1973 a -Popoviciu- Demonstratio Math. - On a quadrature formula of S. Golab and C. Olech (1).pd
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Tiberiu Popoviciu
ON A SQUADRATION FORMULA BY S. GOŁAB AND C. OLECH
Dedicated to MS Gołąb on the occasion of his70^("ième ")70^{\text {ième }}birthday
S. Gołąb and C. Olech demonstrated [1] that there exists one and only one number strictly between 0 and 1(0 < (4 < 1)(0<(4<1), so that the quadrature formula
(1)int_(0)^(1)f(x)dx*=lambda_(0)f(0)+lambda_(1)f(0)+lambda_(2)f(1)+R(f)\int_{0}^{1} f(x) d x \cdot=\lambda_{0} f(0)+\lambda_{1} f(0)+\lambda_{2} f(1)+R(f)
be exact for the functions (x^(0)=x^{0}=)1,x^(p),x^(q),x^(r)1, x^{p}, x^{q}, x^{r}, Orp,qp, q,rrare any positive numbers such thatp < q < rp<q<rThe fact that formula (1) is exact for functions 1,x^(p)x^{p},x^(q),x^(r)x^{q}, x^{r}means that
(2)quad R(1)=R(x^(p))=R(x^(q))=R(x^(r))=0\quad R(1)=R\left(x^{p}\right)=R\left(x^{q}\right)=R\left(x^{r}\right)=0.
The coefficientslambda_(0),lambda_(1),lambda_(2)\lambda_{0}, \lambda_{1}, \lambda_{2}are independent of the functionffand can be easily calculated using the equalities (2). We thus obtainlambda_(0)+lambda_(1)+lambda_(2)=1\lambda_{0}+\lambda_{1}+\lambda_{2}=1and
(3a)quadlambda_(1)=(q-p)/((p+1)(q+1)(omega^(p)-theta^(q)))\quad \lambda_{1}=\frac{q-p}{(p+1)(q+1)\left(\omega^{p}-\theta^{q}\right)};
(3b)
Any real power of a positive number is a well-defined positive number. Other determinations of such a power will not be relevant to this discussion. We have0^(sigma)=00^{\sigma}=0if 6 is positive. The functionx^(6)x^{6}is therefore defined, uniform, continuous and infinitely differentiable on the positive real axis, for any real exponentsigma^(')\sigma^{\prime}. Forsigma=0\sigma=0this function reduces to the constant 1. Ifsigma > 0\sigma>0the functionxxis defined and continuous forx >= 0x \geqslant 0.
which, as S. Goląb and C. Olech have shown [1], has exactly one and only one root in the open interval]0,1[] 0,1[In the work cited fromSSGołąb and C. Olech assume that the exponentsp,q,rp, q, rare (positive) integers. Following their proof, we can easily see that this restriction is not necessary. We will therefore only assume that0 < p < q < r0<p<q<r.
Formula (1) is an interesting generalization of Simpson's formula; the latter is obtained by takingp=1;q=2,r=3p=1 ; q=2, r=3.
In this work we propose to study the remainderR(1)R(1)of formula (1), under well-defined assumptions made about the functionff。
Beforehand, we will establish some results which, being of interest in themselves, can be used in the study of other problems, analogous to the one dealt with in this work.
1st order determinantnnvalues ​​of the functionsg_(t),t==1,2,dots,ng_{t}, t= =1,2, \ldots, non the pointsx_(i),i=1,2,dots,nx_{i}, i=1,2, \ldots, nIn this determinantg_(t)(x_(i))g_{t}\left(x_{i}\right)is the element that is located in the i-th row and twi-th column.
The determinant (5) is obviously zero if the pointsx_( hat(1))x_{\hat{1}}or if the functionsg_(t)g_{t}are not distinct.
