, z_{k+1}, \ldots, z_n) \]

It remains to determine the constant \(H\).

5.7.2. If in formula (5.1.41) we replace the functions \(\varphi_{i,j,k}\) by the solution of the boundary value problem, we shall have

(5.7.11)
\[ \mathscr{P}[f] = (-1)^n \sum_{i,j,k=0}^{n} C_{i,j,k} f(x_i, y_j, z_k) \]

and, replacing the constants \(C_{i,j,k}\) by formulas (5.7.10), we deduce that

(5.7.12)
\[ \begin{aligned} & \mathscr{P}[f] = (-1)^n H \sum_{i,j,k=0}^{n} (-1)^{i+j+k} V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n) \cdot \\ & \qquad \cdot V(y_0, \ldots, y_{j-1}, y_{j+1}, \ldots, y_n) \cdot V(z_0, \ldots, z_{k-1}, z_{k+1}, \ldots, z_n) f(x_i, y_j, z_k) \end{aligned} \]

But by the last boundary condition (5.2.8) we must have

(5.7.13)
\[ \mathscr{P}[x^n y^n z^n] = 1 \]

that is

(5.7.14)
\[ \begin{aligned} & H \sum_{i,j,k=0}^{n} (-1)^{n+i} V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n) x_i^n \cdot \\ & \cdot (-1)^{n+j} V(y_0, \ldots, y_{j-1}, y_{j+1}, \ldots, y_n) y_j^n \cdot (-1)^{n+k} V(z_0, \ldots, z_{k-1}, z_{k+1}, \ldots, z_n) z_k^n = 1. \end{aligned} \]

But

\[ \begin{aligned} & \sum_{i=0}^{n} (-1)^{n+i} V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n) x_i^n = V(x_0, x_1, \ldots, x_n) \\ & \sum_{j=0}^{n} (-1)^{n+j} V(y_0, \ldots, y_{j-1}, y_{j+1}, \ldots, y_n) y_j^n = V(y_0, y_1, \ldots, y_n) \\ & \sum_{k=0}^{n} (-1)^{n+k} V(z_0, \ldots, z_{k-1}, z_{k+1}, \ldots, z_n) z_k^n = V(z_0, z_1, \ldots, z_n) \end{aligned} \]

and equation (5.7.14) then shows that we must have

(5.7.15)
\[ H = \frac{1}{V(x_0, x_1, \ldots, x_n) V(y_0, y_1, \ldots, y_n) V(z_0, z_1, \ldots, z_n)}. \]

The expression (5.7.12) of \(\mathscr{P}[f]\) becomes

(5.7.16)
\[ \begin{aligned} \mathscr{P}[f] = \sum_{i,j,k=0}^{n} & (-1)^{n+i} \frac{V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)}{V(x_0, x_1, \ldots, x_n)} \cdot \\ & \cdot (-1)^{n+j} \frac{V(y_0, \ldots, y_{j-1}, y_{j+1}, \ldots, y_n)}{V(y_0, y_1, \ldots, y_n)} \cdot \\ & \cdot (-1)^{n+k} \frac{V(z_0, \ldots, z_{k-1}, z_{k+1}, \ldots, z_n)}{V(z_0, z_1, \ldots, z_n)} f(x_i, y_j, z_k) \end{aligned} \]

Setting

(5.7.17)
\[ \begin{aligned} \lambda_i &= (-1)^{n+i} \frac{V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)}{V(x_0, x_1, \ldots, x_n)} \\ \mu_j &= (-1)^{n+j} \frac{V(y_0, \ldots, y_{j-1}, y_{j+1}, \ldots, y_n)}{V(y_0, y_1, \ldots, y_n)} \\ \nu_k &= (-1)^{n+k} \frac{V(z_0, \ldots, z_{k-1}, z_{k+1}, \ldots, z_n)}{V(z_0, z_1, \ldots, z_n)} \end{aligned} \]

we shall have

(5.7.18)
\[ C_{i,j,k} = (-1)^n \lambda_i \mu_j \nu_k \]

for \(i, j, k = 0, 1, \ldots, n\), and formula (5.7.16) becomes

(5.7.19)
\[ \mathscr{P}[f] = \sum_{i,j,k=0}^{n} C_{ijk} f(x_i, y_j, z_k). \]

The constants \(C_{i,j,k}\) being determined, the boundary value problem is completely solved.

§ 5.8. The divided difference of order \(n\) of the function \(f\) on the grid of nodes \(M_{i,j,k}(i, j, k = 0, 1, \ldots, n)\) and its integral representation

5.8.1. We have seen in § 5.7 that if in formula (5.1.41) the functions \(\varphi_{i,j,k}\) are replaced by the solution of the boundary value problem, \(\mathscr{P}[f]\) becomes

(5.8.1)
\[ \mathscr{P}[f] = (-1)^n \sum_{i,j,k=0}^{n} C_{i,j,k} f(x_i, y_j, z_k) \]

or

(5.8.2)
\[ \mathscr{P}[f] = \sum_{i,j,k=0}^{n} \lambda_i \mu_j \nu_k f(x_i, y_j, z_k) \]

with

(5.8.3)
\[ \begin{aligned} \lambda_i &= (-1)^{n+i} \frac{V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)}{V(x_0, x_1, \ldots, x_n)} \\ \mu_j &= (-1)^{n+j} \frac{V(y_0, \ldots, y_{j-1}, y_{j+1}, \ldots, y_n)}{V(y_0, y_1, \ldots, y_n)} \\ \nu_k &= (-1)^{n+k} \frac{V(z_0, z_1, \ldots, z_{k-1}, z_{k+1}, \ldots, z_n)}{V(z_0, z_1, \ldots, z_n)} \end{aligned} \]

for \(i, j, k = 0, 1, \ldots, n\).

Definition 5.8.1. The expression \(\mathscr{P}[f]\), given by formula (5.8.2), is called the divided difference of order \(n\) of the function \(f\) on the grid of nodes \(M_{i,j,k}\), \((i, j, k = 0, 1, \ldots, n)\), and is denoted by:

(5.8.4)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f\right]. \]

Theorem 5.8.1. The divided difference of order \(n\) of the function \(f\) on the grid of nodes \(M_{i,j,k}\) \((i, j, k = 0, 1, \ldots, n)\) is given by the formula

(5.8.5)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f\right] = \sum_{i,j,k=0}^{n} \lambda_i \mu_j \nu_k f(x_i, y_j, z_k). \]

Formula (5.8.5) is identical with formula (5.8.1).

