Asupra unor ecuaţii funcţionale

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T. Popoviciu
Institutul de Calcul

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T. Popoviciu, Asupra unor ecuaţii funcţionale, Studii și cercetări științifice (Cluj), Seria I, tom. VI, nr. 34, pag. 37-49 (1955).

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Studii şi cercetări matematice

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Academia Republicii S.R.

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Asupra unor ecuatii functionale

n+1n+1

f0​(x),F1​(x),…,fn​(x),f_{0}\left(x\right),F_{1}\left(x\right),\ldots,f_{n}\left(x\right),

EE.

EE se pot gasi n+1n+1 ci,i=0,1,…,c_{i},i=0,1,\ldots, avem ∑i=0nci​fi​(x)=0\sum_{i=0}^{n}c_{i}f_{i}\left(x\right)=0, oricare ar fi x∈Ex\in E.

EE n+1n+1

V​(f0,f1,…,fnx1,x2,…,xn+1)=‖fj−1​(xj)‖i,j=1,2,…,n+1.V\binom{f_{0},f_{1},\ldots,f_{n}}{x_{1},x_{2},\ldots,x_{n+1}}=\left\|f_{j-1}\left(x_{j}\right)\right\|_{i,j=1,2,\ldots,n+1}.

pe punctele x∈E,i=1,2,…,n+1x\in E,i=1,2,\ldots,n+1 ii jj

V​(1,x,x2,…,xnx1,x2,…,xn+1)=V​(x1,x2,…,xn+1)V\binom{1,x,x^{2},\ldots,x^{n}}{x_{1},x_{2},\ldots,x_{n+1}}=V\left(x_{1},x_{2},\ldots,x_{n+1}\right)

x1,x2,…,xn+1x_{1},x_{2},\ldots,x_{n+1},

[x1,x2,…,xn+1;f]=V​(1,x,…,xn−1,fx1,x2,…,xn+1)V​(x1,x2,…,xn+1)\left[x_{1},x_{2},\ldots,x_{n+1};f\right]=\frac{V\binom{1,x,\ldots,x^{n-1},f}{x_{1},x_{2},\ldots,x_{n+1}}}{V\left(x_{1},x_{2},\ldots,x_{n+1}\right)}

f​(x)f\left(x\right) x1,x2,…,xn+1x_{1},x_{2},\ldots,x_{n+1}.

EE

V​(f0,f1,…,fnx1,x2,…,xn+1)=0V\binom{f_{0},f_{1},\ldots,f_{n}}{x_{1},x_{2},\ldots,x_{n+1}}=0

xi∈E,i=1,2,…,n+1x_{i}\in E,i=1,2,\ldots,n+1.

Pentru n=0n=0 adevarata pentru nn si pentru n+1n+1

fi​(x),i=0,1,…,n−1f_{i}\left(x\right),i=0,1,\ldots,n-1

exista nn puncte xi∈E,i=1,2,…,nx_{i}\in E,i=1,2,\ldots,n,

V​(f0,f1,…,fn−1x1,x2,…,xn)≠0V\binom{f_{0},f_{1},\ldots,f_{n-1}}{x_{1},x_{2},\ldots,x_{n}}\neq 0

Insa

V​(f0,f1,…,fnx1,x2,…,xn,x)=0V\binom{f_{0},f_{1},\ldots,f^{n}}{x_{1},x_{2},\ldots,x_{n},x}=0

oricare ar fi x∈Ex\in E.

2. EE EE. n+1n+1 puncte xi,i=1,2,…,n+1x_{i},i=1,2,\ldots,n+1 EE

V​(f0,f1,…,fnx1,x2,…,xn+1)≠0.V\binom{f_{0},f_{1},\ldots,f_{n}}{x_{1},x_{2},\ldots,x_{n+1}}\neq 0.

punctele distincte x1,x2,…,xn+1x_{1},x_{2},\ldots,x_{n+1} EE. pe multimea EE.

orice sistem de n+1n+1 xi,i=1,2,…,n+1x_{i},i=1,2,\ldots,n+1, n+1n+1 yi,i=1,2,…,n+1y_{i},i=1,2,\ldots,n+1

yy, xi,i=1,2,…,n+1x_{i},i=1,2,\ldots,n+1.

3. EE [a,b]\left[a,b\right].

cat punctele x1,x2,…,xn+1x_{1},x_{2},\ldots,x_{n+1} in ordinea x1<x2<xn+1x_{1}<x_{2}<x_{n+1} gasi punctele xi′,xi′′,i=1,2,…,n+1x_{i}^{\prime},x_{i}^{\prime\prime},i=1,2,\ldots,n+1 EE

x1′<x2′<…<xn+1′,x1′′<x2′′<…<xn+1′′x_{1}^{\prime}<x_{2}^{\prime}<\ldots<x_{n+1}^{\prime},\ x_{1}^{\prime\prime}<x_{2}^{\prime\prime}<\ldots<x_{n+1}^{\prime\prime}

si

V&ZeroWidthSpace;(f0,f1,…,fnx1′,x2′,…,xn+1′)>0,V&ZeroWidthSpace;(f0,f1,…,fnx1′′,x2′′,…,xn+1′′)≤0.V\binom{f_{0},f_{1},\ldots,f_{n}}{x_{1}^{\prime},x_{2}^{\prime},\ldots,x_{n+1}^{\prime}}>0,\ V\binom{f_{0},f_{1},\ldots,f_{n}}{x_{1}^{\prime\prime},x_{2}^{\prime\prime},\ldots,x_{n+1}^{\prime\prime}}\leq 0.

xi=λ&ZeroWidthSpace;xi′′+(1−λ)&ZeroWidthSpace;xi′,i=1,2,…,n+1x_{i}=\lambda x_{i}^{\prime\prime}+\left(1-\lambda\right)x_{i}^{\prime},i=1,2,\ldots,n+1, λ\lambda pentru λ∈[0,1]\lambda\in\left[0,1\right], λ=0\lambda=0,

λ=1\lambda=1. Exista deci un λ,0<λ<1\lambda,0<\lambda<1 astfel de λ\lambda xix_{i}