If the pointsx_(i)x_{i}are not distinct, notation (5) will be used for a suitably modified determinant. This modification consists of replacing the lines corresponding to each group of pointsx_(i)x_{i}confused by lines formed by the values ​​of the functionsg_(t)g_{t}and their successive derivatives at these points. This implies, of course, the existence of the derivatives considered. More precisely, letz_(1),z_(2),dots,z_(m)z_{1}, z_{2}, \ldots, z_{m}the distinct points with which coincide respectivelyk_(1),k_(2),dots,k_(1n)quad(k_(1),k_(2,):}dots,k_(m) >= 1k_{1}, k_{2}, \ldots, k_{1 n} \quad\left(k_{1}, k_{2,}\right. \ldots, k_{m} \geqslant 1) pointsx_(i)x_{i}So for everythingi=1,2,dots,mi=1,2, \ldots, m, there is exactlyk_(i)k_{i}lines made up of the function valuesg_(t)g_{t}and theirk_(i)-1k_{i}-1first derivatives on the pointz_(j)z_{j}.
the determinant thus modified. But it is important to precede the succession of lines of the determinant thus defined, which is indeed of orderk_(1)+k_(2)+dots+k_(m)=nk_{1}+k_{2}+\ldots+k_{m}=n.
We will denote by (6) the determinant of order n whose(k_(1)+k_(2)+dots+k_(i-1)+j)^(i" emes ")\left(k_{1}+k_{2}+\ldots+k_{i-1}+j\right)^{i \text { emes }}lines_(beta){ }_{\beta}for consecutive values ​​1, 2, ...,k_(i)k_{i}ofjj, taken in this order, are the following
(7)quad{[g_(1)(z_(i)),g_(2)(z_(i)),cdots,g_(n)(z_(i))],[g_(1)^(')(z_(i)),g_(2)^(')(z_(i)),cdots,g_(n)^(')(z_(i))],[*,cdots,*,cdots],[(k_(i)-1),(z_(i)),g_(2)(k_(i)-1),(z_(i))]cdots*g_(n)^((k_(i)-1))(z_(i)):}\quad\left\{\begin{array}{llll}g_{1}\left(z_{i}\right) & g_{2}\left(z_{i}\right) & \cdots & g_{n}\left(z_{i}\right) \\ g_{1}^{\prime}\left(z_{i}\right) & g_{2}^{\prime}\left(z_{i}\right) & \cdots & g_{n}^{\prime}\left(z_{i}\right) \\ \cdot & \cdots & \cdot & \cdots \\ \left(k_{i}-1\right) & \left(z_{i}\right) & g_{2}\left(k_{i}-1\right) & \left(z_{i}\right)\end{array} \cdots \cdot g_{n}^{\left(k_{i}-1\right)}\left(z_{i}\right)\right..
The sumk_(1)+k_(2)+dots+k_(i-1)k_{1}+k_{2}+\ldots+k_{i-1}is replaced by 0 fori=1i=1and the accents denote successive derivations.
The lines (7) are consecutive lines in the determinant (6). With this convention the succession of columns and lines is clearly specified in the determinant (6).
Of course, the modified determinant (6) is well-defined even if the pointsz_(1),z_(2),dots,z_(m)z_{1}, z_{2}, \ldots, z_{m}are not distinct, but then it is obviously equal to 0.
Everything comes down, we sum up, to asking
(8)x_(k_(1)+k_(2)+dots+k_(i-1)+j)=z_(i),j=1,2,dots,k_(i),i=1,2,dots,mx_{k_{1}+k_{2}+\ldots+k_{i-1}+j}=z_{i}, j=1,2, \ldots, k_{i}, i=1,2, \ldots, m.
It is important to note that, in general, the lines of the determinant cannot be subjected to any permutation, since the order of these lines has been fixed in advance. By this we mean that, to take an example, while the determinantV([E_(1)",",E_(2)",",E_(3)],[z_(1)",",z_(1)",",z_(2)])V\left(\begin{array}{lll}E_{1}, & E_{2}, & E_{3} \\ z_{1}, & z_{1}, & z_{2}\end{array}\right)is always defined, the symbolV([g_(1)",",g_(2)",",g_(3)],[z_(1)",",z_(2)",",z_(1)])V\left(\begin{array}{lll}g_{1}, & g_{2}, & g_{3} \\ z_{1}, & z_{2}, & z_{1}\end{array}\right)means nothing ifz_(1)!=z_(2)z_{1} \neq z_{2}.