Theorem 5.8.2. If the function \(f\) is continuous on the parallelepiped \(D\) defined by

\[ D: \quad x_0 \leq x \leq x_n, \quad y_0 \leq y \leq y_n, \quad z_0 \leq z \leq z_n \]

together with its partial derivatives

\[ \begin{gathered} \frac{\partial^{3p-2} f}{\partial x^p \partial y^{p-1} \partial z^{p-1}}, \quad \frac{\partial^{3p-2} f}{\partial x^{p-1} \partial y^p \partial z^{p-1}}, \quad \frac{\partial^{3p-2} f}{\partial x^{p-1} \partial y^{p-1} \partial z^p}, \quad \frac{\partial^{3p-1} f}{\partial x^{p-1} \partial y^p \partial z^p}, \\ \frac{\partial^{3p-1} f}{\partial x^p \partial y^{p-1} \partial z^p}, \quad \frac{\partial^{3p-1} f}{\partial x^p \partial y^p \partial z^{p-1}}, \quad \frac{\partial^{3p} f}{\partial x^p \partial y^p \partial z^p} \end{gathered} \]

for \(p = 1, 2, \ldots, n\), and if the nodes \(M_{i,j,k}(x_i, y_j, z_k)\), \((i, j, k = 0, 1, \ldots, n)\) are such that

\[ x_0 \lt x_1 \lt \ldots \lt x_n, \quad y_0 \lt y_1 \lt \ldots \lt y_n, \quad z_0 \lt z_1 \lt \ldots \lt z_n, \]

then the divided difference of order \(n\) of the function \(f\) on the grid \(M_{i,j,k}\), \((i, j, k = 0, 1, \ldots, n)\) has an integral representation given by the formula

(5.8.6)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f\right] = \iiint_D \varphi \frac{\partial^{3n} f}{\partial x^n \partial y^n \partial z^n}\, dx\, dy\, dz, \]

where the function \(\varphi\) is the solution of the boundary value problem treated in § 5.2 — § 5.7.

The proof of this theorem is very simple. It suffices to replace in formula (5.1.41) the functions \(\varphi_{i,j,k}\) by the solution of the boundary value problem.

5.8.2. The function \(\varphi_{i,j,k}\). Replacing the constants \(C_{i,j,k}\) by formulas (5.7.18) in formula (5.5.10), we obtain:

Theorem 5.8.3. The function \(\varphi_{i,j,k}\) is the product of three functions, the first of \(x\), the second of \(y\) and the third of \(z\):

(5.8.7)
\[ \begin{aligned} \varphi_{i,j,k}(x, y, z) = {} & (-1)^n \left[ \lambda_0 \frac{(x - x_0)^{n-1}}{(n-1)!} + \ldots + \lambda_i \frac{(x - x_i)^{n-1}}{(n-1)!} \right] \cdot \\ & \cdot \left[ \mu_0 \frac{(y - y_0)^{n-1}}{(n-1)!} + \ldots + \mu_j \frac{(y - y_j)^{n-1}}{(n-1)!} \right] \left[ \nu_0 \frac{(z - z_0)^{n-1}}{(n-1)!} + \ldots + \nu_k \frac{(z - z_k)^{n-1}}{(n-1)!} \right]. \end{aligned} \]

We shall give a beautiful interpretation of formula (5.8.7).

Let us consider the integral representation of the divided difference of order \(n\) of the function \(u\) on the nodes \(x_0, x_1, \ldots, x_n\), where \(x_0 \lt x_1 \lt \ldots \lt x_n\) and \(u \in C^n[x_0, x_n]\), which is given by the formula

(5.8.8)
\[ [x_0, x_1, \ldots, x_n; u] = \int_{x_0}^{x_n} \psi(x) u^{(n)}(x)\, dx, \]

where the coefficients \(\lambda_0, \lambda_1, \ldots, \lambda_n\) of the left-hand side are given by the formula

(5.7.17)
\[ \lambda_i = (-1)^{n+i} \frac{V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)}{V(x_0, x_1, \ldots, x_n)} \]

and \(\psi\) is the spline function defined by the formula

(5.8.9)
\[ \psi(x) = (-1)^n \left[ \lambda_0 \frac{(x - x_0)_+^{n-1}}{(n-1)!} + \lambda_1 \frac{(x - x_1)_+^{n-1}}{(n-1)!} + \ldots + \lambda_n \frac{(x - x_n)_+^{n-1}}{(n-1)!} \right]. \]

On the intervals \([x_0, x_1]\), \([x_1, x_2]\), \(\ldots\), \([x_{n-1}, x_n]\) it coincides with the polynomials

(5.8.10)
\[ \begin{aligned} \psi_0(x) &= (-1)^n \lambda_0 \frac{(x - x_0)^{n-1}}{(n-1)!} \\ \psi_1(x) &= (-1)^n \left[ \lambda_0 \frac{(x - x_0)^{n-1}}{(n-1)!} + \lambda_1 \frac{(x - x_1)^{n-1}}{(n-1)!} \right] \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ \psi_{n-1}(x) &= (-1)^n \left[ \lambda_0 \frac{(x - x_0)^{n-1}}{(n-1)!} + \lambda_1 \frac{(x - x_1)^{n-1}}{(n-1)!} + \ldots + \lambda_{n-1} \frac{(x - x_{n-1})^{n-1}}{(n-1)!} \right]. \end{aligned} \]

Likewise, let us consider the integral representation of the divided difference of order \(n\) of the function \(v\) of the variable \(y\) on the nodes \(y_0, y_1, \ldots, y_n\), where \(y_0 \lt y_1 \lt \ldots \lt y_n\) and \(v \in C^n[y_0, y_n]\), given by the formula

