A viscoplastic contact problem with normal compliance, unilateral constraint and memory term

Abstract

We consider a mathematical model which describes the quasistatic contact between a viscoplastic body and a foundation. The material’s behavior is modelled with a rate-type constitutive law with internal state variable. The contact is frictionless and is modelled with normal compliance, unilateral constraint and memory term.

We present the classical formulation of the problem, list the assumptions on the data and derive a variational formulation of the model. Then we prove its unique weak solvability. The proof is based on arguments of history-dependent quasivariational inequalities.

We also study the dependence of the solution with respect to the data and prove a convergence result.

Authors

Mircea Sofonea
(Laboratoire de Mathématiques et Physique, Université de Perpignan)

Flavius Patrulescu
(Tiberiu Popoviciu Institute of Numerical Analysis, Romanian Academy)

Anca Farcaş
(Babeş-Bolyai University Faculty of Mathematics and Computer Sciences)

Keywords

viscoplastic material; frictionless contact; normal compliance; unilateral constraint; memory term; history-dependent variational inequality, weak solution; Fréchet space

Cite this paper as:

M. Sofonea, F. Pătrulescu, A. Farcaş, A viscoplastic contact problem with normal compliance, unilateral constraint and memory term, Appl. Math. Opt., vol. 62 (2014), pp. 175-198

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About this paper

Journal

Applied Mathematics and Optimization

Publisher Name

Springer US, New York, NY

Print ISSN

0095-4616

Online ISSN

1432-0606

MR

3175193

ZBL

1297.74086

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[3] N. Cristescu, I. Suliciu, Viscoplasticity, Martinus Nijhoff Publishers, Editura Tehnica, Bucharest, (1982).
[4] A. Farcas, F. Patrulescu, M. Sofonea, A history-dependent contact problem with unilateral constraint, Mathematics and its Applications, 2 (2012), 105-111.
[5] J.R. Fernandez-Garcia, W. Han, M. Sofonea, J.M. Viano, Variational and numerical analysis of a frictionless contact problem for elastic-viscoplastic materials with internal state variable, Quarterly of Mechanics and Applied Mathematics, 54 (2001), 501-522.
[6] W. Han, M. Sofonea, Quasistatic Contact Problems in Viscoelasticity and Viscoplasticity, Studies in Advanced Mathematics, 30, American Mathematical Society–International Press, Sommerville, MA (2002).
[7] I.R. Ionescu, M. Sofonea, Functional and Numerical Methods in Viscoplasticity, Oxford University Press, Oxford (1993).
[8] J. Jarusek, M. Sofonea, On the solvability of dynamic elastic-visco-plastic contact problems, Zeitschrift fur Angewandte Matematik und Mechanik (ZAMM), 88 (2008), 3-22.
[9] N. Kikuchi, J.T. Oden, Contact Problems in Elasticity: A Study of Variational Inequalities and Finite Element Methods, SIAM, Philadelphia, 1988.
[10] A. Klarbring, A. Mikelic, M. Shillor, Frictional contact problems with normal compliance, Int. J. Engng. Sci., 26 (1988), 811-832.
[11] A. Klarbring, A. Mikelic, M. Shillor, On friction problems with normal compliance, Nonlinear Analysis, 13 (1989), 935-955.
[12] J.J. Massera, J.J. Schaffer, Linear Differential Equations and Function Spaces, Academic Press, New York-London (1966).
[13] J.A.C.Martins, J.T. Oden, Existence and uniqueness results for dynamic contact problems with nonlinear normal and friction interface laws, Nonlinear Analysis TMA, 11 (1987), 407-428.
[14] J.T. Oden, J.A.C. Martins, Models and computational methods for dynamic friction phenomena, Computer Methods in Applied Mechanics and Engineering, 52 (1985), 527-634.
[15] M. Shillor, M. Sofonea, J.J. Telega, Models and Analysis of Quasistatic Contact, Lecture Notes in Physics, 655, Springer, Berlin (2004).
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[17] M. Sofonea, A. Matei. History-dependent quasivariational inequalities arising in Contact Mechanics, Eur. J. Appl. Math., 22 (2011), 471-491.
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A Viscoplastic Contact Problem with Normal Compliance, Unilateral Constraint and Memory Term

M. Sofonea 1, F. Pătrulescu 2 and A. Farcaş 3
1 Laboratoire de Mathématiques et Physique
Université de Perpignan Via Domitia
52 Avenue de Paul Alduy, 66860 Perpignan, France
2 Tiberiu Popoviciu Institute of Numerical Analysis
P.O. Box 68-1, 400110 Cluj-Napoca, Romania
3 Faculty of Mathematics and Computer Science Babeş-Bolyai University
Kogălniceanu street, no. 1, 400084, Cluj-Napoca, Romania
Abstract

We consider a mathematical model which describes the quasistatic contact between a viscoplastic body and a foundation. The material’s behavior is modelled with a rate-type constitutive law with internal state variable. The contact is frictionless and is modelled with normal compliance, unilateral constraint and memory term. We present the classical formulation of the problem, list the assumptions on the data and derive a variational formulation of the model. Then we prove its unique weak solvability. The proof is based on arguments of history-dependent quasivariational inequalities. We also study the dependence of the solution with respect to the data and prove a convergence result.

2010 Mathematics Subject Classification : 74M15, 74G25, 74G30, 49J40.

Keywords: viscoplastic material, frictionless contact, normal compliance, unilateral constraint, memory term, history-dependent variational inequality, weak solution, Fréchet space.

1 Introduction

The aim of this paper is to study a frictionless contact problem for rate-type viscoplastic materials within the framework of the Mathematical Theory of Contact Mechanics. We model the material’s behavior with a constitutive law of the form

𝝈˙​(t)=ℰ​𝜺​(𝒖˙​(t))+𝒢​(𝝈​(t),𝜺​(𝒖​(t)),𝜿​(t)),\dot{\boldsymbol{\sigma}}(t)=\mathcal{E}\boldsymbol{\varepsilon}(\dot{\boldsymbol{u}}(t))+\mathcal{G}(\boldsymbol{\sigma}(t),\boldsymbol{\varepsilon}(\boldsymbol{u}(t)),\boldsymbol{\kappa}(t)), (1.1)

where 𝒖\boldsymbol{u} denotes the displacement field, 𝝈\boldsymbol{\sigma} represents the stress tensor, 𝜺​(𝒖)\boldsymbol{\varepsilon}(\boldsymbol{u}) is the linearized strain tensor and 𝜿\boldsymbol{\kappa} denotes an internal state variable. Here ℰ\mathcal{E} is a linear operator which describes the elastic properties of the material and 𝒢\mathcal{G} is a nonlinear constitutive function which describes its viscoplastic behavior. In (1.1) and everywhere in this paper the dot above a variable represents the derivative with respect to the time variable tt. Following [3, 7], the internal state variable 𝜿\boldsymbol{\kappa} is a vector-valued function whose evolution is governed by the differential equation

𝜿˙​(t)=𝑮​(𝝈​(t),𝜺​(𝒖​(t)),𝜿​(t)),\dot{\boldsymbol{\kappa}}(t)=\boldsymbol{G}(\boldsymbol{\sigma}(t),\boldsymbol{\varepsilon}(\boldsymbol{u}(t)),\boldsymbol{\kappa}(t)), (1.2)

in which 𝑮\boldsymbol{G} is a nonlinear constitutive function with values in ℝm,m\mathbb{R}^{m},m being a positive integer.

Various results, examples and mechanical interpretations in the study of viscoplastic materials of the form (1.1), (1.2) can be found in [3, 7, and the references therein. Quasistatic contact problems for such materials have been considered in 5, 6) and the references therein. There, the contact was assumed to be frictionless and was modelled with normal compliance; the unique weak solvability of the corresponding problems was proved by using arguments of nonlinear equations with monotone operators and fixed point; semi-discrete and fully discrete scheme were considered, error estimates and convergence results were proved and numerical simulation in the study of two-dimensional test problems were presented. The normal compliance contact condition was first introduced in [14] and since then used in many publications, see, e.g., 9, 10, 11, 13] and references therein. The term normal compliance was first introduced in [10, 11.

In the particular case without internal state variable the constitutive equation (1.1) reads

𝝈˙​(t)=ℰ​𝜺​(𝒖˙​(t))+𝒢​(𝝈​(t),𝜺​(𝒖​(t))),\dot{\boldsymbol{\sigma}}(t)=\mathcal{E}\boldsymbol{\varepsilon}(\dot{\boldsymbol{u}}(t))+\mathcal{G}(\boldsymbol{\sigma}(t),\boldsymbol{\varepsilon}(\boldsymbol{u}(t))), (1.3)

and was used in the literature in order to model the behaviour of various materials like rubbers, rocks, metals, pastes and polymers. Quasistatic frictionless contact problems for materials of the form (1.3) have been considered in [1, 6, 15, 18] and the references therein, under various contact conditions. In [6, 15] both the Signorini and the normal compliance condition were used which, recall, describe a contact with a rigid and elastic foundation, respectively. In [1, 18] the contact was modelled with normal compliance and unilateral constraint condition. This condition, introduced for the first time in [8], models an elastic-rigid behavior of the foundation.

With respect to the papers above mentioned, the current paper has three traits of novelties that we describe in what follows. First, the model we consider involves a contact condition with normal compliance, unilateral constraint and memory term. This condition takes into account both the deformability, the rigidity, and the memory effects of the foundation. Second, in contrast with the short note [4], we model the behavior of the material with a viscoplastic constitutive law with internal state variable. And, finally, we study the contact process on an unbounded interval of time which implies the use of the framework of Fréchet spaces of continuous functions, instead of that of the classical Banach spaces of continuous functions defined on a bounded interval of time. The three ingredients above lead to a new and interesting mathematical model. The aim of this work is to prove the unique weak solvability of this model and to study the dependence of the weak solution with respect to the data.

The rest of the paper is structured as follows. In Section 2 we present the notation we shall use as well as some preliminary material. In Section 3 we describe the model of the contact process. In Section 4 we list the assumptions on the data and derive the variational formulation of the problem. Then we state and prove our main existence and uniqueness result, Theorem 4.1. In Section 5 we state and prove our converge result, Theorem 5.1. It states the continuous dependence of the solution with respect to the data.

2 Notations and preliminaries

Everywhere in this paper we use the notation ℕ∗\mathbb{N}^{*} for the set of positive integers and ℝ+\mathbb{R}_{+}will represent the set of nonnegative real numbers, i.e. ℝ+=[0,+∞)\mathbb{R}_{+}=[0,+\infty). For a given r∈ℝr\in\mathbb{R} we denote by r+r^{+}its positive part, i.e. r+=max⁡{r,0}r^{+}=\max\{r,0\}. Let Ω\Omega be a bounded domain Ω⊂ℝd​(d=1,2,3)\Omega\subset\mathbb{R}^{d}(d=1,2,3) with a Lipschitz continuous boundary Γ\Gamma and let Γ1\Gamma_{1} be a measurable part of Γ\Gamma such that meas (Γ1)>0\left(\Gamma_{1}\right)>0. We use the notation 𝒙=(xi)\boldsymbol{x}=\left(x_{i}\right) for a typical point in Ω∪Γ\Omega\cup\Gamma and we denote by 𝝂=(νi)\boldsymbol{\nu}=\left(\nu_{i}\right) the outward unit normal at Γ\Gamma. Here and below the indices i,j,k,li,j,k,l run between 1 and dd and, unless stated otherwise, the summation convention over repeated indices is used. An index that follows a comma represents the partial derivative with respect to the corresponding component of the spatial variable, e.g. ui,j=∂ui/∂xju_{i,j}=\partial u_{i}/\partial x_{j}.

We denote by 𝕊d\mathbb{S}^{d} the space of second order symmetric tensors on ℝd\mathbb{R}^{d} or, equivalently, the space of symmetric matrices of order dd. The inner product and norm on ℝd\mathbb{R}^{d} and 𝕊d\mathbb{S}^{d} are defined by

𝒖⋅𝒗=ui​vi,‖𝒗‖=(𝒗⋅𝒗)12∀𝒖,𝒗∈ℝd𝝈⋅𝝉=σi​j​τi​j,‖𝝉‖=(𝝉⋅𝝉)12∀𝝈,𝝉∈𝕊d\begin{array}[]{llrl}\boldsymbol{u}\cdot\boldsymbol{v}=u_{i}v_{i},&\|\boldsymbol{v}\|=(\boldsymbol{v}\cdot\boldsymbol{v})^{\frac{1}{2}}&\forall\boldsymbol{u},\boldsymbol{v}\in\mathbb{R}^{d}\\ \boldsymbol{\sigma}\cdot\boldsymbol{\tau}=\sigma_{ij}\tau_{ij},&\|\boldsymbol{\tau}\|=(\boldsymbol{\tau}\cdot\boldsymbol{\tau})^{\frac{1}{2}}&\forall\boldsymbol{\sigma},\boldsymbol{\tau}\in\mathbb{S}^{d}\end{array}

Also, we use the notation ‖𝜿‖\|\boldsymbol{\kappa}\| for the Euclidean norm of the element 𝜿∈ℝm\boldsymbol{\kappa}\in\mathbb{R}^{m}. In addition, we use standard notation for the Lebesgue and Sobolev spaces associated
to Ω\Omega and Γ\Gamma and, moreover, we consider the spaces

V={𝒗=(vi)∈H1​(Ω)d:𝒗=𝟎​ on ​Γ1},Q={𝝉=(τi​j)∈L2​(Ω)d×d:τi​j=τj​i}.V=\left\{\boldsymbol{v}=\left(v_{i}\right)\in H^{1}(\Omega)^{d}:\boldsymbol{v}=\mathbf{0}\text{ on }\Gamma_{1}\right\},\quad Q=\left\{\boldsymbol{\tau}=\left(\tau_{ij}\right)\in L^{2}(\Omega)^{d\times d}:\tau_{ij}=\tau_{ji}\right\}.

These are real Hilbert spaces endowed with the inner products

(𝒖,𝒗)V=∫Ω𝜺​(𝒖)⋅𝜺​(𝒗)​𝑑x,(𝝈,𝝉)Q=∫Ω𝝈⋅𝝉​𝑑x(\boldsymbol{u},\boldsymbol{v})_{V}=\int_{\Omega}\boldsymbol{\varepsilon}(\boldsymbol{u})\cdot\boldsymbol{\varepsilon}(\boldsymbol{v})dx,\quad(\boldsymbol{\sigma},\boldsymbol{\tau})_{Q}=\int_{\Omega}\boldsymbol{\sigma}\cdot\boldsymbol{\tau}dx

and the associated norms ∥⋅∥V\|\cdot\|_{V} and ∥⋅∥Q\|\cdot\|_{Q}, respectively. Here 𝜺\boldsymbol{\varepsilon} represents the deformation operator given by

𝜺​(𝒗)=(εi​j​(𝒗)),εi​j​(𝒗)=12​(vi,j+vj,i)∀𝒗∈H1​(Ω)d.\boldsymbol{\varepsilon}(\boldsymbol{v})=\left(\varepsilon_{ij}(\boldsymbol{v})\right),\quad\varepsilon_{ij}(\boldsymbol{v})=\frac{1}{2}\left(v_{i,j}+v_{j,i}\right)\quad\forall\boldsymbol{v}\in H^{1}(\Omega)^{d}.

Completeness of the space ( V,∥⋅∥VV,\|\cdot\|_{V} ) follows from the assumption meas (Γ1)>0\left(\Gamma_{1}\right)>0, which allows the use of Korn’s inequality.

For an element 𝒗∈V\boldsymbol{v}\in V we still write 𝒗\boldsymbol{v} for the trace of 𝒗\boldsymbol{v} on the boundary and we denote by vνv_{\nu} and 𝒗τ\boldsymbol{v}_{\tau} the normal and tangential components of 𝒗\boldsymbol{v} on Γ\Gamma, given by vν=𝒗⋅𝝂,𝒗τ=𝒗−vν​𝝂v_{\nu}=\boldsymbol{v}\cdot\boldsymbol{\nu},\boldsymbol{v}_{\tau}=\boldsymbol{v}-v_{\nu}\boldsymbol{\nu}. Let Γ3\Gamma_{3} be a measurable part of Γ\Gamma. Then, by the Sobolev trace theorem, there exists a positive constant c0c_{0} which depends on Ω,Γ1\Omega,\Gamma_{1} and Γ3\Gamma_{3} such that

‖𝒗‖L2​(Γ3)d≤c0​‖𝒗‖V∀𝒗∈V\|\boldsymbol{v}\|_{L^{2}\left(\Gamma_{3}\right)^{d}}\leq c_{0}\|\boldsymbol{v}\|_{V}\quad\forall\boldsymbol{v}\in V (2.1)

Also, for a regular function 𝝈∈Q\boldsymbol{\sigma}\in Q we use the notation σν\sigma_{\nu} and 𝝈τ\boldsymbol{\sigma}_{\tau} for the normal and the tangential traces, i.e. σν=(𝝈​𝝂)⋅𝝂\sigma_{\nu}=(\boldsymbol{\sigma}\boldsymbol{\nu})\cdot\boldsymbol{\nu} and 𝝈τ=𝝈​𝝂−σν​𝝂\boldsymbol{\sigma}_{\tau}=\boldsymbol{\sigma}\boldsymbol{\nu}-\sigma_{\nu}\boldsymbol{\nu}. Moreover, we recall that the divergence operator is defined by the equality Div⁡𝝈=(σi​j,j)\operatorname{Div}\boldsymbol{\sigma}=\left(\sigma_{ij,j}\right) and, finally, the following Green’s formula holds:

∫Ω𝝈⋅𝜺​(𝒗)​𝑑x+∫ΩDiv⁡𝝈⋅𝒗​d​x=∫Γ𝝈​𝝂⋅𝒗​𝑑a∀𝒗∈V\int_{\Omega}\boldsymbol{\sigma}\cdot\boldsymbol{\varepsilon}(\boldsymbol{v})dx+\int_{\Omega}\operatorname{Div}\boldsymbol{\sigma}\cdot\boldsymbol{v}dx=\int_{\Gamma}\boldsymbol{\sigma}\boldsymbol{\nu}\cdot\boldsymbol{v}da\quad\forall\boldsymbol{v}\in V (2.2)

Finally, we denote by 𝐐∞\mathbf{Q}_{\infty} the space of fourth order tensor fields given by

