Programmed motion for a class of families of planar orbits

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Mira-Cristiana Anisiu
Tiberiu Popoviciu Institute of Numerical Analysis Romanian Academy, Romania

George Bozis
Department of Physics, University of Thessalonikim GR-54006, Greece

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Anisiu MC., Bozis G., Programmed motion for a class of families of planar orbits, Inverse Problem, vol. 16., issue 1, 2000, pag. 19-32

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Programmed motion for a class of families of planar orbits

Mira-Cristiana Anisiu \dagger and George Bozis \ddagger
\dagger T Popoviciu Institute of Numerical Analysis, Romanian Academy, PO Box 68, 3400
Cluj-Napoca, Romania
\ddagger Department of Theoretical Mechanics, University of Thessaloniki, GR-540 06 Thessaloniki, Greece
E-mail: MIRA@MATH.UBBCLUJ.RO and GBOZIS@CCF.AUTH.GR
Abstract

Taking as a guide the case of the set of monoparametric families y=h(x)+cy=h(x)+c, for which Szebehely’s equation can be solved by quadratures for the potential V(x,y)V(x,y) generating the given set of orbits, we propose the following programmed motion problem: can we manage so as to have members of the given set inside a preassigned domain T2T\subset\mathbb{R}^{2} of the xyxy plane?
We come to understand that, among the various inequalities by means of which TT can be ascribed, the simplest is b(x,y)0b(x,y)\geqslant 0 where, for each h(x)h(x), the function b(x,y)b(x,y) is related to the kinetic energy of the moving point (equations (19)-(21)). We then proceed to show that, in general, if b(x,y)b(x,y) satisfies two conditions (equations (39) and (40)), the answer to our question is affirmative: on the grounds of the given appropriate b(x,y)b(x,y), a function h(x)h(x) is found, associated with a certain potential V(x,y)V(x,y) creating members of the family y=h(x)+cy=h(x)+c inside the region b(x,y)0b(x,y)\geqslant 0.
Some special cases which stem from the method are studied separately. The limitations and also the promising features of the method developed to face the above inverse problem are discussed.

Received 19 April 1999, in final form 23 November 1999

1. Introduction

The two-dimensional inverse problem of dynamics consists in finding a potential VV which generates a family of curves

f(x,y)=cf(x,y)=c (1)

in the xyxy Euclidean space. The roots of the problem are to be found in Newton’s Principia (1687) where a force law compatible with Kepler’s laws was deduced. Interest in this old problem increased after Szebehely [8] presented the partial differential equation

fxVx+fyVy2(E(f)V)fx2+fy2(fxxfy22fxyfxfy+fyyfx2)=0f_{x}V_{x}+f_{y}V_{y}-\frac{2(E(f)-V)}{f_{x}^{2}+f_{y}^{2}}\left(f_{xx}f_{y}^{2}-2f_{xy}f_{x}f_{y}+f_{yy}f_{x}^{2}\right)=0 (2)

where the subscripts denote partial derivatives. This linear in VV partial differential equation is our tool to find the potential V(x,y)V(x,y) which can produce as orbits a preassigned monoparametric family of curves (1), traced in the xyxy plane, with adequate initial conditions, by a material point of unit mass, with energy dependence

E=E(f(x,y))E=E(f(x,y)) (3)

given in advance.

In spite of its linear character, in practice, equation (2) cannot be solved analytically. Actually, its solvability is directly connected to the possibility of solving a (generally nonlinear) system of ordinary differential equations.

Additional assumptions regarding the form of either the known function f(x,y)f(x,y) or the unknown potential V(x,y)V(x,y) ease the solution of the problem. Thus, for example, for particular sets of functions ff (e.g., homogeneous in x,yx,y ) the compatibility with homogeneous (Bozis and Grigoriadou [1]) or nonhomogeneous (Bozis et al [4]) potentials was already studied.

In this framework, in the present paper a new special case is considered: that of the set of monoparametric families of curves with equation

y=h(x)+cy=h(x)+c (4)

where h(x)h(x) is a nonlinear (h′′(x)0\left(h^{\prime\prime}(x)\neq 0\right. ) function of xx. We consider functions hh defined on an interval where hh^{\prime} has no zeros. For every function h(x)h(x) equation (4) stands for a family of (equidistant) curves (not straight lines), shifted parallel to the yy-axis. It is shown that all potentials which can generate families of the form (4) can be found by quadratures.

On the other hand, it is known that during the motion of a material point of unit mass along an orbit of the family (1), the inequality

B(x,y)0B(x,y)\geqslant 0 (5)

must be observed, with

B=E(f(x,y))V(x,y).B=E(f(x,y))-V(x,y). (6)

This means that the motion is allowed along those members (or part of the members) of the family (1) which are lying only inside some regions of the xyxy plane, limited by the so-called family boundary curves (FBC) (Bozis and Ichtiaroglou [2]), which are given by the equation

B(x,y)=0.B(x,y)=0. (7)

The function B(x,y)B(x,y) is the kinetic energy (expressed in terms of the position coordinates x,y)x,y) of the material point of unit mass, as it moves on any of the orbits (4) in the presence of the potential V(x,y)V(x,y). We shall refer to it here as the BB-function and keep in mind that it is associated with the family (4), which, of course, can have infinitely many BB-functions. The merit of such a function lies in that, by preassigning to (4) a certain BB-function, we can manage to have conservative motion inside a preassigned region T2T\subset\mathbb{R}^{2} of the xyxy plane defined by inequality (5). We remind the reader that if force fields (not necessarily conservative) are demanded, in general, there exist such fields to create any preassigned family (1) inside any preassigned region TT (Bozis [3]).

The question raised and answered in this paper is the following: can any (positive in T2T\subset\mathbb{R}^{2} ) function stand for a BB-function? In other words: are there potentials V(x,y)V(x,y) generating orbits of the form (4) traced with preassigned kinetic energy (6) and, as a consequence, lying inside a preassigned region (5)? Which is the pertinent family (4) and which is the corresponding energy dependence E=E(f)E=E(f) ?

