THE CONVERGENCE OF MEAN VALUE ITERATION FOR A FAMILY OF MAPS
B. E. RHOADES AND ŞTEFAN M. ŞOLTUZ
Received 3 January 2005 and in revised form 6 September 2005
We consider a mean value iteration for a family of functions, which corresponds to the Mann iteration with lim_(n rarr oo)alpha_(n)!=0\lim _{n \rightarrow \infty} \alpha_{n} \neq 0. We prove convergence results for this iteration when applied to strongly pseudocontractive or strongly accretive maps.
1. Introduction
Let XX be a real Banach space. The map J:X rarr2^(X^(**))J: X \rightarrow 2^{X^{*}} given by
{:(1.1)Jx:={f inX^(**):(:x,f:)=||x||^(2),||f||=||x||}","quad AA x in X:}\begin{equation*}
J x:=\left\{f \in X^{*}:\langle x, f\rangle=\|x\|^{2},\|f\|=\|x\|\right\}, \quad \forall x \in X \tag{1.1}
\end{equation*}
is called the normalized duality mapping. Let y in Xy \in X and j(y)in J(y)j(y) \in J(y); note that (:*,j(y):)\langle\cdot, j(y)\rangle is a Lipschitzian map.
Remark 1.1. The above JJ satisfies
{:(1.2)(:x","j(y):) <= ||x||||y||","quad AA x in X","AA j(y)in J(y).:}\begin{equation*}
\langle x, j(y)\rangle \leq\|x\|\|y\|, \quad \forall x \in X, \forall j(y) \in J(y) . \tag{1.2}
\end{equation*}
Definition 1.2. Let BB be a nonempty subset of XX. The map T:B rarr BT: B \rightarrow B is strongly pseudocontractive if there exist k in(0,1)k \in(0,1) and j(x-y)in J(x-y)j(x-y) \in J(x-y) such that
{:(1.3)(:Tx-Ty","j(x-y):) <= k||x-y||^(2)","quad AA x","y in B.:}\begin{equation*}
\langle T x-T y, j(x-y)\rangle \leq k\|x-y\|^{2}, \quad \forall x, y \in B . \tag{1.3}
\end{equation*}
A map S:B rarr BS: B \rightarrow B is called strongly accretive if there exist k in(0,1)k \in(0,1) and j(x-y)in J(x-y)j(x-y) \in J(x-y) such that
{:(1.4)(:Sx-Sy","j(x-y):) >= k||x-y||^(2)","quad AA x","y in B.:}\begin{equation*}
\langle S x-S y, j(x-y)\rangle \geq k\|x-y\|^{2}, \quad \forall x, y \in B . \tag{1.4}
\end{equation*}
In (1.3), take k=1k=1 to obtain a pseudocontractive map. In (1.4), take k=0k=0 to obtain an accretive map.
Let BB be a nonempty and convex subset of X,T:B rarr BX, T: B \rightarrow B and x_(0),u_(0)in Bx_{0}, u_{0} \in B. The Mann iteration (see [3]) is defined by
{:(1.5)u_(n+1)=(1-alpha_(n))u_(n)+alpha_(n)Tu_(n).:}\begin{equation*}
u_{n+1}=\left(1-\alpha_{n}\right) u_{n}+\alpha_{n} T u_{n} . \tag{1.5}
\end{equation*}
The Ishikawa iteration is defined (see [2]) by
{:[x_(n+1)=(1-alpha_(n))x_(n)+alpha_(n)Ty_(n)","],[(1.6)y_(n)=(1-beta_(n))x_(n)+beta_(n)Tx_(n)","]:}\begin{align*}
x_{n+1} & =\left(1-\alpha_{n}\right) x_{n}+\alpha_{n} T y_{n}, \\
y_{n} & =\left(1-\beta_{n}\right) x_{n}+\beta_{n} T x_{n}, \tag{1.6}
\end{align*}
where {alpha_(n)}sub(0,1)\left\{\alpha_{n}\right\} \subset(0,1) and {beta_(n)}sub[0,1)\left\{\beta_{n}\right\} \subset[0,1).