𝐐∞={ℰ=(ℰi​j​k​l):ℰi​j​k​l=ℰj​i​k​l=ℰk​l​i​j∈L∞​(Ω),1≤i,j,k,l≤d}\mathbf{Q}_{\infty}=\left\{\mathcal{E}=\left(\mathcal{E}_{ijkl}\right):\mathcal{E}_{ijkl}=\mathcal{E}_{jikl}=\mathcal{E}_{klij}\in L^{\infty}(\Omega),\quad 1\leq i,j,k,l\leq d\right\}

and we recall that 𝐐∞\mathbf{Q}_{\infty} is a real Banach space with the norm

‖ℰ‖𝐐∞=max1≤i,j,k,l≤d⁡‖ℰi​j​k​l‖L∞​(Ω)\|\mathcal{E}\|_{\mathbf{Q}_{\infty}}=\max_{1\leq i,j,k,l\leq d}\left\|\mathcal{E}_{ijkl}\right\|_{L^{\infty}(\Omega)}

Moreover, a simple calculation shows that

‖ℰ​𝝉‖Q≤d​‖ℰ‖𝐐∞​‖𝝉‖Q∀ℰ∈𝐐∞,𝝉∈Q\|\mathcal{E}\boldsymbol{\tau}\|_{Q}\leq d\|\mathcal{E}\|_{\mathbf{Q}_{\infty}}\|\boldsymbol{\tau}\|_{Q}\quad\forall\mathcal{E}\in\mathbf{Q}_{\infty},\boldsymbol{\tau}\in Q (2.3)

For each Banach space XX we use the notation C​(ℝ+;X)C\left(\mathbb{R}_{+};X\right) for the space of continuous functions defined on ℝ+\mathbb{R}_{+}with values in XX. For a subset K⊂XK\subset X we still use the symbol C​(ℝ+;K)C\left(\mathbb{R}_{+};K\right) for the set of continuous functions defined on ℝ+\mathbb{R}_{+}with values in KK. It is well known that C​(ℝ+;X)C\left(\mathbb{R}_{+};X\right) can be organized in a canonical way as a Fréchet space,
i.e. as a complete metric space in which the corresponding topology is induced by a countable family of seminorms. Details can be found in [2] and [12], for instance. Here we restrict ourseleves to recall that the convergence of a sequence (xk)k\left(x_{k}\right)_{k} to the element xx, in the space C​(ℝ+;X)C\left(\mathbb{R}_{+};X\right), can be described as follows:

{xk→x in ​C​(ℝ+;X)​ as ​k→∞​ if and only if maxr∈[0,n]⁡‖xk​(r)−x​(r)‖X→0​ as ​k→∞, for all ​n∈ℕ∗\left\{\begin{array}[]{l}x_{k}\rightarrow x\quad\text{ in }C\left(\mathbb{R}_{+};X\right)\text{ as }k\rightarrow\infty\text{ if and only if }\\ \max_{r\in[0,n]}\left\|x_{k}(r)-x(r)\right\|_{X}\rightarrow 0\text{ as }k\rightarrow\infty,\text{ for all }n\in\mathbb{N}^{*}\end{array}\right.

The following fixed-point result will be used in Section 4 of the paper.
Theorem 2.1 Let ( X,∥⋅∥XX,\|\cdot\|_{X} ) be a real Banach space and let Λ:C​(ℝ+;X)→C​(ℝ+;X)\Lambda:C\left(\mathbb{R}_{+};X\right)\rightarrow C\left(\mathbb{R}_{+};X\right) be a nonlinear operator with the following property: there exists c>0c>0 such that

‖Λ​u​(t)−Λ​v​(t)‖X≤c​∫0t‖u​(s)−v​(s)‖X​𝑑s\|\Lambda u(t)-\Lambda v(t)\|_{X}\leq c\int_{0}^{t}\|u(s)-v(s)\|_{X}ds (2.5)

for all u,v∈C​(ℝ+;X)u,v\in C\left(\mathbb{R}_{+};X\right) and for all t∈ℝ+t\in\mathbb{R}_{+}. Then the operator Λ\Lambda has a unique fixed point η∗∈C​(ℝ+;X)\eta^{*}\in C\left(\mathbb{R}_{+};X\right).

Theorem 2.1 represents a simplified version of Corollary 2.5 in [16. We underline that in (2.5) and below, the notation Λ​η​(t)\Lambda\eta(t) represents the value of the function Λ​η\Lambda\eta at the point tt, i.e. Λ​η​(t)=(Λ​η)​(t)\Lambda\eta(t)=(\Lambda\eta)(t).

Consider now a real Hilbert space XX with inner product (⋅,⋅)X(\cdot,\cdot)_{X} and associated norm ∥⋅∥X\|\cdot\|_{X} as well as a normed space YY with norm ∥⋅∥Y\|\cdot\|_{Y}. Let KK be a subset of XX and consider the operators A:K→X,ℛ:C​(ℝ+;X)→C​(ℝ+;Y)A:K\rightarrow X,\mathcal{R}:C\left(\mathbb{R}_{+};X\right)\rightarrow C\left(\mathbb{R}_{+};Y\right) as well as the functions φ:Y×K→ℝ,f:ℝ+→X\varphi:Y\times K\rightarrow\mathbb{R},f:\mathbb{R}_{+}\rightarrow X such that:
KK is a nonempty closed convex subset of XX.

 (a) There exists ​m>0​ such that (A​u1−A​u2,u1−u2)X≥m​‖u1−u2‖X2∀u1,u2∈K. (b) There exists ​M>0​ such that ‖A​u1−A​u2‖X≤M​‖u1−u2‖X∀u1,u2∈K.}\left.\begin{array}[]{l}\text{ (a) There exists }m>0\text{ such that }\\ \left(Au_{1}-Au_{2},u_{1}-u_{2}\right)_{X}\geq m\left\|u_{1}-u_{2}\right\|_{X}^{2}\quad\forall u_{1},u_{2}\in K.\\ \text{ (b) There exists }M>0\text{ such that }\\ \left\|Au_{1}-Au_{2}\right\|_{X}\leq M\left\|u_{1}-u_{2}\right\|_{X}\quad\forall u_{1},u_{2}\in K.\end{array}\right\}
For every ​n∈ℕ∗​ there exists ​rn>0​ such that\displaystyle\text{ For every }n\in\mathbb{N}^{*}\text{ there exists }r_{n}>0\text{ such that } (2.8)
‖ℛ​u1​(t)−ℛ​u2​(t)‖Y≤rn​∫0t‖u1​(s)−u2​(s)‖X​𝑑s∀u1,u2∈C​(ℝ+;X),∀t∈[0,n]}\displaystyle\left.\qquad\begin{array}[]{l}\left\|\mathcal{R}u_{1}(t)-\mathcal{R}u_{2}(t)\right\|_{Y}\leq r_{n}\int_{0}^{t}\left\|u_{1}(s)-u_{2}(s)\right\|_{X}ds\\ \forall u_{1},u_{2}\in C\left(\mathbb{R}_{+};X\right),\forall t\in[0,n]\end{array}\right\}
 (a) The function ​φ​(u,⋅):K→ℝ​ is convex and  lower semicontinuous, for all ​u∈Y​.  (b) There exists ​α≥0​ such that φ​(u1,v2)−φ​(u1,v1)+φ​(u2,v1)−φ​(u2,v2)≤α​‖u1−u2‖Y​‖v1−v2‖X∀u1,u2∈Y,∀v1,v2∈K​. }\left.\begin{array}[]{l}\text{ (a) The function }\varphi(u,\cdot):K\rightarrow\mathbb{R}\text{ is convex and }\\ \quad\text{ lower semicontinuous, for all }u\in Y\text{. }\\ \quad\text{ (b) There exists }\alpha\geq 0\text{ such that }\\ \quad\varphi\left(u_{1},v_{2}\right)-\varphi\left(u_{1},v_{1}\right)+\varphi\left(u_{2},v_{1}\right)-\varphi\left(u_{2},v_{2}\right)\\ \quad\leq\alpha\left\|u_{1}-u_{2}\right\|_{Y}\left\|v_{1}-v_{2}\right\|_{X}\quad\forall u_{1},u_{2}\in Y,\forall v_{1},v_{2}\in K\text{. }\end{array}\right\}

The following result, proved in [17], will be used in Section 4 of this paper.
Theorem 2.2 Assume that (2.6)-(2.10) hold. Then there exists a unique function u∈C​(ℝ+;K)u\in C\left(\mathbb{R}_{+};K\right) such that, for all t∈ℝ+t\in\mathbb{R}_{+}, the inequality below holds:

(A​u​(t),v−u​(t))X+φ​(ℛ​u​(t),v)−φ​(ℛ​u​(t),u​(t))\displaystyle(Au(t),v-u(t))_{X}+\varphi(\mathcal{R}u(t),v)-\varphi(\mathcal{R}u(t),u(t)) (2.11)
≥(f​(t),v−u​(t))X∀v∈K\displaystyle\geq(f(t),v-u(t))_{X}\quad\forall v\in K

Following the terminology introduced in [17] we refer to an operator which satisfies condition (2.8) as a history-dependent operator. Moreover, (2.11) represents a historydependent quasivariational inequality.

Finally, assume that XX and YY represent two real Hilbert spaces with the inner products (⋅,⋅)X(\cdot,\cdot)_{X} and (⋅,⋅)Y(\cdot,\cdot)_{Y}, and associated norms ∥⋅∥X\|\cdot\|_{X} and ∥⋅∥Y\|\cdot\|_{Y}, respectively. Then, we denote by X×YX\times Y the product of these spaces. We recall that X×YX\times Y is a real Hilbert space with the canonical inner product (⋅,⋅)X×Y(\cdot,\cdot)_{X\times Y} defined by

(z1,z2)X×Y=(x1,x2)X+(y1,y2)Y∀z1=(x1,y1),z2=(x2,y2)∈X×Y.\left(z_{1},z_{2}\right)_{X\times Y}=\left(x_{1},x_{2}\right)_{X}+\left(y_{1},y_{2}\right)_{Y}\quad\forall z_{1}=\left(x_{1},y_{1}\right),z_{2}=\left(x_{2},y_{2}\right)\in X\times Y.

The associated norm of the space X×YX\times Y, denoted ∥⋅∥X×Y\|\cdot\|_{X\times Y}, satisfies the inequality

‖z‖X×Y≤‖x‖X+‖y‖Y≤2​‖z‖X×Y∀z=(x,y)∈X×Y\|z\|_{X\times Y}\leq\|x\|_{X}+\|y\|_{Y}\leq\sqrt{2}\|z\|_{X\times Y}\quad\forall z=(x,y)\in X\times Y

This inequality will be used several times in Sections 4 and 5 of this manuscript.

3 The model

The physical setting is as follows. A viscoplastic body occupies a bounded domain Ω⊂ℝd​(d=1,2,3)\Omega\subset\mathbb{R}^{d}(d=1,2,3) with a Lipschitz continuous boundary Γ\Gamma, divided into three measurable parts Γ1,Γ2\Gamma_{1},\Gamma_{2} and Γ3\Gamma_{3}, such that meas (Γ1)>0\left(\Gamma_{1}\right)>0. The body is subject to the action of body forces of density 𝒇0\boldsymbol{f}_{0}. We also assume that it is fixed on Γ1\Gamma_{1} and surface tractions of density 𝒇2\boldsymbol{f}_{2} act on Γ2\Gamma_{2}. On Γ3\Gamma_{3}, the body is in frictionless contact with a deformable obstacle, the so-called foundation. We assume that the contact process is quasistatic and we study it in the interval of time ℝ+=[0,∞)\mathbb{R}_{+}=[0,\infty). Then, the classical formulation of the contact problem we consider in this paper is the following.

Problem 𝒫\mathcal{P}. Find a displacement field 𝒖:Ω×ℝ+→ℝd\boldsymbol{u}:\Omega\times\mathbb{R}_{+}\rightarrow\mathbb{R}^{d}, a stress field 𝝈:Ω×ℝ+→𝕊d\boldsymbol{\sigma}:\Omega\times\mathbb{R}_{+}\rightarrow\mathbb{S}^{d} and an internal state variable 𝜿:Ω×ℝ+→ℝm\boldsymbol{\kappa}:\Omega\times\mathbb{R}_{+}\rightarrow\mathbb{R}^{m} such that

𝝈˙​(t)=ℰ​ε​(𝒖˙​(t))+𝒢​(𝝈​(t),𝜺​(𝒖​(t)),𝜿​(t)) in Ω,𝜿˙​(t)=𝑮​(𝝈​(t),𝜺​(𝒖​(t)),𝜿​(t)) in Ω,Div⁡𝝈​(t)+𝒇0​(t)=𝟎 in Ω,𝒖​(t)=𝟎 on Γ1,𝝈​(t)​𝝂=𝒇2​(t) on Γ2,𝝈τ​(t)=𝟎 on Γ3,\begin{array}[]{rll}\dot{\boldsymbol{\sigma}}(t)=\mathcal{E}\varepsilon(\dot{\boldsymbol{u}}(t))+\mathcal{G}(\boldsymbol{\sigma}(t),\boldsymbol{\varepsilon}(\boldsymbol{u}(t)),\boldsymbol{\kappa}(t))&\text{ in }&\Omega,\\ \dot{\boldsymbol{\kappa}}(t)=\boldsymbol{G}(\boldsymbol{\sigma}(t),\boldsymbol{\varepsilon}(\boldsymbol{u}(t)),\boldsymbol{\kappa}(t))&\text{ in }&\Omega,\\ \operatorname{Div}\boldsymbol{\sigma}(t)+\boldsymbol{f}_{0}(t)=\mathbf{0}&\text{ in }&\Omega,\\ \boldsymbol{u}(t)=\mathbf{0}&\text{ on }&\Gamma_{1},\\ \boldsymbol{\sigma}(t)\boldsymbol{\nu}=\boldsymbol{f}_{2}(t)&\text{ on }&\Gamma_{2},\\ \boldsymbol{\sigma}_{\tau}(t)=\mathbf{0}&\text{ on }&\Gamma_{3},\end{array}

for all t∈ℝ+t\in\mathbb{R}_{+}, there exists ξ:Γ3×ℝ+→ℝ\xi:\Gamma_{3}\times\mathbb{R}_{+}\rightarrow\mathbb{R} which satisfies

uν​(t)≤g,σν​(t)+p​(uν​(t))+ξ​(t)≤0(uν​(t)−g)​(σν​(t)+p​(uν​(t))+ξ​(t))=00≤ξ​(t)≤∫0tb​(t−s)​uν+​(s)​𝑑sξ​(t)=0​ if ​uν​(t)<0ξ​(t)=∫0tb​(t−s)​uν+​(s)​𝑑s​ if ​uν​(t)>0} on Γ3\left.\begin{array}[]{l}u_{\nu}(t)\leq g,\sigma_{\nu}(t)+p\left(u_{\nu}(t)\right)+\xi(t)\leq 0\\ \left(u_{\nu}(t)-g\right)\left(\sigma_{\nu}(t)+p\left(u_{\nu}(t)\right)+\xi(t)\right)=0\\ 0\leq\xi(t)\leq\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds\\ \xi(t)=0\text{ if }u_{\nu}(t)<0\\ \xi(t)=\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds\text{ if }u_{\nu}(t)>0\end{array}\right\}\quad\text{ on }\quad\Gamma_{3}

for all t∈ℝ+t\in\mathbb{R}_{+}and, moreover,

𝒖​(0)=𝒖0,𝝈​(0)=𝝈0,𝜿​(0)=𝜿0 in Ω.\boldsymbol{u}(0)=\boldsymbol{u}_{0},\quad\boldsymbol{\sigma}(0)=\boldsymbol{\sigma}_{0},\quad\boldsymbol{\kappa}(0)=\boldsymbol{\kappa}_{0}\quad\text{ in }\quad\Omega. (3.8)

Here and below, in order to simplify the notation, we do not indicate explicitly the dependence of various functions on the spatial variable 𝒙\boldsymbol{x}. Equations (3.1), (3.2) represent the rate-type viscoplastic constitutive law with internal state variable introduced in Section (1. Equation (3.3) represents the equation of equilibrium in which Div denotes the divergence operator for tensor valued functions. Conditions (3.4) and (3.5) are the displacement boundary condition and the traction boundary condition, respectively. Condition (3.6) is the frictionless condition and it shows that the tangential stress on the contact surface vanishes. Finally, (3.8) represents the initial conditions in which 𝒖0,𝝈0,𝜿0\boldsymbol{u}_{0},\boldsymbol{\sigma}_{0},\boldsymbol{\kappa}_{0} denote the initial displacement, the initial stress field and the initial state variable, respectively.

We now describe the contact condition (3.7) in which our main interest is. Here σν\sigma_{\nu} denotes the normal stress, uνu_{\nu} is the normal displacement and uν+u_{\nu}^{+}may be interpreted as the penetration of the body’s surface asperities and those of the foundation. Moreover, pp is a Lipschitz continuous increasing function which vanishes for a negative argument, bb is a positive function and g>0g>0. This condition can be derived in the following way. Let t∈ℝ+t\in\mathbb{R}_{+}be a given time moment. First, we assume that the penetration
is limited by the bound gg and, therefore, at each time moment t∈ℝ+t\in\mathbb{R}_{+}, the normal displacement satisfies the inequality

uν​(t)≤g on ​Γ3.u_{\nu}(t)\leq g\quad\text{ on }\Gamma_{3}. (3.9)

Next, we assume that the normal stress has an additive decomposition of the form

σν​(t)=σνD​(t)+σνR​(t)+σνM​(t) on ​Γ3\sigma_{\nu}(t)=\sigma_{\nu}^{D}(t)+\sigma_{\nu}^{R}(t)+\sigma_{\nu}^{M}(t)\quad\text{ on }\Gamma_{3} (3.10)

in which the functions σνD​(t),σνR​(t)\sigma_{\nu}^{D}(t),\sigma_{\nu}^{R}(t) and σνM​(t)\sigma_{\nu}^{M}(t) describe the deformability, the rigidity and the memory properties of the foundation. We assume that σνD​(t)\sigma_{\nu}^{D}(t) satisfies a normal compliance contact condition, that is

−σνD​(t)=p​(uν​(t)) on ​Γ3.-\sigma_{\nu}^{D}(t)=p\left(u_{\nu}(t)\right)\quad\text{ on }\Gamma_{3}. (3.11)

The part σνR​(t)\sigma_{\nu}^{R}(t) of the normal stress satisfies the Signorini condition in the form with a gap function, i.e.