It turns out that, for every h(x)h(x), there exists a simpler (positive in TT ) function b(x,y)b(x,y), whose positiveness in TT implies the inequality (5). Due to its simplicity, we prefer to represent the FBC by b(x,y)=0b(x,y)=0 and we focus attention on the problem of obtaining compatible pairs of b(x,y)b(x,y) and h(x)h(x). We show that, if the given b(x,y)b(x,y) satisfies two conditions, the function h(x)h(x) (and, consequently, the family f(x,y)=yh(x)=cf(x,y)=y-h(x)=c ) as well as the energy dependence function E(f)E(f) and the potential V(x,y)V(x,y) are determined.

2. Determining the potentials which generate a special family of curves

For the case of the family of curves given by (4), equation (2) has the simpler form

hVxVy=2h′′1+h2(E(f)V),h^{\prime}V_{x}-V_{y}=\frac{2h^{\prime\prime}}{1+h^{\prime 2}}(E(f)-V), (8)

the prime denoting the derivative with respect to the xx variable, and, according to (1), f(x,y)=yh(x)f(x,y)=y-h(x). The subsidiary system of ordinary differential equations is

dxh=dy1=(1+h2)dV2h′′(E(f)V)\frac{\mathrm{d}x}{h^{\prime}}=\frac{\mathrm{d}y}{-1}=\frac{\left(1+h^{\prime 2}\right)\mathrm{d}V}{2h^{\prime\prime}(E(f)-V)} (9)

The first of equations (9) gives

y=c1I(x)y=c_{1}-I(x) (10)

where

I(x)=xdth(t)I(x)=\int^{x}\frac{\mathrm{~d}t}{h^{\prime}(t)} (11)

Equating the third to the first fraction in (9), we obtain a linear equation in VV which has to be solved after replacing yy appearing in the argument of EE by its expression in (10). So the argument of EE will be yh(x)=c1I(x)h(x)y-h(x)=c_{1}-I(x)-h(x), and the equation in VV will have the form
dVdx+2h′′(x)h(x)(1+h2(x))V2h′′(x)h(x)(1+h2(x))E(c1I(x)h(x))=0\frac{\mathrm{d}V}{\mathrm{~d}x}+\frac{2h^{\prime\prime}(x)}{h^{\prime}(x)\left(1+h^{\prime 2}(x)\right)}V-\frac{2h^{\prime\prime}(x)}{h^{\prime}(x)\left(1+h^{\prime 2}(x)\right)}E\left(c_{1}-I(x)-h(x)\right)=0.

The solution of the ordinary differential equation (12) is

V=1+h2(x)h2(x)[c2+K(x,c1)]V=\frac{1+h^{\prime 2}(x)}{h^{\prime 2}(x)}\left[c_{2}+K\left(x,c_{1}\right)\right] (13)

where

K(x,c1)=xE(c1I(s)h(s))2h(s)h′′(s)(1+h2(s))2dsK\left(x,c_{1}\right)=\int^{x}E\left(c_{1}-I(s)-h(s)\right)\frac{2h^{\prime}(s)h^{\prime\prime}(s)}{\left(1+h^{\prime 2}(s)\right)^{2}}\mathrm{~d}s

Integrating by parts the above integral KK, we get

K(x,c1)=11+h2(x)E(c1I(x)h(x))J(x,c1)K\left(x,c_{1}\right)=-\frac{1}{1+h^{\prime 2}(x)}E\left(c_{1}-I(x)-h(x)\right)-J\left(x,c_{1}\right) (14)

where

J(x,c1)=xEc(c1I(s)h(s))1h(s)dsJ\left(x,c_{1}\right)=\int^{x}E_{c}\left(c_{1}-I(s)-h(s)\right)\frac{1}{h^{\prime}(s)}\mathrm{d}s (15)

and where EcE_{c} denotes the derivative of the one-variable function E=E(c)E=E(c) with respect to its argument.

The general solution of the partial differential equation (8) is given by

c2=A(c1)c_{2}=A\left(c_{1}\right) (16)

with AA an arbitrary function of c1=y+I(x)c_{1}=y+I(x). So, for the family of curves (4) traced with a preassigned energy dependence E=E(c)E=E(c), the potentials creating it are given by

V(x,y)=1h2E¯+1+h2h2(A¯J¯),V(x,y)=-\frac{1}{h^{\prime 2}}\bar{E}+\frac{1+h^{\prime 2}}{h^{\prime 2}}(\bar{A}-\bar{J}), (17)

where we adopt the notation

E¯=E(c=yh),A¯=A(c1=y+I)J¯=J(x,c1=y+I)\begin{array}[]{ll}\bar{E}=E(c=y-h),&\bar{A}=A\left(c_{1}=y+I\right)\\ \bar{J}=J\left(x,c_{1}=y+I\right)&\end{array}

with the functions hh and II depending merely on xx.
Clearly, if we consider as given a function h(x)h(x) and select arbitrarily a function E(c)E(c), we can calculate the integrals II and JJ by quadratures from (11) and (15), respectively.

3. Family boundary curves ( 𝑩\boldsymbol{B}-functions and 𝒃\boldsymbol{b}-functions)

Real motion of the moving point takes place only on those members of the family of curves (1) or those parts of each member of the family which lie in the region of the xyxy plane where the inequality (5) is observed.

We proceed to find the pertinent FBC (7) for the specific set of families (4). As the corresponding potentials are given by (17), the function in (6) is found to be given by

B(x,y)=1+h2h2(E¯A¯+J¯)B(x,y)=\frac{1+h^{\prime 2}}{h^{\prime 2}}(\bar{E}-\bar{A}+\bar{J}) (19)

The meaning of (19) is the following: given a family (4), i.e. given a function h(x)h(x), after selecting specific arbitrary functions E(c)E(c) and A(c1)A\left(c_{1}\right), we can find the function B(x,y)B(x,y) and draw conclusions regarding the FBC.

Naturally, wherever B(x,y)0B(x,y)\geqslant 0, with B(x,y)B(x,y) given by (19), it is also

b(x,y)0b(x,y)\geqslant 0 (20)

with

b(x,y)=E¯A¯+J¯b(x,y)=\bar{E}-\bar{A}+\bar{J} (21)

and conversely. Thus, together with the BB-function, we have a simpler function b(x,y)b(x,y) which can serve to describe the FBC or, if given in advance, to create programmed motion inside a region. So, in what follows, we shall represent the preassigned allowed region by inequality (20). The same region, of course, could be represented by θ(x,y)b(x,y)0\theta(x,y)b(x,y)\geqslant 0, where θ(x,y)\theta(x,y) is any arbitrary non-negative function in TT (Bozis [3]).

