ON SOME STEFFENSEN-TYPE ITERATIVE METHODS FOR A CLASS OF NONLINEAR EQUATIONS
EMIL CĂTINAŞ(Cluj-Napoca)
1. INTRODUCTION
Consider a Banach space XX and the equation
{:(1)F(x)+G(x)=0:}\begin{equation*}
F(x)+G(x)=0 \tag{1}
\end{equation*}
where F,G:X rarr XF, G: X \rightarrow X are nonlinear operators, FF being Fréchet differentiable and GG being continuously but nondifferentiable. This is the case when we study an equation H(x)=0H(x)=0, with H:X rarr XH: X \rightarrow X a nondifferentiable operator to which we cannot apply Newton's method. HH is then split into two parts: a differentiable part and a nondifferentiable one.
Various methods have been proposed for solving these kind of problems.
In [8, 9, 10] are considered the Newton-like methods:
{:(2)x_(n+1)=x_(n)-F^(')(x_(n))^(-1)(F(x_(n))+G(x_(n)))","quad n=0","1","dots","x_(0)in X",":}\begin{equation*}
x_{n+1}=x_{n}-F^{\prime}\left(x_{n}\right)^{-1}\left(F\left(x_{n}\right)+G\left(x_{n}\right)\right), \quad n=0,1, \ldots, x_{0} \in X, \tag{2}
\end{equation*}
and, more generally,
{:(3)x_(n+1)=x_(n)-A(x_(n))^(-1)(F(x_(n))+G(x_(n)))","quad n=0","1","dots","x_(0)in X:}\begin{equation*}
x_{n+1}=x_{n}-A\left(x_{n}\right)^{-1}\left(F\left(x_{n}\right)+G\left(x_{n}\right)\right), \quad n=0,1, \ldots, x_{0} \in X \tag{3}
\end{equation*}
where AA is a linear operator approximating F^(')F^{\prime}.
In [1] is studied the secant-type method
{:(4)x_(n+1)=x_(n)-[x_(n-1),x_(n);F]^(-1)(F(x_(n))+G(x_(n)))","quad n=1","2","dots","x_(0)","x_(1)in X:}\begin{equation*}
x_{n+1}=x_{n}-\left[x_{n-1}, x_{n} ; F\right]^{-1}\left(F\left(x_{n}\right)+G\left(x_{n}\right)\right), \quad n=1,2, \ldots, x_{0}, x_{1} \in X \tag{4}
\end{equation*}
[x,y;F][x, y ; F] denoting the first order divided difference of FF at the points x,yx, y. The convergence order of these sequences is linear (as it can be also seen in the numerical example).
In [3] is considered a combination of Newton's method and the secant method:
{:(5)x_(n+1)=x_(n)-(F^(')(x_(n))+[x_(n-1),x_(n);G])^(-1)(F(x_(n))+G(x_(n)))","quad n=1","2","dots","x_(0)","x_(1)in X",":}\begin{equation*}
x_{n+1}=x_{n}-\left(F^{\prime}\left(x_{n}\right)+\left[x_{n-1}, x_{n} ; G\right]\right)^{-1}\left(F\left(x_{n}\right)+G\left(x_{n}\right)\right), \quad n=1,2, \ldots, x_{0}, x_{1} \in X, \tag{5}
\end{equation*}
having the convergence order (1+sqrt5)/(2)~~1.618\frac{1+\sqrt{5}}{2} \approx 1.618, i.e., the convergence order of the secant method.
In the present paper we propose a method based on Steffensen's method and Newton's method, having quadratic convergence:
x_(n+1)=x_(n)-(F^(')(x_(n))+[x_(n),varphi(x_(n));G])^(-1)(F(x_(n))+G(x_(n))),quad n=0,1,dots,x_(0)in Xx_{n+1}=x_{n}-\left(F^{\prime}\left(x_{n}\right)+\left[x_{n}, \varphi\left(x_{n}\right) ; G\right]\right)^{-1}\left(F\left(x_{n}\right)+G\left(x_{n}\right)\right), \quad n=0,1, \ldots, x_{0} \in X, where varphi:X rarr X\varphi: X \rightarrow X,
varphi(x)=x-lambda(F(x)+G(x)),\varphi(x)=x-\lambda(F(x)+G(x)),
lambda\lambda being a fixed positive number.