σνR​(t)≤0,σνR​(t)​(uν​(t)−g)=0 on ​Γ3.\sigma_{\nu}^{R}(t)\leq 0,\quad\sigma_{\nu}^{R}(t)\left(u_{\nu}(t)-g\right)=0\quad\text{ on }\Gamma_{3}. (3.12)

And, finally, the function σνM​(t)\sigma_{\nu}^{M}(t) satisfies the condition

{|σνM​(t)|≤∫0tb​(t−s)​uν+​(s)​𝑑s,σνM​(t)=0 if uν​(t)<0−σνM​(t)=∫0tb​(t−s)​uν+​(s)​𝑑s if uν​(t)>0\left\{\begin{array}[]{l}\left|\sigma_{\nu}^{M}(t)\right|\leq\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds,\quad\sigma_{\nu}^{M}(t)=0\quad\text{ if }\quad u_{\nu}(t)<0\\ -\sigma_{\nu}^{M}(t)=\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds\quad\text{ if }\quad u_{\nu}(t)>0\end{array}\right.

on Γ3\Gamma_{3}. We combine (3.10), (3.11) and denote −σνM​(t)=ξ​(t)-\sigma_{\nu}^{M}(t)=\xi(t) to see that

σνR​(t)=σν​(t)+p​(uν​(t))+ξ​(t) on ​Γ3\sigma_{\nu}^{R}(t)=\sigma_{\nu}(t)+p\left(u_{\nu}(t)\right)+\xi(t)\quad\text{ on }\Gamma_{3} (3.14)

Then we substitute equality (3.14) in (3.12) and use (3.9), (3.13) to obtain the contact condition (3.6).

We now present additional details of the contact condition (3.7). The inequalities and equalities below in this section are valid in an arbitrary point 𝒙∈Γ3\boldsymbol{x}\in\Gamma_{3}. First, we recall that (3.7) describes a condition with unilateral constraint, since inequality (3.9) holds at each time moment. Next, assume that at a given moment tt there is penetration which did not reach the bound gg, i.e. 0<uν​(t)<g0<u_{\nu}(t)<g. Then (3.7) yields

−σν​(t)=p​(uν​(t))+∫0tb​(t−s)​uν+​(s)​𝑑s-\sigma_{\nu}(t)=p\left(u_{\nu}(t)\right)+\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds (3.15)

This equality shows that at the moment tt, the reaction of the foundation depend both on the current value of the penetration (represented by the term p​(uν​(t))p\left(u_{\nu}(t)\right) ) as well as on the history of the penetration (represented by the integral term in (3.15)). Assume now that at a given moment tt there is separation between the body and the foundation, i.e. uν​(t)<0u_{\nu}(t)<0. Then, since p​(uν​(t))=0p\left(u_{\nu}(t)\right)=0, (3.7) shows that σν​(t)=0\sigma_{\nu}(t)=0,
i.e. the reaction of the foundation vanishes. Note that the same behavior of the normal stress is described both in the classical normal compliance condition and in the Signorini contact condition, when separation arises.

In conclusion, condition (3.7) shows that when there is separation then the normal stress vanishes; when there is penetration the contact follows a normal compliance condition with memory term of the form (3.15) but up to the limit gg and then, when this limit is reached, the contact follows a Signorini-type unilateral condition with the gap gg. For this reason we refer to this condition as to a normal compliance contact condition with unilateral constraint and memory term. It can be interpreted physically as follows. The foundation is assumed to be made of a hard material covered by a thin layer of a soft material with thickness gg. The soft material has a viscoelastic behaviour, i.e. is deformable, allows penetration and presents memory effects; the contact with this layer is modelled with normal compliance and memory term, as shown in equality (3.15). The hard material is perfectly rigid and, therefore, it does not allow penetration; the contact with this material is modelled with the Signorini contact condition. To resume, the foundation has a rigid-viscoelastic behavior; its viscoelastic behavior is given by the layer of the soft material while its rigid behavior is given by the hard material.

4 Existence and uniqueness

In this section we list the assumptions on the data, derive the variational formulation of the problem 𝒫\mathcal{P} and then we state and prove its unique weak solvability. To this end we assume that the elasticity tensor ℰ\mathcal{E} and the constitutive functions 𝒢\mathcal{G} and 𝑮\boldsymbol{G} satisfy the following conditions.

{ (a) ​ℰ=(ℰi​j​k​l):Ω×𝕊d→𝕊d. (b) ​ℰi​j​k​l=ℰk​l​i​j=ℰj​i​k​l∈L∞​(Ω),1≤i,j,k,l≤d. (c) There exists ​mℰ>0​ such that ℰ​𝝉⋅𝝉≥mℰ​‖𝝉‖2​∀𝝉∈𝕊d, a.e. in ​Ω.\displaystyle\left\{\begin{array}[]{l}\text{ (a) }\mathcal{E}=\left(\mathcal{E}_{ijkl}\right):\Omega\times\mathbb{S}^{d}\rightarrow\mathbb{S}^{d}.\\ \text{ (b) }\mathcal{E}_{ijkl}=\mathcal{E}_{klij}=\mathcal{E}_{jikl}\in L^{\infty}(\Omega),1\leq i,j,k,l\leq d.\\ \text{ (c) There exists }m_{\mathcal{E}}>0\text{ such that }\\ \mathcal{E}\boldsymbol{\tau}\cdot\boldsymbol{\tau}\geq m_{\mathcal{E}}\|\boldsymbol{\tau}\|^{2}\forall\boldsymbol{\tau}\in\mathbb{S}^{d},\text{ a.e. in }\Omega.\end{array}\right. (4.1)
{ (a) ​𝒢:Ω×𝕊d×𝕊d×ℝm→𝕊d. (b) There exists ​L𝒢>0​ such that ‖𝒢​(𝒙,𝝈1,𝜺1,𝜿1)−𝒢​(𝒙,𝝈2,𝜺2,𝜿2)‖≤L𝒢​(‖𝝈1−𝝈2‖+‖𝜺1−𝜺2‖+‖𝜿1−𝜿2‖)∀𝝈1,𝝈2,𝜺1,𝜺2∈𝕊d,𝜿1,𝜿2∈ℝm, a.e. ​𝒙∈Ω. (c) The mapping ​𝒙↦𝒢​(𝒙,𝝈,𝜺,𝜿)​ is measurable on ​Ω, for any ​𝝈,𝜺∈𝕊d​ and ​𝜿∈ℝm​.  (d) The mapping ​𝒙↦𝒢​(𝒙,𝟎,𝟎,𝟎)​ belongs to ​Q.\displaystyle\left\{\begin{array}[]{l}\text{ (a) }\mathcal{G}:\Omega\times\mathbb{S}^{d}\times\mathbb{S}^{d}\times\mathbb{R}^{m}\rightarrow\mathbb{S}^{d}.\\ \text{ (b) There exists }L_{\mathcal{G}}>0\text{ such that }\\ \left\|\mathcal{G}\left(\boldsymbol{x},\boldsymbol{\sigma}_{1},\boldsymbol{\varepsilon}_{1},\boldsymbol{\kappa}_{1}\right)-\mathcal{G}\left(\boldsymbol{x},\boldsymbol{\sigma}_{2},\boldsymbol{\varepsilon}_{2},\boldsymbol{\kappa}_{2}\right)\right\|\\ \quad\leq L_{\mathcal{G}}\left(\left\|\boldsymbol{\sigma}_{1}-\boldsymbol{\sigma}_{2}\right\|+\left\|\boldsymbol{\varepsilon}_{1}-\boldsymbol{\varepsilon}_{2}\right\|+\left\|\boldsymbol{\kappa}_{1}-\boldsymbol{\kappa}_{2}\right\|\right)\\ \quad\forall\boldsymbol{\sigma}_{1},\boldsymbol{\sigma}_{2},\boldsymbol{\varepsilon}_{1},\boldsymbol{\varepsilon}_{2}\in\mathbb{S}^{d},\boldsymbol{\kappa}_{1},\boldsymbol{\kappa}_{2}\in\mathbb{R}^{m},\text{ a.e. }\boldsymbol{x}\in\Omega.\\ \text{ (c) The mapping }\boldsymbol{x}\mapsto\mathcal{G}(\boldsymbol{x},\boldsymbol{\sigma},\boldsymbol{\varepsilon},\boldsymbol{\kappa})\text{ is measurable on }\Omega,\\ \quad\text{ for any }\boldsymbol{\sigma},\boldsymbol{\varepsilon}\in\mathbb{S}^{d}\text{ and }\boldsymbol{\kappa}\in\mathbb{R}^{m}\text{. }\\ \text{ (d) The mapping }\boldsymbol{x}\mapsto\mathcal{G}(\boldsymbol{x},\mathbf{0},\mathbf{0},\mathbf{0})\text{ belongs to }Q.\end{array}\right. (4.2)
{ (a) ​𝑮:Ω×𝕊d×𝕊d×ℝm→ℝm. (b) There exists ​LG>0​ such that ‖𝑮​(𝒙,𝝈1,𝜺1,𝜿1)−𝑮​(𝒙,𝝈2,𝜺2,𝜿2)‖≤LG​(‖𝝈1−𝝈2‖+‖𝜺1−𝜺2‖+‖𝜿1−𝜿2‖)∀𝝈1,𝝈2,𝜺1,𝜺2∈𝕊d,𝜿1,𝜿2∈ℝm, a.e. ​𝒙∈Ω. (c) The mapping ​𝒙↦𝑮​(𝒙,𝝈,𝜺,𝜿)​ is measurable on ​Ω, for any ​𝝈,𝜺∈𝕊d​ and ​𝜿∈ℝm. (d) The mapping ​𝒙↦𝑮​(𝒙,𝟎,𝟎,𝟎)​ belongs to ​L2​(Ω)m​. \left\{\begin{array}[]{l}\text{ (a) }\boldsymbol{G}:\Omega\times\mathbb{S}^{d}\times\mathbb{S}^{d}\times\mathbb{R}^{m}\rightarrow\mathbb{R}^{m}.\\ \text{ (b) There exists }L_{G}>0\text{ such that }\\ \quad\left\|\boldsymbol{G}\left(\boldsymbol{x},\boldsymbol{\sigma}_{1},\boldsymbol{\varepsilon}_{1},\boldsymbol{\kappa}_{1}\right)-\boldsymbol{G}\left(\boldsymbol{x},\boldsymbol{\sigma}_{2},\boldsymbol{\varepsilon}_{2},\boldsymbol{\kappa}_{2}\right)\right\|\\ \quad\leq L_{G}\left(\left\|\boldsymbol{\sigma}_{1}-\boldsymbol{\sigma}_{2}\right\|+\left\|\boldsymbol{\varepsilon}_{1}-\boldsymbol{\varepsilon}_{2}\right\|+\left\|\boldsymbol{\kappa}_{1}-\boldsymbol{\kappa}_{2}\right\|\right)\\ \quad\forall\boldsymbol{\sigma}_{1},\boldsymbol{\sigma}_{2},\boldsymbol{\varepsilon}_{1},\boldsymbol{\varepsilon}_{2}\in\mathbb{S}^{d},\boldsymbol{\kappa}_{1},\boldsymbol{\kappa}_{2}\in\mathbb{R}^{m},\text{ a.e. }\boldsymbol{x}\in\Omega.\\ \text{ (c) The mapping }\boldsymbol{x}\mapsto\boldsymbol{G}(\boldsymbol{x},\boldsymbol{\sigma},\boldsymbol{\varepsilon},\boldsymbol{\kappa})\text{ is measurable on }\Omega,\\ \quad\text{ for any }\boldsymbol{\sigma},\boldsymbol{\varepsilon}\in\mathbb{S}^{d}\text{ and }\boldsymbol{\kappa}\in\mathbb{R}^{m}.\\ \text{ (d) The mapping }\boldsymbol{x}\mapsto\boldsymbol{G}(\boldsymbol{x},\mathbf{0},\mathbf{0},\mathbf{0})\text{ belongs to }L^{2}(\Omega)^{m}\text{. }\end{array}\right.

The densities of body forces and surface tractions are such that

𝒇0∈C​(ℝ+;L2​(Ω)d),𝒇2∈C​(ℝ+;L2​(Γ2)d)\boldsymbol{f}_{0}\in C\left(\mathbb{R}_{+};L^{2}(\Omega)^{d}\right),\quad\boldsymbol{f}_{2}\in C\left(\mathbb{R}_{+};L^{2}\left(\Gamma_{2}\right)^{d}\right) (4.4)

and the normal compliance function pp satisfies

{ (a) ​p:Γ3×ℝ→ℝ+.(b) There exists ​Lp>0​ such that |p​(𝒙,r1)−p​(𝒙,r2)|≤Lp​|r1−r2|∀r1,r2∈ℝ, a.e. ​𝒙∈Γ3. (c) ​(p​(𝒙,r1)−p​(𝒙,r2))​(r1−r2)≥0∀r1,r2∈ℝ, a.e. ​𝒙∈Γ3. (d) The mapping ​𝒙↦p​(𝒙,r)​ is measurable on ​Γ3, for any ​r∈ℝ. (e) ​p​(𝒙,r)=0​ for all ​r≤0, a.e. ​𝒙∈Γ3.\left\{\begin{array}[]{l}\text{ (a) }p:\Gamma_{3}\times\mathbb{R}\rightarrow\mathbb{R}_{+}.\\ \text{(b) There exists }L_{p}>0\text{ such that }\\ \quad\left|p\left(\boldsymbol{x},r_{1}\right)-p\left(\boldsymbol{x},r_{2}\right)\right|\leq L_{p}\left|r_{1}-r_{2}\right|\\ \quad\forall r_{1},r_{2}\in\mathbb{R},\text{ a.e. }\boldsymbol{x}\in\Gamma_{3}.\\ \text{ (c) }\left(p\left(\boldsymbol{x},r_{1}\right)-p\left(\boldsymbol{x},r_{2}\right)\right)\left(r_{1}-r_{2}\right)\geq 0\\ \quad\forall r_{1},r_{2}\in\mathbb{R},\text{ a.e. }\boldsymbol{x}\in\Gamma_{3}.\\ \text{ (d) The mapping }\boldsymbol{x}\mapsto p(\boldsymbol{x},r)\text{ is measurable on }\Gamma_{3},\\ \quad\text{ for any }r\in\mathbb{R}.\\ \text{ (e) }p(\boldsymbol{x},r)=0\text{ for all }r\leq 0,\text{ a.e. }\boldsymbol{x}\in\Gamma_{3}.\end{array}\right.

Also, the surface memory function and the initial data verify

b∈C​(ℝ+;L∞​(Γ3)),b​(t,𝒙)≥0 for all ​t∈ℝ+,a.e. ​𝒙∈Γ3𝒖0∈U,𝝈0∈Q,𝜿0∈L2​(Ω)m\begin{array}[]{cl}b\in C\left(\mathbb{R}_{+};L^{\infty}\left(\Gamma_{3}\right)\right),\quad b(t,\boldsymbol{x})\geq 0&\text{ for all }t\in\mathbb{R}_{+},\text{a.e. }\boldsymbol{x}\in\Gamma_{3}\\ \boldsymbol{u}_{0}\in U,\quad\boldsymbol{\sigma}_{0}\in Q,\quad\boldsymbol{\kappa}_{0}\in L^{2}(\Omega)^{m}\end{array}

where UU denotes the set of admissible displacements defined by

U={𝒗∈V:vν≤g​ on ​Γ3}U=\left\{\boldsymbol{v}\in V:v_{\nu}\leq g\text{ on }\Gamma_{3}\right\} (4.8)

Assume in what follows that ( 𝒖,𝝈,𝜿\boldsymbol{u},\boldsymbol{\sigma},\boldsymbol{\kappa} ) are sufficiently regular functions which satisfy (3.1)-(3.8) and let 𝒗∈U\boldsymbol{v}\in U and t>0t>0 be given. First, we integrate equations (3.1), (3.2) with the initial conditions (3.8) to obtain

𝝈​(t)=∫0t𝒢​(𝝈​(s),𝜺​(𝒖​(s)),𝜿​(s))​𝑑s+𝝈0−ℰ​𝜺​(𝒖0)+ℰ​𝜺​(𝒖​(t))\boldsymbol{\sigma}(t)=\int_{0}^{t}\mathcal{G}(\boldsymbol{\sigma}(s),\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\boldsymbol{\kappa}(s))ds+\boldsymbol{\sigma}_{0}-\mathcal{E}\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{0}\right)+\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(t)) (4.9)

and

𝜿​(t)=∫0t𝑮​(𝝈​(s),𝜺​(𝒖​(s)),𝜿​(s))​𝑑s+𝜿0\boldsymbol{\kappa}(t)=\int_{0}^{t}\boldsymbol{G}(\boldsymbol{\sigma}(s),\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\boldsymbol{\kappa}(s))ds+\boldsymbol{\kappa}_{0} (4.10)

Next, we use Green formula (2.2) and the equilibrium equation (3.3) to see that

∫Ω𝝈​(t)⋅(ε​(𝒗)−𝜺​(𝒖​(t)))​𝑑x=∫Ω𝒇0​(t)⋅(𝒗−𝒖​(t))​𝑑x+∫Γ𝝈​(t)​𝝂⋅(𝒗−𝒖​(t))​𝑑a\int_{\Omega}\boldsymbol{\sigma}(t)\cdot(\varepsilon(\boldsymbol{v})-\boldsymbol{\varepsilon}(\boldsymbol{u}(t)))dx=\int_{\Omega}\boldsymbol{f}_{0}(t)\cdot(\boldsymbol{v}-\boldsymbol{u}(t))dx+\int_{\Gamma}\boldsymbol{\sigma}(t)\boldsymbol{\nu}\cdot(\boldsymbol{v}-\boldsymbol{u}(t))da

We split the surface integral over Γ1,Γ2\Gamma_{1},\Gamma_{2} and Γ3\Gamma_{3} and, since 𝒗−𝒖​(t)=𝟎\boldsymbol{v}-\boldsymbol{u}(t)=\mathbf{0} a.e. on Γ1\Gamma_{1}, 𝝈​(t)​𝝂=𝒇2​(t)\boldsymbol{\sigma}(t)\boldsymbol{\nu}=\boldsymbol{f}_{2}(t) on Γ2\Gamma_{2}, we deduce that