On the grounds of the previous analysis we now pose the following question: consider a preassigned boundary function b=b(x,y)b=b(x,y), positive inside a region T2T\subset\mathbb{R}^{2} which we want to programme as an allowed region of some orbits (4). Can we find a function h(x)h(x), leading to appropriate functions E(c),A(c1)E(c),A\left(c_{1}\right) and J(x,c1)J\left(x,c_{1}\right), such that equation (21) is satisfied?

If the answer to the above question is in the affirmative, inside TT there exist members of the family (4). These are orbits, traced by the moving point for adequate initial conditions, in the presence of the potential (17) with kinetic energy equal to B(x,y)=1+h2h2b(x,y)B(x,y)=\frac{1+h^{\prime 2}}{h^{\prime 2}}b(x,y) at each point of the orbit.

4. Programmed motion: analysis

Consider a (positive in a region T2T\subset\mathbb{R}^{2} ) boundary function b(x,y)b(x,y) to account for our goal to obtain orbits of the form (4) inside the region TT. For this version of the inverse problem, suppose that there is an affirmative answer, i.e. there exists an appropriate function h(x)h(x) for which (21) can be satisfied.

Since the function AA depends on x,yx,y through c1c_{1}, it is

A¯yA¯x=c1,yc1,x\frac{\bar{A}_{y}}{\bar{A}_{x}}=\frac{c_{1,y}}{c_{1,x}}

and, in view of (10) and (11), it must be

A¯y=hA¯x\bar{A}_{y}=h^{\prime}\bar{A}_{x} (22)

We want to replace into (22) the function A¯=E¯+J¯b\bar{A}=\bar{E}+\bar{J}-b given by (21). To this end we prepare, in view of (3), (15) and (18),

E¯x=hEc,E¯y=Ec,J¯x=1hEc+1hJc1,J¯y=Jc1.\bar{E}_{x}=-h^{\prime}E_{c},\quad\bar{E}_{y}=E_{c},\quad\bar{J}_{x}=\frac{1}{h^{\prime}}E_{c}+\frac{1}{h^{\prime}}J_{c_{1}},\quad\bar{J}_{y}=J_{c_{1}}. (23)

In view of (23), the condition (22) is now written as

h2Ec=b01hb10h^{\prime 2}E_{c}=b_{01}-h^{\prime}b_{10} (24)

where b10b_{10} stands for bxb_{x} and b01b_{01} for byb_{y}. This notation is in agreement with the following more general convention which we adopt in what follows: we denote by bmn(m,nb_{mn}(m,n positive integers) the partial derivative of b(x,y)mb(x,y)m times with respect to xx and nn times with respect to yy.

Since h(x)0h^{\prime}(x)\neq 0, we denote 1h\frac{1}{h^{\prime}} by z=z(x)z=z(x) and we write equation (24) as

Ec=z2b01zb10E_{c}=z^{2}b_{01}-zb_{10} (25)

The simpler case of isoenergetic families of orbits (4), for which Ec=0E_{c}=0, will be treated separately in section 6 . In general, we know that EcE_{c} depends on x,yx,y through cc, given by equation (4): thus, cycx=1h\frac{c_{y}}{c_{x}}=-\frac{1}{h^{\prime}} and we find

(Ec)y+z(Ec)x=0\left(E_{c}\right)_{y}+z\left(E_{c}\right)_{x}=0 (26)

After some straightforward algebra, from (26) and (25) we obtain

b11z2+(b02b20)zb11=(b102b01z)zb_{11}z^{2}+\left(b_{02}-b_{20}\right)z-b_{11}=\left(b_{10}-2b_{01}z\right)z^{\prime} (27)

where z=dzdx(0z^{\prime}=\frac{\mathrm{d}z}{\mathrm{~d}x}\left(\neq 0\right. because h′′(x)0)\left.h^{\prime\prime}(x)\neq 0\right).
Condition (27) is free from the energy and (as we restrict ourselves to choose bb, and not θb\theta b, to represent the FBC) it is necessary and sufficient for our purpose to achieve programmed motion. As it stands, (27) relates the given boundary function b(x,y)b(x,y) (and up to second-order derivatives of it) to the function

z=1h(x)z=\frac{1}{h^{\prime}(x)} (28)

(and its derivative zz^{\prime} ).
To come to know zz and zz^{\prime}, we differentiate twice both members of (27) with respect to yy and we obtain the two equations

b12z2+(b03b21)zb12=(b112b02z)zb_{12}z^{2}+\left(b_{03}-b_{21}\right)z-b_{12}=\left(b_{11}-2b_{02}z\right)z^{\prime} (29)

and

b13z2+(b04b22)zb13=(b122b03z)zb_{13}z^{2}+\left(b_{04}-b_{22}\right)z-b_{13}=\left(b_{12}-2b_{03}z\right)z^{\prime} (30)

Assuming that b102b01z0b_{10}-2b_{01}z\neq 0 (the special case will be treated in section 6) and dividing (29) by (27), we obtain the cubic in zz algebraic equation

α3z3+α2z2+α1z+α0=0\alpha_{3}z^{3}+\alpha_{2}z^{2}+\alpha_{1}z+\alpha_{0}=0 (31)

with

α3=2(b02b11b01b12)\displaystyle\alpha_{3}=2\left(b_{02}b_{11}-b_{01}b_{12}\right)
α2=2b02(b02b20)2b01(b03b21)+b10b12b112\displaystyle\alpha_{2}=2b_{02}\left(b_{02}-b_{20}\right)-2b_{01}\left(b_{03}-b_{21}\right)+b_{10}b_{12}-b_{11}^{2} (32)
α1=2(b01b12b02b11)+b10(b03b21)b11(b02b20)\displaystyle\alpha_{1}=2\left(b_{01}b_{12}-b_{02}b_{11}\right)+b_{10}\left(b_{03}-b_{21}\right)-b_{11}\left(b_{02}-b_{20}\right)
α0=b112b10b12.\displaystyle\alpha_{0}=b_{11}^{2}-b_{10}b_{12}.

