A viscoelastic contact problem with adhesion and surface memory effects

Abstract

We consider a mathematical model which describes the quasistatic contact between a viscoelastic body and an obstacle, the so-called foundation. The material’s behavior is modelled with a constitutive law with long memory. The contact is with normal compliance, unilateral constraint, memory effects and adhesion. We present the classical formulation of the problem, then we derive its variational formulation and prove an existence and uniqueness result. The proof is based on arguments of variational inequalities and fixed point.

Authors

Mircea Sofonea
(Laboratoire de Mathématiques et Physique, Université de Perpignan)

Flavius Patrulescu
(Tiberiu Popoviciu Institute of Numerical Analysis, Romanian Academy)

Keywords

existence, fixed point, mathematical model

Cite this paper as

M. Sofonea, F. Pătrulescu, A viscoelastic contact problem with adhesion and surface memory effects, Math. Model. Anal., vol. 19, no. 5 (2014), pp. 607-626

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Vilnius Gediminas Technical University, Vilnius; Taylor & Francis, Abingdon, Oxfordshire

DOI

10.3846/13926292.201

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1392-6292

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1648-3510

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3281333

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A viscoelastic contact problem with adhesion and surface memory effects

M. Sofonea 1, F. Pătrulescu 2
1 Laboratoire de Mathématiques et Physique
Université de Perpignan, 52 Avenue de Paul Alduy, 66860 Perpignan, France
2 Tiberiu Popoviciu Institute of Numerical Analysis
P.O. Box 68-1, 400110 Cluj-Napoca, Romania
Abstract

We consider a mathematical model which describes the quasistatic contact between a viscoelastic body and an obstacle, the so-called foundation. The material’s behavior is modelled with a constitutive law with long memory. The contact is with normal compliance, unilateral constraint, memory effects and adhesion. We present the classical formulation of the problem, then we derive its variational formulation and prove an existence and uniqueness result. The proof is based on arguments of variational inequalities and fixed point.

2010 Mathematics Subject Classification : 74M15, 74G25, 74G30, 74D05, 49J40
Keywords: existence, fixed point, mathematical model

1 Introduction

Processes of contact with adhesion are important in many industrial settings where parts, usually nonmetallic, are glued together. For this reason, a considerable effort has been made in their modeling, analysis, numerical analysis, and numerical simulations and, as a result, the engineering and computational literature on this related topics is extensive. Moreover, the mathematical literature devoted to the analysis of adhesive contact process is rapidly growing.

General models with adhesion can be found in [7, 8, 9, 15, 18, and the references therein. In particular, a description of the derivation of various equations and conditions related to the adhesive contact can be found in [9]. The analysis of various contact models with adhesion, including existence and uniqueness results for weak solutions, can be found in [1, 2, 3, 4, 20, 26, 25, for instance. In carrying out this analysis, a systematic use of results on elliptic and evolutionary variational inequalities, convex analysis, nonlinear equations with monotone operators, and fixed points of operators was made. The numerical analysis of quasistatic and dynamic models of adhesive contact can be found in [20]. There, fully discrete schemes were considered and error estimates were derived. Moreover, an application of the theory in the medical field of prosthetic limbs was described in [16, 17. There, the bonding arises between the artificial limb and the tissue and is of considerable importance, since debonding may lead to decrease in the person’s ability to use the limb. The main ingredient in the models presented in all the above mentioned papers is the introduction of a surface internal variable, the bonding field, which describes the fractional density of active bonds on the contact surface. As a fraction its values are restricted to 0≤β≤10\leq\beta\leq 1. When β=1\beta=1 at a point of the contact surface, the adhesion is complete and all the bonds are active; when β=0\beta=0 all the bonds are inactive, severed, and there is no adhesion; finally, when 0<β<10<\beta<1 the adhesion is partial and only a fraction β\beta of the bonds is active.

In this paper, we cover the modelling and variational analysis of a new contact problem with adhesion within the infinitesimal strain theory. The evolution of the bonding field is described by a general first order ordinary differential equation, already used in the previously cited papers. Nevertheless, we introduce three novelties in the contact model, which make the difference with our previous papers. First, we describe material’s behavior by a viscoelastic constitutive law with long memory. Second, we model the adhesive contact with a normal compliance condition with unilateral penetration which takes into account the memory effect of the surfaces. A similar condition was introduced in [23, 24] in the study of frictionless contact process without adhesion. Also, a contact condition with normal compliance, unilateral constraint and adhesion was used in [11. There, in contrast with this paper, the memory effects of the foundation were neglected, the process was assumed to be dynamic and the material’s behavior was described with an elastic-visco-plastic constitutive law. The third novelty arises in the fact that, unlike a large number of references, the adhesive contact problem considered in this paper are formulated on the unbounded interval of time ℝ+=[0,∞)\mathbb{R}_{+}=[0,\infty). This implies the use of the framework of Fréchet spaces of continuous functions, instead of that of the classical Banach spaces of continuous functions defined on a bounded interval of time, used in our previous papers.

The rest of the paper is organized as follows. In Section 2 we introduce some notations and preliminary material. In Section 3 we provide a detailed description of the model of adhesive contact. Then, in Section 4, we list the assumptions on the data, derive the variational formulation of the problem and state our main existence
and uniqueness result, Theorem 4.1. The proof is provided in Section 5. It is based on arguments of variational inequalities and fixed point.

2 Notations and Preliminaries

In this short section we present the notations we shall use and some preliminary material. For further details we refer the reader to [10, 18, 22]. Everywhere in this paper we use the notation ℕ\mathbb{N} for the set of positive integers and ℝ+\mathbb{R}_{+}will represent the set of nonnegative real numbers, i.e. ℝ+=[0,+∞)\mathbb{R}_{+}=[0,+\infty). For a given r∈ℝr\in\mathbb{R} we denote by r+r^{+}its positive part, i.e. r+=max⁡{r,0}r^{+}=\max\{r,0\}. Let d∈ℕd\in\mathbb{N}. Then, we denote by 𝕊d\mathbb{S}^{d} the space of second order symmetric tensors on ℝd\mathbb{R}^{d}. The inner product and norm on ℝd\mathbb{R}^{d} and 𝕊d\mathbb{S}^{d} are defined by

𝒖⋅𝒗=ui​vi,‖𝒗‖=(𝒗⋅𝒗)12∀𝒖,𝒗∈ℝd𝝈⋅𝝉=σi​j​τi​j,‖𝝉‖=(𝝉⋅𝝉)12∀𝝈,𝝉∈𝕊d\begin{array}[]{lrrl}\boldsymbol{u}\cdot\boldsymbol{v}=u_{i}v_{i},&\|\boldsymbol{v}\|=(\boldsymbol{v}\cdot\boldsymbol{v})^{\frac{1}{2}}&\forall\boldsymbol{u},\boldsymbol{v}\in\mathbb{R}^{d}\\ \boldsymbol{\sigma}\cdot\boldsymbol{\tau}=\sigma_{ij}\tau_{ij},&\|\boldsymbol{\tau}\|=(\boldsymbol{\tau}\cdot\boldsymbol{\tau})^{\frac{1}{2}}&\forall\boldsymbol{\sigma},\boldsymbol{\tau}\in\mathbb{S}^{d}\end{array}

Here and below the indices i,j,k,li,j,k,l run between 1 and dd and, unless stated otherwise, the summation convention over repeated indices is used.

Let Ω\Omega be a bounded domain Ω⊂ℝd​(d=1,2,3)\Omega\subset\mathbb{R}^{d}(d=1,2,3) with a Lipschitz continuous boundary Γ\Gamma and let Γ1\Gamma_{1} be a measurable part of Γ\Gamma such that meas (Γ1)>0\left(\Gamma_{1}\right)>0. We use the notation 𝒙=(xi)\boldsymbol{x}=\left(x_{i}\right) for a typical point in Ω∪Γ\Omega\cup\Gamma and we denote by 𝝂=(νi)\boldsymbol{\nu}=\left(\nu_{i}\right) the outward unit normal at Γ\Gamma. Also, an index that follows a comma represents the partial derivative with respect to the corresponding component of the spatial variable, e.g. ui,j=∂ui/∂xju_{i,j}=\partial u_{i}/\partial x_{j}. We use standard notations for the Lebesgue and Sobolev spaces associated to Ω\Omega and Γ\Gamma and, moreover, we consider the spaces

V={𝒗=(vi)∈H1​(Ω)d:𝒗=𝟎​ on ​Γ1}\displaystyle V=\left\{\boldsymbol{v}=\left(v_{i}\right)\in H^{1}(\Omega)^{d}:\boldsymbol{v}=\mathbf{0}\text{ on }\Gamma_{1}\right\}
Q={𝝉=(τi​j)∈L2​(Ω)d×d:τi​j=τj​i}\displaystyle Q=\left\{\boldsymbol{\tau}=\left(\tau_{ij}\right)\in L^{2}(\Omega)^{d\times d}:\tau_{ij}=\tau_{ji}\right\}

These are real Hilbert spaces endowed with the inner products

(𝒖,𝒗)V=∫Ω𝜺​(𝒖)⋅𝜺​(𝒗)​𝑑x,(𝝈,𝝉)Q=∫Ω𝝈⋅𝝉​𝑑x(\boldsymbol{u},\boldsymbol{v})_{V}=\int_{\Omega}\boldsymbol{\varepsilon}(\boldsymbol{u})\cdot\boldsymbol{\varepsilon}(\boldsymbol{v})dx,\quad(\boldsymbol{\sigma},\boldsymbol{\tau})_{Q}=\int_{\Omega}\boldsymbol{\sigma}\cdot\boldsymbol{\tau}dx

and the associated norms ∥⋅∥V\|\cdot\|_{V} and ∥⋅∥Q\|\cdot\|_{Q}, respectively. Here 𝜺\boldsymbol{\varepsilon} represents the deformation operator given by

𝜺​(𝒗)=(εi​j​(𝒗)),εi​j​(𝒗)=12​(vi,j+vj,i)∀𝒗∈H1​(Ω)d.\boldsymbol{\varepsilon}(\boldsymbol{v})=\left(\varepsilon_{ij}(\boldsymbol{v})\right),\quad\varepsilon_{ij}(\boldsymbol{v})=\frac{1}{2}\left(v_{i,j}+v_{j,i}\right)\quad\forall\boldsymbol{v}\in H^{1}(\Omega)^{d}.

Completeness of the space ( V,∥⋅∥VV,\|\cdot\|_{V} ) follows from the assumption meas ( Γ1\Gamma_{1} ) >0>0, which allows the use of Korn’s inequality.

For an element 𝒗∈V\boldsymbol{v}\in V we still write 𝒗\boldsymbol{v} for the trace of 𝒗\boldsymbol{v} on the boundary Γ\Gamma. We denote by vνv_{\nu} and 𝒗τ\boldsymbol{v}_{\tau} the normal and the tangential component of 𝒗\boldsymbol{v} on Γ\Gamma, respectively,
defined by vν=𝒗⋅𝝂,𝒗τ=𝒗−vν​𝝂v_{\nu}=\boldsymbol{v}\cdot\boldsymbol{\nu},\quad\boldsymbol{v}_{\tau}=\boldsymbol{v}-v_{\nu}\boldsymbol{\nu}. Let Γ3\Gamma_{3} be a measurable part of Γ\Gamma. Then, by the Sobolev trace theorem, there exists a positive constant c0c_{0} which depends on Ω\Omega, Γ1\Gamma_{1} and Γ3\Gamma_{3} such that

‖𝒗‖L2​(Γ3)d≤c0​‖𝒗‖V∀𝒗∈V.\|\boldsymbol{v}\|_{L^{2}\left(\Gamma_{3}\right)^{d}}\leq c_{0}\|\boldsymbol{v}\|_{V}\quad\forall\boldsymbol{v}\in V. (2.1)

For a regular function 𝝈:Ω∪Γ→𝕊d\boldsymbol{\sigma}:\Omega\cup\Gamma\rightarrow\mathbb{S}^{d} we denote by σν\sigma_{\nu} and 𝝈τ\boldsymbol{\sigma}_{\tau} the normal and the tangential components of the vector 𝝈​𝝂\boldsymbol{\sigma}\boldsymbol{\nu} on Γ\Gamma, respectively, and we recall that σν=𝝈​𝝂⋅𝝂\sigma_{\nu}=\boldsymbol{\sigma}\boldsymbol{\nu}\cdot\boldsymbol{\nu} and 𝝈τ=𝝈​𝝂−σν​𝝂\boldsymbol{\sigma}_{\tau}=\boldsymbol{\sigma}\boldsymbol{\nu}-\sigma_{\nu}\boldsymbol{\nu}.