∫Ω𝝈​(t)⋅(𝜺​(𝒗)−𝜺​(𝒖​(t)))​𝑑x=∫Ω𝒇0​(t)⋅(𝒗−𝒖​(t))​𝑑x\displaystyle\int_{\Omega}\boldsymbol{\sigma}(t)\cdot(\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}(\boldsymbol{u}(t)))dx=\int_{\Omega}\boldsymbol{f}_{0}(t)\cdot(\boldsymbol{v}-\boldsymbol{u}(t))dx
+∫Γ2𝒇2​(t)⋅(𝒗−𝒖​(t))​𝑑a+∫Γ3𝝈​(t)​𝝂⋅(𝒗−𝒖​(t))​𝑑a\displaystyle\quad+\int_{\Gamma_{2}}\boldsymbol{f}_{2}(t)\cdot(\boldsymbol{v}-\boldsymbol{u}(t))da+\int_{\Gamma_{3}}\boldsymbol{\sigma}(t)\boldsymbol{\nu}\cdot(\boldsymbol{v}-\boldsymbol{u}(t))da

Moreover, since

𝝈​(t)​𝝂⋅(𝒗−𝒖​(t))=σν​(t)​(vν−uν​(t))+𝝈τ​(t)⋅(𝒗τ−𝒖τ​(t)) on ​Γ3,\boldsymbol{\sigma}(t)\boldsymbol{\nu}\cdot(\boldsymbol{v}-\boldsymbol{u}(t))=\sigma_{\nu}(t)\left(v_{\nu}-u_{\nu}(t)\right)+\boldsymbol{\sigma}_{\tau}(t)\cdot\left(\boldsymbol{v}_{\tau}-\boldsymbol{u}_{\tau}(t)\right)\quad\text{ on }\Gamma_{3},

taking into account the frictionless condition (3.6) we obtain

∫Ω𝝈\displaystyle\int_{\Omega}\boldsymbol{\sigma} (t)⋅(𝜺​(𝒗)−𝜺​(𝒖​(t)))​d​x=∫Ω𝒇0​(t)⋅(𝒗−𝒖​(t))​𝑑x\displaystyle(t)\cdot(\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}(\boldsymbol{u}(t)))dx=\int_{\Omega}\boldsymbol{f}_{0}(t)\cdot(\boldsymbol{v}-\boldsymbol{u}(t))dx (4.11)
+∫Γ2𝒇2​(t)⋅(𝒗−𝒖​(t))​𝑑a+∫Γ3σν​(t)​(vν−uν​(t))​𝑑a\displaystyle+\int_{\Gamma_{2}}\boldsymbol{f}_{2}(t)\cdot(\boldsymbol{v}-\boldsymbol{u}(t))da+\int_{\Gamma_{3}}\sigma_{\nu}(t)\left(v_{\nu}-u_{\nu}(t)\right)da

We write now

σν​(t)​(vν−uν​(t))=(σν​(t)+p​(uν​(t))+ξ​(t))​(vν−g)\displaystyle\sigma_{\nu}(t)\left(v_{\nu}-u_{\nu}(t)\right)=\left(\sigma_{\nu}(t)+p\left(u_{\nu}(t)\right)+\xi(t)\right)\left(v_{\nu}-g\right)
+(σν​(t)+p​(uν​(t))+ξ​(t))​(g−uν​(t))\displaystyle\quad+\left(\sigma_{\nu}(t)+p\left(u_{\nu}(t)\right)+\xi(t)\right)\left(g-u_{\nu}(t)\right)
−(p​(uν​(t))+ξ​(t))​(vν−uν​(t)) on ​Γ3\displaystyle\quad-\left(p\left(u_{\nu}(t)\right)+\xi(t)\right)\left(v_{\nu}-u_{\nu}(t)\right)\quad\text{ on }\Gamma_{3}

then we use the contact conditions (3.7) and the definition (4.8) of the set UU to see that

σν​(t)​(vν−uν​(t))≥−(p​(uν​(t))+ξ​(t))​(vν−uν​(t)) on ​Γ3\sigma_{\nu}(t)\left(v_{\nu}-u_{\nu}(t)\right)\geq-\left(p\left(u_{\nu}(t)\right)+\xi(t)\right)\left(v_{\nu}-u_{\nu}(t)\right)\quad\text{ on }\Gamma_{3} (4.12)

We use (3.7), again, and the hypothesis (4.6) on function bb to deduce that

(∫0tb​(t−s)​uν+​(s)​𝑑s)​(vν+−uν+​(t))≥ξ​(t)​(vν−uν​(t)) on ​Γ3\left(\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds\right)\left(v_{\nu}^{+}-u_{\nu}^{+}(t)\right)\geq\xi(t)\left(v_{\nu}-u_{\nu}(t)\right)\quad\text{ on }\Gamma_{3} (4.13)

Then we add the inequalities (4.12) and (4.13) and integrate the result on Γ3\Gamma_{3} to find that

∫Γ3σν​(t)​(vν−uν​(t))​𝑑a\displaystyle\int_{\Gamma_{3}}\sigma_{\nu}(t)\left(v_{\nu}-u_{\nu}(t)\right)da (4.14)
≥−(p​(uν​(t)),vν−uν​(t))L2​(Γ3)−(∫0tb​(t−s)​uν+​(s)​𝑑s,vν+−uν+​(t))L2​(Γ3)\displaystyle\quad\geq-\left(p\left(u_{\nu}(t)\right),v_{\nu}-u_{\nu}(t)\right)_{L^{2}\left(\Gamma_{3}\right)}-\left(\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds,v_{\nu}^{+}-u_{\nu}^{+}(t)\right)_{L^{2}\left(\Gamma_{3}\right)}

Finally, we combine (4.11) and (4.14) to deduce that

(𝝈​(t),𝜺​(𝒗)−𝜺​(𝒖​(t)))Q+(p​(uν​(t)),vν−uν​(t))L2​(Γ3)\displaystyle(\boldsymbol{\sigma}(t),\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}(\boldsymbol{u}(t)))_{Q}+\left(p\left(u_{\nu}(t)\right),v_{\nu}-u_{\nu}(t)\right)_{L^{2}\left(\Gamma_{3}\right)} (4.15)
+(∫0tb​(t−s)​uν+​(s)​𝑑s,vν+−uν+​(t))L2​(Γ3)\displaystyle\quad+\left(\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds,v_{\nu}^{+}-u_{\nu}^{+}(t)\right)_{L^{2}\left(\Gamma_{3}\right)}
≥(𝒇0​(t),𝒗−𝒖​(t))L2​(Ω)d+(𝒇2​(t),𝒗−𝒖​(t))L2​(Γ2)d∀𝒗∈U\displaystyle\quad\geq\left(\boldsymbol{f}_{0}(t),\boldsymbol{v}-\boldsymbol{u}(t)\right)_{L^{2}(\Omega)^{d}}+\left(\boldsymbol{f}_{2}(t),\boldsymbol{v}-\boldsymbol{u}(t)\right)_{L^{2}\left(\Gamma_{2}\right)^{d}}\quad\forall\boldsymbol{v}\in U

We gather the results above to obtain the following variational formulation of Problem 𝒫\mathcal{P}.

Problem 𝒫V\mathcal{P}^{V}. Find a displacement field 𝒖:ℝ+→U\boldsymbol{u}:\mathbb{R}_{+}\rightarrow U, a stress field 𝝈:ℝ+→Q\boldsymbol{\sigma}:\mathbb{R}_{+}\rightarrow Q and an internal state variable 𝜿:ℝ+→L2​(Ω)m\boldsymbol{\kappa}:\mathbb{R}_{+}\rightarrow L^{2}(\Omega)^{m} such that (4.9), (4.10) and (4.15) hold, for all t∈ℝ+t\in\mathbb{R}_{+}.

In the study of the problem 𝒫V\mathcal{P}^{V} we have the following existence and uniqueness result.

Theorem 4.1 Assume that (4.1) -(4.7) hold. Then, Problem 𝒫V\mathcal{P}^{V} has a unique solution which satisfies

𝒖∈C​(ℝ+;U),𝝈∈C​(ℝ+;Q) and 𝜿∈C​(ℝ+;L2​(Ω)m).\boldsymbol{u}\in C\left(\mathbb{R}_{+};U\right),\quad\boldsymbol{\sigma}\in C\left(\mathbb{R}_{+};Q\right)\quad\text{ and }\quad\boldsymbol{\kappa}\in C\left(\mathbb{R}_{+};L^{2}(\Omega)^{m}\right). (4.16)

We now turn to the proof of the theorem. We start with the following existence and uniqueness result.

Lemma 4.2 Assume that (4.1) -(4.3) and (4.7) hold. Then, for each 𝒖∈C​(ℝ+;V)\boldsymbol{u}\in C\left(\mathbb{R}_{+};V\right) there exists a unique function 𝒮​𝒖=(𝒮1​𝒖,𝒮2​𝒖)∈C​(ℝ+;Q×L2​(Ω)m)\mathcal{S}\boldsymbol{u}=\left(\mathcal{S}_{1}\boldsymbol{u},\mathcal{S}_{2}\boldsymbol{u}\right)\in C\left(\mathbb{R}_{+};Q\times L^{2}(\Omega)^{m}\right) such that

𝒮1​𝒖​(t)=∫0t𝒢​(𝒮1​𝒖​(s)+ℰ​ε​(𝒖​(s)),𝜺​(𝒖​(s)),𝒮2​𝒖​(s))​𝑑s+𝝈0−ℰ​ε​(𝒖0)\displaystyle\mathcal{S}_{1}\boldsymbol{u}(t)=\int_{0}^{t}\mathcal{G}\left(\mathcal{S}_{1}\boldsymbol{u}(s)+\mathcal{E}\varepsilon(\boldsymbol{u}(s)),\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\mathcal{S}_{2}\boldsymbol{u}(s)\right)ds+\boldsymbol{\sigma}_{0}-\mathcal{E}\varepsilon\left(\boldsymbol{u}_{0}\right) (4.17)
𝒮2​𝒖​(t)=∫0t𝑮​(𝒮1​𝒖​(s)+ℰ​ε​(𝒖​(s)),𝜺​(𝒖​(s)),𝒮2​𝒖​(s))​𝑑s+𝜿0\displaystyle\mathcal{S}_{2}\boldsymbol{u}(t)=\int_{0}^{t}\boldsymbol{G}\left(\mathcal{S}_{1}\boldsymbol{u}(s)+\mathcal{E}\varepsilon(\boldsymbol{u}(s)),\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\mathcal{S}_{2}\boldsymbol{u}(s)\right)ds+\boldsymbol{\kappa}_{0} (4.18)

for all t∈ℝ+t\in\mathbb{R}_{+}. Moreover, the operator 𝒮:C​(ℝ+;V)→C​(ℝ+;Q×L2​(Ω)m)\mathcal{S}:C\left(\mathbb{R}_{+};V\right)\rightarrow C\left(\mathbb{R}_{+};Q\times L^{2}(\Omega)^{m}\right) is a history-dependent operator, i.e. it satisfies the following property: for every n∈ℕ∗n\in\mathbb{N}^{*} there exists sn>0s_{n}>0 which depends only on n,d,𝒢,𝑮n,d,\mathcal{G},\boldsymbol{G} and ℰ\mathcal{E}, such that

‖𝒮​𝒖​(t)−𝒮​𝒗​(t)‖Q×L2​(Ω)m≤sn​∫0t‖𝒖​(s)−𝒗​(s)‖V​𝑑s\displaystyle\|\mathcal{S}\boldsymbol{u}(t)-\mathcal{S}\boldsymbol{v}(t)\|_{Q\times L^{2}(\Omega)^{m}}\leq s_{n}\int_{0}^{t}\|\boldsymbol{u}(s)-\boldsymbol{v}(s)\|_{V}ds (4.19)
∀𝒖,𝒗∈C​(ℝ+;V)∀t∈[0,n]\displaystyle\forall\boldsymbol{u},\boldsymbol{v}\in C\left(\mathbb{R}_{+};V\right)\quad\forall t\in[0,n]

Proof. Let 𝒖∈C​(ℝ+;V)\boldsymbol{u}\in C\left(\mathbb{R}_{+};V\right). We consider the operator Λ:C​(ℝ+;Q×L2​(Ω)m)→C​(ℝ+;Q×L2​(Ω)m)\Lambda:C\left(\mathbb{R}_{+};Q\times L^{2}(\Omega)^{m}\right)\rightarrow C\left(\mathbb{R}_{+};Q\times L^{2}(\Omega)^{m}\right) defined by

Λ​𝝉​(t)=(Λ1​𝝉​(t),Λ2​𝝉​(t))\displaystyle\Lambda\boldsymbol{\tau}(t)=\left(\Lambda_{1}\boldsymbol{\tau}(t),\Lambda_{2}\boldsymbol{\tau}(t)\right) (4.20)
Λ1​𝝉​(t)=∫0t𝒢​(𝜶​(s)+ℰ​𝜺​(𝒖​(s)),𝜺​(𝒖​(s)),𝜷​(s))​𝑑s+𝝈0−ℰ​𝜺​(𝒖0)\displaystyle\Lambda_{1}\boldsymbol{\tau}(t)=\int_{0}^{t}\mathcal{G}(\boldsymbol{\alpha}(s)+\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\boldsymbol{\beta}(s))ds+\boldsymbol{\sigma}_{0}-\mathcal{E}\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{0}\right) (4.21)
Λ2​𝝉​(t)=∫0t𝑮​(𝜶​(s)+ℰ​𝜺​(𝒖​(s)),𝜺​(𝒖​(s)),𝜷​(s))​𝑑s+𝜿0\displaystyle\Lambda_{2}\boldsymbol{\tau}(t)=\int_{0}^{t}\boldsymbol{G}(\boldsymbol{\alpha}(s)+\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\boldsymbol{\beta}(s))ds+\boldsymbol{\kappa}_{0} (4.22)

for all 𝝉=(𝜶,𝜷)∈C​(ℝ+;Q×L2​(Ω)m)\boldsymbol{\tau}=(\boldsymbol{\alpha},\boldsymbol{\beta})\in C\left(\mathbb{R}_{+};Q\times L^{2}(\Omega)^{m}\right) and t∈ℝ+t\in\mathbb{R}_{+}. Note that the operator Λ\Lambda depends on 𝒖\boldsymbol{u} but, for simplicity, we do not indicate explicitly this dependence.

Let 𝝉1=(𝜶1,𝜷1),𝝉2=(𝜶2,𝜷2)∈C​(ℝ+;Q×L2​(Ω)m)\boldsymbol{\tau}_{1}=\left(\boldsymbol{\alpha}_{1},\boldsymbol{\beta}_{1}\right),\boldsymbol{\tau}_{2}=\left(\boldsymbol{\alpha}_{2},\boldsymbol{\beta}_{2}\right)\in C\left(\mathbb{R}_{+};Q\times L^{2}(\Omega)^{m}\right) and let t∈ℝ+t\in\mathbb{R}_{+}. Then, using definition (4.20)-(4.22) and assumptions (4.2), (4.3), we deduce that

‖Λ​𝝉1​(t)−Λ​𝝉2​(t)‖Q×L2​(Ω)m\displaystyle\left\|\Lambda\boldsymbol{\tau}_{1}(t)-\Lambda\boldsymbol{\tau}_{2}(t)\right\|_{Q\times L^{2}(\Omega)^{m}}
≤(L𝒢+LG)​∫0t(‖𝜶1​(s)−𝜶2​(s)‖Q+‖𝜷1​(s)−𝜷2​(s)‖L2​(Ω)m)​𝑑s\displaystyle\quad\leq\left(L_{\mathcal{G}}+L_{G}\right)\int_{0}^{t}\left(\left\|\boldsymbol{\alpha}_{1}(s)-\boldsymbol{\alpha}_{2}(s)\right\|_{Q}+\left\|\boldsymbol{\beta}_{1}(s)-\boldsymbol{\beta}_{2}(s)\right\|_{L^{2}(\Omega)^{m}}\right)ds
=2​(L𝒢+LG)​∫0t‖𝝉1​(s)−𝝉2​(s)‖Q×L2​(Ω)m​𝑑s\displaystyle\quad=\sqrt{2}\left(L_{\mathcal{G}}+L_{G}\right)\int_{0}^{t}\left\|\boldsymbol{\tau}_{1}(s)-\boldsymbol{\tau}_{2}(s)\right\|_{Q\times L^{2}(\Omega)^{m}}ds

This inequality combined with Theorem 2.1 shows that the operator Λ\Lambda has a unique fixed point in C​(ℝ+;Q×L2​(Ω)m)C\left(\mathbb{R}_{+};Q\times L^{2}(\Omega)^{m}\right), denoted 𝒮​𝒖=(𝒮1​𝒖,𝒮2​𝒖)\mathcal{S}\boldsymbol{u}=\left(\mathcal{S}_{1}\boldsymbol{u},\mathcal{S}_{2}\boldsymbol{u}\right). Moreover, combining (4.20)-(4.22) with equality Λ​(𝒮​𝒖)=𝒮​𝒖\Lambda(\mathcal{S}\boldsymbol{u})=\mathcal{S}\boldsymbol{u} we deduce that (4.17)-(4.18) hold.