2. THE CONVERGENCE OF THE METHOD
We shall use, as in [4, 5] the known definitions for the divided differences of an operator:
Definition 1. An operator [x_(0),y_(0);G]\left[x_{0}, y_{0} ; G\right] belonging to the space L(X,X)\mathcal{L}(X, X) (the Banach space of the linear and bounded operators from XX to XX ) is called the first order divided difference of the operator G:X rarr XG: X \rightarrow X at the points x_(0)x_{0}, y_(0)in Xy_{0} \in X if the following properties hold:
a) [x_(0),y_(0);G](y_(0)-x_(0))=G(y_(0))-G(x_(0))\left[x_{0}, y_{0} ; G\right]\left(y_{0}-x_{0}\right)=G\left(y_{0}\right)-G\left(x_{0}\right), for x_(0)!=y_(0)x_{0} \neq y_{0};
b) if GG is Fréchet differentiable at x_(0)x_{0}, then
[x_(0),x_(0);G]=G^(')(x_(0))\left[x_{0}, x_{0} ; G\right]=G^{\prime}\left(x_{0}\right)
Definition 2. An operator belonging to the space L(X,L(X,X))\mathcal{L}(X, \mathcal{L}(X, X)), denoted by [x_(0),y_(0),z_(0);G]\left[x_{0}, y_{0}, z_{0} ; G\right], is called the second-order divided difference of the operator G:X rarr XG: X \rightarrow X at the points x_(0),y_(0),z_(0)in Xx_{0}, y_{0}, z_{0} \in X if the following properties hold:
a) [x_(0),y_(0),z_(0);G](z_(0)-x_(0))=[y_(0),z_(0);G]-[x_(0),y_(0);G]\left[x_{0}, y_{0}, z_{0} ; G\right]\left(z_{0}-x_{0}\right)=\left[y_{0}, z_{0} ; G\right]-\left[x_{0}, y_{0} ; G\right], for the distinct points x_(0),y_(0),z_(0)in Xx_{0}, y_{0}, z_{0} \in X;
b) if GG is two times Fréchet differentiable at x_(0)in Xx_{0} \in X, then
[x_(0),x_(0),x_(0);G]=(1)/(2)G^('')(x_(0))\left[x_{0}, x_{0}, x_{0} ; G\right]=\frac{1}{2} G^{\prime \prime}\left(x_{0}\right)
We shall denote by B_(r)(x_(0))={x in X∣||x-x_(0)|| < r}B_{r}\left(x_{0}\right)=\left\{x \in X \mid\left\|x-x_{0}\right\|<r\right\} the open ball having the center at x_(0)in Xx_{0} \in X and the radius r > 0r>0.
Concerning the convergence of the iterative process (6) we shall prove the following theorem:
Theorem 3. If there exists the element x_(0)in Xx_{0} \in X, and the positive real numbers K,l,epsi,M,rK, l, \varepsilon, M, r such that:
i) GG is continuous on B_(r)(x_(0))B_{r}\left(x_{0}\right);
ii) FF is Fréchet differentiable on B_(r)(x_(0))B_{r}\left(x_{0}\right), with the Fréchet derivative satisfying the Lipschitz condition
||F^(')(x)-F^(')(y)|| <= l||x-y||,quad AA x,y inB_(r)(x_(0));\left\|F^{\prime}(x)-F^{\prime}(y)\right\| \leq l\|x-y\|, \quad \forall x, y \in B_{r}\left(x_{0}\right) ;
iii) The second-order divided difference of GG is uniformly bounded on B_(r)(x_(0))B_{r}\left(x_{0}\right) :
||[x,y,z;G]|| <= K,quad AA x,y,z inB_(r)(x_(0));\|[x, y, z ; G]\| \leq K, \quad \forall x, y, z \in B_{r}\left(x_{0}\right) ;
iv) The operators F^(')(x)+[x,varphi(x);G]F^{\prime}(x)+[x, \varphi(x) ; G] are invertible, with the inverses uniformly bounded: AA x inB_(r)(x_(0))\forall x \in B_{r}\left(x_{0}\right) with varphi(x)inB_(r)(x_(0))\varphi(x) \in B_{r}\left(x_{0}\right) there exists (F^(')(x)+[x,varphi(x);G])^(-1)\left(F^{\prime}(x)+[x, \varphi(x) ; G]\right)^{-1} and
||(F^(')(x)+[x,varphi(x);G])^(-1)|| <= M\left\|\left(F^{\prime}(x)+[x, \varphi(x) ; G]\right)^{-1}\right\| \leq M
v) lambda\lambda is chosen such that lambda <= M\lambda \leq M;
vi) q:=M^(2)epsi((l)/(2)+2K) < 1q:=M^{2} \varepsilon\left(\frac{l}{2}+2 K\right)<1 and the radius is given by
r:=(1)/(M((l)/(2)+2K))sum_(k=0)^(oo)q^(2^(k))r:=\frac{1}{M\left(\frac{l}{2}+2 K\right)} \sum_{k=0}^{\infty} q^{2^{k}}