We also introduce the space of fourth order tensor fields given by

𝐐∞={ℰ=(ℰi​j​k​l)∣ℰi​j​k​l=ℰj​i​k​l=ℰk​l​i​j∈L∞​(Ω),1≤i,j,k,l≤d}\mathbf{Q}_{\infty}=\left\{\mathcal{E}=\left(\mathcal{E}_{ijkl}\right)\mid\mathcal{E}_{ijkl}=\mathcal{E}_{jikl}=\mathcal{E}_{klij}\in L^{\infty}(\Omega),\quad 1\leq i,j,k,l\leq d\right\}

and we recall that 𝐐∞\mathbf{Q}_{\infty} is a real Banach space with the norm

‖ℰ‖𝐐∞=∑1≤i,j,k,l≤d‖ℰi​j​k​l‖L∞​(Ω)\|\mathcal{E}\|_{\mathbf{Q}_{\infty}}=\sum_{1\leq i,j,k,l\leq d}\left\|\mathcal{E}_{ijkl}\right\|_{L^{\infty}(\Omega)}

Moreover, a simple calculation shows that

‖ℰ​𝝉‖Q≤‖ℰ‖𝐐∞​‖𝝉‖Q∀ℰ∈𝐐∞,𝝉∈Q\|\mathcal{E}\boldsymbol{\tau}\|_{Q}\leq\|\mathcal{E}\|_{\mathbf{Q}_{\infty}}\|\boldsymbol{\tau}\|_{Q}\quad\forall\mathcal{E}\in\mathbf{Q}_{\infty},\boldsymbol{\tau}\in Q (2.2)

Given a normed space ( X,∥⋅∥XX,\|\cdot\|_{X} ) we use the notation C​(ℝ+;X)C\left(\mathbb{R}_{+};X\right) for the space of continuous functions defined on ℝ+\mathbb{R}_{+}with values in XX. It is well known that, if XX is a Banach space, then C​(ℝ+;X)C\left(\mathbb{R}_{+};X\right) can be organized in a canonical way as a Fréchet space, i.e., as a complete metric space in which the corresponding topology is induced by a countable family of seminorms. Details can be found in [5] and [14], for instance. Also, for a subset K⊂XK\subset X we still use the symbol C​(ℝ+;K)C\left(\mathbb{R}_{+};K\right) for the set of continuous functions defined on ℝ+\mathbb{R}_{+}with values in KK. Finally, for n∈ℕn\in\mathbb{N} and K⊂XK\subset X we denote by C​([0,n];K)C([0,n];K) the set of continuous functions defined on [0,n][0,n] with values in KK.

We end this section with the following result which will be used in Section 5 of the paper.

Theorem 2.1 Let ( X,∥⋅∥XX,\|\cdot\|_{X} ) be a Banach space, KK a nonempty closed subset of XX and let Λ:C​(ℝ+;K)→C​(ℝ+;K)\Lambda:C\left(\mathbb{R}_{+};K\right)\rightarrow C\left(\mathbb{R}_{+};K\right) be a nonlinear operator. Assume that there exists k∈ℕk\in\mathbb{N} with the following property: for all n∈ℕn\in\mathbb{N} there exist two constants cn≥0c_{n}\geq 0 and dn∈[0,1)d_{n}\in[0,1) such that

‖Λ​u​(t)−Λ​v​(t)‖Xk≤cn​∫0t‖u​(s)−v​(s)‖Xk​𝑑s+dn​‖u​(t)−v​(t)‖Xk\|\Lambda u(t)-\Lambda v(t)\|_{X}^{k}\leq c_{n}\int_{0}^{t}\|u(s)-v(s)\|_{X}^{k}ds+d_{n}\|u(t)-v(t)\|_{X}^{k}

for all u,v∈C​(ℝ+;K)u,v\in C\left(\mathbb{R}_{+};K\right) and for all t∈[0,n]t\in[0,n]. Then the operator Λ\Lambda has a unique fixed point η∗∈C​(ℝ+;K)\eta^{*}\in C\left(\mathbb{R}_{+};K\right).

Theorem 2.1 was proved in [19] in the case when K=XK=X. Nevertheless, a careful examination of the proof shows that the theorem is still valid for operators
Λ:C​(ℝ+;K)→C​(ℝ+;K)\Lambda:C\left(\mathbb{R}_{+};K\right)\rightarrow C\left(\mathbb{R}_{+};K\right), provided that KK is a nonempty closed part of XX. The modification in proof are straightforward and, therefore, we do not provide the details. We only mention that the difference consists in the use of the Banach fixed point argument for contractive maps defined on the set C​([0,n];K)C([0,n];K) with values on C​([0,n];K)C([0,n];K), for all n∈ℕn\in\mathbb{N}, instead of contractive maps defined on the space C​([0,T];X)C([0,T];X) with values in C​([0,T];X)C([0,T];X).

3 Problem statement

The physical setting is as follows. A viscoelastic body occupies a bounded domain Ω⊂ℝd​(d=1,2,3)\Omega\subset\mathbb{R}^{d}(d=1,2,3) with a Lipschitz continuous boundary Γ\Gamma, divided into three measurable parts Γ1,Γ2\Gamma_{1},\Gamma_{2} and Γ3\Gamma_{3}, such that meas (Γ1)>0\left(\Gamma_{1}\right)>0. The body is subject to the action of body forces of density 𝒇0\boldsymbol{f}_{0}, is fixed on Γ1\Gamma_{1} and is submitted to the action of surface tractions of density 𝒇2\boldsymbol{f}_{2} on Γ2\Gamma_{2}. Moreover, the body is in adhesive contact on Γ3\Gamma_{3} with an obstacle, the so-called foundation. We adopt the framework of the small strain theory, we assume that the contact process is quasistatic and we study it in the interval of time ℝ+=[0,∞)\mathbb{R}_{+}=[0,\infty). To derive a mathematical model which corresponds to this physical setting we need to precise the constitutive law of the material, the balance equations and the boundary conditions, as well.

In this paper we assume that the material’s behavior follows a viscoelastic constitutive law with long memory of the form

𝝈​(t)=𝒜​𝜺​(𝒖​(t))+∫0tℬ​(t−s)​𝜺​(𝒖​(s))​𝑑s in ​Ω\boldsymbol{\sigma}(t)=\mathcal{A}\boldsymbol{\varepsilon}(\boldsymbol{u}(t))+\int_{0}^{t}\mathcal{B}(t-s)\boldsymbol{\varepsilon}(\boldsymbol{u}(s))ds\quad\text{ in }\Omega (3.1)

where, here and below, 𝒖\boldsymbol{u} denotes the displacement field, 𝝈\boldsymbol{\sigma} represents the stress field, 𝜺​(𝒖)\boldsymbol{\varepsilon}(\boldsymbol{u}) is the linearized strain tensor and t∈ℝ+t\in\mathbb{R}_{+}represents the time variable. Also, 𝒜\mathcal{A} and ℬ\mathcal{B} represent the elasticity operator and the relaxation tensor, respectively, and are assumed to verify the following conditions.

{ (a) ​𝒜:Ω×𝕊d→𝕊d​.  (b) There exists ​L𝒜>0​ such that ‖𝒜​(𝒙,𝜺1)−𝒜​(𝒙,𝜺2)‖≤L𝒜​‖𝜺1−𝜺2‖∀𝜺1,𝜺2∈𝕊d​, a.e. ​𝒙∈Ω​.  (c) There exists ​m𝒜>0​ such that (𝒜​(𝒙,𝜺1)−𝒜​(𝒙,𝜺2))⋅(𝜺1−𝜺2)≥m𝒜​‖𝜺1−𝜺2‖2∀𝜺1,𝜺2∈𝕊d, a.e. ​𝒙∈Ω​.  (d) The mapping ​𝒙↦𝒜​(𝒙,𝜺)​ is measurable on ​Ω for any ​𝜺∈𝕊d​.  (e) The mapping ​𝒙↦𝒜​(𝒙,𝟎)​ belongs to ​Q​. ℬ∈C​(ℝ+;𝐐∞)​. \left\{\begin{array}[]{l}\text{ (a) }\mathcal{A}:\Omega\times\mathbb{S}^{d}\rightarrow\mathbb{S}^{d}\text{. }\\ \text{ (b) There exists }L_{\mathcal{A}}>0\text{ such that }\\ \left\|\mathcal{A}\left(\boldsymbol{x},\boldsymbol{\varepsilon}_{1}\right)-\mathcal{A}\left(\boldsymbol{x},\boldsymbol{\varepsilon}_{2}\right)\right\|\leq L_{\mathcal{A}}\left\|\boldsymbol{\varepsilon}_{1}-\boldsymbol{\varepsilon}_{2}\right\|\\ \quad\forall\boldsymbol{\varepsilon}_{1},\boldsymbol{\varepsilon}_{2}\in\mathbb{S}^{d}\text{, a.e. }\boldsymbol{x}\in\Omega\text{. }\\ \text{ (c) There exists }m_{\mathcal{A}}>0\text{ such that }\\ \quad\left(\mathcal{A}\left(\boldsymbol{x},\boldsymbol{\varepsilon}_{1}\right)-\mathcal{A}\left(\boldsymbol{x},\boldsymbol{\varepsilon}_{2}\right)\right)\cdot\left(\boldsymbol{\varepsilon}_{1}-\boldsymbol{\varepsilon}_{2}\right)\geq m_{\mathcal{A}}\left\|\boldsymbol{\varepsilon}_{1}-\boldsymbol{\varepsilon}_{2}\right\|^{2}\\ \quad\forall\boldsymbol{\varepsilon}_{1},\boldsymbol{\varepsilon}_{2}\in\mathbb{S}^{d},\text{ a.e. }\boldsymbol{x}\in\Omega\text{. }\\ \text{ (d) The mapping }\boldsymbol{x}\mapsto\mathcal{A}(\boldsymbol{x},\boldsymbol{\varepsilon})\text{ is measurable on }\Omega\\ \quad\text{ for any }\boldsymbol{\varepsilon}\in\mathbb{S}^{d}\text{. }\\ \text{ (e) The mapping }\boldsymbol{x}\mapsto\mathcal{A}(\boldsymbol{x},\mathbf{0})\text{ belongs to }Q\text{. }\\ \quad\mathcal{B}\in C\left(\mathbb{R}_{+};\mathbf{Q}_{\infty}\right)\text{. }\end{array}\right.

Note that in (3.1) and below, in order to simplify the notation, we do not indicate explicitly the dependence of various functions on the spatial variable 𝒙\boldsymbol{x}. Various examples and mechanical interpretation concerning viscoelastic constitutive laws of the from (3.1) can be found in [6, 21, 22,

Next, since process is quasistatic, we shall use the equilibrium equation

Div⁡𝝈​(t)+𝒇0​(t)=𝟎 in ​Ω,\operatorname{Div}\boldsymbol{\sigma}(t)+\boldsymbol{f}_{0}(t)=\mathbf{0}\quad\text{ in }\Omega, (3.4)

where Div\operatorname{Div} denotes the divergence operator for tensor valued functions, i.e. Div⁡𝝈=(σi​j,j)\operatorname{Div}\boldsymbol{\sigma}=\left(\sigma_{ij,j}\right). This equation shows that at each time moment the external forces are balanced by the internal stresses. Moreover, since the body is fixed on Γ1\Gamma_{1} and given tractions are acting on Γ2\Gamma_{2} we impose the following displacement-traction conditions:

𝒖​(t)=𝟎 on ​Γ1\displaystyle\boldsymbol{u}(t)=\mathbf{0}\quad\text{ on }\Gamma_{1} (3.5)
𝝈​(t)​𝝂=𝒇2​(t) on ​Γ2.\displaystyle\boldsymbol{\sigma}(t)\boldsymbol{\nu}=\boldsymbol{f}_{2}(t)\quad\text{ on }\Gamma_{2}. (3.6)

In addition, we assume that the densities of body forces and surface tractions have regularity

𝒇0∈C​(ℝ+;L2​(Ω)d),𝒇2∈C​(ℝ+;L2​(Γ2)d).\boldsymbol{f}_{0}\in C\left(\mathbb{R}_{+};L^{2}(\Omega)^{d}\right),\quad\boldsymbol{f}_{2}\in C\left(\mathbb{R}_{+};L^{2}\left(\Gamma_{2}\right)^{d}\right). (3.7)

We now turn to the description on the adhesive contact conditions on the surface Γ3\Gamma_{3} in which our main interest is. First, we assume that the penetration is limited by a bound g>0g>0 and, therefore, at each time moment t∈ℝ+t\in\mathbb{R}_{+}, the normal displacement satisfies the inequality

uν​(t)≤g on ​Γ3.u_{\nu}(t)\leq g\quad\text{ on }\Gamma_{3}. (3.8)

Next, we assume that the normal stress has an additive decomposition of the form

σν​(t)=σνD​(t)+σνR​(t)+σνM​(t)+σνA​(t) on ​Γ3\sigma_{\nu}(t)=\sigma_{\nu}^{D}(t)+\sigma_{\nu}^{R}(t)+\sigma_{\nu}^{M}(t)+\sigma_{\nu}^{A}(t)\quad\text{ on }\Gamma_{3} (3.9)

where the functions σνD​(t),σνR​(t),σνA​(t)\sigma_{\nu}^{D}(t),\sigma_{\nu}^{R}(t),\sigma_{\nu}^{A}(t) and σνM​(t)\sigma_{\nu}^{M}(t) describe the deformability, the rigidity, the adhesive and the surface memory properties of the foundation. We assume that σνD​(t)\sigma_{\nu}^{D}(t) satisfies the normal compliance contact condition, that is

−σνD​(t)=pν​(uν​(t)) on ​Γ3-\sigma_{\nu}^{D}(t)=p_{\nu}\left(u_{\nu}(t)\right)\quad\text{ on }\Gamma_{3} (3.10)

Here pνp_{\nu} is a given function which satisfies

{ (a) ​pν:Γ3×ℝ→ℝ+.(b) There exists ​Lν>0​ such that |pν​(𝒙,r1)−pν​(𝒙,r2)|≤Lν​|r1−r2|∀r1,r2∈ℝ, a.e. ​𝒙∈Γ3. (c) ​(pν​(𝒙,r1)−pν​(𝒙,r2))​(r1−r2)≥0∀r1,r2∈ℝ, a.e. ​𝒙∈Γ3. (d) The mapping ​𝒙↦pν​(𝒙,r)​ is measurable on ​Γ3, for any ​r∈ℝ. (e) ​pν​(𝒙,r)=0​ for all ​r≤0, a.e. ​𝒙∈Γ3.\left\{\begin{array}[]{l}\text{ (a) }p_{\nu}:\Gamma_{3}\times\mathbb{R}\rightarrow\mathbb{R}_{+}.\\ \text{(b) There exists }L_{\nu}>0\text{ such that }\\ \quad\left|p_{\nu}\left(\boldsymbol{x},r_{1}\right)-p_{\nu}\left(\boldsymbol{x},r_{2}\right)\right|\leq L_{\nu}\left|r_{1}-r_{2}\right|\\ \quad\forall r_{1},r_{2}\in\mathbb{R},\text{ a.e. }\boldsymbol{x}\in\Gamma_{3}.\\ \text{ (c) }\left(p_{\nu}\left(\boldsymbol{x},r_{1}\right)-p_{\nu}\left(\boldsymbol{x},r_{2}\right)\right)\left(r_{1}-r_{2}\right)\geq 0\\ \quad\forall r_{1},r_{2}\in\mathbb{R},\text{ a.e. }\boldsymbol{x}\in\Gamma_{3}.\\ \text{ (d) The mapping }\boldsymbol{x}\mapsto p_{\nu}(\boldsymbol{x},r)\text{ is measurable on }\Gamma_{3},\\ \quad\text{ for any }r\in\mathbb{R}.\\ \text{ (e) }p_{\nu}(\boldsymbol{x},r)=0\text{ for all }r\leq 0,\text{ a.e. }\boldsymbol{x}\in\Gamma_{3}.\end{array}\right.