Let s >= 2s \geq 2 be fixed. Let T_(i):B rarr B,1 <= i <= sT_{i}: B \rightarrow B, 1 \leq i \leq s, be a family of functions. We consider the following multistep procedure:
{:[x_(n+1)=(1-alpha_(n))x_(n)+alpha_(n)T_(1)y_(n)^(1)],[(1.7)y_(n)^(i)=(1-beta_(n)^(i))x_(n)+beta_(n)^(i)T_(i+1)y_(n)^(i+1)","quad i=1","dots","s-2","],[y_(n)^(s-1)=(1-beta_(n)^(s-1))x_(n)+beta_(n)^(s-1)T_(s)x_(n)]:}\begin{gather*}
x_{n+1}=\left(1-\alpha_{n}\right) x_{n}+\alpha_{n} T_{1} y_{n}^{1} \\
y_{n}^{i}=\left(1-\beta_{n}^{i}\right) x_{n}+\beta_{n}^{i} T_{i+1} y_{n}^{i+1}, \quad i=1, \ldots, s-2, \tag{1.7}\\
y_{n}^{s-1}=\left(1-\beta_{n}^{s-1}\right) x_{n}+\beta_{n}^{s-1} T_{s} x_{n}
\end{gather*}
Let A,b in(0,1)A, b \in(0,1) be fixed. The sequence {alpha_(n)}sub(0,1)\left\{\alpha_{n}\right\} \subset(0,1) satisfies
{:[(1.8)0 < A <= alpha_(n) <= b < 2(1-k)","quad AA n inN","],[(1.9){beta_(n)^(i)}sub[0","1)","quad i=1","dots","s-1.]:}\begin{gather*}
0<A \leq \alpha_{n} \leq b<2(1-k), \quad \forall n \in \mathbb{N}, \tag{1.8}\\
\left\{\beta_{n}^{i}\right\} \subset[0,1), \quad i=1, \ldots, s-1 . \tag{1.9}
\end{gather*}
Let F(T_(1),dots,T_(s))F\left(T_{1}, \ldots, T_{s}\right) denote the common fixed points set with respect to BB for the family T_(1),dots,T_(s)T_{1}, \ldots, T_{s}. In this paper, we will prove convergence results for iteration (1.7), for strongly pseudocontractive (accretive) maps when {alpha_(n)}\left\{\alpha_{n}\right\} satisfies (1.8). These results improve the recently obtained results from [6], in which {alpha_(n)}\left\{\alpha_{n}\right\} and {beta_(n)}\left\{\beta_{n}\right\} converge to zero. We give two numerical examples in which iteration (1.7), when {alpha_(n)}\left\{\alpha_{n}\right\} satisfies (1.8), converges faster as in [6]. Note that, in both cases, iteration (1.7) converges faster than Ishikawa iteration.
Lemma 1.3 [4]. Let XX be a real Banach space, and let J:X rarr2^(X^(**))J: X \rightarrow 2^{X^{*}} be the duality mapping. Then for any given x,y in Xx, y \in X,
{:(1.10)||x+y||^(2) <= ||x||^(2)+2(:y","j(x+y):)","quad AA x","y in X","AA j(x+y)in J(x+y).:}\begin{equation*}
\|x+y\|^{2} \leq\|x\|^{2}+2\langle y, j(x+y)\rangle, \quad \forall x, y \in X, \forall j(x+y) \in J(x+y) . \tag{1.10}
\end{equation*}
Lemma 1.4 [7]. Let {a_(n)}\left\{a_{n}\right\} be a nonnegative sequence which satisfies the inequality
{:(1.11)a_(n+1) <= (1-t)a_(n)+sigma_(n)",":}\begin{equation*}
a_{n+1} \leq(1-t) a_{n}+\sigma_{n}, \tag{1.11}
\end{equation*}
where t in(0,1)t \in(0,1) is fixed, lim_(n rarr oo)sigma_(n)=0\lim _{n \rightarrow \infty} \sigma_{n}=0. Then lim_(n rarr oo)a_(n)=0\lim _{n \rightarrow \infty} a_{n}=0.
2. Main result
Theorem 2.1. Let s >= 2s \geq 2 be fixed, XX a real Banach space, and BB a nonempty, closed, convex subset of XX. Let T_(1):B rarr BT_{1}: B \rightarrow B be a strongly pseudocontractive operator and T_(2),dots,T_(s):B rarr BT_{2}, \ldots, T_{s}: B \rightarrow B,
with T_(i)(B)T_{i}(B) bounded for all 1 <= i <= s1 \leq i \leq s, such that F(T_(1),dots,T_(s))!=O/F\left(T_{1}, \ldots, T_{s}\right) \neq \varnothing. If A,b in(0,1),{alpha_(n)}sub(0,1)A, b \in(0,1),\left\{\alpha_{n}\right\} \subset (0,1) satisfies (1.8), x_(0)in Bx_{0} \in B, and the following condition is satisfied:
{:(2.1)lim_(n rarr oo)||T_(1)x_(n+1)-T_(1)y_(n)^(1)||=0:}\begin{equation*}
\lim _{n \rightarrow \infty}\left\|T_{1} x_{n+1}-T_{1} y_{n}^{1}\right\|=0 \tag{2.1}
\end{equation*}
then iteration (1.7) converges to the unique common fixed point of T_(1),dots,T_(s)T_{1}, \ldots, T_{s}, which is the unique fixed point of T_(1)T_{1}.
Proof. Any common fixed point of T_(1),dots,T_(s)T_{1}, \ldots, T_{s}, in particular, is a fixed point of T_(1)T_{1}. However, T_(1)T_{1} can have at most one fixed point since it is strongly pseudocontractive. Let x^(**)=F(T_(1),dots,T_(s))x^{*}=F\left(T_{1}, \ldots, T_{s}\right). Denote
{:(2.2)M=s u p_(n inN){||T_(1)y_(n)^(1)||,||x_(0)||,||x^(**)||}:}\begin{equation*}
M=\sup _{n \in \mathbb{N}}\left\{\left\|T_{1} y_{n}^{1}\right\|,\left\|x_{0}\right\|,\left\|x^{*}\right\|\right\} \tag{2.2}
\end{equation*}
Then if we assume ||x_(n)|| <= M\left\|x_{n}\right\| \leq M, by
{:(2.3)||x_(n+1)|| <= (1-alpha_(n))||x_(n)||+alpha_(n)||T_(1)y_(n)^(1)|| <= M",":}\begin{equation*}
\left\|x_{n+1}\right\| \leq\left(1-\alpha_{n}\right)\left\|x_{n}\right\|+\alpha_{n}\left\|T_{1} y_{n}^{1}\right\| \leq M, \tag{2.3}
\end{equation*}
we get ||x_(n+1)|| <= M\left\|x_{n+1}\right\| \leq M.