△h(x;f0,f1,…,fn)=V&ZeroWidthSpace;(f0,f1,…,fnx,x+h,x+2&ZeroWidthSpace;h,…,x+n&ZeroWidthSpace;h)\bigtriangleup_{h}\left(x;f_{0},f_{1},\ldots,f_{n}\right)=V\binom{f_{0},f_{1},\ldots,f_{n}}{x,x+h,x+2h,\ldots,x+nh}

xix_{i} pentru orice x,x+n&ZeroWidthSpace;h∈[a,b]x,x+nh\in\left[a,b\right].

pentru functiile (n−2)\left(n-2\right)

f0&ZeroWidthSpace;(x)\displaystyle f_{0}\left(x\right) =(1+x)&ZeroWidthSpace;(2+x),f1&ZeroWidthSpace;(x)=1+x,f2,−x&ZeroWidthSpace;(1−x),x∈[−2−1]\displaystyle=\left(1+x\right)\left(2+x\right),f_{1}\left(x\right)=1+x,\ f_{2},-x\left(1-x\right),\ \ \ \ \ \ \ \ \ \ \ \ x\in\left[-2-1\right]
f0&ZeroWidthSpace;(x)\displaystyle f_{0}\left(x\right) =f1&ZeroWidthSpace;(x)=f2&ZeroWidthSpace;(x)=0,x∈[−1,1]\displaystyle=f_{1}\left(x\right)=f_{2}\left(x\right)=0,\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x\in\left[-1,1\right]
f0&ZeroWidthSpace;(x)\displaystyle f_{0}\left(x\right) =1−x,f1&ZeroWidthSpace;(x)=−x&ZeroWidthSpace;(1−x),f2&ZeroWidthSpace;(x)=(1−x)&ZeroWidthSpace;(2−x),x∈[1,2]\displaystyle=1-x,\ f_{1}\left(x\right)=-x\left(1-x\right),\ f_{2}\left(x\right)=\left(1-x\right)\left(2-x\right),\ \ \ \ x\in\left[1,2\right]

[−2,2]\left[-2,2\right] △h(x;f0,f1,f2)=0\bigtriangleup_{h}\left(x;f_{0},f_{1},f_{2}\right)=0, oricare ar fi −2≤x,x+2&ZeroWidthSpace;h≤2-2\leq x,x+2h\leq 2.

Totusi functiile f0&ZeroWidthSpace;(x),f1&ZeroWidthSpace;(x),f2&ZeroWidthSpace;(x)f_{0}\left(x\right),f_{1}\left(x\right),f_{2}\left(x\right) [−2,2]\left[-2,2\right]

5.

fi&ZeroWidthSpace;(x)=xi,i=0,1,…,n−1f_{i}\left(x\right)=x^{i}\ ,i=0,1,\ldots,n-1
1!&ZeroWidthSpace;2!,…,(n−1)!&ZeroWidthSpace;hn&ZeroWidthSpace;(n−1)2&ZeroWidthSpace;∑i=0n(−1)n−i&ZeroWidthSpace;(ni)&ZeroWidthSpace;fn&ZeroWidthSpace;(x+i&ZeroWidthSpace;h).1!2!,\ldots,\left(n-1\right)!h^{\frac{n\left(n-1\right)}{2}}\sum_{i=0}^{n}\left(-1\right)^{n-i}\binom{n}{i}f_{n}\left(x+ih\right).
∑i=0n(−1)n−i&ZeroWidthSpace;(ni)&ZeroWidthSpace;f&ZeroWidthSpace;(x+i&ZeroWidthSpace;h)=0,x,x+n&ZeroWidthSpace;h∈[a,b]\sum_{i=0}^{n}\left(-1\right)^{n-i}\binom{n}{i}f\left(x+ih\right)=0,\ x,x+nh\in\left[a,b\right]

n−1n-1. f&ZeroWidthSpace;(x)f\left(x\right) f&ZeroWidthSpace;(x)f\left(x\right) [a,b]\left[a,b\right].

pe intervalul [a,b]\left[a,b\right].

△h(f0,f1,…,fn−1,f)=0,x,x+n&ZeroWidthSpace;h∈[a,b]\bigtriangleup_{h}\left(f_{0},f_{1},\ldots,f_{n-1},f\right)=0,\ \ x,x+nh\in\left[a,b\right]

6.

Sa considerma n+2n+2 puncte x1,x2,…,xn+2x_{1},x_{2},\ldots,x_{n+2} 2&ZeroWidthSpace;n+12n+1