Now dividing (30) by (27) we obtain a second cubic

β3z3+β2z2+β1z+β0=0\beta_{3}z^{3}+\beta_{2}z^{2}+\beta_{1}z+\beta_{0}=0 (33)

with

β3=2(b03b11b01b13)\displaystyle\beta_{3}=2\left(b_{03}b_{11}-b_{01}b_{13}\right)
β2=2b03(b02b20)2b01(b04b22)+b10b13b11b12\displaystyle\beta_{2}=2b_{03}\left(b_{02}-b_{20}\right)-2b_{01}\left(b_{04}-b_{22}\right)+b_{10}b_{13}-b_{11}b_{12}
β1=2(b01b13b03b11)+b10(b04b22)b12(b02b20)\displaystyle\beta_{1}=2\left(b_{01}b_{13}-b_{03}b_{11}\right)+b_{10}\left(b_{04}-b_{22}\right)-b_{12}\left(b_{02}-b_{20}\right) (34)
β0=b11b12b10b13\displaystyle\beta_{0}=b_{11}b_{12}-b_{10}b_{13}

It can be checked easily that βi\beta_{i} can be obtained alternatively by differentiating each αi\alpha_{i} ( i=0,1,2,3i=0,1,2,3 ) with respect to yy. A problem may arise when all the αi\alpha_{i} are zero, so we cannot make use of equations (31) and (33). This case will be treated in section 6.

Equations (31) and (33) are necessary conditions for zz inherited from the unique necessary and sufficient condition (27) which we wish to satisfy, if this is possible, in the first place, with a z=z(x)z=z(x). So, if, for a given bb, such a zz does exist, this has to be the (at least one) common root of (31) and (33). Of course, for such a root to exist, a sixth-order determinant, called the resultant of the two polynomials in (31) and (33) (Mishina and Proskuryakov [7], p 164) must vanish identically. This requirement will lead to a (rather complicated) condition including derivatives of b(x,y)b(x,y) up to the fourth order. Yet, it is understood that we need not write down this condition. Instead, taking for granted that an appropriate z=z(x)z=z(x) to be put in (27) does exist and that this zz cannot be anything but the common root of (31) and (33), we proceed to find it as follows.

We multiply (31) by β3\beta_{3} and (33) by α3\alpha_{3} and subtract. Assuming that α2β3α3β20\alpha_{2}\beta_{3}-\alpha_{3}\beta_{2}\neq 0 (the special case will be treated in section 6), we obtain

z2=γ1z+γ0z^{2}=\gamma_{1}z+\gamma_{0} (35)

with

γ0=α0β3α3β0α3β2α2β3,γ1=α1β3α3β1α3β2α2β3\gamma_{0}=\frac{\alpha_{0}\beta_{3}-\alpha_{3}\beta_{0}}{\alpha_{3}\beta_{2}-\alpha_{2}\beta_{3}},\quad\quad\gamma_{1}=\frac{\alpha_{1}\beta_{3}-\alpha_{3}\beta_{1}}{\alpha_{3}\beta_{2}-\alpha_{2}\beta_{3}} (36)

In view of (35), we replace z3z^{3} into (31) by z3=(γ12+γ0)z+γ0γ1z^{3}=\left(\gamma_{1}^{2}+\gamma_{0}\right)z+\gamma_{0}\gamma_{1} and we find

δ1z+δ0=0\delta_{1}z+\delta_{0}=0 (37)

with

δ1=α3(γ12+γ0)+α2γ1+α1\displaystyle\delta_{1}=\alpha_{3}\left(\gamma_{1}^{2}+\gamma_{0}\right)+\alpha_{2}\gamma_{1}+\alpha_{1} (38)
δ0=α3γ0γ1+α2γ0+α0\displaystyle\delta_{0}=\alpha_{3}\gamma_{0}\gamma_{1}+\alpha_{2}\gamma_{0}+\alpha_{0}

We assume that δ10\delta_{1}\neq 0 (the special case δ1=0\delta_{1}=0 is examined in section 6) and we conclude by writing down the two conditions which the given function b(x,y)b(x,y) must satisfy:
(i) The function zz, found from (37), must depend only on the variable xx, i.e.

δ0,yδ1=δ0δ1,y\delta_{0,y}\delta_{1}=\delta_{0}\delta_{1,y} (39)

(ii) The function zz must satisfy the equation (27), i.e.

δ1{δ02b11(b02b20)δ0δ1b11δ12}=(δ1b10+2δ0b01)(δ0δ1,xδ0,xδ1)\delta_{1}\left\{\delta_{0}^{2}b_{11}-\left(b_{02}-b_{20}\right)\delta_{0}\delta_{1}-b_{11}\delta_{1}^{2}\right\}=\left(\delta_{1}b_{10}+2\delta_{0}b_{01}\right)\left(\delta_{0}\delta_{1,x}-\delta_{0,x}\delta_{1}\right) (40)

Clearly, if we expressed the above conditions (39) and (40) in terms of the given function b(x,y)b(x,y) only, there would appear partial derivatives of bb up to the fifth order.

5. Programmed motion: synthesis

We want to have monoparametric families of orbits of the form (4) ’inside’ a preassigned region T2T\subset\mathbb{R}^{2} given by inequality (20) with the given function b(x,y)b(x,y) to be defined as in (21).

In view of the analysis in section 4 and aided by a symbolic algebra program (e.g. MATHEMATICA) we proceed as follows:
(i) For the given b(x,y)b(x,y) we prepare its partial derivatives bijb_{ij} up to the fourth order and, from equations (32), (34), (36) and (38), we find all the functions αi,βi(i=0,1,2,3)\alpha_{i},\beta_{i}(i=0,1,2,3) and γk,δk(k=0,1)\gamma_{k},\delta_{k}(k=0,1). We make sure that

α2β3α3β20 and δ10\alpha_{2}\beta_{3}-\alpha_{3}\beta_{2}\neq 0\quad\text{ and }\quad\delta_{1}\neq 0 (41)

(Otherwise we act as in section 6.)
(ii) We prepare the partial derivatives δ0,x,δ0,y,δ1,x,δ1,y\delta_{0,x},\delta_{0,y},\delta_{1,x},\delta_{1,y} of the two functions δk(x,y)\delta_{k}(x,y) ( k=k= 0,1 ) and we check the conditions (39) and (40).

