Hybrid Nehari-Schauder type fixed point results and applications

Abstract

This paper develops a fixed point version of the well-known Nehari manifold method from critical point theory. The main result is formulated for systems of operator equations, relying on the fixed point theorems of Schauder and Schaefer. The framework also allows for potential extensions combining our Nehari type approach with other fixed point principles. To demonstrate the applicability of the method, an example involving a system of nonlinear integral equations is provided.

Authors

Radu Precup
Faculty of Mathematics and Computer Science and Institute of Advanced Studies in Science and Technology, Babes-Bolyai, University, Cluj-Napoca, Romania
Tiberiu Popoviciu Institute of Numerical Analysis, Romanian Academy, Romania

Andrei Stan
Tiberiu Popoviciu Institute of Numerical Analysis, Romanian Academy, Romania
Department of Mathematics, Babes-Bolyai University, Cluj-Napoca, Romania

Keywords

Critical point, Nehari manifold, Birkhoff-Kellogg invariant-direction, cone, p-Laplace operator, positive solution, multiple solutions

Paper coordinates

Precup R, Stan A, Hybrid Nehari-Schauder type fixed point results and applications, 2025. 

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Hybrid Nehari-Schauder type fixed point results and applications

Radu Precup Faculty of Mathematics and Computer Science, and
Institute of Advanced Studies in Science and Technology, Babeş-Bolyai University,
Cluj-Napoca, 400084, Romania, and
Tiberiu Popoviciu Institute of Numerical Analysis, Romanian Academy,
Cluj-Napoca, 400110, Romania
r.precup@ictp.acad.ro
   Andrei Stan Faculty of Mathematics and Computer Science, Babeş-Bolyai University,
Cluj-Napoca, 400084, Romania, and
Tiberiu Popoviciu Institute of Numerical Analysis, Romanian Academy,
Cluj-Napoca, 400110, Romania
andrei.stan@ubbcluj.ro
Abstract.

This paper develops a fixed point version of the well-known Nehari manifold method from critical point theory. The main result is formulated for systems of operator equations, relying on the fixed point theorems of Schauder and Schaefer. The framework also allows for potential extensions combining our Nehari type approach with other fixed point principles. To demonstrate the applicability of the method, an example involving a system of nonlinear integral equations is provided.

Key words and phrases:
Nehari manifold method, hybrid fixed point theorem, nonlinear integral equation
1991 Mathematics Subject Classification:
35J50, 47J30, 45G15

1. Introduction and Preliminaries

In the context of critical point theory, various methods have been developed to establish conditions such that a given functional possesses critical points. Among them, we highlight the Nehari manifold method, which has its origins in the classical works of Nehari [17, 18]. A remarkable paper about this method is the one by Szulkin and Weth [16], which provides a clear exposition of how this method should be applied, along with illustrative examples.

Typically, following [16], the procedure reads as follows: given a C1C^{1} functional E:XE\colon X\to\mathbb{R} (usually of energy type), where XX is a Banach space, one considers the associated Nehari manifold defined by

𝒩:={uX{0}:E(u),u=0}.\mathcal{N}:=\left\{u\in X\setminus\{0\}\;:\;\langle E^{\prime}(u),u\rangle=0\right\}. (1.1)

The main idea of this method is to show that the infimum of EE over 𝒩\mathcal{N} is attained at some point u0𝒩u_{0}\in\mathcal{N}, and that this point is a critical point of EE. Such a point is usually referred to as a ground state solution, as it minimizes the functional EE among all nontrivial critical points, since every nontrivial critical point of EE lies on the Nehari manifold 𝒩\mathcal{N}.

This approach is typically effective under the following assumptions:

  • (i)

    EC1(X,)E\in C^{1}(X,\mathbb{R}), and for each uX{0}u\in X\setminus\{0\}, the function

    φ:+{0},φ(s):=E(su),\varphi\colon\mathbb{R}_{+}\setminus\{0\}\to\mathbb{R},\quad\varphi(s):=E(su),

    admits a unique critical point su>0s_{u}>0;

  • (ii)

    φ(s)>0\varphi^{\prime}(s)>0 for 0<s<su0<s<s_{u} and φ(s)<0\varphi^{\prime}(s)<0 for s>sus>s_{u};

  • (ii)

    The mapping usuu\mapsto s_{u} is continuous.

However, when dealing with problems that lack a variational structure, the method described above becomes ineffective. Since a critical point problem is equivalent to a fixed point problem (for instance, by considering u=uE(u)u=u-E^{\prime}(u)), the motivation of this paper is to adapt ideas from the Nehari manifold method to the setting of a standard fixed point problem of the form T(u)=uT(u)=u. This approach becomes particularly relevant in situations where there is no underlying functional whose derivative is related to the operator TT (e.g., when the problem can not be equivalently expressed as a critical point problem).

The novelty of this paper lies in the development of an entirely new fixed point method, inspired by the Nehari manifold technique, and formulated in the context of a fixed point problem for a system of two operator equations.

The central idea introduced in this paper is to replace the classical Nehari manifold 𝒩\mathcal{N} with another set UbU_{b}, defined as the collection of all nonzero points in a given domain for which a certain functional \mathcal{F} vanishes. Thus, given a fixed point problem (T1(u,v),T2(u,v))=(u,v)(T_{1}(u,v),T_{2}(u,v))=(u,v), we derive conditions such that a fixed point exists in K1×DK_{1}\times D, where K1K_{1} is a cone in a Banach space and DD is a bounded, closed, and convex set of a possibly different Banach space. To the best of our knowledge, the idea of adapting the Nehari manifold method to the non-variational setting is entirely new, both for single equations and for systems. In the case of systems, our approach further integrates this idea with Schauder’s fixed point theorem through the use of the fixed point index.

We would like to mention the paper [6], which, using the Nehari manifold method, provides conditions that ensure the existence of a critical point of a functional within a cone with nonempty interior. Although the methods presented in [6] are well suited for many applications, a key distinction from our approach is that the cone K1K_{1} in our setting is not required to have nonempty interior. Also, in [15, 12], the authors employed the Nehari manifold technique to obtain localization of critical points in conical annular sets, where the cones involved are closed, as in our case, and no openness condition was imposed.

In the variational case, with an appropriate choice of the functional \mathcal{F}, our set UbU_{b} essentially coincides with the Nehari manifold 𝒩\mathcal{N}. However, a key advantage of our approach is that it allows for the construction of alternative sets that may possess more favorable geometric properties. As a result, this can lead to different and possibly less restrictive conditions for the existence of a critical point. Of course, it must be emphasized that if a critical point is obtained via our method, and the set UbU_{b} differs from 𝒩\mathcal{N} (in the variational setting), then the resulting critical point generally loses the property of being a ground state solution.