(5.8.11)
\[ [y_0, y_1, \ldots, y_n; v] = \int_{y_0}^{y_n} \theta(y) v^{(n)}(y)\, dy, \]

where the coefficients of the left-hand side are given by the formulas

(5.7.17)
\[ \mu_j = (-1)^{n+j} \frac{V(y_0, \ldots, y_{j-1}, y_{j+1}, \ldots, y_n)}{V(y_0, y_1, \ldots, y_n)} \]

and \(\theta\) is the spline function defined by the formula

(5.8.12)
\[ \theta(y) = (-1)^n \left[ \mu_0 \frac{(y - y_0)_+^{n-1}}{(n-1)!} + \mu_1 \frac{(y - y_1)_+^{n-1}}{(n-1)!} + \ldots + \mu_n \frac{(y - y_n)_+^{n-1}}{(n-1)!} \right]. \]

On the intervals \([y_0, y_1]\), \([y_1, y_2]\), \(\ldots\), \([y_{n-1}, y_n]\) it coincides with the polynomials

(5.8.13)
\[ \begin{aligned} \theta_0(y) &= (-1)^n \mu_0 \frac{(y - y_0)^{n-1}}{(n-1)!} \\ \theta_1(y) &= (-1)^n \left[ \mu_0 \frac{(y - y_0)^{n-1}}{(n-1)!} + \mu_1 \frac{(y - y_1)^{n-1}}{(n-1)!} \right] \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ \theta_{n-1}(y) &= (-1)^n \left[ \mu_0 \frac{(y - y_0)^{n-1}}{(n-1)!} + \mu_1 \frac{(y - y_1)^{n-1}}{(n-1)!} + \ldots + \mu_{n-1} \frac{(y - y_{n-1})^{n-1}}{(n-1)!} \right]. \end{aligned} \]

Finally, let us consider the integral representation of the divided difference of order \(n\) of the function \(w\) of the variable \(z\) on the nodes \(z_0, z_1, \ldots, z_n\), where \(z_0 \lt z_1 \lt \ldots \lt z_n\) and \(w \in C^n[z_0, z_n]\), given by the formula

(5.8.14)
\[ [z_0, z_1, \ldots, z_n; w] = \int_{z_0}^{z_n} \chi(z) w^{(n)}(z)\, dz, \]

where the coefficients of the left-hand side are given by the formulas

(5.7.17)
\[ \nu_k = (-1)^{n+k} \frac{V(z_0, \ldots, z_{k-1}, z_{k+1}, \ldots, z_n)}{V(z_0, z_1, \ldots, z_n)} \]

and \(\chi\) is the spline function defined by the formula

(5.8.15)
\[ \chi(z) = (-1)^n \left[ \nu_0 \frac{(z - z_0)_+^{n-1}}{(n-1)!} + \nu_1 \frac{(z - z_1)_+^{n-1}}{(n-1)!} + \ldots + \nu_n \frac{(z - z_n)_+^{n-1}}{(n-1)!} \right]. \]

On the intervals \([z_0, z_1]\), \([z_1, z_2]\), \(\ldots\), \([z_{n-1}, z_n]\) it coincides with the polynomials

(5.8.16)
\[ \begin{aligned} \chi_0(z) &= (-1)^n \nu_0 \frac{(z - z_0)^{n-1}}{(n-1)!} \\ \chi_1(z) &= (-1)^n \left[ \nu_0 \frac{(z - z_0)^{n-1}}{(n-1)!} + \nu_1 \frac{(z - z_1)^{n-1}}{(n-1)!} \right] \\ & \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ \chi_{n-1}(z) &= (-1)^n \left[ \nu_0 \frac{(z - z_0)^{n-1}}{(n-1)!} + \nu_1 \frac{(z - z_1)^{n-1}}{(n-1)!} + \ldots + \nu_{n-1} \frac{(z - z_{n-1})^{n-1}}{(n-1)!} \right]. \end{aligned} \]

We have proved that the spline functions \(\psi, \theta, \chi\) are positive on the intervals \((x_0, x_n)\), \((y_0, y_n)\), \((z_0, z_n)\).

Taking into account formulas (5.8.1), (5.8.16), formula (5.8.7) shows that

(5.8.17)
\[ \varphi_{i,j,k}(x, y, z) = \psi_i(x) \theta_j(y) \chi_k(z) \quad \text{for } i, j, k = 0, 1, \ldots, n-1 \]

and consequently we have the following theorem:

Theorem 5.8.4. The function \(\varphi\) in the integral representation (5.8.6) is the product of the spline functions \(\psi\), \(\theta\) and \(\chi\) of the integral representations (5.8.8), (5.8.11) and (5.8.14), that is

(5.8.18)
\[ \varphi(x, y, z) = \psi(x) \theta(y) \chi(z). \]

To prove this it suffices to observe that formula (5.8.18) coincides with formula (5.8.17) on each parallelepiped \(D_{i,j,k}\).

5.8.3. Theorem 5.8.5. The function \(\varphi\) in the integral representation (5.8.6) of the divided difference of order \(n\) of the function \(f\) of three variables is positive on the open parallelepiped \(D\) and vanishes on the boundary of this parallelepiped.

Indeed, it has been proved that the spline functions \(\psi\), \(\theta\) and \(\chi\) are positive on the respective intervals \((x_0, x_n)\), \((y_0, y_n)\), \((z_0, z_n)\). It then follows from formula (5.8.18) that the function \(\varphi\) is positive on the parallelepiped \(D\) and vanishes on the boundary of this parallelepiped.

The function \(\varphi\) is an example of a spline function of three variables.