On the contrary, we can subject the lines of the determinant to a permutation by group of points combined; which amounts, in short, to a permutation of the pointsz_(i)z_{i}More precisely, eitherv_(1),v_(2),dots,v_(n)v_{1}, v_{2}, \ldots, v_{n}a permutation of indices1,2,dots,n1,2, \ldots, nLet us then assume, to simplify the notation.x_(i)^(')=x_(v_(i)),i=1,2,dots,nx_{i}^{\prime}=x_{v_{i}}, i=1,2, \ldots, nThe determinant (6), with the corresponding rows permuted, is then
1a succession of lines for a group of pointsx_(i)^(')x_{i}^{\prime}equals with az_(i)z_{i}being respected according to the rule described by table (7). This means that we only consider permutationsv_(1),v_(2),dots,v_(n)v_{1}, v_{2}, \ldots, v_{n}for which we have
(10)
x_(k_(1)^(')+k_(2)^(')+dots+k_(i-1)^(')+j)^(')=z_(i)^('),j=1,2,dots,k_(i)^('),i=1,2,dots,mx_{k_{1}^{\prime}+k_{2}^{\prime}+\ldots+k_{i-1}^{\prime}+j}^{\prime}=z_{i}^{\prime}, j=1,2, \ldots, k_{i}^{\prime}, i=1,2, \ldots, m
the sequelz_(1)^('),z_(2)^('),dots,z_(m)^(')z_{1}^{\prime}, z_{2}^{\prime}, \ldots, z_{m}^{\prime}being a permutation of the sequencez_(1),z_(2),dots,z_(m)z_{1}, z_{2}, \ldots, z_{m}The value of the determinant (9) differs from that of (6) at most by the sign, according to formula (17) which will be established later.
Let us now point out the following special cases: 1^(@)1^{\circ}For the functionsg_(t)=x^(t-1),t=1,2,dots,ng_{t}=x^{t-1}, t=1,2, \ldots, n, the ending deus (5) reduces to the determinant of VandermondeV(x_(1),x_(2),dots,x_(n))V\left(x_{1}, x_{2}, \ldots, x_{n}\right)numbersx_(1),x_(2),dots,x_(n)x_{1}, x_{2}, \ldots, x_{n}So we have
2^(0)2^{0}In the case where all the pointsx_(i)x_{i}coincident (with x) the modified determinant (6) reduces to the WronskianW(g_(1),g_(2),dots,g_(n))(x)W\left(g_{1}, g_{2}, \ldots, g_{n}\right)(x)functionsg_(t)^(**))g_{t}{ }^{*)}We can therefore write
*) This is why we sometimes call the determinant (5) the Prewronskian of functionsE_(t)\mathrm{E}_{t}.
We can also obtain the modified determinant (6) by a suitable limit. To avoid complicating matters, we will assume that all the derivatives involved exist and are continuous, at least in certain neighborhoods of the pointsz_(1)z_{1}.
So be itnndistinct pointsx_(j)^((i)),j=1,2,dots,k_(j)x_{j}^{(i)}, j=1,2, \ldots, k_{j},i=1,2,dots,m_(", et considérons le déterminant "D)d^(')i=1,2, \ldots, m_{\text {, et considérons le déterminant } D} d^{\prime}ééordernn(=k_(1)+k_(2)+dots+k_(m)=k_{1}+k_{2}+\ldots+k_{m}) of which the element of lå (k_(1)+k_(2)+dots++cdots+k_(i-1)+j)^(ieme)k_{1}+k_{2}+\ldots+ \left.+\cdots+k_{i-1}+j\right)^{i e m e}line and thet^(ieme)t^{i e m e}column is the usual divided difference[x_(1)^((i)),x_(2)^((i)),dots,x_(j)^((i));g_(t)]\left[x_{1}^{(i)}, x_{2}^{(i)}, \ldots, x_{j}^{(i)} ; g_{t}\right]of the functiong_(t)g_{t}on the nodesx_(1)^((i)),x_(2)^((i)),dots,x_(j)^((i))x_{1}^{(i)}, x_{2}^{(i)}, \ldots, x_{j}^{(i)}and wherej==1,2,dots,k_(i),t=1,2,dots,nj= =1,2, \ldots, k_{i}, t=1,2, \ldots, nIf we observe that this divided difference tends towards(1)/((j-1)!)g_(t)^((j cdots1))(z_(1))\frac{1}{(j-1)!} g_{t}^{(j \cdots 1)}\left(z_{1}\right)when the pointsx_(v)^((i)),v=1,2,dots,jx_{v}^{(i)}, v=1,2, \ldots, jtend towardsz_(i)z_{i}, we see that the determinantDDtends towards the modified determinant (6) divided by the numberprod_(i=1)^(m)(k_(i)-1)\prod_{i=1}^{m}\left(k_{i}-1\right)!! whenx_(V)^((i))rarrz_(i),v=1,2,dots,k_(j),i=1,2,dots,m_(0)x_{V}^{(i)} \rightarrow z_{i}, v=1,2, \ldots, k_{j}, i=1,2, \ldots, m_{0}
We use the abbreviated notationalpha!!=1!2!dots alpha\alpha!!=1!2!\ldots \alpha! (0!!=10!!=1).