It is worth noting that the literature contains numerous contributions in which various fixed point techniques are combined to study systems of equations. For instance, Krasnosel’skiĭ’s fixed point theorem has been applied componentwise to systems of two equations (see, e.g., [10, 11]), combined with the method of lower and upper solutions [13], or used jointly with Schauder’s fixed point theorem (see [9]).

Likewise, the proposed non-variational Nehari-type approach can be also combined with other fixed point principles, leading to other new hybrid results such as Nehari–Krasnosel’skiĭ, Nehari–Darbo, Nehari–Sadovskiĭ, or Nehari–Mönch, under either invariance conditions or Leray–Schauder-type boundary conditions. Moreover, the method can be extended to operator systems of higher dimension, by combining the Nehari technique with various fixed point principles—for instance, Avramescu’s theorem. Another direction could aim at exploiting the properties of the fixed point degree in combination with the Nehari technique.

We conclude this introductory section by recalling some useful properties of the fixed point index for compact maps. For more details, we refer the reader to [1, 7] (see also [3, Section 20.1]).

Proposition 1.1.

Let CC be a closed and convex subset of a normed linear space XX, and let UU be a relatively open subset of CC. Additionally, let

T:U¯CT:\bar{U}\to C

be a compact map with no fixed points on the boundary of UU. Then, the fixed point index of TT in CC over UU, denoted by indC(T,U)\mathrm{ind}_{C}(T,U), has the following properties:

  • 1.

    (Existence) If indC(T,U)0\mathrm{ind}_{C}(T,U)\neq 0, then there exists uUu\in U such that u=Tuu=Tu.

  • 2.

    (Homotopy invariance) If

    H:U¯×[0,1]CH:\overline{U}\times[0,1]\to C

    is a compact mapping such that

    H(u,t)ufor all uU and t[0,1],H(u,t)\,\neq\,u\quad\text{for all }u\in\partial U\text{ and }t\in[0,1],

    then

    indC(H(,1),U)=indC(H(,0),U).\mathrm{ind}_{C}(H(\cdot,1),U)=\mathrm{ind}_{C}(H(\cdot,0),U).
  • 3.

    (Normalization) If TT is constant with T(u)=u0T(u)=u_{0} for every uU¯u\in\overline{U}, then

    indC(T,U)={1,if u0U,0,if u0CU¯.\mathrm{ind}_{C}(T,U)=\begin{cases}1,&\text{if }u_{0}\in U,\\[3.0pt] 0,&\text{if }u_{0}\in C\setminus\bar{U}.\end{cases}

2. Main results

2.1. Nehari-Schauder fixed point theorem

Let (X1,||1)\left(X_{1},|\cdot|_{1}\right) and (X2,||2)\left(X_{2},|\cdot|_{2}\right) be two Banach spaces, let K1X1K_{1}\subset X_{1} be a non-degenerate cone, i.e., a closed, convex set with λK1K1\lambda K_{1}\subset K_{1} for all λ+\lambda\in\mathbb{R}_{+}, K1{0}K_{1}\setminus\{0\}\neq\emptyset, and DX2D\subset X_{2} a nonempty, bounded, closed, convex set.

We consider the fixed-point problem

{T1(u,v)=uT2(u,v)=v,\begin{cases}T_{1}(u,v)=u\\ T_{2}(u,v)=v,\end{cases}

where

T=(T1,T2):K1×DK1×DT=\bigl(T_{1},T_{2}\bigr)\colon K_{1}\times D\to K_{1}\times D

is a completely continuous operator. We also consider a continuous functional

:K1×K1,\mathcal{F}\colon K_{1}\times K_{1}\to\mathbb{R},

with the property that for any uK1{0}u\in K_{1}\setminus\{0\} and λ>0\lambda>0, one has

(λu,u)=0 if and only if λ=1.\mathcal{F}\bigl(\lambda\,u,\,u\bigr)=0\,\,\ \text{ if and only if }\,\,\lambda=1. (2.1)

Concerning the functional \mathcal{F}, we impose the following conditions:

(h1):

For every (u,v)(K1{0})×D(u,v)\in\left(K_{1}\setminus\{0\}\right)\times D, there exists a unique number s(u,v)>0s(u,v)>0 such that

(T1(s(u,v)u,v),s(u,v)u)=0.\mathcal{F}\Bigl(T_{1}\bigl(s(u,v)\,u,\,v\bigr),\,s(u,v)\,u\Bigr)=0.
(h2):

There exists 0<m<M<0<m<M<\infty such that

infSK11×Ds(,)>m,\inf_{S_{K_{1}}^{1}\times D}s(\cdot,\cdot)>m,

and

supSK11×Ds(,)<M,\sup_{S_{K_{1}}^{1}\times D}s\left(\cdot,\cdot\right)<M,

where

SK11:={uK1:|u|1=1}.S_{K_{1}}^{1}:=\bigl\{u\in K_{1}:\,|u|_{1}=1\bigr\}.

The first result derived from conditions (h1)-(h2), essential for our subsequent analysis, is the continuity of the mapping

s:(K1{0})×D(0,).s\colon\bigl(K_{1}\setminus\{0\}\bigr)\times D\to(0,\infty).
Proposition 2.1.

Under assumptions (h1)-(h2), the mapping ss is continuous.

Proof.

First, let us note that for any pair (u,v)(K1{0})×D(u,v)\in\bigl(K_{1}\setminus\{0\}\bigr)\times D and any t>0t>0, we have

s(tu,v)=1ts(u,v).s\bigl(tu,v\bigr)=\frac{1}{t}\,s\bigl(u,v\bigr). (2.2)

Indeed, denoting

λ:=s(tu,v)t,\lambda:=s(tu,v)\,t,

we observe that

0=(T1(s(tu,v)tu,v),s(tu,v)tu)=(T1(λu,v),λu).0=\mathcal{F}\bigl(T_{1}\bigl(s(tu,v)\,t\,u,\,v\bigr),\,s(tu,v)\,t\,u\bigr)=\mathcal{F}\bigl(T_{1}\bigl(\lambda\,u,\,v\bigr),\,\lambda\,u\bigr).

The uniqueness of s(u,v)s(u,v), ensured by assumption (h1), implies that

s(u,v)=λ,s(u,v)=\lambda,

so relation (2.2) is satisfied.

Let (u,v)(K1{0})×D(u,v)\in\bigl(K_{1}\setminus\{0\}\bigr)\times D, and consider any sequence (uk,vk)(K1{0})×D(u_{k},v_{k})\subset\bigl(K_{1}\setminus\{0\}\bigr)\times D such that

(uk,vk)(u,v)as k.(u_{k},v_{k})\to(u,v)\quad\text{as }k\to\infty.