After the remark which follows we shall continue with our synthesis by assuming that we do have an appropriate bb-function at our disposal.

Remark. As a rule, of course, one does not expect the conditions (39) and (40) to be satisfied. Consequently, one cannot programme motion inside T2T\subset\mathbb{R}^{2}, described by the bb-function at hand. Yet, such an appropriate bb-function may be hidden! It may correspond to another selection of the function h(x)h(x) in equation (4) and, most likely, to different selections of the arbitrary functions EE and AA, as given by the equations (3) and (16).

One then may try to find a good bb-function. Thus, for example:

  • If bb is given with some free constants, one may try to determine these constants so that the conditions (39) and (40) are satisfied.

  • If this cannot be achieved, we may write (39) and (40) for bθb(x,y)b\rightarrow\theta b(x,y) and try to find even one (positive in TT ) particular solution θ0(x,y)\theta_{0}(x,y) satisfying these conditions. This assignment is far from being a simple task, of course.

Assuming that the given bb is appropriate, we now proceed as follows:
(iii) From (37) and (28) we find zz and hh^{\prime} and then, in turn, h(x)h(x) up to an additive constant h0h_{0}. Then, out of the set of orbits (4), we obtain the specific monoparametric family f(x,y)=yh(x)=cf(x,y)=y-h(x)=c. In general, the two equations (31) and (33) have one common root, so we obtain one family (4) for some members of which we can manage to have them trapped inside the preassigned region (20). To this end we must determine the appropriate potential.
(iv) From equation (25) we now determine EcE_{c} and, as we already know the expression for c=yh(x)c=y-h(x), we determine uniquely (apart from an additive constant E0E_{0} ) the energy dependence function (3) E=E(c)E=E(c) and, from the first of equations (18), we come to know E¯\bar{E}, into which the constants h0h_{0} and E0E_{0} will enter.
(v) Finally, since the kinetic energy is

B=1+h2h2b(x,y)B=\frac{1+h^{\prime 2}}{h^{\prime 2}}b(x,y) (42)

we write down the potential

V(x,y)=E¯BV(x,y)=\bar{E}-B (43)

which gives rise to orbits with equation (4) lying inside the region (20).

Comment. In spite of the fact that the two integration constants, h0h_{0} and E0E_{0} enter into (43) through E¯\bar{E}, the potential V(x,y)V(x,y) is essentially unique, at least as far as the study of the present family is concerned. Indeed, h0h_{0} and E0E_{0} appear in (43) either purely as an additive constant or through a combination which amounts to a (constant, again) additive arbitrary function V0(f)V_{0}(f), where f=yh(x)=cf=y-h(x)=c is the family under consideration. For these reasons we can set both h0h_{0} and E0E_{0} equal to zero and this is actually what we do in the example of section 7 .

6. Special cases

6.1. Isoenergetic families ( Ec=0E_{c}=0 )

Actually condition (26)-and consequently (27)-as it is written is valid for isoenergetic families, i.e. families of orbits all traced with the same (constant) value of the energy E0E_{0}. Yet the case needs to be treated separately in the sense that, as seen from (24), when Ec=0E_{c}=0, from the given bb-function we obtain immediately

h=b01b10h^{\prime}=\frac{b_{01}}{b_{10}} (44)

which is acceptable provided that

(b01b10)y=0\left(\frac{b_{01}}{b_{10}}\right)_{y}=0 (45)

or, equivalently,

b=b(c1)b=b\left(c_{1}\right) (46)

with c1=y+Ic_{1}=y+I and I=b10b01dxI=\int\frac{b_{10}}{b_{01}}\mathrm{~d}x.
Then the BB-function (42) is

B=b102+b012b012b¯B=\frac{b_{10}^{2}+b_{01}^{2}}{b_{01}^{2}}\bar{b}

where

b¯=b(c1=y+I(x))\bar{b}=b\left(c_{1}=y+I(x)\right)

and the potential is

V=E0b102+b012b012b¯V=E_{0}-\frac{b_{10}^{2}+b_{01}^{2}}{b_{01}^{2}}\bar{b} (47)

The meaning of the above reasoning is the following: given a boundary function b(x,y)b(x,y) which satisfies (45), we can directly obtain from (44) hh^{\prime} and from (11) I(x)I(x), then c1=y+Ic_{1}=y+I and check that the given bb is of the form (46). The family of orbits yh(x)=cy-h(x)=c is traced isoenergetically with energy E0E_{0} by the potential (47).

Thus, e.g., given b=yx2b=y-x^{2}, we find h=12x,h(x)=12lnx,x>0,I=x2h^{\prime}=-\frac{1}{2x},h(x)=-\frac{1}{2}\ln x,x>0,I=-x^{2}, c1=yx2,b¯=yx2c_{1}=y-x^{2},\bar{b}=y-x^{2} and V=(1+4x2)(yx2)V=-\left(1+4x^{2}\right)\left(y-x^{2}\right).

The isoenergetic family is y+12lnx=cy+\frac{1}{2}\ln x=c, traced with E0=0E_{0}=0, by the potential VV.

6.2. The case b102b01z=0b_{10}-2b_{01}z=0

Having

z=b102b01z=\frac{b_{10}}{2b_{01}} (48)

we must also zero the left-hand side of equation (27). This leads to

b11b102+2b01b10(b02b20)=4b012b11b_{11}b_{10}^{2}+2b_{01}b_{10}\left(b_{02}-b_{20}\right)=4b_{01}^{2}b_{11} (49)

Since (b10b01)y=0\left(\frac{b_{10}}{b_{01}}\right)_{y}=0, we have

b=F(y+ι(x))b=F(y+\iota(x)) (50)

where FF is an arbitrary function of its argument y+ιy+\iota and ι=b10b01dx\iota=\int\frac{b_{10}}{b_{01}}\mathrm{~d}x.