f0&ZeroWidthSpace;(x1)f_{0}\left(x_{1}\right) f1&ZeroWidthSpace;(x1)f_{1}\left(x_{1}\right) ⋯\cdots fn−1&ZeroWidthSpace;(x1)f_{n-1}\left(x_{1}\right) f&ZeroWidthSpace;(x1)f\left(x_{1}\right) f0&ZeroWidthSpace;(x1)f_{0}\left(x_{1}\right) f1&ZeroWidthSpace;(x1)f_{1}\left(x_{1}\right) ⋯\cdots fn−1&ZeroWidthSpace;(x1)f_{n-1}\left(x_{1}\right)
f0&ZeroWidthSpace;(x2)f_{0}\left(x_{2}\right) f1&ZeroWidthSpace;(x2)f_{1}\left(x_{2}\right) ⋯\cdots fn−1&ZeroWidthSpace;(x2)f_{n-1}\left(x_{2}\right) f&ZeroWidthSpace;(x2)f\left(x_{2}\right) 0 0 ⋯\cdots 0
f0&ZeroWidthSpace;(x3)f_{0}\left(x_{3}\right) f1&ZeroWidthSpace;(x3)f_{1}\left(x_{3}\right) ⋯\cdots fn−1&ZeroWidthSpace;(x3)f_{n-1}\left(x_{3}\right) f&ZeroWidthSpace;(x3)f\left(x_{3}\right) 0 0 ⋯\cdots 0
⋯\cdots ⋯\cdots
f0&ZeroWidthSpace;(xi−1)f_{0}\left(x_{i-1}\right) f1&ZeroWidthSpace;(xi−1)f_{1}\left(x_{i-1}\right) ⋯\cdots fn−1&ZeroWidthSpace;(xi−1)f_{n-1}\left(x_{i-1}\right) f&ZeroWidthSpace;(xi−1)f\left(x_{i-1}\right) 0 0 ⋯\cdots 0
f0&ZeroWidthSpace;(xi)f_{0}\left(x_{i}\right) f1&ZeroWidthSpace;(xi)f_{1}\left(x_{i}\right) ⋯\cdots fn−1&ZeroWidthSpace;(xi)f_{n-1}\left(x_{i}\right) f&ZeroWidthSpace;(xi)f\left(x_{i}\right) f0&ZeroWidthSpace;(xi)f_{0}\left(x_{i}\right) f1&ZeroWidthSpace;(xi)f_{1}\left(x_{i}\right) ⋯\cdots fn−1&ZeroWidthSpace;(xi)f_{n-1}\left(x_{i}\right)
f0&ZeroWidthSpace;(xi+1)f_{0}\left(x_{i+1}\right) f1&ZeroWidthSpace;(xi+1)f_{1}\left(x_{i+1}\right) ⋯\cdots fn−1&ZeroWidthSpace;(xi+1)f_{n-1}\left(x_{i+1}\right) f&ZeroWidthSpace;(xi+1)f\left(x_{i+1}\right) 0 0 ⋯\cdots 0
f0&ZeroWidthSpace;(xi+2)f_{0}\left(x_{i+2}\right) f1&ZeroWidthSpace;(xi+2)f_{1}\left(x_{i+2}\right) ⋯\cdots fn−1&ZeroWidthSpace;(xi+2)f_{n-1}\left(x_{i+2}\right) f&ZeroWidthSpace;(xi+2)f\left(x_{i+2}\right) 0 0 ⋯\cdots 0
⋯\cdots ⋯\cdots
f0&ZeroWidthSpace;(xn+1)f_{0}\left(x_{n+1}\right) f1&ZeroWidthSpace;(xn+1)f_{1}\left(x_{n+1}\right) ⋯\cdots fn−1&ZeroWidthSpace;(xn+1)f_{n-1}\left(x_{n+1}\right) f&ZeroWidthSpace;(xn+1)f\left(x_{n+1}\right) 0 0 ⋯\cdots 0
f0&ZeroWidthSpace;(xn+2)f_{0}\left(x_{n+2}\right) f1&ZeroWidthSpace;(xn+2)f_{1}\left(x_{n+2}\right) ⋯\cdots fn&ZeroWidthSpace;(xn+2)f_{n}\left(x_{n+2}\right) f&ZeroWidthSpace;(xn+2)f\left(x_{n+2}\right) f0&ZeroWidthSpace;(xn+2)f_{0}\left(x_{n+2}\right) f1&ZeroWidthSpace;(xn+2)f_{1}\left(x_{n+2}\right) ⋯\cdots fn−1&ZeroWidthSpace;(xn+2)f_{n-1}\left(x_{n+2}\right)
0 0 ⋯\cdots 0 0 f0&ZeroWidthSpace;(x2)f_{0}\left(x_{2}\right) f1&ZeroWidthSpace;(x2)f_{1}\left(x_{2}\right) ⋯\cdots fn−1&ZeroWidthSpace;(x2)f_{n-1}\left(x_{2}\right)
0 0 ⋯\cdots 0 0 f0&ZeroWidthSpace;(x3)f_{0}\left(x_{3}\right) f1&ZeroWidthSpace;(x3)f_{1}\left(x_{3}\right) ⋯\cdots fn−1&ZeroWidthSpace;(x3)f_{n-1}\left(x_{3}\right)
⋯\cdots ⋯\cdots
0 0 ⋯\cdots 0 0 f0&ZeroWidthSpace;(x&ZeroWidthSpace;l&ZeroWidthSpace;i−1)f_{0}\left(xli-1\right) f1&ZeroWidthSpace;(xi−1)f_{1}\left(x_{i-1}\right) ⋯\cdots fn−1&ZeroWidthSpace;(xi−1)f_{n-1}\left(x_{i-1}\right)
0 0 ⋯\cdots 0 0 f0&ZeroWidthSpace;(xi+1)f_{0}\left(x_{i+1}\right) f?&ZeroWidthSpace;?&ZeroWidthSpace;(xi+1)f_{??}\left(x_{i+1}\right) ⋯\cdots fn−1&ZeroWidthSpace;(xi+1)f_{n-1}\left(x_{i+1}\right)
0 0 ⋯\cdots 0 0 f0&ZeroWidthSpace;(xi+2)f_{0}\left(x_{i+2}\right) f1&ZeroWidthSpace;(xi+2)f_{1}\left(x_{i+2}\right) ⋯\cdots fn−1&ZeroWidthSpace;(xi+2)f_{n-1}\left(x_{i+2}\right)
⋯\cdots ⋯\cdots
0 0 ⋯\cdots 0 0 f0&ZeroWidthSpace;(xn+1)f_{0}\left(x_{n+1}\right) f1&ZeroWidthSpace;(xn+1)f_{1}\left(x_{n+1}\right) ⋯\cdots fn−1&ZeroWidthSpace;(xn+?&ZeroWidthSpace;?&ZeroWidthSpace;?)f_{n-1}\left(x_{n+???}\right)

2≤i≤n+12\leq i\leq n+1 i=2i=2 si i=n+1i=n+1.

n+1n+1

V&ZeroWidthSpace;(f0,f1,…,fn−1x2,x3,…,xn+1)&ZeroWidthSpace;V&ZeroWidthSpace;(f0,f1,…,fn−1x1,x2,…,xi−1,xi+1,xi+2,…,xn+2)=\displaystyle V\binom{f_{0},f_{1},\ldots,f_{n-1}}{x_{2},x_{3},\ldots,x_{n+1}}V\binom{f_{0},f_{1},\ldots,f_{n-1}}{x_{1},x_{2},\ldots,x_{i-1},x_{i+1},x_{i+2},\ldots,x_{n+2}}=
|\displaystyle| =V&ZeroWidthSpace;(f0,f1,…,fn−1x2,x3,…,xi−1,xi+1,xi+2,…,xn+2)&ZeroWidthSpace;V&ZeroWidthSpace;(f0,f1,…,fn−1,fx1,x2,…,xn+1)+\displaystyle=V\binom{f_{0},f_{1},\ldots,f_{n-1}}{x_{2},x_{3},\ldots,x_{i-1},x_{i+1},x_{i+2},\ldots,x_{n+2}}V\binom{f_{0},f_{1},\ldots,f_{n-1},f}{x_{1},x_{2},\ldots,x_{n+1}}+
+V&ZeroWidthSpace;(f0,f1,…,fn−1x1,x2,…,xi−1,xi+1,xi+2,…,x?&ZeroWidthSpace;?&ZeroWidthSpace;?+1)&ZeroWidthSpace;V&ZeroWidthSpace;(f0,f1,…,fn−1,fx2,x3,…,xn+2)\displaystyle+V\binom{f_{0},f_{1},\ldots,f_{n-1}}{x_{1},x_{2},\ldots,x_{i-1},x_{i+1},x_{i+2},\ldots,x_{???+1}}V\binom{f_{0},f_{1},\ldots,f_{n-1},f}{x_{2},x_{3},\ldots,x_{n+2}}

i=2i=2 sau i=n+1i=n+1.