The part σνR​(t)\sigma_{\nu}^{R}(t) of the normal stress satisfies the Signorini condition in the form with a gap function, i.e.

σνR​(t)≤0,σνR​(t)​(uν​(t)−g)=0 on ​Γ3.\sigma_{\nu}^{R}(t)\leq 0,\quad\sigma_{\nu}^{R}(t)\left(u_{\nu}(t)-g\right)=0\quad\text{ on }\Gamma_{3}. (3.12)

Details on the Signorini condition and normal compliance function can be found in [10, 12, 13, 18, for instance. Here we restrict ourselves to recall that the normal compliance condition describes the contact with a deformable foundation and the Signorini contact condition describes the contact with a perfectly rigid foundation.

The function σνM​(t)\sigma_{\nu}^{M}(t) satisfies the condition

{|σνM​(t)|≤∫0tb​(t−s)​uν+​(s)​𝑑sσνM​(t)=0​ if ​uν​(t)<0σνM​(t)=−∫0tb​(t−s)​uν+​(s)​𝑑s​ if ​uν​(t)>0 on ​Γ3\left\{\begin{array}[]{l}\left|\sigma_{\nu}^{M}(t)\right|\leq\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds\\ \sigma_{\nu}^{M}(t)=0\text{ if }u_{\nu}(t)<0\\ \sigma_{\nu}^{M}(t)=-\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds\text{ if }u_{\nu}(t)>0\end{array}\quad\text{ on }\Gamma_{3}\right.

where bb is a surface memory function which verifies

b∈C​(ℝ+;L∞​(Γ3)),b​(t,𝒙)≥0 for all ​t∈ℝ+,a.e. ​𝒙∈Γ3.b\in C\left(\mathbb{R}_{+};L^{\infty}\left(\Gamma_{3}\right)\right),\quad b(t,\boldsymbol{x})\geq 0\quad\text{ for all }t\in\mathbb{R}_{+},\text{a.e. }\boldsymbol{x}\in\Gamma_{3}. (3.14)

Details on this condition can be found in [24.
Finally, the contribution of the bonding to the normal traction, σνA​(t)\sigma_{\nu}^{A}(t), satisfies

σνA​(t)=γν​β2​(t)​R~​(uν​(t)) on ​Γ3\sigma_{\nu}^{A}(t)=\gamma_{\nu}\beta^{2}(t)\widetilde{R}\left(u_{\nu}(t)\right)\quad\text{ on }\Gamma_{3} (3.15)

where R~\widetilde{R} is the truncation function given by

R~​(s)={L if ​s<−L−s if −L≤s≤00 if ​s>0\widetilde{R}(s)=\left\{\begin{array}[]{cc}L&\text{ if }s<-L\\ -s&\text{ if }-L\leq s\leq 0\\ 0&\text{ if }s>0\end{array}\right.

Here and below L>0L>0 is the characteristic length of the bond, beyond which it stretches without offering any additional resistance (see, e.g., [15]) and γν\gamma_{\nu} represents an adhesion coefficient. More details on this condition can be found in [20.

We combine (3.9), (3.10), (3.15) and denote −σνM​(t)=ξ​(t)-\sigma_{\nu}^{M}(t)=\xi(t) to see that

σνR​(t)=σν​(t)+pν​(uν​(t))−γν​β2​(t)​R~​(uν​(t))+ξ​(t) on ​Γ3\sigma_{\nu}^{R}(t)=\sigma_{\nu}(t)+p_{\nu}\left(u_{\nu}(t)\right)-\gamma_{\nu}\beta^{2}(t)\widetilde{R}\left(u_{\nu}(t)\right)+\xi(t)\quad\text{ on }\Gamma_{3} (3.17)

Then we substitute equality (3.17) in (3.12) and use (3.8), (3.13) and (3.14) to obtain
the following contact condition

{uν​(t)≤g,σν​(t)+pν​(uν​(t))+ξ​(t)−γν​β2​(t)​R~​(uν​(t))≤0(uν​(t)−g)​(σν​(t)+pν​(uν​(t))+ξ​(t)−γν​β2​(t)​R~​(uν​(t)))=00≤ξ​(t)≤∫0tb​(t−s)​uν+​(s)​𝑑sξ​(t)=0​ if ​uν​(t)<0ξ​(t)=∫0tb​(t−s)​uν+​(s)​𝑑s​ if ​uν​(t)>0\left\{\begin{array}[]{l}u_{\nu}(t)\leq g,\sigma_{\nu}(t)+p_{\nu}\left(u_{\nu}(t)\right)+\xi(t)-\gamma_{\nu}\beta^{2}(t)\widetilde{R}\left(u_{\nu}(t)\right)\leq 0\\ \left(u_{\nu}(t)-g\right)\left(\sigma_{\nu}(t)+p_{\nu}\left(u_{\nu}(t)\right)+\xi(t)-\gamma_{\nu}\beta^{2}(t)\widetilde{R}\left(u_{\nu}(t)\right)\right)=0\\ 0\leq\xi(t)\leq\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds\\ \xi(t)=0\text{ if }u_{\nu}(t)<0\\ \xi(t)=\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds\text{ if }u_{\nu}(t)>0\end{array}\right.

To complete our model we assume that the resistance to tangential motion is generated mainly by the glue, and the frictional traction can be neglected. In particular, when all the adhesive bonds are inactive, or broken, the motion is frictionless. Thus, the tangential traction depends on the intensity of adhesion and on the tangential displacement, but only up to the bond length LL, that is

−𝝈τ​(t)=pτ​(β​(t))​𝑹∗​(𝒖τ​(t)) on ​Γ3,-\boldsymbol{\sigma}_{\tau}(t)=p_{\tau}(\beta(t))\boldsymbol{R}^{*}\left(\boldsymbol{u}_{\tau}(t)\right)\quad\text{ on }\Gamma_{3}, (3.19)

where the truncation operator 𝑹∗\boldsymbol{R}^{*} is defined by

𝑹∗​(𝒗)={𝒗 if ​‖𝒗‖≤L,L‖𝒗‖​𝒗 if ​‖𝒗‖≥L.\boldsymbol{R}^{*}(\boldsymbol{v})=\left\{\begin{array}[]{cc}\boldsymbol{v}&\text{ if }\|\boldsymbol{v}\|\leq L,\\ \frac{L}{\|\boldsymbol{v}\|}\boldsymbol{v}&\text{ if }\|\boldsymbol{v}\|\geq L.\end{array}\right.

Then, pτ​(β)p_{\tau}(\beta) acts as the stiffness or spring constant, and the traction is in direction opposite to the displacement. The tangential function pτp_{\tau} satisfies

{ (a) ​pτ:Γ3×ℝ→ℝ+.(b) There exists ​Lτ>0​ such that |pτ​(𝒙,β1)−pτ​(𝒙,β2)|≤Lτ​|β1−β2|∀β1,β2∈ℝ, a.e. ​𝒙∈Γ3. (c) There exists ​Mτ>0​ such that ​pτ​(𝒙,β)≤Mτ∀β∈ℝ, a.e. ​𝒙∈Γ3. (d) The mapping ​𝒙↦pτ​(𝒙,β)​ is measurable on ​Γ3, for any ​β∈ℝ. (e) ​pτ​(𝒙,0)=0​ a.e. ​𝒙∈Γ3.\left\{\begin{array}[]{l}\text{ (a) }p_{\tau}:\Gamma_{3}\times\mathbb{R}\rightarrow\mathbb{R}_{+}.\\ \text{(b) There exists }L_{\tau}>0\text{ such that }\\ \quad\left|p_{\tau}\left(\boldsymbol{x},\beta_{1}\right)-p_{\tau}\left(\boldsymbol{x},\beta_{2}\right)\right|\leq L_{\tau}\left|\beta_{1}-\beta_{2}\right|\\ \quad\forall\beta_{1},\beta_{2}\in\mathbb{R},\text{ a.e. }\boldsymbol{x}\in\Gamma_{3}.\\ \text{ (c) There exists }M_{\tau}>0\text{ such that }p_{\tau}(\boldsymbol{x},\beta)\leq M_{\tau}\\ \quad\forall\beta\in\mathbb{R},\text{ a.e. }\boldsymbol{x}\in\Gamma_{3}.\\ \text{ (d) The mapping }\boldsymbol{x}\mapsto p_{\tau}(\boldsymbol{x},\beta)\text{ is measurable on }\Gamma_{3},\\ \quad\text{ for any }\beta\in\mathbb{R}.\\ \text{ (e) }p_{\tau}(\boldsymbol{x},0)=0\text{ a.e. }\boldsymbol{x}\in\Gamma_{3}.\end{array}\right.

We follow [7, 8, 20] and assume that the bonding field satisfies the unilateral constraint

0≤β​(t)≤1 on Γ3.0\leq\beta(t)\leq 1\quad\text{ on }\quad\Gamma_{3}. (3.22)

Moreover, its evolution is governed by the differential equation

β˙​(t)=−(γν​β​(t)​[R​(uν​(t))]2−εa)+ on Γ3\dot{\beta}(t)=-\left(\gamma_{\nu}\beta(t)\left[R\left(u_{\nu}(t)\right)\right]^{2}-\varepsilon_{a}\right)^{+}\quad\text{ on }\quad\Gamma_{3} (3.23)

in which εa\varepsilon_{a} represents the Dupré energy and RR is the truncation operator given by

R​(s)={−L if ​s<−Ls if −L≤s≤LL if ​s>LR(s)=\left\{\begin{array}[]{cc}-L&\text{ if }s<-L\\ s&\text{ if }-L\leq s\leq L\\ L&\text{ if }s>L\end{array}\right.

We complete this differential equation with the initial condition

β​(0)=β0​ on ​Γ3\beta(0)=\beta_{0}\text{ on }\Gamma_{3} (3.25)

and we assume that the adhesion coefficient, γν\gamma_{\nu}, the Dupré energy εa\varepsilon_{a}, and initial bonding field, β0\beta_{0}, satisfy the conditions

γν∈L∞​(Γ3),γν≥0,εa∈L∞​(Γ3),εa≥0β0∈L2​(Γ3),0≤β0≤1 a.e. on ​Γ3.\begin{array}[]{ll}\gamma_{\nu}\in L^{\infty}\left(\Gamma_{3}\right),&\gamma_{\nu}\geq 0,\quad\varepsilon_{a}\in L^{\infty}\left(\Gamma_{3}\right),\quad\varepsilon_{a}\geq 0\\ \beta_{0}\in L^{2}\left(\Gamma_{3}\right),&0\leq\beta_{0}\leq 1\quad\text{ a.e. on }\Gamma_{3}.\end{array}

We gather the above equations and conditions to obtain the following formulation of the mechanical problem of quasistatic adhesive contact with normal compliance, unilateral constraint and surface memory term.