Finally, if we multiply the determinantDDby the product
and if we perform some elementary operations on the lines, we obtain the determinant
(14)V(x_(1)^((1)),x_(2)^((1)),dots,x_(k_(1))^((1)),x_(1)^((2)),x_(2)^((2)),dots,x_(k_(2))^((2)),dots,x_(1)^((m)),x_(2)^((m)),dots,x_(k_(m))^((m)))V\left(x_{1}^{(1)}, x_{2}^{(1)}, \ldots, x_{k_{1}}^{(1)}, x_{1}^{(2)}, x_{2}^{(2)}, \ldots, x_{k_{2}}^{(2)}, \ldots, x_{1}^{(m)}, x_{2}^{(m)}, \ldots, x_{k_{m}}^{(m)}\right)
It follows that the determinant (6) is obtained by multiplying (14) paxprod_(i=1)^(m)(k_(i)-1)11\prod_{i=1}^{m}\left(k_{i}-1\right) 11, by dividing it by (13) and then making the points stretchx_(j)^((i))x_{j}^{(i)}towardsz_(i)z_{i}, Forj==1,2,dots,k_(i),i=1,2,dots,mj= =1,2, \ldots, k_{i}, i=1,2, \ldots, m,
The concept of difference divided is well known. Wel^("" ")l^{\text {" }}We will employ it in its general form as set forth in the memoir cited below concerning the study of the remainder of formula (1) [5]. The usual divided differences are those with respect to successive non-negative integer powers.1,x,x^(2),dots1, x, x^{2}, \ldots. of the variable.
4. As a first application, we will find the formula giving the value of the generalized Vandermonde determinant
x_(1)^('),x_(2)^('),dots,x_(n)^(')x_{1}^{\prime}, x_{2}^{\prime}, \ldots, x_{n}^{\prime}being an admissible permutation of the sequencex_(1),x_(2),dots,x_(n)x_{1}, x_{2}, \ldots, x_{n}assuming thatx_(1) <= x_(2) <= dots <= x_(n)x_{1} \leqslant x_{2} \leqslant \ldots \leqslant x_{n}and where we employ the function
sg x={[1","," pour "],[0",",x > 0],[-1","," pour "]quad x=0:}\operatorname{sg} x=\left\{\begin{array}{rl}
1, & \text { pour } \\
0, & x>0 \\
-1, & \text { pour }
\end{array} \quad x=0\right.
which satisfies the functional equationsg(xy)=sgx*sgys g(x y)=s g x \cdot s g yForxxAndyyany real numbers.
using notation (10) and assuming thatz_(1) < z_(2)<<dots < z_(m)z_{1}<z_{2}< <\ldots<z_{m}.
Let us note in passing that if among the numbersk_(1,8)k_(2)k_{1,8} k_{2}, ...,k_(m)k_{m}heyya at most one which is odd, the determinant (9) does not depend on the admissible permutationx_(1)^(')x_{1}^{\prime},x_(2)^('),dots,x_(n)^(')dex_{2}^{\prime}, \ldots, x_{n}^{\prime} d ethe sequelx_(1),x_(2),dots,x_(n)x_{1}, x_{2}, \ldots, x_{n}5.
We will now establish a formula that reduces the calculation of a determinant of the form (6) of order n to the calculation of a determinant of the same form but of order n - 1.
Let's modify the lines of the determinant (6) as follows: Let's return to table (7). Leibniz's formula
Orh_(t)=g_(t)//g_(1),t=1,2,dots,nh_{t}=g_{t} / g_{1}, t=1,2, \ldots, n, the functions and derivatives of various orders being calculated at the pointz_(i)z_{i}. Ifk_(i)==1k_{i}= =1No such modification is made to table (7). Note that the elements in the first column of table (18) are all zero.
These results were obtained based on the fact that a determinant does not change value when any linear combination of other rows is added to a row. After these operations, the rows that remained unchanged form the table.