then
j) The sequence (x_(n))_(n >= 0)\left(x_{n}\right)_{n \geq 0} given by (6) is well defined and (x_(n))_(n >= 0)subB_(r)(x_(0));\left(x_{n}\right)_{n \geq 0} \subset B_{r}\left(x_{0}\right) ;
jj) (x_(n))_(n >= 0)\left(x_{n}\right)_{n \geq 0} converges to some x^(**)in bar(B_(r)(x_(0)))x^{*} \in \overline{B_{r}\left(x_{0}\right)}, which is a solution of equation (1);
jjj) The following estimation holds:
||x^(**)-x_(n)|| <= (q^(2^(n)))/(M((l)/(2)+2K)(1-q^(2^(n))))\left\|x^{*}-x_{n}\right\| \leq \frac{q^{2^{n}}}{M\left(\frac{l}{2}+2 K\right)\left(1-q^{2^{n}}\right)}
Proof. From the hypothesis ii ) concerning FF it is known [6] that we get
{:(7)||F(y)-F(x)-F^(')(x)(y-x)|| <= (l)/(2)||y-x||^(2).:}\begin{equation*}
\left\|F(y)-F(x)-F^{\prime}(x)(y-x)\right\| \leq \frac{l}{2}\|y-x\|^{2} . \tag{7}
\end{equation*}
From the definitions of the divided differences we obtain
{:(8)G(y)-G(x)-[x","varphi(x);G](y-x)=[x","varphi(x)","y;G](y-varphi(x))(y-x):}\begin{equation*}
G(y)-G(x)-[x, \varphi(x) ; G](y-x)=[x, \varphi(x), y ; G](y-\varphi(x))(y-x) \tag{8}
\end{equation*}
Indeed,
{:[[x","varphi(x)","y;G](y-varphi(x))(y-x)=],[=[varphi(x)","y;G](y-varphi(x))-[x","varphi(x);G](y-varphi(x))],[=G(y)-G(varphi(x))+[x","varphi(x);G](varphi(x)-x)-[x","varphi(x);G](y-x)],[=G(y)-G(varphi(x))+G(varphi(x))-G(x)-[x","varphi(x);G](y-x)],[=G(y)-G(x)-[x","varphi(x);G](y-x)]:}\begin{aligned}
& {[x, \varphi(x), y ; G](y-\varphi(x))(y-x)=} \\
& =[\varphi(x), y ; G](y-\varphi(x))-[x, \varphi(x) ; G](y-\varphi(x)) \\
& =G(y)-G(\varphi(x))+[x, \varphi(x) ; G](\varphi(x)-x)-[x, \varphi(x) ; G](y-x) \\
& =G(y)-G(\varphi(x))+G(\varphi(x))-G(x)-[x, \varphi(x) ; G](y-x) \\
& =G(y)-G(x)-[x, \varphi(x) ; G](y-x)
\end{aligned}
We shall prove by induction that
{:[(9)x_(k)","varphi(x_(k)) inB_(r)(x_(0))","quad k inN],[||F(x_(k))+G(x_(k))|| <= M^(-2)((l)/(2)+2K)^(-1)q^(2^(k))","quad k inN]:}\begin{align*}
x_{k}, \varphi\left(x_{k}\right) & \in B_{r}\left(x_{0}\right), \quad k \in \mathbb{N} \tag{9}\\
\left\|F\left(x_{k}\right)+G\left(x_{k}\right)\right\| & \leq M^{-2}\left(\frac{l}{2}+2 K\right)^{-1} q^{2^{k}}, \quad k \in \mathbb{N}
\end{align*}
From the above inequality it can be easily deduced by (6) that EEx_(k+1)\exists x_{k+1} and
{:[(10)||x_(k+1)-x_(k)||=||(F^(')(x_(k))+[x_(k),varphi(x_(k));G])^(-1)(F(x_(k))+G(x_(k)))||],[ <= M^(-1)((l)/(2)+2K)^(-1)q^(2^(k))]:}\begin{align*}
\left\|x_{k+1}-x_{k}\right\| & =\left\|\left(F^{\prime}\left(x_{k}\right)+\left[x_{k}, \varphi\left(x_{k}\right) ; G\right]\right)^{-1}\left(F\left(x_{k}\right)+G\left(x_{k}\right)\right)\right\| \tag{10}\\
& \leq M^{-1}\left(\frac{l}{2}+2 K\right)^{-1} q^{2^{k}}
\end{align*}
For k=0k=0 we have:
{:[x_(0) inB_(r)(x_(0));],[||x_(0)-varphi(x_(0))||=||x_(0)-x_(0)+lambda(F(x_(0))+G(x_(0)))|| <= lambda epsi <= M epsi < r","]:}\begin{aligned}
x_{0} & \in B_{r}\left(x_{0}\right) ; \\
\left\|x_{0}-\varphi\left(x_{0}\right)\right\| & =\left\|x_{0}-x_{0}+\lambda\left(F\left(x_{0}\right)+G\left(x_{0}\right)\right)\right\| \leq \lambda \varepsilon \leq M \varepsilon<r,
\end{aligned}
which imply that
{:[varphi(x_(0)) inB_(r)(x_(0))],[||F(x_(0))+G(x_(0))|| <= epsi=M^(-2)((l)/(2)+2K)^(-1)q^(2^(0))]:}.\begin{aligned}
\varphi\left(x_{0}\right) & \in B_{r}\left(x_{0}\right) \\
\left\|F\left(x_{0}\right)+G\left(x_{0}\right)\right\| & \leq \varepsilon=M^{-2}\left(\frac{l}{2}+2 K\right)^{-1} q^{2^{0}}
\end{aligned} .