From (1.2) and (1.10), with
{:[x:=(1-alpha_(n))(x_(n)-x^(**))","],[(2.4)y:=alpha_(n)(T_(1)y_(n)^(1)-T_(1)x^(**))","],[x+y=x_(n+1)-x^(**)","]:}\begin{align*}
x: & =\left(1-\alpha_{n}\right)\left(x_{n}-x^{*}\right), \\
y:= & \alpha_{n}\left(T_{1} y_{n}^{1}-T_{1} x^{*}\right), \tag{2.4}\\
& x+y=x_{n+1}-x^{*},
\end{align*}
we get
{:[||x_(n+1)-x^(**)||^(2)=||(1-alpha_(n))(x_(n)-x^(**))+alpha_(n)(T_(1)y_(n)^(1)-T_(1)x^(**))||^(2)],[ <= (1-alpha_(n))^(2)||x_(n)-x^(**)||^(2)+2alpha_(n)(:T_(1)y_(n)^(1)-T_(1)x^(**),j(x_(n+1)-x^(**)):)],[=(1-alpha_(n))^(2)||x_(n)-x^(**)||^(2)+2alpha_(n)(:T_(1)x_(n+1)-T_(1)x^(**),j(x_(n+1)-x^(**)):)],[+2alpha_(n)(:T_(1)y_(n)^(1)-T_(1)x_(n+1),j(x_(n+1)-x^(**)):)],[(2.5) <= (1-alpha_(n))^(2)||x_(n)-x^(**)||^(2)+2alpha_(n)k||x_(n+1)-x^(**)||^(2)],[+2alpha_(n)(:T_(1)y_(n)^(1)-T_(1)x_(n+1),j(x_(n+1)-x^(**)):)],[ <= (1-alpha_(n))^(2)||x_(n)-x^(**)||^(2)+2alpha_(n)k||x_(n+1)-x^(**)||^(2)],[+2alpha_(n)||T_(1)y_(n)^(1)-T_(1)x_(n+1)||||x_(n+1)-x^(**)||],[ <= (1-alpha_(n))^(2)||x_(n)-x^(**)||^(2)+2alpha_(n)k||x_(n+1)-x^(**)||^(2)],[+4alpha_(n)||T_(1)y_(n)^(1)-T_(1)x_(n+1)||M.]:}\begin{align*}
\left\|x_{n+1}-x^{*}\right\|^{2}= & \left\|\left(1-\alpha_{n}\right)\left(x_{n}-x^{*}\right)+\alpha_{n}\left(T_{1} y_{n}^{1}-T_{1} x^{*}\right)\right\|^{2} \\
\leq & \left(1-\alpha_{n}\right)^{2}\left\|x_{n}-x^{*}\right\|^{2}+2 \alpha_{n}\left\langle T_{1} y_{n}^{1}-T_{1} x^{*}, j\left(x_{n+1}-x^{*}\right)\right\rangle \\
= & \left(1-\alpha_{n}\right)^{2}\left\|x_{n}-x^{*}\right\|^{2}+2 \alpha_{n}\left\langle T_{1} x_{n+1}-T_{1} x^{*}, j\left(x_{n+1}-x^{*}\right)\right\rangle \\
& +2 \alpha_{n}\left\langle T_{1} y_{n}^{1}-T_{1} x_{n+1}, j\left(x_{n+1}-x^{*}\right)\right\rangle \\
\leq & \left(1-\alpha_{n}\right)^{2}\left\|x_{n}-x^{*}\right\|^{2}+2 \alpha_{n} k\left\|x_{n+1}-x^{*}\right\|^{2} \tag{2.5}\\
& +2 \alpha_{n}\left\langle T_{1} y_{n}^{1}-T_{1} x_{n+1}, j\left(x_{n+1}-x^{*}\right)\right\rangle \\
\leq & \left(1-\alpha_{n}\right)^{2}\left\|x_{n}-x^{*}\right\|^{2}+2 \alpha_{n} k\left\|x_{n+1}-x^{*}\right\|^{2} \\
& +2 \alpha_{n}\left\|T_{1} y_{n}^{1}-T_{1} x_{n+1}\right\|\left\|x_{n+1}-x^{*}\right\| \\
\leq & \left(1-\alpha_{n}\right)^{2}\left\|x_{n}-x^{*}\right\|^{2}+2 \alpha_{n} k\left\|x_{n+1}-x^{*}\right\|^{2} \\
& +4 \alpha_{n}\left\|T_{1} y_{n}^{1}-T_{1} x_{n+1}\right\| M .