(xn+2−x1)&ZeroWidthSpace;[x1,x2,…,xi−1,xi+1,xi+2,…,xn+2;f]\displaystyle\left(x_{n+2}-x_{1}\right)\left[x_{1},x_{2},\ldots,x_{i-1},x_{i+1},x_{i+2},\ldots,x_{n+2};f\right]
=(xi−x1)&ZeroWidthSpace;[x1,x2,…,xn+1;f]+(xn+2−xi)&ZeroWidthSpace;[x2,x3,…,xn+2;f].\displaystyle=\left(x_{i}-x_{1}\right)\left[x_{1},x_{2},\ldots,x_{n+1};f\right]+\left(x_{n+2}-x_{i}\right)\left[x_{2},x_{3},\ldots,x_{n+2};f\right].

7. finita x1,x2,…,xm&ZeroWidthSpace;(m≥n+1)x_{1},x_{2},\ldots,x_{m}\left(m\geq n+1\right) [a,b]\left[a,b\right]

V&ZeroWidthSpace;(f0,f1,…,fn−1,fnxi,xi+1,…,xi+n)=0,i=1,2,…,m−nV\binom{f_{0},f_{1},\ldots,f_{n-1},f_{n}}{x_{i},x_{i+1},\ldots,x_{i+n}}=0,\ i=1,2,\ldots,m-n

f&ZeroWidthSpace;(x)f\left(x\right)

V&ZeroWidthSpace;(f0,f1,…,fn−1,&ZeroWidthSpace;fx1,x2,…,xn+1)=0V\binom{f_{0},f_{1},\ldots,f_{n-1,}f}{x_{1},x_{2},\ldots,x_{n+1}}=0

x1,x2,…,xn+1∈[a,b]x_{1},x_{2},\ldots,x_{n+1}\in\left[a,b\right]

Punctele xx xr−xsx_{r}-x_{s}

grup de n+1n+1 intervalul [a,b]\left[a,b\right].

f&ZeroWidthSpace;(x)f\left(x\right) [a,b]\left[a,b\right], orice grup de n+1n+1

[a,b]\left[a,b\right],

f&ZeroWidthSpace;(x)=c0&ZeroWidthSpace;f0&ZeroWidthSpace;(x)+c1&ZeroWidthSpace;f1&ZeroWidthSpace;(x)+⋯+cn−1&ZeroWidthSpace;fn−1&ZeroWidthSpace;(x),f\left(x\right)=c_{0}f_{0}\left(x\right)+c_{1}f_{1}\left(x\right)+\cdots+c_{n-1}f_{n-1}\left(x\right),

unde ci,i=0,1,…,n−1c_{i},\ i=0,1,\ldots,n-1,

pentru nn\ x1,x2,…,xnx_{1},x_{2},\ldots,x_{n} va  variabil xn+1=xx_{n+1}=x

1.

f0&ZeroWidthSpace;(x)=sin⁡x,f,(x)=cos⁡xf_{0}\left(x\right)=\sin x,\ f,\ \left(x\right)=\cos x

[a,b]\left[a,b\right] unde 0≤a<b≤π,b−a<π=π0\leq a<b\leq\pi,b-a<\pi=\allowbreak\pi.

f&ZeroWidthSpace;(x)−2&ZeroWidthSpace;cosh⁡f&ZeroWidthSpace;(x+h)=f&ZeroWidthSpace;(x+2&ZeroWidthSpace;h)=0f\left(x\right)-2\cosh f\left(x+h\right)=f\left(x+2h\right)=0

c0&ZeroWidthSpace;sin⁡x+c1&ZeroWidthSpace;cos⁡xc_{0}\sin x+c_{1}\cos x.

2.

f0&ZeroWidthSpace;(x)=1,f&ZeroWidthSpace;(x)=sin⁡x,f2&ZeroWidthSpace;(x)=cos⁡xf_{0}\left(x\right)=1,\ f\left(x\right)=\sin x,\ f_{2}\left(x\right)=\cos x

[a,b]\left[a,b\right] 0≤a<b≤2&ZeroWidthSpace;π,b−a<2&ZeroWidthSpace;π\leq a<b\leq 2\pi,\ b-a<2\pi.

f&ZeroWidthSpace;(x)−f&ZeroWidthSpace;(x+3&ZeroWidthSpace;h)=(2&ZeroWidthSpace;cosh+1)&ZeroWidthSpace;[f&ZeroWidthSpace;(x+h)−f&ZeroWidthSpace;(x+2&ZeroWidthSpace;h)]f\left(x\right)-f\left(x+3h\right)=\left(2\cosh+1\right)\left[f\left(x+h\right)-f\left(x+2h\right)\right]

este deci de forma c0+c1&ZeroWidthSpace;sin⁡x+c2&ZeroWidthSpace;cos⁡xc_{0}+c_{1}\sin x+c_{2}\cos x.

sin⁡x,cos⁡x,sin⁡2&ZeroWidthSpace;x,cos⁡2&ZeroWidthSpace;x,…,sin⁡n&ZeroWidthSpace;x,cos⁡n&ZeroWidthSpace;x\sin x,\cos x,\sin 2x,\cos 2x,\ldots,\sin nx,\cos nx

sau

1,sin⁡x,cos⁡x,sin⁡2&ZeroWidthSpace;x,cos⁡2&ZeroWidthSpace;x,…,sin⁡n&ZeroWidthSpace;x,cos⁡n&ZeroWidthSpace;x.1,\sin x,\cos x,\sin 2x,\cos 2x,\ldots,\sin nx,\cos nx.