Suppose now that 9 is true for k= bar(1,n-1)k=\overline{1, n-1}. By it follows that EEx_(n)\exists x_{n}, and we have that x_(n)inB_(r)(x_(0))x_{n} \in B_{r}\left(x_{0}\right). Indeed,
||x_(n)-x_(0)|| <= ||x_(1)-x_(0)||+cdots+||x_(n)-x_(n-1)|| <= M^(-1)((l)/(2)+2K)^(-1)sum_(k=0)^(n-1)q^(2^(k)) < r\left\|x_{n}-x_{0}\right\| \leq\left\|x_{1}-x_{0}\right\|+\cdots+\left\|x_{n}-x_{n-1}\right\| \leq M^{-1}\left(\frac{l}{2}+2 K\right)^{-1} \sum_{k=0}^{n-1} q^{2^{k}}<r
Then, using (6), (7), (8) and (9),
{:[||F(x_(n))+G(x_(n))|| <= ||F(x_(n))-F(x_(n-1))-F^(')(x_(n-1))(x_(n)-x_(n-1))||],[+||G(x_(n))-G(x_(n-1))-[x_(n-1),varphi(x_(n-1));G](x_(n)-x_(n-1))||],[ <= (l)/(2)||x_(n)-x_(n-1)||^(2)+K||x_(n)-x_(n-1)||*||x_(n)-varphi(x_(n-1))|| <= ]:}\begin{aligned}
\left\|F\left(x_{n}\right)+G\left(x_{n}\right)\right\| \leq & \left\|F\left(x_{n}\right)-F\left(x_{n-1}\right)-F^{\prime}\left(x_{n-1}\right)\left(x_{n}-x_{n-1}\right)\right\| \\
& +\left\|G\left(x_{n}\right)-G\left(x_{n-1}\right)-\left[x_{n-1}, \varphi\left(x_{n-1}\right) ; G\right]\left(x_{n}-x_{n-1}\right)\right\| \\
\leq & \frac{l}{2}\left\|x_{n}-x_{n-1}\right\|^{2}+K\left\|x_{n}-x_{n-1}\right\| \cdot\left\|x_{n}-\varphi\left(x_{n-1}\right)\right\| \leq
\end{aligned}
{:[ <= (l)/(2)M^(-2)((l)/(2)+2K)^(-2)q^(2^(n))],[+KM^(-1)((l)/(2)+2K)^(-1)q^(2^(n-1))(M^(-1)((l)/(2)+2K)^(-1)q^(2^(n-1))+lambdaM^(2)((l)/(2)+2K)^(-1)q^(2^(n-1)))],[ <= M^(-2)((l)/(2)+2K)^(-1)q^(2^(n))]:}\begin{aligned}
\leq & \frac{l}{2} M^{-2}\left(\frac{l}{2}+2 K\right)^{-2} q^{2^{n}} \\
& +K M^{-1}\left(\frac{l}{2}+2 K\right)^{-1} q^{2^{n-1}}\left(M^{-1}\left(\frac{l}{2}+2 K\right)^{-1} q^{2^{n-1}}+\lambda M^{2}\left(\frac{l}{2}+2 K\right)^{-1} q^{2^{n-1}}\right) \\
\leq & M^{-2}\left(\frac{l}{2}+2 K\right)^{-1} q^{2^{n}}
\end{aligned}
It remains to show that varphi(x_(n))inB_(r)(x_(0))\varphi\left(x_{n}\right) \in B_{r}\left(x_{0}\right) :
{:[||x_(0)-varphi(x_(n))|| <= ||x_(0)-x_(n)||+lambda||F(x_(n))+G(x_(n))||],[ <= M^(-1)((l)/(2)+2K)^(-1)sum_(k=0)^(n-1)q^(2^(k))+M^(-1)((l)/(2)+2K)^(-1)q^(2^(n)) < r.]:}\begin{aligned}
\left\|x_{0}-\varphi\left(x_{n}\right)\right\| & \leq\left\|x_{0}-x_{n}\right\|+\lambda\left\|F\left(x_{n}\right)+G\left(x_{n}\right)\right\| \\
& \leq M^{-1}\left(\frac{l}{2}+2 K\right)^{-1} \sum_{k=0}^{n-1} q^{2^{k}}+M^{-1}\left(\frac{l}{2}+2 K\right)^{-1} q^{2^{n}}<r .
\end{aligned}
The induction (9) is proved.