\end{align*}
Using (1.8), we obtain
{:(2.6)(1-alpha_(n))^(2) <= 1-2alpha_(n)+alpha_(n)b < 1-2alpha_(n)+alpha_(n)2(1-k)=1-2alpha_(n)k:}\begin{equation*}
\left(1-\alpha_{n}\right)^{2} \leq 1-2 \alpha_{n}+\alpha_{n} b<1-2 \alpha_{n}+\alpha_{n} 2(1-k)=1-2 \alpha_{n} k \tag{2.6}
\end{equation*}
thus,
{:(2.7)||x_(n+1)-x^(**)||^(2) <= ((1-alpha_(n))^(2))/(1-2alpha_(n)k)||x_(n)-x^(**)||^(2)+(4alpha_(n)M)/(1-2alpha_(n)k)||T_(1)y_(n)^(1)-T_(1)x_(n+1)||:}\begin{equation*}
\left\|x_{n+1}-x^{*}\right\|^{2} \leq \frac{\left(1-\alpha_{n}\right)^{2}}{1-2 \alpha_{n} k}\left\|x_{n}-x^{*}\right\|^{2}+\frac{4 \alpha_{n} M}{1-2 \alpha_{n} k}\left\|T_{1} y_{n}^{1}-T_{1} x_{n+1}\right\| \tag{2.7}
\end{equation*}
The following inequality is satisfied:
{:[((1-alpha_(n))^(2))/(1-2alpha_(n)k)=((1-alpha_(n))^(2)(1-2alpha_(n)k+2alpha_(n)k))/(1-2alpha_(n)k)=(1-alpha_(n))^(2)(1+(2alpha_(n)k)/(1-2alpha_(n)k))],[=(1-alpha_(n))^(2)+(2alpha_(n)k(1-alpha_(n))^(2))/(1-2alpha_(n)k) <= (1-alpha_(n))^(2)+2alpha_(n)k <= 1-2alpha_(n)+alpha_(n)b+2alpha_(n)k],[(2.8)=1-(2(1-k)-b)alpha_(n) <= 1-(2(1-k)-b)A]:}\begin{align*}
\frac{\left(1-\alpha_{n}\right)^{2}}{1-2 \alpha_{n} k} & =\frac{\left(1-\alpha_{n}\right)^{2}\left(1-2 \alpha_{n} k+2 \alpha_{n} k\right)}{1-2 \alpha_{n} k}=\left(1-\alpha_{n}\right)^{2}\left(1+\frac{2 \alpha_{n} k}{1-2 \alpha_{n} k}\right) \\
& =\left(1-\alpha_{n}\right)^{2}+\frac{2 \alpha_{n} k\left(1-\alpha_{n}\right)^{2}}{1-2 \alpha_{n} k} \leq\left(1-\alpha_{n}\right)^{2}+2 \alpha_{n} k \leq 1-2 \alpha_{n}+\alpha_{n} b+2 \alpha_{n} k \\
& =1-(2(1-k)-b) \alpha_{n} \leq 1-(2(1-k)-b) A \tag{2.8}
\end{align*}
Substituting (2.6) and (2.8) into (2.7), we obtain
{:(2.9)||x_(n+1)-x^(**)||^(2) <= (1-(2(1-k)-b)A)||x_(n)-x^(**)||^(2)+(4bM)/(1-2bk)||T_(1)y_(n)^(1)-T_(1)x_(n+1)||:}\begin{equation*}
\left\|x_{n+1}-x^{*}\right\|^{2} \leq(1-(2(1-k)-b) A)\left\|x_{n}-x^{*}\right\|^{2}+\frac{4 b M}{1-2 b k}\left\|T_{1} y_{n}^{1}-T_{1} x_{n+1}\right\| \tag{2.9}
\end{equation*}
Set
{:[a_(n):=||x_(n)-x^(**)||^(2)],[(2.10)t:=(2(1-k)-b)A in(0","1)],[sigma_(n):=(4bM)/(1-2bk)||T_(1)y_(n)^(1)-T_(1)x_(n+1)||]:}\begin{gather*}
a_{n}:=\left\|x_{n}-x^{*}\right\|^{2} \\
t:=(2(1-k)-b) A \in(0,1) \tag{2.10}\\
\sigma_{n}:=\frac{4 b M}{1-2 b k}\left\|T_{1} y_{n}^{1}-T_{1} x_{n+1}\right\|
\end{gather*}
From (2.1), we know that lim_(n rarr oo)sigma_(n)=0\lim _{n \rightarrow \infty} \sigma_{n}=0; all the assumptions of Lemma 1.4 are fulfilled and consequently we have lim_(n rarr oo)||x_(n)-x^(**)||=0\lim _{n \rightarrow \infty}\left\|x_{n}-x^{*}\right\|=0.
In Theorem 2.1, {alpha_(n)}\left\{\alpha_{n}\right\} does not converge to zero, while in [6], {alpha_(n)}\left\{\alpha_{n}\right\} converges to zero.