9. f&ZeroWidthSpace;(x)f\left(x\right) [a,b]\left[a,b\right] [a,b]\left[a,b\right]

|f&ZeroWidthSpace;(x)|<M,x∈[a,b].\left|f\left(x\right)\right|<M,x\in\left[a,b\right].

functia f&ZeroWidthSpace;(x)f\left(x\right) [a,b]\left[a,b\right]

x0x_{0} α1,α2,…,αn−1,n−1\alpha_{1},\alpha_{2},\ldots,\alpha_{n-1},n-1 x0x_{0} [a,b]\left[a,b\right]

Avem

V&ZeroWidthSpace;(f0,f1,…,fn−2α1,α2,…,αn−1,x0)=λ≠0.V\binom{f_{0},f_{1},\ldots,f_{n-2}}{\alpha_{1},\alpha_{2},\ldots,\alpha_{n-1},x_{0}}=\lambda\neq 0.

V&ZeroWidthSpace;(f0,f1,…,fn−1x1,x2,…,xa&ZeroWidthSpace;?&ZeroWidthSpace;?&ZeroWidthSpace;?)V\binom{f_{0},f_{1},\ldots,f_{n-1}}{x_{1},x_{2},\ldots,x_{a\ ???}} x1,x2,…,xnx_{1},x_{2},\ldots,x_{n}, ε\varepsilon μ<|λ|\mu<\left|\lambda\right|,,{}^{\text{,}} δ\delta x∈(x0−δ,x0+δ),αi′∈(αi+δ,)i=1,2,…,n−1x\in\left(x_{0}-\delta,x_{0}+\delta\right),\alpha_{i}^{\prime}\in\left(\alpha_{i}+\delta,\right)i=1,2,\ldots,n-1

|V&ZeroWidthSpace;(f0,f1,…,fn−1x,α1′,α2′,…,αn−1′)|>μ\displaystyle\left|V\binom{f_{0},f_{1},\ldots,f_{n-1}}{x,\alpha_{1}^{\prime},\alpha_{2}^{\prime},\ldots,\alpha_{n-1}^{\prime}}\right|>\mu
|f&ZeroWidthSpace;(x0)|&ZeroWidthSpace;|V&ZeroWidthSpace;(f0,f1,…,fn−1x0,α1′,α2′,…,αn−1′)−V&ZeroWidthSpace;(f0,f1,…,fn−1x,α1′,α2′,…,αn−1′)|<μ&ZeroWidthSpace;ε2\displaystyle\left|f\left(x_{0}\right)\right|\left|V\binom{f_{0},f_{1},\ldots,f_{n-1}}{x_{0},\alpha_{1}^{\prime},\alpha_{2}^{\prime},\ldots,\alpha_{n-1}^{\prime}}-V\binom{f_{0},f_{1},\ldots,f_{n-1}}{x,\alpha_{1}^{\prime},\alpha_{2}^{\prime},\ldots,\alpha_{n-1}^{\prime}}\right|<\frac{\mu\varepsilon}{2}
|V&ZeroWidthSpace;(f0,f1,…,fn−1x,x0,α1′,α´2,…,αi−1′&ZeroWidthSpace;αi+1,αi+2′′,…,αn−1′)|<μ&ZeroWidthSpace;ε2&ZeroWidthSpace;(n−1)&ZeroWidthSpace;M,i=1,2,…,n−1.\displaystyle\left|V\binom{f_{0},f_{1},\ldots,f_{n-1}}{x,x_{0},\alpha_{1}^{\prime},\acute{\alpha}_{2},\ldots,\alpha_{i-1}^{\prime}\alpha_{i+1},\alpha_{i+2}^{\prime\prime},\ldots,\alpha_{n-1}^{\prime}}\right|<\frac{\mu\varepsilon}{2\left(n-1\right)M},i=1,2,\ldots,n-1.

x∈(x0−δ,x0+δ)x\in\left(x_{0}-\delta,x_{0}+\delta\right) αi′\alpha_{i}^{\prime} α1′,α2′,…,αn−1′,x0,x\alpha_{1}^{\prime},\alpha_{2}^{\prime},\ldots,\alpha_{n-1}^{\prime},x_{0},x

V&ZeroWidthSpace;(f0,f1,…,fn−1,fα1′,α2′,…,αn−1′,x0,x)=0V\binom{f_{0},f_{1},\ldots,f_{n-1},f}{\alpha_{1}^{\prime},\alpha_{2}^{\prime},\ldots,\alpha_{n-1}^{\prime},x_{0},x}=0

din care deducem

[f&ZeroWidthSpace;(x0)−f&ZeroWidthSpace;(x)]&ZeroWidthSpace;V&ZeroWidthSpace;(f0,f1,…,fn−1x0,α1′,α2′,…,αn−1′)=\displaystyle\left[f\left(x_{0}\right)-f\left(x\right)\right]V\binom{f_{0},f_{1},\ldots,f_{n-1}}{x_{0},\alpha_{1}^{\prime},\alpha_{2}^{\prime},\ldots,\alpha_{n-1}^{\prime}}=
=f&ZeroWidthSpace;(x0)&ZeroWidthSpace;[V&ZeroWidthSpace;(f0,f1,…,fn−1x0,α1′,α2′,…,αn−1′)−V&ZeroWidthSpace;(f0,f1,…,fn−1x,α1′,α2′,…,αn−1′)]+\displaystyle=f\left(x_{0}\right)\left[V\binom{f_{0},f_{1},\ldots,f_{n-1}}{x_{0},\alpha_{1}^{\prime},\alpha_{2}^{\prime},\ldots,\alpha_{n-1}^{\prime}}-V\binom{f_{0},f_{1},\ldots,f_{n-1}}{x,\alpha_{1}^{\prime},\alpha_{2}^{\prime},\ldots,\alpha_{n-1}^{\prime}}\right]+
+∑i=1n−1(−1)i&ZeroWidthSpace;f&ZeroWidthSpace;(αi′)&ZeroWidthSpace;V&ZeroWidthSpace;(f0,f1,…,fn−1x,x0,α1′,α2′,…,αi−1′,αi+1′,αi+2′,…,αn−1′)\displaystyle+\sum_{i=1}^{n-1}\left(-1\right)^{i}f\left(\alpha_{i}^{\prime}\right)V\binom{f_{0},f_{1},\ldots,f_{n-1}}{x,x_{0},\alpha_{1}^{\prime},\alpha_{2}^{\prime},\ldots,\alpha_{i-1}^{\prime},\alpha_{i+1}^{\prime},\alpha_{i+2}^{\prime},\ldots,\alpha_{n-1}^{\prime}}
|f&ZeroWidthSpace;(x0)−f&ZeroWidthSpace;(x)|<1μ⋅μ&ZeroWidthSpace;ε2+(n−1)&ZeroWidthSpace;Mμ⋅μ&ZeroWidthSpace;ε2&ZeroWidthSpace;(n−1)&ZeroWidthSpace;M=ε\left|f\left(x_{0}\right)-f\left(x\right)\right|<\frac{1}{\mu}\cdot\frac{\mu\varepsilon}{2}+\frac{\left(n-1\right)M}{\mu}\cdot\frac{\mu\varepsilon}{2\left(n-1\right)M}=\varepsilon