Now we prove that the sequence (x_(n))_(n >= 0)\left(x_{n}\right)_{n \geq 0} is a Cauchy sequence, hence it converges to some element x^(**)in bar(B_(r)(x_(0)))x^{*} \in \overline{B_{r}\left(x_{0}\right)} :
{:[||x_(n+p)-x_(n)|| <= ||x_(n+p)-x_(n+p-1)||+cdots+||x_(n+1)-x_(n)||],[ <= M^(-1)((l)/(2)+2K)^(-1)sum_(k=n)^(n+p-1)q^(2^(k))],[=M^(-1)((l)/(2)+2K)^(-1)q^(2^(n))sum_(k=n)^(n+p-1)q^(2^(k)-2^(n))],[ <= M^(-1)((l)/(2)+2K)^(-1)q^(2^(n))(1+q^(2*2^(n)-2^(n))+q^(4*2^(n)-2^(n))+dots)],[ <= M^(-1)((l)/(2)+2K)^(-1)(q^(2^(n)))/(1-q^(2^(n)))]:}\begin{aligned}
\left\|x_{n+p}-x_{n}\right\| & \leq\left\|x_{n+p}-x_{n+p-1}\right\|+\cdots+\left\|x_{n+1}-x_{n}\right\| \\
& \leq M^{-1}\left(\frac{l}{2}+2 K\right)^{-1} \sum_{k=n}^{n+p-1} q^{2^{k}} \\
& =M^{-1}\left(\frac{l}{2}+2 K\right)^{-1} q^{2^{n}} \sum_{k=n}^{n+p-1} q^{2^{k}-2^{n}} \\
& \leq M^{-1}\left(\frac{l}{2}+2 K\right)^{-1} q^{2^{n}}\left(1+q^{2 \cdot 2^{n}-2^{n}}+q^{4 \cdot 2^{n}-2^{n}}+\ldots\right) \\
& \leq M^{-1}\left(\frac{l}{2}+2 K\right)^{-1} \frac{q^{2^{n}}}{1-q^{2^{n}}}
\end{aligned}
Passing to limit for n rarr oon \rightarrow \infty in relation (6) and taking into account the hypotheses concerning FF and GG, we get that x^(**)x^{*} is a solution of (1).
The estimation jjjj j j ) is obtained from the above relation, for p rarr oop \rightarrow \infty.
3. NUMERICAL EXAMPLES
Given the system
{[3x^(2)y+y^(2)-1+|x-1|=0],[x^(4)+xy^(3)-1+|y|=0]:}\left\{\begin{array}{c}
3 x^{2} y+y^{2}-1+|x-1|=0 \\
x^{4}+x y^{3}-1+|y|=0
\end{array}\right.
we shall consider X=(R^(2),||*||_(oo))X=\left(\mathbb{R}^{2},\|\cdot\|_{\infty}\right) and F,G:X rarr X,F=(f_(1),f_(2)),G=(g_(1),g_(2))F, G: X \rightarrow X, F=\left(f_{1}, f_{2}\right), G=\left(g_{1}, g_{2}\right), with f_(1)(x,y)=3x^(2)y+y^(2)-1,f_(2)(x,y)=x^(4)+xy^(3)-1,g_(1)(x,y)=|x-1|f_{1}(x, y)=3 x^{2} y+y^{2}-1, f_{2}(x, y)=x^{4}+x y^{3}-1, g_{1}(x, y)=|x-1|, g_(2)(x,y)=|y|g_{2}(x, y)=|y|.
We shall take [x,y;G]inM_(2)(R)[x, y ; G] \in \mathbb{M}_{2}(\mathbb{R}) given by
[x,y;G](i,1)=(g_(i)(y^(1),y^(2))-g(x^(1),y^(2)))/(y^(1)-x^(1)),quad[x,y;G](i,2)=(g_(i)(x^(1),y^(2))-g_(i)(x^(1),x^(2)))/(y^(2)-x^(2))[x, y ; G](i, 1)=\frac{g_{i}\left(y^{1}, y^{2}\right)-g\left(x^{1}, y^{2}\right)}{y^{1}-x^{1}}, \quad[x, y ; G](i, 2)=\frac{g_{i}\left(x^{1}, y^{2}\right)-g_{i}\left(x^{1}, x^{2}\right)}{y^{2}-x^{2}}
i=1,2i=1,2.