Based on (2.2), we have

s(uk,vk)=1|uk|1s(uk|uk|1,vk).s(u_{k},v_{k})=\frac{1}{\lvert u_{k}\rvert_{1}}\,s\left(\frac{u_{k}}{\lvert u_{k}\rvert_{1}},\,v_{k}\right).

Since by (h2) the sequence s(uk|uk|1,vk)s\left(\frac{u_{k}}{\lvert u_{k}\rvert_{1}},\,v_{k}\right) is bounded both away from zero and from above, and

1|uk|11|u|1 as k,\frac{1}{\lvert u_{k}\rvert_{1}}\;\to\;\frac{1}{\lvert u\rvert_{1}}\,\,\text{ as }k\to\infty,

it follows that the sequence s(uk,vk)s(u_{k},v_{k}) is also bounded both from below and above, i.e., there exists 0<c<C<0<c<C<\infty such that s(uk,vk)[c,C]s(u_{k},v_{k})\in[c,C] for all kk\in\mathbb{N}. In order to prove that s(uk,vk)s(u,v)s(u_{k},v_{k})\to s(u,v) as kk\to\infty, it suffices to show that any convergent subsequence converges to s(u,v)s(u,v) (see, e.g., [4, Lemma 1.1]). Thus, let s(ukq,vkq)s(u_{k_{q}},v_{k_{q}}) be a subsequence convergent to some s[c,C]s_{\ast}\in[c,C]. Then, by the definition of the mapping ss, we have

0=(T1(s(ukq,vkq)ukq,vkq),s(ukq,vkq)ukq).0=\mathcal{F}\left(T_{1}\left(s(u_{k_{q}},v_{k_{q}})u_{k_{q}},v_{k_{q}}\right),s\bigl(u_{k_{q}},\,v_{k_{q}}\bigr)u_{k_{q}}\right).

Now, passing to the limit, one obtains that

(T1(su,v),su)=0.\mathcal{F}\left(T_{1}(s_{\ast}u,v),s_{\ast}u\right)=0.

From (h1), there exists a unique s(u,v)>0s(u,v)>0 such that

((s(u,v)u,v),s(u,v)u)= 0,\bigl(\mathcal{F}\bigl(s(u,v)\,u,\,v\bigr),\,s(u,v)u\bigr)\;=\;0,

so s=s(u,v)s_{\ast}=s(u,v) as desired. This completes the proof, since the choice of (u,v)(u,v) and the sequence (uk,vk)(u_{k},v_{k}) was arbitrary. ∎

In the subsequent, we consider the sets

Ub={(u,v)(K1{0})×D:s(u,v)=1}U_{b}=\bigl\{\left(u,v\right)\in(K_{1}\setminus\{0\})\times D\,:\,s(u,v)=1\bigl\}

and

U={(λu,v):0λ<1 and (u,v)Ub}.U=\bigl\{\left(\lambda u,v\right):0\leq\lambda<1\,\,\text{ and }\,\,(u,v)\in U_{b}\bigl\}.
Remark 2.2.

A simple observation based on assumption (h1) allows us to establish an equivalent characterization of the set UbU_{b}, namely,

Ub={(u,v)(K1{0})×D:(T1(u,v),u)=0}.U_{b}=\left\{\left(u,v\right)\in(K_{1}\setminus\{0\})\times D\,:\,\mathcal{F}\Bigl(T_{1}\bigl(u,\,v\bigr),\,u\Bigr)=0\right\}.
Lemma 2.3.

The set UU is open in the relative topology of K1×D.K_{1}\times D. Moreover, it is a bounded set.

Before proving this, we need the following auxiliary result.

Proposition 2.4.

Let (uk,vk)(K1{0})×D(u_{k},v_{k})\in\left(K_{1}\setminus\{0\}\right)\times D be a sequence such that

(uk,vk)(0,v) as k,(u_{k},v_{k})\to(0,v)\,\,\text{ as }k\to\infty,

for some vDv\in D. Then,

s(uk,vk) as k.s(u_{k},v_{k})\to\infty\,\,\,\text{ as }k\to\infty.
Proof.

Since uk0u_{k}\neq 0, by assumption (h2), one has

s(uk|uk|1,vk)m for all k.s\left(\frac{u_{k}}{|u_{k}|_{1}},v_{k}\right)\geq m\,\,\,\text{ for all }k\in\mathbb{N}.

Using (2.2) we see that

s(uk,vk)=s(|uk|1uk|uk|1,vk)=1|uk|1s(uk|uk|1,vk),s\left(u_{k},v_{k}\right)=s\left(|u_{k}|_{1}\frac{u_{k}}{|u_{k}|_{1}},v_{k}\right)=\frac{1}{|u_{k}|_{1}}s\left(\frac{u_{k}}{|u_{k}|_{1}},v_{k}\right),

which implies

s(uk,vk)m|uk|1.s\left(u_{k},v_{k}\right)\geq\frac{m}{|u_{k}|_{1}}.

Finally, since uk0u_{k}\to 0 as kk\to\infty, the desired conclusion follows immediately. ∎

Now, we continue with the proof of Lemma \latexrefU open stated above.

Proof of Lemma \latexrefU open.

To prove that UU is open in the relative topology of K1×DK_{1}\times D, it suffices to show that the set (K1×D)U(K_{1}\times D)\setminus U is closed. To this aim, let (uk,vk)(K1×D)U(u_{k},v_{k})\in(K_{1}\times D)\setminus U be any sequence convergent to some (u,v)K1×D(u,v)\in K_{1}\times D. We need to show that (u,v)U(u,v)\notin U.

First, we claim that

(s(uk,vk)uk,vk)Ub.\left(s\left(u_{k},v_{k}\right)u_{k},v_{k}\right)\in U_{b}. (2.3)

Observe that, since {0}×DU\{0\}\times D\subset U and (uk,vk)U(u_{k},v_{k})\notin U, we have uk0u_{k}\neq 0. Now, using relation (2.2), we have

s(s(uk,vk)uk,vk)=1s(uk,vk)s(uk,vk)=1,s\left(s\left(u_{k},v_{k}\right)u_{k},v_{k}\right)=\frac{1}{s\left(u_{k},v_{k}\right)}s\left(u_{k},v_{k}\right)=1,

whence our claim is verified.