Problem 𝒫\mathcal{P}. Find a displacement field 𝒖:Ω×ℝ+→ℝd\boldsymbol{u}:\Omega\times\mathbb{R}_{+}\rightarrow\mathbb{R}^{d}, a stress field 𝝈:Ω×ℝ+→𝕊d\boldsymbol{\sigma}:\Omega\times\mathbb{R}_{+}\rightarrow\mathbb{S}^{d} and a adhesion field β:Γ3×ℝ+→[0,1]\beta:\Gamma_{3}\times\mathbb{R}_{+}\rightarrow[0,1] such that

𝝈​(t)=𝒜​𝜺​(𝒖​(t))+∫0tℬ​(t−s)​𝜺​(𝒖​(s))​𝑑s\displaystyle\boldsymbol{\sigma}(t)=\mathcal{A}\boldsymbol{\varepsilon}(\boldsymbol{u}(t))+\int_{0}^{t}\mathcal{B}(t-s)\boldsymbol{\varepsilon}(\boldsymbol{u}(s))ds in Ω,\displaystyle\text{ in }\quad\Omega, (3.28)
Div⁡𝝈​(t)+𝒇0​(t)=𝟎\displaystyle\operatorname{Div}\boldsymbol{\sigma}(t)+\boldsymbol{f}_{0}(t)=\mathbf{0} in Ω,\displaystyle\text{ in }\quad\Omega, (3.29)
𝒖​(t)=𝟎\displaystyle\boldsymbol{u}(t)=\mathbf{0} on Γ1,\displaystyle\text{ on }\quad\Gamma_{1}, (3.30)
𝝈​(t)​𝝂=𝒇2​(t)\displaystyle\boldsymbol{\sigma}(t)\boldsymbol{\nu}=\boldsymbol{f}_{2}(t) on Γ2,\displaystyle\text{ on }\quad\Gamma_{2}, (3.31)
−𝝈τ​(t)=pτ​(β​(t))​𝑹∗​(𝒖τ​(t))\displaystyle-\boldsymbol{\sigma}_{\tau}(t)=p_{\tau}(\beta(t))\boldsymbol{R}^{*}\left(\boldsymbol{u}_{\tau}(t)\right) on Γ3,\displaystyle\text{ on }\quad\Gamma_{3}, (3.32)
β˙​(t)=−(γν​β​(t)​[R​(uν​(t))]2−εa)+\displaystyle\dot{\beta}(t)=-\left(\gamma_{\nu}\beta(t)\left[R\left(u_{\nu}(t)\right)\right]^{2}-\varepsilon_{a}\right)^{+} on Γ3,\displaystyle\text{on }\quad\Gamma_{3}, (3.33)

for all t∈ℝ+t\in\mathbb{R}_{+}, there exists ξ:Γ3×ℝ+→ℝ\xi:\Gamma_{3}\times\mathbb{R}_{+}\rightarrow\mathbb{R} which satisfies

uν​(t)≤g,σν​(t)+pν​(uν​(t))+ξ​(t)−γν​β2​(t)​R~​(uν​(t))≤0,(uν​(t)−g)​[σν​(t)+pν​(uν​(t))+ξ​(t)−γν​β2​(t)​R~​(uν​(t))]=0,0≤ξ​(t)≤∫0tb​(t−s)​uν+​(s)​𝑑s,ξ​(t)=0​ if ​uν​(t)<0,ξ​(t)=∫0tb​(t−s)​uν+​(s)​𝑑s​ if ​uν​(t)>0}​ on ​Γ3\left.\begin{array}[]{l}u_{\nu}(t)\leq g,\sigma_{\nu}(t)+p_{\nu}\left(u_{\nu}(t)\right)+\xi(t)-\gamma_{\nu}\beta^{2}(t)\widetilde{R}\left(u_{\nu}(t)\right)\leq 0,\\ \left(u_{\nu}(t)-g\right)\left[\sigma_{\nu}(t)+p_{\nu}\left(u_{\nu}(t)\right)+\xi(t)-\gamma_{\nu}\beta^{2}(t)\widetilde{R}\left(u_{\nu}(t)\right)\right]=0,\\ 0\leq\xi(t)\leq\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds,\\ \xi(t)=0\text{ if }u_{\nu}(t)<0,\\ \xi(t)=\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds\text{ if }u_{\nu}(t)>0\end{array}\right\}\text{ on }\Gamma_{3}

for all t∈ℝ+t\in\mathbb{R}_{+}and, moreover,

β​(0)=β0 on ​Γ3\beta(0)=\beta_{0}\quad\text{ on }\Gamma_{3} (3.35)

The unique weak solvability of the contact problem 𝒫\mathcal{P} will be stated in Section 4 and proved in Section 5. We end this current section with some additional comments of the contact condition (3.34), which represents one of the novelties of this paper.

First, we recall that (3.34) describes a condition with unilateral constraint, since inequality (3.8) holds at each time moment. The rest of the comments in this paragraph, together with the corresponding equalities and inequalities, are valid for a given point 𝒙\boldsymbol{x} on the contact surface Γ3\Gamma_{3}. Nevertheless, we recall that, for simplicity, we skip the dependence of various functions on 𝒙\boldsymbol{x}. Assume that at a given moment tt there is penetration which did not reach the bound gg, i.e. 0<uν​(t)<g0<u_{\nu}(t)<g. Then, (3.34) yields

−σν​(t)=pν​(uν​(t))+∫0tb​(t−s)​uν+​(s)​𝑑s-\sigma_{\nu}(t)=p_{\nu}\left(u_{\nu}(t)\right)+\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds (3.36)

This equality shows that at the moment tt, the reaction of the foundation depends both on the current value of the penetration (represented by the term pν​(uν​(t))p_{\nu}\left(u_{\nu}(t)\right) ) and on the history of the penetration (represented by the integral term in (3.36)). Assume now that at a given moment tt there is separation between the body and the foundation, i.e. uν​(t)<0u_{\nu}(t)<0. Then, (3.34) shows that

σν​(t)=γν​β2​(t)​R~​(uν​(t))\sigma_{\nu}(t)=\gamma_{\nu}\beta^{2}(t)\widetilde{R}\left(u_{\nu}(t)\right) (3.37)

i.e. the reaction of the foundation is nonnegative and depends on adhesion coefficient, on the square of intensity of adhesion and on the normal displacement, but as it does not exceed the bound length LL. Once it exceeds it the normal traction remains constant and |σν​(t)|≤γν​L\left|\sigma_{\nu}(t)\right|\leq\gamma_{\nu}L.

In conclusion, condition (3.34) shows that delimitation takes place when there is separation. When there is penetration the contact stress is given by a normal compliance condition with memory term of the form (3.36) but up to the limit gg. When the limit gg is reached, the stress is given by a Signorini-type unilateral condition. This condition can be interpreted physically as follows. The foundation is assumed to be made of a hard material covered with a thin layer made of a soft adhesive material with thickness gg. The layer has adhesive viscoelastic behavior, i.e. is deformable, allows penetration and develops memory effects. The hard material is perfectly rigid and, therefore, it does not allow penetration. To summarize, the foundation has a rigid-adhesive-viscoelastic behavior; its adhesive- viscoelastic behavior is caused by the layer of the soft material while its rigid behavior is caused by the hard material.

4 Variational formulation and main result

We now turn to the variational formulation of Problem 𝒫\mathcal{P} and, to this end, we assume in what follows that ( 𝒖,𝝈,𝜷\boldsymbol{u},\boldsymbol{\sigma},\boldsymbol{\beta} ) represent a triple of regular functions which satisfy (3.28)-(3.35). We introduce the set of admissible displacements and the set of admissible bonding fields, respectively, defined by

U={𝒗∈V:vν≤g a.e. on Γ3}\displaystyle U=\left\{\boldsymbol{v}\in V:v_{\nu}\leq g\quad\text{ a.e. on }\quad\Gamma_{3}\right\} (4.1)
Z={ω∈L2​(Γ3):0≤ω≤1 a.e. on ​Γ3}.\displaystyle Z=\left\{\omega\in L^{2}\left(\Gamma_{3}\right):0\leq\omega\leq 1\quad\text{ a.e. on }\Gamma_{3}\right\}. (4.2)

Let 𝒗∈U\boldsymbol{v}\in U and t∈ℝ+t\in\mathbb{R}_{+}be given. We use the Green’s formula to see that

∫Ω𝝈​(t)⋅𝜺​(𝒗)​𝑑x+∫ΩDiv⁡𝝈​(t)⋅𝒗​𝑑x=∫Γ𝝈​(t)​𝝂⋅𝒗​𝑑a∀𝒗∈V\int_{\Omega}\boldsymbol{\sigma}(t)\cdot\boldsymbol{\varepsilon}(\boldsymbol{v})dx+\int_{\Omega}\operatorname{Div}\boldsymbol{\sigma}(t)\cdot\boldsymbol{v}dx=\int_{\Gamma}\boldsymbol{\sigma}(t)\boldsymbol{\nu}\cdot\boldsymbol{v}da\quad\forall\boldsymbol{v}\in V

and, combining this equality with the equilibrium equation (3.29), we find that

∫Ω𝝈​(t)⋅(𝜺​(𝒗)−𝜺​(𝒖​(t)))​𝑑x=∫Ω𝒇0​(t)⋅(𝒗−𝒖​(t))​𝑑x+∫Γ𝝈​(t)​𝝂⋅(𝒗−𝒖​(t))​𝑑a\int_{\Omega}\boldsymbol{\sigma}(t)\cdot(\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}(\boldsymbol{u}(t)))dx=\int_{\Omega}\boldsymbol{f}_{0}(t)\cdot(\boldsymbol{v}-\boldsymbol{u}(t))dx+\int_{\Gamma}\boldsymbol{\sigma}(t)\boldsymbol{\nu}\cdot(\boldsymbol{v}-\boldsymbol{u}(t))da

Then, we split the surface integral over Γ1,Γ2\Gamma_{1},\Gamma_{2} and Γ3\Gamma_{3} and, since 𝒗−𝒖​(t)=𝟎\boldsymbol{v}-\boldsymbol{u}(t)=\mathbf{0} a.e. on Γ1,𝝈​(t)​𝝂=𝒇2​(t)\Gamma_{1},\boldsymbol{\sigma}(t)\boldsymbol{\nu}=\boldsymbol{f}_{2}(t) on Γ2\Gamma_{2}, we deduce that

∫Ω𝝈​(t)⋅(𝜺​(𝒗)−𝜺​(𝒖​(t)))​𝑑x=∫Ω𝒇0​(t)⋅(𝒗−𝒖​(t))​𝑑x\displaystyle\int_{\Omega}\boldsymbol{\sigma}(t)\cdot(\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}(\boldsymbol{u}(t)))dx=\int_{\Omega}\boldsymbol{f}_{0}(t)\cdot(\boldsymbol{v}-\boldsymbol{u}(t))dx
+∫Γ2𝒇2​(t)⋅(𝒗−𝒖​(t))​𝑑a+∫Γ3𝝈​(t)​𝝂⋅(𝒗−𝒖​(t))​𝑑a\displaystyle\quad+\int_{\Gamma_{2}}\boldsymbol{f}_{2}(t)\cdot(\boldsymbol{v}-\boldsymbol{u}(t))da+\int_{\Gamma_{3}}\boldsymbol{\sigma}(t)\boldsymbol{\nu}\cdot(\boldsymbol{v}-\boldsymbol{u}(t))da

Moreover, since

𝝈​(t)​𝝂⋅(𝒗−𝒖​(t))=σν​(t)​(vν−uν​(t))+𝝈τ​(t)⋅(𝒗τ−𝒖τ​(t)) on ​Γ3,\boldsymbol{\sigma}(t)\boldsymbol{\nu}\cdot(\boldsymbol{v}-\boldsymbol{u}(t))=\sigma_{\nu}(t)\left(v_{\nu}-u_{\nu}(t)\right)+\boldsymbol{\sigma}_{\tau}(t)\cdot\left(\boldsymbol{v}_{\tau}-\boldsymbol{u}_{\tau}(t)\right)\quad\text{ on }\Gamma_{3},

taking into account condition (3.32) we obtain

∫Ω\displaystyle\int_{\Omega} 𝝈​(t)⋅(𝜺​(𝒗)−𝜺​(𝒖​(t)))​d​x\displaystyle\boldsymbol{\sigma}(t)\cdot(\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}(\boldsymbol{u}(t)))dx (4.3)
=\displaystyle= ∫Ω𝒇0​(t)⋅(𝒗−𝒖​(t))​𝑑x+∫Γ2𝒇2​(t)⋅(𝒗−𝒖​(t))​𝑑a\displaystyle\int_{\Omega}\boldsymbol{f}_{0}(t)\cdot(\boldsymbol{v}-\boldsymbol{u}(t))dx+\int_{\Gamma_{2}}\boldsymbol{f}_{2}(t)\cdot(\boldsymbol{v}-\boldsymbol{u}(t))da
+∫Γ3σν​(t)​(vν−uν​(t))​𝑑a−∫Γ3pτ​(β​(t))​𝑹∗​(𝒖τ​(t))⋅(𝒗τ−𝒖τ​(t))​𝑑a\displaystyle+\int_{\Gamma_{3}}\sigma_{\nu}(t)\left(v_{\nu}-u_{\nu}(t)\right)da-\int_{\Gamma_{3}}p_{\tau}(\beta(t))\boldsymbol{R}^{*}\left(\boldsymbol{u}_{\tau}(t)\right)\cdot\left(\boldsymbol{v}_{\tau}-\boldsymbol{u}_{\tau}(t)\right)da

We write now

σν​(t)\displaystyle\sigma_{\nu}(t) (vν−uν​(t))=[σν​(t)+pν​(uν​(t))+ξ​(t)−γν​β2​(t)​R~​(uν​(t))]​(vν−g)\displaystyle\left(v_{\nu}-u_{\nu}(t)\right)=\left[\sigma_{\nu}(t)+p_{\nu}\left(u_{\nu}(t)\right)+\xi(t)-\gamma_{\nu}\beta^{2}(t)\widetilde{R}\left(u_{\nu}(t)\right)\right]\left(v_{\nu}-g\right)
+\displaystyle+ [σν​(t)+pν​(uν​(t))+ξ​(t)−γν​β2​(t)​R~​(uν​(t))]​(g−uν​(t))\displaystyle{\left[\sigma_{\nu}(t)+p_{\nu}\left(u_{\nu}(t)\right)+\xi(t)-\gamma_{\nu}\beta^{2}(t)\widetilde{R}\left(u_{\nu}(t)\right)\right]\left(g-u_{\nu}(t)\right)}
−[pν​(uν​(t))+ξ​(t)−γν​β2​(t)​R~​(uν​(t))]​(vν−uν​(t)) on ​Γ3\displaystyle-\left[p_{\nu}\left(u_{\nu}(t)\right)+\xi(t)-\gamma_{\nu}\beta^{2}(t)\widetilde{R}\left(u_{\nu}(t)\right)\right]\left(v_{\nu}-u_{\nu}(t)\right)\quad\text{ on }\Gamma_{3}

then we use the contact condition (3.34) and definition (4.1) of the set UU to see that