To proceed, let 𝒖,𝒗∈C​(ℝ+;V),n∈ℕ∗\boldsymbol{u},\boldsymbol{v}\in C\left(\mathbb{R}_{+};V\right),n\in\mathbb{N}^{*} and let t∈[0,n]t\in[0,n]. Then using (4.17)(4.18) and taking into account (4.1)-(4.3) and (2.3) we obtain that

∥𝒮1𝒖(t)−\displaystyle\|\mathcal{S}_{1}\boldsymbol{u}(t)- 𝒮1𝒗(t)∥=Q∥∫0t𝒢(𝒮1𝒖(s)+ℰ𝜺(𝒖(s)),𝜺(𝒖(s)),𝒮2𝒖(s))ds\displaystyle\mathcal{S}_{1}\boldsymbol{v}(t)\left\|{}_{Q}=\right\|\int_{0}^{t}\mathcal{G}\left(\mathcal{S}_{1}\boldsymbol{u}(s)+\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\mathcal{S}_{2}\boldsymbol{u}(s)\right)ds
−∫0t𝒢​(𝒮1​𝒗​(s)+ℰ​𝜺​(𝒗​(s)),𝜺​(𝒗​(s)),𝒮2​𝒗​(s))​𝑑s∥Q\displaystyle\quad-\int_{0}^{t}\mathcal{G}\left(\mathcal{S}_{1}\boldsymbol{v}(s)+\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{v}(s)),\boldsymbol{\varepsilon}(\boldsymbol{v}(s)),\mathcal{S}_{2}\boldsymbol{v}(s)\right)ds\|_{Q}
≤\displaystyle\leq L𝒢​∫0t(‖𝒮1​𝒖​(s)−𝒮1​𝒗​(s)‖Q+‖𝒮2​𝒖​(s)−𝒮2​𝒗​(s)‖L2​(Ω)m)​𝑑s\displaystyle L_{\mathcal{G}}\int_{0}^{t}\left(\left\|\mathcal{S}_{1}\boldsymbol{u}(s)-\mathcal{S}_{1}\boldsymbol{v}(s)\right\|_{Q}+\left\|\mathcal{S}_{2}\boldsymbol{u}(s)-\mathcal{S}_{2}\boldsymbol{v}(s)\right\|_{L^{2}(\Omega)^{m}}\right)ds
+L𝒢​(d​‖ℰ‖𝐐∞+1)​∫0t‖𝜺​(𝒖​(s))−𝜺​(𝒗​(s))‖Q​𝑑s\displaystyle\quad+L_{\mathcal{G}}\left(d\|\mathcal{E}\|_{\mathbf{Q}_{\infty}}+1\right)\int_{0}^{t}\|\boldsymbol{\varepsilon}(\boldsymbol{u}(s))-\boldsymbol{\varepsilon}(\boldsymbol{v}(s))\|_{Q}ds
≤\displaystyle\leq 2​L𝒢​∫0t‖𝒮​𝒖​(s)−𝒮​𝒗​(s)‖Q×L2​(Ω)m​𝑑s\displaystyle\sqrt{2}L_{\mathcal{G}}\int_{0}^{t}\|\mathcal{S}\boldsymbol{u}(s)-\mathcal{S}\boldsymbol{v}(s)\|_{Q\times L^{2}(\Omega)^{m}}ds
+L𝒢​(d​‖ℰ‖𝐐∞+1)​∫0t‖𝒖​(s)−𝒗​(s)‖V​𝑑s\displaystyle\quad+L_{\mathcal{G}}\left(d\|\mathcal{E}\|_{\mathbf{Q}_{\infty}}+1\right)\int_{0}^{t}\|\boldsymbol{u}(s)-\boldsymbol{v}(s)\|_{V}ds
∥𝒮2𝒖(t)−\displaystyle\|\mathcal{S}_{2}\boldsymbol{u}(t)- 𝒮2𝒗(t)∥=L2​(Ω)m∥∫0t𝑮(𝒮1𝒖(s)+ℰ𝜺(𝒖(s)),𝜺(𝒖(s)),𝒮2𝒖(s))ds\displaystyle\mathcal{S}_{2}\boldsymbol{v}(t)\left\|{}_{L^{2}(\Omega)^{m}}=\right\|\int_{0}^{t}\boldsymbol{G}\left(\mathcal{S}_{1}\boldsymbol{u}(s)+\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\mathcal{S}_{2}\boldsymbol{u}(s)\right)ds
−∫0t𝑮​(𝒮1​𝒗​(s)+ℰ​𝜺​(𝒗​(s)),𝜺​(𝒗​(s)),𝒮2​𝒗​(s))​𝑑s∥L2​(Ω)m\displaystyle\quad-\int_{0}^{t}\boldsymbol{G}\left(\mathcal{S}_{1}\boldsymbol{v}(s)+\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{v}(s)),\boldsymbol{\varepsilon}(\boldsymbol{v}(s)),\mathcal{S}_{2}\boldsymbol{v}(s)\right)ds\|_{L^{2}(\Omega)^{m}}
≤\displaystyle\leq LG​∫0t(‖𝒮1​𝒖​(s)−𝒮1​𝒗​(s)‖Q+‖𝒮2​𝒖​(s)−𝒮2​𝒗​(s)‖L2​(Ω)m)​𝑑s\displaystyle L_{G}\int_{0}^{t}\left(\left\|\mathcal{S}_{1}\boldsymbol{u}(s)-\mathcal{S}_{1}\boldsymbol{v}(s)\right\|_{Q}+\left\|\mathcal{S}_{2}\boldsymbol{u}(s)-\mathcal{S}_{2}\boldsymbol{v}(s)\right\|_{L^{2}(\Omega)^{m}}\right)ds
+LG​(d​‖ℰ‖𝐐∞+1)​∫0t‖𝜺​(𝒖​(s))−𝜺​(𝒗​(s))‖Q​𝑑s\displaystyle\quad+L_{G}\left(d\|\mathcal{E}\|_{\mathbf{Q}_{\infty}}+1\right)\int_{0}^{t}\|\boldsymbol{\varepsilon}(\boldsymbol{u}(s))-\boldsymbol{\varepsilon}(\boldsymbol{v}(s))\|_{Q}ds
≤\displaystyle\leq 2​LG​∫0t‖𝒮​𝒖​(s)−𝒮​𝒗​(s)‖Q×L2​(Ω)m​𝑑s\displaystyle\sqrt{2}L_{G}\int_{0}^{t}\|\mathcal{S}\boldsymbol{u}(s)-\mathcal{S}\boldsymbol{v}(s)\|_{Q\times L^{2}(\Omega)^{m}}ds
+LG​(d​‖ℰ‖𝐐∞+1)​∫0t‖𝒖​(s)−𝒗​(s)‖V​𝑑s\displaystyle\quad+L_{G}\left(d\|\mathcal{E}\|_{\mathbf{Q}_{\infty}}+1\right)\int_{0}^{t}\|\boldsymbol{u}(s)-\boldsymbol{v}(s)\|_{V}ds

Therefore, we have

‖𝒮​𝒖​(t)−𝒮​𝒗​(t)‖Q×L2​(Ω)m≤‖𝒮1​𝒖​(t)−𝒮1​𝒗​(t)‖Q+‖𝒮2​𝒖​(t)−𝒮2​𝒗​(t)‖L2​(Ω)m\displaystyle\|\mathcal{S}\boldsymbol{u}(t)-\mathcal{S}\boldsymbol{v}(t)\|_{Q\times L^{2}(\Omega)^{m}}\leq\left\|\mathcal{S}_{1}\boldsymbol{u}(t)-\mathcal{S}_{1}\boldsymbol{v}(t)\right\|_{Q}+\left\|\mathcal{S}_{2}\boldsymbol{u}(t)-\mathcal{S}_{2}\boldsymbol{v}(t)\right\|_{L^{2}(\Omega)^{m}}
≤𝒦​(∫0t‖𝒮​𝒖​(s)−𝒮​𝒗​(s)‖Q×L2​(Ω)m​𝑑s+∫0t‖𝒖​(s)−𝒗​(s)‖V​𝑑s)\displaystyle\quad\leq\mathcal{K}\left(\int_{0}^{t}\|\mathcal{S}\boldsymbol{u}(s)-\mathcal{S}\boldsymbol{v}(s)\|_{Q\times L^{2}(\Omega)^{m}}ds+\int_{0}^{t}\|\boldsymbol{u}(s)-\boldsymbol{v}(s)\|_{V}ds\right)

where

𝒦=max⁡{2​(L𝒢+LG),(L𝒢+LG)​(d​‖ℰ‖𝐐∞+1)}.\mathcal{K}=\max\left\{\sqrt{2}\left(L_{\mathcal{G}}+L_{G}\right),\left(L_{\mathcal{G}}+L_{G}\right)\left(d\|\mathcal{E}\|_{\mathbf{Q}_{\infty}}+1\right)\right\}. (4.23)

Using now a Gronwall argument we deduce that

‖𝒮​𝒖​(t)−𝒮​𝒗​(t)‖Q×L2​(Ω)m≤𝒦​en​𝒦​∫0t‖𝒖​(s)−𝒗​(s)‖V​𝑑s\|\mathcal{S}\boldsymbol{u}(t)-\mathcal{S}\boldsymbol{v}(t)\|_{Q\times L^{2}(\Omega)^{m}}\leq\mathcal{K}e^{n\mathcal{K}}\int_{0}^{t}\|\boldsymbol{u}(s)-\boldsymbol{v}(s)\|_{V}ds (4.24)

This inequality shows that inequality (4.19) holds with sn=𝒦​en​𝒦s_{n}=\mathcal{K}e^{n\mathcal{K}}, which concludes the proof.

Next, using the Riesz representation Theorem we define the operators P:V→VP:V\rightarrow V, ℬ:C​(ℝ+;V)→C​(ℝ+;L2​(Γ3))\mathcal{B}:C\left(\mathbb{R}_{+};V\right)\rightarrow C\left(\mathbb{R}_{+};L^{2}\left(\Gamma_{3}\right)\right) and the function 𝒇:ℝ+→V\boldsymbol{f}:\mathbb{R}_{+}\rightarrow V by equalities

(P​𝒖,𝒗)V=∫Γ3p​(uν)​vν​𝑑a∀𝒖,𝒗∈V\displaystyle(P\boldsymbol{u},\boldsymbol{v})_{V}=\int_{\Gamma_{3}}p\left(u_{\nu}\right)v_{\nu}da\quad\forall\boldsymbol{u},\boldsymbol{v}\in V (4.25)
(ℬ​𝒖​(t),ξ)L2​(Γ3)=(∫0tb​(t−s)​uν+​(s)​𝑑s,ξ)L2​(Γ3)\displaystyle(\mathcal{B}\boldsymbol{u}(t),\xi)_{L^{2}\left(\Gamma_{3}\right)}=\left(\int_{0}^{t}b(t-s)u_{\nu}^{+}(s)ds,\xi\right)_{L^{2}\left(\Gamma_{3}\right)} (4.26)
∀𝒖∈C​(ℝ+;V),ξ∈L2​(Γ3),t∈ℝ+\displaystyle\quad\forall\boldsymbol{u}\in C\left(\mathbb{R}_{+};V\right),\xi\in L^{2}\left(\Gamma_{3}\right),t\in\mathbb{R}_{+}
(𝒇​(t),𝒗)V=∫Ω𝒇0​(t)⋅𝒗​𝑑x+∫Γ2𝒇2​(t)⋅𝒗​𝑑a∀𝒗∈V,t∈ℝ+\displaystyle(\boldsymbol{f}(t),\boldsymbol{v})_{V}=\int_{\Omega}\boldsymbol{f}_{0}(t)\cdot\boldsymbol{v}dx+\int_{\Gamma_{2}}\boldsymbol{f}_{2}(t)\cdot\boldsymbol{v}da\quad\forall\boldsymbol{v}\in V,t\in\mathbb{R}_{+} (4.27)

We use the operator 𝒮:C​(ℝ+;V)→C​(ℝ+;Q×L2​(Ω)m)\mathcal{S}:C\left(\mathbb{R}_{+};V\right)\rightarrow C\left(\mathbb{R}_{+};Q\times L^{2}(\Omega)^{m}\right) defined in Lemma 4.2 to obtain the following equivalence result.

Lemma 4.3 Let ( 𝒖,𝝈,𝜿\boldsymbol{u},\boldsymbol{\sigma},\boldsymbol{\kappa} ) be a triple of functions which satisfy (4.16). Then (u, 𝝈,𝜿\boldsymbol{\sigma},\boldsymbol{\kappa} ) is a solution of 𝒫V\mathcal{P}^{V} if and only if

𝝈​(t)=ℰ​𝜺​(𝒖​(t))+𝒮1​(𝒖​(t))\displaystyle\boldsymbol{\sigma}(t)=\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(t))+\mathcal{S}_{1}(\boldsymbol{u}(t)) (4.28)
𝜿​(t)=𝒮2​𝒖​(t)\displaystyle\boldsymbol{\kappa}(t)=\mathcal{S}_{2}\boldsymbol{u}(t) (4.29)
(ℰ​𝜺​(𝒖​(t)),𝜺​(𝒗)−𝜺​(𝒖​(t)))Q+(𝒮1​𝒖​(t),𝜺​(𝒗)−𝜺​(𝒖​(t)))Q\displaystyle(\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(t)),\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}(\boldsymbol{u}(t)))_{Q}+\left(\mathcal{S}_{1}\boldsymbol{u}(t),\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}(\boldsymbol{u}(t))\right)_{Q} (4.30)
+(P​𝒖​(t),𝒗−𝒖​(t))V+(ℬ​𝒖​(t),vν+−uν+​(t))L2​(Γ3)\displaystyle\quad+(P\boldsymbol{u}(t),\boldsymbol{v}-\boldsymbol{u}(t))_{V}+\left(\mathcal{B}\boldsymbol{u}(t),v_{\nu}^{+}-u_{\nu}^{+}(t)\right)_{L^{2}\left(\Gamma_{3}\right)}
≥(𝒇​(t),𝒗−𝒖​(t))V,∀𝒗∈U\displaystyle\quad\geq(\boldsymbol{f}(t),\boldsymbol{v}-\boldsymbol{u}(t))_{V},\quad\forall\boldsymbol{v}\in U

for all t∈ℝ+t\in\mathbb{R}_{+}.
Proof. First we suppose that ( 𝒖,𝝈,𝜿\boldsymbol{u},\boldsymbol{\sigma},\boldsymbol{\kappa} ) is solution for Problem 𝒫V\mathcal{P}^{V} and let t∈ℝ+t\in\mathbb{R}_{+}. Using (4.9) and (4.10) we obtain

𝝈​(t)\displaystyle\boldsymbol{\sigma}(t) −ℰ​𝜺​(𝒖​(t))\displaystyle-\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(t)) (4.31)
=∫0t𝒢​(𝝈​(s)−ℰ​𝜺​(𝒖​(s))+ℰ​𝜺​(𝒖​(s)),𝜺​(𝒖​(s)),𝜿​(s))​𝑑s+𝝈0−ℰ​𝜺​(𝒖0)\displaystyle=\int_{0}^{t}\mathcal{G}(\boldsymbol{\sigma}(s)-\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(s))+\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\boldsymbol{\kappa}(s))ds+\boldsymbol{\sigma}_{0}-\mathcal{E}\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{0}\right)
𝜿​(t)\displaystyle\boldsymbol{\kappa}(t) =∫0t𝑮​(𝝈​(s)−ℰ​𝜺​(𝒖​(s))+ℰ​𝜺​(𝒖​(s)),𝜺​(𝒖​(s)),𝜿​(s))​𝑑s+𝜿0\displaystyle=\int_{0}^{t}\boldsymbol{G}(\boldsymbol{\sigma}(s)-\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(s))+\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\boldsymbol{\kappa}(s))ds+\boldsymbol{\kappa}_{0} (4.32)

We now use the definitions of 𝒮1\mathcal{S}_{1} and 𝒮2\mathcal{S}_{2} in Lemma 4.2 to obtain (4.28) and (4.29). Then we combine (4.15), (4.28) and use notation (4.25)-(4.27) to see that (4.30) holds.

Conversely, assume that ( 𝒖,𝝈,𝜿\boldsymbol{u},\boldsymbol{\sigma},\boldsymbol{\kappa} ) satisfies (4.28)-(4.30) and let t∈ℝ+t\in\mathbb{R}_{+}. We use (4.28), (4.29) and the definitions (4.17), (4.18) of the operators 𝒮1\mathcal{S}_{1} and 𝒮2\mathcal{S}_{2} to obtain (4.31) and (4.32), which show that (4.9) and (4.10) hold. Moreover, using (4.28), (4.30) and the definitions (4.25)-(4.27) we find (4.15), which concludes the proof.

We are now in position to provide the proof for Theorem 4.1.
Proof. We first define the operators A:V→V,ℛ:C​(ℝ+;V)→C​(ℝ+;Q×L2​(Γ3))A:V\rightarrow V,\mathcal{R}:C\left(\mathbb{R}_{+};V\right)\rightarrow C\left(\mathbb{R}_{+};Q\times L^{2}\left(\Gamma_{3}\right)\right) and the functional φ:Q×L2​(Γ3)×V→ℝ\varphi:Q\times L^{2}\left(\Gamma_{3}\right)\times V\rightarrow\mathbb{R} by equalities

(A​𝒖,𝒗)=(ℰ​ε​(𝒖),𝜺​(𝒗))Q+(P​𝒖,𝒗)V∀𝒖,𝒗∈V\displaystyle(A\boldsymbol{u},\boldsymbol{v})=(\mathcal{E}\varepsilon(\boldsymbol{u}),\boldsymbol{\varepsilon}(\boldsymbol{v}))_{Q}+(P\boldsymbol{u},\boldsymbol{v})_{V}\quad\forall\boldsymbol{u},\boldsymbol{v}\in V (4.33)
ℛ​𝒖​(t)=(𝒮1​𝒖​(t),ℬ​𝒖​(t))∀𝒖∈C​(ℝ+;V)\displaystyle\mathcal{R}\boldsymbol{u}(t)=\left(\mathcal{S}_{1}\boldsymbol{u}(t),\mathcal{B}\boldsymbol{u}(t)\right)\quad\forall\boldsymbol{u}\in C\left(\mathbb{R}_{+};V\right) (4.34)
φ​(𝝈,ξ,𝒗)=(𝝈,𝜺​(𝒗))Q+(ξ+,vν+)L2​(Γ3)∀𝝈∈Q,ξ∈L2​(Γ3),𝒗∈V\displaystyle\varphi(\boldsymbol{\sigma},\xi,\boldsymbol{v})=(\boldsymbol{\sigma},\boldsymbol{\varepsilon}(\boldsymbol{v}))_{Q}+\left(\xi^{+},v_{\nu}^{+}\right)_{L^{2}\left(\Gamma_{3}\right)}\quad\forall\boldsymbol{\sigma}\in Q,\xi\in L^{2}\left(\Gamma_{3}\right),\boldsymbol{v}\in V (4.35)

With these notation we consider the problem of finding a function 𝒖:ℝ+→V\boldsymbol{u}:\mathbb{R}_{+}\rightarrow V such that, for all t∈ℝ+t\in\mathbb{R}_{+}, the following inequality holds:

𝒖​(t)∈U,(A​𝒖​(t),𝒗−𝒖​(t))V+φ​(ℛ​𝒖​(t),𝒗)−φ​(ℛ​𝒖​(t),𝒖​(t))\displaystyle\boldsymbol{u}(t)\in U,\quad(A\boldsymbol{u}(t),\boldsymbol{v}-\boldsymbol{u}(t))_{V}+\varphi(\mathcal{R}\boldsymbol{u}(t),\boldsymbol{v})-\varphi(\mathcal{R}\boldsymbol{u}(t),\boldsymbol{u}(t)) (4.36)
≥(𝒇,𝒗−𝒖​(t))V∀𝒗∈U\displaystyle\geq(\boldsymbol{f},\boldsymbol{v}-\boldsymbol{u}(t))_{V}\quad\forall\boldsymbol{v}\in U