Next, write

(uk,vk)=(1s(uk,vk)s(uk,vk)uk,vk).(u_{k},v_{k})=\left(\frac{1}{s(u_{k},v_{k})}s(u_{k},v_{k})u_{k},v_{k}\right). (2.4)

Since (uk,vk)(K1×D)U(u_{k},v_{k})\in(K_{1}\times D)\setminus U, by (2.3) it follows that

1s(uk,vk)1.\frac{1}{s(u_{k},v_{k})}\geq 1. (2.5)

This inequality implies that the limit of the sequence uku_{k} is nonzero, i.e., u0u\neq 0. Indeed, if this were not the case, that is, if u=0u=0, then by Proposition \latexreflema_conv_zero we would have

s(uk,vk) as k,s(u_{k},v_{k})\,\to\,\infty\,\,\text{ as }k\to\infty,

which yields a contradiction with (2.5).

The final step in our proof is to pass to the limit in (2.5). To see why, note that s(uk,vk)s(u,v)s(u_{k},v_{k})\to s(u,v). Also, by relation (2.5), we have

1s(u,v)1.\frac{1}{s(u,v)}\geq 1.

Moreover, since (s(u,v)u,v)Ub\left(s(u,v)u,v\right)\in U_{b}, from the definition of UU we conclude that

(u,v)=(1s(u,v)s(u,v)u,v)U,(u,v)=\left(\frac{1}{s(u,v)}s(u,v)u,v\right)\notin U,

as desired.

To show the second part, observe that we are concerned with the boundedness only with respect to the first component, since by definition, DD is a bounded set.

Suppose now that there exists a sequence (uk,vk)Ub(u_{k},v_{k})\in U_{b} such that |uk|1|u_{k}|_{1}\to\infty. Then, using

1=s(uk,vk)=1|uk|1s(uk|uk|1,vk)1|uk|1M,1=s(u_{k},v_{k})=\frac{1}{|u_{k}|_{1}}s\left(\frac{u_{k}}{|u_{k}|_{1}},v_{k}\right)\leq\frac{1}{|u_{k}|_{1}}M,

by letting kk\to\infty we arrive at a contradiction, so the set UbU_{b} is bounded. From this, the boundedness of UU follows immediately. ∎

Remark 2.5.

The boundary of UU relative to K1×DK_{1}\times D is Ub,U_{b}, i.e.,

U=Ub.\partial U=U_{b}.

We are ready now to state the first main result of our paper.

Theorem 2.6.

Assume that conditions (h1)-(h3) are satisfied. Then, the operator (T1,T2)(T_{1},T_{2}) admits a fixed point (u,v)K1×D(u,v)\in K_{1}\times D. If in addition the operator (T1,T2)(T_{1},T_{2}) has no fixed point of the form (0,v¯)(0,\bar{v}), with v¯D\bar{v}\in D, then (u,v)Ub(u,v)\in U_{b}.

Proof.

Let ωD\omega\in D and consider the homotopy H:U¯×[0,1]K1×D,H\colon\overline{U}\times[0,1]\to K_{1}\times D,

H((u,v),t)=(tT1(u,v),tT2(u,v)+(1t)ω).H\bigl((u,v),\,t\bigr)=\Bigl(\,t\,T_{1}(u,v),\;t\,T_{2}(u,v)\;+\;\bigl(1-t\bigr)\,\omega\Bigr).

Clearly, HH is a compact mapping. We distinguish two possible cases:

  • (a)

    The homotopy HH has no fixed points on U\partial U, i.e.,

    0(IH)(U×[0,1]),0\notin\bigl(I-H\bigr)\bigl(\,\partial U\times[0,1]\bigr),

    or

  • (b)

    There exists (u,v)U(u,v)\in\partial U and t[0,1]t\in[0,1] such that

    (u,v)=H((u,v),t).(u,v)=H((u,v),t). (2.6)

In case (a), we show that (T1,T2)(T_{1},T_{2}) has only fixed points of the form (0,v)(0,v) with vDv\in D. To prove the existence of such a fixed point, we use the homotopy invariance of the fixed point index, which ensures that

indK1×D((T1,T2),U)=indK1×D(H(,1),U)=indK1×D(H(,0),U).\mathrm{ind}_{K_{1}\times D}((T_{1},T_{2}),U)=\mathrm{ind}_{K_{1}\times D}(H(\cdot,1),U)=\mathrm{ind}_{K_{1}\times D}(H(\cdot,0),U).

Since H(,0)=(0,ω)UH(\cdot,0)=(0,\omega)\in U, the normalization property of the fixed point index yields

indK1×D((T1,T2),U)=indK1×D((0,ω),U)=1.\mathrm{ind}_{K_{1}\times D}((T_{1},T_{2}),U)=\mathrm{ind}_{K_{1}\times D}((0,\omega),U)=1.

Therefore, the mapping (T1,T2)(T_{1},T_{2}) has a fixed point in UU, i.e., there exists (u,v)U(u,v)\in U such that

u=T1(u,v) and v=T2(u,v).u=T_{1}(u,v)\quad\text{ and }\quad v=T_{2}(u,v).

Assume that u0u\neq 0. Then, using property (2.1), we observe that

(T1(u,v),u)=(u,u)=0.\mathcal{F}\bigl(T_{1}(u,v),\,u\bigr)=\mathcal{F}\bigl(u,\,u\bigr)=0.

This implies that s(u,v)=1s(u,v)=1, so (u,v)Ub=U(u,v)\in U_{b}=\partial U. However, this leads to a contradiction since (u,v)U(u,v)\in U and UU is open. Therefore, u=0u=0, so (0,v)(0,v) is a fixed point for (T1,T2)(T_{1},T_{2}).

In the case (b), relation (2.6) is equivalent to

u=tT1(u,v)andv=tT2(u,v)+(1t)ω.u=t\,T_{1}(u,v)\quad\text{and}\quad v=t\,T_{2}(u,v)+(1-t)\,\omega. (2.7)

If t=0t=0, then u=0u=0, which contradicts the assumption that (u,v)U(u,v)\in\partial U, since (0,v)U(0,v)\in U and UU is open. If t(0,1]t\in(0,1], then from (2.7) we have

T1(u,v)=1tu.T_{1}(u,v)=\frac{1}{t}\,u. (2.8)

Given that (u,v)Ub=U(u,v)\in U_{b}=\partial U, and using (2.8), by the definition of the set UbU_{b}, it follows that

0=(T1(u,v),u)=(1tu,u).0=\mathcal{F}\bigl(T_{1}(u,v),\,u\bigr)=\mathcal{F}\bigl(\tfrac{1}{t}\,u,\,u\bigr).