σν​(t)​(vν−uν​(t))\displaystyle\sigma_{\nu}(t)\left(v_{\nu}-u_{\nu}(t)\right) (4.4)
≥−[pν​(uν​(t))+ξ​(t)−γν​β2​(t)​R~​(uν​(t))]​(vν−uν​(t)) on ​Γ3\displaystyle\quad\geq-\left[p_{\nu}\left(u_{\nu}(t)\right)+\xi(t)-\gamma_{\nu}\beta^{2}(t)\widetilde{R}\left(u_{\nu}(t)\right)\right]\left(v_{\nu}-u_{\nu}(t)\right)\quad\text{ on }\Gamma_{3}

We use (3.34), again, and the hypothesis (3.14) on function bb to deduce that

(∫0tb​(t−s)​uν+​(s)​𝑑s)​(vν+−uν+​(t))≥ξ​(t)​(vν−uν​(t)) on ​Γ3\left(\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds\right)\left(v_{\nu}^{+}-u_{\nu}^{+}(t)\right)\geq\xi(t)\left(v_{\nu}-u_{\nu}(t)\right)\quad\text{ on }\Gamma_{3} (4.5)

Then we add the inequalities (4.4) and (4.5) and integrate the result on Γ3\Gamma_{3} to find that

∫Γ3σν​(t)​(vν−uν​(t))​𝑑a+∫Γ3(∫0tb​(t−s)​uν+​(s)​𝑑s)​(vν+−uν+​(t))​𝑑a\displaystyle\int_{\Gamma_{3}}\sigma_{\nu}(t)\left(v_{\nu}-u_{\nu}(t)\right)da+\int_{\Gamma_{3}}\left(\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds\right)\left(v_{\nu}^{+}-u_{\nu}^{+}(t)\right)da (4.6)
≥−∫Γ3pν​(uν​(t))​(vν−uν​(t))​𝑑a+∫Γ3γν​β2​(t)​R~​(uν​(t))​(vν−uν​(t))​𝑑a\displaystyle\quad\geq-\int_{\Gamma_{3}}p_{\nu}\left(u_{\nu}(t)\right)\left(v_{\nu}-u_{\nu}(t)\right)da+\int_{\Gamma_{3}}\gamma_{\nu}\beta^{2}(t)\widetilde{R}\left(u_{\nu}(t)\right)\left(v_{\nu}-u_{\nu}(t)\right)da

Finally, we combine (4.3) and (4.6) to obtain that

∫Ω𝝈(t)⋅(𝜺(𝒗)−𝜺(𝒖(t))dx+∫Γ3pν(uν(t))(vν−uν(t))da\displaystyle\int_{\Omega}\boldsymbol{\sigma}(t)\cdot\left(\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}(\boldsymbol{u}(t))dx+\int_{\Gamma_{3}}p_{\nu}\left(u_{\nu}(t)\right)\left(v_{\nu}-u_{\nu}(t)\right)da\right. (4.7)
+∫Γ3pτ​(β​(t))​𝑹∗​(𝒖τ​(t))⋅(𝒗τ−𝒖τ​(t))​𝑑a\displaystyle\quad+\int_{\Gamma_{3}}p_{\tau}(\beta(t))\boldsymbol{R}^{*}\left(\boldsymbol{u}_{\tau}(t)\right)\cdot\left(\boldsymbol{v}_{\tau}-\boldsymbol{u}_{\tau}(t)\right)da
+∫Γ3(∫0tb​(t−s)​uν+​(s)​𝑑s)​(vν+−uν+​(t))​𝑑a\displaystyle\quad+\int_{\Gamma_{3}}\left(\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds\right)\left(v_{\nu}^{+}-u_{\nu}^{+}(t)\right)da
−∫Γ3γν​β2​(t)​R~​(uν​(t))​(vν−uν​(t))​𝑑a\displaystyle\quad-\int_{\Gamma_{3}}\gamma_{\nu}\beta^{2}(t)\widetilde{R}\left(u_{\nu}(t)\right)\left(v_{\nu}-u_{\nu}(t)\right)da
≥∫Ω𝒇0​(t)⋅(𝒗−𝒖​(t))​𝑑x+∫Γ2𝒇2​(t)⋅(𝒗−𝒖​(t))​𝑑x∀𝒗∈U\displaystyle\quad\geq\int_{\Omega}\boldsymbol{f}_{0}(t)\cdot(\boldsymbol{v}-\boldsymbol{u}(t))dx+\int_{\Gamma_{2}}\boldsymbol{f}_{2}(t)\cdot(\boldsymbol{v}-\boldsymbol{u}(t))dx\quad\forall\boldsymbol{v}\in U

Next, we use the Riesz representation Theorem to define the operator P:V→VP:V\rightarrow V and the function 𝒇:ℝ+→V\boldsymbol{f}:\mathbb{R}_{+}\rightarrow V by equalities

(P​𝒖,𝒗)V=∫Γ3pν​(uν)​vν​𝑑a∀𝒖,𝒗∈V\displaystyle(P\boldsymbol{u},\boldsymbol{v})_{V}=\int_{\Gamma_{3}}p_{\nu}\left(u_{\nu}\right)v_{\nu}da\quad\forall\boldsymbol{u},\boldsymbol{v}\in V (4.8)
(𝒇​(t),𝒗)V=∫Ω𝒇0​(t)⋅𝒗​𝑑x+∫Γ2𝒇2​(t)⋅𝒗​𝑑a∀𝒗∈V\displaystyle(\boldsymbol{f}(t),\boldsymbol{v})_{V}=\int_{\Omega}\boldsymbol{f}_{0}(t)\cdot\boldsymbol{v}dx+\int_{\Gamma_{2}}\boldsymbol{f}_{2}(t)\cdot\boldsymbol{v}da\quad\forall\boldsymbol{v}\in V (4.9)

It follows from assumptions (3.11) and (2.1) that

(P​𝒖−P​𝒗,𝒖−𝒗)V≥0,‖P​𝒖−P​𝒗‖V≤c02​Lν​‖𝒖−𝒗‖V∀𝒖,𝒗∈V,(P\boldsymbol{u}-P\boldsymbol{v},\boldsymbol{u}-\boldsymbol{v})_{V}\geq 0,\quad\|P\boldsymbol{u}-P\boldsymbol{v}\|_{V}\leq c_{0}^{2}L_{\nu}\|\boldsymbol{u}-\boldsymbol{v}\|_{V}\quad\forall\boldsymbol{u},\boldsymbol{v}\in V, (4.10)

which shows that P:V→VP:V\rightarrow V is a monotone Lipschitz continuous operator. Moreover, the regularity (3.7) implies that

𝒇∈C​(ℝ+;V).\boldsymbol{f}\in C\left(\mathbb{R}_{+};V\right). (4.11)

We also consider the functional j:Z×V×V→ℝj:Z\times V\times V\rightarrow\mathbb{R} defined by

j​(β,𝒖,𝒗)=∫Γ3[pτ​(β​(t))​𝑹∗​(𝒖τ​(t))⋅𝒗τ−γν​β2​(t)​R~​(uν​(t))​vν]​𝑑aj(\beta,\boldsymbol{u},\boldsymbol{v})=\int_{\Gamma_{3}}\left[p_{\tau}(\beta(t))\boldsymbol{R}^{*}\left(\boldsymbol{u}_{\tau}(t)\right)\cdot\boldsymbol{v}_{\tau}-\gamma_{\nu}\beta^{2}(t)\widetilde{R}\left(u_{\nu}(t)\right)v_{\nu}\right]da (4.12)

Then, we use (4.7) and notations (4.8)-(4.12) to deduce that

(𝝈​(t),𝜺​(𝒗)−𝜺​(𝒖​(t)))Q+(P​𝒖​(t),𝒗−𝒖​(t))V\displaystyle(\boldsymbol{\sigma}(t),\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}(\boldsymbol{u}(t)))_{Q}+(P\boldsymbol{u}(t),\boldsymbol{v}-\boldsymbol{u}(t))_{V} (4.13)
+j​(β​(t),𝒖​(t),𝒗)−j​(β​(t),𝒖​(t),𝒖​(t))\displaystyle\quad+j(\beta(t),\boldsymbol{u}(t),\boldsymbol{v})-j(\beta(t),\boldsymbol{u}(t),\boldsymbol{u}(t))
+(∫0tb​(t−s)​uν+​(s)​𝑑s,vν+−uν+​(t))L2​(Γ3)\displaystyle\quad+\left(\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds,v_{\nu}^{+}-u_{\nu}^{+}(t)\right)_{L^{2}\left(\Gamma_{3}\right)}
≥(𝒇​(t),𝒗−𝒖​(t))V\displaystyle\quad\geq(\boldsymbol{f}(t),\boldsymbol{v}-\boldsymbol{u}(t))_{V}

Also we integrate the differential equation (3.33) with the initial condition (3.35) to obtain that

β​(t)=β0−∫0t(γν​β​(s)​[R​(uν​(s))]2−εa)+​𝑑s on ​Γ3\beta(t)=\beta_{0}-\int_{0}^{t}\left(\gamma_{\nu}\beta(s)\left[R\left(u_{\nu}(s)\right)\right]^{2}-\varepsilon_{a}\right)^{+}ds\quad\text{ on }\Gamma_{3} (4.14)

Finally, we recall that the unilateral constraints imposed to the displacement and bonding field, combined with the definitions (4.1) and (4.2), yield

𝒖​(t)∈U,β​(t)∈Z.\boldsymbol{u}(t)\in U,\quad\beta(t)\in Z. (4.15)

We now gather the constitutive law (3.28), the variational inequality (4.13), the integral equation (4.14) and the unilateral constraints (4.15) to obtain the following variational formulation of Problem 𝒫\mathcal{P}.

Problem 𝒫V\mathcal{P}^{V}. Find a displacement field 𝒖:ℝ+→U\boldsymbol{u}:\mathbb{R}_{+}\rightarrow U, a stress field 𝝈:ℝ+→Q\boldsymbol{\sigma}:\mathbb{R}_{+}\rightarrow Q and a bonding field β:ℝ+→Z\beta:\mathbb{R}_{+}\rightarrow Z such that for all t∈ℝ+t\in\mathbb{R}_{+}we have

𝝈​(t)=𝒜​𝜺​(𝒖​(t))+∫0tℬ​(t−s)​𝜺​(𝒖​(s))​𝑑s\displaystyle\boldsymbol{\sigma}(t)=\mathcal{A}\boldsymbol{\varepsilon}(\boldsymbol{u}(t))+\int_{0}^{t}\mathcal{B}(t-s)\boldsymbol{\varepsilon}(\boldsymbol{u}(s))ds (4.16)
(𝝈​(t),𝜺​(𝒗)−𝜺​(𝒖​(t)))Q+(P​𝒖​(t),𝒗−𝒖​(t))V\displaystyle(\boldsymbol{\sigma}(t),\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}(\boldsymbol{u}(t)))_{Q}+(P\boldsymbol{u}(t),\boldsymbol{v}-\boldsymbol{u}(t))_{V} (4.17)
+(∫0tb​(t−s)​uν+​(s)​𝑑s,vν+−uν+​(t))L2​(Γ3)+j​(β​(t),𝒖​(t),𝒗−𝒖​(t))\displaystyle\quad+\left(\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds,v_{\nu}^{+}-u_{\nu}^{+}(t)\right)_{L^{2}\left(\Gamma_{3}\right)}+j(\beta(t),\boldsymbol{u}(t),\boldsymbol{v}-\boldsymbol{u}(t))
≥(𝒇​(t),𝒗−𝒖​(t))V∀𝒗∈U\displaystyle\quad\geq(\boldsymbol{f}(t),\boldsymbol{v}-\boldsymbol{u}(t))_{V}\quad\forall\boldsymbol{v}\in U
β​(t)=β0−∫0t(γν​β​(s)​[R​(uν​(s))]2−εa)+​𝑑s\displaystyle\beta(t)=\beta_{0}-\int_{0}^{t}\left(\gamma_{\nu}\beta(s)\left[R\left(u_{\nu}(s)\right)\right]^{2}-\varepsilon_{a}\right)^{+}ds (4.18)

The existence of the unique solution of Problem 𝒫V\mathcal{P}^{V} is stated below and proved in the next section.

Theorem 4.1 Assume that (3.2), (3.3), 3.7), (3.11), 3.14, (3.21), 3.261), and (3.27) hold. Then, there exists a unique solution ( 𝒖,𝝈,β\boldsymbol{u},\boldsymbol{\sigma},\beta ) of Problem 𝒫V\mathcal{P}^{V}. Moreover, the solution satisfies,

𝒖∈C​(ℝ+;U),𝝈∈C​(ℝ+;Q),β∈C​(ℝ+;Z).\boldsymbol{u}\in C\left(\mathbb{R}_{+};U\right),\quad\boldsymbol{\sigma}\in C\left(\mathbb{R}_{+};Q\right),\quad\beta\in C\left(\mathbb{R}_{+};Z\right). (4.19)

We conclude that, under assumptions of Theorem 4.1, Problem 𝒫\mathcal{P} has a unique weak solution with regularity (4.19).