These lines retain their positions in determinant (6). Still without changing the value of determinant (6), we can subtract (i-1).^(ième){ }^{i e ̀ m e}line multiplied by(g_(1)(z_(i)))/(g_(1)(z_(i-1)))\frac{g_{1}\left(z_{i}\right)}{g_{1}\left(z_{i-1}\right)}of thei^(i)i^{i}and this for the second linei=1,2,dots,mi=1,2, \ldots, mThe elements of the table (19) thus transformed are obtained by applying the (Newton-Leibniz) formula.
g_(t)(z_(i))-g_(t)(z_(i-1))(g_(1)(z_(i)))/(g_(1)(z_(i-1)))=g_(1)(z_(i))int_(z_(i-1))^(z_(i))((g_(t)(y))/(g_(1)(y)))^(')dy.g_{t}\left(z_{i}\right)-g_{t}\left(z_{i-1}\right) \frac{g_{1}\left(z_{i}\right)}{g_{1}\left(z_{i-1}\right)}=g_{1}\left(z_{i}\right) \int_{z_{i-1}}^{z_{i}}\left(\frac{g_{t}(y)}{g_{1}(y)}\right)^{\prime} d y .
Whenm=1m=1Table (19) has only one row which is left unchanged.
After all these transformations, the elements of the first column of the determinant (6) all become zero, except for the first one, which is equal tog_(1)(z_(1))g_{1}\left(z_{1}\right)Finally, by taking out the lactourprod_(i=1)^(m)(g_(1)(z_(i)))^(k_(i))=prod_(i=1)^(n)g_(1)(x_(i))\prod_{i=1}^{m}\left(g_{1}\left(z_{i}\right)\right)^{k_{i}}=\prod_{i=1}^{n} g_{1}\left(x_{i}\right)and by expanding the determinant from the first column, we obtain the formula
=(prod_(i=1)^(m)g_(1)(x_(i)))int_(z_(1))^(z_(2))int_(z_(2))^(z_(3))cdotsint_(z_(m-1))^(z_(m))psi(y_(1),y_(2),dots,y_(m-1))dy_(1)dy_(2)dots dy_(m-1)=\left(\prod_{i=1}^{m} g_{1}\left(x_{i}\right)\right) \int_{z_{1}}^{z_{2}} \int_{z_{2}}^{z_{3}} \cdots \int_{z_{m-1}}^{z_{m}} \psi\left(y_{1}, y_{2}, \ldots, y_{m-1}\right) d y_{1} d y_{2} \ldots d y_{m-1}
Or
=v(ubrace((g_(2)//g_(1))^(@),(g_(3)//g_(1))^(@),dots,(g_(n)//g_(1))^(@)ubrace)_(k_(1)-1)(ubrace(z_(1),z_(1),dots,z_(1)ubrace)_(k_(2)-1),y_(1),z_(2),z_(2),dots,z_(2),y_(2),dots,y_(m-1),ubrace(z_(m)z_(m),dots,z_(m)ubrace)_(k_(m)-1))=v(\underbrace{\left(g_{2} / g_{1}\right)^{\circ},\left(g_{3} / g_{1}\right)^{\circ}, \ldots,\left(g_{n} / g_{1}\right)^{\circ}}_{k_{1}-1}(\underbrace{z_{1}, z_{1}, \ldots, z_{1}}_{k_{2}-1}, y_{1}, z_{2}, z_{2}, \ldots, z_{2}, y_{2}, \ldots, y_{m-1}, \underbrace{z_{m} z_{m}, \ldots, z_{m}}_{k_{m}-1})This is the formula
we wanted to establish. We also used the notations (8)
We assume, of course, that all the functions, derivatives, and integrals involved are meaningful. In particular, for example, that the functiong_(1)g_{1}does not cancel out, that the functionpsi(y_(1),y_(2),dots,y_(m-1))\psi\left(y_{1}, y_{2}, \ldots, y_{m-1}\right)is continuous, etc.
Ifk_(1)=1k_{1}=1the pointz_(i)z_{i}does not appear on the second member of (21). Finally, ifm=1m=1Formula (20) is meaningless. In this case, it is replaced by the well-known formula [2]:
(22)w(g_(1),g_(2),dots,g_(n))=g_(1)^(n)w(((g_(2))/(g_(1)))^('),((g_(3))/(g_(1)))^('),dots,((g_(n))/(g_(1)))^('))w\left(g_{1}, g_{2}, \ldots, g_{n}\right)=g_{1}^{n} w\left(\left(\frac{g_{2}}{g_{1}}\right)^{\prime},\left(\frac{g_{3}}{g_{1}}\right)^{\prime}, \ldots,\left(\frac{g_{n}}{g_{1}}\right)^{\prime}\right).