Theorem 2.2 [6]. Let s >= 2s \geq 2 be fixed, XX a real Banach space with a uniformly convex dual, and BB a nonempty, closed, convex subset of XX. Let T_(1):B rarr BT_{1}: B \rightarrow B be a strongly pseudocontractive operator and T_(2),dots,T_(s):B rarr BT_{2}, \ldots, T_{s}: B \rightarrow B, with T_(i)(B)T_{i}(B) bounded for all 1 <= i <= s1 \leq i \leq s, such that F(T_(1),dots,T_(s))!=O/F\left(T_{1}, \ldots, T_{s}\right) \neq \varnothing. If {alpha_(n)}sub(0,1)\left\{\alpha_{n}\right\} \subset(0,1) satisfies lim_(n rarr oo)alpha_(n)=0,sum_(n=1)^(oo)alpha_(n)=+oo\lim _{n \rightarrow \infty} \alpha_{n}=0, \sum_{n=1}^{\infty} \alpha_{n}=+\infty, and {beta_(n)^(i)}sub[0,1),i=1,dots,s-1\left\{\beta_{n}^{i}\right\} \subset [0,1), i=1, \ldots, s-1, satisfy lim_(n rarr oo)beta_(n)^(1)=0\lim _{n \rightarrow \infty} \beta_{n}^{1}=0, then iteration (1.7) converges to a fixed point of T_(1),dots,T_(s)T_{1}, \ldots, T_{s}.
The Banach space in Theorem 2.1 contains no restrictions.
3. Further results
Denote by II the identity map.
Remark 3.1. Let T,S:X rarr XT, S: X \rightarrow X and let f in Xf \in X be given. Then,
(i) a fixed point for the map Tx=f+(I-S)xT x=f+(I-S) x, for all x in Xx \in X, is a solution for Sx=fS x=f;
(ii) a fixed point for Tx=f-SxT x=f-S x is a solution for x+Sx=fx+S x=f.
Remark 3.2 [5]. The following are true.
(i) The operator T:X rarr XT: X \rightarrow X is a (strongly) pseudocontractive map if and only if ( I-T):X rarr XI- T): X \rightarrow X is (strongly) accretive.
(ii) If S:X rarr XS: X \rightarrow X is an accretive map, then T=f-S:X rarr XT=f-S: X \rightarrow X is a strongly pseudocontractive map.
We consider iteration (1.7), with T_(i)x=f_(i)+(I-S_(i))x,1 <= i <= sT_{i} x=f_{i}+\left(I-S_{i}\right) x, 1 \leq i \leq s and s >= 2,{alpha_(n)}sub(0,1)s \geq 2,\left\{\alpha_{n}\right\} \subset(0,1), {beta_(n)^(i)}sub[0,1),i=1,dots,s-1\left\{\beta_{n}^{i}\right\} \subset[0,1), i=1, \ldots, s-1 satisfying (1.8):
{:[x_(n+1)=(1-alpha_(n))x_(n)+alpha_(n)(f_(1)+(I-S_(1))y_(n)^(1))],[(3.1)y_(n)^(i)=(1-beta_(n)^(i))x_(n)+beta_(n)^(i)(f_(i+1)+(I-S_(i+1))y_(n)^(i+1))","quad i=1","dots","s-2],[y_(n)^(s-1)=(1-beta_(n)^(s-1))x_(n)+beta_(n)^(s-1)(f_(s-1)+(I-S_(s))x_(n))]:}\begin{gather*}
x_{n+1}=\left(1-\alpha_{n}\right) x_{n}+\alpha_{n}\left(f_{1}+\left(I-S_{1}\right) y_{n}^{1}\right) \\
y_{n}^{i}=\left(1-\beta_{n}^{i}\right) x_{n}+\beta_{n}^{i}\left(f_{i+1}+\left(I-S_{i+1}\right) y_{n}^{i+1}\right), \quad i=1, \ldots, s-2 \tag{3.1}\\
y_{n}^{s-1}=\left(1-\beta_{n}^{s-1}\right) x_{n}+\beta_{n}^{s-1}\left(f_{s-1}+\left(I-S_{s}\right) x_{n}\right)
\end{gather*}
Theorem 2.1, Remark 3.1(i), and Remark 3.2(i) lead to the following result.
Corollary 3.3. Let s >= 2s \geq 2 be fixed, XX a real Banach space, and S_(1):X rarr XS_{1}: X \rightarrow X a strongly accretive operator, S_(2),dots,S_(s):X rarr XS_{2}, \ldots, S_{s}: X \rightarrow X, such that the equations S_(i)x=f_(i),1 <= i <= sS_{i} x=f_{i}, 1 \leq i \leq s, have a common solution and T_(i)(X),1 <= i <= sT_{i}(X), 1 \leq i \leq s, are bounded. If A,b in(0,1),{alpha_(n)}sub(0,1)A, b \in(0,1),\left\{\alpha_{n}\right\} \subset(0,1) satisfies (1.8), and condition (2.1) is satisfied, then iteration (3.1) converges to a common solution of S_(i)x=f_(i)S_{i} x=f_{i}, 1 <= i <= s1 \leq i \leq s.