5.8.4. By formula (5.6.2) we have

\[ \begin{aligned} \frac{\partial^{3(n-1)} \varphi_{i,j,k}}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}} = {} & C_{0,0,0} + \ldots + C_{0,0,k} + \ldots + C_{i,0,0} + \ldots + C_{i,0,k} + \\ & + \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots + \\ & + C_{0,j,0} + \ldots + C_{0,j,k} + \ldots + C_{i,j,0} + \ldots + C_{i,j,k}. \end{aligned} \]

Replacing the constants \(C_{i,j,k}\) by formula (5.7.18), we shall have

(5.8.19)
\[ \frac{\partial^{3(n-1)} \varphi_{i,j,k}}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}} = (-1)^n (\lambda_0 + \lambda_1 + \ldots + \lambda_i)(\mu_0 + \mu_1 + \ldots + \mu_j)(\nu_0 + \nu_1 + \ldots + \nu_k). \]

But we have proved (see Theorem 1.1.2) that

(5.8.20)
\[ \begin{aligned} & (-1)^i (\lambda_0 + \lambda_1 + \ldots + \lambda_i) \gt 0, \\ & (-1)^j (\mu_0 + \mu_1 + \ldots + \mu_j) \gt 0, \\ & (-1)^k (\nu_0 + \nu_1 + \ldots + \nu_k) \gt 0, \end{aligned} \]

and consequently we have the following theorem:

Theorem 5.8.6. On each parallelepiped \(D_{i,j,k}\) the partial derivative

(5.8.21)
\[ \frac{\partial^{3(n-1)} \varphi_{i,j,k}}{\partial x^{n-1} \partial y^{n-1} \partial z^{n-1}} \]

has the sign of \((-1)^{n+i+j+k}\).

This follows from formulas (5.7.19), (5.8.20).

5.8.5. We have proved that the integral representation (5.8.6) of the divided difference of order \(n\) of a function of three variables is analogous to the integral representation for a function of one variable or of two variables, and that it can be obtained by means of a boundary value problem. Theorem 5.8.4 on the positivity of the function \(\varphi\) on the open parallelepiped \(D\) was obtained thanks to a theorem which we studied in depth, for functions of one variable, in the first chapter of this work.

One could go further and obtain the definition of the divided difference of order \(n\) and its integral representation for a function of several variables, but the work would become more and more cumbersome, so we stop here.

↑ Contents

Română

Chapter VI

The divided difference of order \(n\) of a function \(f\) of \(p\) variables and its representation by a multiple integral

D. V. Ionescu, Diferențe divizate [Divided Differences], Editura Academiei Republicii Socialiste România, Bucharest, 1978, pp. 293–298

In this chapter we give the definition of the divided difference of order \(n\) of a function \(f\) of \(p\) variables by means of a recurrence formula (§ 6.1), and then its integral representation by a multiple integral (§ 6.2), making, however, hypotheses on the function \(f\) which are different from those made in the cases \(p = 2\) and \(p = 3\), cases that were treated in Chapters IV and V.

§ 6.1. Definition of the divided difference of order \(n\) of a function of \(p\) variables by a recurrence formula

6.1.1. The divided difference of order \(n\) of the function \(f\) on the nodes \(x_0, x_1, \ldots, x_n\) is

(6.1.1)
\[ [x_0, x_1, \ldots, x_n ; f] = \sum_{i=0}^{n} \lambda_i f(x_i), \]

where

(6.1.2)
\[ \lambda_i = (-1)^{n+i} \frac{V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)}{V(x_0, x_1, \ldots, x_n)} . \]

In § 4.3 we were led, by the boundary value problem treated in § 4.1 and § 4.2, to define the divided difference of order \(n\) of the function \(f\) of two variables on the grid of nodes \(M_{i,k}\), \((i, k = 0, 1, \ldots, n)\), by the formula

(6.1.3)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right] = \sum_{i,k=0}^{n} \lambda_i \mu_k f(x_i, y_k), \]

where

(6.1.4)
\[ \begin{aligned} \lambda_i &= (-1)^{n+i} \frac{V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)}{V(x_0, x_1, \ldots, x_n)} \\ \mu_k &= (-1)^{n+k} \frac{V(y_0, \ldots, y_{k-1}, y_{k+1}, \ldots, y_n)}{V(y_0, y_1, \ldots, y_n)} \end{aligned} \]

for \(i, k = 0, 1, \ldots, n\), and we were led to the recurrence formula for the divided difference of the function \(f\) on the grid \(M_{ik}(x_i, y_k)\)

(6.1.5)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right] = [x_0, x_1, \ldots, x_n ; [y_0, y_1, \ldots, y_n ; f(x, y)]]. \]

Formula (6.1.5) was given by T. Popoviciu [31] a priori as the definition of the divided difference of order \(n\) of a function of two variables on the grid \(M_{ik}(x_i, y_k)\), \((i, k = 0, 1, \ldots, n)\) (see subsection 4.3.3).

6.1.2. We were likewise led, by a boundary value problem treated in § 5.1 — § 5.7, to define the divided difference of order \(n\) of the function \(f\) of three variables on the grid of nodes \(M_{i,j,k}(x_i, y_j, z_k)\), \((i, j, k = 0, 1, \ldots, n)\), by the formula

(6.1.6)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f\right] = \sum_{i,j,k=0}^{n} \lambda_i \mu_j \nu_k f(x_i, y_j, z_k), \]

where

(6.1.7)
\[ \begin{aligned} \lambda_i &= (-1)^{n+i} \frac{V(x_0, \ldots, x_{i-1}, x_{i+1}, \ldots, x_n)}{V(x_0, x_1, \ldots, x_n)} \\ \mu_j &= (-1)^{n+j} \frac{V(y_0, \ldots, y_{j-1}, y_{j+1}, \ldots, y_n)}{V(y_0, y_1, \ldots, y_n)} . \\ \nu_k &= (-1)^{n+k} \frac{V(z_0, \ldots, z_{k-1}, z_{k+1}, \ldots, z_n)}{V(z_0, z_1, \ldots, z_n)} \end{aligned} \]

Theorem 6.1.1. The divided difference of order \(n\) of the function \(f\) of three variables on the grid of nodes \(M_{i,j,k}\) satisfies the recurrence formula:

(6.1.8)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f\right] = \left[ x_0, x_1, \ldots, x_n ; \left[\begin{array}{l} y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f(x, y, z)\right]\right]. \]

Indeed, formula (6.1.6) can be written in the form

(6.1.9)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f\right] = \sum_{i=0}^{n} \lambda_i \sum_{j,k=0}^{n} \mu_j \nu_k f(x_i, y_j, z_k) \]

which, by formulas (6.1.1) and (6.1.3), coincides with formula (6.1.8).

6.1.3. Formula (6.1.8) is important; it gives us an idea of how one could define the divided difference of a function \(f\) of \(p\) variables on a grid of nodes \(M_{i_1, i_2, \ldots, i_p}\) and how one could obtain its integral representation by making suitable hypotheses on the function \(f\), hypotheses other than those made in order to arrive, through the boundary value problems treated in this work, at formulas of the form (6.1.3) and (6.1.6).