Inserting (50) into (49) we obtain after some algebra

F′′F=2ι′′ι2+2=k0\frac{F^{\prime\prime}}{F^{\prime}}=-\frac{2\iota^{\prime\prime}}{\iota^{\prime 2}+2}=k_{0} (51)

where primes in FF and ι\iota denote differentiation with respect to their respective arguments y+ιy+\iota and xx and where the constant k0k_{0} was put to make equal the two functions of different argument.

Solving the two equations (51) we find

b=c1ek0ycos22c2k0x2b=c_{1}^{*}\mathrm{e}^{k_{0}y}\cos^{2}\frac{2c_{2}^{*}-k_{0}x}{\sqrt{2}} (52)

where c1,c2c_{1}^{*},c_{2}^{*} are integration constants. Then, in turn, from (48) we find zz, from (28) we find h(x)h^{\prime}(x) and, integrating it, h(x)h(x) and from (4) we find the family

y+1k0ln(sin22c2k0x2)=c.y+\frac{1}{k_{0}}\ln\left(\sin^{2}\frac{2c_{2}^{*}-k_{0}x}{\sqrt{2}}\right)=c. (53)

From (25) we find EcE_{c} and then the energy

E=12c1ek0cE=-\frac{1}{2}c_{1}^{*}\mathrm{e}^{k_{0}c} (54)

with which each member of the family (53) is traced.
Finally, from (43) we find the potential

V(x,y)=c1ek0y.V(x,y)=-c_{1}^{*}\mathrm{e}^{k_{0}y}. (55)

It is worth noticing that, since b(x,y)0b(x,y)\geqslant 0 everywhere or nowhere (depending on the sign of c1c_{1}^{*} ), orbits (53) exist everywhere or nowhere in the xyxy plane.
6.3. The case αi=0(i=0,1,2,3)\alpha_{i}=0(i=0,1,2,3)

In this case we have not at our disposal the polynomial equations (31) and (33), so we are obliged to consider only the differential equation (27). However, if all the coefficients αi=0\alpha_{i}=0 ( i=0,1,2,3i=0,1,2,3 ) are zero, the function bb must have some particular expressions which we are going to find.

Equating to zero α3\alpha_{3} and α0\alpha_{0} we get

b02b11b01b12=0\displaystyle b_{02}b_{11}-b_{01}b_{12}=0 (56)
b112b10b12=0\displaystyle b_{11}^{2}-b_{10}b_{12}=0 (57)

(i) If b11=0b_{11}=0, it follows that bb is a sum of two functions, one in the variable xx and the other in yy. Replacing it in the equations α1=0\alpha_{1}=0 and α2=0\alpha_{2}=0 we get only two possibilities for bb (apart from an additive constant):

b=my+g(x),m,b=r(x2+y2)+py+qx,r,p,q,r0.\begin{array}[]{ll}b=my+g(x),&m\in\mathbb{R},\\ b=r\left(x^{2}+y^{2}\right)+py+qx,&r,p,q\in\mathbb{R},\quad r\neq 0.\end{array}

In fact, bb can be also given as b=akeky,a,k,k0b=\frac{a}{k}\mathrm{e}^{ky},a,k\in\mathbb{R},k\neq 0, which is a special case of (60) below.
(ii) If b110b_{11}\neq 0, from (56) we get (b01b11)y=0\left(\frac{b_{01}}{b_{11}}\right)_{y}=0, hence b01=C(x)b11b_{01}=C(x)b_{11}; from (57), (b10b11)y=0\left(\frac{b_{10}}{b_{11}}\right)_{y}=0, hence b10=D(x)b11b_{10}=D(x)b_{11}. It follows b01b10=C(x)D(x)\frac{b_{01}}{b_{10}}=\frac{C(x)}{D(x)}; so b=U(y+D(x)C(x)dx)b=U\left(y+\int\frac{D(x)}{C(x)}\mathrm{d}x\right). Replacing in (56) we obtain

U′′U=1D(x)=k\frac{U^{\prime\prime}}{U^{\prime}}=\frac{1}{D(x)}=k

so

b=c0kekyekG(x),c0,k,k0,G an arbitrary function, b=\frac{c_{0}}{k}\mathrm{e}^{ky}\mathrm{e}^{kG(x)},\quad c_{0},k\in\mathbb{R},\quad k\neq 0,\quad G\text{ an arbitrary function, } (60)

this special expression of bb also making α1\alpha_{1} and α2\alpha_{2} vanish in equation (31).

For the three cases (58)-(60) we analyse equation (27).
Consider first b=my+g(x)b=my+g(x). In this case (27) becomes

g′′z=(g2mz)z-g^{\prime\prime}z=\left(g^{\prime}-2mz\right)z^{\prime}

with the solution z(x)=12m(g±g24mc0)z(x)=\frac{1}{2m}\left(g^{\prime}\pm\sqrt{g^{\prime 2}-4mc_{0}^{*}}\right), giving Ec=c0E_{c}=-c_{0}^{*} and E(c)=c0cE(c)=-c_{0}^{*}c.
For bb given by (59), equation (27) has no nonconstant solution zz independent of yy.
For bb given by (60) we obtain from equation (27) a differential equation in zz with coefficients depending only on xx, having the form

kGz2+(kkG2G′′)zkG=(G2z)zkG^{\prime}z^{2}+\left(k-kG^{2}-G^{\prime\prime}\right)z-kG^{\prime}=\left(G^{\prime}-2z\right)z^{\prime} (61)

As an example consider G(x)=G0=G(x)=G_{0}= const for which G=G′′=0G^{\prime}=G^{\prime\prime}=0. Then (61) becomes kz=2zzkz=-2zz^{\prime}, so z=k2xz=-\frac{k}{2}x and h=2klnxh=-\frac{2}{k}\ln x. Hence for b=d0kekyb=\frac{d_{0}}{k}\mathrm{e}^{ky}, where d0=c0ekG0d_{0}=c_{0}\mathrm{e}^{kG_{0}}, we have Ec=d0k24ekyx2=d0k24ekcE_{c}=\frac{d_{0}k^{2}}{4}\mathrm{e}^{ky}x^{2}=\frac{d_{0}k^{2}}{4}\mathrm{e}^{kc} and E=d0k4ekc,V=d0kekyE=\frac{d_{0}k}{4}\mathrm{e}^{kc},V=-\frac{d_{0}}{k}\mathrm{e}^{ky}.
6.4. The case α2β3α3β2=0\alpha_{2}\beta_{3}-\alpha_{3}\beta_{2}=0

Apparently, in this case, the task of finding the common roots of equations (31) and (33) becomes easier. Suppose then that we do have such a ( yy-independent) root z=z(x)z=z(x). We proceed and check if the condition (27) is valid. If so, with this appropriate zz we find successfully: the function h(x)h(x) (from equation (28)), the energy dependence E=E(f)E=E(f) (from (25)), the function BB (from (42)) and, finally, the potential V(x,y)V(x,y) (from equation (43)).