Using the method (2) with x_(0)=(1,0)x_{0}=(1,0), we obtain
| nn |
x_(n)^(1)x_{n}^{1} |
x_(n)^(2)x_{n}^{2} |
||x_(n)-x_(n-1)||\left\|x_{n}-x_{n-1}\right\| |
| 0 |
1.00000000000000*10^(+0)1.00000000000000 \cdot 10^{+0} |
0.00000000000000*10^(+0)0.00000000000000 \cdot 10^{+0} |
|
| 1 |
1.00000000000000*10^(+0)1.00000000000000 \cdot 10^{+0} |
3.33333333333333*10^(-1)3.33333333333333 \cdot 10^{-1} |
3.33*10^(-01)3.33 \cdot 10^{-01} |
| 2 |
9.06550218340611*10^(-1)9.06550218340611 \cdot 10^{-1} |
3.54002911208151*10^(-1)3.54002911208151 \cdot 10^{-1} |
9.344*10^(-02)9.344 \cdot 10^{-02} |
| 3 |
8.85328400663412*10^(-1)8.85328400663412 \cdot 10^{-1} |
3.38027276361332*10^(-1)3.38027276361332 \cdot 10^{-1} |
2.122*10^(-02)2.122 \cdot 10^{-02} |
| 4 |
8.91329556832800*10^(-1)8.91329556832800 \cdot 10^{-1} |
3.26613976593566*10^(-1)3.26613976593566 \cdot 10^{-1} |
1.141*10^(-02)1.141 \cdot 10^{-02} |
| 39 |
8.94655373334687*10^(-1)8.94655373334687 \cdot 10^{-1} |
3.27826521746298*10^(-1)3.27826521746298 \cdot 10^{-1} |
5.149*10^(-19)5.149 \cdot 10^{-19} |
n x_(n)^(1) x_(n)^(2) ||x_(n)-x_(n-1)||
0 1.00000000000000*10^(+0) 0.00000000000000*10^(+0)
1 1.00000000000000*10^(+0) 3.33333333333333*10^(-1) 3.33*10^(-01)
2 9.06550218340611*10^(-1) 3.54002911208151*10^(-1) 9.344*10^(-02)
3 8.85328400663412*10^(-1) 3.38027276361332*10^(-1) 2.122*10^(-02)
4 8.91329556832800*10^(-1) 3.26613976593566*10^(-1) 1.141*10^(-02)
39 8.94655373334687*10^(-1) 3.27826521746298*10^(-1) 5.149*10^(-19)| $n$ | $x_{n}^{1}$ | $x_{n}^{2}$ | $\left\\|x_{n}-x_{n-1}\right\\|$ |
| :--- | :--- | :--- | :--- |
| 0 | $1.00000000000000 \cdot 10^{+0}$ | $0.00000000000000 \cdot 10^{+0}$ | |
| 1 | $1.00000000000000 \cdot 10^{+0}$ | $3.33333333333333 \cdot 10^{-1}$ | $3.33 \cdot 10^{-01}$ |
| 2 | $9.06550218340611 \cdot 10^{-1}$ | $3.54002911208151 \cdot 10^{-1}$ | $9.344 \cdot 10^{-02}$ |
| 3 | $8.85328400663412 \cdot 10^{-1}$ | $3.38027276361332 \cdot 10^{-1}$ | $2.122 \cdot 10^{-02}$ |
| 4 | $8.91329556832800 \cdot 10^{-1}$ | $3.26613976593566 \cdot 10^{-1}$ | $1.141 \cdot 10^{-02}$ |
| 39 | $8.94655373334687 \cdot 10^{-1}$ | $3.27826521746298 \cdot 10^{-1}$ | $5.149 \cdot 10^{-19}$ |
Using the method ( 5 ) with x_(0)=(1,1),x_(1)=(2,2)x_{0}=(1,1), x_{1}=(2,2) we get:
| nn |
x_(n)^(1)x_{n}^{1} |
x_(n)^(2)x_{n}^{2} |
||x_(n)-x_(n-1)||\left\|x_{n}-x_{n-1}\right\| |
| 0 |
2.00000000000000*10^(+0)2.00000000000000 \cdot 10^{+0} |
2.00000000000000*10^(+0)2.00000000000000 \cdot 10^{+0} |
|
| 1 |
1.00000000000000*10^(+0)1.00000000000000 \cdot 10^{+0} |
1.00000000000000*10^(+0)1.00000000000000 \cdot 10^{+0} |
1.000*10^(+00)1.000 \cdot 10^{+00} |
| 2 |
3.33333333333333*10^(-1)3.33333333333333 \cdot 10^{-1} |
1.33333333333333*10^(+0)1.33333333333333 \cdot 10^{+0} |
6.666*10^(+01)6.666 \cdot 10^{+01} |
| 3 |
9.62025316455696*10^(-1)9.62025316455696 \cdot 10^{-1} |
3.54430379746835*10^(-1)3.54430379746835 \cdot 10^{-1} |
9.789*10^(-01)9.789 \cdot 10^{-01} |
| 4 |
9.00696217156264*10^(-1)9.00696217156264 \cdot 10^{-1} |
3.30465935597986*10^(-1)3.30465935597986 \cdot 10^{-1} |
6.132*10^(-02)6.132 \cdot 10^{-02} |
| 5 |
8.94706409693425*10^(-1)8.94706409693425 \cdot 10^{-1} |
3.27855252188766*10^(-1)3.27855252188766 \cdot 10^{-1} |
5.989*10^(-03)5.989 \cdot 10^{-03} |
| 6 |
8.94655376809408*10^(-1)8.94655376809408 \cdot 10^{-1} |