Let us consider a function \(f\) of the variables \(x_1, x_2, \ldots, x_p\) and let us take on the axis \(Ox_h\), corresponding to the variable \(x_h\), the nodes \(x_h^{(0)}, x_h^{(1)}, \ldots, x_h^{(n)}\) such that

(6.1.10)
\[ x_h^{(0)} \lt x_h^{(1)} \lt \ldots \lt x_h^{(n)}. \]

Giving \(h\) the values \(1, 2, \ldots, p\), we obtain a grid of nodes \(M_{i_1, i_2, \ldots, i_p}\) with coordinates \((x_1^{(i_1)}, x_2^{(i_2)}, \ldots, x_p^{(i_p)})\), \(i_1, i_2, \ldots, i_p\) taking values in the set of numbers \(0, 1, 2, \ldots, n\).

We have the following definition:

Definition 6.1.1. The divided difference of order \(n\) of the function \(f\) of the variables \(x_1, x_2, \ldots, x_p\) on the grid of nodes \(M_{i_1, i_2, \ldots, i_p}\), which we denote by

(6.1.11)
\[ \left[\begin{array}{l} x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} \\ x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] \]

is defined by the formula

(6.1.12)
\[ \left[\begin{array}{l} x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} \\ x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] = \sum_{i_1, \ldots, i_p = 0}^{n} \lambda_1^{(i_1)} \lambda_2^{(i_2)} \ldots \lambda_p^{(i_p)} f(x_1^{(i_1)}, x_2^{(i_2)}, \ldots, x_p^{(i_p)}), \]

where

(6.1.13)
\[ \lambda_h^{(i)} = (-1)^{n+i} \frac{V(x_h^{(0)}, \ldots, x_h^{(i-1)}, x_h^{(i+1)}, \ldots, x_h^{(n)})}{V(x_h^{(0)}, x_h^{(1)}, \ldots, x_h^{(n)})} \]

for \(h = 1, 2, \ldots, p\) and \(i = 0, 1, \ldots, n\).

Theorem 6.1.2. The divided difference of order \(n\) of the function \(f\) of \(p\) variables on the grid of nodes \(M_{i_1, i_2, \ldots, i_p}\) satisfies the recurrence formula

(6.1.14)
\[ \left[\begin{array}{l} x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} \\ x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] = \left[ x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} ; \left[\begin{array}{l} x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ x_3^{(0)}, x_3^{(1)}, \ldots, x_3^{(n)} \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right]\right] \]

Indeed, we can write formula (6.1.12) in the form

(6.1.15)
\[ \left[\begin{array}{l} x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} \\ x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] = \sum_{i_1=0}^{n} \lambda_1^{(i_1)} \sum_{i_2, \ldots, i_p = 0}^{n} \lambda_2^{(i_2)} \ldots \lambda_p^{(i_p)} f(x_1^{(i_1)}, x_2^{(i_2)}, \ldots, x_p^{(i_p)}). \]

Let us prove formula (6.1.14) by the method of complete induction.

For \(p = 3\) it is true, since in this case it coincides with formula (6.1.8). Let us assume that formula (6.1.14) is true for the index \(p - 1\). Then formula (6.1.15) shows that it is also true for the index \(p\).

§ 6.2. The integral representation of the divided difference of order \(n\) of the function \(f\) on the grid of nodes \(M_{i_1, i_2, \ldots, i_p}\)

6.2.1. One can give the integral representation of the divided difference of order \(n\) of a function \(f\) on the grid of nodes \(M_{i_1, i_2, \ldots, i_p}\) by taking into account the integral representation of the divided difference of a function \(g\) of a single variable on the nodes \(x_0, x_1, \ldots, x_n\), where \(x_0 \lt x_1 \lt \ldots \lt x_n\) and when \(g \in C^n[x_0, x_n]\) (see § 1.1). This representation is

(6.2.1)
\[ [x_0, x_1, \ldots, x_n ; g] = \int_{x_0}^{x_n} \varphi(s) g^{(n)}(s)\, ds, \]

where \(\varphi\) is the spline function

(6.2.2)
\[ \varphi(s) = (-1)^n \left[ \lambda_0 \frac{(s - x_0)_+^{n-1}}{(n-1)!} + \lambda_1 \frac{(s - x_1)_+^{n-1}}{(n-1)!} + \ldots + \lambda_n \frac{(s - x_n)_+^{n-1}}{(n-1)!} \right]. \]

The function \(\varphi\) is positive on the interval \((x_0, x_n)\) and we have

(6.2.3)
\[ \int_{x_0}^{x_n} \varphi(s)\, ds = \frac{1}{n!}. \]

6.2.2. This being recalled, we can obtain the integral representation of the divided difference of order \(n\) (6.1.6) of the function \(f\) on the grid of nodes \(M_{i_1, i_2, \ldots, i_p}\) with the help of some hypotheses on the function \(f\), which we denote by \((H_p)\), \((H_{p-1})\), \(\ldots\), \((H_1)\).

Considering the domain \(D\) defined by the inequalities

\[ D: x_1^{(0)} \leq x_1 \leq x_1^{(n)}, \quad x_2^{(0)} \leq x_2 \leq x_2^{(n)}, \quad \ldots, \quad x_p^{(0)} \leq x_p \leq x_p^{(n)} \]

hypothesis \((H_p)\) expresses that all the partial derivatives

(6.2.4)
\[ \frac{\partial^h f}{\partial x_p^h} \]

exist and are continuous in \(D\), for \(h = 0, 1, 2, \ldots, n\).

Hypothesis \((H_{p-1})\) expresses that all the partial derivatives

(6.2.5)
\[ \frac{\partial^{h+n} f}{\partial x_{p-1}^h \partial x_p^n} \]

exist and are continuous in \(D\), for \(h = 0, 1, \ldots, n\).

And so on.

The last hypothesis \((H_1)\) expresses that all the partial derivatives

(6.2.6)
\[ \frac{\partial^{h+(p-1)n} f}{\partial x_1^h \partial x_2^n \ldots \partial x_p^n} \]

exist and are continuous in \(D\), for \(h = 0, 1, \ldots, n\).