We end this section with some inequalities involving the functional jj which will be used in the proof of Theorem 4.1. Below in this section β,β1\beta,\beta_{1}, and β2\beta_{2} denote elements of ZZ while 𝒖1,𝒖2\boldsymbol{u}_{1},\boldsymbol{u}_{2}, and 𝒗\boldsymbol{v} represent elements of VV; recall also that ui​νu_{i\nu} and 𝒖i​τ\boldsymbol{u}_{i\tau} denote the normal component and the tangential part of 𝒖i\boldsymbol{u}_{i}, for i=1,2i=1,2; and, finally, cc denotes a generic positive constant which may depend on Ω,Γ1,Γ2,Γ3,𝒜\Omega,\Gamma_{1},\Gamma_{2},\Gamma_{3},\mathcal{A}, ℬ,pν,pτ,γν\mathcal{B},p_{\nu},p_{\tau},\gamma_{\nu} and LL, but does not depend on tt nor on the rest of the input data, and whose value may change from place to place.

First, we note that jj is linear with respect to the last argument and, therefore,

j​(β,𝒖,−𝒗)=−j​(β,𝒖,𝒗).j(\beta,\boldsymbol{u},-\boldsymbol{v})=-j(\beta,\boldsymbol{u},\boldsymbol{v}). (4.20)

Next, using (4.12) we find that

j​(β1,𝒖1,𝒖2−𝒖1)+j​(β2,𝒖2,𝒖1−𝒖2)\displaystyle j\left(\beta_{1},\boldsymbol{u}_{1},\boldsymbol{u}_{2}-\boldsymbol{u}_{1}\right)+j\left(\beta_{2},\boldsymbol{u}_{2},\boldsymbol{u}_{1}-\boldsymbol{u}_{2}\right)
=∫Γ3γν​β12​(R~​(u1​ν)−R~​(u2​ν))​(u1​ν−u2​ν)​𝑑a\displaystyle=\int_{\Gamma_{3}}\gamma_{\nu}\beta_{1}^{2}\left(\widetilde{R}\left(u_{1\nu}\right)-\widetilde{R}\left(u_{2\nu}\right)\right)\left(u_{1\nu}-u_{2\nu}\right)da
+∫Γ3γν​(β12−β22)​R~​(u2​ν)​(u1​ν−u2​ν)​𝑑a\displaystyle\quad+\int_{\Gamma_{3}}\gamma_{\nu}\left(\beta_{1}^{2}-\beta_{2}^{2}\right)\widetilde{R}\left(u_{2\nu}\right)\left(u_{1\nu}-u_{2\nu}\right)da
+∫Γ3pτ​(β1)​(𝑹∗​(𝒖1​τ)−𝑹∗​(𝒖2​τ))⋅(𝒖2​τ−𝒖1​τ)​𝑑a\displaystyle\quad+\int_{\Gamma_{3}}p_{\tau}\left(\beta_{1}\right)\left(\boldsymbol{R}^{*}\left(\boldsymbol{u}_{1\tau}\right)-\boldsymbol{R}^{*}\left(\boldsymbol{u}_{2\tau}\right)\right)\cdot\left(\boldsymbol{u}_{2\tau}-\boldsymbol{u}_{1\tau}\right)da
+∫Γ3(pτ​(β1)−pτ​(β2))​𝑹∗​(𝒖2​τ)⋅(𝒖2​τ−𝒖1​τ)​𝑑a\displaystyle\quad+\int_{\Gamma_{3}}\left(p_{\tau}\left(\beta_{1}\right)-p_{\tau}\left(\beta_{2}\right)\right)\boldsymbol{R}^{*}\left(\boldsymbol{u}_{2\tau}\right)\cdot\left(\boldsymbol{u}_{2\tau}-\boldsymbol{u}_{1\tau}\right)da

and since

(R~​(u1​ν)−R~​(u2​ν))​(u1​ν−u2​ν)≤0 a.e. on ​Γ3,(𝑹∗​(𝒖1​τ)−𝑹∗​(𝒖2​τ))⋅(𝒖2​τ−𝒖1​τ)≤0 a.e. on ​Γ3,\begin{gathered}\left(\widetilde{R}\left(u_{1\nu}\right)-\widetilde{R}\left(u_{2\nu}\right)\right)\left(u_{1\nu}-u_{2\nu}\right)\leq 0\quad\text{ a.e. on }\Gamma_{3},\\ \left(\boldsymbol{R}^{*}\left(\boldsymbol{u}_{1\tau}\right)-\boldsymbol{R}^{*}\left(\boldsymbol{u}_{2\tau}\right)\right)\cdot\left(\boldsymbol{u}_{2\tau}-\boldsymbol{u}_{1\tau}\right)\leq 0\quad\text{ a.e. on }\Gamma_{3},\end{gathered}

we obtain

j​(β1,𝒖1,𝒖2−𝒖1)+j​(β2,𝒖2,𝒖1−𝒖2)\displaystyle j\left(\beta_{1},\boldsymbol{u}_{1},\boldsymbol{u}_{2}-\boldsymbol{u}_{1}\right)+j\left(\beta_{2},\boldsymbol{u}_{2},\boldsymbol{u}_{1}-\boldsymbol{u}_{2}\right)
≤∫Γ3γν​(β12−β22)​R~​(u2​ν)​(u1​ν−u2​ν)​𝑑a\displaystyle\leq\int_{\Gamma_{3}}\gamma_{\nu}\left(\beta_{1}^{2}-\beta_{2}^{2}\right)\widetilde{R}\left(u_{2\nu}\right)\left(u_{1\nu}-u_{2\nu}\right)da
+∫Γ3(pτ​(β1)−pτ​(β2))​𝑹∗​(𝒖2​τ)⋅(𝒖2​τ−𝒖1​τ)​𝑑a\displaystyle\quad+\int_{\Gamma_{3}}\left(p_{\tau}\left(\beta_{1}\right)-p_{\tau}\left(\beta_{2}\right)\right)\boldsymbol{R}^{*}\left(\boldsymbol{u}_{2\tau}\right)\cdot\left(\boldsymbol{u}_{2\tau}-\boldsymbol{u}_{1\tau}\right)da

Using now the inequalities |R~​(u2​ν)|≤L,‖𝑹∗​(𝒖2​τ)‖≤L,|β1|≤1,|β2|≤1\left|\widetilde{R}\left(u_{2\nu}\right)\right|\leq L,\left\|\boldsymbol{R}^{*}\left(\boldsymbol{u}_{2\tau}\right)\right\|\leq L,\left|\beta_{1}\right|\leq 1,\left|\beta_{2}\right|\leq 1, valid a.e. on Γ3\Gamma_{3}, and the property (3.21) (c) of the function pτp_{\tau}, we deduce that

j​(β1,𝒖1,𝒖2−𝒖1)+j​(β2,𝒖2,𝒖1−𝒖2)≤c​∫Γ3|β1−β2|​‖𝒖1−𝒖2‖V​𝑑a.\begin{array}[]{r}j\left(\beta_{1},\boldsymbol{u}_{1},\boldsymbol{u}_{2}-\boldsymbol{u}_{1}\right)+j\left(\beta_{2},\boldsymbol{u}_{2},\boldsymbol{u}_{1}-\boldsymbol{u}_{2}\right)\\ \quad\leq c\int_{\Gamma_{3}}\left|\beta_{1}-\beta_{2}\right|\left\|\boldsymbol{u}_{1}-\boldsymbol{u}_{2}\right\|_{V}da.\end{array}

Next, we combine the previous inequality with (2.1) to obtain

j​(β1,𝒖1,𝒖2−𝒖1)+j​(β2,𝒖2,𝒖1−𝒖2)≤c​‖β1−β2‖L2​(Γ3)​‖𝒖1−𝒖2‖V.\begin{array}[]{r}j\left(\beta_{1},\boldsymbol{u}_{1},\boldsymbol{u}_{2}-\boldsymbol{u}_{1}\right)+j\left(\beta_{2},\boldsymbol{u}_{2},\boldsymbol{u}_{1}-\boldsymbol{u}_{2}\right)\\ \leq c\left\|\beta_{1}-\beta_{2}\right\|_{L^{2}\left(\Gamma_{3}\right)}\left\|\boldsymbol{u}_{1}-\boldsymbol{u}_{2}\right\|_{V}.\end{array}

We now choose β1=β2=β\beta_{1}=\beta_{2}=\beta in (4.21) to find that

j​(β,𝒖1,𝒖2−𝒖1)+j​(β,𝒖2,𝒖1−𝒖2)≤0.j\left(\beta,\boldsymbol{u}_{1},\boldsymbol{u}_{2}-\boldsymbol{u}_{1}\right)+j\left(\beta,\boldsymbol{u}_{2},\boldsymbol{u}_{1}-\boldsymbol{u}_{2}\right)\leq 0. (4.22)

Similar manipulations, based on the Lipschitz continuity of the truncation operators R~\widetilde{R} and 𝑹∗\boldsymbol{R}^{*} and on the boundedness of the function pτp_{\tau}, show that

|j​(β,𝒖1,𝒗)−j​(β,𝒖2,𝒗)|≤c​‖𝒖1−𝒖2‖V​‖𝒗‖V\left|j\left(\beta,\boldsymbol{u}_{1},\boldsymbol{v}\right)-j\left(\beta,\boldsymbol{u}_{2},\boldsymbol{v}\right)\right|\leq c\left\|\boldsymbol{u}_{1}-\boldsymbol{u}_{2}\right\|_{V}\|\boldsymbol{v}\|_{V} (4.23)

Inequalities (4.21)-(4.23) and equality (4.20) will be used in various places in the next section.

5 Proof of Theorem 4.1

The proof of Theorem 4.1 will be carried out in several steps. To present it everywhere below we assume that the hypothesis (3.2), (3.3), (3.7), (3.11), (3.14), (3.21), (3.26), and (3.27) hold. Also, we use the product space X=Q×L2​(Γ3)×L2​(Γ3)X=Q\times L^{2}\left(\Gamma_{3}\right)\times L^{2}\left(\Gamma_{3}\right), endowed with the norm

‖𝜼‖X=‖𝜽‖Q+‖ζ‖L2​(Γ3)+‖β‖L2​(Γ3)∀𝜼=(𝜽,ζ,β)∈X.\|\boldsymbol{\eta}\|_{X}=\|\boldsymbol{\theta}\|_{Q}+\|\zeta\|_{L^{2}\left(\Gamma_{3}\right)}+\|\beta\|_{L^{2}\left(\Gamma_{3}\right)}\quad\forall\boldsymbol{\eta}=(\boldsymbol{\theta},\zeta,\beta)\in X.

Let 𝜼=(𝜽,ζ,β)∈C​(ℝ+;Q×L2​(Γ3)×Z)\boldsymbol{\eta}=(\boldsymbol{\theta},\zeta,\beta)\in C\left(\mathbb{R}_{+};Q\times L^{2}\left(\Gamma_{3}\right)\times Z\right). In the first step we consider the following variational problem.

Problem 𝒫ηV\mathcal{P}_{\eta}^{V}. Find a displacement field 𝒖η:ℝ+→U\boldsymbol{u}_{\eta}:\mathbb{R}_{+}\rightarrow U such that, for all t∈ℝ+t\in\mathbb{R}_{+}, 𝒖η​(t)∈U\boldsymbol{u}_{\eta}(t)\in U and

(𝒜​𝜺​(𝒖η​(t)),𝜺​(𝒗)−𝜺​(𝒖η​(t)))Q+(𝜽​(t),𝜺​(𝒗)−𝜺​(𝒖η​(t)))Q\displaystyle\left(\mathcal{A}\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\eta}(t)\right),\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\eta}(t)\right)\right)_{Q}+\left(\boldsymbol{\theta}(t),\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\eta}(t)\right)\right)_{Q} (5.1)
+(P​𝒖η​(t),𝒗−𝒖η​(t))V+(ζ+​(t),vν+−uη​ν+​(t))L2​(Γ3)\displaystyle\quad+\left(P\boldsymbol{u}_{\eta}(t),\boldsymbol{v}-\boldsymbol{u}_{\eta}(t)\right)_{V}+\left(\zeta^{+}(t),v_{\nu}^{+}-u_{\eta\nu}^{+}(t)\right)_{L^{2}\left(\Gamma_{3}\right)}
+j​(β​(t),𝒖η​(t),𝒗−𝒖η​(t))≥(𝒇​(t),𝒗−𝒖η​(t))V∀𝒗∈U.\displaystyle\quad+j\left(\beta(t),\boldsymbol{u}_{\eta}(t),\boldsymbol{v}-\boldsymbol{u}_{\eta}(t)\right)\geq\left(\boldsymbol{f}(t),\boldsymbol{v}-\boldsymbol{u}_{\eta}(t)\right)_{V}\quad\forall\boldsymbol{v}\in U.

We have the following result concerning this problem.