Formula (20) should therefore be regarded as a generalization of the latter formula (22).
6. All the assumptions concerning the continuity, differentiability, integrability, etc., of the functions involved are verified if we apply the preceding results to the functionsg_(t)(x)=x^(sigma_(t)),t=1,2,dots,ng_{t}(x)=x^{\sigma_{t}}, t=1,2, \ldots, ndefined forx > 0x>0, THEsigma_(t)\sigma_{t}being any given real numbers. If we note that, in this case,
((g_(t)(x))/(g_(1)(x)))^(')=(sigma_(t)-sigma_(1))x^(sigma_(t)-sigma_(1)-1),t=1,2,dots,n,\left(\frac{g_{t}(x)}{g_{1}(x)}\right)^{\prime}=\left(\sigma_{t}-\sigma_{1}\right) x^{\sigma_{t}-\sigma_{1}-1}, t=1,2, \ldots, n,
From this formula we deduce
Theorem 1. With the previous notation, if0 < z_(1) < z_(2) < dots < z_(m)0<z_{1}<z_{2}<\ldots<z_{m}Andsigma_(1) < sigma_(2) < dots < sigma_(n)\sigma_{1}<\sigma_{2}<\ldots<\sigma_{n}, the determinant
The demonstration presents no difficulties and is principally based on formula (23). We can proceed by complete induction. Let us first note that the property is via forn=1n=1because then the determinant (24) is reduced &x_(1)^(6)x_{1}^{6}which is indeed a positive number. Let's also remember that forn=1n=1(nn(any) the property is true guisqu alons on a
Let us now assume that the property is true for the order determinantn-1(n-1)n-1(n-1)and demonstrated for the order determinantnnWe can assume m> uarr>\uparrowThe property then results from formula (23) in which we have
and the function to be integrated is continuous over its entire domain of definition[z_(1),z_(2)]xx[z_(2),z_(3)]xx dots x[z_(m-1),z_(m)]\left[z_{1}, z_{2}\right] \times\left[z_{2}, z_{3}\right] \times \ldots x\left[z_{m-1}, z_{m}\right]and is (by hypothesis) positive at every internal point of this domain.
If we now take into account the general formula (16), we deduce the
Corollary 1. If the numbersx_(i),i=1,2,dots,nx_{i}, i=1,2, \ldots, nare positive, we have
THEz_(i)z_{i}and thek_(i)k_{i}being always determined by formulas (8).
In the second memberV(x_(1),x_(2),dots,x_(n))V\left(x_{1}, x_{2}, \ldots, x_{n}\right)is the generalized Vandermonde determinant (15), butV^(2)(sigma_(1),sigma_(2),dots,sigma_(n))V^{2}\left(\sigma_{1}, \sigma_{2}, \ldots, \sigma_{n}\right)is the usual Vandermonde determinant of numberssigma_(1),sigma_(2),dots,sigma_(n)\sigma_{1}, \sigma_{2}, \ldots, \sigma_{n}, different or not, given by formula (11). Formula (26) is also true in the case where thesigma_(t)\sigma_{t}are not all distinct, since then both members are equal to 0.
The special casem=nm=n, therefore the case where the pointsx_(i)x_{i}.i=1,2,dots,ni=1,2, \ldots, n, are distinct, has also been dealt with by us in an earlier work [3].
7. We can now return to the study of the remainder of the quadrature formula (1). For this, we will use our results concerning generalized convex functions and the notion of a linear functional of simple form, presented in our work cited [5]. The reader is advised to refer to this work for the justification of all the statements that follow.
Formula (1) can be obtained by replacing the function f with the (generalized) Lagrange-Hermite type polynomial
whose coefficientsc_(0),c_(1),c_(2),c_(3)c_{0}, c_{1}, c_{2}, c_{3}are well determined by the interpolatory conditions
(27)L(0)=f(0),L^(')(L(0)=f(0), L^{\prime}(四)=f(:})=f\left(\right.四),L^(')(0)=f^(')(o+),L(1)=f(1)L^{\prime}(0)=f^{\prime}(\oplus), L(1)=f(1).