As an example consider as given the bb-function on (,0)(-\infty,0) or (0,+)(0,+\infty) :

b=1x4+x222yx2.b=\frac{1}{x^{4}}+\frac{x^{2}}{2}-\frac{2y}{x^{2}}. (62)

From (32) and (34) we find: α3=0,α2=32x6,α1=162+x6x9,α0=16x6\alpha_{3}=0,\alpha_{2}=\frac{32}{x^{6}},\alpha_{1}=16\frac{2+x^{6}}{x^{9}},\alpha_{0}=\frac{16}{x^{6}} and β3=β2=β1=β0=0\beta_{3}=\beta_{2}=\beta_{1}=\beta_{0}=0.

Out of the two roots of the quadratic α2z2+α1z+α0=0\alpha_{2}z^{2}+\alpha_{1}z+\alpha_{0}=0, only the root z=x32z=-\frac{x^{3}}{2} satisfies the condition (27). This zz leads to h=1x2,y=1x2+c,E=c2h=\frac{1}{x^{2}},y=\frac{1}{x^{2}}+c,E=c^{2} and to the potential

V(x,y)=18(6(2y2x2)(x42y)2).V(x,y)=\frac{1}{8}\left(6\left(2y^{2}-x^{2}\right)-\left(x^{4}-2y\right)^{2}\right). (63)

It is understood that only those members or parts of members of the family

y1x2=cy-\frac{1}{x^{2}}=c (64)

are actually traced by the potential (63) which lies in the nonshaded region of figure 1,

yx44+12x2,y\leqslant\frac{x^{4}}{4}+\frac{1}{2x^{2}},

where the curves with c=3,2,,2c=-3,-2,\ldots,2 are displayed.
6.5. The case δ1=0\delta_{1}=0

If δ1=0\delta_{1}=0 and δ00\delta_{0}\neq 0, equation (37) has no solution, hence we cannot determine a family of orbits in the region b(x,y)0b(x,y)\geqslant 0. If δ1=0\delta_{1}=0 and δ0=0\delta_{0}=0, equation (37) is an identity and one can use, for example, equation (35) to determine the common root of (31) and (33).

Thus, given b=ex+y+xyb=\mathrm{e}^{x+y}+xy, we have α2β3α3β20\alpha_{2}\beta_{3}-\alpha_{3}\beta_{2}\neq 0, so that the case cannot be treated as in subsection 6.4. For this specific function bb (for which the equation b=0b=0 is equivalent with y=y=- Lambert W(exx)\mathrm{W}\left(\frac{\mathrm{e}^{x}}{x}\right) on the interval x>0x>0 ), one has δ1=δ0=0\delta_{1}=\delta_{0}=0. Equation (35) becomes z2=1z^{2}=1, hence in this case a nonlinear hh cannot be obtained.

Refer to caption
Figure 1: Figure 1. The twelve (symmetric in pairs with respect to the yy-axis) unbounded curves y=1/x2+cy=1/x^{2}+c (for c=3,2,1,0,1,2c=-3,-2,-1,0,1,2 ) are real orbits, created by the potential (63) and traced in the nonshaded region of the figure.

7. An example for the general case

For x>0x>0, let us start with the bb-function

b=b2y2+b1y+b0b=b_{2}y^{2}+b_{1}y+b_{0} (65)

with

b2=3x\displaystyle b_{2}=-\frac{3}{x}
b1=3x2(x4+1)\displaystyle b_{1}=\frac{3}{x^{2}}\left(x^{4}+1\right) (66)
b0=1x3(3x4(x45+1)+1)\displaystyle b_{0}=-\frac{1}{x^{3}}\left(3x^{4}\left(\frac{x^{4}}{5}+1\right)+1\right)

We want to check if families of the form (4) exist inside the (nonshaded) region of figure 2, given by b(x,y)0b(x,y)\geqslant 0, which we engage as the allowed region for such families.

According to the procedure exposed in section 5, we write down the equations (31) and (33) and see first if they possess any yy-independent common roots. The coefficients αi,βi\alpha_{i},\beta_{i}, found from (32) and (34), are (apart from unimportant multiplicative factors)

α3=2x4(3x41)\displaystyle\alpha_{3}=-2x^{4}\left(3x^{4}-1\right)
α2=x2(3x2y22x(3x4+1)y3(3x85x4+1))\displaystyle\alpha_{2}=x^{2}\left(3x^{2}y^{2}-2x\left(3x^{4}+1\right)y-3\left(3x^{8}-5x^{4}+1\right)\right)
α1=x2(3x4+1)y22x(3x8+1)y(3x1216x8+6x41)\displaystyle\alpha_{1}=x^{2}\left(3x^{4}+1\right)y^{2}-2x\left(3x^{8}+1\right)y-\left(3x^{12}-16x^{8}+6x^{4}-1\right)
α0=x2(x2y2+2x(x41)y+(3x83x4+1))\displaystyle\alpha_{0}=x^{2}\left(x^{2}y^{2}+2x\left(x^{4}-1\right)y+\left(3x^{8}-3x^{4}+1\right)\right)
Refer to caption
Figure 2: Figure 2. The six bounded curves y=1/x+cy=1/x+c (for c=3,4,5,6,7,8c=3,4,5,6,7,8 ) in the nonshaded region of the figure are real orbits (librational motion), created by the potential (68).

and

β3=0\displaystyle\beta_{3}=0
β2=x2(3xy+(3x4+1))\displaystyle\beta_{2}=x^{2}\left(-3xy+\left(3x^{4}+1\right)\right)
β1=x(3x4+1)y+(3x8+1)\displaystyle\beta_{1}=-x\left(3x^{4}+1\right)y+\left(3x^{8}+1\right)
β0=x2(xy+(x41)).\displaystyle\beta_{0}=-x^{2}\left(xy+\left(x^{4}-1\right)\right).