We consider iteration (1.7), with T_(i)x=f_(i)-S_(i)x,1 <= i <= sT_{i} x=f_{i}-S_{i} x, 1 \leq i \leq s, and s >= 2,{alpha_(n)}sub(0,1)s \geq 2,\left\{\alpha_{n}\right\} \subset(0,1), {beta_(n)^(i)}sub[0,1),i=1,dots,s-1\left\{\beta_{n}^{i}\right\} \subset[0,1), i=1, \ldots, s-1, satisfying (1.8):
{:[x_(n+1)=(1-alpha_(n))x_(n)+alpha_(n)(f_(1)-S_(1)y_(n)^(1))],[(3.2)y_(n)^(i)=(1-beta_(n)^(i))x_(n)+beta_(n)^(i)(f_(i+1)-S_(i+1)y_(n)^(i+1))","quad i=1","dots","s-2],[y_(n)^(s-1)=(1-beta_(n)^(s-1))x_(n)+beta_(n)^(s-1)(f_(s-1)-S_(s)x_(n))]:}\begin{gather*}
x_{n+1}=\left(1-\alpha_{n}\right) x_{n}+\alpha_{n}\left(f_{1}-S_{1} y_{n}^{1}\right) \\
y_{n}^{i}=\left(1-\beta_{n}^{i}\right) x_{n}+\beta_{n}^{i}\left(f_{i+1}-S_{i+1} y_{n}^{i+1}\right), \quad i=1, \ldots, s-2 \tag{3.2}\\
y_{n}^{s-1}=\left(1-\beta_{n}^{s-1}\right) x_{n}+\beta_{n}^{s-1}\left(f_{s-1}-S_{s} x_{n}\right)
\end{gather*}
Theorem 2.1, Remark 3.1(ii), and Remark 3.2(ii) lead to the following result.
Corollary 3.4. Let s >= 2s \geq 2 be fixed, XX a real Banach space, and S_(1):X rarr XS_{1}: X \rightarrow X an accretive operator, S_(2),dots,S_(s):X rarr XS_{2}, \ldots, S_{s}: X \rightarrow X, such that the equations x+S_(i)x=f_(i),1 <= i <= sx+S_{i} x=f_{i}, 1 \leq i \leq s, have a common solution and S_(i)(X),1 <= i <= sS_{i}(X), 1 \leq i \leq s, are bounded. If A,b in(0,1),{alpha_(n)}sub(0,1)A, b \in(0,1),\left\{\alpha_{n}\right\} \subset(0,1) satisfies (1.8), and condition (2.1) is satisfied, then iteration (3.2) converges to a common solution of x+S_(i)x=f_(i),1 <= i <= sx+S_{i} x= f_{i}, 1 \leq i \leq s.
4. Numerical examples
Let X=R^(2)X=\mathbb{R}^{2} be the euclidean plane, consider x=(a,b)inR^(2)x=(a, b) \in \mathbb{R}^{2}, with x^(_|_)=(b,-a)inR^(2)x^{\perp}=(b,-a) \in \mathbb{R}^{2}. We know that (:x,x^(_|_):)=0,||x||=||x^(_|_)||,(:x^(_|_),y^(_|_):)=(:x,y:),||x^(_|_)-y^(_|_)||=||x-y||\left\langle x, x^{\perp}\right\rangle=0,\|x\|=\left\|x^{\perp}\right\|,\left\langle x^{\perp}, y^{\perp}\right\rangle=\langle x, y\rangle,\left\|x^{\perp}-y^{\perp}\right\|=\|x-y\|, and (:x^(_|_),y:)+(:x,y^(_|_):)=0\left\langle x^{\perp}, y\right\rangle+\left\langle x, y^{\perp}\right\rangle=0, for all x,y inR^(2)x, y \in \mathbb{R}^{2}. Denote by BB the closed unit ball. In [1], we can get the following example in which Ishikawa iteration (1.6) converges and (1.5) is not convergent.
Table 4.1
| \Iteration (1.7) |
Case 1 |
Case 2 |
| Step 10 |
(0.2217,0.1480) |
(0.0151, -0.0023) |
| Step 15 |
(0.1837, 0.1184) |
(0.0017,-0.0006) |
| Step 20 |
(0.1603, 0.1015) |
(0.0002, -0.0001) |
| Step 21 |
(0.1566, 0.0989) |
10^(-3)*(0.1156,-0.0686)10^{-3} \cdot(0.1156,-0.0686) |
| Step 22 |
(0.1531, 0.0965) |
10^(-4)*(0.7406,-0.4641)10^{-4} \cdot(0.7406,-0.4641) |
| Step 23 |
(0.1499, 0.0942) |
10^(-4)*(0.4743,-0.3129)10^{-4} \cdot(0.4743,-0.3129) |
| Step 24 |
(0.1468, 0.0921) |
10^(-4)*(0.3037,-0.2103)10^{-4} \cdot(0.3037,-0.2103) |
| Step 25 |
(0.1440, 0.0902) |
10^(-4)*(0.1945,-0.1409)10^{-4} \cdot(0.1945,-0.1409) |
\Iteration (1.7) Case 1 Case 2
Step 10 (0.2217,0.1480) (0.0151, -0.0023)
Step 15 (0.1837, 0.1184) (0.0017,-0.0006)
Step 20 (0.1603, 0.1015) (0.0002, -0.0001)
Step 21 (0.1566, 0.0989) 10^(-3)*(0.1156,-0.0686)