Let us then consider, in general, the integral representation of the divided difference of order \(n\) of the function \(g\) of the variable \(x_h\) on the nodes \(x_h^{(0)}, x_h^{(1)}, \ldots, x_h^{(n)}\); when \(g \in C^n[x_h^{(0)}, x_h^{(n)}]\), it is given by the formula

(6.2.7)
\[ [x_h^{(0)}, x_h^{(1)}, \ldots, x_h^{(n)} ; g] = \int_{x_h^{(0)}}^{x_h^{(n)}} \varphi_h(s) g^{(n)}(s)\, ds, \]

where \(\varphi_h\) is the spline function already considered in subsection 6.2.1

(6.2.8)
\[ \varphi_h(s) = (-1)^n \left[ \lambda_h^{(0)} \frac{(s - x_h^{(0)})_+^{n-1}}{(n-1)!} + \ldots + \lambda_h^{(n)} \frac{(s - x_h^{(n)})_+^{n-1}}{(n-1)!} \right] \]

which is positive on the interval \((x_h^{(0)}, x_h^{(n)})\).

We shall consider the function (6.2.8) further on for \(h = p, p - 1, \ldots, 1\).

6.2.3. Let us consider the function \(f\) of the variables \(x_1, x_2, \ldots, x_p\), which satisfies hypotheses \((H_p)\), \((H_{p-1})\), \(\ldots\), \((H_1)\), and the divided difference \([x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} ; f]\), where we regard the function \(f\) as a function of the variable \(x_p\) only. Taking hypothesis \((H_p)\) into account, we can write the integral representation

(6.2.9)
\[ [x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} ; f] = \int_{x_p^{(0)}}^{x_p^{(n)}} \varphi_p(s_p) \frac{\partial^n f}{\partial s_p^n}(x_1, x_2, \ldots, x_{p-1}, s_p)\, ds_p. \]

Next let us write the recurrence formula

\[ \left[\begin{array}{l} x_{p-1}^{(0)}, x_{p-1}^{(1)}, \ldots, x_{p-1}^{(n)} \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] = [x_{p-1}^{(0)}, x_{p-1}^{(1)}, \ldots, x_{p-1}^{(n)} ; [x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} ; f]] \]

and on the right-hand side let us replace the divided difference \([x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} ; f]\) by formula (6.2.9). We shall have

(6.2.10)
\[ \left[\begin{array}{l} x_{p-1}^{(0)}, x_{p-1}^{(1)}, \ldots, x_{p-1}^{(n)} \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] = \int_{x_p^{(0)}}^{x_p^{(n)}} \varphi_p(s_p) \left[x_{p-1}^{(0)}, x_{p-1}^{(1)}, \ldots, x_{p-1}^{(n)} ; \frac{\partial^n f}{\partial s_p^n}(x_1, x_2, \ldots, x_{p-1}, s_p)\right]\, ds_p. \]

On the right-hand side let us regard the function \(\frac{\partial^n f}{\partial s_p^n}(x_1, x_2, \ldots, x_{p-1}, s_p)\) as a function of the variable \(x_{p-1}\) only. Taking hypothesis \((H_{p-1})\) into account, we can write formula (6.2.10) in the form

(6.2.11)
\[ \left[\begin{array}{l} x_{p-1}^{(0)}, x_{p-1}^{(1)}, \ldots, x_{p-1}^{(n)} \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] = \int_{x_{p-1}^{(0)}}^{x_{p-1}^{(n)}} \int_{x_p^{(0)}}^{x_p^{(n)}} \varphi_{p-1}(s_{p-1}) \varphi_p(s_p) \frac{\partial^{2n} f}{\partial s_{p-1}^n \partial s_p^n}(x_1, x_2, \ldots, x_{p-2}, s_{p-1}, s_p)\, ds_{p-1}\, ds_p. \]

This procedure can be repeated, and one finally arrives at the integral representation by means of hypotheses \((H_{p-2})\), \(\ldots\), \((H_1)\). We arrive at:

Theorem 6.2.1. We have

(6.2.12)
\[ \begin{aligned} & \left[\begin{array}{l} x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} \\ x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] = \\ & = \int_{x_1^{(0)}}^{x_1^{(n)}} \int_{x_2^{(0)}}^{x_2^{(n)}} \ldots \int_{x_p^{(0)}}^{x_p^{(n)}} \varphi_1(s_1) \varphi_2(s_2) \ldots \varphi_p(s_p) \frac{\partial^{pn} f}{\partial s_1^n \partial s_2^n \ldots \partial s_p^n}(s_1, s_2, \ldots, s_p)\, ds_1\, ds_2 \ldots ds_p \end{aligned} \]

that is, at a representation of the form

(6.2.13)
\[ \left[\begin{array}{l} x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} \\ x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] = \iint \ldots \int_D \varphi(s_1, s_2, \ldots, s_p) \frac{\partial^{pn} f}{\partial s_1^n \partial s_2^n \ldots \partial s_p^n}\, ds_1\, ds_2 \ldots ds_p, \]

where the function \(\varphi\) is the product of the spline functions \(\varphi_1, \varphi_2, \ldots, \varphi_p\), that is

(6.2.14)
\[ \varphi(s_1, s_2, \ldots, s_p) = \varphi_1(s_1) \varphi_2(s_2) \ldots \varphi_p(s_p). \]

The function \(\varphi\) is positive in the interior of the domain \(D\) and vanishes on the boundary of this domain.

The integral representation (6.2.13) has been the subject of this chapter.

6.2.4. It should be noted that formula (6.2.13) has been proved by means of the fundamental formula (6.2.1) and under hypotheses \((H_p)\), \((H_{p-1})\), \(\ldots\), \((H_1)\).

However, formula (6.2.13) can be proved under a smaller number of hypotheses on the function \(f\), as we did, for example, to obtain Theorems 4.2.4 and 4.3.5 in the case \(p = 2\) and Theorems 5.8.4 and 5.8.5 in the case \(p = 3\).