Lemma 5.1 There exists a unique solution to Problem 𝒫ηV\mathcal{P}_{\eta}^{V} which satisfies 𝒖η∈C​(ℝ+;U)\boldsymbol{u}_{\eta}\in C\left(\mathbb{R}_{+};U\right). Moreover, if 𝒖i\boldsymbol{u}_{i} represents the solution of Problem 𝒫ηV\mathcal{P}_{\eta}^{V} for 𝜼=𝜼i∈C​(ℝ+;Q×L2​(Γ3)×Z),i=1,2\boldsymbol{\eta}=\boldsymbol{\eta}_{i}\in C\left(\mathbb{R}_{+};Q\times L^{2}\left(\Gamma_{3}\right)\times Z\right),i=1,2, then there exists c>0c>0 such that

‖𝒖1​(t)−𝒖2​(t)‖V≤c​‖𝜼1​(t)−𝜼2​(t)‖X∀t∈ℝ+\left\|\boldsymbol{u}_{1}(t)-\boldsymbol{u}_{2}(t)\right\|_{V}\leq c\left\|\boldsymbol{\eta}_{1}(t)-\boldsymbol{\eta}_{2}(t)\right\|_{X}\quad\forall t\in\mathbb{R}_{+} (5.2)

Proof. Let t∈ℝ+t\in\mathbb{R}_{+}and consider the operator Aη​t:V→VA_{\eta t}:V\rightarrow V and the functional φη​t:V→ℝ\varphi_{\eta t}:V\rightarrow\mathbb{R} defined by

(Aη​t​𝒖,𝒗)V=(𝒜​𝜺​(𝒖),𝜺​(𝒗))Q+(P​𝒖,𝒗)V+j​(β​(t),𝒖,𝒗)∀𝒖,𝒗∈V\displaystyle\left(A_{\eta t}\boldsymbol{u},\boldsymbol{v}\right)_{V}=(\mathcal{A}\boldsymbol{\varepsilon}(\boldsymbol{u}),\boldsymbol{\varepsilon}(\boldsymbol{v}))_{Q}+(P\boldsymbol{u},\boldsymbol{v})_{V}+j(\beta(t),\boldsymbol{u},\boldsymbol{v})\quad\forall\boldsymbol{u},\boldsymbol{v}\in V (5.3)
φη​t​(𝒗)=(𝜽​(t),𝜺​(𝒗))Q+(ζ+​(t),vν+)L2​(Γ3)∀𝒗∈V\displaystyle\varphi_{\eta t}(\boldsymbol{v})=(\boldsymbol{\theta}(t),\boldsymbol{\varepsilon}(\boldsymbol{v}))_{Q}+\left(\zeta^{+}(t),v_{\nu}^{+}\right)_{L^{2}\left(\Gamma_{3}\right)}\quad\forall\boldsymbol{v}\in V (5.4)

We use (3.2), (4.10), (4.20), (4.22) and (4.23) to see that the operator Aη​tA_{\eta t} is strongly monotone and Lipschitz continuous; moreover, it is easy to see that the functional φη​t\varphi_{\eta t} is convex and lower semicontinuous and, in addition, the set UU is a closed convex nonempty subset of VV. Using these ingredients, it follows from standard arguments on variational inequalities (see, for instance Theorem 2.8 in [22]) that there exists a unique element 𝒖η​t∈U\boldsymbol{u}_{\eta t}\in U such that

(Aη​t​𝒖η​t,𝒗−𝒖η​t)V+φη​t​(𝒗)−φη​t​(𝒖η​t)≥(𝒇​(t),𝒗−𝒖η​t)V∀𝒗∈U.\left(A_{\eta t}\boldsymbol{u}_{\eta t},\boldsymbol{v}-\boldsymbol{u}_{\eta t}\right)_{V}+\varphi_{\eta t}(\boldsymbol{v})-\varphi_{\eta t}\left(\boldsymbol{u}_{\eta t}\right)\geq\left(\boldsymbol{f}(t),\boldsymbol{v}-\boldsymbol{u}_{\eta t}\right)_{V}\quad\forall\boldsymbol{v}\in U. (5.5)

Denote 𝒖η​(t)=𝒖η​t\boldsymbol{u}_{\eta}(t)=\boldsymbol{u}_{\eta t}. Then, it follows from (5.3)-(5.5) that the element 𝒖η​(t)∈U\boldsymbol{u}_{\eta}(t)\in U is the unique element which solves the variational inequality (5.1).

We now prove the continuity of the function t↦𝒖η​(t):ℝ+→Vt\mapsto\boldsymbol{u}_{\eta}(t):\mathbb{R}_{+}\rightarrow V. To this end, let t1,t2∈ℝ+t_{1},t_{2}\in\mathbb{R}_{+}and denote 𝒖η​(ti)=𝒖i,𝜽​(ti)=𝜽i,ζ​(ti)=ζi,β​(ti)=βi,𝒇​(ti)=𝒇i\boldsymbol{u}_{\eta}\left(t_{i}\right)=\boldsymbol{u}_{i},\boldsymbol{\theta}\left(t_{i}\right)=\boldsymbol{\theta}_{i},\zeta\left(t_{i}\right)=\zeta_{i},\beta\left(t_{i}\right)=\beta_{i},\boldsymbol{f}\left(t_{i}\right)=\boldsymbol{f}_{i}, for i=1,2i=1,2. We use standard arguments in (5.1) to find that

(𝒜​ε​(𝒖1)−𝒜​ε​(𝒖2),𝜺​(𝒖1)−𝜺​(𝒖2))Q+(P​𝒖1−P​𝒖2,𝒖1−𝒖2)V\displaystyle\left(\mathcal{A}\varepsilon\left(\boldsymbol{u}_{1}\right)-\mathcal{A}\varepsilon\left(\boldsymbol{u}_{2}\right),\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{1}\right)-\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{2}\right)\right)_{Q}+\left(P\boldsymbol{u}_{1}-P\boldsymbol{u}_{2},\boldsymbol{u}_{1}-\boldsymbol{u}_{2}\right)_{V}
≤(𝜽1−𝜽2,𝜺​(𝒖2)−𝜺​(𝒖1))Q+(ζ1+−ζ2+,u2​ν+−u1​ν+)L2​(Γ3)\displaystyle\quad\leq\left(\boldsymbol{\theta}_{1}-\boldsymbol{\theta}_{2},\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{2}\right)-\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{1}\right)\right)_{Q}+\left(\zeta_{1}^{+}-\zeta_{2}^{+},u_{2\nu}^{+}-u_{1\nu}^{+}\right)_{L^{2}\left(\Gamma_{3}\right)}
+j​(β1,𝒖1,𝒖2−𝒖1)+j​(β2,𝒖2,𝒖1−𝒖2)+(𝒇1−𝒇2,𝒖1−𝒖2)V\displaystyle\quad+j\left(\beta_{1},\boldsymbol{u}_{1},\boldsymbol{u}_{2}-\boldsymbol{u}_{1}\right)+j\left(\beta_{2},\boldsymbol{u}_{2},\boldsymbol{u}_{1}-\boldsymbol{u}_{2}\right)+\left(\boldsymbol{f}_{1}-\boldsymbol{f}_{2},\boldsymbol{u}_{1}-\boldsymbol{u}_{2}\right)_{V}

Therefore, (3.2), (4.10), (4.21) and (2.1) yield

‖𝒖1−𝒖2‖V\displaystyle\left\|\boldsymbol{u}_{1}-\boldsymbol{u}_{2}\right\|_{V} (5.6)
≤c​(‖𝜽1−𝜽2‖Q+‖ζ1−ζ2‖L2​(Γ3)+‖β1−β2‖L2​(Γ3)+‖𝒇1−𝒇2‖V)\displaystyle\quad\leq c\left(\left\|\boldsymbol{\theta}_{1}-\boldsymbol{\theta}_{2}\right\|_{Q}+\left\|\zeta_{1}-\zeta_{2}\right\|_{L^{2}\left(\Gamma_{3}\right)}+\left\|\beta_{1}-\beta_{2}\right\|_{L^{2}\left(\Gamma_{3}\right)}+\left\|\boldsymbol{f}_{1}-\boldsymbol{f}_{2}\right\|_{V}\right)

where cc is a positive constant. This inequality combined with (4.11) and the regularity of the functions 𝜽,ζ,β\boldsymbol{\theta},\zeta,\beta show that 𝒖η∈C​(ℝ+;V)\boldsymbol{u}_{\eta}\in C\left(\mathbb{R}_{+};V\right). Thus, we conclude the existence part in Lemma 5.1. The uniqueness part follows from of the unique solvability of (5.1) for each t∈ℝ+t\in\mathbb{R}_{+}. Finally, the estimate (5.2) follows by using simuilar arguments as those used in the proof of the inequality (5.6).

We now consider the operator Λ\Lambda which maps every element 𝜼=(𝜽,ζ,β)∈C​(ℝ+;Q×L2​(Γ3)×Z)\boldsymbol{\eta}=(\boldsymbol{\theta},\zeta,\beta)\in C\left(\mathbb{R}_{+};Q\times L^{2}\left(\Gamma_{3}\right)\times Z\right) into the element Λ​𝜼\Lambda\boldsymbol{\eta} given by

Λ𝜼(t)=(∫0tℬ(t−s)𝜺(𝒖η(s))ds\displaystyle\Lambda\boldsymbol{\eta}(t)=\left(\int_{0}^{t}\mathcal{B}(t-s)\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\eta}(s)\right)ds\right. (5.7)
∫0tb(t−s)uη​ν+(s)ds,(β0−∫0t(γνβ(s)[R(uη​ν(s))]2−εa)+ds)+)\displaystyle\left.\quad\int_{0}^{t}b(t-s)u_{\eta\nu}^{+}(s)ds,\left(\beta_{0}-\int_{0}^{t}\left(\gamma_{\nu}\beta(s)\left[R\left(u_{\eta\nu}(s)\right)\right]^{2}-\varepsilon_{a}\right)^{+}ds\right)^{+}\right)

for all t∈ℝ+t\in\mathbb{R}_{+}. Here 𝒖η∈C​(ℝ+;U)\boldsymbol{u}_{\eta}\in C\left(\mathbb{R}_{+};U\right) is the solution of Problem 𝒫ηV\mathcal{P}_{\eta}^{V} provided in Lemma 5.1. We have the following result.

Lemma 5.2 The operator Λ\Lambda takes values in the set C​(ℝ+;Q×L2​(Γ3)×Z)C\left(\mathbb{R}_{+};Q\times L^{2}\left(\Gamma_{3}\right)\times Z\right). Moreover, it has a unique fixed point 𝜼∗∈C​(ℝ+;Q×L2​(Γ3)×Z)\boldsymbol{\eta}^{*}\in C\left(\mathbb{R}_{+};Q\times L^{2}\left(\Gamma_{3}\right)\times Z\right).

Proof. Let 𝜼=(𝜽,ζ,β)∈C​(ℝ+;Q×L2​(Γ3)×Z)\boldsymbol{\eta}=(\boldsymbol{\theta},\zeta,\beta)\in C\left(\mathbb{R}_{+};Q\times L^{2}\left(\Gamma_{3}\right)\times Z\right) and denote by ω\omega the function defined by

ω​(t)=(β0−∫0t(γν​β​(s)​[R​(uη​ν​(s))]2−εa)+​𝑑s)+∀t∈ℝ+\omega(t)=\left(\beta_{0}-\int_{0}^{t}\left(\gamma_{\nu}\beta(s)\left[R\left(u_{\eta\nu}(s)\right)\right]^{2}-\varepsilon_{a}\right)^{+}ds\right)^{+}\quad\forall t\in\mathbb{R}_{+} (5.8)

Then, using (3.26) and (3.27) it follows that ω​(t)∈L2​(Γ3)\omega(t)\in L^{2}\left(\Gamma_{3}\right) and, moreover, 0≤ω​(t)≤β0≤10\leq\omega(t)\leq\beta_{0}\leq 1 a.e. on Γ3\Gamma_{3}, for all t∈ℝ+t\in\mathbb{R}_{+}. We conclude from here that ω​(t)∈Z\omega(t)\in Z. On the other hand, it is easy to see that t↦Λ​(t)t\mapsto\Lambda(t) is a continuous function from ℝ+\mathbb{R}_{+}to the product space X=Q×L2​(Γ3)×L2​(Γ3)X=Q\times L^{2}\left(\Gamma_{3}\right)\times L^{2}\left(\Gamma_{3}\right), which concludes the first part of the lemma.

For the second part, we consider 𝜼1=(𝜽1,ζ1,β1),𝜼2=(𝜽2,ζ2,β2)∈C​(ℝ+;Q×L2​(Γ3)×Z)\boldsymbol{\eta}_{1}=\left(\boldsymbol{\theta}_{1},\zeta_{1},\beta_{1}\right),\boldsymbol{\eta}_{2}=\left(\boldsymbol{\theta}_{2},\zeta_{2},\beta_{2}\right)\in C\left(\mathbb{R}_{+};Q\times\right.\left.L^{2}\left(\Gamma_{3}\right)\times Z\right) and, for the sake of simplicity, we use the notation 𝒖ηi=𝒖i\boldsymbol{u}_{\eta_{i}}=\boldsymbol{u}_{i}, for i=i= 1,2 . Let n∈ℕn\in\mathbb{N} and let t∈[0,n]t\in[0,n]. We use assumptions (3.3) and (3.14) on ℬ\mathcal{B} and bb, respectively, inequalities (2.2) and (2.1) as well as the bounds |R​(u1​ν​(s))|≤L\left|R\left(u_{1\nu}(s)\right)\right|\leq L, |R​(u2​ν​(s))|≤L,|β1​(s)|≤1,|β2​(s)|≤1\left|R\left(u_{2\nu}(s)\right)\right|\leq L,\left|\beta_{1}(s)\right|\leq 1,\left|\beta_{2}(s)\right|\leq 1, valid a.e. on Γ3\Gamma_{3}, for all s∈[0,t]s\in[0,t]. After some elementary calculation we deduce that