3.27826524565125*10^(-1)3.27826524565125 \cdot 10^{-1} |
5.103*10^(-05)5.103 \cdot 10^{-05} |
| 7 |
8.94655373334687*10^(-1)8.94655373334687 \cdot 10^{-1} |
3.27826521746298*10^(-1)3.27826521746298 \cdot 10^{-1} |
3.474*10^(-09)3.474 \cdot 10^{-09} |
| 8 |
8.94655373334687*10^(-1)8.94655373334687 \cdot 10^{-1} |
3.27826521746298*10^(-1)3.27826521746298 \cdot 10^{-1} |
2.003*10^(-17)2.003 \cdot 10^{-17} |
| 9 |
8.94655373334687*10^(-1)8.94655373334687 \cdot 10^{-1} |
3.27826521746298*10^(-1)3.27826521746298 \cdot 10^{-1} |
2.710*10^(-20)2.710 \cdot 10^{-20} |
n x_(n)^(1) x_(n)^(2) ||x_(n)-x_(n-1)||
0 2.00000000000000*10^(+0) 2.00000000000000*10^(+0)
1 1.00000000000000*10^(+0) 1.00000000000000*10^(+0) 1.000*10^(+00)
2 3.33333333333333*10^(-1) 1.33333333333333*10^(+0) 6.666*10^(+01)
3 9.62025316455696*10^(-1) 3.54430379746835*10^(-1) 9.789*10^(-01)
4 9.00696217156264*10^(-1) 3.30465935597986*10^(-1) 6.132*10^(-02)
5 8.94706409693425*10^(-1) 3.27855252188766*10^(-1) 5.989*10^(-03)
6 8.94655376809408*10^(-1) 3.27826524565125*10^(-1) 5.103*10^(-05)
7 8.94655373334687*10^(-1) 3.27826521746298*10^(-1) 3.474*10^(-09)
8 8.94655373334687*10^(-1) 3.27826521746298*10^(-1) 2.003*10^(-17)
9 8.94655373334687*10^(-1) 3.27826521746298*10^(-1) 2.710*10^(-20)| $n$ | $x_{n}^{1}$ | $x_{n}^{2}$ | $\left\\|x_{n}-x_{n-1}\right\\|$ |
| :--- | :--- | :--- | :--- |
| 0 | $2.00000000000000 \cdot 10^{+0}$ | $2.00000000000000 \cdot 10^{+0}$ | |
| 1 | $1.00000000000000 \cdot 10^{+0}$ | $1.00000000000000 \cdot 10^{+0}$ | $1.000 \cdot 10^{+00}$ |
| 2 | $3.33333333333333 \cdot 10^{-1}$ | $1.33333333333333 \cdot 10^{+0}$ | $6.666 \cdot 10^{+01}$ |
| 3 | $9.62025316455696 \cdot 10^{-1}$ | $3.54430379746835 \cdot 10^{-1}$ | $9.789 \cdot 10^{-01}$ |
| 4 | $9.00696217156264 \cdot 10^{-1}$ | $3.30465935597986 \cdot 10^{-1}$ | $6.132 \cdot 10^{-02}$ |
| 5 | $8.94706409693425 \cdot 10^{-1}$ | $3.27855252188766 \cdot 10^{-1}$ | $5.989 \cdot 10^{-03}$ |
| 6 | $8.94655376809408 \cdot 10^{-1}$ | $3.27826524565125 \cdot 10^{-1}$ | $5.103 \cdot 10^{-05}$ |
| 7 | $8.94655373334687 \cdot 10^{-1}$ | $3.27826521746298 \cdot 10^{-1}$ | $3.474 \cdot 10^{-09}$ |
| 8 | $8.94655373334687 \cdot 10^{-1}$ | $3.27826521746298 \cdot 10^{-1}$ | $2.003 \cdot 10^{-17}$ |
| 9 | $8.94655373334687 \cdot 10^{-1}$ | $3.27826521746298 \cdot 10^{-1}$ | $2.710 \cdot 10^{-20}$ |
Using method (6) with lambda=0.5\lambda=0.5 and x_(0)=(1,1)x_{0}=(1,1) we get:
| nn |
x_(n)^(1)x_{n}^{1} |
x_(n)^(2)x_{n}^{2} |
||x_(n)-x_(n-1)||\left\|x_{n}-x_{n-1}\right\| |
| 0 |
1.00000000000000*10^(+0)1.00000000000000 \cdot 10^{+0} |
0.00000000000000*10^(+00)0.00000000000000 \cdot 10^{+00} |
|
| 1 |
1.40000000000000*10^(+0)1.40000000000000 \cdot 10^{+0} |
0.00000000000000*10^(+00)0.00000000000000 \cdot 10^{+00} |
1.000*10^(+00)1.000 \cdot 10^{+00} |
| 2 |
1.15421294962624*10^(+0)1.15421294962624 \cdot 10^{+0} |
1.43841335097579*10^(-01)1.43841335097579 \cdot 10^{-01} |
2.457*10^(-01)2.457 \cdot 10^{-01} |
| 3 |
1.01057150046324*10^(+1)1.01057150046324 \cdot 10^{+1} |
2.69169893550861*10^(-01)2.69169893550861 \cdot 10^{-01} |
1.436*10^(-01)1.436 \cdot 10^{-01} |
| 4 |
8.99073392876452*10^(-1)8.99073392876452 \cdot 10^{-1} |
3.76267383109311*10^(-01)3.76267383109311 \cdot 10^{-01} |
1.114*10^(-01)1.114 \cdot 10^{-01} |
| 5 |
8.95022505657807*10^(-1)8.95022505657807 \cdot 10^{-1} |