Note that property (2.1) implies 1t=1\tfrac{1}{t}=1, which holds only if t=1t=1. In this case, relation (2.7) shows that (u,v)(u,v) is a fixed point of the operator (T1,T2)\bigl(T_{1},\,T_{2}\bigr). ∎

2.2. Nehari type fixed point theorem

Consider now a single fixed point equation

T(u)=u,T(u)=u, (2.9)

in a cone KK of a Banach space (X,||)(X,|\cdot|). Let us take X1:=XX_{1}:=X, K1:=KK_{1}:=K, and let DD be a singleton, that is, D={v0}D=\{v_{0}\} for some fixed v0Xv_{0}\in X. By identifying

T1(u,v0):=T(u),T2(u,v0):=v0,T_{1}(u,v_{0}):=T(u),\qquad T_{2}(u,v_{0}):=v_{0},

we recover the fixed point problem (T1(u,v),T2(u,v))=(u,v)(T_{1}(u,v),T_{2}(u,v))=(u,v) in the special case where the second component remains constant. This yields the following fixed point principle.

Assume that T:KKT:K\rightarrow K is completely continuous, :K×K\mathcal{F}:K\times K\rightarrow\mathbb{R} is any continuous functional satisfying (\latexrefproprietate F), and consider the following conditions:

(c1):

For every uK{0}u\in K\setminus\{0\}, there exists a unique number s(u)>0s(u)>0 such that

(T(s(u)u),s(u)u)=0.\mathcal{F}\Bigl(T\bigl(s(u)\,u\bigr),\,s(u)\,u\Bigr)=0.
(c2):

Denoting SK1:={uK:|u|=1},S_{K}^{1}:=\left\{u\in K:\ \left|u\right|=1\right\}, there exists 0<m<M<0<m<M<\infty such that

infSK1s()>m\inf_{S_{K}^{1}}s(\cdot)>m

and

supSK1s()<M.\sup_{S_{K}^{1}}s\left(\cdot\right)<M.
Corollary 2.7.

Assume conditions (c1)-(c2) hold. Then, the operator TT has a fixed point uu\in KK. In addition, if  0\,0 is not a solution of (\latexrefepf), then s(u)=1.s\left(u\right)=1.

Remaining in the setting of a single equation, we now let X:=HX:=H be a Hilbert space endowed with the inner product (,)H(\cdot,\cdot)_{H}, and identified with its dual. Consider a C1C^{1} functional

E:H,E\colon H\to\mathbb{R},

whose Fréchet derivative is denoted by E:HHE^{\prime}\colon H\to H. In this framework, define the operator

T(u)=uE(u),T(u)=u-E^{\prime}(u), (2.10)

and assume that TT is completely continuous and satisfies the invariance condition

T(K)K.T(K)\subset K.

Further, considering the functional :K×K\mathcal{F}\colon K\times K\to\mathbb{R} given by

(u~,u):=(uu~,u)H,\mathcal{F}(\tilde{u},u):=(u-\tilde{u},u)_{H}, (2.11)

we recover the classical Nehari manifold 𝒩K\mathcal{N}_{K} defined by

𝒩K={uK{0}:(E(u),u)H=0}.\mathcal{N}_{K}=\left\{u\in K\setminus\{0\}\,:\,\left(E^{\prime}(u),u\right)_{H}=0\right\}. (2.12)

Then, for any uKu\in K, we have

(T(u),u)=(uT(u),u)1=(E(u),u)H.\mathcal{F}(T(u),u)=(u-T(u),u)_{1}=(E^{\prime}(u),u)_{H}.

Therefore, based on Remark \latexrefremarca_echivalenta_cu_nehari, the set UbU_{b} becomes

Ub={uK{0}:(E(u),u)H=0},U_{b}=\left\{u\in K\setminus\{0\}\;:\;(E^{\prime}(u),u)_{H}=0\right\},

i.e., Ub=𝒩KU_{b}=\mathcal{N}_{K}.

Remark 2.8.

Returning to the general case of a Banach space (X,||X)(X,|\cdot|_{X}) endowed with the cone KK, and inspired by the construction of the Nehari manifold, one may consider the following example of a functional \mathcal{F}. Assume that XX is continuously embedded into a Hilbert space (H,(,)H)(H,(\cdot,\cdot)_{H}). Then, \mathcal{F} can be defined by

(u~,u):=(uu~,u)H(u,u~K).\mathcal{F}(\tilde{u},u):=(u-\tilde{u},u)_{H}\quad(u,\tilde{u}\in K).

2.3. Nehari-Schaefer fixed point theorem

The previous result was established under the invariance condition on T2T_{2}, namely,

T2(K1×D)D,T_{2}\bigl(K_{1}\times D\bigr)\,\subset\,D,

where DD is a given nonempty, bounded, closed, and convex set, as in Schauder’s fixed point theorem. The next result does not require such an invariance condition.

Under the above notations, assume that, instead of DD, we consider a closed ball BRX2B_{R}\subset X_{2}, centered at the origin and of radius R>0R>0. Assume further that the operators

T1:K1×X2K1,T2:K1×BRX2,T_{1}\colon K_{1}\times X_{2}\to K_{1},\quad T_{2}\colon K_{1}\times B_{R}\to X_{2},

are completely continuous, and that the following conditions are satisfied:

(a1):

The set T2(K1×BR)T_{2}\left(K_{1}\times B_{R}\right) is bounded in X2.X_{2}.

(a2):

For every (u,v)(K1{0})×BR(u,v)\in\left(K_{1}\setminus\{0\}\right)\times B_{R}, there exists a unique number s(u,v)>0s(u,v)>0 such that

(T1(s(u,v)u,v),s(u,v)u)=0.\mathcal{F}\Bigl(T_{1}\bigl(s(u,v)\,u,\,v\bigr),\,s(u,v)\,u\Bigr)=0.
(a3):

There exists 0<m<M<0<m<M<\infty such that

infSK11×Ds(,)>m,\inf_{S_{K_{1}}^{1}\times D}s(\cdot,\cdot)>m,

and

supSK11×Ds(,)<M.\sup_{S_{K_{1}}^{1}\times D}s\left(\cdot,\cdot\right)<M.
Theorem 2.9.

Assume conditions (a1)-(a3) hold. In addition, assume that

vλT2(u,v)for all uK1,vBR, and λ(0,1).v\neq\lambda T_{2}\left(u,v\right)\ \ \ \text{for all }u\in K_{1},v\in\partial B_{R},\text{ and }\lambda\in\left(0,1\right).

Then, the operator (T1,T2)(T_{1},T_{2}) has a fixed point in K1×BR.K_{1}\times B_{R}.

Proof.

We reduce the problem to that one from Section 2.1. To this aim, we let

D:=BR~,D:=B_{\widetilde{R}},

where R~R\widetilde{R}\geq R is such that

T2(K1×BR)BR~.T_{2}\left(K_{1}\times B_{R}\right)\subset B_{\widetilde{R}}.