↑ Contents

Română

Bibliography

D. V. Ionescu, Diferențe divizate [Divided Differences], Editura Academiei Republicii Socialiste România, Bucharest, 1978, pp. 299–300

  1. C. M. Bucur, Metode numerice, Ed. Facla, Timișoara, 1973.
  2. I. Cuculescu, Analiza numerică, Editura tehnică, Bucharest, 1967.
  3. M. Fréchet, Une définition fonctionnelle des polynomes. Nouvelles Annales Mathématiques, 1909, p. 145–162.
  4. M. Frenkel, Asupra unei teoreme a lui D. Jackson. Studii și cercetări matematice. Babeș-Bolyai University (in press).
  5. A. Ghizzetti, Quadrature formulae. Akademie Verlag, Berlin, 1970.
  6. D. V. Ionescu, Despre o formulă de cuadratură mecanică. Lucrările sesiunii generale științifice a Academiei R.P.R. din 2–12 iunie 1950, Editura Academiei R.P.R., 1951, p. 238–243.
  7. — Cîteva formule de cuadratură mecanică. Studii și cercetări științifice (Cluj), 2 (1951), no. 3–4, p. 16–37.
  8. — Cuadraturi numerice. Editura tehnică, Bucharest, 1957.
  9. — Sur la formule de quadrature de Gauss. Mathematica (Cluj), 7 (30) (1965), p. 43–46.
  10. — Restes des formules de quadrature de Gauss et de Turán. Acta Math. Acad. Sci. Hungar., 18 (1967), p. 283–295.
  11. — Sur une formule de quadrature de type Gauss. Rev. Roumaine Math. Pures Appl., 17 (1972), p. 1357–1372.
  12. — La représentation de la différence divisée généralisée par une intégrale définie, dans le cas des noeuds simples. I. An. Șt. Univ. “Al. I. Cuza” Iași, Secț. I a Mat. (N.S.), 11B (1965), p. 165–184.
  13. — La représentation de la différence divisée généralisée d’une fonction par une intégrale définie dans le cas des noeuds multiples. II. Bull. Math. Soc. Sci. Math. Phys. R. P. Roumaine, 9 (57) (1965), p. 31–57.
  14. — Introduction à la théorie des “fonctions spline”. Acta Math. Acad. Sci. Hungar., 21 (1970), p. 21–26.
  15. — O aplicație a reprezentării diferenței divizate de ordinul \(n\) a unei funcții \(f\) pe nodurile \(x_0, x_1, \ldots, x_n\) printr-o integrală definită. Communication at the Polytechnic Institute of Cluj, on the occasion of its 20th anniversary. Cluj, 12 Oct. 1968.
  16. — O identitate și reprezentarea integrală a unei funcționale liniare. Communication at the “Gh. Gheorghiu-Dej” Polytechnic Institute, on the occasion of the commemoration of 150 years of technical education in the Romanian language. Bucharest, 1 November 1968.
  17. — La représentation de la différence divisée d’une fonction de deux variables par une intégrale double. part I: Mathematica (Cluj), 3 (26) (1961), p. 59–78; part II: ibid., p. 231–271.
  18. — Predstavlenie razdelennoj raznosti porjadka \((m, n)\) funkcii ot dvuh peremennyh dvojnym integralom. part I: Dokl. Akad. Nauk SSSR, 141 (1961), p. 1026–1029; part II: ibid., p. 1294–1297.
  19. — Une identité et la représentation intégrale d’un certain opérateur linéaire. Bul. Inst. Politehn. București, 31 (1969), no. 6, p. 21–36.
  20. — La différence divisée d’une fonction de trois variables et sa représentation par une intégrale triple. Rev. Roumaine Math. Pures Appl., 15 (1970), p. 1425–1436.
  21. — La différence divisée d’ordre \(n\) d’une fonction de \(p\) variables et sa représentation par une intégrale multiple. An. Șt. Univ. “Al. I. Cuza” Iași, Secț. I a Mat. (N.S.), 18 (1972), p. 87–92.
  22. D. Jackson, On functions of closest approximation. Trans. of the Am. Math. Soc., 1921, p. 117–128.
  23. G. Kowalewski, Interpolation und genäherte Quadratur. Leipzig–Berlin, 1932.
  24. P. J. Laurent, Demonstrația reprezentării integrale a unei diferențe divizate.
  25. Gh. Marinescu, Analiza numerică. Editura Academiei R.S.R., Bucharest, 1974.
  26. M. Nicolescu, Contribuțiuni la o analiză de tip hiperbolic a planului. St. și cer. mat., Bucharest, 1952, p. 7–51.
  27. A. Ossicini, Quadrature formulae. Acad. Verlag, Berlin, 1970.
  28. P. Pavel, Formule de cuadratură de tip Gauss. Doctoral thesis. “Babeș-Bolyai” University, Cluj, 1967.
  29. M. Pavelescu, Analiza numerică pentru reactori nucleari. Editura Acad. R.S.R., Bucharest, 1974.
  30. G. Peano, Resto nelle formule di quadratura espresso con un integrale definito. Atti Acad. Nazl. Lincei. Rend. Classe Sci. Fis-Math-Nat., 1913, p. 562–569.
  31. T. Popoviciu, Sur quelques propriétés des fonctions d’une ou de deux variables réelles. Mathematica (Cluj), 8 (1934), p. 1–85.
  32. — Analiză numerică. Noțiuni introductive de calcul aproximativ. Editura Academiei R.S.R., Bucharest, 1975.
  33. J. Radon, Restausdrücke bei Interpolation und Quadratur Formeln durch bestimmte Integrale. Monatshefte für Math. u. Phys., 1935, p. 389–396.
  34. A. Sard, Integral representations of remainder. Duke Math., 5, 1948, p. 333–345.
  35. I. J. Schoenberg, Spline functions convex curves and mechanical quadrature. Bull. Am. Math. Soc., 1958, p. 352–357.
  36. Th. J. Stieltjes, Quelques recherches sur la théorie des quadratures dites mécaniques. Ann. Ecole Normale Supérieure, 1884, p. 409–426.
  37. Al. I. Șchiop, Metode numerice pentru rezolvarea ecuațiilor diferențiale. Editura Acad. R.S.R., Bucharest, 1975.
  38. — Metode aproximative în analiza neliniară. Editura Acad. R.S.R., Bucharest, 1972.
  39. D. D. Stancu, Asupra formulelor de cuadratură de tip Gauss. Mathematica, 1960, p. 167–182.
  40. — Generalizarea formulei de cuadratură a lui Gauss-Christoffel. St. și cerc. mat. Iași, 1957, p. 1–18.
  41. — Asupra unei clase de polinoame ortogonale și a unor formule generale de cuadratură cu un număr minim de termeni. Bul. Mat. Soc. St. R.P.R. Mat-Fiz., 1957, p. 478–498.
  42. — Quadrature formulas with multiple gaussian nodes. Siam. Numer. Anal., 1965, p. 129–143.
  43. — Quadrature formulas with simple gaussian Nodes and multiple fixed nodes. Math. Comput., 1963, p. 384–394.
  44. A. H. Stroud, Quadrature formulas with multiple gaussian nodes. Siam Numer. Anal., 1965, p. 129–143.
  45. — Quadrature formulas with simple gaussian Nodes and multiple fixed nodes. Math. Comput., 1963, p. 384–394.
  46. L. Tchakaloff, Über eine Darstellung des Newtonschen Differenzen-quotienten und ihre Anwendung. Congrès Intern. des Math. Oslo, 1936.
  47. P. Turán, On the theory of the mechanical quadrature. Acta Sci. Math. Szeged, 1950, p. 30–37.