Step 22 (0.1531, 0.0965) 10^(-4)*(0.7406,-0.4641)
Step 23 (0.1499, 0.0942) 10^(-4)*(0.4743,-0.3129)
Step 24 (0.1468, 0.0921) 10^(-4)*(0.3037,-0.2103)
Step 25 (0.1440, 0.0902) 10^(-4)*(0.1945,-0.1409)| \Iteration (1.7) | Case 1 | Case 2 |
| :--- | :--- | :--- |
| Step 10 | (0.2217,0.1480) | (0.0151, -0.0023) |
| Step 15 | (0.1837, 0.1184) | (0.0017,-0.0006) |
| Step 20 | (0.1603, 0.1015) | (0.0002, -0.0001) |
| Step 21 | (0.1566, 0.0989) | $10^{-3} \cdot(0.1156,-0.0686)$ |
| Step 22 | (0.1531, 0.0965) | $10^{-4} \cdot(0.7406,-0.4641)$ |
| Step 23 | (0.1499, 0.0942) | $10^{-4} \cdot(0.4743,-0.3129)$ |
| Step 24 | (0.1468, 0.0921) | $10^{-4} \cdot(0.3037,-0.2103)$ |
| Step 25 | (0.1440, 0.0902) | $10^{-4} \cdot(0.1945,-0.1409)$ |
Example 4.1 [1]. Let H=R^(2)H=\mathbb{R}^{2} and let
{:(4.1)B_(1)={x inR^(2):||x|| <= (1)/(2)}","quadB_(2)={x inR^(2):(1)/(2) <= ||x|| <= 1}.:}\begin{equation*}
B_{1}=\left\{x \in \mathbb{R}^{2}:\|x\| \leq \frac{1}{2}\right\}, \quad B_{2}=\left\{x \in \mathbb{R}^{2}: \frac{1}{2} \leq\|x\| \leq 1\right\} . \tag{4.1}
\end{equation*}
The map T:B rarr BT: B \rightarrow B is given by
{:(4.2)Tx={[x+x^(_|_)",",x inB_(1)],[(x)/(||x||)-x+x^(_|_)",",x inB_(2).]:}:}T x= \begin{cases}x+x^{\perp}, & x \in B_{1} \tag{4.2}\\ \frac{x}{\|x\|}-x+x^{\perp}, & x \in B_{2} .\end{cases}
Then the following are true:
(i) TT is Lipschitz and pseudocontractive;
(ii) for all (alpha_(n))_(n)sub(0,1)\left(\alpha_{n}\right)_{n} \subset(0,1), the Mann iteration does not converge to the fixed point of TT (which is the point (0,0)(0,0) and it is unique).
The main result from [2] assures the convergence of the Ishikawa iteration (1.6) applied to the map TT given by (4.2). The convergence is very slow. In [6], for the same TT, it was shown that iteration (1.7) converges faster. Here, we give an example for which (1.7) with {alpha_(n)}\left\{\alpha_{n}\right\} satisfying (1.8) converges even faster as in [6].
Case 1 [6]. Consider now T_(1)(x,y)=0.5*(x,y)T_{1}(x, y)=0.5 \cdot(x, y), for all (x,y)in B,T_(2)=T(x, y) \in B, T_{2}=T, and s=2s=2, where TT is given by (4.2), the initial point x_(0)=(0.5,0.7)x_{0}=(0.5,0.7), and alpha_(n)=beta_(n)=1//(n+1)\alpha_{n}=\beta_{n}=1 /(n+1) in (1.7). The main result from [6] assures the convergence of (1.7).
Case 2. Consider T_(1)(x,y)=0.5*(x,y)T_{1}(x, y)=0.5 \cdot(x, y), for all (x,y)in B,T_(2)=T(x, y) \in B, T_{2}=T, and s=2s=2, where TT is given by (4.2), the initial point x_(0)=(0.5,0.7),alpha_(n)=0.7x_{0}=(0.5,0.7), \alpha_{n}=0.7, for all n inNn \in \mathbb{N}, and beta_(n)=1//(n+1)\beta_{n}=1 /(n+1) in (1.7). The fixed point for both functions is (0,0)(0,0). Observe that k=0.5k=0.5, and {alpha_(n)}\left\{\alpha_{n}\right\} satisfies (1.8):
{:(4.3)A=0.7=alpha_(n)=b <= 2(1-k)=1","quad AA n inN.:}\begin{equation*}
A=0.7=\alpha_{n}=b \leq 2(1-k)=1, \quad \forall n \in \mathbb{N} . \tag{4.3}
\end{equation*}
Note that Mann iteration does not converge for any {alpha_(n)}sub(0,1)\left\{\alpha_{n}\right\} \subset(0,1). Using a Matlab program, we obtain Table 4.1.
Case 3. Consider in (1.7) the same T_(1),T_(2),s=2T_{1}, T_{2}, s=2, and x_(0)x_{0} as in Case 1 and alpha_(n)=beta_(n)=1//sqrt(n+1)\alpha_{n}=\beta_{n}= 1 / \sqrt{n+1}.