Numbersp,q,rp, q, rand (ii) have the meanings given in rr. 1.
As a result, the restR(f)R(f)is given by the formula
{:(28)R(f)=int_(0)^(1)(f(x)-I(x))dx:}\begin{equation*}
R(f)=\int_{0}^{1}(f(x)-I(x)) d x \tag{28}
\end{equation*}
But it's easy to point out the differencef(x)=L(x)f(x)=L(x)
in a remarkable form toIIusing the generalized divided difference
(29)
Orssis a positive number> r quad( > q > p)>r \quad(>q>p)We see that
, by virtue of corollary 1, this divided difference exists regardless of the pointsx_(1),x_(2),x_(3),x_(4),x_(5)x_{1}, x_{2}, x_{3}, x_{4}, x_{5}, non-negative, but of which at most one is equal toOOThe two determinants of the second member of (29) are taken in the generalized sense (9) (with thez_(j)z_{j}distinct). Note that ifx_(1)=0x_{1}=0and the pointsx_(2),x_(3),x_(4),x_(5)x_{2}, x_{3}, x_{4}, x_{5}are positive, we have #)
assuming thatxxbe positive and different fromTheta\Thetaand 1. In our examplexxalone is always a group of pointsz_(i)z_{i}In this way the determinantquad V((1,x^(p),x^(q),x^(x),x^(s))/(0,Theta,Theta,1,x))\quad V\binom{1, x^{p}, x^{q}, x^{x}, x^{s}}{0, \Theta, \Theta, 1, x}
is zero ifxxcoincides with 0, or 1, and then the difference divided[0,(4,0,1,x_(9)f]n:}\left[0,\left(4,0,1, x_{9} f\right] n\right.'is not defined. This difficulty can easily be remedied, but it is unnecessary to do so in this work. Forx=0,Thetax=0, \Thetaor 1 the second member of (30) does not make sense, but then the polynomial valuesIIare given by (27).
8. The coefficient of the divided difference of the right-hand side of (30) is, by virtue of corollary 3, negative at every point of[0,1][0,1], outside of 0, (1) and 1.
Let us now recall that the functionffis said to be convex with respect to the sequence of functions 1,x^(p),x^(q),x^(r),x^(s)x^{p}, x^{q}, x^{r}, x^{s}on the interval [0,1] if the divided difference (29) is> 0>0for any group of 5 distinct pointsx_(1),x_(2),x_(3),x_(4),x_(5)x_{1}, x_{2}, x_{3}, x_{4}, x_{5}In this case, the divided difference (29) is still positive if the pointsx_(1),x_(2),x_(3),x_(4),x_(5)x_{1}, x_{2}, x_{3}, x_{4}, x_{5}are not all confused, at least in the case where this difference divides exists. In the case (the only one that interests us here) where the functionffis convex we have[0,(1),(1),1,x:f] > 0[0,(1),(1), 1, x: f]>0Forxxdifferent0,(4)0,(4)and 1. Ift in C[0,1]t \in C[0,1], therefore if the functionffis continuous on[0,1][0,1], it follows from formulas (28) and (30) that if, in addition, the function is convex with respect to the sequence1,x^(p),x^(q),x^(1),x^(5)1, x^{p}, x^{q}, x^{1}, x^{5}We haveR(f)!=0quad(plusR(f) \neq 0 \quad(p l u sExactlyR(f) < 0)R(f)<0).
ButR(f)R(f)is a linear (additive and homogeneous) functional defined onC[0,1]C[0,1]It therefore follows from the study we have carried out on linear functionals of the simple form (see again work [5]) that
Theorem 2. Iff in C[0,1]f \in C[0,1], the restR(f)R(f)of the quadrature formula (1) is of the form
Orxi_(1),xi_(2),xi_(3),xi_(4),xi_(5)\xi_{1}, \xi_{2}, \xi_{3}, \xi_{4}, \xi_{5}are 5 distinct points of the open interval[0,1][0,1](generally dependent on the function)ff) and the divided difference of the second member is defined by formula (29).
The coefficient
R(x^(s))=int_(0)^(1)x^(s)dx-lambda_(1)(1)^(s)-lambda_(2)R\left(x^{s}\right)=\int_{0}^{1} x^{s} d x-\lambda_{1}(1)^{s}-\lambda_{2}
The value of formula (31) can be calculated using the values ​​(3a) and (3b) of the coefficientslambda_(1),lambda_(2)\lambda_{1}, \lambda_{2}from formula (1). We obtain
where (10) Є]0,1[:}] 0,1\left[\right.satisfied &1^(@)1^{\circ}equation (4).