↑ Contents

Română

Brief introduction

D. V. Ionescu, Diferențe divizate [Divided Differences], Editura Academiei Republicii Socialiste România, Bucharest, 1978, pp. 301–302

The definition of the divided difference of order \(n\) of a function \(f\) on the simple nodes \(x_0, x_1, x_2, \ldots, x_n\), ordered so that \(x_0 \lt x_1 \lt \ldots \lt x_n\), is well known. In the present work, when \(f \in C^n[x_0, x_n]\), this notion is defined by a boundary value problem, by applying the method of the function \(\varphi\). We arrive at the fundamental formula

(1)
\[ [x_0, x_1, \ldots, x_n; f] = \int_{x_0}^{x_n} \varphi(s) f^{(n)}(s)\, ds, \]

whose left-hand side is the divided difference of order \(n\) on the nodes \(x_0, x_1, \ldots, x_n\), and in whose right-hand side \(\varphi\) is the solution of the boundary value problem. It is proved that the function \(\varphi\) is positive on the interval \((x_0, x_n)\), which is a fundamental theorem.

The preceding definition and the integral representation (1) also extend to the case of multiple nodes, again by a boundary value problem posed by the method of the function \(\varphi\).

The applications of formula (1), and of the one corresponding to multiple nodes, are numerous. Let us mention the Lagrange and Lagrange–Hermite interpolation formulas, their remainders, and the remainders of the Gauss and Turán quadrature formulas.

The interest of our work also lies in the application of the method of the function \(\varphi\) to functions of several variables, by a boundary value problem with suitably chosen boundary conditions. Under suitable hypotheses on the function \(f\) of two variables, we arrive at the formula

(2)
\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \end{array} ; f\right] = \iint_D \varphi \frac{\partial^{2n} f}{\partial x^n \partial y^n}\, dx\, dy. \]

analogous to formula (1), whose left-hand side is by definition the divided difference of order \(n\) of the function \(f\) on the nodes \(M_{i,k}\) \((i, k = 0, 1, \ldots, n)\), \(x_0 \lt x_1 \lt \ldots \lt x_n\); \(y_0 \lt y_1 \lt \ldots \lt y_n\), and in which \(D\) is the rectangle \(x_0 \leq x \leq x_n\); \(y_0 \leq y \leq y_n\). As in formula (1), the function \(\varphi\) is the solution of the boundary value problem; it is positive on the open rectangle \(D\) and vanishes on its boundary.

Analogously, by applying the method of the function \(\varphi\), under suitable hypotheses on the function \(f\) of three variables and with suitable boundary conditions, we arrive at the formula

\[ \left[\begin{array}{l} x_0, x_1, \ldots, x_n \\ y_0, y_1, \ldots, y_n \\ z_0, z_1, \ldots, z_n \end{array} ; f\right] = \iiint_D \varphi \frac{\partial^{3n} f}{\partial x^n \partial y^n \partial z^n}\, dx\, dy\, dz. \]

analogous to formula (2), whose left-hand side is by definition the divided difference of order \(n\) of the function \(f\) on the nodes \(M_{i,j,k}(i, j, k = 0, 1, \ldots, n)\), \(x_0 \lt x_1 \lt \ldots \lt x_n\); \(y_0 \lt y_1 \lt \ldots \lt y_n\); \(z_0 \lt z_1 \lt \ldots \lt z_n\), and in which \(D\) is the parallelepiped \(x_0 \leq x \leq x_n\); \(y_0 \leq y \leq y_n\); \(z_0 \leq z \leq z_n\). The function \(\varphi\) is the solution of the boundary value problem; it is positive on the open parallelepiped \(D\) and vanishes on its boundary.

The divided differences of order \(n\) of a function \(f\) of \(p\) variables are connected by a recurrence relation, which has been established for \(p = 2, 3\). Taken in general, this relation leads to the divided difference of order \(n\) of the function \(f\) of \(p\) variables \(x_1, x_2, \ldots, x_p\) on the grid of nodes \(M_{i_1, i_2, \ldots i_p}\).

It is proved, under certain hypotheses on the function \(f\), that we have the formula

\[ \left[\begin{array}{l} x_1^{(0)}, x_1^{(1)}, \ldots, x_1^{(n)} \\ x_2^{(0)}, x_2^{(1)}, \ldots, x_2^{(n)} \\ \ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots \\ x_p^{(0)}, x_p^{(1)}, \ldots, x_p^{(n)} \end{array} ; f\right] = \iint \cdots \int_D \varphi \frac{\partial^{pn} f}{\partial x_1^n \partial x_2^n \ldots \partial x_p^n}\, dx_1\, dx_2 \ldots dx_p. \]

where \(D\) is the domain \(x_1^{(0)} \leq x_1 \leq x_1^{(n)}\); \(\ldots\); \(x_p^{(0)} \leq x_p \leq x_p^{(n)}\).

It is proved that the function \(\varphi\) is positive on the open domain \(D\) and vanishes on its boundary.

↑ Contents

1978

Related Posts