3.28815382034089*10^(-01)3.28815382034089 \cdot 10^{-01} |
4.745*10^(-02)4.745 \cdot 10^{-02} |
| 6 |
8.94655504144107*10^(-1)8.94655504144107 \cdot 10^{-1} |
3.27827488746546*10^(-01)3.27827488746546 \cdot 10^{-01} |
9.878*10^(-04)9.878 \cdot 10^{-04} |
| 7 |
8.94655373334787*10^(-1)8.94655373334787 \cdot 10^{-1} |
3.27826521746806*10^(-01)3.27826521746806 \cdot 10^{-01} |
9.669*10^(-07)9.669 \cdot 10^{-07} |
| 8 |
8.94655373334687*10^(-1)8.94655373334687 \cdot 10^{-1} |
3.27826521746298*10^(-01)3.27826521746298 \cdot 10^{-01} |
5.086*10^(-13)5.086 \cdot 10^{-13} |
| 9 |
8.94655373334687*10^(-1)8.94655373334687 \cdot 10^{-1} |
3.27826521746298*10^(-01)3.27826521746298 \cdot 10^{-01} |
2.710*10^(-20)2.710 \cdot 10^{-20} |
n x_(n)^(1) x_(n)^(2) ||x_(n)-x_(n-1)||
0 1.00000000000000*10^(+0) 0.00000000000000*10^(+00)
1 1.40000000000000*10^(+0) 0.00000000000000*10^(+00) 1.000*10^(+00)
2 1.15421294962624*10^(+0) 1.43841335097579*10^(-01) 2.457*10^(-01)
3 1.01057150046324*10^(+1) 2.69169893550861*10^(-01) 1.436*10^(-01)
4 8.99073392876452*10^(-1) 3.76267383109311*10^(-01) 1.114*10^(-01)
5 8.95022505657807*10^(-1) 3.28815382034089*10^(-01) 4.745*10^(-02)
6 8.94655504144107*10^(-1) 3.27827488746546*10^(-01) 9.878*10^(-04)
7 8.94655373334787*10^(-1) 3.27826521746806*10^(-01) 9.669*10^(-07)
8 8.94655373334687*10^(-1) 3.27826521746298*10^(-01) 5.086*10^(-13)
9 8.94655373334687*10^(-1) 3.27826521746298*10^(-01) 2.710*10^(-20)| $n$ | $x_{n}^{1}$ | $x_{n}^{2}$ | $\left\\|x_{n}-x_{n-1}\right\\|$ |
| :--- | :--- | :--- | :--- |
| 0 | $1.00000000000000 \cdot 10^{+0}$ | $0.00000000000000 \cdot 10^{+00}$ | |
| 1 | $1.40000000000000 \cdot 10^{+0}$ | $0.00000000000000 \cdot 10^{+00}$ | $1.000 \cdot 10^{+00}$ |
| 2 | $1.15421294962624 \cdot 10^{+0}$ | $1.43841335097579 \cdot 10^{-01}$ | $2.457 \cdot 10^{-01}$ |
| 3 | $1.01057150046324 \cdot 10^{+1}$ | $2.69169893550861 \cdot 10^{-01}$ | $1.436 \cdot 10^{-01}$ |
| 4 | $8.99073392876452 \cdot 10^{-1}$ | $3.76267383109311 \cdot 10^{-01}$ | $1.114 \cdot 10^{-01}$ |
| 5 | $8.95022505657807 \cdot 10^{-1}$ | $3.28815382034089 \cdot 10^{-01}$ | $4.745 \cdot 10^{-02}$ |
| 6 | $8.94655504144107 \cdot 10^{-1}$ | $3.27827488746546 \cdot 10^{-01}$ | $9.878 \cdot 10^{-04}$ |
| 7 | $8.94655373334787 \cdot 10^{-1}$ | $3.27826521746806 \cdot 10^{-01}$ | $9.669 \cdot 10^{-07}$ |
| 8 | $8.94655373334687 \cdot 10^{-1}$ | $3.27826521746298 \cdot 10^{-01}$ | $5.086 \cdot 10^{-13}$ |
| 9 | $8.94655373334687 \cdot 10^{-1}$ | $3.27826521746298 \cdot 10^{-01}$ | $2.710 \cdot 10^{-20}$ |
It seems that the best results are not obtained here for lambda\lambda taken too small, because the divided differences cannot be computed in this case for ||x_(n)-x_(n-1)|| <= 1.0*10^(-16)\left\|x_{n}-x_{n-1}\right\| \leq 1.0 \cdot 10^{-16}.
REFERENCES
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[2] M. Balázs, A bilateral approximating method for finding the real roots of real equations, Rev. Anal. Numér. Théor. Approx., 21 (1992) no. 2, pp. 111-117. ㄸ
[3] E. Cătinaş, On some iterative methods for solving nonlinear equations, Rev. Anal. Numér. Théor. Approx., 23 (1994) no. 1, pp. 47-53. «
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Recevied: December 1, 1994
Academia Română
Institutul de Calcul "Tiberiu Popoviciu"
P.O. Box 68
3400 Cluj-Napoca 1
Romania