|x0−x|<δ\left|x_{0}-x\right|<\delta, f&ZeroWidthSpace;(x)f\left(x\right) x0x_{0}.

pe intervalul [a,b]\left[a,b\right], unde ci,i=0,1,…,n−1c_{i},i=0,1,\ldots,n-1

f&ZeroWidthSpace;(x)f\left(x\right) [a,b]\left[a,b\right]. f&ZeroWidthSpace;(x)f\left(x\right)

10. F&ZeroWidthSpace;(x,y)F\left(x,y\right) xx si yy f&ZeroWidthSpace;(x)&ZeroWidthSpace;g&ZeroWidthSpace;(x)f\left(x\right)g\left(x\right), xx

yy.

F&ZeroWidthSpace;(x,y)=∑i=1mfi&ZeroWidthSpace;(x)&ZeroWidthSpace;gi&ZeroWidthSpace;(y).F\left(x,y\right)=\sum_{i=1}^{m}f_{i}\left(x\right)g_{i}\left(y\right).

Daca F&ZeroWidthSpace;(x,y)F\left(x,y\right)

‖∂1+jF∂xi&ZeroWidthSpace;∂yf‖i′,j=0,1,…,m=0\left\|\frac{\partial^{1+j}F}{\partial x^{i}\partial y^{f}}\right\|_{i^{\prime},j=0,1,\ldots,m}=0

F&ZeroWidthSpace;(x,y)F\left(x,y\right).

11. F&ZeroWidthSpace;(x,y)F\left(x,y\right) pe o multime EE de puncte (x,y)\left(x,y\right) ca xx

ExE_{x} si EyE_{y}).

Vom zice ca mm grad m1>mm_{1}>m.

f1&ZeroWidthSpace;(x),f2&ZeroWidthSpace;(x),…,jf_{1}\left(x\right),f_{2}\left(x\right),\ldots,j

ExE_{x}

g1&ZeroWidthSpace;(y),g2&ZeroWidthSpace;(y),…,g&ZeroWidthSpace;(y)g_{1}\left(y\right),g_{2}\left(y\right),\ldots,g\left(y\right)

EyE_{y}.

functii numai xx numai de yy. efectiv 0.

este de gradul efectiv mm, r<mr<m.

gasi un numar rr mm rr functii φ1&ZeroWidthSpace;(x),φ2&ZeroWidthSpace;(x),…,φr\varphi_{1}\left(x\right),\varphi_{2}\left(x\right),\ldots,\varphi_{r}

fi&ZeroWidthSpace;(x)=ci,1&ZeroWidthSpace;φ1&ZeroWidthSpace;(x)+xi,2&ZeroWidthSpace;φ2&ZeroWidthSpace;(x)+⋯+ci,r&ZeroWidthSpace;φr&ZeroWidthSpace;(x),i=1,2,…,mf_{i}\left(x\right)=c_{i,1}\varphi_{1}\left(x\right)+x_{i,2}\varphi_{2}\left(x\right)+\cdots+c_{i,r}\varphi_{r}\left(x\right),\ \ i=1,2,\ldots,m

unde ci,jc_{i,j}

F&ZeroWidthSpace;(x,y)=∑i=1rφi&ZeroWidthSpace;(x)&ZeroWidthSpace;ψi&ZeroWidthSpace;(y)F\left(x,y\right)=\sum_{i=1}^{r}\varphi_{i}\left(x\right)\psi_{i}\left(y\right)

unde

ψi&ZeroWidthSpace;(y)=c1,i&ZeroWidthSpace;g1&ZeroWidthSpace;(y)+⋯+cm,i&ZeroWidthSpace;gm&ZeroWidthSpace;(y),i=1,2,…,r.\psi_{i}\left(y\right)=c_{1,i}g_{1}\left(y\right)+\cdots+c_{m,i}g_{m}\left(y\right),\ i=1,2,\ldots,r.

12

D&ZeroWidthSpace;(x1,x2,…,xm+1;Fy1,y2,…,ym+1)=‖F&ZeroWidthSpace;(xi,yi)‖i,j=1,2,…,m+1D\left(\begin{array}[c]{cc}x_{1},x_{2},\ldots,x_{m+1}&\\ &;F\\ y_{1},y_{2},\ldots,y_{m+1}&\end{array}\right)=\left\|F\left(x_{i},y_{i}\right)\right\|_{i,j=1,2,\ldots,m+1}

unde x1,x2,…,xm+1x_{1},x_{2},\ldots,x_{m+1} sunt m+1m+1 ExE_{x} iar y1,y2,…,ym+1&ZeroWidthSpace;m+1y_{1},y_{2},\ldots,y_{m+1}m+1 EyE_{y}.

D&ZeroWidthSpace;(x1,x2,…,xm+1y1,y2,…,ym+1;F)=0D\left(\begin{tabular}[c]{l}$x_{1},x_{2},\ldots,x_{m+1}$\\ \\ $y_{1},y_{2},\ldots,y_{m+1}$\end{tabular};F\right)=0

pe EE.