Out of the two roots z=x2z=-x^{2} and z=xy+(x41)x2(3xy+3x4+1)z=\frac{xy+\left(x^{4}-1\right)}{x^{2}\left(-3xy+3x^{4}+1\right)} of equation (33), only the first root is yy-independent and this root happens to satisfy the equation (31) also. In this case α2β3α3β20\alpha_{2}\beta_{3}-\alpha_{3}\beta_{2}\neq 0 and the root z=x2z=-x^{2} can be obtained directly from (37), conditions (39) and (40) being fulfilled. So, we continue with z=x2z=-x^{2} and check the second condition (equation (27)) for our problem to admit of an affirmative answer. For the case at hand, (27) is indeed satisfied.

Now, from (28) we find h=1xh=\frac{1}{x} and from (4) we find the family of orbits

y1x=c,y-\frac{1}{x}=c, (67)

inside the nonshaded region of figure 2 being traced the curves with c=3,4,,8c=3,4,\ldots,8.
From (25) we find Ec=3(xy1)2x2E_{c}=\frac{3(xy-1)^{2}}{x^{2}} and, having cc at our disposal, we understand that Ec=3c2E_{c}=3c^{2}, i.e. E=c3E=c^{3}, giving E¯=(y1x)3\bar{E}=\left(y-\frac{1}{x}\right)^{3}.

From (42) we find the kinetic energy BB and, finally, from (43) we find the potential

V(x,y)=y3+3x3y23x2(x4+2)y+15x(3x8+18x4+20).V(x,y)=y^{3}+3x^{3}y^{2}-3x^{2}\left(x^{4}+2\right)y+\frac{1}{5}x\left(3x^{8}+18x^{4}+20\right). (68)

We conclude that, in the presence of the potential (68) and for adequate initial conditions, members of the family (67) can be traced, but only branches (like the arc AB for c=3c=3 in figure 2) on which motion is librational.

8. Concluding remarks

According to Galiullin [5], dynamical systems with programmed (or controlled) motion ’are solved in such a way that the process occurring in these systems satisfies some preset requirements’.

The dynamical system here is as simple as one material point moving in the presence of an autonomous two-dimensional potential V(x,y)V(x,y). In Galiullin’s terminology, the ’programme of the motion’ consists of two elements: (i) the material point moves on a curve with preassigned equation and (ii) the totality of such motions takes place in a preassigned region of the xyxy plane.

The equation of the orbits is of the (very special, indeed) form (4). For this form, Szebehely’s equation is solvable by quadratures, for any function h(x)h(x). For any specific h(x)h(x), as many potentials as two arbitrary functions introduce can generate the monoparametric family (4). In fact, to each selection of the arbitrary functions there correspond different families (4) in the sense that their members exist as real orbits inside different regions of the xyxy plane.

So now, in this paper and for this particular solvable inverse problem, we preassign the allowed region also. We effectuate this, essentially by preassigning a positive function b(x,y)b(x,y), related to the (positive) kinetic energy B(x,y)B(x,y) of the moving point and such that its positiveness implies that the preassigned region is allowed.

To the above additional requirement the system may not respond positively and, in fact, this is what generally happens. We prove, however, that if the given function b(x,y)b(x,y) satisfies certain conditions, there is an affirmative answer to our problem. Once this is assured, in general, we are led to a unique specification of the basic data of the motion: i.e., (i) the equation of the family (4), (ii) the energy dependence function and (iii) the potential V(x,y)V(x,y) creating the family.

It is true that the method developed in sections 4 and 5 and all the pertinent formulae refer exclusively to the set of families of orbits (4) for which we cannot offer a convincing motivation of physical nature but which we selected on grounds of simplicity, i.e. because for such sets of families we can write down an analytic expression (17) for the potentials. Yet, in the framework of the inverse problem of dynamics, questions of this sort are interesting. In fact, the reasoning followed in sections 4 and 5 may be adjusted to include similar solvable cases of Szebehely’s equation (Grigoriadou et al [6]).

A displeasing feature of the method presented is the inherent difficulty of having infinitely many ways of representing analytically a preassigned region TT. Out of all these we dealt only with what we defined as the bb-function. We mentioned, however, that more generally we are led to a (hard to deal with) problem of solving a partial differential equation. So or otherwise, the calculations involved even in the present version of the problem are almost impossible to be carried out without the help of a program of symbolic algebra.

Finally, let us note a good feature of equations (39) and (40), which generally constitute the criteria to be satisfied by the given function b(x,y)b(x,y) : for homogeneous in x,ybx,yb-functions, they are behaving homogeneously. This can be seen easily from the formulae (38), (36), (34) and (32).

Acknowledgment

The research of MCA was supported in part by the Romanian Academy (GAR 96/1999).

References

[1] Bozis G and Grigoriadou S 1993 Celest. Mech. 57461
[2] Bozis G and Ichtiaroglou S 1994 Celest. Mech. 58371
[3] Bozis G 1996 Proc. 2nd Hellenic Astronomical Conf. (Thessaloniki, June-July 1995) ed M E Contadakis et al p 587
[4] Bozis G, Anisiu M-C and Blaga C 1997 Astron. Nachr. 318313
[5] Galiullin A S 1984 Inverse Problem of Dynamics (Moscow: Mir) p 91
[6] Grigoriadou S, Bozis G and Elmabsout B 1999 Solvable cases of Szebehely’s equation Celest. Mech. 74211
[7] Mishina A P and Proskuryakov I V 1965 Higher Algebra (Oxford: Pergamon) p 164
[8] Szebehely V 1974 Proc. Int. Meeting on the Earth’s Rotations by Satellite Observations ed E Proverbio (Bologna: University of Caligari) p 31

2000

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