In order to solve (4.36) we employ Theorem 2.2 with X=V,K=UX=V,K=U and Y=Q×L2​(Γ3)Y=Q\times L^{2}\left(\Gamma_{3}\right). To this end we use the definition (4.33) and inequalities (2.1), (2.3) to obtain that

|(A​𝒖−A​𝒗,𝒘)V|≤|(ℰ​ε​(𝒖)−ℰ​ε​(𝒗),𝜺​(𝒘))Q|+|(P​𝒖−P​𝒗,𝒘)V|≤d​‖ℰ‖𝐐∞​‖𝒖−𝒗‖V​‖𝒘‖V+Lp​‖𝒘‖L2​(Γ3)d​‖𝒖−𝒗‖L2​(Γ3)d≤(d​‖ℰ‖𝐐∞+c02​Lp)​‖𝒖−𝒗‖V​‖𝒘‖V∀𝒖,𝒗,𝒘∈V.\begin{gathered}\left|(A\boldsymbol{u}-A\boldsymbol{v},\boldsymbol{w})_{V}\right|\leq\left|(\mathcal{E}\varepsilon(\boldsymbol{u})-\mathcal{E}\varepsilon(\boldsymbol{v}),\boldsymbol{\varepsilon}(\boldsymbol{w}))_{Q}\right|+\left|(P\boldsymbol{u}-P\boldsymbol{v},\boldsymbol{w})_{V}\right|\\ \leq d\|\mathcal{E}\|_{\mathbf{Q}_{\infty}}\|\boldsymbol{u}-\boldsymbol{v}\|_{V}\|\boldsymbol{w}\|_{V}+L_{p}\|\boldsymbol{w}\|_{L^{2}\left(\Gamma_{3}\right)^{d}}\|\boldsymbol{u}-\boldsymbol{v}\|_{L^{2}\left(\Gamma_{3}\right)^{d}}\\ \leq\left(d\|\mathcal{E}\|_{\mathbf{Q}_{\infty}}+c_{0}^{2}L_{p}\right)\|\boldsymbol{u}-\boldsymbol{v}\|_{V}\|\boldsymbol{w}\|_{V}\quad\forall\boldsymbol{u},\boldsymbol{v},\boldsymbol{w}\in V.\end{gathered}

Then we take 𝒘=A​𝒖−A​𝒗\boldsymbol{w}=A\boldsymbol{u}-A\boldsymbol{v} in the previous inequality to find that

‖A​𝒖−A​𝒗‖V≤(d​‖ℰ‖𝐐∞+c02​Lp)​‖𝒖−𝒗‖V∀𝒖,𝒗∈V.\|A\boldsymbol{u}-A\boldsymbol{v}\|_{V}\leq\left(d\|\mathcal{E}\|_{\mathbf{Q}_{\infty}}+c_{0}^{2}L_{p}\right)\|\boldsymbol{u}-\boldsymbol{v}\|_{V}\quad\forall\boldsymbol{u},\boldsymbol{v}\in V. (4.37)

On the other hand, from (4.1) and the monotonicity of the function pp we deduce that

(A​𝒖−A​𝒗,𝒖−𝒗)V≥mε​‖𝒖−𝒗‖V2.(A\boldsymbol{u}-A\boldsymbol{v},\boldsymbol{u}-\boldsymbol{v})_{V}\geq m_{\varepsilon}\|\boldsymbol{u}-\boldsymbol{v}\|_{V}^{2}. (4.38)

Inequalities (4.37) and (4.38) imply that the operator AA satisfies assumption (2.7).
Let n∈ℕ∗n\in\mathbb{N}^{*} and let t∈[0,n]t\in[0,n]. Then, using (4.34), (4.19) and the trace inequality (2.1) we find that

‖ℛ​𝒖​(t)−ℛ​𝒗​(t)‖Q×L2​(Γ3)\displaystyle\|\mathcal{R}\boldsymbol{u}(t)-\mathcal{R}\boldsymbol{v}(t)\|_{Q\times L^{2}\left(\Gamma_{3}\right)}
≤(sn+c0⋅maxr∈[0,n]⁡‖b​(r)‖L∞​(Γ3))​∫0t‖𝒖​(s)−𝒗​(s)‖V​𝑑s\displaystyle\quad\leq\left(s_{n}+c_{0}\cdot\max_{r\in[0,n]}\|b(r)\|_{L^{\infty}\left(\Gamma_{3}\right)}\right)\int_{0}^{t}\|\boldsymbol{u}(s)-\boldsymbol{v}(s)\|_{V}ds

which shows that (2.8) holds with rn=sn+c0⋅maxr∈[0,n]⁡‖b​(r)‖L∞​(Γ3)r_{n}=s_{n}+c_{0}\cdot\max_{r\in[0,n]}\|b(r)\|_{L^{\infty}\left(\Gamma_{3}\right)}.
We now take into account (4.35) and (2.1) to deduce that

φ​((𝝈1,ξ1),𝒖2)−φ​((𝝈1,ξ1),𝒖1)+φ​((𝝈2,ξ2),𝒖1)−φ​((𝝈2,ξ2),𝒖2)=(𝝈1−𝝈2,𝜺​(𝒖2)−𝜺​(𝒖1))Q+(ξ1+−ξ2+,u2​ν+−u1​ν+)L2​(Γ3)≤(‖𝝈1−𝝈2‖Q+c0​‖ξ1−ξ2‖L2​(Γ3))​‖𝒖1−𝒖2‖V≤2​max⁡{1,c0}​‖(𝝈1,ξ1)−(𝝈2,ξ2)‖Q×L2​(Γ3)​‖𝒖1−𝒖2‖V,∀𝝈1,𝝈1∈Q,ξ1,ξ2∈L2​(Γ3),𝒖1,𝒖2∈V,\begin{gathered}\varphi\left(\left(\boldsymbol{\sigma}_{1},\xi_{1}\right),\boldsymbol{u}_{2}\right)-\varphi\left(\left(\boldsymbol{\sigma}_{1},\xi_{1}\right),\boldsymbol{u}_{1}\right)+\varphi\left(\left(\boldsymbol{\sigma}_{2},\xi_{2}\right),\boldsymbol{u}_{1}\right)-\varphi\left(\left(\boldsymbol{\sigma}_{2},\xi_{2}\right),\boldsymbol{u}_{2}\right)\\ =\left(\boldsymbol{\sigma}_{1}-\boldsymbol{\sigma}_{2},\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{2}\right)-\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{1}\right)\right)_{Q}+\left(\xi_{1}^{+}-\xi_{2}^{+},u_{2\nu}^{+}-u_{1\nu}^{+}\right)_{L^{2}\left(\Gamma_{3}\right)}\\ \leq\left(\left\|\boldsymbol{\sigma}_{1}-\boldsymbol{\sigma}_{2}\right\|_{Q}+c_{0}\left\|\xi_{1}-\xi_{2}\right\|_{L^{2}\left(\Gamma_{3}\right)}\right)\left\|\boldsymbol{u}_{1}-\boldsymbol{u}_{2}\right\|_{V}\\ \leq\sqrt{2}\max\left\{1,c_{0}\right\}\left\|\left(\boldsymbol{\sigma}_{1},\xi_{1}\right)-\left(\boldsymbol{\sigma}_{2},\xi_{2}\right)\right\|_{Q\times L^{2}\left(\Gamma_{3}\right)}\left\|\boldsymbol{u}_{1}-\boldsymbol{u}_{2}\right\|_{V},\\ \forall\boldsymbol{\sigma}_{1},\boldsymbol{\sigma}_{1}\in Q,\xi_{1},\xi_{2}\in L^{2}\left(\Gamma_{3}\right),\boldsymbol{u}_{1},\boldsymbol{u}_{2}\in V,\end{gathered}

which shows that (2.9) (b) holds with α=2​max⁡{1,c0}\alpha=\sqrt{2}\max\left\{1,c_{0}\right\}. In addition, we note that the function φ​((𝝈,ξ),⋅):V→ℝ\varphi((\boldsymbol{\sigma},\xi),\cdot):V\rightarrow\mathbb{R} is convex and lower semi-continuous for all (𝝈,ξ)∈Q×L2​(Γ3)(\boldsymbol{\sigma},\xi)\in Q\times L^{2}\left(\Gamma_{3}\right) and, therefore, (2.9) (a) holds, too.

Finally, using assumption (4.4) and definition (4.27) we deduce that 𝒇\boldsymbol{f} has the regularity expressed in (2.10). It follows now from Theorem 2.2 that there exists a unique function 𝒖∈C​(ℝ+;V)\boldsymbol{u}\in C\left(\mathbb{R}_{+};V\right) which solves the inequality (4.36). And, using notation (4.33)-(4.35), we deduce the existence of a unique function 𝒖∈C​(ℝ+;U)\boldsymbol{u}\in C\left(\mathbb{R}_{+};U\right)
which satisfies (4.30) for any t∈ℝ+t\in\mathbb{R}_{+}. Let 𝝈,𝜿\boldsymbol{\sigma},\boldsymbol{\kappa} be the functions defined by (4.28) and (4.29). Then, it follows that the triple ( 𝒖,𝝈,𝜿\boldsymbol{u},\boldsymbol{\sigma},\boldsymbol{\kappa} ) is the unique triple of functions with regularity (4.16) which satisfies (4.28)-(4.30). Theorem 4.1 is now a consequence of Lemma 4.3.

We refer in the rest of the paper to solution of Problem 𝒫V\mathcal{P}^{V} as a weak solution to the contact problem 𝒫\mathcal{P}. We conclude by Theorem 4.1 that, Problem 𝒫\mathcal{P} has a unique weak solution solution with regularity (4.16), provided that (4.1)-(4.7) hold.

5 A convergence result

We now study the dependence of the solution of Problem 𝒫V\mathcal{P}^{V} with respect to perturbations of the data. To this end, we assume in what follows that (4.1)-(4.7) hold and we denote by ( 𝒖,𝝈,𝜿\boldsymbol{u},\boldsymbol{\sigma},\boldsymbol{\kappa} ) the solution of Problem 𝒫V\mathcal{P}^{V} obtained in Theorem 4.1, For each ρ>0\rho>0 let pρ,bρ,𝒇0​ρ,𝒇2​ρ,𝒖0​ρ,𝝈0​ρp_{\rho},b_{\rho},\boldsymbol{f}_{0\rho},\boldsymbol{f}_{2\rho},\boldsymbol{u}_{0\rho},\boldsymbol{\sigma}_{0\rho} and 𝜿0​ρ\boldsymbol{\kappa}_{0\rho} represent perturbations of p,bp,b, 𝒇0,𝒇2,𝒖0,𝝈0\boldsymbol{f}_{0},\boldsymbol{f}_{2},\boldsymbol{u}_{0},\boldsymbol{\sigma}_{0} and 𝜿0\boldsymbol{\kappa}_{0}, respectively, which satisfy conditions (4.4)-(4.7). With these data, we consider the following perturbation of Problem 𝒫V\mathcal{P}^{V}.

Problem 𝒫ρV\mathcal{P}_{\rho}^{V}. Find a displacement field 𝒖ρ:ℝ+→U\boldsymbol{u}_{\rho}:\mathbb{R}_{+}\rightarrow U, a stress field 𝝈ρ:ℝ+→Q\boldsymbol{\sigma}_{\rho}:\mathbb{R}_{+}\rightarrow Q and an internal state variable 𝜿ρ:ℝ+→L2​(Ω)m\boldsymbol{\kappa}_{\rho}:\mathbb{R}_{+}\rightarrow L^{2}(\Omega)^{m} such that

𝝈ρ​(t)=∫0t𝒢​(𝝈ρ​(s),𝜺​(𝒖ρ​(s)),𝜿ρ​(s))​𝑑s+𝝈0​ρ−ℰ​𝜺​(𝒖0​ρ)+ℰ​𝜺​(𝒖ρ​(t))\displaystyle\boldsymbol{\sigma}_{\rho}(t)=\int_{0}^{t}\mathcal{G}\left(\boldsymbol{\sigma}_{\rho}(s),\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\rho}(s)\right),\boldsymbol{\kappa}_{\rho}(s)\right)ds+\boldsymbol{\sigma}_{0\rho}-\mathcal{E}\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{0\rho}\right)+\mathcal{E}\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\rho}(t)\right) (5.1)
𝜿ρ​(t)=∫0t𝑮​(𝝈ρ​(s),𝜺​(𝒖ρ​(s)),𝜿ρ​(s))​𝑑s+𝜿0​ρ\displaystyle\boldsymbol{\kappa}_{\rho}(t)=\int_{0}^{t}\boldsymbol{G}\left(\boldsymbol{\sigma}_{\rho}(s),\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\rho}(s)\right),\boldsymbol{\kappa}_{\rho}(s)\right)ds+\boldsymbol{\kappa}_{0\rho} (5.2)
(𝝈ρ​(t),𝜺​(𝒗)−𝜺​(𝒖ρ​(t)))Q+(pρ​(uρ​ν​(t)),vν−uρ​ν​(t))L2​(Γ3)\displaystyle\left(\boldsymbol{\sigma}_{\rho}(t),\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\rho}(t)\right)\right)_{Q}+\left(p_{\rho}\left(u_{\rho\nu}(t)\right),v_{\nu}-u_{\rho\nu}(t)\right)_{L^{2}\left(\Gamma_{3}\right)} (5.3)
+(∫0tbρ​(t−s)​uρ​ν+​(s)​𝑑s,vν+−uρ​ν+​(t))L2​(Γ3)\displaystyle+\left(\int_{0}^{t}b_{\rho}(t-s)u_{\rho\nu}^{+}(s)ds,v_{\nu}^{+}-u_{\rho\nu}^{+}(t)\right)_{L^{2}\left(\Gamma_{3}\right)}
≥(𝒇0​ρ​(t),𝒗−𝒖ρ​(t))L2​(Ω)d+(𝒇2​ρ​(t),𝒗−𝒖ρ​(t))L2​(Γ2)d∀𝒗∈U\displaystyle\geq\left(\boldsymbol{f}_{0\rho}(t),\boldsymbol{v}-\boldsymbol{u}_{\rho}(t)\right)_{L^{2}(\Omega)^{d}}+\left(\boldsymbol{f}_{2\rho}(t),\boldsymbol{v}-\boldsymbol{u}_{\rho}(t)\right)_{L^{2}\left(\Gamma_{2}\right)^{d}}\quad\forall\boldsymbol{v}\in U

for all t∈ℝ+t\in\mathbb{R}_{+}.
Here and below uρ​νu_{\rho\nu} represents the normal component of the function 𝒖ρ\boldsymbol{u}_{\rho}. It follows from Theorem 4.1 that, for each ρ>0\rho>0, Problem 𝒫ρV\mathcal{P}_{\rho}^{V} has a unique solution ( 𝒖ρ,𝝈ρ,𝜿ρ\boldsymbol{u}_{\rho},\boldsymbol{\sigma}_{\rho},\boldsymbol{\kappa}_{\rho} ) with the regularity 𝒖ρ∈C​(ℝ+;U),𝝈ρ∈C​(ℝ+;Q)\boldsymbol{u}_{\rho}\in C\left(\mathbb{R}_{+};U\right),\boldsymbol{\sigma}_{\rho}\in C\left(\mathbb{R}_{+};Q\right) and 𝜿ρ∈C​(ℝ+;L2​(Ω)m)\boldsymbol{\kappa}_{\rho}\in C\left(\mathbb{R}_{+};L^{2}(\Omega)^{m}\right). Consider now the following assumptions:

{ There exists ​F:ℝ+→ℝ+​and ​α∈ℝ+​such that  (a) ​|pρ​(𝒙,r)−p​(𝒙,r)|≤F​(ρ)​(|r|+α)∀r∈ℝ​, a.e. ​𝒙∈Γ3​, for each ​ρ>0​.  (b) ​F​(ρ)→0​ as ​ρ→0​. \left\{\begin{array}[]{l}\text{ There exists }F:\mathbb{R}_{+}\rightarrow\mathbb{R}_{+}\text{and }\alpha\in\mathbb{R}_{+}\text{such that }\\ \text{ (a) }\left|p_{\rho}(\boldsymbol{x},r)-p(\boldsymbol{x},r)\right|\leq F(\rho)(|r|+\alpha)\\ \quad\forall r\in\mathbb{R}\text{, a.e. }\boldsymbol{x}\in\Gamma_{3}\text{, for each }\rho>0\text{. }\\ \text{ (b) }F(\rho)\rightarrow 0\text{ as }\rho\rightarrow 0\text{. }\end{array}\right.
bρ→b in ​C​(ℝ+;L∞​(Γ3)) as ρ→0.𝒇0​ρ→𝒇0 in ​C​(ℝ+;L2​(Ω)d) as ​ρ→0.𝒇2​ρ→𝒇2 in ​C​(ℝ+;L2​(Γ2)d) as ​ρ→0.𝒖0​ρ→𝒖0 in ​V as ​ρ→0.𝝈0​ρ→𝝈0 in ​Q as ​ρ→0.𝜿0​ρ→𝜿0 in ​L2​(Ω)m as ​ρ→0.\begin{array}[]{ll}b_{\rho}\rightarrow b&\text{ in }C\left(\mathbb{R}_{+};L^{\infty}\left(\Gamma_{3}\right)\right)\quad\text{ as }\quad\rho\rightarrow 0.\\ \boldsymbol{f}_{0\rho}\rightarrow\boldsymbol{f}_{0}&\text{ in }C\left(\mathbb{R}_{+};L^{2}(\Omega)^{d}\right)\quad\text{ as }\rho\rightarrow 0.\\ \boldsymbol{f}_{2\rho}\rightarrow\boldsymbol{f}_{2}&\text{ in }C\left(\mathbb{R}_{+};L^{2}\left(\Gamma_{2}\right)^{d}\right)\quad\text{ as }\rho\rightarrow 0.\\ \boldsymbol{u}_{0\rho}\rightarrow\boldsymbol{u}_{0}&\text{ in }V\quad\text{ as }\rho\rightarrow 0.\\ \boldsymbol{\sigma}_{0\rho}\rightarrow\boldsymbol{\sigma}_{0}&\text{ in }Q\quad\text{ as }\rho\rightarrow 0.\\ \boldsymbol{\kappa}_{0\rho}\rightarrow\boldsymbol{\kappa}_{0}&\text{ in }L^{2}(\Omega)^{m}\quad\text{ as }\rho\rightarrow 0.\end{array}

We have the following convergence result.
Theorem 5.1 Assume that (5.4)-(5.10) hold. Then the solution ( 𝒖ρ,𝝈ρ,𝜿ρ\boldsymbol{u}_{\rho},\boldsymbol{\sigma}_{\rho},\boldsymbol{\kappa}_{\rho} ) of Problem 𝒫ρV\mathcal{P}_{\rho}^{V} converges to the solution ( 𝒖,𝝈,𝜿\boldsymbol{u},\boldsymbol{\sigma},\boldsymbol{\kappa} ) of Problem 𝒫V\mathcal{P}^{V}, i.e.