Orice functie F&ZeroWidthSpace;(x,y)F\left(x,y\right) EE mm.

functia F&ZeroWidthSpace;(x,y)F\left(x,y\right) r,1≤r≤m,rr,1\leq r\leq m,r puncte x1,x2,…,x∈Exx_{1},x_{2},\ldots,x\in E_{x} si r\ r puncte y1,y2,…,yr∈Eyy_{1},y_{2},\ldots,y_{r}\in E_{y}

D=D&ZeroWidthSpace;(x1,x2,…,xr;Fy1,y2,…,yr)≠0D=D\left(\begin{array}[c]{cc}x_{1},x_{2},\ldots,x_{r}&\\ &;F\\ y_{1},y_{2},\ldots,y_{r}&\end{array}\right)\neq 0

si

D&ZeroWidthSpace;(x1,x2,…,xr,xy1,y2,…,yr,y;F)=0D\left(\begin{array}[c]{c}x_{1},x_{2},\ldots,x_{r},x\\ \\ y_{1},y_{2},\ldots,y_{r},y\end{array};F\right)=0

oricare ar fi (x,y)∈E\left(x,y\right)\in E. F&ZeroWidthSpace;(x,y)F\left(x,y\right)

Daca rr efectiv rr. Ai,jA_{i,j} DD.

F&ZeroWidthSpace;(x,y)=∑i=1rfi&ZeroWidthSpace;(x)&ZeroWidthSpace;gi&ZeroWidthSpace;(y)F\left(x,y\right)=\sum_{i=1}^{r}f_{i}\left(x\right)g_{i}\left(y\right)

unde, de exemplu

fi&ZeroWidthSpace;(x)=F&ZeroWidthSpace;(x,yi),gi&ZeroWidthSpace;(y)=1D&ZeroWidthSpace;∑s=1r(−1)s+r−i&ZeroWidthSpace;F&ZeroWidthSpace;(xs,y)&ZeroWidthSpace;As,i,i=1,2,…,rf_{i}\left(x\right)=F\left(x,y_{i}\right),g_{i}\left(y\right)=\frac{1}{D}\sum_{s=1}^{r}\left(-1\right)^{s+r-i}F\left(x_{s},y\right)A_{s,i},\ i=1,2,\ldots,r

fi&ZeroWidthSpace;(x)f_{i}\left(x\right) gi&ZeroWidthSpace;(y)g_{i}\left(y\right)

Daca ExE_{x} m+1m+1 EyE_{y} m+1m+1 orice functie F&ZeroWidthSpace;(x,y)F\left(x,y\right) EE mm.

13. Un cuasi-polinom mm mi<mm_{i}<m.

mm m−1m-1.

D&ZeroWidthSpace;(x1,x2,…,xmy1,y2,…,ym&ZeroWidthSpace;j&ZeroWidthSpace;?&ZeroWidthSpace;?&ZeroWidthSpace;?;F)=V&ZeroWidthSpace;(f1,f2,…,fmx1,x2,…,xm)&ZeroWidthSpace;V&ZeroWidthSpace;(g1,g2,…,gmy1,y2,…,ym).D\left(\begin{array}[c]{c}x_{1},x_{2},\ldots,x_{m}\\ \\ y_{1},y_{2},\ldots,y_{mj???}\end{array};F\right)=V\binom{f_{1},f_{2},\ldots,f_{m}}{x_{1},x_{2},\ldots,x_{m}}V\binom{g_{1},g_{2},\ldots,g_{m}}{y_{1},y_{2},\ldots,y_{m}}.

punctele xix_{i} yiy_{i}

Conditia efectiv mm ExE_{x} EyE_{y}.

14. EE R(a≤x≤b,c≤y≤d)R\left(a\leq x\leq b,c\leq y\leq d\right).

Putem considera functii F&ZeroWidthSpace;(x,y)F\left(x,y\right)

D&ZeroWidthSpace;(x1,x2,…,xmy1,y2,…,yn;F)≠0D\left(\begin{tabular}[c]{l}$x_{1},x_{2},\ldots,x_{m}$\\ \\ $y_{1},y_{2},\ldots,y_{n}$\end{tabular};F\right)\neq 0

x1,x2,…,xm∈[a,b]x_{1},x_{2},\ldots,x_{m}\in\left[a,b\right] y1,y2,…,y∈[c,d]y_{1},y_{2},\ldots,y\in\left[c,d\right]

F&ZeroWidthSpace;(x,y)F\left(x,y\right) cu xx yy x1<x2<…<xm,y1<y2<…<ymx_{1}<x_{2}<\ldots<x_{m},y_{1}<y_{2}<\ldots<y_{m},

observam ca pentru y1,i=1,2,…,my_{1},i=1,2,\ldots,m si pentru xi,i=1,2,…,mx_{i},i=1,2,\ldots,m

D&ZeroWidthSpace;(x,x+h,x+2&ZeroWidthSpace;h,…,x+m&ZeroWidthSpace;hy,y+k,y+2&ZeroWidthSpace;k,…,y+m&ZeroWidthSpace;k;F)=0D\left(\begin{array}[c]{c}x,x+h,x+2h,\ldots,x+mh\\ \\ y,y+k,y+2k,\ldots,y+mk\end{array};F\right)=0

unde x,y,h,kx,y,h,k ca a≤x,x+m&ZeroWidthSpace;h≤b,c≤y,y+m&ZeroWidthSpace;k≤da\leq x,x+mh\leq b,c\leq y,y+mk\leq d si mm

Daca functia F&ZeroWidthSpace;(x,y)F\left(x,y\right) x,yx,y pe RR mm.

yy si kk,

D&ZeroWidthSpace;(x1,x2,…,xm+1y,y+k,…,y+mk;F)=0D\left(\begin{tabular}[c]{l}$x_{1},x_{2},\ldots,x_{m+1}$\\ \\ $y,y+k,\ldots,y+mk$\end{tabular};F\right)=0

oricare ar fi xi∈[a,b],i=1,2,…,m+1x_{i}\in\left[a,b\right],i=1,2,\ldots,m+1.

punem fi&ZeroWidthSpace;(x)=F&ZeroWidthSpace;(x,y+i&ZeroWidthSpace;k),i=1,2,…,m,f&ZeroWidthSpace;(x)=F&ZeroWidthSpace;(x,y)f_{i}\left(x\right)=F\left(x,y+ik\right),\ i=1,2,\ldots,m,\ f\left(x\right)=F\left(x,y\right). punctele x1,x2,…,xm+1x_{1},x_{2},\ldots,x_{m+1} si punem fi&ZeroWidthSpace;(y)=F&ZeroWidthSpace;(xi,y),i=1,2,…,m,f&ZeroWidthSpace;(y)=F&ZeroWidthSpace;(x,y)f_{i}\left(y\right)=F\left(x_{i},y\right),\ i=1,2,\ldots,m,f\left(y\right)=F\left(x,y\right),

D&ZeroWidthSpace;(x1,x2,…,xm+1y1,y2,…,ym+1;F)=0D\left(\begin{array}[c]{c}x_{1},x_{2},\ldots,x_{m+1}\\ \\ y_{1},y_{2},\ldots,y_{m+1}\end{array};F\right)=0

oricare ar fi xi∈[a,b],yi∈[c,d],i=1,2,…,m+1x_{i}\in\left[a,b\right],y_{i}\in\left[c,d\right],i=1,2,\ldots,m+1.