Such a ball exists based on assumption (a1). Next, we extend the operators T1T_{1} and T2T_{2} from K1×BRK_{1}\times B_{R} to K1×BR~\,K_{1}\times B_{\widetilde{R}}\, by defining

T~1:K1×BR~K1andT~2:K1×BR~BR~,\widetilde{T}_{1}\colon K_{1}\times B_{\widetilde{R}}\to K_{1}\quad\text{and}\quad\widetilde{T}_{2}\colon K_{1}\times B_{\widetilde{R}}\to B_{\widetilde{R}},

as follows

T~i(u,v)={Ti(u,v),if 0|v|2R,Ti(u,R|v|2v),if R<|v|2R~,for i=1,2.\widetilde{T}_{i}(u,v)=\begin{cases}T_{i}(u,v),&\text{if }0\leq|v|_{2}\leq R,\\ T_{i}\left(u,\frac{R}{|v|_{2}}v\right),&\text{if }R<|v|_{2}\leq\widetilde{R},\end{cases}\quad\text{for }i=1,2.

Letting T~:=(T~1,T~2),\widetilde{T}:=\left(\widetilde{T}_{1},\widetilde{T}_{2}\right), we aim to apply Theorem \latexrefthm principala. First, note that the operator T~\widetilde{T} is completely continuous and invariant with respect to K1×BR~K_{1}\times B_{\widetilde{R}}. Next, we show that the mapping

s~:(K1{0})×BR~(0,),s~(u,v)={s(u,v)if|v|2Rs(u,R|v|2v)ifR<|v|2R~,\widetilde{s}\colon\left(K_{1}\setminus\{0\}\right)\times B_{\widetilde{R}}\to(0,\infty),\quad\widetilde{s}\left(u,v\right)=\left\{\begin{array}[]{lll}s\left(u,v\right)&\text{if}&\left|v\right|_{2}\leq R\\ s\left(u,\frac{R}{\left|v\right|_{2}}v\right)&\text{if}&R<\left|v\right|_{2}\leq\widetilde{R},\end{array}\right.

satisfies (h1). Let uK1{0}u\in K_{1}\setminus\{0\}. If vBRv\in B_{R}, the statement follows directly from assumption (a2). Now, consider vBR~BRv\in B_{\widetilde{R}}\setminus B_{R}, and define w:=R|v|2vBRw:=\frac{R}{|v|_{2}}v\in B_{R}. Then, we have

(T~1(s~(u,v)u,v),s~(u,v)u)\displaystyle\mathcal{F}\left(\widetilde{T}_{1}\left(\tilde{s}(u,v)\,u,v\right),\,\tilde{s}(u,v)\,u\right) =(T1(s(u,w)u,w),s(u,w)u)=0,\displaystyle=\mathcal{F}\left(T_{1}\left(s(u,w)\,u,w\right),\,s(u,w)\,u\right)=0,

by assumption (a2) and the fact that wBRw\in B_{R}. Clearly, assumption (h2) and (h3) also are satisfied. Thus, Theorem \latexrefthm principala applies and guarantees the existence of a fixed point (u,v)\left(u,v\right) of T~,\widetilde{T}, with uK1u\in K_{1} and vBR~.v\in B_{\widetilde{R}}. It remains to show that in fact vBR.v\in B_{R}. Assume, by contradiction, that vBR~BRv\in B_{\widetilde{R}}\setminus B_{R}. Then, by the definition of T~2\widetilde{T}_{2}, we have

v=T~2(u,v)=T2(u,R|v|2v).v=\widetilde{T}_{2}(u,v)=T_{2}\left(u,\frac{R}{|v|_{2}}v\right).

Denote w:=R|v|2vw:=\frac{R}{|v|_{2}}v and λ:=R|v|2\lambda:=\frac{R}{|v|_{2}}. Then,

wBR,λ(0,1),andλT2(u,w)=w,w\in\partial B_{R},\quad\lambda\in(0,1),\quad\text{and}\quad\lambda\,T_{2}(u,w)=w,

which contradicts assumption (a1). Hence, vBRv\in B_{R}, and therefore

(u,v)=T~(u,v)=T(u,v),(u,v)=\widetilde{T}(u,v)=T(u,v),

which completes the proof.

3. Application

We now illustrate the applicability of Theorem \latexrefthm principala by considering the system

{u(t)=01k1(t,θ)f(u(θ),v(θ))𝑑s:=T1(u,v)(t)v(t)=01k2(t,θ)g(u(θ),v(θ))𝑑s:=T2(u,v)(t),\begin{cases}u(t)=\int_{0}^{1}k_{1}(t,\theta)f(u(\theta),v(\theta))ds:=T_{1}(u,v)(t)\\ v(t)=\int_{0}^{1}k_{2}(t,\theta)g(u(\theta),v(\theta))ds:=T_{2}(u,v)(t),\end{cases} (3.1)

where k1,k2k_{1},k_{2} are nonnegative continuous functions on [0,1]2[0,1]^{2}; f,gC(2,)f,g\in C\left(\mathbb{R}^{2},\mathbb{R}\right) and f(x,y)0f(x,y)\geq 0 for all x0x\geq 0 and yy\in\mathbb{R}. Related to the kernel k1k_{1}, assume that

(H1):

There exists a continuous function Φ:[0,1]+\Phi\colon[0,1]\to\mathbb{R}_{+}, an interval [a,b][0,1][a,b]\subset[0,1] and a constant c1>0c_{1}>0 such that

k1(t,θ)Φ(θ) for all t,θ[0,1],\displaystyle k_{1}(t,\theta)\leq\Phi(\theta)\quad\text{ for all }\,\,t,\theta\in[0,1], (3.2)
c1Φ(θ)k1(t,θ) for all t[a,b] and θ[0,1].\displaystyle c_{1}\Phi(\theta)\leq k_{1}(t,\theta)\quad\text{ for all }\,\,t\in[a,b]\text{ and }\theta\in[0,1]. (3.3)

In order to apply Theorem \latexrefthm principala, take

X1=X2=C([0,1],),X_{1}=X_{2}=C\bigl([0,1],\,\mathbb{R}\bigr),

endowed with the supremum norm

|u|=maxt[0,1]|u(t)|.|u|_{\infty}=\max_{t\in[0,1]}\,|u(t)|.