Table 4.2
| \Iteration |
Case 3 (1.7) |
Case 4 (1.7) |
Ishikawa iteration |
| Step 10 |
(0.0631, -0.0333) |
(0.0044, -0.0164) |
(0.4545, 0.2689) |
| Step 15 |
(0.0256, -0.0221) |
(-0.0010, -0.0018) |
(0.1289, -0.4827) |
| Step 20 |
(0.0117,-0.0139) |
10^(-5)*(-22.6516,-11.0267)10^{-5} \cdot(-22.6516,-11.0267) |
(-0.4456, -0.1532) |
| Step 11 |
(0.0101, -0.0126) |
10^(-5)*(-15.5657,-5.4373)10^{-5} \cdot(-15.5657,-5.4373) |
(-0.4651,-0.0274) |
| Step 22 |
(0.0087,-0.0115) |
10^(-5)*(-10.5234,-2.3727)10^{-5} \cdot(-10.5234,-2.3727) |
(-0.4511, 0.0941) |
| Step 23 |
(0.0075,-0.0105) |
10^(-5)*(-7.0134,-0.7743)10^{-5} \cdot(-7.0134,-0.7743) |
(-0.4077, 0.2037) |
| Step 24 |
(0.0066, -0.0096) |
10^(-5)*(-4.6140,-0.0022)10^{-5} \cdot(-4.6140,-0.0022) |
(-0.3407, 0.2954) |
| Step 25 |
(0.0057,-0.0088) |
10^(-5)*(-2.9993,0.3215)10^{-5} \cdot(-2.9993,0.3215) |
(-0.2562, 0.3654) |
| Step 1500 |
- |
- |
(0.0790, -0.0311) |
\Iteration Case 3 (1.7) Case 4 (1.7) Ishikawa iteration
Step 10 (0.0631, -0.0333) (0.0044, -0.0164) (0.4545, 0.2689)
Step 15 (0.0256, -0.0221) (-0.0010, -0.0018) (0.1289, -0.4827)
Step 20 (0.0117,-0.0139) 10^(-5)*(-22.6516,-11.0267) (-0.4456, -0.1532)
Step 11 (0.0101, -0.0126) 10^(-5)*(-15.5657,-5.4373) (-0.4651,-0.0274)
Step 22 (0.0087,-0.0115) 10^(-5)*(-10.5234,-2.3727) (-0.4511, 0.0941)
Step 23 (0.0075,-0.0105) 10^(-5)*(-7.0134,-0.7743) (-0.4077, 0.2037)
Step 24 (0.0066, -0.0096) 10^(-5)*(-4.6140,-0.0022) (-0.3407, 0.2954)
Step 25 (0.0057,-0.0088) 10^(-5)*(-2.9993,0.3215) (-0.2562, 0.3654)
Step 1500 - - (0.0790, -0.0311)| \Iteration | Case 3 (1.7) | Case 4 (1.7) | Ishikawa iteration |
| :--- | :--- | :--- | :--- |
| Step 10 | (0.0631, -0.0333) | (0.0044, -0.0164) | (0.4545, 0.2689) |
| Step 15 | (0.0256, -0.0221) | (-0.0010, -0.0018) | (0.1289, -0.4827) |
| Step 20 | (0.0117,-0.0139) | $10^{-5} \cdot(-22.6516,-11.0267)$ | (-0.4456, -0.1532) |
| Step 11 | (0.0101, -0.0126) | $10^{-5} \cdot(-15.5657,-5.4373)$ | (-0.4651,-0.0274) |
| Step 22 | (0.0087,-0.0115) | $10^{-5} \cdot(-10.5234,-2.3727)$ | (-0.4511, 0.0941) |
| Step 23 | (0.0075,-0.0105) | $10^{-5} \cdot(-7.0134,-0.7743)$ | (-0.4077, 0.2037) |
| Step 24 | (0.0066, -0.0096) | $10^{-5} \cdot(-4.6140,-0.0022)$ | (-0.3407, 0.2954) |
| Step 25 | (0.0057,-0.0088) | $10^{-5} \cdot(-2.9993,0.3215)$ | (-0.2562, 0.3654) |
| Step 1500 | - | - | (0.0790, -0.0311) |
Case 4. Consider in (1.7) T_(1),T_(2),s=2T_{1}, T_{2}, s=2, and x_(0)x_{0} as above and alpha_(n)=0.7\alpha_{n}=0.7, for all n inN,beta_(n)=1//sqrt(n+1)n \in \mathbb{N}, \beta_{n}= 1 / \sqrt{n+1}.
Also, consider the Ishikawa iteration with the same TT as in (4.2), x_(0)=(0.5,0.7),alpha_(n)=beta_(n)=1//sqrt(n+1)x_{0}=(0.5,0.7), \alpha_{n}= \beta_{n}=1 / \sqrt{n+1}, for all n inNn \in \mathbb{N}. The main result from [2] assures the convergence of Ishikawa iteration. Note that in this case the convergence is very slow. Eventually, Example 4.1 assures that for the same map, Mann iteration does not converge. A Matlab program leads to the evaluations illustrated in Table 4.2.
Acknowledgment
The authors are indebted to the referee for carefully reading the paper and for making useful suggestions.
References
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[3] W. R. Mann, Mean value methods in iteration, Proc. Amer. Math. Soc. 4 (1953), 506-510.
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[6] -, Mean value iteration for a family of functions, to appear in Nonlinear Funct. Anal. Appl.
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