15. simetrica de xx si yy.

fi&ZeroWidthSpace;(x)=ai,1&ZeroWidthSpace;g1&ZeroWidthSpace;(x)+ai,2&ZeroWidthSpace;g2&ZeroWidthSpace;(x)+⋯+ai,m&ZeroWidthSpace;gm&ZeroWidthSpace;(x),i=1,2,…,mf_{i}\left(x\right)=a_{i,1}g_{1}\left(x\right)+a_{i,2}g_{2}\left(x\right)+\cdots+a_{i,m}g_{m}\left(x\right),\ i=1,2,\ldots,m

unde ai,ja_{i,j} ai,j=aj,ia_{i,j}=a_{j,i}.

multime liniara ee (deci ca Ex=Ey=eE_{x}=E_{y}=e) mm

(cu a&ZeroWidthSpace;i&ZeroWidthSpace;j=a&ZeroWidthSpace;j,ia\,ij=a\,j,i)

independente pe ee. mm x1,x2,…,xm∈ex_{1},x_{2},\ldots,x_{m}\in e

V∗=V&ZeroWidthSpace;(g1,g1,…,gmx1,x2,…,xm)≠0.V^{\ast}=V\binom{g_{1},g_{1},\ldots,g_{m}}{x_{1},x_{2},\ldots,x_{m}}\neq 0.

permite sa scriem

∑i=1mfi&ZeroWidthSpace;(x)&ZeroWidthSpace;gi&ZeroWidthSpace;(xk)=∑i=12mfi&ZeroWidthSpace;(xk)&ZeroWidthSpace;gi&ZeroWidthSpace;(x),k=1,2,…,m\sum_{i=1}^{m}f_{i}\left(x\right)g_{i}\left(x_{k}\right)=\sum_{i=12}^{m}f_{i}\left(x_{k}\right)g_{i}\left(x\right),\ k=1,2,\ldots,m

fi&ZeroWidthSpace;(x)f_{i}\left(x\right) aratam ca ai,j=aj,ia_{i,j}=a_{j,i}.

∑i≠j1,2,…,m(ai,j−aj,i)&ZeroWidthSpace;[gi&ZeroWidthSpace;(x)&ZeroWidthSpace;gi&ZeroWidthSpace;(y)−gi&ZeroWidthSpace;(x)&ZeroWidthSpace;gj&ZeroWidthSpace;(y)]=0.\sum_{i\neq j}^{1,2,\ldots,m}\left(a_{i,j}-a_{j,i}\right)\left[g_{i}\left(x\right)g_{i}\left(y\right)-g_{i}\left(x\right)g_{j}\left(y\right)\right]=0.

Dind lui xx si yy xxx_{x} si xlx_{l} (m2)\binom{m}{2} (m2)\binom{m}{2} ai,j−aj,ia_{i,j}-a_{j,i}.

al determinantului V∗V^{\ast}. este o putere a lui V∗V^{\ast} ( V∗m+1V^{\ast m+1})..\

Rezulta ca ai,j−aj,i=0,i,j=1,2,…,ma_{i,j}-a_{j,i}=0,\ i,j=1,2,\ldots,m,

coeficientilor ai,ja_{i,j} 0. efectiv mm, cu determinantul ‖ai,j‖\left\|a_{i,j}\right\| de 0.

grad efectiv r<mr<m sume de rr numai de xx yy.

de doua variabile x,yx,y, φ1&ZeroWidthSpace;(x),φ2&ZeroWidthSpace;(x),…,φr&ZeroWidthSpace;(x),φ1&ZeroWidthSpace;(y),φ2&ZeroWidthSpace;(y),…,φr&ZeroWidthSpace;(y)\varphi_{1}\left(x\right),\varphi_{2}\left(x\right),\ldots,\varphi_{r}\left(x\right),\varphi_{1}\left(y\right),\varphi_{2}\left(y\right),\ldots,\varphi_{r}\left(y\right), unde rr φi&ZeroWidthSpace;(x)\varphi_{i}\left(x\right)

References

  • [1] L.J. Magnus, ”Über die Relaitonen der Functionen welche der Gleichung F1&ZeroWidthSpace;y&ZeroWidthSpace;φ1&ZeroWidthSpace;x+F2&ZeroWidthSpace;y&ZeroWidthSpace;φ2&ZeroWidthSpace;x+⋯+Fn&ZeroWidthSpace;y&ZeroWidthSpace;φn&ZeroWidthSpace;x=F1&ZeroWidthSpace;x&ZeroWidthSpace;φ1&ZeroWidthSpace;y+F2&ZeroWidthSpace;x&ZeroWidthSpace;φ2&ZeroWidthSpace;y+⋯+Fn&ZeroWidthSpace;x&ZeroWidthSpace;φn&ZeroWidthSpace;yF_{1}y\varphi_{1}x+F_{2}y\varphi_{2}x+\cdots+F_{n}y\varphi_{n}x=F_{1}x\varphi_{1}y+F_{2}x\varphi_{2}y+\cdots+F_{n}x\varphi_{n}y genugthung”,Journalf.die Reine u,angew.Math.,5, 365-373(1830).
  • [2] Tiberiu Popoviciu, ”Sur les soltions bornées et les solutions mesurables de certaines, équations fonctionnelles”, Mathematica, 14, 47-106 (1938).
  • [3] C. Stephanos, ”Sur une catégorie d’équations fonctionnelles” Rendic. Cric. Mat. Palermo, 18, 360-363 (1904).
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