Apparently, in the proof of Theorem 2, in addition to the continuity of the function f, its differentiability also comes into play, at least with respect to point (ii). But this theorem remains true without this last restriction. This results, on the one hand, from the fact that the derivative of the function I does not appear in formula (1) and, on the other hand, from the fact that a function is convex with respect to the sequence1,x^(p)1, x^{p},x^(q),x^(r),x^(s)x^{q}, x^{r}, x^{s}on1^("intervalle ")[0,1]1^{\text {intervalle }}[0,1]eat necessarily (continuous and) differentiable on]0,1[] 0,1[We established this latter property previously [4].
9. Formula (31) is inconvenient for delimiting the remainderR(I)R(\mathcal{I})But, it also follows from our work cited [5], that if the functioniihas a deximate4^("ieme ")4^{\text {ieme }}on1^(@)1^{\circ}interm valle ouvert ] 0,1 [ one can in (31) produce the pointsxi_(1)xi_(2,0)xi_(3,)xi_(4,0)xi_(5)\xi_{1} \xi_{2,0} \xi_{3,} \xi_{4,0} \xi_{5}equal to a child point{: xi in]0_(0)1[\left.\xi \in\right] 0_{0} 1[。
V((1,x^(p),x^(q),x^(r),x^(s))/(xi,xi,xi,xi,xi))=xi^(p+q+x+s-10)pqrsV(p,q,r,s)V\binom{1, x^{p}, x^{q}, x^{r}, x^{s}}{\xi, \xi, \xi, \xi, \xi}=\xi^{p+q+x+s-10} p q r s V(p, q, r, s)
assumingxi in]0,1[\xi \in] 0,1[
By doing the calculations, we will find
and we therefore deduce
Theorem 3. If the functionf in C[0,1]f \in C[0,1]has a fourth derivative on]0,1[] 0,1[, the restR(f)R(f)of formula (1) is given by
Orepsi^(˙)\dot{\varepsilon}is a point in the open interval ]0,1[ (generally depending on the function .f).
10. We will finish with two examples. ExE xExample 1. From Simpson's formula(p=1,q=2(p=1, q=2,r=3r=3), the remainder is given by the formula
If we takes=4s=4we find the rest well known-(1)/(2880)f^("IV ")(xi)-\frac{1}{2880} \mathrm{f}^{\text {IV }}(\xi)By takings=(7)/(2)s=\frac{7}{2}respectivelys=5s=5we find the remainder respectively in the form
Example 2. Let's takep=(1)/(2),q=1,r=(3)/(2)p=\frac{1}{2}, q=1, r=\frac{3}{2}.LLequation then givesTheta=(9)/(25)\Theta=\frac{9}{25}and formula (32) shows us that the remainder of the quadrature formula
int_(0)^(1)f(x)dx=(1)/(36)[2f(0)+25 f((9)/(25))+9f(1)]+R(f)\int_{0}^{1} f(x) d x=\frac{1}{36}\left[2 f(0)+25 f\left(\frac{9}{25}\right)+9 f(1)\right]+R(f)
BIBLIOGRAPHY
[1] S. Goła b, C. O lech: Contribution to the theory of the Simpsonian formula of approximate quadratures. Ann. Polon. Math. (1954) 176-183.
[2] G. P ol y a, G. S zeg ö: Aufgaben und Lehrsätze aus der Analysis, II. Berlin 1925.
[3] T. Popoviciu: Asupra unui determinant. Gas. Mast. Ser. A. 36 (1931) 405-408 (in Romanian).
[4] 'T. Popoviciu: Notes on higher order functions I. Mathematica (Cluj) 12 (1936) 81-92.
[5] T. Po poviciu: On the remainder in certain linear formulas of approximation of the analysis. Mathematica (Cluj) 24 (1959) 95-142。
CALCULATION INSTITUTE, Str. Republicii nr. 37, CLUJ, ROMANIA
When at least two of the pointsx_(1),x_(2),x_(3),x_(4),x_(5)x_{1}, x_{2}, x_{3}, x_{4}, x_{5}are equal to 0, the difference divided (29, (at least forp <= 1p \leqslant 1, is not defined.