‖Λ​𝜼1​(t)−Λ​𝜼2​(t)‖X≤c​maxs∈[0,n]⁡‖ℬ​(s)‖𝐐∞​∫0t‖𝒖1​(s)−𝒖2​(s)‖V​𝑑s\displaystyle\left\|\Lambda\boldsymbol{\eta}_{1}(t)-\Lambda\boldsymbol{\eta}_{2}(t)\right\|_{X}\leq c\max_{s\in[0,n]}\|\mathcal{B}(s)\|_{\mathbf{Q}_{\infty}}\int_{0}^{t}\left\|\boldsymbol{u}_{1}(s)-\boldsymbol{u}_{2}(s)\right\|_{V}ds (5.9)
+c​maxs∈[0,n]⁡‖b​(s)‖L∞​(Γ3)​∫0t‖𝒖1​(s)−𝒖2​(s)‖V​𝑑s\displaystyle\quad+c\max_{s\in[0,n]}\|b(s)\|_{L^{\infty}\left(\Gamma_{3}\right)}\int_{0}^{t}\left\|\boldsymbol{u}_{1}(s)-\boldsymbol{u}_{2}(s)\right\|_{V}ds
+c​(∫0t‖𝒖1​(s)−𝒖2​(s)‖V​𝑑s+∫0t‖β1​(s)−β2​(s)‖L2​(Γ3)​𝑑s)\displaystyle\quad+c\left(\int_{0}^{t}\left\|\boldsymbol{u}_{1}(s)-\boldsymbol{u}_{2}(s)\right\|_{V}ds+\int_{0}^{t}\left\|\beta_{1}(s)-\beta_{2}(s)\right\|_{L^{2}\left(\Gamma_{3}\right)}ds\right)

where, here and below, cc represent various positive constants which do not depend on nn. We conclude from here that

‖Λ​𝜼1​(t)−Λ​𝜼2​(t)‖X\displaystyle\left\|\Lambda\boldsymbol{\eta}_{1}(t)-\Lambda\boldsymbol{\eta}_{2}(t)\right\|_{X} (5.10)
≤cn​∫0t‖𝒖1​(s)−𝒖2​(s)‖V​𝑑s+c​∫0t‖β1​(s)−β2​(s)‖L2​(Γ3)​𝑑s\displaystyle\quad\leq c_{n}\int_{0}^{t}\left\|\boldsymbol{u}_{1}(s)-\boldsymbol{u}_{2}(s)\right\|_{V}ds+c\int_{0}^{t}\left\|\beta_{1}(s)-\beta_{2}(s)\right\|_{L^{2}\left(\Gamma_{3}\right)}ds

where now cnc_{n} represent various positive constants which depend on nn. We now combine the inequalities (5.10) and (5.2) to deduce that

‖Λ​𝜼1​(t)−Λ​𝜼2​(t)‖X≤cn​∫0t‖𝜼1​(s)−𝜼2​(s)‖X​𝑑s\left\|\Lambda\boldsymbol{\eta}_{1}(t)-\Lambda\boldsymbol{\eta}_{2}(t)\right\|_{X}\leq c_{n}\int_{0}^{t}\left\|\boldsymbol{\eta}_{1}(s)-\boldsymbol{\eta}_{2}(s)\right\|_{X}ds

and we note that, obviously, Q×L2​(Γ3)×ZQ\times L^{2}\left(\Gamma_{3}\right)\times Z is a closed subset of the space XX. These ingredients allow us to apply Theorem 2.1 to conclude the proof.

Now, we have all the ingredients needed to prove Theorem 4.1.
Existence. Let 𝜼∗=(𝜽∗,ζ∗,β∗)∈C​(ℝ+;Q×L2​(Γ3)×Z)\boldsymbol{\eta}^{*}=\left(\boldsymbol{\theta}^{*},\zeta^{*},\beta^{*}\right)\in C\left(\mathbb{R}_{+};Q\times L^{2}\left(\Gamma_{3}\right)\times Z\right) be the fixed point of Λ\Lambda and let 𝒖∗,𝝈∗\boldsymbol{u}^{*},\boldsymbol{\sigma}^{*} be the functions defined by

𝒖∗​(t)\displaystyle\boldsymbol{u}^{*}(t) =𝒖η∗​(t)\displaystyle=\boldsymbol{u}_{\eta^{*}}(t) (5.11)
𝝈∗​(t)\displaystyle\boldsymbol{\sigma}^{*}(t) =𝒜​𝜺​(𝒖∗​(t))+∫0tℬ​(t−s)​𝜺​(𝒖∗​(s))​𝑑s\displaystyle=\mathcal{A}\boldsymbol{\varepsilon}\left(\boldsymbol{u}^{*}(t)\right)+\int_{0}^{t}\mathcal{B}(t-s)\boldsymbol{\varepsilon}\left(\boldsymbol{u}^{*}(s)\right)ds (5.12)

for all t∈ℝ+t\in\mathbb{R}_{+}. We recall that 𝜼∗=Λ​𝜼∗\boldsymbol{\eta}^{*}=\Lambda\boldsymbol{\eta}^{*} and, using the equalities (5.7), (5.11) and assumption (3.14) we deduce that

𝜽∗​(t)\displaystyle\boldsymbol{\theta}^{*}(t) =∫0tℬ​(t−s)​𝜺​(𝒖∗​(s))​𝑑s\displaystyle=\int_{0}^{t}\mathcal{B}(t-s)\boldsymbol{\varepsilon}\left(\boldsymbol{u}^{*}(s)\right)ds (5.13)
ζ∗+​(t)\displaystyle\zeta^{*+}(t) =∫0tb​(t−s)​uν∗+​(s)​𝑑s\displaystyle=\int_{0}^{t}b(t-s)u_{\nu}^{*+}(s)ds (5.14)
β∗​(t)\displaystyle\beta^{*}(t) =(β0−∫0t(γν​β∗​(s)​[R​(uν∗​(s))]2−εa)+​𝑑s)+\displaystyle=\left(\beta_{0}-\int_{0}^{t}\left(\gamma_{\nu}\beta^{*}(s)\left[R\left(u_{\nu}^{*}(s)\right)\right]^{2}-\varepsilon_{a}\right)^{+}ds\right)^{+} (5.15)

for all t∈ℝ+t\in\mathbb{R}_{+}. We show that (𝒖∗,𝝈∗,β∗)\left(\boldsymbol{u}^{*},\boldsymbol{\sigma}^{*},\beta^{*}\right) satisfies the system (4.16)-(4.18).
First, we note that (4.16) is a direct consequence of (5.12). Next, we write the variational inequality (5.1) for 𝜼=𝜼∗\boldsymbol{\eta}=\boldsymbol{\eta}^{*} and use the equalities (5.11)-(5.14) to see that (4.17) holds. And, finally, we claim that (4.18) also holds. Indeed, let ω∗\omega^{*} be the function defined by

ω∗​(t)=β0−∫0t(γν​β∗​(s)​[R​(uν∗​(s))]2−εa)+​𝑑s∀t∈ℝ+\omega^{*}(t)=\beta_{0}-\int_{0}^{t}\left(\gamma_{\nu}\beta^{*}(s)\left[R\left(u_{\nu}^{*}(s)\right)\right]^{2}-\varepsilon_{a}\right)^{+}ds\quad\forall t\in\mathbb{R}_{+} (5.16)

A careful examination of equalities (5.16) and (5.15) show that the following properties hold, a.e. on Γ3:t↦ω∗​(t)\Gamma_{3}:t\mapsto\omega^{*}(t) is a non increasing function, ω​(0)=β0≥0\omega(0)=\beta_{0}\geq 0 and, if there exists t0∈ℝ+t_{0}\in\mathbb{R}_{+}such that ω​(t0)=0\omega\left(t_{0}\right)=0, then ω​(t)=0\omega(t)=0 for all t≥t0t\geq t_{0}. We deduce from here that ω∗​(t)≥0\omega^{*}(t)\geq 0 for any t∈ℝ+t\in\mathbb{R}_{+}. Therefore, since (5.15) and (5.16) imply that β∗​(t)=ω∗​(t)+\beta^{*}(t)=\omega^{*}(t)^{+}we find that

β∗​(t)=ω∗​(t)∀t∈ℝ+\beta^{*}(t)=\omega^{*}(t)\quad\forall t\in\mathbb{R}_{+} (5.17)

Equality (4.18) is now a direct consequence of the equalities (5.16) and (5.17).
This proves that the triple (𝒖∗,𝝈∗,β∗)\left(\boldsymbol{u}^{*},\boldsymbol{\sigma}^{*},\beta^{*}\right) represents a solution of Problem 𝒫V\mathcal{P}^{V}. The regularity expressed in (4.19) is a direct consequence of the Lemmas 5.1 and 5.2 , combined with assumptions (3.2) and (3.3).

Uniqueness. The uniqueness of the solution follows from the uniqueness of the fixed point of operator Λ\Lambda defined by (5.7) combined with the unique solvability of Problem
𝒫ηV\mathcal{P}_{\eta}^{V}. Indeed, let (𝒖,𝝈,β)(\boldsymbol{u},\boldsymbol{\sigma},\beta) be a solution of Problem 𝒫V\mathcal{P}^{V} which satisfies (4.19) and let 𝜼=(𝜽,ζ,β)∈C​(ℝ+;Q×L2​(Γ3)×Z)\boldsymbol{\eta}=(\boldsymbol{\theta},\zeta,\beta)\in C\left(\mathbb{R}_{+};Q\times L^{2}\left(\Gamma_{3}\right)\times Z\right) be given by

𝜼​(t)=\displaystyle\boldsymbol{\eta}(t)= (∫0tℬ(t−s)𝜺(𝒖(s))ds\displaystyle\left(\int_{0}^{t}\mathcal{B}(t-s)\boldsymbol{\varepsilon}(\boldsymbol{u}(s))ds\right. (5.18)
∫0tb(t−s)uν+(s)ds,(β0−∫0t(γνβ(s)[R(uν(s))]2−εa)+ds)+)\displaystyle\left.\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds,\left(\beta_{0}-\int_{0}^{t}\left(\gamma_{\nu}\beta(s)\left[R\left(u_{\nu}(s)\right)\right]^{2}-\varepsilon_{a}\right)^{+}ds\right)^{+}\right)

for all t∈ℝ+t\in\mathbb{R}_{+}. We substitute equality (4.16) in (4.17) and, using (5.18), we deduce that 𝒖\boldsymbol{u} satisfies the inequality (5.1), at each time moment t∈ℝ+t\in\mathbb{R}_{+}. On the other hand, it follows from Lemma 5.1 that Problem 𝒫ηV\mathcal{P}_{\eta}^{V} has a unique solution, denoted 𝒖η\boldsymbol{u}_{\eta}, with regularity 𝒖η∈C​(ℝ+;U)\boldsymbol{u}_{\eta}\in C\left(\mathbb{R}_{+};U\right). Therefore, we conclude that

𝒖=𝒖η.\boldsymbol{u}=\boldsymbol{u}_{\eta}. (5.19)

We use (5.19) to see that

∫0tℬ​(t−s)​𝜺​(𝒖η​(s))​𝑑s=∫0tℬ​(t−s)​𝜺​(𝒖​(s))​𝑑s∫0tb​(t−s)​uη​ν+​(s)​𝑑s=∫0tb​(t−s)​uν+​(s)​𝑑s(β0−∫0t(γν​β​(s)​[R​(uη​ν​(s))]2−εa)+​𝑑s)+=(β0−∫0t(γν​β​(s)​[R​(uν​(s))]2−εa)+​𝑑s)+\begin{gathered}\int_{0}^{t}\mathcal{B}(t-s)\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\eta}(s)\right)ds=\int_{0}^{t}\mathcal{B}(t-s)\boldsymbol{\varepsilon}(\boldsymbol{u}(s))ds\\ \int_{0}^{t}b(t-s)u_{\eta\nu}^{+}(s)ds=\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds\\ \left(\beta_{0}-\int_{0}^{t}\left(\gamma_{\nu}\beta(s)\left[R\left(u_{\eta\nu}(s)\right)\right]^{2}-\varepsilon_{a}\right)^{+}ds\right)^{+}\\ =\left(\beta_{0}-\int_{0}^{t}\left(\gamma_{\nu}\beta(s)\left[R\left(u_{\nu}(s)\right)\right]^{2}-\varepsilon_{a}\right)^{+}ds\right)^{+}\end{gathered}

for all t∈ℝ+t\in\mathbb{R}_{+}. Therefore, (5.7) and (5.18) show that Λ​𝜼=𝜼\Lambda\boldsymbol{\eta}=\boldsymbol{\eta} and, using the uniqueness part in Lemma 5.2, we deduce that

η=η∗.\eta=\eta^{*}. (5.20)

We now use (5.19), (5.20) and (5.11) to see that

𝒖=𝒖η=𝒖η∗=𝒖∗.\boldsymbol{u}=\boldsymbol{u}_{\eta}=\boldsymbol{u}_{\eta^{*}}=\boldsymbol{u}^{*}. (5.21)

Then we use (4.16), (5.21) and (5.12) to deduce that

𝝈​(t)\displaystyle\boldsymbol{\sigma}(t) =𝒜​𝜺​(𝒖​(t))+∫0tℬ​(t−s)​𝜺​(𝒖​(s))​𝑑s\displaystyle=\mathcal{A}\boldsymbol{\varepsilon}(\boldsymbol{u}(t))+\int_{0}^{t}\mathcal{B}(t-s)\boldsymbol{\varepsilon}(\boldsymbol{u}(s))ds (5.22)
=𝒜​𝜺​(𝒖∗​(t))+∫0tℬ​(t−s)​𝜺​(𝒖∗​(s))​𝑑s=𝝈∗​(t)∀t∈ℝ+\displaystyle=\mathcal{A}\boldsymbol{\varepsilon}\left(\boldsymbol{u}^{*}(t)\right)+\int_{0}^{t}\mathcal{B}(t-s)\boldsymbol{\varepsilon}\left(\boldsymbol{u}^{*}(s)\right)ds=\boldsymbol{\sigma}^{*}(t)\quad\forall t\in\mathbb{R}_{+}

and, finally, (5.20) and (4.18) show that

β=β∗.\beta=\beta^{*}. (5.23)

The uniqueness part of the theorem is now a consequence of equalities (5.21), (5.22) and (5.23).

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