By standard arguments (see, e.g., [8]), both operators T1,T2T_{1},T_{2} are completely continuous from C([0,1],)2C([0,1],).C\bigl([0,1],\,\mathbb{R}\bigr)^{2}\to C\bigl([0,1],\,\mathbb{R}\bigr). Furthermore, in C([0,1],)C\bigl([0,1],\,\mathbb{R}\bigr) we consider the cone

K1:={uC([0,1],):u0 and mint[a,b]u(t)c1|u|},K_{1}:=\bigl\{u\in C\bigl([0,1],\,\mathbb{R}\bigr)\,:\,u\geq 0\,\,\text{ and }\,\,\min_{t\in[a,b]}u(t)\,\geq c_{1}\,|u|_{\infty}\bigr\},

and the bounded, closed, and convex set

D=BR={uC([0,1],):|u|R},D=B_{R}=\bigl\{u\in C\bigl([0,1],\,\mathbb{R}\bigr)\,:\,|u|_{\infty}\leq R\bigl\},

where R>0R>0 is a given number. The functional :K1×K1\,\mathcal{F}\colon K_{1}\times K_{1}\to\mathbb{R}\, is chosen to be

(u,u~)=01(u(t)u~(t))u(t)𝑑t.\mathcal{F}(u,\tilde{u})=\int_{0}^{1}\bigl(u(t)-\tilde{u}(t)\bigr)\,u(t)\,dt.

Additionally, define

α1:=maxt[0,1]Φ(t),α2:=ababk1(t,θ)𝑑θ𝑑tandα3=maxt[0,1]01k2(t,θ)𝑑θ.\alpha_{1}:=\max_{t\in[0,1]}\Phi(t),\,\,\,\,\alpha_{2}:=\int_{a}^{b}\int_{a}^{b}k_{1}(t,\theta)\,d\theta\,dt\,\,\,\,\text{and}\,\,\,\,\alpha_{3}=\max_{t\in[0,1]}\int_{0}^{1}k_{2}(t,\theta)d\theta.

Related to the functions f,gf,g, we assume that the following conditions are satisfied.

(H2):

There exists a positive constant c2<1α1\,c_{2}<\frac{1}{\alpha_{1}} such that

limx0f(x,y)xc2 for all |y|R.\lim_{x\searrow 0}\frac{f(x,y)}{x}\leq c_{2}\quad\text{ for all }\,\,|y|\leq R.
(H3):

There exists   0<c30<c_{3}\leq\infty  such that

limxf(x,y)xc3 for all |y|R,\lim_{x\to\infty}\frac{f(x,y)}{x}\geq c_{3}\quad\text{ for all }\,\,|y|\leq R, (3.4)

and

c3>1c12α2.c_{3}>\frac{1}{c_{1}^{2}\alpha_{2}}. (3.5)
(H4):

For each yy with |y|R|y|\leq R, the mapping

xf(x,y)xx\mapsto\frac{f(x,y)}{x}

is strictly increasing on (0,)(0,\infty).

(H5):

For every x0x\geq 0 and any yy with |y|R|y|\leq R, one has

g(x,y)α,g(x,y)\leq\alpha,

where

α<1α3.\alpha<\frac{1}{\alpha_{3}}.

From (H5), one clearly has

T2(K1×D)D(D=BR).T_{2}\bigl(K_{1}\times D\bigr)\;\subset\;D\,\,\,\,\,\,(D=B_{R}).

Also, for any uK1u\in K_{1} and vDv\in D, using (3.2) and (3.3), we have

T1(u,v)(t)\displaystyle T_{1}(u,v)(t) =01k1(t,θ)f(u(θ),v(θ))𝑑θ\displaystyle=\int_{0}^{1}k_{1}(t,\theta)\,f\bigl(u(\theta),v(\theta)\bigr)d\theta
c101Φ(θ)f(u(θ),v(θ))𝑑θ\displaystyle\geq c_{1}\int_{0}^{1}\Phi(\theta)\,f\bigl(u(\theta),v(\theta)\bigr)d\theta
c101k1(t,θ)f(u(θ),v(θ))𝑑θ\displaystyle\geq c_{1}\int_{0}^{1}k_{1}(t^{\prime},\theta)\,f\bigl(u(\theta),v(\theta)\bigr)d\theta
=c1T1(u,v)(t)\displaystyle=c_{1}\,T_{1}(u,v)(t^{\prime})

for all t[a,b]t\in[a,b] and t[0,1]t^{\prime}\in[0,1]. Consequently,

T1(K1×BR)K1.T_{1}\bigl(K_{1}\times B_{R}\bigr)\;\subset\;K_{1}.

Note that for any uK1{0}u\in K_{1}\setminus\{0\}, vDv\in D and σ>0\sigma>0, one may write

(T1(σu,v),σu)\displaystyle\mathcal{F}\left(T_{1}(\sigma u,v),\sigma u\right) (3.6)
=01T1(σu(t),v(t))σu(t)𝑑tσ201u2(t)𝑑t\displaystyle=\int_{0}^{1}T_{1}(\sigma u(t),v(t))\sigma u(t)dt-\sigma^{2}\int_{0}^{1}u^{2}(t)dt (3.7)
=σ2(01(011σk1(t,θ)f(σu(θ),v(θ)dθ)u(t)dt01u(t)2dt).\displaystyle=\sigma^{2}\left(\int_{0}^{1}\left(\int_{0}^{1}\frac{1}{\sigma}k_{1}(t,\theta)f(\sigma u(\theta),v(\theta)d\theta\right)u(t)dt-\int_{0}^{1}u(t)^{2}dt\right).

In the sequel, without further mention, we will use the fact that whenever vDv\in D, one has

|v(t)|R for all t[0,1].|v(t)|\leq R\,\,\text{ for all }t\in[0,1].

Check of condition (h2). Let uK1u\in K_{1} with |u|=1|u|_{\infty}=1, and vDv\in D. From assumption (H2), there exists δ0>0\delta_{0}>0 such that

f(x,y)c2x for all   0x<δ0 and|y|R.f(x,y)\leq c_{2}x\,\,\text{ for all }\,\,0\leq x<\delta_{0}\text{ and}\,\,|y|\leq R. (3.8)

Thus, for 0σ<δ00\leq\sigma<\delta_{0}, using (h1), (3.8) and the Holder’s inequality, we estimate

01(011σk1(t,θ)f(σu(θ),v(θ)dθ)u(t)dt\displaystyle\int_{0}^{1}\left(\int_{0}^{1}\frac{1}{\sigma}k_{1}(t,\theta)f(\sigma u(\theta),v(\theta)d\theta\right)u(t)dt 01Φ(θ)u(θ)2𝑑θ01u(t)𝑑t\displaystyle\leq\int_{0}^{1}\Phi(\theta)u(\theta)^{2}d\theta\int_{0}^{1}u(t)dt
c2max[0,1]Φ()(01u(t)𝑑t)2\displaystyle\leq c_{2}\max_{[0,1]}\Phi(\cdot)\left(\int_{0}^{1}u(t)dt\right)^{2}
c2α101u2(t)𝑑t.\displaystyle\leq\frac{c_{2}}{\alpha_{1}}\int_{0}^{1}u^{2}(t)dt.