{𝒖ρ→𝒖 in C​(ℝ+;V)𝝈ρ→𝝈 in C​(ℝ+;Q)𝜿ρ→𝜿 in C​(ℝ+;L2​(Ω)m)\left\{\begin{array}[]{lll}\boldsymbol{u}_{\rho}\rightarrow\boldsymbol{u}&\text{ in }&C\left(\mathbb{R}_{+};V\right)\\ \boldsymbol{\sigma}_{\rho}\rightarrow\boldsymbol{\sigma}&\text{ in }&C\left(\mathbb{R}_{+};Q\right)\\ \boldsymbol{\kappa}_{\rho}\rightarrow\boldsymbol{\kappa}&\text{ in }&C\left(\mathbb{R}_{+};L^{2}(\Omega)^{m}\right)\end{array}\right.

as ρ→0\rho\rightarrow 0.
Proof. Let ρ>0\rho>0. We define the operators Pρ:V→V,ℬρ:C​(ℝ+;V)→C​(ℝ+;L2​(Γ3))P_{\rho}:V\rightarrow V,\mathcal{B}_{\rho}:C\left(\mathbb{R}_{+};V\right)\rightarrow C\left(\mathbb{R}_{+};L^{2}\left(\Gamma_{3}\right)\right) and the function 𝒇ρ:ℝ+→V\boldsymbol{f}_{\rho}:\mathbb{R}_{+}\rightarrow V by equalities

(Pρ​𝒖,𝒗)V=∫Γ3pρ​(uν)​vν​𝑑a∀𝒖,𝒗∈V\displaystyle\left(P_{\rho}\boldsymbol{u},\boldsymbol{v}\right)_{V}=\int_{\Gamma_{3}}p_{\rho}\left(u_{\nu}\right)v_{\nu}da\quad\forall\boldsymbol{u},\boldsymbol{v}\in V (5.12)
(ℬρ​𝒖​(t),ξ)L2​(Γ3)=(∫0tbρ​(t−s)​uν+​(s)​𝑑s,ξ)L2​(Γ3)\displaystyle\left(\mathcal{B}_{\rho}\boldsymbol{u}(t),\xi\right)_{L^{2}\left(\Gamma_{3}\right)}=\left(\int_{0}^{t}b_{\rho}(t-s)u_{\nu}^{+}(s)ds,\xi\right)_{L^{2}\left(\Gamma_{3}\right)} (5.13)
∀𝒖∈C​(ℝ+;V),ξ∈L2​(Γ3),t∈ℝ+\displaystyle\quad\forall\boldsymbol{u}\in C\left(\mathbb{R}_{+};V\right),\xi\in L^{2}\left(\Gamma_{3}\right),t\in\mathbb{R}_{+}
(𝒇ρ​(t),𝒗)V=∫Ω𝒇0​ρ​(t)⋅𝒗​𝑑x+∫Γ2𝒇2​ρ​(t)⋅𝒗​𝑑a∀𝒗∈V,t∈ℝ+\displaystyle\left(\boldsymbol{f}_{\rho}(t),\boldsymbol{v}\right)_{V}=\int_{\Omega}\boldsymbol{f}_{0\rho}(t)\cdot\boldsymbol{v}dx+\int_{\Gamma_{2}}\boldsymbol{f}_{2\rho}(t)\cdot\boldsymbol{v}da\quad\forall\boldsymbol{v}\in V,t\in\mathbb{R}_{+} (5.14)

Also, we use Lemma 4.2 to define the operator 𝒮ρ:C​(ℝ+;V)→C​(ℝ+;Q×L2​(Ω)m)\mathcal{S}_{\rho}:C\left(\mathbb{R}_{+};V\right)\rightarrow C\left(\mathbb{R}_{+};Q\times L^{2}(\Omega)^{m}\right) by equalities

𝒮ρ​𝒖​(t)=(𝒮1​ρ​𝒖​(t),𝒮2​ρ​𝒖​(t))\displaystyle\mathcal{S}_{\rho}\boldsymbol{u}(t)=\left(\mathcal{S}_{1\rho}\boldsymbol{u}(t),\mathcal{S}_{2\rho}\boldsymbol{u}(t)\right) (5.15)
𝒮1​ρ​𝒖​(t)=∫0t𝒢​(𝒮1​ρ​𝒖​(s)+ℰ​𝜺​(𝒖​(s)),𝜺​(𝒖​(s)),𝒮2​ρ​𝒖​(s))​𝑑s+𝝈0​ρ−ℰ​𝜺​(𝒖0​ρ)\displaystyle\mathcal{S}_{1\rho}\boldsymbol{u}(t)=\int_{0}^{t}\mathcal{G}\left(\mathcal{S}_{1\rho}\boldsymbol{u}(s)+\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\mathcal{S}_{2\rho}\boldsymbol{u}(s)\right)ds+\boldsymbol{\sigma}_{0\rho}-\mathcal{E}\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{0\rho}\right) (5.16)
𝒮2​ρ​𝒖​(t)=∫0t𝑮​(𝒮1​ρ​𝒖​(s)+ℰ​𝜺​(𝒖​(s)),𝜺​(𝒖​(s)),𝒮2​ρ​𝒖​(s))​𝑑s+𝜿0​ρ\displaystyle\mathcal{S}_{2\rho}\boldsymbol{u}(t)=\int_{0}^{t}\boldsymbol{G}\left(\mathcal{S}_{1\rho}\boldsymbol{u}(s)+\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\boldsymbol{\varepsilon}(\boldsymbol{u}(s)),\mathcal{S}_{2\rho}\boldsymbol{u}(s)\right)ds+\boldsymbol{\kappa}_{0\rho} (5.17)

for all 𝒖∈C​(ℝ+;V)\boldsymbol{u}\in C\left(\mathbb{R}_{+};V\right) and t∈ℝ+t\in\mathbb{R}_{+}. Finally, we recall Lemma 4.3 which shows that the solution ( 𝒖ρ,𝝈ρ,𝜿ρ\boldsymbol{u}_{\rho},\boldsymbol{\sigma}_{\rho},\boldsymbol{\kappa}_{\rho} ) satisfies

𝝈ρ​(t)=ℰ​𝜺​(𝒖ρ​(t))+𝒮1​ρ​(𝒖ρ​(t))\displaystyle\boldsymbol{\sigma}_{\rho}(t)=\mathcal{E}\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\rho}(t)\right)+\mathcal{S}_{1\rho}\left(\boldsymbol{u}_{\rho}(t)\right) (5.18)
𝜿ρ​(t)=𝒮2​ρ​𝒖ρ​(t)\displaystyle\boldsymbol{\kappa}_{\rho}(t)=\mathcal{S}_{2\rho}\boldsymbol{u}_{\rho}(t) (5.19)
(ℰ​𝜺​(𝒖ρ​(t)),𝜺​(𝒗)−𝜺​(𝒖ρ​(t)))Q+(𝒮1​ρ​𝒖ρ​(t),𝜺​(𝒗)−𝜺​(𝒖ρ​(t)))Q+(Pρ​𝒖ρ​(t),𝒗−𝒖ρ​(t))V+(ℬρ​𝒖ρ​(t),vν+−uρ​ν+​(t))L2​(Γ3)≥(𝒇​(t),𝒗−𝒖ρ​(t))V\displaystyle\begin{array}[]{l}\left(\mathcal{E}\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\rho}(t)\right),\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\rho}(t)\right)\right)_{Q}+\left(\mathcal{S}_{1\rho}\boldsymbol{u}_{\rho}(t),\boldsymbol{\varepsilon}(\boldsymbol{v})-\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\rho}(t)\right)\right)_{Q}\\ \quad+\left(P_{\rho}\boldsymbol{u}_{\rho}(t),\boldsymbol{v}-\boldsymbol{u}_{\rho}(t)\right)_{V}+\left(\mathcal{B}_{\rho}\boldsymbol{u}_{\rho}(t),v_{\nu}^{+}-u_{\rho\nu}^{+}(t)\right)_{L^{2}\left(\Gamma_{3}\right)}\\ \quad\geq\left(\boldsymbol{f}(t),\boldsymbol{v}-\boldsymbol{u}_{\rho}(t)\right)_{V}\end{array} (5.20)

for all t∈ℝ+t\in\mathbb{R}_{+}.
Let ρ>0,n∈ℕ∗\rho>0,n\in\mathbb{N}^{*} and let t∈[0,n]t\in[0,n]. We take 𝒗=𝒖​(t)\boldsymbol{v}=\boldsymbol{u}(t) in (5.20) and 𝒗=𝒖ρ​(t)\boldsymbol{v}=\boldsymbol{u}_{\rho}(t) in (4.30) and add the resulting inequalities to obtain

(ℰ​ε​(𝒖​(t))−ℰ​ε​(𝒖ρ​(t)),𝜺​(𝒖​(t))−𝜺​(𝒖ρ​(t)))Q\displaystyle\left(\mathcal{E}\varepsilon(\boldsymbol{u}(t))-\mathcal{E}\varepsilon\left(\boldsymbol{u}_{\rho}(t)\right),\boldsymbol{\varepsilon}(\boldsymbol{u}(t))-\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\rho}(t)\right)\right)_{Q} (5.21)
≤(𝒮1​ρ​𝒖ρ​(t)−𝒮1​𝒖​(t),𝜺​(𝒖​(t))−𝜺​(𝒖ρ​(t)))Q\displaystyle\leq\left(\mathcal{S}_{1\rho}\boldsymbol{u}_{\rho}(t)-\mathcal{S}_{1}\boldsymbol{u}(t),\boldsymbol{\varepsilon}(\boldsymbol{u}(t))-\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\rho}(t)\right)\right)_{Q}
+(Pρ​𝒖ρ​(t)−P​𝒖​(t),𝒖​(t)−𝒖ρ​(t))V\displaystyle\quad+\left(P_{\rho}\boldsymbol{u}_{\rho}(t)-P\boldsymbol{u}(t),\boldsymbol{u}(t)-\boldsymbol{u}_{\rho}(t)\right)_{V}
+(ℬρ​𝒖ρ​(t)−ℬ​𝒖​(t),uν+​(t)−uρ​ν+​(t))L2​(Γ3)\displaystyle\quad+\left(\mathcal{B}_{\rho}\boldsymbol{u}_{\rho}(t)-\mathcal{B}\boldsymbol{u}(t),u_{\nu}^{+}(t)-u_{\rho\nu}^{+}(t)\right)_{L^{2}\left(\Gamma_{3}\right)}
+(𝒇ρ​(t)−𝒇​(t),𝒖​(t)−𝒖ρ​(t))V\displaystyle\quad+\left(\boldsymbol{f}_{\rho}(t)-\boldsymbol{f}(t),\boldsymbol{u}(t)-\boldsymbol{u}_{\rho}(t)\right)_{V}

We now estimate each term in the previous inequality. First, we use assumption (4.1) to deduce that

mℰ​‖𝒖ρ​(t)−𝒖​(t)‖V2≤(ℰ​𝜺​(𝒖​(t))−ℰ​𝜺​(𝒖ρ​(t)),𝜺​(𝒖​(t))−𝜺​(𝒖ρ​(t)))Q.m_{\mathcal{E}}\left\|\boldsymbol{u}_{\rho}(t)-\boldsymbol{u}(t)\right\|_{V}^{2}\leq\left(\mathcal{E}\boldsymbol{\varepsilon}(\boldsymbol{u}(t))-\mathcal{E}\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\rho}(t)\right),\boldsymbol{\varepsilon}(\boldsymbol{u}(t))-\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\rho}(t)\right)\right)_{Q}. (5.22)

Next, using the Cauchy-Schwarz inequality we deduce that

(𝒮1​ρ​𝒖ρ​(t)−𝒮1​𝒖​(t),𝜺​(𝒖​(t))−𝜺​(𝒖ρ​(t)))Q\displaystyle\left(\mathcal{S}_{1\rho}\boldsymbol{u}_{\rho}(t)-\mathcal{S}_{1}\boldsymbol{u}(t),\boldsymbol{\varepsilon}(\boldsymbol{u}(t))-\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\rho}(t)\right)\right)_{Q} (5.23)
≤‖𝒮ρ​𝒖ρ​(t)−𝒮​𝒖​(t)‖Q×L2​(Ω)m​‖𝒖​(t)−𝒖ρ​(t)‖V\displaystyle\quad\leq\left\|\mathcal{S}_{\rho}\boldsymbol{u}_{\rho}(t)-\mathcal{S}\boldsymbol{u}(t)\right\|_{Q\times L^{2}(\Omega)^{m}}\left\|\boldsymbol{u}(t)-\boldsymbol{u}_{\rho}(t)\right\|_{V}

Moreover, by arguments similar to those used in the proof of (4.24) we deduce that

‖𝒮ρ​𝒖ρ​(t)−𝒮​𝒖​(t)‖Q×L2​(Ω)m≤(𝒦​∫0t‖𝒖ρ​(s)−𝒖​(s)‖V​𝑑s+τ0​ρ)​en​𝒦\left\|\mathcal{S}_{\rho}\boldsymbol{u}_{\rho}(t)-\mathcal{S}\boldsymbol{u}(t)\right\|_{Q\times L^{2}(\Omega)^{m}}\leq\left(\mathcal{K}\int_{0}^{t}\left\|\boldsymbol{u}_{\rho}(s)-\boldsymbol{u}(s)\right\|_{V}ds+\tau_{0\rho}\right)e^{n\mathcal{K}} (5.24)

where 𝒦\mathcal{K} is given by (4.23) and

τ0​ρ=‖𝝈0​ρ−𝝈0‖Q+d​‖ℰ‖𝐐∞​‖𝒖0​ρ−𝒖0‖V+‖𝜿0​ρ−𝜿0‖L2​(Ω)m\tau_{0\rho}=\left\|\boldsymbol{\sigma}_{0\rho}-\boldsymbol{\sigma}_{0}\right\|_{Q}+d\|\mathcal{E}\|_{\mathbf{Q}^{\infty}}\left\|\boldsymbol{u}_{0\rho}-\boldsymbol{u}_{0}\right\|_{V}+\left\|\boldsymbol{\kappa}_{0\rho}-\boldsymbol{\kappa}_{0}\right\|_{L^{2}(\Omega)^{m}} (5.25)

We combine now (5.23) and (5.24) and use the notation sn=𝒦​en​𝒦s_{n}=\mathcal{K}e^{n\mathcal{K}} introduced in the proof of Lemma 4.2 to deduce that

(𝒮1​ρ​𝒖ρ​(t)−𝒮1​𝒖​(t),𝜺​(𝒖​(t))−𝜺​(𝒖ρ​(t)))Q\displaystyle\left(\mathcal{S}_{1\rho}\boldsymbol{u}_{\rho}(t)-\mathcal{S}_{1}\boldsymbol{u}(t),\boldsymbol{\varepsilon}(\boldsymbol{u}(t))-\boldsymbol{\varepsilon}\left(\boldsymbol{u}_{\rho}(t)\right)\right)_{Q} (5.26)
≤(sn​∫0t‖𝒖ρ​(s)−𝒖​(s)‖V​𝑑s+τ0​ρ​en​𝒦)​‖𝒖ρ​(t)−𝒖​(t)‖V\displaystyle\quad\leq\left(s_{n}\int_{0}^{t}\left\|\boldsymbol{u}_{\rho}(s)-\boldsymbol{u}(s)\right\|_{V}ds+\tau_{0\rho}e^{n\mathcal{K}}\right)\left\|\boldsymbol{u}_{\rho}(t)-\boldsymbol{u}(t)\right\|_{V}

To proceed, we use the definitions (5.12) and (4.25), the monotonicity of the function pρp_{\rho} and assumption (5.4) to see that

(Pρ​𝒖ρ​(t)−P​𝒖​(t),𝒖​(t)−𝒖ρ​(t))V\displaystyle\left(P_{\rho}\boldsymbol{u}_{\rho}(t)-P\boldsymbol{u}(t),\boldsymbol{u}(t)-\boldsymbol{u}_{\rho}(t)\right)_{V}
=∫Γ3(pρ​(uρ​ν​(t))−p​(uν​(t)))​(uν​(t)−uρ​ν​(t))​𝑑a\displaystyle\quad=\int_{\Gamma_{3}}\left(p_{\rho}\left(u_{\rho\nu}(t)\right)-p\left(u_{\nu}(t)\right)\right)\left(u_{\nu}(t)-u_{\rho\nu}(t)\right)da
≤∫Γ3(pρ​(uν​(t))−p​(uν​(t)))​(uν​(t)−uρ​ν​(t))​𝑑a\displaystyle\quad\leq\int_{\Gamma_{3}}\left(p_{\rho}\left(u_{\nu}(t)\right)-p\left(u_{\nu}(t)\right)\right)\left(u_{\nu}(t)-u_{\rho\nu}(t)\right)da
≤∫Γ3|pρ​(uν​(t))−p​(uν​(t))|​|uν​(t)−uρ​ν​(t)|​𝑑a\displaystyle\quad\leq\int_{\Gamma_{3}}\left|p_{\rho}\left(u_{\nu}(t)\right)-p\left(u_{\nu}(t)\right)\right|\left|u_{\nu}(t)-u_{\rho\nu}(t)\right|da
≤∫Γ3F​(ρ)​(|uν​(t)|+α)​|uν​(t)−uρ​ν​(t)|​𝑑a\displaystyle\quad\leq\int_{\Gamma_{3}}F(\rho)\left(\left|u_{\nu}(t)\right|+\alpha\right)\left|u_{\nu}(t)-u_{\rho\nu}(t)\right|da

Therefore, using the trace inequality (2.1), after some elementary calculus we find that