Since c2<1α1c_{2}<\frac{1}{\alpha_{1}}, we see that

(T1(σu,v),σu)σ2(c21α1Φ()1)01u2(t)𝑑t<0,\displaystyle\mathcal{F}\bigl(T_{1}(\sigma u,v),\,\sigma\,u\bigr)\leq\sigma^{2}\left(c_{2}\frac{1}{\alpha_{1}}\Phi(\cdot)-1\right)\int_{0}^{1}u^{2}(t)dt<0,

for all 0σ<δ0.0\leq\sigma<\delta_{0}. Consequently, if σ\sigma satisfies

(T1(σu,v),σu)=0,\mathcal{F}\bigl(T_{1}(\sigma u,v),\,\sigma\,u\bigr)=0,

then necessarily σδ0.\sigma\geq\delta_{0}. Since δ0\delta_{0} is independent of the choice of uu and vv, condition (h2) is satisfied.

To verify that σ<M\sigma<M for some M>0M>0 whenever |u|=1|u|_{\infty}=1 and |v|R|v|_{\infty}\leq R, note that using condition (3.4) from (H3), there exist constants σ0>0\sigma_{0}>0 and c4>1c12α2c_{4}>\frac{1}{c_{1}^{2}\alpha_{2}} such that

f(σx,y)σc4x for all σσ0,xc1 and |y|R.f(\sigma x,y)\geq\sigma c_{4}x\,\,\text{ for all }\sigma\geq\sigma_{0},\,x\geq c_{1}\,\text{ and }\,|y|\leq R. (3.9)

Let t[0,1]t\in[0,1] and σσ0\sigma\geq\sigma_{0}. Using (H1) and (3.9), we estimate

011σk1(t,θ)f(σu(θ),v(θ)dθ\displaystyle\int_{0}^{1}\frac{1}{\sigma}k_{1}(t,\theta)f(\sigma u(\theta),v(\theta)d\theta ab1σk1(t,θ)f(σu(θ),v(θ)dθ\displaystyle\geq\int_{a}^{b}\frac{1}{\sigma}k_{1}(t,\theta)f(\sigma u(\theta),v(\theta)d\theta
c4abk1(t,θ)u(θ)𝑑θ\displaystyle\geq c_{4}\int_{a}^{b}k_{1}(t,\theta)u(\theta)d\theta
c1c4abk1(t,θ)𝑑θ.\displaystyle\geq c_{1}c_{4}\int_{a}^{b}k_{1}(t,\theta)d\theta.

Therefore, we further have

01(011σk1(t,θ)f(σu(θ),v(θ)dθ)u(t)dt\displaystyle\int_{0}^{1}\left(\int_{0}^{1}\frac{1}{\sigma}k_{1}(t,\theta)f(\sigma u(\theta),v(\theta)d\theta\right)u(t)dt c1c401(abk1(t,θ)𝑑θ)u(t)𝑑t\displaystyle\geq c_{1}c_{4}\int_{0}^{1}\left(\int_{a}^{b}k_{1}(t,\theta)d\theta\right)u(t)dt
c1c4ab(abk1(t,θ)𝑑θ)u(t)𝑑t\displaystyle\geq c_{1}c_{4}\int_{a}^{b}\left(\int_{a}^{b}k_{1}(t,\theta)d\theta\right)u(t)dt
c12c4ababk1(t,θ)𝑑θ𝑑t\displaystyle\geq c_{1}^{2}c_{4}\int_{a}^{b}\int_{a}^{b}k_{1}(t,\theta)d\theta dt
=c12c4α2.\displaystyle=c_{1}^{2}c_{4}\alpha_{2}.

Applying the above estimate in (3.6), together with the obvious inequality

01u(t)2𝑑t|u|2=1,\int_{0}^{1}u(t)^{2}dt\leq|u|_{\infty}^{2}=1,

and relation (3.5), we obtain

(T1(σu,v),σu)\displaystyle\mathcal{F}\left(T_{1}(\sigma u,v),\sigma u\right) σ2(c12c4α01u(t)2𝑑t)\displaystyle\geq\sigma^{2}\left(c_{1}^{2}c_{4}\alpha-\int_{0}^{1}u(t)^{2}dt\right)
σ2(c12c4α21)\displaystyle\geq\sigma^{2}\left(c_{1}^{2}c_{4}\alpha_{2}-1\right)
>0.\displaystyle>0.

Consequently, if (T1(σu,v),σu)=0\mathcal{F}\left(T_{1}(\sigma u,v),\sigma u\right)=0 for some |u||u|_{\infty} and |v|R|v|_{\infty}\leq R, then we necessarily have σσ0\sigma\leq\sigma_{0}. Thus, condition (h2) is verified.

Check of condition (h1). Let uK1{0}u\in K_{1}\setminus\{0\} and vDv\in D. From (H4), we see that the mapping

σ01(011σk1(t,θ)f(σu(θ),v(θ))𝑑θ)u(t)𝑑t01u2(t)𝑑t\sigma\mapsto\int_{0}^{1}\left(\int_{0}^{1}\frac{1}{\sigma}\,k_{1}(t,\theta)\,f\bigl(\sigma\,u(\theta),\,v(\theta)\bigr)\,d\theta\right)\,u(t)\,dt-\int_{0}^{1}u^{2}(t)\,dt

is strictly increasing. Therefore, corroborating this with (h2), we conclude that there exists a unique σ>0\sigma^{\ast}>0 such that

(T1(σu,v),σu)=0.\mathcal{F}\bigl(T_{1}(\sigma^{\ast}\,u,\,v),\,\sigma^{\ast}\,u\bigr)=0.

Thus, defining s(u,v):=σs(u,v):=\sigma^{\ast}, condition (h1) follows.

Remark 3.1 (Typical examples of function ff).

Let f1:f_{1}\colon\mathbb{R}\to\mathbb{R} be a continuous and positive function. Then the function

f(x,y)=|x|pf1(y),f(x,y)=|x|^{p}\,f_{1}(y),

with p>1p>1, satisfies conditions (H2)–(H4). The function gg can be any continuous function bounded by a constant as specified in (H5).

Remark 3.2.

Integral systems like (3.1) often arise from the reformulation of bi-local boundary value problems, where the kernels k1k_{1} and k2k_{2} correspond to Green’s functions [2]. For this class of problems, properties (3.2) and (3.3) are properties of the Green’s function (see, e.g., [5, 11]), where condition (3.3) is a Harnack-type inequality [11].


Acknowledgements The authors thank the reviewers for taking the time to read the manuscript and for their appreciations.
Author contributions Both authors have contributed equally to the preparation of this manuscript. Both authors read and approved the final manuscript.
Funding Authors did not receive any funding for this work.


Data Availability No datasets were generated or analyzed during the current study.
Declarations


Conflict of interest The authors have no relevant financial or non-financial interests to disclose.

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