(Pρ​𝒖ρ​(t)−P​𝒖​(t),𝒖​(t)−𝒖ρ​(t))V\displaystyle\left(P_{\rho}\boldsymbol{u}_{\rho}(t)-P\boldsymbol{u}(t),\boldsymbol{u}(t)-\boldsymbol{u}_{\rho}(t)\right)_{V} (5.27)
≤F(ρ)(c02∥𝒖(t)∥V+c0αmeas(Γ3)12)∥𝒖ρ(t)−𝒖(t)∥V\displaystyle\quad\leq F(\rho)\left(c_{0}^{2}\|\boldsymbol{u}(t)\|_{V}+c_{0}\alpha\operatorname{meas}\left(\Gamma_{3}\right)^{\frac{1}{2}}\right)\left\|\boldsymbol{u}_{\rho}(t)-\boldsymbol{u}(t)\right\|_{V}

Next, using definitions (5.13), (4.26) and condition (4.6) we have

(ℬρ​𝒖ρ​(t)−ℬ​𝒖​(t),uν+​(t)−uρ​ν+​(t))L2​(Γ3)\displaystyle\left(\mathcal{B}_{\rho}\boldsymbol{u}_{\rho}(t)-\mathcal{B}\boldsymbol{u}(t),u_{\nu}^{+}(t)-u_{\rho\nu}^{+}(t)\right)_{L^{2}\left(\Gamma_{3}\right)}
=(∫0t(bρ​(t−s)​uρ​ν+​(s)−b​(t−s)​uν+​(s))​𝑑s,uν+​(t)−uρ​ν+​(t))L2​(Γ3)\displaystyle\quad=\left(\int_{0}^{t}\left(b_{\rho}(t-s)u_{\rho\nu}^{+}(s)-b(t-s)u_{\nu}^{+}(s)\right)ds,u_{\nu}^{+}(t)-u_{\rho\nu}^{+}(t)\right)_{L^{2}\left(\Gamma_{3}\right)}
≤(∫0t∥bρ(t−s)(uρ​ν+(s)−uν+(s))∥L2​(Γ3)ds\displaystyle\quad\leq\left(\int_{0}^{t}\left\|b_{\rho}(t-s)\left(u_{\rho\nu}^{+}(s)-u_{\nu}^{+}(s)\right)\right\|_{L^{2}\left(\Gamma_{3}\right)}ds\right.
+∫0t∥bρ(t−s)uν+(s)−b(t−s)uν+(s)∥L2​(Γ3)ds)∥𝒖ρ(t)−𝒖(t)∥L2​(Γ3)d\displaystyle\left.\quad+\int_{0}^{t}\left\|b_{\rho}(t-s)u_{\nu}^{+}(s)-b(t-s)u_{\nu}^{+}(s)\right\|_{L^{2}\left(\Gamma_{3}\right)}ds\right)\left\|\boldsymbol{u}_{\rho}(t)-\boldsymbol{u}(t)\right\|_{L^{2}\left(\Gamma_{3}\right)^{d}}

Therefore,

(ℬρ​𝒖ρ​(t)−ℬ​𝒖​(t),uν+​(t)−uρ​ν+​(t))L2​(Γ3)\displaystyle\left(\mathcal{B}_{\rho}\boldsymbol{u}_{\rho}(t)-\mathcal{B}\boldsymbol{u}(t),u_{\nu}^{+}(t)-u_{\rho\nu}^{+}(t)\right)_{L^{2}\left(\Gamma_{3}\right)} (5.28)
≤(θρ​n​∫0t‖𝒖ρ​(s)−𝒖​(s)‖V​𝑑s+ωρ​n​∫0t‖𝒖​(s)‖V​𝑑s)​‖𝒖ρ​(t)−𝒖​(t)‖V\displaystyle\quad\leq\left(\theta_{\rho n}\int_{0}^{t}\left\|\boldsymbol{u}_{\rho}(s)-\boldsymbol{u}(s)\right\|_{V}ds+\omega_{\rho n}\int_{0}^{t}\|\boldsymbol{u}(s)\|_{V}ds\right)\left\|\boldsymbol{u}_{\rho}(t)-\boldsymbol{u}(t)\right\|_{V}

where

θρ​n=c02​maxr∈[0,n]⁡‖bρ​(r)‖L∞​(Γ3),\displaystyle\theta_{\rho n}=c_{0}^{2}\max_{r\in[0,n]}\left\|b_{\rho}(r)\right\|_{L^{\infty}\left(\Gamma_{3}\right)}, (5.29)
ωρ​n=c02​maxr∈[0,n]⁡‖bρ​(r)−b​(r)‖L∞​(Γ3).\displaystyle\omega_{\rho n}=c_{0}^{2}\max_{r\in[0,n]}\left\|b_{\rho}(r)-b(r)\right\|_{L^{\infty}\left(\Gamma_{3}\right)}. (5.30)

Finally, it is easy to see that

(𝒇ρ​(t)−𝒇​(t),𝒖​(t)−𝒖ρ​(t))V≤δρ​n​‖𝒖ρ​(t)−𝒖​(t)‖V\left(\boldsymbol{f}_{\rho}(t)-\boldsymbol{f}(t),\boldsymbol{u}(t)-\boldsymbol{u}_{\rho}(t)\right)_{V}\leq\delta_{\rho n}\left\|\boldsymbol{u}_{\rho}(t)-\boldsymbol{u}(t)\right\|_{V} (5.31)

where

δρ​n=maxr∈[0,n]⁡‖𝒇ρ​(r)−𝒇​(r)‖V\delta_{\rho n}=\max_{r\in[0,n]}\left\|\boldsymbol{f}_{\rho}(r)-\boldsymbol{f}(r)\right\|_{V} (5.32)

We now combine (5.21), (5.22), (5.26), (5.27), (5.28) and (5.31) to deduce that

∥𝒖ρ(t)\displaystyle\|\boldsymbol{u}_{\rho}(t) −𝒖(t)∥≤Vsnmℰ∫0t∥𝒖ρ(s)−𝒖(s)∥Vds+τ0​ρ​en​𝒦mℰ\displaystyle-\boldsymbol{u}(t)\left\|{}_{V}\leq\frac{s_{n}}{m_{\mathcal{E}}}\int_{0}^{t}\right\|\boldsymbol{u}_{\rho}(s)-\boldsymbol{u}(s)\|_{V}ds+\frac{\tau_{0\rho}e^{n\mathcal{K}}}{m_{\mathcal{E}}} (5.33)
+\displaystyle+ F​(ρ)mℰ(c02∥𝒖(t)∥V+c0αmeas(Γ3)12)\displaystyle\frac{F(\rho)}{m_{\mathcal{E}}}\left(c_{0}^{2}\|\boldsymbol{u}(t)\|_{V}+c_{0}\alpha\operatorname{meas}\left(\Gamma_{3}\right)^{\frac{1}{2}}\right)
+θρ​nmℰ​∫0t‖𝒖ρ​(s)−𝒖​(s)‖V​𝑑s+ωρ​nmℰ​∫0t‖𝒖​(s)‖V​𝑑s+δρ​nmℰ\displaystyle+\frac{\theta_{\rho n}}{m_{\mathcal{E}}}\int_{0}^{t}\left\|\boldsymbol{u}_{\rho}(s)-\boldsymbol{u}(s)\right\|_{V}ds+\frac{\omega_{\rho n}}{m_{\mathcal{E}}}\int_{0}^{t}\|\boldsymbol{u}(s)\|_{V}ds+\frac{\delta_{\rho n}}{m_{\mathcal{E}}}

Let

ξn,u=max{en​𝒦mℰ,1mℰ(c02maxt∈[0,n]∥𝒖(t)∥V+c0αmeas(Γ3)12)1mℰ∫0n∥𝒖(s)∥Vds,1mℰ}\begin{gathered}\xi_{n,u}=\max\left\{\frac{e^{n\mathcal{K}}}{m_{\mathcal{E}}},\frac{1}{m_{\mathcal{E}}}\left(c_{0}^{2}\max_{t\in[0,n]}\|\boldsymbol{u}(t)\|_{V}+c_{0}\alpha\operatorname{meas}\left(\Gamma_{3}\right)^{\frac{1}{2}}\right)\right.\\ \left.\frac{1}{m_{\mathcal{E}}}\int_{0}^{n}\|\boldsymbol{u}(s)\|_{V}ds,\frac{1}{m_{\mathcal{E}}}\right\}\end{gathered}

and note that ξn,u\xi_{n,u} depends on n,𝒖,d,ℰ,𝒢,G,c0,αn,\boldsymbol{u},d,\mathcal{E},\mathcal{G},G,c_{0},\alpha and Γ3\Gamma_{3} but does not depends neither on ρ\rho nor on tt. Then, (5.33) yields

∥𝒖ρ(t)−\displaystyle\|\boldsymbol{u}_{\rho}(t)- 𝒖​(t)∥V≤(F​(ρ)+ωρ​n+δρ​n+τ0​ρ)​ξn,u\displaystyle\boldsymbol{u}(t)\|_{V}\leq\left(F(\rho)+\omega_{\rho n}+\delta_{\rho n}+\tau_{0\rho}\right)\xi_{n,u} (5.34)
+θρ​n+snmℰ​∫0t‖𝒖ρ​(s)−𝒖​(s)‖V​𝑑s\displaystyle+\frac{\theta_{\rho n}+s_{n}}{m_{\mathcal{E}}}\int_{0}^{t}\left\|\boldsymbol{u}_{\rho}(s)-\boldsymbol{u}(s)\right\|_{V}ds

Next, we use assumption (5.5) and equivalence (2.4) to see that the sequence (θρ​n)ρ\left(\theta_{\rho n}\right)_{\rho} defined by (5.29) is bounded. Therefore, there exists ζn>0\zeta_{n}>0 which depends on nn and is independent of ρ\rho such that

0≤θρ​n+snmℰ≤ζn for all ρ>00\leq\frac{\theta_{\rho n}+s_{n}}{m_{\mathcal{E}}}\leq\zeta_{n}\quad\text{ for all }\quad\rho>0

and, using this inequality in (5.34) we obtain that

∥𝒖ρ(t)−\displaystyle\|\boldsymbol{u}_{\rho}(t)- 𝒖​(t)∥V≤(F​(ρ)+ωρ​n+δρ​n+τ0​ρ)​ξn,u\displaystyle\boldsymbol{u}(t)\|_{V}\leq\left(F(\rho)+\omega_{\rho n}+\delta_{\rho n}+\tau_{0\rho}\right)\xi_{n,u} (5.35)
+ζn​∫0t‖𝒖ρ​(s)−𝒖​(s)‖V​𝑑s\displaystyle+\zeta_{n}\int_{0}^{t}\left\|\boldsymbol{u}_{\rho}(s)-\boldsymbol{u}(s)\right\|_{V}ds

Then, we use the Gronwall inequality to see that

‖𝒖ρ​(t)−𝒖​(t)‖V≤(F​(ρ)+ωρ​n+δρ​n+τ0​ρ)​ξn,u​et​ζn\left\|\boldsymbol{u}_{\rho}(t)-\boldsymbol{u}(t)\right\|_{V}\leq\left(F(\rho)+\omega_{\rho n}+\delta_{\rho n}+\tau_{0\rho}\right)\xi_{n,u}e^{t\zeta_{n}}

and, passing to the upper bound as t∈[0,n]t\in[0,n] we find that

maxt∈[0,n]⁡‖𝒖ρ​(t)−𝒖​(t)‖V≤(F​(ρ)+ωρ​n+δρ​n+τ0​ρ)​ξn,u​en​ζn\max_{t\in[0,n]}\left\|\boldsymbol{u}_{\rho}(t)-\boldsymbol{u}(t)\right\|_{V}\leq\left(F(\rho)+\omega_{\rho n}+\delta_{\rho n}+\tau_{0\rho}\right)\xi_{n,u}e^{n\zeta_{n}} (5.36)

Note that (5.5), (2.4) and (5.30) imply that

ωρ​n→0 as ρ→0\omega_{\rho n}\rightarrow 0\quad\text{ as }\quad\rho\rightarrow 0 (5.37)

Moreover, (5.6), (5.7), (2.4) and (5.32) yield

δρ​n→0 as ρ→0\delta_{\rho n}\rightarrow 0\quad\text{ as }\quad\rho\rightarrow 0 (5.38)

and, finally, (5.8)-(5.10) and (5.25) show that

τ0​ρ→0 as ρ→0\tau_{0\rho}\rightarrow 0\quad\text{ as }\quad\rho\rightarrow 0 (5.39)

We use now the convergences (5.4) (b), (5.37)-(5.39) and inequality (5.36) to obtain that

maxt∈[0,n]⁡‖𝒖ρ​(t)−𝒖​(t)‖V→0 as ​ρ→0\max_{t\in[0,n]}\left\|\boldsymbol{u}_{\rho}(t)-\boldsymbol{u}(t)\right\|_{V}\rightarrow 0\quad\text{ as }\rho\rightarrow 0 (5.40)

On the other hand using equalities (5.18), (5.19) and (4.28), (4.29) we find that

‖𝝈ρ​(t)−𝝈​(t)‖Q+‖𝜿ρ​(t)−𝜿​(t)‖L2​(Ω)m\displaystyle\left\|\boldsymbol{\sigma}_{\rho}(t)-\boldsymbol{\sigma}(t)\right\|_{Q}+\left\|\boldsymbol{\kappa}_{\rho}(t)-\boldsymbol{\kappa}(t)\right\|_{L^{2}(\Omega)^{m}} (5.41)
≤d​‖ℰ‖𝐐∞​‖𝒖ρ​(t)−𝒖​(t)‖V+2​‖𝒮ρ​𝒖ρ​(t)−𝒮​𝒖​(t)‖Q×L2​(Ω)m\displaystyle\quad\leq d\|\mathcal{E}\|_{\mathbf{Q}_{\infty}}\left\|\boldsymbol{u}_{\rho}(t)-\boldsymbol{u}(t)\right\|_{V}+\sqrt{2}\left\|\mathcal{S}_{\rho}\boldsymbol{u}_{\rho}(t)-\mathcal{S}\boldsymbol{u}(t)\right\|_{Q\times L^{2}(\Omega)^{m}}

We write

‖𝒮ρ​𝒖ρ​(t)−𝒮​𝒖​(t)‖Q×L2​(Ω)m\displaystyle\left\|\mathcal{S}_{\rho}\boldsymbol{u}_{\rho}(t)-\mathcal{S}\boldsymbol{u}(t)\right\|_{Q\times L^{2}(\Omega)^{m}}
≤‖𝒮ρ​𝒖ρ​(t)−𝒮ρ​𝒖​(t)‖Q×L2​(Ω)m+‖𝒮ρ​𝒖​(t)−𝒮​𝒖​(t)‖Q×L2​(Ω)m\displaystyle\quad\leq\left\|\mathcal{S}_{\rho}\boldsymbol{u}_{\rho}(t)-\mathcal{S}_{\rho}\boldsymbol{u}(t)\right\|_{Q\times L^{2}(\Omega)^{m}}+\left\|\mathcal{S}_{\rho}\boldsymbol{u}(t)-\mathcal{S}\boldsymbol{u}(t)\right\|_{Q\times L^{2}(\Omega)^{m}}

then we use inequalities (4.19) and (5.24) to see that

‖𝒮ρ​𝒖ρ​(t)−𝒮​𝒖​(t)‖Q×L2​(Ω)m≤sn​∫0t‖𝒖ρ​(s)−𝒖​(s)‖V​𝑑s\displaystyle\left\|\mathcal{S}_{\rho}\boldsymbol{u}_{\rho}(t)-\mathcal{S}\boldsymbol{u}(t)\right\|_{Q\times L^{2}(\Omega)^{m}}\leq s_{n}\int_{0}^{t}\left\|\boldsymbol{u}_{\rho}(s)-\boldsymbol{u}(s)\right\|_{V}ds
+(𝒦​∫0t‖𝒖ρ​(s)−𝒖​(s)‖V​𝑑s+τ0​ρ)​en​𝒦\displaystyle\quad+\left(\mathcal{K}\int_{0}^{t}\left\|\boldsymbol{u}_{\rho}(s)-\boldsymbol{u}(s)\right\|_{V}ds+\tau_{0\rho}\right)e^{n\mathcal{K}}

This inequality combined with convergences (5.39) and (5.40) implies that

maxt∈[0,n]⁡‖𝒮ρ​𝒖ρ​(t)−𝒮​𝒖​(t)‖Q×L2​(Ω)m→0 as ​ρ→0\max_{t\in[0,n]}\left\|\mathcal{S}_{\rho}\boldsymbol{u}_{\rho}(t)-\mathcal{S}\boldsymbol{u}(t)\right\|_{Q\times L^{2}(\Omega)^{m}}\rightarrow 0\quad\text{ as }\rho\rightarrow 0 (5.42)

Therefore, using equality (5.41) and convergences (5.40), (5.42) we deduce that

maxt∈[0,n]⁡‖𝝈ρ​(t)−𝝈​(t)‖Q→0 as ​ρ→0\displaystyle\max_{t\in[0,n]}\left\|\boldsymbol{\sigma}_{\rho}(t)-\boldsymbol{\sigma}(t)\right\|_{Q}\rightarrow 0\quad\text{ as }\rho\rightarrow 0 (5.43)
maxt∈[0,n]⁡‖𝜿ρ​(t)−𝜿​(t)‖L2​(Ω)m→0 as ​ρ→0\displaystyle\max_{t\in[0,n]}\left\|\boldsymbol{\kappa}_{\rho}(t)-\boldsymbol{\kappa}(t)\right\|_{L^{2}(\Omega)^{m}}\rightarrow 0\quad\text{ as }\rho\rightarrow 0 (5.44)

The convergence (5.11) is now a direct consequence of the convergences (5.40), (5.43) and (5.44).

In addition to the mathematical interest in the convergence result (5.11) it is of importance from mechanical point of view, since it states that the weak solution of the problem (3.1)-(3.8) depends continuously on the normal compliance function, the surface memory function, the densities of body forces and surface tractions and the initial data, as well.

Acknowledgement

The work of the first two authors was supported within the Sectorial Operational Programme for Human Resources Development 2007-2013, co-financed by the European Social Fund, under the projects POSDRU/88/1.5/S/60185 and POSDRU/107/1.5/ S/76841, respectively, entitled Modern Doctoral Studies: Internationalization and Interdisciplinarity, at University Babeş-Bolyai, Cluj-Napoca, Romania.

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